Which shows the most reasonable way to estimate 3 4/7 (-2 1/12) using compatible fractions

Answer:

[tex] \boxed{\sf Final \ velocity \ (v) = 26 \ m/s} [/tex]

Given:

[tex] \sf v = v_{0} + at[/tex]

[tex]\sf Initial \ velocity \ (v_{0}) = 20 \ m/s \\ \sf Acceleration \ (a) = 1.5 \ m/s^{2} \\ \sf Time \ (t) = 4 \ sec[/tex]

To Find:

Final velocity (v)

Step-by-step explanation:

[tex]\sf Substituting \ value \ of \ Initial \ velocity \\ \sf acceleration \ and \ time \ in \ given \ equation: \\ \\ \sf \implies v = v_{0} + at \\ \\ \sf \implies v = 20 + 1.5(4) \\ \\ \sf 1.5 \times 4 = 6 : \\ \sf \implies v = 20 + \boxed{6} \\ \\ \sf 20 + 6 = 26 : \\ \sf \implies v = 26 \: m/s[/tex]

Answer:

[tex]n=(\frac{2.58(0.34)}{0.05})^2 =307.79 \approx 308[/tex]

So the answer for this case would be n=308 rounded up to the nearest integer

Step-by-step explanation:

The margin of error is given by this formula:

[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]    (a)

And on this case we have that ME =0.1/2 =0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

[tex]n=(\frac{z_{\alpha/2} s}{ME})^2[/tex]   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution since the sample size is large enough to assume the estimation of the standard deviation as the population deviation. The critical value for this case is [tex]z_{\alpha/2}=2.58[/tex], replacing into formula (b) we got:

[tex]n=(\frac{2.58(0.34)}{0.05})^2 =307.79 \approx 308[/tex]

So the answer for this case would be n=308 rounded up to the nearest integer

Answer:

The calculated  value Z = 3.775 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

The Two Population proportion are not equal

Step-by-step explanation:

Given first sample size n₁ = 677

First sample proportion

                             [tex]p^{-} _{1} = \frac{x_{1} }{n_{1} } = \frac{172}{677} = 0.254[/tex]

Given second sample size n₂ = 3377

second sample proportion

                             [tex]p^{-} _{2} = \frac{x_{2} }{n_{2} } = \frac{654}{3377} = 0.1936[/tex]

Null Hypothesis : H₀ :  p₁ = p₂.

Alternative Hypothesis : H₁ :  p₁ ≠ p₂.

      Test statistic

                [tex]Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{P Q(\frac{1}{n_{1} } +\frac{1}{n_{2} }) } }[/tex]

where

        [tex]P = \frac{n_{1} p_{1} + n_{2} p_{2} }{n_{1}+n_{2} } = \frac{677 X 0.254+3377 X 0.1936}{677+3377}[/tex]

       P =  0.2036

      Q = 1 - P = 1 - 0.2036 = 0.7964

         [tex]Z = \frac{0.254- 0.1936 }{\sqrt{0.2036 X 0.7964(\frac{1}{677 } +\frac{1}{3377 }) } }[/tex]

        Z =  3.775

Critical value ∝=0.05

Z- value = 1.96

The calculated  value Z = 3.775 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

The Two Population proportion are not equal

Answer:

Step-by-step explanation:

Area of the circular zone = [tex]\pi[/tex]r^2

= 3.14 × 40^2 = 3.14 × 1600 = 5024 m^2

Area of the basketball court = l × b

= 30 × 15 = 450 m^2

Area of the trapezium shaped park =  ( 6 + 4 ) 3.5 / 2

= 35/2 = 17.5 m^2

∴ Area left in the circular zone = Area of the circular zone - ( Area of the basketball court + Area of the trapezium shaped park )

= 5024 - ( 450 + 17.5 )

= 5024 - 467.5

= 4556.5 m^2

hope this helps

plz mark it as brainliest!!!!!!!

Answer:

25/88

Step-by-step explanation:

25 red marbles, 27 blue marbles, and 36 yellow marbles. = 88 marbles

P(red) = number of red/total

          = 25/88

Answer:

Dear user,

Answer to your query is provided below

Probability of choosing a red marble is 0.28 or (25/88)

Step-by-step explanation:

Total number of marbles = 88

Number of red marbles = 25

Probability = 25/88

Answer:

Step-by-step explanation:

We shall find the solution of this problem with the help of vector notation of i , j , which show east and  north direction .

The first displacement can be represented by the following

D₁ = - 3 cos 45 i + 3 sin45 j = - 3 / √2 i + 3 / √2 j

The second  displacement can be represented by the following

D₂ = - 5 cos 45 i - 5 sin45 j = - 5 /√2 i - 5 /√2 j

The third  displacement can be represented by the following

D₃ =  4 cos 45 i + 4 sin45 j =  4 /√2 i + 4 /√2 j

Total displacement D =

D₁ +D₂ + D₃

= i ( -3 -5 + 4 ) / √2 + j ( 3 - 5 + 4 ) / √2 j

= - 4  / √2 i + 2 / √2 j

D = - 2.8288 i + 1.414 j

Magnitude of D

= √ ( 2.8288² + 1.414² )

= 3.16 miles

For direction we calculate angle with X axis

Tanθ = 1.414 / 2.8288

θ = 26 °

As x is negative and Y is positive ,

the direction will be north of west .

Answer:

US

World

Step-by-step explanation:

It depends on where you are. A "trapezium" outside the US is the same as a "trapezoid" in the US, and vice versa.

A trapezium (World; trapezoid in the US) is characterized by exactly one pair of parallel lines. One of the lines that are not parallel may be perpendicular to the parallel lines, but that will only be true for the specific case of a "right" trapezium.

__

A trapezium (US; trapezoid in the World) is characterized by no parallel lines. It may have one angle or opposite angles that are right angles (one or two sets of perpendicular lines), but neither diagonal may bisect the other.

In the US, "trapezium" is rarely used. The term "quadrilateral" is generally applied to a 4-sided figure with no sides parallel.

Answer:

The lowest score eligible for an award is 92.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 82.2, \sigma = 5[/tex]

If the top 2.5% of test scores receive merit awards, what is the lowest score eligible for an award

The lowest score is the 100 - 2.5 = 97.5th percentile, which is X when Z has a pvalue of 0.975. So X when Z = 1.96. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.96 = \frac{X - 82.2}{5}[/tex]

[tex]X - 82.2 = 5*1.96[/tex]

[tex]X = 92[/tex]

The lowest score eligible for an award is 92.

Answer:

-4*4^7

Step-by-step explanation:

Answer:

-65536

Step-by-step explanation:

I do not think I understand the question but -4*4*4*4*4*4*4*4=-65536

I think there may be missing information like if the question is multiple choice.

Hope that helps

Answer:

[tex]71.35-2.093\frac{22.48}{\sqrt{20}}=60.83[/tex]    

[tex]71.35+2.093\frac{22.48}{\sqrt{20}}=81.87[/tex]    

Step-by-step explanation:

Information given

90 34 41 106 84 53 55 48 41 75 49 97 92 73 74 80 94 102 56 83

In order to calculate the mean and the sample deviation we can use the following formulas:  

[tex]\bar X= \sum_{i=1}^n \frac{x_i}{n}[/tex] (2)  

[tex]s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}[/tex] (3)  

[tex]\bar X=71.35[/tex] represent the sample mean for the sample  

[tex]\mu[/tex] population mean (variable of interest)

s=22.48 represent the sample standard deviation

n=20 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]   (1)

The degrees of freedom are given by:

[tex]df=n-1=20-1=19[/tex]

Since the Confidence is 0.95 or 95%, the significance is [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and the critical value would be [tex]t_{\alpha/2}=2.093[/tex]

And replacing we got:

[tex]71.35-2.093\frac{22.48}{\sqrt{20}}=60.83[/tex]    

[tex]71.35+2.093\frac{22.48}{\sqrt{20}}=81.87[/tex]    

Answer:

The answer is nothing duh

Step-by-step explanation:

Answer:

The future value of the annuity due to the nearest cent is $2956.

Step-by-step explanation:

Consider the provided information:

It is provided that monthly payment is $175, interest is 7% and time is 11 years.

The formula for the future value of the annuity due is:

Now, substitute P = 175, r = 0.07 and t = 11 in above formula.

Hence, the future value of the annuity due to the nearest cent is $2956.

Step-by-step explanation:

Answer:

you will want to have a good understanding of these properties to make the problems in ... Here, the same problem is worked by grouping 5 and 6 first, 5 + 6 = 11. ... “three times the variable x” can be written in a number of ways: 3x, 3(x), or 3 · x. ... Use the distributive property to evaluate the expression 5(2x – 3) when x = 2.

y

The distributive property tells us that if were given an expression such as 3(x + 2), we can multiply the 3 by both the x and the 2 to get 3x + 6.

Answer:

The value of a is 0.

Step-by-step explanation:

Given that (x+1) is a factor to a function, it means that when x = -1 is substitute into the function, you will get a 0 value. So you have to substitute the value of x into the function and make it 0, to find a :

[tex]p(x) = a {x}^{2} + x + 1[/tex]

[tex]let \: p( - 1) = 0 \\ let \: x = -1[/tex]

[tex]p( - 1) = a {( - 1)}^{2} + ( - 1) + 1[/tex]

[tex]0 = a - 1 + 1[/tex]

[tex]a = 0[/tex]

Answer:

Solution,

To find a,

We should know that,

Factor of polynomial gives root of polynomial like:x-a if a factor of p(X) then p(a)=0 at X=a

So,

X+1=0

X=0-1

X=-1

put x=-1 into p(X) it gives zero.

[tex]p( - 1) = 0 \\ a {( - 1)}^{2} + ( - 1) + 1 = 0 \\ a(1) - 1 + 1 = 0 \\ a = 0[/tex]

hope this helps....

Good luck on your assignment....

Answer:

216-343

Step-by-step explanation:

the number 312 lies between 125 and 330

The result will be the probability that 17 or fewer out of the 50 sampled students are bilingual.

To determine the probability that 17 or fewer out of 50 sampled students are bilingual, we can use the binomial probability formula. Let's calculate it step by step:

First, we need to determine the probability of an individual student being bilingual. We can do this by dividing the number of bilingual students by the total number of students:

P(bilingual) = 466 / 1320

Next, we'll use this probability to calculate the probability of having 17 or fewer bilingual students out of a sample of 50. We'll sum up the probabilities for having 0, 1, 2, ..., 17 bilingual students using the binomial probability formula:

P(X ≤ 17) = P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 17)

Where:

P(X = k) = (nCk) * (P(bilingual))^k * (1 - P(bilingual))^(n - k)

n = Sample size = 50

k = Number of bilingual students (0, 1, 2, ..., 17)

Now, let's use a calculator to compute these probabilities. Assuming you have access to a scientific calculator, you can follow these steps:

Convert the probability of an individual being bilingual to decimal form: P(bilingual) = 466 / 1320 = 0.353

Calculate the cumulative probabilities for having 0 to 17 bilingual students:

P(X ≤ 17) = P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 17)

Using the binomial probability formula, we'll substitute the values:

P(X ≤ 17) = (50C0) * (0.353)^0 * (1 - 0.353)^(50 - 0) + (50C1) * (0.353)^1 * (1 - 0.353)^(50 - 1) + ... + (50C17) * (0.353)^17 * (1 - 0.353)^(50 - 17)

Evaluate this expression using your calculator to get the final probability. Make sure to use the combination (nCr) function on your calculator to calculate the binomial coefficients.

for such more question on probability

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Using the central limit theorem, the probability that 17 or fewer of them are bilingual.

The following information is given in the question:

Population size N = 1320

Number of bilingual students = 466

Sample size n = 50

number of bilingual students in the sample = 17

Population proportion:

[tex]P =\frac{466}{1320}[/tex]

P =0.3530

Q= 1-3530

Q = 0.647

Sample proportion:

[tex]p = \frac{17}{50}[/tex]

p = 0.34

q = 1-0.34

q = 0.66

Since,

[tex]X \sim B(n, p)[/tex]

E(x) = np and var(x) = npq

Here, the sample size (50) is large and the probability p is small.

So we can use the central limit theorem, which says that for large n and small p :

[tex]X \sim (nP, nPQ)[/tex]

Where, P =0.3530

nP = 50 x 0.3530 = 17.65

and nPQ = 50x0.3530x0.647 = 11.41

Now, we want to calculate P(X≤17)

[tex]P(X\leq 17) = P(\frac{x-nP}{\sqrt{nPQ}}\leq \frac{17-17.65}{\sqrt{11.41}})[/tex]

[tex]P(X\leq 17) = P(z}\leq \frac{-0.65}{3.78}})[/tex]

[tex]P(X\leq 17) = P(z}\leq -0.172)[/tex]

[tex]P(X\leq 17) = P(z}\geq 0.172)[/tex]

[tex]P(X\leq 17) =1- P(z}\leq 0.172)[/tex]

[tex]P(X\leq 17) =1-0.56[/tex]

[tex]P(X\leq 17) =0.44[/tex]

Hence, the probability that 17 or fewer of the students are bilingual is 0.44.

Learn more about central limit theorem here:

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Answer:

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

Answer: 24 ounce jar

Step-by-step explanation:

Unit price of 16 ounce jar

= 2.59 / 16

= 0.161875

Unit price of 24 ounce jar

= 3.29 / 24

= 0.137083

Answer:

Step-by-step explanation:

max can be found by the formula:

t=-b/2a

t=-9.8/2*(-4.9)

t=-9.8/-9.8

t=1

1 sec

to find maximum height obtained we find the vertex:

plug in 1 for t and simply solve:

h(t)= -4.9t^2 + 9.8t + 1

h(t)= -4.9*1^2 + 9.8*1 + 1

h(t)= -4.9*1 + 9.8 + 1

h(t)= -4.9 + 10.8

h(t)= 5.9

height is 5.9

Answer:

2

Step-by-step explanation:

Scale Factor = [tex]\frac{AnySideOfDiagram}{AnySideOfMP3Player}[/tex]

So,

Scale Factor = [tex]\frac{8}{4} = \frac{14}{7}[/tex] = 2

So,

The scale factor is 2

Answer:

Nothing can be further done to this equation. It has been simplified all the way.

Answer:

97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

Step-by-step explanation:

We are given that a random sample of tires is chosen and are driven until they wear out and the number of thousands of miles is recorded;

32, 33, 28, 37, 29, 30, 22, 35, 23, 28, 30, 36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                                P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample average number of miles = [tex]\frac{\sum X}{n}[/tex] = 30.25

            s  = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = 4.71

            n = sample of tires = 12

            [tex]\mu[/tex] = population average number of miles

Here for constructing a 97% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 97% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.55 < [tex]t_1_1[/tex] < 2.55) = 0.97  {As the critical value of t at 11 degrees of

                                              freedom are -2.55 & 2.55 with P = 1.5%}  

P(-2.55 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.55) = 0.97

P( [tex]-2.55 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.55 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.97

P( [tex]\bar X-2.55 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.55 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.97

97% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.55 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.55 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                        = [ [tex]30.25-2.55 \times {\frac{4.71}{\sqrt{12} } }[/tex] , [tex]30.25+2.55 \times {\frac{4.71}{\sqrt{12} } }[/tex] ]

                                        = [26.78 miles, 33.72 miles]

Therefore, 97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

Answer:

P(33) = 0.0826

Step-by-step explanation:

The binomial distribution in this case has parameters n=55 and p=0.55.

The probability that k successes happen with these parameters can be calculated as:

[tex]P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{55}{k} 0.55^{k} 0.45^{55-k}\\\\\\[/tex]

We have to calculate the probability fo X=33 succesess.

This can be calculated using the formula above as:

[tex]P(x=33) = \dbinom{55}{33} p^{33}(1-p)^{22}\\\\\\P(x=33) =1300853625660220*0.0000000027*0.0000000235\\\\\\P(x=33) =0.0826\\\\\\[/tex]

Answer: The distance of the shortest route of return is 400

Step-by-step explanation:

The direction of travel of the plane forms a right angle triangle ABC as shown in the attached photo. C represents the starting point of the plane. To determine the distance of the shortest by which the plane can return to its starting point, BC, we would apply the Pythagorean theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

BC² = 320² + 240²

BC² = 160000

BC = √160000

BC = 400

Answer:

x = -25/3

Step-by-step explanation:

The equation simplifies to -3x - 25 = 0, so

-3x = 25 =>

x = -25/3

Answer:

Your correct answer is 31/50 + -4/25 i

Step-by-step explanation:

5+4i/6+8i = 31/50 + -4/25 i

Answer:

Option (A)

Step-by-step explanation:

For equation of the line,

Let the equation is, y = mx + b

Slope 'm' of the line passing through two points (-3, 4) and (2, -1),

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

   = [tex]\frac{4+1}{-3-2}[/tex]

   = -1

y-intercept of this line, b = 1

Now we substitute these values in the equation,

y = -x + 1

Let the equation of the parabola is,

y = a(x - h)² + k

Here, (h, k) is the vertex of the parabola,

Since vertex of the given parabola is (0, -5),

then the equation will be,

y = a(x - 0)²- 5

y = ax² - 5

Since a point (2, -1) lies on this parabola,

-1 = a(2)² - 5

5 - 1 = 4a

a = 1

Equation of the parabola will be,

y = x² - 5

Therefore, Option (A) will be the answer.

Answer:

end

January

April

1st blank might also be (account)

Answer:

January and April

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

3x+2-x>8

2x+2>8

2x>8-2

2x>6

x>3

Answer:

C

Step-by-step explanation: