Which type of molecule is shown below? I CH3 C=C H CH3 O A. Alkene O B. Cyclic alkane O C. Alkane O D. Alkyne​

Which Type Of Molecule Is Shown Below? I CH3 C=C H CH3 O A. Alkene O B. Cyclic Alkane O C. Alkane O D.

Answers

Answer 1

Answer:

Alkene

Explanation:

Took the test.

Answer 2

The correct answer is Option (A) Alkene.

What is Alkene?Alkenes are the hydrocarbon which contain double bond of carbon and carbon.The general formula of alkene are CnH2n.Alkenes are unsaturated hydrocarbons.   Why other options are incorrect?The other options are incorrect because the structure given in the question is C4H8. The IUPAC name of the structure is is 1- butene .The structure describes  the general formula of alkene CnH2n where we can say that n= 4Hence ,  Option (A) is correct and rest options are incorrect.  

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Related Questions

An atom or ion has 16 protons, 15 neutrons, and 17 electrons. Is it positive, negative, or
neutral? Why? What element is it?
I really need help on this so can someone tell me the answer please!

Answers

Its negative I think, if I remember correctly it is phosphorus-32....

Why Does the Moon Appear in the Daytime? ...
How Much Does the Sky Weigh? ...
How Much Does the Earth Weigh? ...
How Do Airplanes Stay in the Air? ...
Why Is Water Wet? ...
What Makes a Rainbow? ...
Why Don't Birds Get Electrocuted When They Land on Electric Wires?

Answers

The moon appears in the day time because the sun reflects off of it
The sky weighs 12,107,415,382,493,169,564 pounds
The earth weighs 1.317x10^24 pounds
Airplanes stay in the air because air going around the wings and the jets give it lift
Water is wet because it is touching another liquid (water)
Rainbows are created by light passing through water droplets and slowing down
Birds are tiny gods.
The other person sounds brainliest. Mark them brainliest

A neutral atom with the electron configuration 2-7 would most likely form a bond with an atom having the configuration

Answers

Answer:

1s2 2s2

Explanation:

Consider the substances in the reaction: Uranium-235, Krypton-93, and Barium-140. The values of “235”, “93”, and “140” all represent what characteristic of the elements?

Answers

Answer:

Relative atomic mass

Explanation:

How many grams of chlorine gas are needed to make 5.20 x 100 g of a solution that is 2.00 ppm chlorine by mass?
mass:
CI,

Answers

Answer:

mass of chlorine = 10.4 grams

Explanation:

Mass of the solution = 5.20 × 10⁶ g

ppm chlorine by mass = 2.00

Recall that:

[tex]ppm = \dfrac{mass \ of \ chorine \ gas (solute)}{ mass of the solution }\times 10^6[/tex]

[tex]2 = \dfrac{mass \ of \ chorine \ gas (solute)}{ 5.20\times 10^6}\times 10^6[/tex]

mass of chlorine = 5.20 × 2.0

mass of chlorine = 10.4 grams

For the reaction: 2H2 + O2 → 2H2O, how many grams of water are produced from

6.00 moles of H2?

Answers

Answer:

108 g

Explanation:

2H₂ + O₂ → 2H₂O

First we convert 6.00 moles of H₂ into moles of H₂O, using the stoichiometric coefficients of the reaction:

6.00 mol H₂ * [tex]\frac{2molH_2O}{2molH_2}[/tex] = 6.00 mol H₂O

Then we can convert 6.00 moles of H₂O into grams, using the molar mass of water:

6.00 mol H₂O * 18 g/mol = 108 g

The answer is 108 grams of water.

What is the mass in grams of 4.63 mol of C8H18?

Answers

Answer: 114.22852 grams

HOPE THIS HELPS

Please solve I will give brainliest to correct answer

Answers

Answer:

-846 kJ

Explanation:

Using Henderson Hasselbach's law,

2Al + 3/2 O2 -> Al2O3    H = -1670 kJ

-(2Fe + 3/2 O2 -> Fe2O3) = Fe2O3 -> 2Fe + 3/2 O2    H = 824 kJ

-1670 kJ + 824kJ = -846 kJ

What is the mass in grams of 2.00 10 5 atoms of naturally occurring neon

Answers

Answer:

2.00X10^5 x 20gNe/6.02x10^23=6.46x10^-18 but books answer is 797.

Explanation:

The mass is grams 2.00 x 10⁵ atoms of naturally occurring neon is 6.70 x 10⁻¹⁸g.

What is neon?

Neon is a chemical element in the periodic table. Its atomic number is 10, and it is a Nobel gas. It is a colorless, monatomic, and odorless gas.

Mass is the quantity of matter in a physical body. It can be calculated by the volume and density of the element. The mass can be calculated by the number of atoms.

Given the number of atoms of Ne is 2.00 x 10⁵

The molar mass Ne = 20.18 g/mol

6.022 x 10²³ Ne atoms have a mass of 20.18 g.

The number of atoms is divided by the Avogadro number and the mass of the element.

2.00 x 10⁵ atoms Ne has mass = (2.00*10⁵) / (6.022*10²³) x 20.18 g =

6.70 x 10⁻¹⁸g.

Thus, the mass is grams 2.00 x 10⁵ atoms is 6.70 x 10⁻¹⁸g.

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Which two come together to form an ionic bond?

a. a positive cation and a ngetaive cation
b. a positive cation and a negative anion
c. a positive cation and a positive anion
d. a positive anion and a negative anion

Answers

[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]

b. a positive cation and a negative anion

✏ Anions are negative in nature while cations are positive in nature. Together they come together by an attractive electrostatic force to form an ionic bond.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

[tex] \huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}[/tex]

Consider the incorrectly balanced combustion equation:
2C6H6 + 602 => 12CO2 + 6H2O
Select ALL elements that are not balanced.
Carbon
Hydrogen
Oxygen

Answers

Oxygen is balanced incorrectly.
The correct balanced equation: 2C6H6+15O2=12CO2+6H2O


How many molecules are in 4.67 mols of H2O

Answers

Answer:

2.81 × 10²⁴ molecules

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 4.67 × 6.02 × 10²³

We have the final answer as

2.81 × 10²⁴ molecules

Hope this helps you

A solution has a pH of 10.
What is the concentration of hydrogen ions?

Answers

[H+] = 10−pH, by exponentiating both sides with base 10 to "undo" the common logarithm. The hydrogen ion concentration of "Solution A" is, [H+] = 10−5.6 ≈ 0.0000025 = 2.51 × 10−6 M.

Pls just help me out the vid is 6 Chemical Reactions That Changed History; need help on no.6. I DON’T EVEN KNOW HOW TO SOLVE IT

Answers

Explanation:

HCL you can do it yourself .try again

What volume, in milliliters,

Answers

Answer:

25.4

Explanation:

PLZ mark me brainlist

Select the element(s) that will have ONE unpaired electron in the p orbital.

Ca

N

B

Ar

Br

Answers

Answer: The element B will have ONE unpaired electron in the p orbital.

Explanation:

The electronic configuration of each given element is as follows.

Atomic number of calcium (Ca) is 20.

Ca: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}[/tex]

Atomic number of nitrogen (N) is 7.

N: [tex]1s^{2} 2s^{2} 2p^{3}[/tex]

Atomic number of boron (B) is 5.

B: [tex]1s^{2} 2s^{2} 2p^{1}[/tex]

Atomic number of argon (Ar) is 18.

Ar: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex]

Atomic number of bromine (Br) is 35.

Br: [tex][Ar] 4s^{2} 3d^{10} 4p^{5}[/tex]

Therefore, boron is the only element that have one unpaired electron in the p-orbital.

Thus, we can conclude that element B will have ONE unpaired electron in the p orbital.

1A: Consider these compounds:
A. PbF2
B. Ni(CN)2
C. FeS
D. CaSO4
Complete the following statements by entering the letter(s) corresponding to the correct compound(s). (If more than one compound fits the description, include all the relevant compounds by writing your answer as a string of characters without punctuation, e.g, ABC.)
Without doing any calculations it is possible to determine that magnesium hydroxide is more soluble than __________, and magnesium hydroxide is less soluble than _______.
It is not possible to determine whether magnesium hydroxide is more or less soluble than_______ by simply comparing Ksp values.
1B: For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate solubilities.
(If more than one salt on the right can be directly compared, include all the relevant salts by writing your answer as a string of characters without punctuation, e.g, ABC.)
1. nickel(II) hydroxide
A. Fe(OH)2
2. silver chloride
B. PbS
C. AlPO4
D. MnS
Write the expression for K in terms of the solubility, s, for each salt, when dissolved in water.
nickel(II) hydroxide
silver chloride
Ksp=_______
Ksp=________
Note: Multiply out any number and put it first in the Ksp expression. Combine all exponents for s.

Answers

Solution :

Compound                      Ksp

[tex]$PbF_2$[/tex]                               [tex]$3.3 \times 10^{-8}$[/tex]

[tex]$Ni(CN)_2$[/tex]                        [tex]$3 \times 10^{-23}$[/tex]

FeS                                [tex]$8 \times 10^{-19}$[/tex]

[tex]$CaSO_4$[/tex]                           [tex]$4.93 \times 10^{-5}$[/tex]

[tex]$Mg(OH)_2$[/tex]                      [tex]$5.61 \times 10^{-12}$[/tex]

Ksp of [tex]$Ni(CN)_2 << Ksp \text{ of}\ \ Mg(OH)_2$[/tex] and both compounds dissociate the same way. Hence [tex]$Mg(OH)_2$[/tex] is more soluble than [tex]$(B). \ Ni(CN)_2$[/tex]

[tex]$Mg(OH)_2$[/tex]  is less soluble than [tex]$(A). \ \ PbF_2 \ ()Ksp \ PbF_2 > Ksp \ \text{ of } \ Mg(OH)_2$[/tex]

It is not possible to determine CD - [tex]$FeS \text{ or} \ CaSO_4$[/tex]  is more or less soluble than [tex]$Mg(OH)_2$[/tex]  as though they have a different Ksp values their molecular dissociation is also different and they may have a close solubility values.

[tex]$Ni(OH)_2$[/tex]  can be directly compared with PbS, [tex]$AlPO_4, MnS$[/tex]

[tex]$\text{For } \ Ni(OH)_2$[/tex]

[tex]$AB_2(s) \rightarrow A^{2+} + 2B^{-}$[/tex]

[tex]$Ni(OH)_2(s) \rightarrow Ni^{2+} + 2OH^-$[/tex]

100

1-s s 2s

Ksp = [tex][A2+][B-]^2 = s \times (2s)^2 = 4s^3[/tex]

Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

For Silver Chloride

[tex]$AB(s) \rightarrow A^{x+}+B^{x-}$[/tex]

[tex]$AgCl(s) \rightarrow Ag^+ + Cl^-$[/tex]

1 0 0

1 - s s s

Ksp [tex]$=[A^{x+}][B^{x-}]=s \times s = s^2$[/tex]

Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

How many moles of CH2 must react in order to produce 50 moles

Answers

20 should be the answer

Calculate the molarity of a solution that contains 5 mol of Li2O in 2.35 L of solution.

Answers

Answer:

2.13 M

Explanation:

To solve this problem we need to keep in mind the definition of molarity:

Molarity = moles / liters

As the problem gives us both the number of moles and the volume of solution, we can proceed to calculate the molarity:

Molarity = 5 mol / 2.35 LMolarity = 2.13 M

The answer is 2.13 M.

Use Hess’s Law to calculate the heat of reaction for the following reaction:

2H2O2 → 2H2O +O2 ∆H=?
2H2 +O2 → 2H2O ∆H=-572 KJ
2H2O2 → 2H2 + 2O2 ∆H=376 KJ

Answers

2H2O2 ===> 2H2O + O2 ... TARGET EQUATION
We want to use the other equations that are given in order to make the target equation.
1) 2H2 + O2 ==> 2H2O ∆H = -572 kJ
2) H2 + O2 ==> H2O2 ∆H = -188 kJ

Reverse eq. 2 and multiply by 2 to get 2H2O2 on the left
2H2O2 ==> 2H2 + 2O2 ∆H = +376 kJ (change sign of ∆H and multiply by 2)
Copy eq.1
2H2 + O2 ==> 2H2O ∆H = -572
Add the two to get...
2H2O2 + 2H2 + O2 ==> 2H2 + 2O2 + 2H2O and cancel like terms on each side to get...
2H2O2 ==> 2H2O + O2 <==TARGET EQUATION
∆H = +376 kJ - 572 kJ = -196 kJ

The heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ

Calculating heat of reaction using Hess's law

From the question, we are to calculate the heat of reaction for the reaction

2H₂O₂ → 2H₂O +O₂               ∆H=?

Using Hess's law

Hess's Law of constant heat summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes

From the given equations,

2H₂ +O₂ → 2H₂O                   ∆H= -572 KJ ---------- (1)

2H₂O₂ → 2H₂ + 2O₂              ∆H= 376 KJ ----------- (2)

Adding equations (1) and (2), we get

2H₂O₂ → 2H₂O +O₂               ∆H= -572 KJ + 376 KJ

2H₂O₂ → 2H₂O +O₂               ∆H= -196 KJ

Hence, the heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ.

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molar mass (NH4)2SO4

Answers

Answer:

132.15

Explanation:

Molar mass N = 14.00

Molar mass H = 1.01

Molar mass H4 = 1.01 x 4 = 4.04

Molar mass NH4 = 14.00 + 4.04 = 18.04

Molar mass (NH4)2 = 18.04 x 2 = 36.08

Molar mass S = 32.07

Molar mass O = 16.00

Molar mass O4 = 16.00 x 4 = 64.00

Molar mass SO4 = 32.07 + 64.00 = 96.07

Molar mass (NH4)2SO4 = 36.08 + 96.07 = 132.14

In the graphic,
X represents which element?
40
20

Answers

Answer:Ca

Explanation:

does anyone know how many grams of of fe2o3 react to produce 450 grams of fe

Answers

Answer:

14.4g

Explanation:

The subatomic particle which has the ability to transfer from one object to another, creating an
electric current, is ...
O neutron
O proton
O electron
O quark

Answers

(C )electron I’m pretty sure

This element has an oxidation number of -3 and it has 16 neutrons. What element is this room made of

Answers

Answer: Element is P, phosphor

Explanation:  Phosphor has oxidation number -III and it has 15 protons. So it is possible to have 16 neutrons. Other elements having oxidation number -III are N and As which can not have an isotope with 16 neutrons.

WOULD YOU BE ABLE TO FORM RUST WITHOUT OXYGEN? Explain.

Answers

Answer:

No

Explanation:

Rust is an iron oxide, a usually reddish-brown oxide formed by the reaction of iron and oxygen in the catalytic presence of water or air moisture.

What is the difference between gases and nonmetal?

Answers

Answer:

1) some of the gas maybe metal but non metal directly refers it self to not begin metal

2) gases are present in only air . non metals are available in solid form too

N2O3 → N2 + O2
Name the reactants in this reaction.
Name the products in this reaction.

Answers

[tex]\text{N}_{2}\text{O}_{3}=\text{nitrogen trioxide}\\\text{N}_{2}=\text{nitrogen}\\\text{O}_{2}=\text{oxygen}[/tex]

whats the chemical equation for gypsum (made from Cacl2·2H20 and H2SO4)

Answers

The answer is CaCl2·2H2O + H2SO4 → CaSO4·2H2O + 2HCl, hope this helps!

what class is sodiumtrioxocarbonate(IV) strong or weak base and why?​

Answers

Answer:

Strong base

Explanation:

Anhydrous sodiumtrioxocarbonate(IV) Na2CO3 and crystalline sodiumtrioxocarbonate(IV) Na2CO3 are two forms of sodiumtrioxocarbonate(IV) Na2CO3. The Solvay process is the most common name for the sodiumtrioxocarbonate(IV) Na2CO3 production process.

Still, as Na2CO3 reacts, it produces CO3. That tends to be a weak acid's conjugate base. As a result of the removal of H+, carbonic acid was formed (Strong Base)

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