Which statement is true regarding the intervals where the function is increasing and decreasing? The function is increasing from (–∞, 0). The function is increasing from (0, ∞). The function is decreasing from (–∞, 0). The function is decreasing from (–∞, ∞).

Answer:

numbers dont do into math please move this to englash

Step-by-step explanation:

it posted Wong

Answer:

d

Step-by-step explanation:

Answer:

more than a number = addition

so it is D because the end result has to be 33.

Step-by-step explanation:

Hope this helped!

Answer:

this is clear that answer

Answer:

option b .

yes, by SAS.

.............

Answer:

Step-by-step explanation:

x+y = 8

y = 8-x

xy = 17

x(8-x)  = 17

8x - x² = 17

x² - 8x + 17 = 0

Quadratic formula

x = [8 ± √(8² – 4·1·17)] / [2·1]

 = [8 ± √(-4)] / 2

 = [8 ± 2i] /2

 = 4±i

x = 4+i

y = 4-i

A quadratic equation is written in the form of ax²+bx+c. The two numbers whose sum is 8 and whose product is 17​ are (4+i) and (4-i).

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

Let the first number be 'a' and the second number be 'b'. Therefore, the sum of the two numbers is,

a+b=8

The product of the two numbers is,

ab=17

b=17/a

now, the equation can be written as,

a+b=8

a+(17/a)=8

a² + 17 = 8a

a²-8a+17=0

a = 4±i

Hence, the two numbers whose sum is 8 and whose product is 17​ are (4+i) and (4-i).

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Answer:

$56.10

Step-by-step explanation:

Answer:

$8.50

Step-by-step explanation:

Answer:

(f o h)(-5)=-33

Step-by-step explanation:

Let f(x) = 4x - 1, h(x) = - X-3.

(f o h)=4(-x-3)-1

(f o h)=-4x-12-1

(f o h)=-4x-13

(f o h)(-5)=-4(-(-5))-13

(f o h)(-5)=-20-13

(f o h)(-5)=-33

Answer:

[tex]P(X > 11) = 0.368[/tex]

[tex]P(X > 22) = 0.135[/tex]

[tex]P(X > 33) = 0.050[/tex]

[tex]x = 33[/tex]

Step-by-step explanation:

Given

[tex]E(x) = 11[/tex] --- Mean

Required (Missing from  the question)

[tex](a)\ P(X>11)[/tex]

[tex](b)\ P(X>22)[/tex]

[tex](c)\ P(X>33)[/tex]

(d) x such that [tex]P(X <x)=0.95[/tex]

In an exponential distribution:

[tex]f(x) = \lambda e^{-\lambda x}, x \ge 0[/tex] --- the pdf

[tex]F(x) = 1 - e^{-\lambda x}, x \ge 0[/tex] --- the cdf

[tex]P(X > x) = 1 - F(x)[/tex]

In the above equations:

[tex]\lambda = \frac{1}{E(x)}[/tex]

Substitute 11 for E(x)

[tex]\lambda = \frac{1}{11}[/tex]

Now, we solve (a) to (d) as follows:

Solving (a): P(X>11)

[tex]P(X > 11) = 1 - F(11)[/tex]

Substitute 11 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{1}{11}* 11})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{11}{11}})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-1})[/tex]

Remove bracket

[tex]P(X > 11) = 1 - 1 + e^{-1}[/tex]

[tex]P(X > 11) = e^{-1}[/tex]

[tex]P(X > 11) = 0.368[/tex]

Solving (b): P(X>22)

[tex]P(X > 22) = 1 - F(22)[/tex]

Substitute 22 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{1}{11}* 22})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{22}{11}})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-2})[/tex]

Remove bracket

[tex]P(X > 22) = 1 - 1 + e^{-2}[/tex]

[tex]P(X > 22) = e^{-2}[/tex]

[tex]P(X > 22) = 0.135[/tex]

Solving (c): P(X>33)

[tex]P(X > 33) = 1 - F(33)[/tex]

Substitute 33 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{1}{11}* 33})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{33}{11}})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-3})[/tex]

Remove bracket

[tex]P(X > 33) = 1 - 1 + e^{-3}[/tex]

[tex]P(X > 33) = e^{-3}[/tex]

[tex]P(X > 33) = 0.050[/tex]

Solving (d): x when [tex]P(X <x)=0.95[/tex]

Here, we make use of:

[tex]P(X<x) = F(x)[/tex]

Substitute [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X<x) = 1 - e^{-\lambda x}[/tex]

So, we have:

[tex]0.95 = 1 - e^{-\lambda x}[/tex]

Subtract 1 from both sides

[tex]0.95 -1= 1-1 - e^{-\lambda x}[/tex]

[tex]-0.05=- e^{-\lambda x}[/tex]

Reorder the equation

[tex]e^{-\lambda x} = 0.05[/tex]

Substitute 1/11 for [tex]\lambda[/tex]

[tex]e^{-\frac{1}{11} x} = 0.05[/tex]

Solve for x:

[tex]x = -\frac{1}{1/11}\ ln(0.05)[/tex]

[tex]x = -11\ ln(0.05)[/tex]

[tex]x = 32.9530550091[/tex]

[tex]x = 33[/tex] --- approximated

Answer:

4

Step-by-step explanation:

subtract negative 4 by negative 8

Answer:

Length of the person = 1.9 m

Step-by-step explanation:

Actual length of the lorry = 9.5 m

Length of the lorry as per scale = 10 cm

Scale factor used to get the actual length of the lorry = [tex]\frac{\text{Actual length}}{\text{Length on scale}}[/tex]

                                                                                         = [tex]\frac{9.5}{10}[/tex]

                                                                                         = 0.95 : 1

Let the actual length of the person = x meters

Length of the person as per scale = 2 cm

Scale factor used to get the length of person is same.

Therefore, relation between the actual length of the person and scale length will be,

[tex]\frac{x}{2}= \frac{0.95}{1}[/tex]

x = 2 × 0.95

x = 1.9 meters

Answer:

Image attached

Step-by-step explanation:

Just wandering, no hate, you can post answers on brainly but can't read an analog clock.

BTW I've got one in my house

The number of bananas that Ron sold is 315.

Division is one of the operation in mathematics where number is divided  into equal parts as that of a definite number.

Given that,

Cost for a banana = $0.60

Also given, he made $150.00, after taking off $39.00 for his banana stand rental.

Total amount of money that Ron made by selling the bananas = $150 + $39 = $189

Number of bananas sold = 189 / 0.6

                                          = 315

Hence Ron sold 315 bananas.

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Answer: it's b on edge

Step-by-step explanation:

Answer:

Step-by-step explanation:

Each circle represents : [tex]\frac{3}{5}[/tex] and 5 circles

5 * [tex]\frac{3}{5}[/tex]

Answer

Step-by-step explanation:

is Each circle represents : 3/2 and 5 circles

Answer:

4

Step-by-step explanation:keep change flip 4/5 x 5/1 = 20/5= 4

Answer:

D

Step-by-step explanation:

Answer:

I love algebra anyways

The ans is in the picture with the  steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

answer is x =-8

hope that helps^^

Answer:

The difference between the greatest and smallest rational number   [tex]=\frac{3}{20}[/tex]              

Step-by-step explanation:

Step(i):-

Given that the rational numbers

[tex]\frac{7}{15} , \frac{11}{20} ,\frac{2}{5} ,\frac{12}{25}[/tex]

we have to find that the difference between the greatest and the smallest rational numbers

solution:-

The greatest rational number  =  [tex]\frac{11}{20}[/tex]

Convert into decimal = 0.55

The smallest rational number = [tex]\frac{2}{5}[/tex]

Convert into decimal = 0.4

The difference between the greatest and smallest rational number

                     [tex]= \frac{11}{20} - \frac{2}{5}[/tex]

                     = [tex]\frac{11-8}{20}[/tex]

                    [tex]=\frac{3}{20}[/tex]

Final answer:-

The difference between the greatest and smallest rational number     [tex]=\frac{3}{20}[/tex]

0

1

2

3

4

5

take x 1 so 1-1

2-1..........

Answer:

1742 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Single light:

Mean of 1700 hours and standard deviation of 400 hours, which means that [tex]\mu = 1700, \sigma = 400[/tex]

Sample of 64:

This means that [tex]n = 64, s = \frac{400}{\sqrt{64}} = 50[/tex]

The probability is 0.20 that the sample mean lifetime is more than how many hours?

This is the 100 - 20 = 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.84

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]0.84 = \frac{X - 1700}{50}[/tex]

[tex]X - 1700 = 50*0.84[/tex]

[tex]X = 1700 + 50*0.84[/tex]

[tex]X = 1742[/tex]

Answer:

3.75

Step-by-step explanation:

To make it a fraction form answer, you multiply the dividend numerator by the divisor denominator to make a new numerator.

Furthermore, you multiply the dividend denominator by the divisor numerator to make a new denominator:

To make the answer to 3/4 divided by 1/5 in decimal form, you simply divide the numerator by the denominator from the fraction answer above:

15/4 = 3.75

The answer is rounded to the nearest four decimal points if necessary.

15/4 is an improper fraction and should be written as 3 3/4.

Answer:

3.75

Step-by-step explanation:

Answer:

1.268 cups

Step-by-step explanation:

60 G=0.2536 cups  (I found a G to cup converter on the internet)

0.2536x5=1.268 cups of paint it would mix with at a 1 to 5 ratio

Answer:

Step-by-step explanation:

-7 which set of number belongs, betwen

Natural

Whole

Intergers

Rational

Irrational

Real