Which substance is a base? a. HCOOH b. RbOH c. H2CO3 d. NaNO3

Answer:

( About ) 0.03232 M

Explanation:

Based on the units for this reaction it should be a second order reaction, and hence you would apply the integrated rate law equation "1 / [X] = kt + 1 / [[tex]X_o[/tex]]"

This formula would be true for the following information -

{ [tex]X_o[/tex] = the initial concentration of X, k = rate constant, [ X ] = the concentration after a certain time ( which is what you need to determine ), and t = time in minutes }

________

Therefore, all we have left to do is plug in the known values. The initial concentration of X is 0.467 at a time of 0 minutes, as you can tell from the given data. This is not relevant to the time needed in the formula, as we need to calculate the concentration of X after 18 minutes ( time = 18 minutes ). And of course k, the rate constant = 1.6

1 / [X] = ( 1.6 )( 18 minutes ) + 1 / ( 0.467 ) - Now let's solve for X

1 / [X] = 28.8 + 1 / ( 0.467 ),

1 / [X] = 28.8 + 2.1413...,

1 / [X] = 31,

[X] = 1 / 31 = ( About ) 0.03232 M

Now for this last bit here you probably are wondering why 1 / 31 is not 0.03232, rather 0.032258... Well, I did approximate one of the numbers along the way ( 2.1413... ) and took the precise value into account on my own and solved a bit more accurately. So that is your solution! The concentration of X after 18 minutes is about 0.03232 M

The concentration after 18 minutes is 1.45 × 10^-13 M.

We have the equation of the reaction as; X(g)⇌Y(g)+Z(g)X(g)⇌Y(g)+Z(g) and we are informed in the question that the reaction follows the first order kinetics.

From the first order kinetics; ln[A] = ln[A]o - kt

Where;

[A] = concentration at time t

[A]o = initial concentration

k = rate constant

t = time taken

Hence;

ln[A] = ln[0.467] - (1.60 M^−1⋅min^−1 × 18 min)

A = 1.45 × 10^-13 M

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Answer:

61.54%

Explanation:

Hello,

To calculate the percent yield of a product, we express it as ratio between the actual yield to the theoretical yield multiplied by 100.

Percent yield = (actual yield / theoretical yield) × 100

Actual yield = 400mg

Theoretical yield = 650mg

Percent yield = (400 / 650) × 100

Percent yield = 0.6154 × 100

Percent yield = 61.54%

Percent yield of guaifenesin in the drug is 61.54%

The number of moles of carbon atoms in 0.500 mol of ethane (C₂H₆) is equal to one mole.

A mole can be defined as a scientific unit that is utilized to calculate the quantities such as atoms, molecules, ions, or other particular particles. The mass of one mole of a given chemical element is atomic mass and that of 1 mole of a chemical compound is molar mass.

The number of entities found in one mole is equal to 6.023 × 10 ²³ which is known as Avogadro’s constant.

Given, the number of moles of C₂H₆ = 0.500 mole

One molecule of ethane has carbons = 2

One mole of ethane has moles of carbons = 2 moles

0.500 mol of ethane has moles of carbon atoms = 0.500×2 = 1 mol

Therefore, one mole of carbon atoms is present in 0.500 mol of ethane C₂H₆.

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Answer:

Slow combustion

Spontaneous combustion

Explosive combustion

Explanation:

-Slow combustion reactions: Occurs at low temperatures. Cellular respiration is an example.

-Spontaneous combustion reactions: Occurs suddenly without an outside heat source. The heat source is the result of oxidation.

-Explosive combustion reactions: Involves an oxidizing agent.

hopefully this helped :3

Answer:

Three types are: Rapid Combustion, Complete Combustion, and Spontaneous Combustion.

Explanation:

Note: there are more types! This is just three random ones I picked to list. Hope this helps! :)

Answer:

Mg²⁺

Explanation:

Electronic configuration = 1s22s22p6 (or [Ne] )

Charge = -2

This means the element has two extra electrons. So total electrons = 12.

The lement is Magnesium and the ion is Mg²⁺

Answer:

The answer is D or information about when plants first appeared.

Explanation:

Answer:

1. Ionic bond.

2.Ions

3. Covalent

4.Single bond

5. Double bond

6. Polar bond

7.Non polar bond

8. Hydrogen bond

Answer:

1. Ionic bond.

2.Ions

3. Covalent

4.Single bond

5. Double bond

6. Polar bond

7.Non polar bond

8. Hydrogen bond

Explanation:

Answer:

The physical and chemical change that occurs in the aquaponics are given below.

Explanation:

The plants and animals grow in size and decrease the mass of plant due to eating by the fishes is a physical changes which occurs in aquaponics. The sunlight has a heat energy which is absorb by the plants present in aquaponics which is a type of endothermic reaction. In aquaponics, the ammonia present in water is converted into nitrates which is used by the plants as a nutrients. When the mass is converted into energy, it increases the temperature of the ecosystem and also the earth surface. For example, if a wood is burn, it change into heat energy which increases the temperature and cause the global warming on the earth surface.

Answer:

6.0 moles NO2(g)

Explanation:

Based on the reaction every 2 moles N2O5(g) gives reaction with 4 moles NO2(g).Then when we have 3.0 mol N2O5(g),

2 moles N2O5(g)       4 moles NO2(g)

3 moles N2O5(g)        ? moles NO2(g)

______________________________________

3 *4 / 2 = 6.00 moles NO2(g)

Answer:

There are 6 mol of NO2 with respect to 3 mol of N2O5

Explanation:

Approach 1 ( dimensional analysis ) :

3 Moles of N2O5 [tex]*[/tex] ( 4 moles of NO2 / 2 Moles of N2O5 ) - moles of N2O5 cancel out, leaving you with the moles of NO2 -

3 [tex]*[/tex] 4 / 2 = 12 / 2 = 6 moles of NO2

So as you can see in the formula there are 4 moles of NO2 present per 2 Moles of N2O5 - " 4NO2 and 2N2O5. " As we wanted the moles of N2O5 to cancel out, the 2 moles of N2O5 was kept as the denominator, and hence we received the fraction we needed.

Approach 2 :

There are 3 Moles of N2O5. The ratio of Moles of N2O5 to moles of NO2 is provided by the reaction -

Moles of N2O5 : Moles of NO2,

2 : 4,

1 : 2

Therefore the moles of NO2 will be two times as much as the given moles of N2O5, or 3 [tex]*[/tex] 2 = 6 moles of NO2

five oxygen molecules

step by step explanation.

according to the equation,one molecule of oxygen is enough to react with two carbon molecules thus 10 carbon molecules need 5oxygen molecules

Answer:

7 (neutral).

Explanation:

Hello,

In this case, for the chemical reaction:

[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]

We can notice that since hydrochloric acid and sodium hydroxide are strong, they will fully dissociate during the titration, therefore, as they are in stoichiometric proportions in equal concentrations for the equivalence point, the pH will be 7 (neutral) since all the chloride ions are neutralized by the sodium ions.

Moreover, for the given acid solution, the required volume of sodium hydroxide will be:

[tex]V_{NaOH}=\frac{25.0mL*0.150M}{0.150M}=25.0mL[/tex]

To attain a complete titration until the equivalence point.

Best regards.

Answer:

Answer:

The correct answer is 1335.4 J/ °C.

Explanation:

Based on the given information, the amount of benzoic acid burned is 0.7521 grams, the amount of water present within a calorimeter is 1000 grams and there is an elevation in temperature of 3.60 °C. The heat of combustion of benzoic acid given is -26.42 kJ per mole.  

Now the amount of heat discharged in a reaction is:  

= 0.7521 grams × -26.42 kJ / gram = -19.872 kJ or -19870 J

qreaction = - (qwater + qcal)

-19870 J = - (mwatersΔT + CcalΔT

= - [(1000 grams × 4.184 J/g degree C × 3.60 degree C) + (Ccal 3.60 °C)] (The specific heat of water is 4.184 J/gram °C)

(1000 gram × 4.184 J/g °C × 3.60 °C) + (Ccal 3.60 °C) = 19870 J

15062 J + Ccal 3.60 °C = 19870 J

Ccal 3.60 °C = 4807.6 J

Ccal = 4807.6 J / 3.60 °C = 1335.4 J/°C or 1.3 kJ/°C.  

Explanation:

5.5 billion grains of sand ( 5.5×109 grains)

If the concentration of brown sand is 6.0% , how many grains of brown sand are in the bucket?

Number of grains = Concentration of brown side *  Bucket of sand

Brown grains = 0.06 *  5.5×10^9  = 0.33 x 10^9 = 3.3 x 10^8 grains

If the concentration of brown sand is 6.0 ppm, how many grains of brown sand are in the bucket?

Number of grains = Concentration of brown side *  Bucket of sand

6ppm = 6 / 1000000 = 0.000006

Brown grains =  0.000006  *  5.5×10^9  = 3.3 x 10^4 grains

If the concentration of brown sand is 6.0 ppb, how many grains of brown sand are in the bucket?

