Why can gene duplication lead to so much important variation in gene families such as the globin genes? A.because any time a duplication occurs "good things" happen
B. because the duplicated copy is now free to evolve a new function
C. it can't.gene duplication is always bad D.this can only happen in genes that are not very important to the survival of the organism

Answers

Answer 1

Gene duplication can lead to significant variation in gene families, such as globin genes, as the duplicated copy is free to evolve new functions, increasing genetic diversity and  providing new adaptive advantages.

Gene duplication is a crucial mechanism in the evolution of gene families and the generation of genetic diversity. When a gene is duplicated, an extra copy of the gene is created in the genome. This duplicated copy is not subjected to the same selective pressures as the original gene and is therefore free to accumulate mutations and evolve new functions.

The duplicated gene copy can undergo various evolutionary processes, such as neofunctionalization or subfunctionalization. Neofunctionalization occurs when the duplicated copy acquires a completely new function that was not present in the original gene. This can result in the evolution of novel traits or biochemical activities.

On the other hand, subfunctionalization occurs when the duplicated copies divide the functions of the original gene between them. Each copy retains only a subset of the original functions, and this division of labor allows for functional specialization and potentially increased efficiency.

In the case of gene families like the globin genes, which play crucial roles in oxygen transport and storage, gene duplication has led to the evolution of multiple globin genes with specialized functions. Different globin genes have diversified to adapt to specific physiological conditions, such as oxygenation at different levels, in different tissues or developmental stages, or under different environmental conditions.

In summary, gene duplication provides opportunities for genetic variation and innovation by allowing duplicated gene copies to acquire new functions or divide existing functions. This process is crucial in the evolution of gene families like the globin genes, leading to the diversification and specialization of genes within the family, ultimately contributing to the adaptability and evolutionary success of organisms.

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Related Questions

Three genotypes in a very large population have, on average, the following values of survival and fecundity, regardless of their relative frequencies: Genotype A1A1 A1A2 A2A2 Survival to adulthood (viability) 0.80 0.90 0.50 Number of offspring 3.0 4.0 8.0 Absolute fitness 2.4 3.6 4.0 Which of the following best describes what will happen at this locus in the long run? There will be a stable polymorphism because the heterozygote has a higher survival rate than either homozygote. Nothing will happen because the differences among genotypes in survival and fecundity cancel each other out. Allele A2 will be fixed eventually. One allele will be fixed but we cannot predict which one. Allele Al will be fixed eventually.

Answers

The population under observation has three genotypes: A1A1, A1A2, and A2A2. These genotypes have survival rates of 0.80, 0.90, and 0.50, and fecundity rates of 3.0, 4.0, and 8.0, respectively.

The absolute fitness of these genotypes is 2.4, 3.6, and 4.0, respectively. Which of the following statements best describes what will happen to the locus in the long run? Allele A2 will eventually become fixed is the correct option. This is due to the fact that allele A2 has the highest fitness of the three alleles, with a fitness of 4.0, and will thus outcompete the other two alleles in the population over time. Eventually, A2 will become the only allele present in the population because it is more effective at reproducing and surviving than A1. Over time, A2 will increase in frequency while A1 will decrease, and ultimately, A2 will become fixed in the population because it will be the only allele remaining.

Therefore, allele A2 will be fixed eventually. The statement "There will be a stable polymorphism because the heterozygote has a higher survival rate than either homozygote" is incorrect.

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Which of the following will most likely happen to a population when the size of the population far overshoots their carrying capacity? (such as the deer on St. Matthew's island) O the population will exhibit exponential growth O the population crashes. the birth rate increases and the death rate decreases. the growth rate remains unchanged.

Answers

The most likely outcome to occur when the size of a population far overshoots their carrying capacity is that the population will crash. A population crash refers to a rapid decrease in the size of a population that results from the inability of the environment to support the population's carrying capacity.

The carrying capacity is the maximum number of individuals in a species that can be supported by a given habitat without causing any negative impacts on the environment.There are a number of factors that can contribute to a population crash, such as disease, predation, environmental degradation, and resource depletion. When a population overshoots their carrying capacity, competition for resources increases, which can lead to reduced food availability, malnutrition, and starvation. The death rate increases, and the birth rate decreases as a result of the scarcity of resources.

So, when the size of a population far overshoots their carrying capacity, the most likely outcome is that the population will experience a crash. This is due to the increased competition for resources, which leads to a decrease in the birth rate and an increase in the death rate.

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Which of the following is not a dietary recommendation? a. Consume 0 grams of trans fats.
b. Consume 48 grams of dietary fiber. c. Consume no more than 50 grams of sugar, and preferably less than 36 grams. d. Consume no more than 80 grams of protein, and preferably less than 50 grams.
e. Consume no more than 2300 mg (2.3 grams) of sodium, and preferably less than 1500 mg.

Answers

Option (d) "Consume no more than 80 grams of protein, and preferably less than 50 grams" is not a dietary recommendation.

Option (d) is not a dietary recommendation because it suggests limiting protein intake to no more than 80 grams, preferably less than 50 grams. However, protein requirements can vary based on factors such as age, sex, body weight, activity level, and overall health. The appropriate amount of protein intake for an individual depends on their specific needs and goals, such as muscle building, weight management, or medical conditions. There is no universally recommended limit on protein intake, and it is generally advised to consume an adequate amount of protein to support overall health.

On the other hand, options (a), (b), (c), and (e) are dietary recommendations commonly advised for maintaining a healthy diet. These recommendations focus on avoiding trans fats, consuming an adequate amount of dietary fiber, limiting sugar intake, and controlling sodium intake for optimal health.

In summary, option (d) "Consume no more than 80 grams of protein, and preferably less than 50 grams" is not a general dietary recommendation, as protein requirements vary among individuals.

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How does the major difference between the heart of a frog and a
pig affect the blood?

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The main difference between the heart of a frog and a pig is that a frog has a three-chambered heart while a pig has a four-chambered heart. This difference in heart structure affects how the blood flows through the body.

Frogs have a three-chambered heart that consists of two atria and one ventricle. The atria receive oxygen-poor blood from the body and oxygen-rich blood from the lungs, respectively. The ventricle then pumps the blood out to the rest of the body.

Because of the single ventricle, blood from both atria is mixed together before being pumped out. This means that oxygen-poor blood may mix with oxygen-rich blood, which lowers the overall oxygen content of the blood.

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Which of the following will most likely disrupt the Hardy-Weinberg equilibrium that xists for a population of small rodents ving in a habitat with ample resources? a. The rodents reproduce frequently and have large litters, so the population size is increasing. b. Mate selection is completely random within the population of rodents. c. The population continues to remain isolated from other populations of the rodent. d. The coding region of a gene is altered in sperm produced by a particular male that mates with several of the female rodents, which produce many progeny as a result.

Answers

The option that is most likely to disrupt the Hardy-Weinberg equilibrium in a population of small rodents living in a habitat with ample resources is: The coding region of a gene is altered in sperm produced by a particular male that mates with several of the female rodents, which produce many progeny as a result. So, option D is accurate.

The Hardy-Weinberg equilibrium describes the genetic equilibrium that occurs in an ideal, non-evolving population. It is based on several assumptions, including random mating, no genetic drift, no gene flow, no mutation, and no selection.

In this scenario, if the coding region of a gene is altered in the sperm produced by a male and is passed on to a large number of progeny, it introduces a genetic change into the population. This alteration can disrupt the equilibrium by changing the allele frequencies. As the altered gene spreads through the population, it can result in a departure from the expected genotype frequencies predicted by the Hardy-Weinberg equilibrium.

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What is the function of Troponin C, Troponin I and Troponin T? How do they each cause muscle contraction? Include detail

Answers

Troponin C, Troponin I, and Troponin T are three subunits of the troponin complex found in muscle cells. They play crucial roles in regulating muscle contraction, specifically in skeletal and cardiac muscles.

Troponin C (TnC): Troponin C is a calcium-binding protein that is essential for muscle contraction. It binds to calcium ions (Ca2+) when the concentration of Ca2+ increases in the cytoplasm of muscle cells, triggering a series of events that lead to muscle contraction.

Troponin I (TnI): Troponin I is another subunit of the troponin complex that inhibits the interaction between actin and myosin, two key proteins involved in muscle contraction. Troponin I prevents muscle contraction in the absence of calcium ions. When calcium ions bind to troponin C, it causes a conformational change in troponin I, relieving its inhibitory effect on actin.

Troponin T (TnT): Troponin T is the third subunit of the troponin complex and plays a structural role in muscle contraction. Troponin T binds to tropomyosin, another protein that is associated with the actin filament. When troponin C binds to calcium ions, it induces a conformational change in troponin T, which in turn shifts the position of tropomyosin.

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Which of the following statements on selection bias is correct? (Multiple answers allowed.)
A. If cases are selected from a single hospital, the identified risk factors may be unique to that hospital.
B. If the cases are drawn from a tertiary care facility, the risk factors identified may be only in persons with severe forms of the disease.
IC. t is generally preferable to use incident cases of the disease in case-control studies of disease etiology.
D.A mother who has had a child with a birth defect often tries to identify some unusual event that occurred during her pregnancy with that child.

Answers

The correct statements on selection bias are: A. If cases are selected from a single hospital, the identified risk factors may be unique to that hospital. B. If the cases are drawn from a tertiary care facility, the risk factors identified may be only in persons with severe forms of the disease. The correct answer is options (A) and (B).

A. When cases are selected from a single hospital, the identified risk factors may be specific to that particular hospital. This is because the patient population and characteristics of that hospital may differ from other hospitals, leading to unique risk factors associated with the disease. B. Selecting cases from a tertiary care facility can introduce selection bias, as the risk factors identified may be applicable only to individuals with severe forms of the disease. Tertiary care facilities often deal with complex and severe cases, which may have different risk factors compared to milder cases seen in primary or secondary care settings.

C. The statement regarding incident cases in case-control studies is not correct. Case-control studies compare cases (individuals with the disease) to controls (individuals without the disease) and are retrospective in nature. Therefore, using incident cases (newly diagnosed cases) is not a requirement for case-control studies.Regarding the additional statement about a mother trying to identify unusual events during her pregnancy, it describes a situation where recall bias may occur. Recall bias refers to the tendency for individuals, in this case, a mother, to selectively remember and report specific events or exposures that they believe might be linked to an outcome, such as a birth defect.

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Explain the relationship between each of the following terms: (a) energy and work (b) potential energy and kinetic energy (c) free energy and spontaneous changes

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(a) Energy and work are related concepts in physics. Energy is a broad term that refers to the capacity of a system to do work or transfer heat.

It exists in different forms such as kinetic energy, potential energy, thermal energy, and more. Work, on the other hand, is a specific type of energy transfer that occurs when a force is applied to an object, causing it to move in the direction of the force. Work is the process of converting energy from one form to another or transferring it from one object to another. (b) Potential energy and kinetic energy are two forms of energy. Potential energy is the energy possessed by an object due to its position or condition. It is stored energy that can be converted into other forms, such as kinetic energy. Kinetic energy, on the other hand, is the energy possessed by an object due to its motion. It depends on the mass of the object and its velocity. When an object moves, its potential energy may be converted into kinetic energy, and vice versa. (c) Free energy and spontaneous changes are related to thermodynamics. Free energy (G) is a measure of the energy available in a system to do useful work. It takes into account both the enthalpy (H) and entropy (S) of the system through the equation: ΔG = ΔH - TΔS, where ΔG is the change in free energy, ΔH is the change in enthalpy, T is the temperature, and ΔS is the change in entropy. Spontaneous changes are processes that occur without the need for external intervention and tend to increase the disorder or entropy of a system. In thermodynamics, a spontaneous process occurs when the change in free energy (ΔG) is negative, indicating that the system's energy is decreasing and becoming more stable.

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1. Describe three differences between prokaryotic and
eukaryotic cells.
2. Discuss the major differences between a plant cell and an
animal cell.

Answers

Prokaryotic and eukaryotic cells have fundamental differences that separate them in terms of structure, function, and overall complexity. Here are three differences between prokaryotic and eukaryotic cells Prokaryotic cells do not have a nucleus, while eukaryotic cells have a nucleus.

Eukaryotic cells have membrane-bound organelles, whereas prokaryotic cells do not. Eukaryotic cells are more complex than prokaryotic cells. A plant cell and an animal cell are similar in that they are both eukaryotic cells and have many similarities in terms of structure and function. However, there are some significant differences between the two. Here are some major differences between a plant cell and an animal cell Plant cells have cell walls, while animal cells do not.

Plant cells contain chloroplasts, which are responsible for photosynthesis, while animal cells do not have chloroplasts. Plant cells have large central vacuoles, while animal cells have small vacuoles or none at all. Plant cells have a more regular shape, while animal cells can take on various shapes. Plant cells store energy as starch, while animal cells store energy as glycogen.

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Prokaryotic genomes can be said to be and as compared to eukaryotic ones. O gene dense; non-coding DNA poor gene poor, non-coding DNA rich gene poor; non-coding DNA poor O gene dense; non-coding DNA rich

Answers

Prokaryotic genomes can be said to be gene dense; non-coding DNA poor, as compared to eukaryotic ones. Prokaryotes have single, circular chromosomes which contain most of their genetic material, whereas eukaryotes have multiple linear chromosomes enclosed in a nucleus.

Prokaryotes are unicellular organisms that lack a true nucleus and membrane-bound organelles, while eukaryotes are organisms that have a true nucleus and membrane-bound organelles, like mitochondria, chloroplasts, and a Golgi apparatus. Eukaryotic DNA is wound around histones to form nucleosomes, which give the chromatin its structure and organization. Non-coding DNA accounts for the majority of the DNA in eukaryotes, while prokaryotes have a relatively small amount of non-coding DNA.Prokaryotic genomes are gene-rich because they have evolved to be very efficient. The high gene density is a result of the compact organization of prokaryotic genomes, which allows them to fit into a small cell. In comparison, eukaryotic genomes are much larger and more complex than prokaryotic ones. Eukaryotic DNA contains introns and exons, which can be alternatively spliced to produce a variety of protein isoforms. As a result, eukaryotic genomes are able to produce a greater diversity of proteins than prokaryotic ones.In conclusion, prokaryotic genomes are gene dense and non-coding DNA poor, while eukaryotic genomes are gene poor, non-coding DNA rich, and more complex.

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To correct sickle-cell anemia via gene therapy using a viral vector, the cells that would need to be collected from a sickle cell patient are called:
a. embryonic stem cells.
b. mesenchymal stem cells.
c. totipotent stem cells.
d. hematopoietic stem cells.
e. neural stem cells.

Answers

To correct sickle-cell anemia via gene therapy using a viral vector, the cells that would need to be collected from a sickle cell patient are hematopoietic stem cells. The correct option is d.

Hematopoietic stem cells are the cells responsible for generating the various types of blood cells, including red blood cells. In sickle-cell anemia, there is a mutation in the gene that codes for hemoglobin, resulting in the production of abnormal hemoglobin molecules that cause the characteristic sickle-shaped red blood cells.

To correct this mutation, gene therapy can be performed by introducing a functional copy of the gene into the patient's cells. Hematopoietic stem cells are an ideal target for gene therapy in sickle-cell anemia because they are the precursor cells that give rise to red blood cells.

By collecting hematopoietic stem cells from the patient, modifying them with the functional gene using a viral vector (such as a modified virus), and then reintroducing these genetically modified cells back into the patient's body, it is possible to restore normal hemoglobin production and alleviate the symptoms of sickle-cell anemia.

Therefore, the correct answer is d.

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After cloning an insert into a plasmid, determining its orientation is best accomplished with ... O Two restriction endonucleases that cut in the insert. O Two restriction endonuclease, one that cuts once within the insert and the other that cuts once in the plasmid backbone. A single restriction endonuclease that cuts twice to release the insert. A single endonuclease that cuts twice in the plasmid backbone.

Answers

The answer is that when a foreign DNA fragment is inserted into a cloning vector, the orientation of the insert is crucial.

After cloning an insert into a plasmid, determining its orientation is best accomplished with two restriction endonucleases, one that cuts once within the insert and the other that cuts once in the plasmid backbone.

The correct orientation of the insert guarantees that the promoter and terminator sequences in the plasmid will be effective. The incorrect orientation of the insert will result in the inactivation of the promoter and terminator sequences in the plasmid. Therefore, to ensure the correct orientation of the insert, it is necessary to perform a diagnostic restriction enzyme digestion. The two enzymes selected should have recognition sites that cut the plasmid in one site and the insert in another site. The end result is to get two bands on a gel, which confirms the orientation of the insert. One band should correspond to the uncut plasmid, while the other should correspond to the plasmid cut by the restriction enzyme. The band's size will differ depending on the position of the restriction enzyme site in the insert. Determining the orientation of the insert in the vector is crucial because if the insert's orientation is reversed, the inserted gene's reading frame may be disrupted, leading to a complete loss of function. A gene inserted in reverse orientation with respect to the promoter and terminator is in the opposite orientation, making it impossible to transcribe and translate the protein properly. Diagnostic restriction enzyme digestion is one of the techniques used to determine the orientation of the insert in the plasmid. Two different restriction enzymes are used to digest the plasmid DNA. One of the restriction enzymes must cleave the insert DNA, while the other must cleave the plasmid DNA. As a result, two fragments are generated, one of which is the original, unaltered plasmid, while the other is a plasmid containing the inserted DNA. The length of the fragment with the insert and the distance between the restriction enzyme cleavage site in the insert and the site in the plasmid will determine the insert's orientation in the plasmid. In conclusion, determining the insert's orientation in the plasmid is critical for efficient expression of the inserted gene. Therefore, it is best accomplished using two restriction enzymes, one that cuts once within the insert and the other that cuts once in the plasmid backbone.

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Q10 How does transferring the mating mixtures from YED to CSM-LEU-TRP plates allow us to select for diploids (i.e. why can only diploids survive on this media)? ( 2 )
Q11 What does the colour and growth of colonies on these plates suggest to you about the gde genotype and mating type of the strains X and Y ? Explain your answer. (6) Q12 Suggest two advantages that diploidy has over haploidy (for the organism concerned) Q13 Why do you think the ability of yeast to exist as haploid cells is an advantage to geneticists? ( 2 )

Answers

Transferring the mating mixtures from YED (yeast extract dextrose) plates to CSM-LEU-TRP (complete synthetic medium lacking leucine and tryptophan) plates allows us to select for diploids because the CSM-LEU-TRP plates lack these two essential amino acids, The color and growth of colonies on the CSM-LEU-TRP plates can provide information about the gde genotype and mating type of the strains X and Y.

Q10: Only diploid cells that have undergone mating and successfully fused their nuclei will have the ability to grow on CSM-LEU-TRP plates since they can complement each other's auxotrophic (deficient) mutations.

The diploid cells contain two copies of each gene, so if one copy carries a mutation causing an auxotrophy for leucine and the other copy carries a mutation causing an auxotrophy for tryptophan, the diploid cell will be able to grow on the CSM-LEU-TRP plates.

Q11: If the colonies on the plates appear white and exhibit good growth, it suggests that both strains carry functional copies of the GDE genes and are mating type "a" (or "α"). If the colonies appear pink or have reduced growth, it suggests that one or both of the strains have a mutation in the GDE genes or may have a different mating type.

Q12: Two advantages of diploidy over haploidy for the organism concerned (likely referring to yeast) are:

Genetic Redundancy: Diploid organisms have two copies of each gene, providing redundancy in case one copy contains a harmful mutation. This redundancy helps ensure that at least one functional copy of each gene is present in the organism, reducing the impact of deleterious mutations on survival and reproduction.Genetic Variation and Adaptability: Diploidy allows for the shuffling and recombination of genetic material through sexual reproduction. This increases genetic diversity within the population, enabling the organism to adapt and respond better to changing environmental conditions. The presence of two copies of each gene also allows for the exploration of different combinations of alleles, potentially leading to advantageous traits.

Q13: The ability of yeast to exist as haploid cells is advantageous to geneticists because it simplifies genetic analysis and manipulation. Haploid cells have a single copy of each gene, making it easier to study the effects of specific mutations or to introduce targeted genetic modifications.

Haploidy allows for straightforward genetic crosses and the isolation of pure genetic strains. Additionally, the presence of a single allele simplifies the interpretation of phenotypic traits, as the observed trait can be directly linked to a specific mutation or genetic change.

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Name the building block that makes up 40% of the plasma
membrane. (one word)

Answers

The building block that makes up 40% of the plasma membrane is phospholipids.

The plasma membrane is composed primarily of a bilayer of phospholipids. Phospholipids are a type of lipid molecule that consists of a hydrophilic (water-loving) head and two hydrophobic (water-repelling) tails. The hydrophilic heads face the aqueous environment both inside and outside the cell, while the hydrophobic tails are sandwiched between them, forming the interior of the membrane.

These phospholipids arrange themselves in a bilayer structure, with the hydrophilic heads oriented towards the aqueous surroundings and the hydrophobic tails facing inward. This arrangement creates a stable barrier that separates the cell's internal contents from the external environment, controlling the movement of substances in and out of the cell.

Due to their abundance and fundamental role in forming the plasma membrane, phospholipids make up a significant portion of it, accounting for approximately 40% of its composition. Other components of the plasma membrane include proteins, cholesterol, and various types of lipids, but phospholipids are the primary building blocks responsible for its structural integrity and selective permeability.

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Please make a prediction about how the following species could evolve in the future, based on current pressures:
- medium ground finch
- snake

Answers

However, based on current pressures, medium ground finch might adapt further to changes in food availability and habitat, while snakes could potentially evolve in response to changes in prey distribution or climate.

Pressures can have both positive and negative impacts on individuals. They can motivate and drive people to achieve their goals, pushing them to perform at their best. However, excessive or constant pressures can lead to stress, anxiety, and burnout. The pressure to succeed academically, professionally, or socially can create a significant burden on individuals, affecting their mental and physical well-being. It is important to find a balance and manage pressures effectively to maintain a healthy and fulfilling life. Seeking support, setting realistic expectations, and practicing self-care can help alleviate the negative effects of pressures.

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Assuming brown or blue eye color is determined by different alleles of a single gene. A woman with brown eye marries a man who also has brown eye color. Their daughter has blue eye color. The daughter then married to a man with blue eye color vision. What is the probability of the daughter's first child to have brown eye color?
50%
0%
100%
25%

Answers

The probability of the daughter's first child having brown eye color can be determined by considering the inheritance patterns of eye color alleles. The correct answer is option b.

If brown eye color is determined by a dominant allele and blue eye color is determined by a recessive allele, and both the daughter and her husband have blue eyes, it suggests that they both carry two copies of the recessive blue allele. In this case, the probability of their child inheriting the dominant brown allele from either parent would be zero, as neither parent possesses the brown allele.

Therefore, the probability of the daughter's first child having brown eye color would be 0%. However, it is important to note that eye color inheritance can be more complex and involve multiple genes, so this simplified explanation assumes a single gene model for eye color determination.

The correct answer is option b.

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Complete Question

Assuming brown or blue eye color is determined by different alleles of a single gene. A woman with brown eye marries a man who also has brown eye color. Their daughter has blue eye color. The daughter then married to a man with blue eye color vision. What is the probability of the daughter's first child to have brown eye color?

a. 50%

b. 0%

c. 100%

d. 25%

3) Staphylococcus aureus infections are know to cause: A. impetego B. Scalded skin syndrome C. Endocarditis D. All of these 4) Prions cause: A. Kuru B. Scrapie C.,boxine spongiform encephalopathy. D. All of the above 5) A sexually transmitted disease that is recurrent because of viral latency is. A chancroid B. Herpes C. Syphilis D gonorrhea E. PID 6) Pathogenicity of tetanus. Is due to: A. Exotoxin B. Endotoxin C.invasive action of the organism D. Collagenase activity 7) Disorders in w high pseudomonas aeruginosa has been implicated are: A. Infections in cystic. Fibrosis patients B. Conjunctivitis C. Burn sequelae Otis. Media E. Al of these D. 8) German measles is also termed: A. bubeloa B. Ribella C.variola D. Varicella 9) Which of the following are true: A. Attenuated whole agent vaccines can offer life long immunity B. Subunit vaccines produce the most side effects C. Toxin vaccines do not require boosters D. All of the above

Answers

1. Staphylococcus aureus infections can cause impetigo, scalded skin syndrome, and endocarditis.

2. Prions are responsible for causing diseases such as kuru, scrapie, and bovine spongiform encephalopathy (BSE).

3. Herpes is a sexually transmitted disease that can recur due to viral latency.

4. The pathogenicity of tetanus is due to the production of an exotoxin by the bacteria.

5. Pseudomonas aeruginosa has been implicated in various disorders, including infections in cystic fibrosis patients, conjunctivitis, burn sequelae, and otitis media.

6. German measles is also known as rubella.

7. Attenuated whole agent vaccines can provide long-lasting immunity, subunit vaccines may produce side effects, and toxin vaccines may require boosters.

1. Staphylococcus aureus is a bacterium known to cause multiple infections. It can lead to impetigo, a superficial skin infection, as well as scalded skin syndrome, a more severe blistering condition. Additionally, it can cause endocarditis, an infection of the inner lining of the heart.

2. Prions are abnormal proteins that can cause neurodegenerative diseases. Kuru is a prion disease transmitted through cannibalistic rituals, scrapie affects sheep and goats, and bovine spongiform encephalopathy (BSE), also known as "mad cow disease," affects cattle.

3. Herpes is a sexually transmitted infection caused by the herpes simplex virus (HSV). The virus establishes latency in nerve cells, leading to recurrent outbreaks of symptoms such as painful sores or blisters.

4. Tetanus is caused by the bacterium Clostridium tetani. Its pathogenicity is primarily due to the production of a neurotoxin called tetanospasmin, which affects the nervous system and leads to muscle stiffness and spasms.

5. Pseudomonas aeruginosa is a bacterium associated with various infections. It can cause infections in cystic fibrosis patients, including respiratory infections. It is also known to cause conjunctivitis (pink eye), otitis media (middle ear infection), and can contribute to burn wound infections and their sequelae.

6. German measles is another term for rubella, a viral infection characterized by a rash and fever. It is caused by the rubella virus and can cause complications, especially if contracted during pregnancy.

7. Attenuated whole agent vaccines, such as the measles, mumps, and rubella (MMR) vaccine, can provide long-lasting immunity. Subunit vaccines, which contain only specific parts of the pathogen, may produce fewer side effects compared to whole agent vaccines.

Toxin vaccines, such as the diphtheria and tetanus vaccines, may require periodic boosters to maintain immunity against the toxins produced by the pathogens.

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Statement 1: Dendritic cells are phagocytes with professional antigen-presenting properties Statement 2: Neutrophils circulate as part of the blood and act as surveillance to detect presence of pathogens O Statement 1 is true Statement 2 is false. O Statement 2 is true. Statement 1 is false. O Both statements are true. O Both statements are false points Statement 1: Fever is a sign of pathogen infection. Statement 2: Vasodilation is a type of immune response that can cause redness and swelling at the infection site. O Statement 1 is true. Statement 2 is false, O Statement 2 is true. Statement 1 is false. O Both statements are true. O Both statements are false Which of the following describes passive immunity? O vaccination for polio O allowing oneself to become infected with chicken pox O catching a common cold O antibodies transferred to the fetus from the mother across the placenta If Peter is allergic to peanuts and Paul is not, what is the precise molecular difference in Peter's bloodstream responsible for this? O Peter's blood has mast cells and basophils carrying IgEs that match an antigen on peanuts. Peter's blood has mast cells and basophils carrying IgGs that match an antigen on peanuts. O Peter's blood has mast cells and basophils carrying IgMs that match an antigen on peanuts O Peter's blood has mast cells and basophils carrying IgAs that match an antigen on peanuts Sive Answer 1 points Statement 1: The cell-mediated immune response is brought about by T cells Statement 2: In humoral immunity, some B cells become memory cells which are long-lived cells that can recognize an antigen that once already infected the body O Statement 1 is true. Statement 2 is false. Statement 2 is true. Statement 1 is false O Both statements are true Both statements are false.

Answers

Dendritic cells are phagocytes with professional antigen-presenting properties. Neutrophils circulate as part of the blood and act as surveillance to detect presence of pathogens.

The correct answer is that statement 1 is true and statement 2 is false. Fever is a sign of pathogen infection. Vasodilation is a type of immune response that can cause redness and swelling at the infection site. The correct answer is that both statements are true.

Passive immunity is antibodies transferred to the fetus from the mother across the placenta.The precise molecular difference in Peter's bloodstream responsible for this is Peter's blood has mast cells and basophils carrying IgEs that match an antigen on peanuts.

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SDS-PAGE can only efficiently separate proteins since:
- the pores of the polyacrylamide gel are smaller compared with
agarose gel
- DNA is more negative
- proteins are smaller compared with DNA
- SDS

Answers

SDS-PAGE can efficiently separate proteins because the pores of the polyacrylamide gel used in SDS-PAGE are smaller compared to an agarose gel, allowing for better resolution and separation of proteins based on their size and molecular weight.

SDS-PAGE (Sodium Dodecyl Sulfate-Polyacrylamide Gel Electrophoresis) is a widely used technique in molecular biology and biochemistry to separate proteins based on their molecular weight. It is a powerful tool due to several factors, one of which is the size of the pores in the gel matrix.

Polyacrylamide gels used in SDS-PAGE have smaller pore sizes compared to agarose gels, which are commonly used for separating nucleic acids like DNA. The smaller pore size of the polyacrylamide gel allows for more efficient separation of proteins. The proteins are forced to move through the gel matrix during electrophoresis, and their migration is impeded by the size of the pores. Smaller proteins can move more easily through the smaller pores, while larger proteins are hindered and migrate more slowly.

By applying an electric field, the proteins in the sample are separated based on their size and molecular weight. SDS (Sodium Dodecyl Sulfate) is a detergent used in SDS-PAGE that denatures the proteins and imparts a negative charge to them, making them move toward the positive electrode during electrophoresis. This further aids in the separation of proteins based on their molecular weight.

In summary, SDS-PAGE efficiently separates proteins due to the smaller pore size of the polyacrylamide gel, which allows for better resolution and separation based on size and molecular weight.

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Suppose you have a couple who are both heterozygous for BOTH albinism and sickle cell anemia. Use A and a for the albinism alleles, and T and t for the sickle cell alleles. (Technically, the sickle alleles are codominant, but since we’re interested in the disease rather than sickle trait, we’ll use dominant/recessive notation.)
What are the genotypes for the couple described above? Their phenotypes? Keep in mind that a genotype must include two alleles per genetic locus! (Phenotype will be albino or not albino and sickle cell anemia or healthy.)

Answers

The genotypes of the couple described are AaTt for the male and AaTt for the female. Their phenotypes will depend on whether they express the recessive traits or not.

For the couple described, the male is heterozygous for both albinism (Aa) and sickle cell anemia (Tt), and the female is also heterozygous for both traits (AaTt). The genotype for each individual includes two alleles per genetic locus.

In terms of phenotypes, the presence of the dominant allele (A) for albinism means that neither the male nor the female will express the albino phenotype. Therefore, their phenotype will be non-albino.

For sickle cell anemia, the presence of the recessive allele (t) is necessary for the expression of the disease. Since both individuals are heterozygous for the sickle cell trait (Tt), they will not have sickle cell anemia. Instead, their phenotype for sickle cell will be healthy or unaffected.

To summarize, the genotypes of the couple are AaTt, and their phenotypes are non-albino and healthy for sickle cell anemia.

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Signal transduction- yeast genetics
in one sentence, what does alpha factor in the WT 'a' cell do?
(In terms of cell cycle/budding and FUS1 transcription)

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In terms of cell cycle/budding and FUS1 transcription, the alpha factor in the WT 'a' cell induces the pheromone response pathway, leading to cell cycle arrest and activation of transcription factors that initiate FUS1 transcription.

In Saccharomyces cerevisiae, alpha factor is a peptide pheromone that activates a cell signaling pathway that controls mating and cell cycle progression. Alpha factor activates the G protein-coupled receptor, Ste2p, initiating a cascade of signal transduction events that result in the activation of the mitogen-activated protein kinase (MAPK) pathway. The pheromone response pathway results in cell cycle arrest and activation of transcription factors that initiate the transcription of mating-specific genes, including the FUS1 gene.

FUS1 encodes a protein involved in cell fusion and mating. The pheromone response pathway is a model system for studying signal transduction in yeast genetics, as many of the signaling proteins and pathways are conserved in higher eukaryotes.

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What is a shared derived characteristic for the stramenopiles?
What is a shared primitive characteristic for this group? How do
these differ from autopomorphies and synapomorpies?

Answers

The shared derived characteristic for the stramenopiles is the presence of two flagella. The presence of chlorophyll c, on the other hand, is a shared primitive characteristic of the stramenopiles.

A shared derived characteristic for the stramenopiles is the presence of two flagella.

One of the flagella has a smooth surface, while the other has fine, hair-like projections known as "straw-like" or "hairy" flagella. This unique flagellar arrangement is a distinguishing feature of the stramenopiles.

A shared primitive characteristic for the stramenopiles is the presence of chlorophyll c.

This type of chlorophyll pigment is also found in other algal groups. Chlorophyll c is considered primitive because it is a common feature among various algal lineages and not specific to the stramenopiles.

Stramenophiles are a specific group of organisms that share common characteristics, including the presence of two flagella with distinct structures. Autapomorphies are uniquely derived characteristics specific to individual taxa, while synapomorphies are shared derived characteristics that indicate common ancestry between multiple taxa.

Therefore, the shared derived characteristic and shared primitive characteristic for the stramenopiles is the presence of two flagella and chlorophyll c respectively.

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At values of Y (fractional saturation below 0,1 and
above 0,9, the slopes of Hill plots tend to a value of 1,
indicating an absence of cooperativity. True or False
SUPPORT YOUR ANSWER.

Answers

The statement "At values of Y (fractional saturation below 0,1 and above 0,9, the slopes of Hill plots tend to a value of 1, indicating an absence of cooperativity" is False.

The Hill plot is a linear plot with a log dose vs response curve. The Hill coefficient (nH) determines the degree of cooperativity in the Hill plot, which ranges from 0 to 1. If nH is equal to 1, there is no cooperativity; if nH is between 0 and 1, it indicates the degree of cooperativity.

The slope of the Hill plot at fractional saturation levels of less than 0.1 and greater than 0.9 is almost horizontal. At these limits, the concentration of binding sites on the protein is low.

The sites are almost entirely vacant at fractional saturation levels less than 0.1 and almost completely occupied at saturation levels greater than 0.9. As a result, the binding behavior at both ends is non-cooperative.

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The correct sequence of layers in the wall of the alimentary canal, from internal to external, is a.mucosa, muscularis, serosa, submucosa. b.submucosa, mucosa, serosa, muscularis. c.mucosa, submucosa, muscularis, serosa. d.serosa, muscularis, mucosa, submucosa.

Answers

The correct sequence of layers in the wall of the alimentary canal, from internal to external, is mucosa, submucosa, muscularis, serosa.

The correct option is C.

Mucosa, submucosa, muscularis, serosa.What is the alimentary canal?The alimentary canal is a muscular tube that begins at the mouth and extends through the pharynx, esophagus, stomach, small intestine, and large intestine to the anus. It is composed of four distinct layers of tissues that function together to perform digestion and absorption of nutrients from food.

These layers are referred to as mucosa, submucosa, muscularis, and serosa.The four layers of the alimentary canal are:Mucosa: The mucosa is the innermost layer of the alimentary canal. It is made up of three layers of tissues: the epithelium, the lamina propria, and the muscularis mucosae. It produces mucus, enzymes, and hormones that aid in digestion.Submucosa: The submucosa is the second layer of the alimentary canal. It is composed of connective tissues that contain blood vessels, nerves, and lymphatics. It also contains glands that produce mucus, enzymes, and hormones.

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a) Compare and contrast the basal states of glucocorticoid and retinoid X receptors and their activation mechanisms by their cognate steroid hormones which lead to gene transcription. (20 marks)

Answers

Glucocorticoid Receptor (GR) and Retinoid X Receptor (RXR) are both nuclear receptors that function as transcription factors.

Here is a comparison and contrast of their basal states and activation mechanisms:

Basal State:

Glucocorticoid Receptor (GR): In the absence of its ligand (e.g., cortisol), the GR resides in the cytoplasm as part of a multiprotein complex.

Retinoid X Receptor (RXR): RXR can exist in both the cytoplasm and the nucleus.

Activation Mechanisms:

Glucocorticoid Receptor (GR): Upon binding of cortisol (the cognate hormone), the GR undergoes a conformational change, leading to dissociation from HSPs.

Retinoid X Receptor (RXR): RXR can be activated by its cognate ligand, 9-cis retinoic acid (9-cis RA), or through heterodimerization with other nuclear receptors.

Gene Transcription:

Glucocorticoid Receptor (GR): Activation of the GR by cortisol leads to the recruitment of coactivators to the GREs on target genes.

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In contrast to Mitosis where the daughter cells are exact copies (genetically identical) of the parent cell, Meiosis results in genetically different cells, that will eventually also have the potential to create genetically unique offspring. But meiosis and mitosis are different in many other ways as well. Watch the videos and view the practical presentation. You will view stages of Meiosis in the Lily Anther EXERCISE 1: View the different stages of Meiosis occurring in the Lily Anther under the microscope. 1.1 Identify and draw Prophase I OR Prophase Il of Meiosis, as seen under the microscope. Label correctly (5) 1.2 What happens in Prophase I which does not occur Prophase II? (2) 1.3 Define: a. Homologous chromosome? (2) b. Synapsis (2) c. Crossing over (2) d. Chiasma (1) 1.4 Why is that siblings don't look identical to each other? (5)

Answers

Meiosis is the process in which genetically different cells are created, and they also have the potential to generate genetically unique offspring. The daughter cells produced in Mitosis are exact copies of the parent cell (genetically identical).

There are, however, several other distinctions between meiosis and mitosis. The stages of Meiosis in the Lily Anther are shown in the videos and the practical presentation.1.1 Prophase I of Meiosis, as seen under the microscope, is identified and sketched.

Correct labeling is done. 1.2 Unlike Prophase II, Prophase I involves synapsis and crossing over. 1.3 a. Homologous chromosomes are chromosomes that have similar genes, but they can carry distinct alleles. b. The pairing of homologous chromosomes is known as synapsis. c.

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Dehydration during exercise:
A. is dangerous if we lose 1-2% bodyweight
B. causes hyponatremia
C. may occur when runners are allowed to drink ad libidum
D. is a training technique to improve lactate t

Answers

Dehydration during exercise can have various consequences, including danger if a person loses 1-2% of their body weight, the possibility of hyponatremia. It is not a recommended training technique to improve lactate threshold.

Dehydration during exercise can have significant impacts on the body and athletic performance. It is important to maintain proper hydration levels to ensure optimal functioning of the body's physiological processes.

A. Losing 1-2% of body weight through dehydration during exercise can be dangerous. Even a small percentage of dehydration can lead to decreased performance, increased heart rate, impaired thermoregulation, and reduced blood volume, which can affect cardiovascular function and increase the risk of heat-related illnesses.

B. Hyponatremia is a condition characterized by low sodium levels in the blood. While dehydration typically involves a loss of body fluids, hyponatremia occurs when excessive water intake dilutes the sodium concentration in the blood. This can be a potential risk during prolonged exercise if individuals consume large amounts of water without adequate electrolyte replenishment.

C. Allowing runners to drink ad libitum means they can drink freely as desired. In some cases, athletes may drink excessively during exercise, leading to hyponatremia or overhydration. Proper guidance and monitoring of fluid intake are important to prevent dehydration and hyponatremia.

D. Dehydration is not considered a training technique to improve lactate threshold. Lactate threshold training typically involves structured workouts designed to increase the body's ability to tolerate and clear lactate during intense exercise. Adequate hydration is important during training to support optimal performance and recovery.

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True or False: A piece of silver can be cut indefinitely into pieces and still retain all of the properties of silver Al Truc. All particles, including subatomic particles that make up the element, possess the proporties of the element. B) True. Atoms are the smallest units of matter, are indivisible, and possess the properties of their element. C) False. Once the pieces are smaller than an atom of silver, the pieces no longer retain the properties of silver D) False. Silver atoms are too small to possess the properties of silver E) False. As a piece of silver is cut into smaller pieces, the atoms begin to take on the properties of smaller elements on

Answers

The statement "False. Once the pieces are smaller than an atom of silver, the pieces no longer retain the properties of silver" is the correct answer to this question.

Elements are made up of atoms that are identical in nature, including their physical and chemical properties. This is valid for silver as well. A silver atom can be cut into several pieces and still maintain its silver properties.

However, once the pieces are reduced to less than one silver atom, they lose their chemical properties as they no longer have the silver properties.

Once the pieces are smaller than an atom of silver, the pieces no longer retain the properties of silver.

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You have isolated a microbe from the soil and sequenced its genome. Please discuss how you could use the sequence information to identify the organism and establish if it is a prokaryotic or eukaryotic microorganisms

Answers

To identify the organism and establish whether it is a prokaryotic or eukaryotic microorganism after isolating a microbe from the soil and sequencing its genome, the following steps could be taken: Assemble the genome sequencing reads into a contiguous sequence (contig).

Contigs are produced by sequencing the DNA multiple times and assembling the resulting DNA sequences together. During this process, overlapping regions are identified and used to construct a single continuous DNA sequence.Step 2: Using a genome annotation software, a genome annotation is made. The annotation process identifies genes and noncoding sequences, predicts gene function, and assigns them to functional classes. Gene identification can help determine whether the organism is prokaryotic or eukaryotic.

Comparison of the genome sequence with sequences of known organisms in a database. The comparison of genome sequences is commonly used to identify microbes, as sequence similarity is an indicator of evolutionary relatedness. In the case of eukaryotes, a comparison of gene sequences can also be used to identify and classify organisms.Another way of establishing whether an organism is prokaryotic or eukaryotic is by looking at the organization of the genome. Prokaryotic genomes are generally simpler in their organization, with no nucleus or organelles, and they have a circular chromosome. Eukaryotic genomes, on the other hand, are usually larger and more complex, with multiple chromosomes, a nucleus, and various organelles such as mitochondria, chloroplasts, and endoplasmic reticulum.

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The heterozygous jiggle beetles represents pleiotropy. O polygenic. O incomplete dominance. codominance. complete domiance. Question 40 What can be concluded about the green allele and hot pink allele. O The green allele is recessive and the hot pink allele is dominant. O The green allele and pink allele are recessive. O The green allele is dominant and the hot pink allele is recessive. O The green allele and pink allele are dominant.

Answers

The green allele is recessive, and the hot pink allele is dominant in the case of the heterozygous jiggle beetles.

Based on the information provided, we can conclude that the green allele is recessive, and the hot pink allele is dominant. Pleiotropy refers to a single gene having multiple effects on an organism, which is not evident from the given context. Polygenic inheritance involves multiple genes contributing to a trait, which is also not mentioned in the scenario. Incomplete dominance occurs when neither allele is completely dominant over the other, resulting in an intermediate phenotype in heterozygotes. Codominance occurs when both alleles are expressed equally in the phenotype of heterozygotes. Complete dominance occurs when one allele is completely dominant over the other, resulting in the expression of only one allele in the phenotype of heterozygotes.

Since the scenario states that the beetles are heterozygous, meaning they carry two different alleles, we can deduce that the hot pink allele must be dominant because it is expressed in the phenotype. The green allele, on the other hand, is recessive because it remains unexpressed in the presence of the dominant hot pink allele. Therefore, the correct conclusion is that the green allele is recessive, and the hot pink allele is dominant.

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