A mutation that changes a GC base pair to AT is a(n): 1) synonymous mutation. 2) transition. 3) transversion, 4) missense mutation. 5) induced mutation.

Answers

Answer 1

In genetics, a mutation refers to a change in the DNA sequence of a gene. A mutation that changes a GC base pair to AT is a transversion.

Mutations can occur in various ways, including substitutions, insertions, deletions, and inversions. One type of mutation is a base substitution, which involves the replacement of one nucleotide base with another.

When a mutation changes a GC base pair to AT, it is classified as a transversion. Transversions are a specific type of base substitution mutation where a purine (adenine or guanine) is replaced by a pyrimidine (thymine or cytosine) or vice versa. In this case, the GC base pair (guanine-cytosine) is changed to an AT base pair (adenine-thymine), representing a transversion mutation.

It is important to note that transversions are distinct from transitions, which involve the substitution of a purine for another purine or a pyrimidine for another pyrimidine. In this scenario, since the substitution involves different types of bases (a purine to a pyrimidine), it is categorized as a transversion rather than a transition.

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Related Questions

rDNA O when 2 different DNA from two different species are joined together
O example human insulin gene placed in a bacterial cell O DNA is copied along with bacterial DNA O Proteins are then made known as recombinant proteins. O All of the above •

Answers

All of the statements mentioned about DNA and recombinant DNA are correct.

The correct answer is: All of the above.

What occurs in the DNA combination?

When two different DNA from two different species are joined together, several processes occur:

The human insulin gene, for example, can be placed in a bacterial cell. This is achieved through genetic engineering techniques such as gene cloning or recombinant DNA technology.

The DNA containing the human insulin gene is copied along with the bacterial DNA through DNA replication. This ensures that the foreign DNA is replicated along with the host DNA during cell division.

Once the recombinant DNA is present in the bacterial cell, the cell's machinery translates the genetic information into proteins. In the case of the human insulin gene, the bacterial cell will produce insulin proteins using the instructions provided by the inserted gene. These proteins are known as recombinant proteins.

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What is the major constraint of using the body surface for external exchange? A. Using the body surface for respiration prevents the animal being camouflaged
B. As animals get bigger their surface area to volume ratio gets smaller C. It is impossible to keep the body surface moist D.Using the body surface for respiration requires special hemoglobin E. Animals that use their body surface to respire must move quickly to ensure sufficient gas exchange

Answers

The major constraint of using the body surface for external exchange is that, as animals get bigger, their surface area to volume ratio gets smaller.

As the size of an animal increases, the ratio of surface area to volume decreases. This is because volume increases more quickly than surface area. As a result, larger animals have less surface area relative to their size than smaller animals. The body surface is the outer covering of an organism, which is responsible for the exchange of gases and nutrients with the surrounding environment.

The body surface is a common site of gas exchange in many animals, including insects, earthworms, and fish. Animals that respire through their body surface are known as cutaneous respirators.

The correct answer is B. As animals get bigger, their surface area to volume ratio gets smaller.

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Microtubules are «dynamically unstable».
What is dynamic instability, and what does this mean for the function of the microtubules?
Explain the mechanism behind this process.

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Microtubules are the largest elements of the cytoskeleton, which are composed of protein polymers that are intrinsically polar and assembled by the regulated polymerization of α- and β-tubulin heterodimers.

Microtubules are highly dynamic, which means that they are continuously being generated and broken down. This process is referred to as dynamic instability.

Dynamic instability is a mechanism that explains the dynamic behaviour of microtubules. The term dynamic instability is a description of the way in which microtubules change shape over time.

It means that microtubules are constantly shifting and changing shape, breaking down and reforming in a process that is dependent on the activity of the microtubule network.

Microtubules are able to undergo dynamic instability because of their unique composition. Each microtubule is made up of multiple tubulin subunits that are arranged in a spiral pattern.

This arrangement creates a structure that is both strong and flexible, allowing the microtubules to bend and twist in response to changes in the cell environment.

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Which integument layer has the greatest capacity to retain fluid
?

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The integumentary system is composed of the skin, hair, nails, and glands. Its main function is to protect the body from damage and external elements. The skin is the largest organ in the body, and it is composed of three layers: the epidermis, dermis, and subcutaneous layer.

The epidermis is the outermost layer of the skin and is composed of dead cells that are constantly being shed. The dermis is the middle layer of the skin and is composed of connective tissue, blood vessels, and nerves. The subcutaneous layer is the innermost layer of the skin and is composed of fat, connective tissue, and blood vessels.The subcutaneous layer has the greatest capacity to retain fluid. This layer is made up of adipose tissue, which is composed of fat cells. These fat cells can absorb and store large amounts of fluid. This helps to protect the body from dehydration and helps to regulate body temperature.In addition to its role in fluid retention, the subcutaneous layer also provides insulation and protection for the body.

Overall, the integumentary system plays an essential role in protecting the body and maintaining homeostasis.

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1.
Statement 1: Dendritic cells are phagocytes with professional antigen-presenting properties.
Statement 2: Neutrophils circulate as part of the blood and act as surveillance to detect presence of pathogens.
A) Statement 1 is true. Statement 2 is false.
B) Statement 2 is true. Statement 1 is false.
C) Both statements are true.
D) Both statements are false.
2. Histamine is a signaling molecule that plays a significant role in regulating immune responses such as during allergic reactions and inflammation. It causes blood vessels to dilate and become more permeable so that white blood cells can immediately reach the site of injury, damage, or infection. What types of white blood cells can release histamine?
A) basophils and mast cells
B) B cells and T cells
C) dendritic cells
D) neutrophils
3. What molecules are released by activated helper T cells?
A) immunoglobulins
B) antigen
C) cytokines
D) histamine

Answers

1. The correct answer is A) Statement 1 is true. Statement 2 is false. Dendritic cells are indeed phagocytes with professional antigen-presenting properties,

Whereas neutrophils are primarily known for their role in phagocytosis and are not considered professional antigen-presenting cells.

2. The correct answer is A) basophils and mast cells. Basophils and mast cells are types of white blood cells that can release histamine. Histamine release by these cells is associated with allergic reactions and inflammation.

3. The correct answer is C) cytokines. Activated helper T cells release cytokines, which are signaling molecules that play a critical role in coordinating and regulating immune responses.

Immunoglobulins are antibodies produced by B cells, while antigen is the target of an immune response. Histamine is released by basophils and mast cells, as mentioned in the previous question.

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Which statement about Mitosis is correct?
At the end of mitosis there is four different daughther cells
At the end of mitosis there is four identical daughther cells
At the end of mitosis there is two different daughther cells
At the end of mitosis there is two identical daughther cells

Answers

The correct statement about mitosis is that (D) at the end of mitosis, there are two identical daughter cells. During mitosis, the replicated chromosomes align and separate, ensuring that each daughter cell receives a complete set of chromosomes.

Mitosis is a process of cell division in which a single cell divides into two identical daughter cells.

This process occurs in various stages, including prophase, metaphase, anaphase, and telophase. At the end of telophase, the cytoplasm divides through cytokinesis, resulting in the formation of two separate cells.

These daughter cells contain the same genetic information as the parent cell and are identical to each other. Mitosis plays a crucial role in growth, tissue repair, and asexual reproduction in organisms.

Therefore, (D) at the end of mitosis, there are two identical daughter cells is the correct answer.

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A woman and her husband both show the normal phenotype for pigmentation, but each had one parent who was an albino. Albinism is an autosomal recessive trait. If their first two children have normal pigmentation, what is the probability that their third child will be an albino?

Answers

The given information states that both the husband and the wife are phenotypically normal but they each had one albino parent.

we can assume that both parents are phenotypically carriers for the recessive trait of albinism.

A dominant trait is the one that masks the effects of the other gene whereas, the recessive trait is the one that remains masked in the presence of the dominant trait.

Thus, to inherit an autosomal recessive trait, both the parents must be carriers or must be affected by the trait.

Using a Punnett square, let us determine the genotypes of the parents.

Let A denote the dominant allele for normal pigmentation and for the recessive allele of albinism.

Wife's genotype:

Aa (phenotypically normal)

Husband's genotype:

Aa (phenotypically normal)

In this case, the Punnett square will look like the following:

[tex]AA| Aa |Aa Aa| Aa |aa[/tex]

The probability that the third child will be an albino is 25% or 1/4.

the probability that their third child will be an albino is 1/4 or 25%.

Hence, the required probability is 25%.

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Giantism is a consequence of O Production of T4 above the normal O Production of GH after puberty above the normal O Production of GH above the normal after birth and before puberty O Production of Gn

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Gigantism is a consequence of excessive production of growth hormone (GH) before the closure of growth plates.

Growth hormone is responsible for stimulating the growth and development of bones and tissues. In cases of gigantism, there is an overproduction of GH by the pituitary gland, usually due to a benign tumor called pituitary adenoma. This excess GH is released into the bloodstream and stimulates the growth plates in the long bones, leading to excessive linear growth.

Gigantism typically occurs before the closure of the growth plates, which happens during puberty. If excessive GH production occurs after the growth plates have closed, it leads to a different condition called acromegaly, characterized by enlargement of the bones and soft tissues, rather than an increase in height.

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Discuss the role of the autonomic nervous system in controlling the body’s
functions.Your response should discuss both the sympathetic and the
parasympathetic divisions. Your response sho

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The autonomic nervous system (ANS) plays a crucial role in controlling the body's functions and maintaining homeostasis. It consists of two main divisions: the sympathetic and the parasympathetic nervous systems.

The sympathetic division of the ANS is responsible for the body's "fight-or-flight" response during stressful or emergency situations. When activated, it prepares the body for intense physical activity or response to a threat. The sympathetic division increases heart rate, dilates the airways, stimulates the release of stress hormones like adrenaline, and redirects blood flow to vital organs and skeletal muscles. This division helps mobilize energy resources, enhances alertness, and heightens overall physical performance.

On the other hand, the parasympathetic division is responsible for the body's "rest-and-digest" response. It promotes relaxation, conserves energy, and supports normal bodily functions during non-stressful situations. The parasympathetic division decreases heart rate, constricts the airways, stimulates digestion, and promotes nutrient absorption. It also helps maintain normal blood pressure, supports sexual arousal, and aids in the elimination of waste materials.

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Question 47 Not yet graded / 7 pts Part C about the topic of nitrogen. The nucleotides are also nitrogenous. What parts of them are nitrogenous? What are the two classes of these parts? And, what are

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Nitrogenous refers to the presence of nitrogen in a molecule. Nucleotides are also nitrogenous.

Nucleotides have three parts: nitrogenous base, sugar, and phosphate. The nitrogenous base of a nucleotide is nitrogenous.

The two classes of these nitrogenous bases in nucleotides are purines and pyrimidines.

Purines are nitrogenous bases that contain two rings.

Adenine (A) and guanine (G) are examples of purines.

Pyrimidines are nitrogenous bases that contain one ring.

Cytosine (C), thymine (T), and uracil (U) are examples of pyrimidines.

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1 pts Arrange the following correct sequence of events during exhalation: 1. Air (gases) flows out of lungs down its pressure gradient until intrapulmonary pressure is 0 (equal to atmospheric pressure

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Air flows out of the lungs during bin the following correct sequence of events:

1. Contraction of the diaphragm and external intercostal muscles reduces intrapleural pressure.

2. Decreased intrapleural pressure causes the lungs to recoil, compressing the air within the alveoli.

3. The compressed air flows out of the lungs down its pressure gradient until intrapulmonary pressure is 0, equal to atmospheric pressure.

During exhalation, the primary muscles involved are the diaphragm and the external intercostal muscles. These muscles contract, causing the volume of the thoracic cavity to decrease. As a result, the intrapleural pressure within the pleural cavity decreases. The decreased intrapleural pressure leads to the recoil of the elastic lung tissue, which compresses the air within the alveoli.

As the volume of the thoracic cavity decreases, the pressure within the alveoli increases. This increased pressure creates a pressure gradient between the lungs and the atmosphere. The air naturally flows from an area of higher pressure (within the lungs) to an area of lower pressure (outside the body) until the pressures equalize. This process continues until the intrapulmonary pressure reaches 0, which is equal to atmospheric pressure.

Overall, the sequence of events during exhalation involves the contraction of the diaphragm and external intercostal muscles, the recoil of the lungs, and the resulting flow of air out of the lungs down its pressure gradient until the intrapulmonary pressure matches the atmospheric pressure.

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QUESTION 25 Which of following does NOT secrete a lipase? a. the salivary glands
b. the stomach c.the small intestine d. the pancreas
QUESTION 26 Which of the following is the correct sequence of regions of the small intestine, from beginning to end? a. Ileum-duodenum -jejunum b. Duodenum-ileum -jejunum c. Ileum-jejunum - duodenum
d. Duodenum-jejunum - ileum QUESTION 27 Accessory organs of the digestive system include all the following except. a. salivary glands b. teeth.
c. liver and gall bladder d.adrenal gland QUESTION 28 The alimentary canal is also called the. a. intestines b.bowel c. gastrointestinal (Gl) tract
d. esophagus
QUESTION 29 The tube that connects the oral cavity to the stomach is called the a. small intestine b. trachea c.esophagus d.oral canal

Answers

In this set of questions, to identify the option that does NOT secrete a lipase, the correct sequence of regions in the small intestine, the organs that are considered accessory organs of the digestive system.

In question 25, the correct answer is option a. the salivary glands. Salivary glands secrete amylase to initiate the digestion of carbohydrates but do not secrete lipase.

In question 26, the correct answer is option b. Duodenum-ileum-jejunum. The correct sequence of regions in the small intestine, from beginning to end, is duodenum, jejunum, and ileum.

In question 27, the correct answer is option d. adrenal gland. Accessory organs of the digestive system include the salivary glands, teeth, liver, and gallbladder. The adrenal gland is not directly involved in the digestive process.

In question 28, the correct answer is option c. gastrointestinal (GI) tract. The alimentary canal, or the digestive tract, is also referred to as the gastrointestinal tract.

In question 29, the correct answer is option c. esophagus. The tube that connects the oral cavity to the stomach is called the esophagus, which serves the purpose of transporting food from the mouth to the stomach.

Overall, these questions cover various aspects of the digestive system, including secretions, anatomical sequences, and organs classification. Understanding these concepts is essential for comprehending the process of digestion and the functions of different components of the digestive system.

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Pedigrees and Mendelian inheritance
In Labrador retrievers, coat color is controlled by two genes, one that determines whether pigment is deposited in the hair and one that controls the color of the pigment. The first gene has two alleles, one for black pigment and one for brown (chocolate) pigment. The black allele is dominant. The alleles at the second gene determine if the pigment is deposited in the fur of the animal. If the dog has two recessive alleles at this locus, no pigment will be deposited in the fur and the dog will be a yellow lab. If the dog has at least one dominant allele at this locus and at least one black pigment allele, they will be a black lab. If the dog has two brown alleles and at least one dominant allele at the second locus, they will be a chocolate lab.
Take a deep breath. You’ve got this. The information you have in the problem is:
The structure of the pedigree through the naming of individuals (the pedigree is already drawn for you)
How the inheritance of coat color works in Labrador retrievers
The phenotype of the individuals in the pedigree
The steps you need to take to solve it:
Assign phenotypes to every dog Figure out the genotype for the color deposition locus – use D/d to indicate whether the color is deposited/not deposited
Figure out the genotype for the pigment locus – use B/b to indicate Black allele/brown allele
Using the pedigree below, fill in the genotypes and phenotypes in the table following the pedigree for the family of Labrador retrievers. Mom and Dad are indicated for you. If a genotype is indeterminate, use a dash (-). Once you have done that, use that information to answer the questions below.
Family: Leia, the mom, is a black lab. Han, the dad, is a brown lab. Leia’s father is a black lab, and her mother is a black lab, both heterozygous for the color deposition locus and the pigmentation locus. Han’s father is a yellow lab from a homozygous black father and brown mother. Han’s mother is a brown lab from two brown labs that are homozygous for the color deposition gene. Leia and Han have three puppies: one female brown lab named Jaina, one male black lab called Jacen, and one male yellow lab named Ben.

Answers

Phenotypes of all the dogs were identified and genotypes of the color deposition locus and pigmentation locus of each dog were assigned. With the help of this information, the genotypes and phenotypes of Leia and Han’s puppies were found.

Phenotypes of all the dogs were identified and genotypes of the color deposition locus and pigmentation locus of each dog were assigned. In the color deposition locus, D/d was used to indicate whether the color is deposited/not deposited. In the pigmentation locus, B/b was used to indicate Black allele/brown allele. With the help of this information, the genotypes and phenotypes of Leia and Han’s puppies were found. The genotypes and phenotypes of the puppies are as follows:Jaina, the female brown lab: bbD/-Jacen, the male black lab: BbD/-Ben, the male yellow lab: bbdd.

Therefore, the conclusions that can be drawn from the given information are that Leia and Han are heterozygous for the color deposition and pigmentation locus. Their puppies have different genotypes and phenotypes for the color deposition and pigmentation locus. The brown puppy has the genotype bbD/-, black puppy has BbD/-, and the yellow puppy has the genotype bbdd.

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One way of identifying a drug target in a complex cellular extract is to use an affinity approach, i.e. fix the drug to a resin (agarose etc) and use it to "pull down "" the target from the extract. What potential problems do you think may be encountered with attempting this approach?

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One way of identifying a drug target in a complex cellular extract is by using an affinity approach which involves fixing the drug to a resin such as agarose. The target is then "pulled down" from the extract.

However, this approach may encounter some potential problems such as:

Non-specific binding: The drug resin could bind to other molecules that are unrelated to the target protein, leading to inaccurate results.Difficulty in obtaining a pure sample: Even though the target molecule could bind to the drug resin, other proteins and molecules can also bind which makes it challenging to obtain a pure sample.Low Abundance Targets: In a complex cellular extract, the target molecule may exist in low abundance and the signal might not be strong enough to detect, making it difficult to pull down.Biochemical Incompatibility: The drug and the resin may not be compatible with the target, thus it may not bind or bind weakly which means the target protein might not be able to be pulled down.

Therefore, while the affinity approach is a very useful and important method for drug target identification, it also has its limitations and potential problems that need to be considered.

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In some insect species the males are haploid. What process (meiosis or mitosis) is used to produce gametes in these males?
Wiskott-Aldrich Syndrome (WAS) is an X-linked disorder characterized by low platelet counts, eczema, and recurrent infections that usually kill the child by mid childhood. A woman with one copy of the mutant gene has normal phenotype but a woman with two copies will have WAS. Select all that apply: WAS shows the following
Pleiotropy
Overdominance
Incomplete dominance
Dominance/Recessiveness
Epistasis

Answers

In some insect species, the males are haploid, and mitosis is used to produce gametes in these males. Wiskott-Aldrich Syndrome (WAS) shows Dominance/Recessiveness.

In some insect species, the males are haploid. Mitosis is used to produce gametes in these males. This is because mitosis is the type of cell division that occurs in somatic cells. It results in the production of two identical daughter cells with the same chromosome number as the parent cell. Meiosis, on the other hand, is the type of cell division that occurs in germ cells. It results in the production of four genetically diverse daughter cells with half the chromosome number of the parent cell.Therefore, mitosis is used to produce gametes in male haploid insect species.

.Wiskott-Aldrich Syndrome (WAS) shows the Dominance/Recessiveness. Dominant alleles are those that determine a phenotype in a heterozygous (Aa) or homozygous (AA) state. Recessive alleles determine a phenotype only when homozygous (aa). In the case of WAS, a woman with one copy of the mutant gene has a normal phenotype because the normal gene can mask the effect of the mutant gene. However, a woman with two copies of the mutant gene will have WAS because the mutant gene is now in a homozygous state. Therefore, the mutant allele is recessive to the normal allele.

In some insect species, the males are haploid, and mitosis is used to produce gametes in these males. Wiskott-Aldrich Syndrome (WAS) shows Dominance/Recessiveness.

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Which of the following three
conditions contribute to the Hardy-Weinberg Equilibrium?
a.
No selection of one individual over
another, stable environment, non-random mating
b.
No select

Answers

Thus, option (d) is the correct choice While non-random mating can disturb the Hardy-Weinberg equilibrium, it is not one of the three conditions that contribute to the equilibrium.

The model provides a theoretical foundation for studying genetic variation in a population.

These are random mating, no mutation, no gene flow (immigration or emigration), large population size, and no selection. The three conditions that contribute to the Hardy-Weinberg Equilibrium are no selection of one individual over another, no migration, and stable environment.

Thus, option (d) is the correct choice While non-random mating can disturb the Hardy-Weinberg equilibrium, it is not one of the three conditions that contribute to the equilibrium.

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1. Write all the factors that determine the amount of
protein synthesis.
2. Write all the factors that affect the function of
protein.

Answers

Proteins are essential macromolecules that play diverse roles in the structure, function, and regulation of cells and organisms. Protein synthesis is the cellular process through which proteins are produced, involving the transcription of DNA into mRNA and the translation of mRNA into a polypeptide chain, which then folds into a functional protein.

1. Factors that determine the amount of protein synthesis:

Availability of amino acidsEnergy supplyTranscription factorsRibosomes and tRNAsCo- and post-translational modificationsEnvironmental factors (such as temperature, pH, etc.)The rate of protein breakdown and degradationRegulatory proteins and microRNAs

2. Factors that affect the function of protein:

Environmental factors such as temperature, pH, and salt concentrationPost-translational modificationsOther proteins, such as chaperonesMembrane compositionLipid binding.

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Submit your answer to this question in order to open week 5 lessons page. Complete the table: Cellular location Cellular location Uses Main products produced at the Process in prokaryotic in eukaryotic oxygen cells cells end Glycolysis Intermediate step (prep for Krebs cycle) Krebs cycle Aerobic electron transport chain

Answers

The table compares the cellular locations, uses, and main products produced at various stages of cellular respiration in prokaryotic and eukaryotic cells.

In prokaryotic cells, glycolysis occurs in the cytoplasm, where glucose is converted into pyruvate, producing a small amount of ATP and NADH. The intermediate step, also known as the preparatory step for the Krebs cycle, takes place in the cytoplasm as well, where pyruvate is converted into acetyl-CoA.

In eukaryotic cells, glycolysis also occurs in the cytoplasm, generating ATP and NADH from glucose. However, the intermediate step takes place in the mitochondria, where pyruvate is transported and converted into acetyl-CoA.

The Krebs cycle, also known as the citric acid cycle or the tricarboxylic acid cycle (TCA cycle), takes place in the mitochondrial matrix of both prokaryotic and eukaryotic cells. It generates high-energy molecules such as NADH, FADH2, and ATP through a series of enzymatic reactions.

The aerobic electron transport chain, which is the final stage of cellular respiration, occurs in the inner mitochondrial membrane of eukaryotic cells and the plasma membrane of prokaryotic cells. It involves the transfer of electrons from NADH and FADH2 to oxygen, generating a large amount of ATP through oxidative phosphorylation.

Overall, cellular respiration is a crucial metabolic process in both prokaryotic and eukaryotic cells, enabling the production of ATP and the efficient utilization of energy from glucose in the presence of oxygen.

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Homologous DNA recombination:
A)Requires 5'-end generation at double-stranded DNA breaks
B)Occurs at the tetrad stage during meiosis
C)Is responsible for transposon movement in human cells
D)Repairs mutations caused by deamination events
E)Inverts DNA sequences as a mechanism to regulate genes

Answers

Homologous DNA recombination repairs mutations caused by deamination events. The correct option is (D).

Homologous recombination is the exchange of genetic information between two DNA molecules with high sequence similarity. This can occur during normal DNA replication in dividing cells, but the process is usually regulated to ensure that accurate copies are made and the genome remains stable.

During homologous recombination, a broken DNA molecule is repaired using a template DNA molecule that has the same or very similar sequence. The two DNA molecules are aligned, and sections are swapped between the two, resulting in a complete, unbroken DNA molecule.

A mutation is a change in DNA sequence that may occur naturally or be induced by external factors such as radiation, chemicals, or other environmental agents. Deamination is a type of mutation that can occur when a nitrogenous base is changed to a different base through the removal of an amine group. For example, cytosine can be deaminated to uracil, which is normally found only in RNA. If this change occurs in a DNA molecule, it can lead to problems with replication and transcription, which may result in genetic disorders or diseases.

Homologous recombination can be used to repair mutations caused by deamination events by providing a template DNA molecule with the correct sequence. When a broken DNA molecule is repaired using homologous recombination, the template DNA molecule is used to fill in the missing or damaged sections of the broken DNA molecule. This ensures that the correct sequence is restored, and any mutations caused by deamination or other factors are repaired.

Thus, the correct option is D.

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Question 13 0.05 pts Which of the following mechanisms produces the MOST diversity in T cell receptors? imprecise joining of VDJ segments O having multiple V region segments from which to choose somatic hypermutation having multiple C region gene segments from which to choose Question 17 0.05 pts Which statement BEST DESCRIBES the function of the C3 component of complement? It forms part of a convertase on the bacteria and is recognized by neutrophils through the receptor CR1. It binds to antibody Fc that are bound to the surface of the bacteria. It initiates the end-stage of complement to form part of the Membrane Attack Complex (MAC). O It initiates the extrinsic pathway of coagulation

Answers

13. Imprecise joining of VDJ segments. The answer 1 is correct.

20. IgE and mast cells. The option 4 is correct.

17. It initiates the end-stage of complement to form part of the Membrane Attack Complex (MAC). The option 3 is correct.

Question 13: The mechanism that produces the MOST diversity in T cell receptors is the "imprecise joining of VDJ segments." This process involves the rearrangement of variable (V), diversity (D), and joining (J) gene segments during T cell development.

Question 20: An inflammatory response that occurs immediately upon exposure to antigen is MOST LIKELY to be mediated by "IgE and mast cells." IgE antibodies are specialized immunoglobulins that are involved in allergic and immediate hypersensitivity reactions.

Upon exposure to an antigen, IgE antibodies bind to mast cells, which are present in tissues throughout the body.

Question 17: The function of the C3 component of complement is BEST DESCRIBED by the statement "It initiates the end-stage of complement to form part of the Membrane Attack Complex (MAC)." The complement system is a part of the innate immune response and plays a crucial role in host defense against pathogens.

C3 is a central component of the complement cascade. Activation of C3 leads to the formation of C3 convertase, which cleaves C3 into C3a and C3b.

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7. A small section of bacterial enzyme has the amino acid sequence arginine, threonine, alanine, and isoleucine. The tRNA anticodons for the amino acid sequence shown above is A. GCA UGA CGA UAC B. UCU UGG CGC UAU C. UCG UGU CGU UAG D. GCG UGC CCC UAA

Answers

The answer to the given question is option B. Bacteria are microscopic organisms that have various shapes, sizes, and physiological characteristics. Bacterial enzymes are proteins that catalyze biochemical reactions in bacteria.

The amino acid sequence of bacterial enzymes can be determined using various methods such as X-ray crystallography, nuclear magnetic resonance spectroscopy, and mass spectrometry.The tRNA anticodons for the amino acid sequence shown above is UCU UGG CGC UAU. The tRNA anticodons are complementary to the mRNA codons, and they carry the amino acids to the ribosomes during translation.Main answer in 3 lines: The tRNA anticodons for the amino acid sequence shown above is UCU UGG CGC UAU. The amino acid sequence of bacterial enzymes can be determined using various methods such as X-ray crystallography, nuclear magnetic resonance spectroscopy, and mass spectrometry. Bacterial enzymes are proteins that catalyze biochemical reactions in bacteria.

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STATION 3 - SALTATORIAL VERTEBRATES (kangaroos, kangaroo rats,
gerbils, jerboas, tarsiers, frogs)
3e. How has the trunk of frogs become shorter (1 mark)? What is
the adaptive advantage?
3b. What is th

Answers

STATION 3 - SALTATORIAL VERTEBRATES (kangaroos, kangaroo rats, gerbils, jerboas, tarsiers, frogs)3e. The trunk of frogs has become shorter in order to achieve a more advanced way of jumping.

The shorter trunk increases the efficiency of the jump, as it makes the body more compact, and lessens the weight of the hind legs as the frog moves in the air. The shorter trunk of the frog also provides an advantage by enabling it to move easily and smoothly through the water, as the decreased drag allows it to swim faster.

Saltatorial is a type of locomotion that involves hopping or jumping, and it is one of the most energy-efficient ways of getting around for the animals that use it. The kangaroo rat is one of the most notable examples of a saltatorial vertebrate, and it has evolved a number of adaptations to suit its jumping lifestyle.

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Examination of a child revealed some whitish spots looking like coagulated milk on the mucous membrane of his cheeks and tongue. Analysis of smears revealed Gram-positive oval yeast-like cells. Which of the following causative agents are they?
A. Candida
D. Corynebacteria diphtheria
B. Fusobacteria
E. Staphylococci
C. Actinomycetes
An 18-year old patient has enlarged lymphnodes. They are painless, thickened on palpation. In the area of oral mucous membrane there is a smallsized ulcer with theckened edges and "laquer" bottom of greyish colour. Which of the following diseases is the most probable diagnosis?
A. Syphilis
D. Gonorrhea
B. Candidiasis
E. Tuberculosis
C. Scarlet fever

Answers

The causative agents of the disease are Candida.The symptoms described in the question indicate oral candidiasis, which is also known as thrush. The presence of whitish spots on the mucous membranes of the cheeks and tongue is a common sign of thrush. Gram-positive oval yeast-like cells were detected during smear analysis, which indicates that the causative agent is a type of yeast-like fungus.

Candida is the most probable causative agent, as it is the most common cause of oral thrush.Answer: A. CandidaExplanation:Oral candidiasis, or thrush, is a fungal infection of the mouth that is caused by the fungus Candida. It typically appears as white or cream-colored spots on the tongue, gums, and other areas of the mouth. The condition is most common in infants and older adults, as well as people with weakened immune systems. It can also occur in people who take antibiotics or use certain types of inhalers for asthma or other respiratory conditions.In the second case, the most probable diagnosis is Syphilis.

Syphilis is a sexually transmitted disease caused by the bacterium Treponema pallidum. It is characterized by a series of stages, each with its own set of symptoms. The primary stage is characterized by the appearance of a painless ulcer at the site of infection. The ulcer may be accompanied by swollen lymph nodes. Without treatment, the disease can progress to the secondary and tertiary stages, which can cause serious health problems.

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36. Which film composer is considered to be a pioneer in the use
of digital synthesizers, electronic keyboards, and the latest
computer technology?
Hugo Blowdorn
Harry Lovelog
Elmer Earplug
Manny Fli

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Hans Zimmer is considered to be a pioneer in the use of digital synthesizers, electronic keyboards, and the latest computer technology in film composition. Throughout his career, Zimmer has pushed the boundaries of music production by incorporating innovative and cutting-edge technologies into his work.

Zimmer's use of digital synthesizers and electronic keyboards brought a fresh and distinctive sound to the world of film scores. He embraced the capabilities of these instruments, exploring new sonic possibilities and creating unique textures and atmospheres that added depth and emotion to his compositions. Furthermore, Zimmer's expertise in harnessing the power of computer technology revolutionized film scoring.

He integrated computer-based music production techniques, allowing for precise control over orchestral arrangements, sound manipulation, and the creation of complex musical layers. His pioneering work in films such as "Blade Runner 2049," "Inception," and "The Dark Knight" demonstrated the immense creative potential of these technologies and cemented Zimmer's reputation as a trailblazer in the industry.

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Variable number tandem repeat (VNTR) is a ______
a. Gene b. polymorphism c. translocation d. both a and b

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Variable number tandem repeat (VNTR) is both a gene and a polymorphism. Therefore, the correct answer is d. both a and b, as VNTRs are both a gene and a polymorphism.

VNTR refers to a type of DNA sequence variation characterized by the presence of short DNA segments that are repeated in tandem (i.e., consecutive repetitions of the same sequence). These repetitive sequences can vary in the number of repeats between individuals, giving rise to the term "variable number tandem repeat."

In terms of being a gene, VNTRs can be present within or near genes and can influence gene expression or function. They can be associated with specific traits, diseases, or genetic disorders.

Moreover, VNTRs are also considered a type of polymorphism. Polymorphisms refer to variations in DNA sequences that are present in a population. VNTRs represent one form of genetic polymorphism due to their variable nature. The number of repeats in a VNTR region can differ between individuals, making it a useful tool for genetic analysis, including forensic DNA profiling and paternity testing.

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what is virus host interaction ? i dont find clear info. i have assingment ant i dont know what i write please helppppp

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Virus-host interaction refers to the relationship and interactions between a virus and its host organism. It involves the complex interplay between the virus and the host's cells, tissues, and immune system.

During virus-host interaction, viruses infect host cells and hijack their cellular machinery to replicate and produce new virus particles. The virus enters the host's cells, releases its genetic material (DNA or RNA), and takes control of the cellular processes to produce viral proteins and replicate its genetic material.

This can lead to various consequences for the host, ranging from mild symptoms to severe diseases.

The host organism's immune system plays a crucial role in the virus-host interaction. It detects the presence of viruses and mounts an immune response to eliminate the infection.

The interaction between the virus and the host's immune system can result in a dynamic battle, with the virus trying to evade the immune response and the immune system attempting to control and eliminate the virus.

The outcome of virus-host interaction can vary depending on factors such as the virulence of the virus, the host's immune response, and the specific mechanisms employed by the virus to evade or manipulate the host's defenses.

Understanding virus-host interactions is essential for developing strategies to prevent and control viral infections.

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Meet the Rat Lung Worm - Video Clip "Rat Lung Worm"
Disease / Medical condition:
How do humans contract this disease (i.e. how is it transmitted)?
Signs and symptoms of disease:
Describe the course of the disease:
Are humans a normal part for the rat lung worm’s life cycle?
How can rat lung worm infections be prevented in humans?
Type of parasite (bacteria, protozoan, fungus, helminth, insect, virus):
Scientific name of parasite (properly formatted):

Answers

Angiostrongyliasis, commonly known as rat lungworm disease, is transmitted to humans through the ingestion of raw or undercooked snails, slugs, or contaminated produce.

Once inside the body, the larvae of the rat lungworm migrate to the central nervous system, leading to various symptoms such as headaches, nausea, and neurological complications. Humans are accidental hosts in the life cycle of the rat lungworm, as the adult worms primarily reside in the pulmonary arteries of rats and other rodents.

To prevent infections, it is crucial to thoroughly wash raw produce, especially leafy greens, and avoid consuming snails or slugs that may carry the parasite.

Therefore, the type of parasite is Helminth and the Scientific name of the parasite is Angiostrongylus cantonensis.

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Both the extrinsic and intrinsic activation pathways of procoagulation converge to activate _________________ which subsequently converts fibrinogen into fibrin, among its many functions.
O Von Willebrand Factor
O Factor XIII
O Protein C
O Thrombin
O Factor V

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Both the extrinsic and intrinsic activation pathways of procoagulation converge to activate thrombin which subsequently converts fibrinogen into fibrin, among its many functions. So, the correct option is Thrombin.

What is thrombin?

Thrombin is a protease enzyme that can cleave and activate numerous clotting factors, as well as fibrinogen and factor XIII, among other proteins. It is critical in the coagulation process, which is the body's natural way of stopping bleeding.

The formation of thrombin occurs through the activation of either the intrinsic or extrinsic coagulation pathway. Prothrombin is transformed into thrombin through a complex series of intermediate reactions that necessitate the involvement of other coagulation factors.

Thus, the correct option is Thrombin.

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For many medical conditions, adult stem cells are not suitable for treatment so researchers aim to use embryonic stem cells. Compare and contrast the advantages and disadvantages of both adult and embryonic stem cells in cell- based regenerative therapies. Your answer should demonstrate a detailed knowledge of both embryonic and adult stem cell sources, their isolation and characterisation. Your answer should also address the potential ethical and political issues related to stem cell research. (10 marks)

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Embroynic and adult stem cells both have advantages and disadvantages in the cell-based regenerative therapies.

Below are some of the comparisons and contrasts:

Embryonic stem cells :Embryonic stem cells are derived from the inner cell mass of blastocysts that have been fertilized by in vitro fertilization (IVF) procedures or cloned by somatic cell nuclear transfer (SCNT).

Advantages: Embryonic stem cells have a high potential to differentiate into any type of cells in the human body and they can divide indefinitely, therefore, can be used to develop any type of cell to regenerate tissues for therapeutic use.

Disadvantages: One of the major disadvantages of embryonic stem cells is their potential to form tumors when transplanted in the human body. They require the administration of immunosuppressive drugs to reduce the risk of rejection. Adult stem cells are present in various organs, tissues, and blood of the human body. They can be isolated from bone marrow, blood, adipose tissue, and other organs.

Advantages: Adult stem cells are present in an already developed organ so they do not require the destruction of an embryo, hence there are no ethical issues involved in their usage. They can be obtained from the patient's own body, therefore, there are no issues of immune rejection. They also have a low risk of tumor formation when used for therapeutic purposes.

Disadvantages: Adult stem cells have limited differentiation potential. they can differentiate only into a limited number of cell types. Also, the number of adult stem cells in the human body decreases with age, which can limit their potential to be used in regenerative therapies.  The ethical and political issues relating to stem cell research are complex and require a careful consideration of the interests of patients, scientists, and society as a whole.

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Transmembrane movement of a substance down a concentration gradient with no involvement of membrane protein a.belongs to passive transport
b. is called facilitated diffusion c.belongs to active transport d.is called simple diffusion

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Transmembrane movement of a substance down a concentration gradient with no involvement of membrane protein is called simple diffusion. Simple diffusion is a type of passive transport that occurs without the involvement of membrane proteins.

Passive transport, also known as passive diffusion, does not require energy input from the cell, and substances move down their concentration gradient. It includes simple diffusion and facilitated diffusion.In simple diffusion, molecules move directly through the lipid bilayer of the plasma membrane from high concentration to low concentration. Small molecules such as oxygen, carbon dioxide, and water can move across the membrane through simple diffusion. Facilitated diffusion, on the other hand, requires the involvement of membrane proteins to transport molecules across the membrane.

The membrane protein creates a channel or a carrier for the solute to cross the membrane, but the movement still goes down the concentration gradient.The movement of molecules in active transport is opposite to that of passive transport, moving from an area of low concentration to an area of high concentration. Active transport requires the use of energy, usually in the form of ATP, to pump molecules across the membrane against the concentration gradient. Therefore, we can conclude that the correct option is d. is called simple diffusion.

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