Which table represents viable solutions for y = 5x, where x is the number of tickets sold for the school play and y is the amount of money collected for the tickets?

A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries negative 100, negative 25, 40, 600. The second column is labeled money collected (y) with entries negative 500, negative 125, 250, 3000.
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries negative 20, 20, 100, 109. The second column is labeled money collected (y) with entries negative 100, 100, 500, 545.
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 0, 10, 51, 400. The second column is labeled money collected (y) with entries 0, 50, 255, 2000.
A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 5, 65, 80, 200. The second column is labeled money collected (y) with entries 25, 350, 400, 1000.

Third table is true with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 0, 10, 51, 400 and the second column is labeled money collected (y) with entries 0, 50, 255,2000.

Here, the equation is given as;

y = 5x

Where, x is the number of tickets sold for the school play and y is the amount of money collected for the tickets.

What is linear equation?

A linear equation is an algebraic equation of the form y = mx + b

involving only a constant and a first order (linear) term.

Now, we have the following equation;

y = 5 x

For finding the table that complies with this restriction and also have the corresponding values for x and y.

The third table complies with the given condition and has correct values for the given variables;

⇒ x = 0 then y = 0

⇒ x = 10 then y= 50

⇒ x = 51 then y = 255

⇒ x = 400 then y = 2000

Clearly, Third table is true with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 0, 10, 51, 400 and the second column is labeled money collected (y) with entries 0, 50, 255,2000.

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Answer:

Step-by-step explanation:

Which table represents viable solutions for y = 5x, where x is the number of tickets sold for the school play and y is the amount of money collected for the tickets?

A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries negative 100, negative 25, 40, 600. The second column is labeled money collected (y) with entries negative 500, negative 125, 250, 3000.

A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries negative 20, 20, 100, 109. The second column is labeled money collected (y) with entries negative 100, 100, 500, 545.

A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 0, 10, 51, 400. The second column is labeled money collected (y) with entries 0, 50, 255, 2000.

A 2-column table with 4 rows titled School Play Tickets. The first column is labeled tickets (x) with entries 5, 65, 80, 200. The second column is labeled money collected (y) with entries 25, 350, 400, 1000.

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