Which three terms are needed to describe the energy a BASE Jumper has as
she falls toward the ground?
A. Potential
B. Kinetic
C. Gravitational
D. Electromagnetic

Answer:

(C) because the elevator is not accelerating

Note  F = M a = M g (the resultant force on the elevator is due to gravity)

or  Fup = Fc   the force exerted on the elevator by the cable

and Fdown = Fe    the force exerted on the elevator by gravity

F = M a = Fup - Fdown = zero    resultant force on elevator

Answer:

hope this answer helps this is what I understand

Answer:

In the southern hemisphere it is fall but almost winter

Explanation:

They are 6 months ahead of the northern hemisphere. at least thats

how I think about it

Solution :

The volume of the rigid cylinder = [tex]$100 \ cm^3 = 100 \times 10^{-6} \ m^3$[/tex]

Initial pressure inside the cylinder, [tex]$P_i = 800 \ kPa$[/tex]

Initial temperature inside the cylinder, [tex]$T_i = 35^\circ C= 308 \ K$[/tex]

Final temperature inside the cylinder, [tex]$T_f = 5^\circ C= 278 \ K$[/tex]

Final pressure inside the cylinder, [tex]$P_f = 100 \ kPa$[/tex]

Area of the hole, A = [tex]$0.3 \ mm^2 = 3 \times 10^{-7} \ m^2$[/tex]

Velocity of the air through the hole, V = 100 m/s

The final pressure and the temperature inside the cylinder will be the condition same as the ambient conditions.

At initial state, from the equation of state,

PV = mRT,    where R = 287 J/kg-K for air

[tex]$800 \times 10^3 \times100 \times10^{-6} = m_1 \times 287 \times 308$[/tex]

∴  [tex]$m_1=9.1 \times 10^{-4} \ kg$[/tex]

Since the exit condition does not change with time, we have ,

At ambient condition, [tex]$P_f = 100 \kPa$[/tex] and [tex]$T_f= 278 \ K$[/tex].

Therefore, we can find the density of the air

[tex]$P=\rho R T$[/tex]

[tex]$\rho = \frac{P}{RT}$[/tex]

  [tex]$=\frac{100 \times 10^3}{287 \times 278}$[/tex]

 [tex]$= 1.25 \ kg/m^3$[/tex]

Mass flow rate of air from the cylinder = [tex]$\dot m$[/tex]

[tex]$\dot m$[/tex] can be written as [tex]$\dot m$[/tex] [tex]$=\rho_{f} \times A \times v$[/tex]

[tex]$\dot m$[/tex] = [tex]$1.25 \times 3 \times 10^{-7} \times 100$[/tex]

[tex]$\dot m$[/tex] = [tex]$3.75 \times 10^{-5}$[/tex] kg/s

Mass escaped from the cylinder in 5 seconds

[tex]$m=3.75 \times 10^{-5} \times 5$[/tex]

   [tex]$= 1.875 \times 10^{-4} \ kg$[/tex]

Mass of air remaining in the cylinder after 5 seconds :

[tex]$m_2 = m_1 - m$[/tex]

[tex]$m_2 = 9.1 \times 10^{-4} - 1.875 \times 10^{-4}$[/tex]

[tex]$m_2 = 7.225 \times 10^{-4} \ kg$[/tex]

    = 0.7225 grams

Answer:

terminal velocity is;

v = 117.54 m/s

v = 423.144 km/hr

Explanation:

Given the data in the question;

we know that, the force on a body due to gravity is;

[tex]F_g[/tex] = mg

where m is mass and g is acceleration due to gravity

Force of drag is;

[tex]F_d[/tex] = [tex]\frac{1}{2}[/tex]pCAv²

where p is the density of fluid, C is the drag coefficient, A is the area and v is the terminal velocity.

Terminal velocity is reach when the force of gravity is equal to the force of drag.

[tex]F_g = F_d[/tex]

mg =  [tex]\frac{1}{2}[/tex]pCAv²

we solve for v

v = √( 2mg / pCA )

so we substitute in our values

v = √( [2×(86 kg)×9.8 m/s² ] / [ 1.21 kg/m³ × 0.7 × 0.145 m²] )

v = √( 1685.6 / 0.122015 )

v = √( 13814.6949 )

v  = 117.54 m/s

v = ( 117.54 m/s × 3.6 ) = 423.144 km/hr

Therefore terminal velocity is;

v = 117.54 m/s

v = 423.144 km/hr

Answer:

Velocity.

Explanation:

The slope of a displacement time graph for a uniform motion represent the gradient of the line i.e. the velocity of the object.

The velocity of an object is given by :

v = d/t

Where

d is displacement

t is time

Hence, the slope of the displacement-time graph gives the velocity of the object.

Answer:

The cyclist with the greatest average speed is Cyclist 4 with average speed of 4.5 m/s

Explanation:

Given;

Cyclist 1 travels 9 m    in    27 s

Cyclist 2 travels 87 m  in    22 s

Cyclist 3 travels 106 m  in   26 s

Cyclist 4 travels 108 m   in   24 s

Determine the average speed of the cyclists as follows;

Average speed of Cyclist 1:    v =  9/27  = 0.33 m/s

Average speed of Cyclist 2:    v = 87/22 = 3.96 m/s

Average speed of Cyclist 3:    v =   106/26 = 4.08 m/s

Average speed of Cyclist 4:     v =   108/24 = 4.5 m/s

Therefore, the cyclist with the greatest average speed is Cyclist 4 with average speed of 4.5 m/s

Answer:

v = 12.1 m/s

Explanation:

       [tex]F_{c} = N + m*g (1)[/tex]

       [tex]F_{c} = m*\frac{v^{2}}{r} (2)[/tex]

Answer: This (random) thermal motion of the particles due to the temperature is also called Brownian motion. ... The higher the temperature, the faster the diffusion will be, because the stronger the molecule movement and thus the “mixing”.

Explanation:

2 people

Explanation:

Answer: P = 120 kg·9.81 m/s² · 2 m / 30 s = 78 W

Explanation: power P = Work done / time

Work is lifting work = mgh in which g = 9.81 m/s²

Time 30 s

Answer:

The circuit is missing attached below is the required circuit

answer :

a) Ic = 1.944 mA

  Rp = 288.66 kΩ

b) The Emitter-base Junction of the BJT is forward biased while its collector-base junction is reverse biased

Explanation:

Rc = 3.6 kΩ

VBE = 0.8 v

1) predict Ic and specify Rp to establish Vce at 5 V

we will apply Kirchhoff's voltage law to resolve this

solution attached below

b ) The BJT is said to be in Forward reverse bias because The Emitter-base Junction of the BJT is forward biased while its collector-base junction is reverse biased

Answer:

They will fall at the same time.  This is because gravity accelerates all objects at the same speed, Earth's gravity being approximately 9.8m/s²

They'll both fall at the same time. This is because gravity accelerates everything at the same rate, with Earth's gravity being approximately 9.8 m/s2.

To learn more about gravity, refer to:

https://brainly.com/question/16275567

#SPJ2

Answer:

Current in a parallel circuit = 0.61 amps (Approx)

Explanation:

Given:

Voltage V = 6 volt

Two resistors = 17.2 , 22.4 in parallel circuit

Find:

Current in a parallel circuit

Computation:

1/R = 1/r1 + 1 / r2

1/R = 1/17.2 + 1 / 22.4

R = 9.73 ohms (Approx)

Current in a parallel circuit = V / R

Current in a parallel circuit = 6 / 9.73

Current in a parallel circuit = 0.61 amps (Approx)

Answer:

6km

Explanation:

Answer:

A) Because light is due to the electromagnetic fields (fields moving at the speed of light)

Note: Electrical energy is also used to describe the energy usage

in RLC circuits

Answer:

he times are getting closer as we use each filter, in the expression n would be the number of filters  

t = [tex]\sqrt{ \frac{2(y_o - (n-1) h)}{g} }[/tex]

Explanation:

For this exercise let's use the kinematics relations

          y = y₀ + v₀ t - ½ g t²

When the first filter reaches the ground, its height is y = 0, as they release its initial velocity is zero

for the 1st filter

          0 = y₀ - ½ g t²

          t² = 2y₀ / g

          t = [tex]\sqrt{ \frac{2y_o}{g} }[/tex]

when we release the second filter upon arrival it has a height y = h where h is the height of each filter

         h = y₀ - ½ g t²

         t = [tex]\sqrt{ \frac{2(y_o- h)}{g} }[/tex]

when we release the third filter it reaches y = 2h

         2h = y₀ - ½ g t²

          t = [tex]\sqrt{ \frac{2(y_o -2h)}{g} }[/tex]

we can write the terms of this succession

          (n-1) = y₀ - [tex]\frac{1}{2}[/tex] g t²

           t = [tex]\sqrt{ \frac{2(y_o - (n-1) h)}{g} }[/tex]

therefore we see that the times are getting closer as we use each filter, in the expression n would be the number of filters

Answer:

1.B, 2.A

Explanation:

Answer:

the density of mobile electrons in the material is 3.4716 × 10²⁵ m⁻³

Explanation:

Given the data in the question;

we make use of the following expression;

hall Voltage VH = IB / ned

where I = 2.25 A

B = 0.685 T

d =  0.107 mm =  0.107 × 10⁻³ m

e = 1.602×10⁻¹⁹ C

VH = 2.59 mV = 2.59 × 10⁻³ volt

n is the electron density

so from the form; VH = IB / ned

VHned = IB

n = IB / VHed

so we substitute

n = (2.25 × 0.685) / ( 2.59 × 10⁻³ × 1.602×10⁻¹⁹ × 0.107 × 10⁻³ )

n = 1.54125 /  4.4396226 × 10⁻²⁶

n = 3.4716 × 10²⁵ m⁻³

Therefore, the density of mobile electrons in the material is 3.4716 × 10²⁵ m⁻³

the correct answer would be "B"

Answer:

C. Nucleic Acids.

Explanation:

Nucleic acids are thus uniquely capable of directing their own self-replication, allowing them to function as the fundamental informational molecules of the cell. The information carried by DNA and RNA directs the synthesis of specific proteins, which control most cellular activities.

Did some simple research, if that's fine and I hope this is correct as it says on the sites. Have a good one :)

Answer:

The correct answer is:

(a) 0

(b) 0.5 m/s

(c) 7740 N

(d) 0

Explanation:

The given values are:

mass,

m = 3000 kg

Tension,

T = 7,200 N

Angle,

= 30°

(a)

Even as the block speed becomes unchanged, the kinetic energy (KE) will adjust as well:

⇒ [tex]\Delta K =0[/tex]

By using the theorem of energy, the net work done will be:

⇒  [tex]\Delta K =0[/tex]

(b)

According to the question, After 0.25 m the block is moving with the constant speed

= 0.5 m/s.

(c)

The given kinetic friction coefficient is:

u = 0.3

The friction force will be:

= [tex]u(mg-Tsin30^{\circ})[/tex]  

On substituting the values, we get,

= [tex]0.3[(3000\times 9.8)-(7200\times 0.5)][/tex]

= [tex]0.3[29400-3600][/tex]

= [tex]0.3\times 25800[/tex]

= [tex]7,740 \ N[/tex]

(d)

On including the friction,

The net work will be:

⇒ [tex]\Delta K=0[/tex]

Answer:

the laws of physics are the same for all non-accelerating observers

Explanation:

Answer:

The final velocity of the 2kg ball is 1.270 m/s

Explanation:

According to Newton's second and third laws of motion

Newton's second law state that "the rate of change of momentum is proportional to the applied force and takes place in the direction of that force".

Newton's third law state that "for every action, there must be an equal and opposite reaction".

The combinations of these two laws resulted in an elastic collision

Given that:

m1 = 2kg

u1 = 2.20m/s

m2 = 4.00kg

u2 = 0m/s

An Elastic collision is when kinetic energy before = kinetic energy after

E.K before = [tex]1/2mv^{2}[/tex]

E.K before = 1/2 * 2 * (2.20)^2

E.K = 1/2 * 2 * 4.84

E.K before = 4.84j

E.K after = 1/2 x (4 + 2)v^2

E.K after = 1/2(6v^2)

E.K after = 3v^2

Since E.K before = E.K after

4.84 = 3v^2

Divide through by 3

4.84/3 = 3v^2/3

1.6133 = v^2

[tex]V = \sqrt{1.6133} \\V = 1.270 m/s[/tex]

Answer:

a) t = 9.2s

b) Δx = 242.2 m

Explanation:

a)

       [tex]v_{f1} = a_{1} * t_{1} = 11.5m/s2* 3.30 s = 38.0 m/s (1)[/tex]

       [tex]t_{2} = \frac{v_{f1}}{a_{2} } = \frac{38m/s}{4.15m/s} = 9.2 s (2)[/tex]

b)

       [tex]v_{f1} ^{2} = 2* a_{1} * x_{1} (3)[/tex]

       [tex]x_{1} =\frac{v_{f1}^{2} }{2*a_{1}} =\frac{(38m/s)^{2} }{2*11.5m/s2} =62.8 m (4)[/tex]

       [tex]-v_{f1} ^{2} = 2* a_{2} * x_{2} (5)[/tex]

       [tex]x_{2} =\frac{-v_{f1}^{2} }{2*a_{2}} =\frac{-(38m/s)^{2} }{2*(-4.15m/s)^2} =174.0 m (6)[/tex]

Answer:

Explanation:

because it is godhood