Number of grains = Concentration of brown side *  Bucket of sand

6ppb = 6 / 1000000000 = 0.000000006

Brown grains =  0.000000006  *  5.5×10^9  = 3.3 x 10^1 = 33 grains

Answer: There are [tex]2.29\times 10^{23}[/tex] formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{36.0g}{95g/mol}=0.38moles[/tex]

1 mole of [tex]MgCl_2[/tex] contains = [tex]6.023\times 10^{23}[/tex] formula units

Thus 0.38 moles of [tex]MgCl_2[/tex] contains = [tex]\frac{6.023\times 10^{23}}{1}\times 0.38=2.29\times 10^{23}[/tex] formula units

Thus there are [tex]2.29\times 10^{23}[/tex] formula units

Answer:

A) at the rod's geometrical center

Explanation:

Let us assume that the rod is replaced by water. And now this water volume is in translational and in rotational equilibrium.

Therefore, a net upward force must have been exerted by the surrounding liquid which acts at the center of mass of the water volume.

This force determines through the geometric center of the column of the cylindrical water  

Moreover, the force is also independent of submerged body into it

Hence, the first option is correct

Answer:

Path A-B-D involves a catalyst and is slower than A-C-D

Explanation:

The diagram above illustrates both the catalyzed path and the uncatalyzed path of a chemical reaction.

The catalysed path is the path expressed with broken lines and the uncatalyzed path is the path expressed with thick small line as shown in the diagram above.

The catalyzed path has a higher activation energy than the uncatalyzed path.

Therefore, the catalyzed path will be slower that the uncatalyzed path because, the catalyzed path will require a higher energy to overcome the activation energy in order for the reaction to proceed to product.

On the other hand, the uncatalyzed path has a lower activation energy and a lesser amount of energy is needed to overcome it in order for the reaction to proceed to product.

Answer:

The main component of natural gas is methane (CH4) at 60 to 90% followed by various combination of ethane, propane, and butane whose percentage can vary from 0 to 20% each. For each unit mass of alkanes, the combustion energy (energy released when the fuel reacts with oxygen) released is very high about 13 to 15 kcal/g, which is higher than even those generated by petrol or diesel. So, for heating or other energy generation purpose for household purposes, this source of energy is used.

The equation for combustion of methane is shown below. Upon combustion, carbondioxide and water is produced with simultaneous generation of heat which is the source of energy used for consumption.

CH4 + 2O2 --> CO2+ 2H2O + heat [ For methane, the combustion energy is ~ 6kcal/g]

As the CH2 units are increased in the alkanes, the combustion energy increases, for e.g., ethane has combustion energy of 7 kcal/g and propane has about 12 kcal/g.

Explanation:

Answer:

1.418688 atm

Explanation:

(a)  Moles of PCl5 = mass / molar mass

                      =1.5 g / 208.22 g/mol

                     = 0.0072 moles

Also given,

T = 600 K

V = 0.500 L

Pressure of PCl5, P = nRT / V

                             = 0.0072 mol×0.0821 L-atm / (mol.K)×600 K / 0.500 L

                             = 0.709344 atm

(b)  PCl5(g) ⇄ PCl3(g) + Cl2(g)

Initial               0.965         0               0

Change               -x            +x             +x

Equilibrium (0.709344 -x)         x               x

K_p = 11.5 = x×x / (0.965 -x)

solving, we get x = 0.67027

So partial pressure of PCl5 at equilibrium = 0.709344 - 0.67027 = 0.039074 atm

(c)   Partial pressure of PCl3 = Cl2 = 0.709344 atm

So total pressure = 0.709344+0.039074+ 0.67027= 1.418688 atm

Answer:

Explanation:

Partial pressure of oil = mole fraction of oil x total pressure

mole fraction of oil = mole of oil / mole of water + mole of oil

= mole of oil = mass of oil / molecular weight of oil

= 20 / 100 = .2

mole of water = 80 / 18

= 4.444

mole fraction of oil =  .2 / .2 + 4.444

= .2 / 4.644

Partial pressure of oil = mole fraction of oil x total pressure

= (.2 / 4.644 ) x 760 mm

= 32.73 mm Hg .

Answer:

6

Explanation:

Norepinephrine has one benzene cycle , so it has 6 carbon atoms in aromatic group.

Answer:

Kinetic energy = 1/2mv²

where m is the mass

v = velocity

m = 5.31 × 10^-23 kg

v = 1.00 × 10^2 m/s

Kinetic energy = 1/2 × 5.31 × 10^-23 × ( 1.00 × 10^2)²

= 2.655 × 10^-19 Joules

Hope this helps

Answer:

The reaction would shift toward the reactants

When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm

Explanation:

For the reaction:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

Where K is defined as:

[tex]K = \frac{P_{N_{2}}*P_{H_2}^3}{P_{NH_3}^2} = 0.83[/tex]

As initial pressures of all 3 gases is 1.0atm, reaction quotient, Q, is:

[tex]Q = \frac{1atm*{1atm}^3}{1atm^2} = 1[/tex]

As Q > K, the reaction will produce more NH₃ until Q = K consuming N₂ and H₂.

Thus, there are true:

Answer:

it can be recycled over and over again

Answer:

It requires a large amount of energy

Explanation:

Answer:

12: This is decomposition because nitrogen triiodide is breaking apart.

13: This is double displacement because the elements in the compounds are "switching".

14: This is synthesis because the water and carbon dioxide are combining.

15: This is also synthesis because the hydrogen and oxygen are combining.

16: This is single displacement because the sodium is "switching" the element it's bonding with.

Answer:

The pressure will be twice the initial pressure

Explanation:

Gay-Lussac's law states that the pressure of a gas is directely proportional to absolute temperature under constant volume. That is because vibrations of a gas increase when temperature increases, increasing the pressure of the gas.

That means if the temperature of a gas is doubled, the pressure will be twice the initial pressure.

Answer:

[tex]V=142L[/tex]

Explanation:

Hello,

In this case, for the given reaction:

[tex]2H_2O_2(aq) \rightarrow 2H_2O(l) + O_2(g)[/tex]

Starting with 315 g of hydrogen peroxide, we can compute the yielded moles of oxygen by using the following stoichiometric factor whereas the hydrogen peroxide to oxygen mole ratio is 2:1:

[tex]n_{O_2}=315gH_2O_2*\frac{1molH_2O_2}{34gH_2O_2}*\frac{1molO_2}{2molH_2O_2} \\\\n_{O_2}=4.63molO_2[/tex]

Then, by using the ideal gas equation we can compute the resulting volume if the 4.63 moles of oxygen are collected at 0.792 atm and 23 °C as shown below:

[tex]PV=nRT\\\\V=\frac{nRT}{P}=\frac{4.63mol*0.082\frac{atm*L}{mol*K}*(23+273.15)K}{0.792 atm}\\ \\V=142L[/tex]

Best regards.

Answer:

[tex]=C_3H_4O_3[/tex]

Explanation:

When percentage composition is given, and asked for the empirical formula, it is simplest to  assume 100 g of material. Thus,

Mass C = 40.92 g.  Moles C = 40.92 g x 1 mole/12 g = 3.41 moles C

Mass H = 4.58 g.  Moles H = 4.58 g x 1 mole/1.0 g = 4.58 moles H

Mass O = 54.50 g.  Moles O = 54.50 g x 1 mole/16 g = 3.41 moles O

Now, we want to get the moles into whole numbers, so we begin by dividing all by the smallest, i.e. divide all values by 3.41.

Moles C = 3.41/3.41 = 1

Moles H = 4.58/3.41 = 1.34

Moles O = 3.41/3.41 = 1

Now, in order to get 1.34 to be a whole number we multiply it (and all others) by 3

Moles C = 1x3 = 3

Moles H = 1.34x3 = 4

Moles O = 1x3 = 3

Empirical Formula [tex]=C_3H_4O_3[/tex]

Answer:

The two would end up repelling each other very strongly and more energy would ultimately be required to keep the metal-ligand system in place

Explanation:

A complex is made up a central metal atom or ion and ligands. Ligands are lewis bases and they possess lone pairs of electrons. A complex is formed when electrons are donated from ligand species to metals.

However, if the ligand has a negative charge at a particular location and we try to put electrons from the metal near the electrons from the ligand, the two would end up repelling each other very strongly and more energy would ultimately be required to keep the metal-ligand system in place.

If you tried to put electrons from the metal near the electrons from the ligand is :

- They will repel each other.

If you tried to put electrons from the metal near the electrons from the ligand is

The two would end up repelling each other exceptionally strongly and more vitality would eventually be required to keep the metal-ligand framework in place

A complex is made up a central metal particle or particle and ligands. Ligands are lewis bases and they have solitary sets of electrons.

A complex is shaped when electrons are given from ligand species to metals.

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Answer:

Alumunium

Explanation:

Alumunium = [Ne] 3s² 3p¹

Ne = [He]2s²2p⁶

He = 1s

Alumunium = 1s 2s²2p⁶3s² 3p¹

Answer:

D

Explanation: