WHOEVER GET'S THIS QUESTION RIGHT I WILL GIVE A BRAINLIEST


The right rectangular prism is packed with unit cubes of the appropriate unit fraction edge lengths. Find the volume of the right rectangular prism in centimeters. (Figure not to scale)


A)
12 1 / 2 cm^3


B)
45 cm^3


C)
67 1 / 2 cm^3


D)
85 cm^3

Answer:

Never:

Step-by-step explanation:

because its more understandable we know this because it wouldnt be always

Answer:

Step-by-step explanation:

Is the second exponent 6, or 6x ?

If it is 6x, then x = -½

Step-by-step explanation:

perp. -1/2

y + 3 = -1/2(x - 4)

y + 3 = -1/2x + 2

y = -1/2x - 1

Answer:

c=5/72

Step-by-step explanation:

5/9=14c-5/12

Switch sides

14c-5/12=5/9

Add 5/12 tp both sides

14c-5/12+5/12=5/9+5/12

Simplify;

14c-5/12+5/12

=14c

Simplify;

5/9+5/12

LCM of 9, 12;

36

The least common multiplier of a, b is the smallest positive number that is divisible by both a and b.

Prime factorization of 9;

3*3

Prime factorization of 12;

2*6

=2*2*3

=3*3*2*2

=36

5/9=5*4/9*4=20/36

5/12=5*3/12*3=15/36

=20/36+15/36

20+15/36

=35/36

14c=35/36

14c/14=35/36/14

14c/14=c

35/36*14

=35/504

=5/72

Answer c=5/72

Answer to the following question is as follows;

Value of C = 5 / 72

Step-by-step explanation:

Given:

[tex]\frac{5}{9} = 14c - \frac{5}{12}\\\\[/tex]

Find:

Value of C

Computation:

[tex]\frac{5}{9} = 14c - \frac{5}{12}\\\\[/tex]

By taking 5/12 to LHS Side

[tex]\frac{5}{9} + \frac{5}{12} = 14c\\\\[/tex]

By taking LCM;

[tex]\frac{(4)(5) + (3)(5)}{36} = 14c\\\\[/tex]

[tex]\frac{20 + 15}{36} = 14c\\\\[/tex]

[tex]\frac{35}{36} = 14c\\\\[/tex]

By transfer 14 to LHS side

[tex]\frac{35}{36 \times 14 } = c\\\\[/tex]

[tex]\frac{5}{36 \times 2 } = c\\\\[/tex]

[tex]\frac{5}{72} = c\\\\[/tex]

Value of C = 5 / 72

Learn more;

https://brainly.com/question/21481562?referrer=searchResults

Answer:

Q.1 a²+10a+24

splitting the middle.

a²+6a+4a+24

=a(a+6)+4(a+6)

(a+6)(a+4)

Q.2 x²+9x+18

splitting the middle

x²+6x+3x+18

x(x+6)+3(x+6)

(x+6)(x+3)

where is the question I dont see it

Answer:

54, 63

Step-by-step explanation:

6 x 9 = 54

7 x 9 = 63

Answer:

a - Mutual

b - (x+21)+(2x+3)=90

c - 3x +24 =90

3x=90-24

3x=66

X=22

Answer:

okay the answer 13.02 enjoy

Answer:

x=27

Step-by-step explanation:

Hey there!

the exterior angles of a quadrilateral add up to equal 360

so 360=2x+40+4x+3x+x+50

step 1 combine like terms

2x+4x+3x+x=10x

50+40=90

now we have

360=10x+90

step 2 subtract each side by 90

360-90=270

90-90 cancels out

now we have 270=10x

step 3 divide each side by 10

270/10=27

we're left with

x=27

Answer:

[tex]\theta=41.18^{\circ}[/tex]

Step-by-step explanation:

Given that,

The height of the tree, h = 14 ft

The height of the shadow, b = 16 ft

We need to find the angle of elevation of the sun from the ground. Let the angle be θ. We can use trigonometry to find it. So,

[tex]\tan\theta=\dfrac{P}{B}\\\\\tan\theta=\dfrac{14}{16}\\\\\theta=41.18^{\circ}[/tex]

So, the required angle of elevation of the sun is equal to [tex]41.18^{\circ}[/tex].

Answer:

65 percent chance right

Step-by-step explanation:

so she opens it 13 out of 20 times, so divide 13 by 20 and you get it

Answer:

[tex]l = \sqrt[3]{\frac{2V}{7}}[/tex]     [tex]b = \sqrt[3]{\frac{2V}{7}}[/tex]       [tex]h = \sqrt[3]{\frac{49V}{4}}[/tex]

Step-by-step explanation:

Represent the volume of the box with V and the dimensions with l, b and h.

The volume (V) is:

[tex]V = l * b * h[/tex]

Make h the subject of the formula

[tex]h = \frac{V}{lb}[/tex]

The surface area (S) of the aquarium is:

[tex]S = lb + 2(lh + bh)[/tex]

Where lb represents the area of the base (i.e. slate):

The cost (C) of the surface area is:

[tex]C = 7 * lb + 1 * 2(lh + bh)[/tex]

[tex]C = 7lb + 2(lh + bh)[/tex]

[tex]C = 7lb + 2h(l + b)[/tex]

Substitute [tex]\frac{V}{lb}[/tex] for h in the above equation

[tex]C = 7lb + 2*\frac{V}{lb}(l + b)[/tex]

[tex]C = 7lb + \frac{2V}{lb}(l + b)[/tex]

[tex]C = 7lb + \frac{2V}{b} + \frac{2V}{l}[/tex]

Differentiate with respect to l and with respect to b

[tex]C_l=7b - \frac{2V}{l^2}[/tex] [tex]=0[/tex]

[tex]C_b=7l - \frac{2V}{b^2}[/tex] [tex]=0[/tex]

To solve for b and l, we equate both equations and set l to b (to minimize the cost)

[tex]7b - \frac{2V}{l^2}=7l - \frac{2V}{b^2}[/tex]

[tex]7l - \frac{2V}{l^2}=7b - \frac{2V}{b^2}[/tex]

By comparison:

[tex]l =b[/tex]

[tex]C_l=7b - \frac{2V}{l^2}[/tex] [tex]=0[/tex] becomes

[tex]7l - \frac{2V}{l^2}=0[/tex]

[tex]7l = \frac{2V}{l^2}[/tex]

Cross Multiply

[tex]7l^3 = 2V[/tex]

Solve for l

[tex]l^3 = \frac{2V}{7}[/tex]

[tex]l = \sqrt[3]{\frac{2V}{7}}[/tex]

Recall that: [tex]l =b[/tex]

[tex]b = \sqrt[3]{\frac{2V}{7}}[/tex]

Also recall that:

[tex]h = \frac{V}{lb}[/tex]

[tex]h = \frac{V}{\sqrt[3]{\frac{2V}{7}}*\sqrt[3]{\frac{2V}{7}}}[/tex]

[tex]h = \frac{V}{\sqrt[3]{\frac{4V^2}{49}}}[/tex]

Apply law of indices

[tex]h = \sqrt[3]{\frac{49V^3}{4V^2}}[/tex]

[tex]h = \sqrt[3]{\frac{49V}{4}}[/tex]

The dimension that minimizes the cost of material of the aquarium is:

[tex]l = \sqrt[3]{\frac{2V}{7}}[/tex]     [tex]b = \sqrt[3]{\frac{2V}{7}}[/tex]       [tex]h = \sqrt[3]{\frac{49V}{4}}[/tex]

Answer:

0.887966

Step-by-step explanation:

1. Divide by 3500

(5000/3500)(2^x) = (3^x)

2. divide by 2^x and simplify

10/7 = (3/2)^x.

3. apply 'ln' function

ln(10/7) = xln(3/2)

4. divide ln(3/2)

ln(10/7) / ln(3/2) = x

x = 0.87966

Step-by-step explanation:

Given

GPA = NO + B1Study + B2work + B3leisure + B4sleep + u

1. No it makes no sense. There is an intercorellation between these explanatory variables. Changing study while holding the rest variables constant or fixed would not make sense. If study us changed then one or more of the other predictors should be changed so that they can still be equal to 168

2. Study is a perfect linear function of work, leisure and sleep. There is the problem of multicollinearity among these independent variables. One assumption of the MLR is no multicollinearity.

3. To reformulate model, you have to drop the variable that is having the issue. Let's say that leisure is dropped from the model. After this the assumption is satisfied.

GPA = b0 + B1Study + b2sleep + b3work + u

Answer:

1.5x-y=6

x-y=5+6

x-y=11

2.x + 6y =4

x+y=6-4

X+y=2

xy=2

SORRY THE WRONG

Step-by-step explanation:

FROM INDONESIAN

Answer:

A,B

Step-by-step explanation:

I think bc I had the same question well something like this in A in B was it

Answer:

6 units to the right, 3 units down

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the given information:

[tex]a_n = a_{n-1} + a_{n-2}; \ \ \ n \ge 2 \\ \\ a_o = 1 \\ \\ a_1 =1 \ \ \ \ \ since \ \ a_o = a_1 = 1[/tex]

A)

[tex]a_n - a_{n-1} - a_{n-2} = 0 \\ \\ \implies \sum \limits ^{\infty}_{n=2}(a_n -a_{n-1}-a_{n-2} ) x^n = 0 \\ \\ \implies \sum \limits ^{\infty}_{n=2} a_nx^n - \sum \limits ^{\infty}_{n=2} a_{n-1}x^n - \sum \limits ^{\infty}_{n=2}a_{n-2} x^n = 0 \\ \\ \implies (a(x) -a_o-a_1x) - (x(a(x) -a_o)) -x^2a(x) = 0 \\ \\ \implies a(x) (1 -x-x^2) -a_o-a_1x+a_ox = 0 \\ \\ \implies a(x)(1-x-x^2)-1-x+x=0 \\ \\ \implies a(x) (1-x-x^2) = 1[/tex]

[tex]\mathbf{Generating \ Function: a(x) = \dfrac{1}{1-x-x^2}=f(x)}[/tex]

B)

[tex]If \ \ 1 -x-x^2 = (1 - \alpha x) ( 1- \beta x) \\ \\ \implies 1 -x - ^2 = 1 + \alpha \beta x^2 - ( \alpha + \beta )x \\ \\ \text{It implies that:} \\ \\ \alpha \beta = -1 \\ \\ \alpha + \beta = 1 \\ \\ \implies \alpha = ( 1-\beta) \\ \\ ( 1- \beta) \beta = -1 \\ \\ \implies \beta - \beta^2 = -1 \implies \beta - \beta^2 -1 = 0\\ \\ \beta = \dfrac{-(-1) \pm \sqrt{(-1)^2 -4(1)(-1)}}{2(1)}[/tex]

[tex]\beta = \dfrac{1\pm \sqrt{5}}{2} \\ \\ \beta = \dfrac{1 + \sqrt{5}}{2} \ \ and \ \ \alpha = \dfrac{1 - \sqrt{5}}{2}[/tex]

C)

[tex]\dfrac{1}{1-x-x^2}= \dfrac{A}{1-\alpha x}+ \dfrac{\beta}{1-\beta x} \\ \\ = \dfrac{A(1-\beta x) + B(1-\alpha x)}{(1-\alpha x) (1 - \beta x)} \\ \\ = \dfrac{(A+B)-(A\beta+B\alpha)x}{(1-\alpha x) (1-\beta x)}[/tex]

[tex]\text{It means:} \\ \\ A+B=1 \\ \\ B = (1-A) \\ \\ A\beta+ B \alpha =0 \\ \\ A\beta ( 1 -A) \alpha = 0 \\ \\ A( \beta - \alpha ) = -\alpha \\ \\ A = \dfrac{\alpha}{\alpha - \beta } \\ \\ \\ \\ B = 1 - \dfrac{\alpha }{\alpha - \beta} \implies \dfrac{\alpha - \beta - \alpha }{\alpha - \beta } \\ \\ =\dfrac{-\beta }{\alpha - \beta} \\ \\ \mathbf{B = \dfrac{\beta }{\beta - \alpha }}[/tex]

D)

[tex]\text{The formula for} a_n: \\ \\ a(x) = \dfrac{\alpha }{\alpha - \beta }\sum \limits ^{\infty}_{n=0} \alpha ^n x^n - \dfrac{\beta}{\beta - \alpha }\sum \limits ^{\infty}_{n=0} \beta x^n \\ \\ \implies \sum \limits ^{\infty}_{n =0} \dfrac{\alpha ^{n+1}- \beta ^{n+1}}{\alpha - \beta}x^n \\ \\ a_n = \dfrac{\alpha ^{n+1}- \beta ^{n+1}}{\alpha - \beta } \\ \\ \\ a_n = \dfrac{1}{\sqrt{5}} \Big (\Big( \dfrac{\sqrt{5}+1}{2}\Big)^{n+1}- \Big ( \dfrac{1-\sqrt{5}}{2}\Big) ^{n+1}\Big)[/tex]

Answer:

24

Step-by-step explanation:

8 * 3 = 24

12 * 2 = 24

(the star is the multiplication sign)

Hope this helps :)

Answer:

D. The same point

Step-by-step explanation:

An equilateral triangle can be defined as a type of triangle that has all of its sides being equal in length.

This ultimately implies that, an equilateral triangle comprises of three (3) congruent sides and as such creates three (3) congruent angles that measures 60° each. Also, the sum of the congruent angles of an equilateral is always equal to 180°.

Hence, in an equilateral triangle, the incenter, orthocenter, circumcenter, and centroid are the same point i.e all of the three (3) centers fall on the same point or spot.

You have 2 points with the same x value of 2 and 2 points with the same y value of 4.

You now need 2 points with the same x value of 4 ( you are given 1) and 2 y values of 1 ( you are given 1.

The missing point would need to be (4,1)

The width would be x2-x1 = 4-2 = 2 units

The length would be y2-y1 = 4-1 = 3 units

Area = 3x 2 = 6 square units

Answer:

182.82812

Step-by-step explanation:

Answer:

65

Step-by-step explanation:

Answer:

Last one

Step-by-step explanation:

Answer:Analyze the results of the correlation using the given residual plot.

Residual

Step-by-step explanation:

Answer:

By the way that it is worded, I believe that you are only allowed to put 1 charm on the bracelet, so there are 9 ways to pick a charm.

Hope this helps(and also if you have a more refined wording please put it in the comments)!

Answer:

By the way that it is worded, I believe that you are only allowed to put 1 charm on the bracelet, so there are 9 ways to pick a charm.

Answer:

x

∈

R

y

≤

1

Step-by-step explanation:

Answer:

[tex]y\geq -1[/tex]

Step-by-step explanation:

see graph below for reference

Answer: so here is what you have to do

Step-by-step explanation:Determine Whether a Number

Is a Solution to an Equation

2 Solve Linear Equations

3 Determine Whether an Equation Is a Conditional Equation, Identity, or Contradiction

Preparing for Linear Equations

Before getting started, take this readiness quiz. If you get a problem wrong, go back to the section cited and review the material.

P1. Determine the additive inverse of 5.

P2. Determine the multiplicative inverse of - 3.

P3. Use the Reduction Property to simplify 15 # 5x.

P4. Find the Least Common Denominator of 3 and 5 .

8 12

P5. Use the Distributive Property to remove the parentheses: 61z - 22

P6. What is the coefficient of - 4x?

P7. Simplify by combining like terms: 41y - 22 - y + 5 P8. Evaluate the expression -51x + 32 - 8 when x = -2

P9. Isx = 3inthedomainof 2 ?Isx = -3inthe domain? x + 3

[Section R.3, p. 21] [Section R.3, pp. 23–24]

[Section R.3, pp. 25–26] [Section R.3, pp. 27–28]

[Section R.3, pp. 29–30] [Section R.5, p. 41] [Section R.5, pp. 41–43] [Section R.5, pp. 40–41]

[Section R.5, pp. 43–44]

 In Words

In the equation 2

2 + 5 is the left side of the equation and 0 is the right side. In this equation only the left side contains the variable, y. In the equation 4 +5=-2x+10,theexpression

4 + 5 is the left side of the equation and - 2 + 10 is the right side. In this equation both sides have expressions that contain the variable, x.

1 Determine Whether a Number Is a Solution to an Equation

An equation in one variable is a statement made up of two expressions that are equal, and in the statement, at least one of the expressions contains the variable. The expres- sions are called the sides of the equation. Examples of equations in one variable are

2y + 5 = 0 4x + 5 = -2x + 10 3 = 9 z+2

In this section, we will concentrate on solving linear equations in one variable.