Answer:
A
Explanation:
cause I'm big brain :)
I will give 14 points & make you the brainiest
Terrestrial planets are primarily composed of what two materials?
a. hydrogen and helium
b. silicate rocks and metals
c. frozen water and methane
d. helium and iron
Answer:
B. silicate rocks and metals
Terrestrial planets, such as Earth, are primarily composed of silicate rocks and metals. The correct answer is b. silicate rocks and metals.
Silicate rocks, which are made up of silicon and oxygen, are the dominant building blocks of these planets. They include minerals like quartz, feldspar, and mica. Terrestrial planets contain significant amounts of metals such as iron, nickel, and other heavy elements. These metals are found in the planet's core, providing structural strength and contributing to the planet's magnetic field.
This composition differentiates terrestrial planets from gas giants like Jupiter and Saturn, which are predominantly composed of hydrogen and helium. The combination of silicate rocks and metals forms the solid, rocky surfaces that characterize terrestrial planets.
Therefore, The correct answer is b. silicate rocks and metals.
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what is the direction of the sum of these two vectors?
Answer:
what is the direction of the sum of these two vectors?
Answer:
69.6
Explanation:
Ax= 0
Ay= 63.5
Bx= 101 cos 57= 55.009
By= 101 sin 57= 84.706
Tan-1 = (84.706/55.009)
= 69.6
Which line represents a stationary object?
A. Line A
B. Line B
C. Line C
D. Line D
PLZ HELP
Line D represents a stationary object.
When an object is stationary, the line on the graph is horizontal.
When the object is stationary the gradient is?We know, that an object is stationary means the slope of its position-time graph is zero or its pt graph is a straight line parallel to the x-axis.
What is an example of a stationary object?The nest, or the resting place, is a stationary object, and one cannot put one's foot in front of it. A string is then tied from the head assembly to another stationary object.
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A positive charge is 1 m to the left of a negative charge. The positive charge is then moved and placed 1 m to the right of the negative charge. What happens to the electrostatic force between the charges?
The electrostatic force remains attractive, and the magnitude does not change.
The electrostatic force remains repulsive, and the magnitude does not change.
The electrostatic force remains repulsive, but the magnitude changes.
The electrostatic force remains attractive, but the magnitude changes.
Answer:
Option (a) is correct.
Explanation:
Let the magnitude of the positive charge = [tex]q_1[/tex] and the magnitude of the negative charge = [tex]q_2[/tex]
Earlier, the distance between both the charge, d = 1m
By using Coulomb's law, the magnitude of the force between two charge
[tex]F=k\frac {q_1 q_2}{d^2}[/tex], where k is a constant.
So, the magnitude of the force in the initial configuration,
[tex]F_i = k\frac {q_1 q_2}{1^2}= k q_1q_2\cdots(i)[/tex]
The nature of the force is attractive, as both the charges are opposite in nature.
On replacing the positive charge from 1m left to 1 m right side of the negative charge, the distance between the charges remains the same, i.e d=1m.
Moreover, the magnitude, and nature of each charge, [tex]q_1[/tex] as well as [tex]q_2[/tex], are remain the same.
So, the magnitude of the force in the final configuration,
[tex]F_f = k\frac {q_1 q_2}{1^2}= k q_1q_2[/tex]
From equation (i), [tex]F_f=F_i[/tex]
The nature of the force is attractive, as both the charges are opposite in nature.
So, the electrostatic force remains attractive, and the magnitude does not change.
Hence, option (a) is correct.
When the electrostatic force lies between the charges so here the force should remain attractive, also the magnitude should remain the same.
Impact on the electrostatic force:Here we assume the magnitude of the positive charge should be q1 and the magnitude of the negative charge should be q2
Also, the distance between the charge should be d = 1 m
So here we use the columb law
F = kq1q2/d2
here k should be constant
Here the nature of the force should be attractive since the both the charges should be opposite.
Hence, the first option is correct.
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brainlists please help
on the coner opposite of 8n is 5n
Answer:
resultant force=16N→(TOWARDS THE DIRECTION OF 8N)
Explanation:
resultant force=8N+13N-5N
=16N→(TOWARDS THE DIRECTION OF 8N)
Please help me idk what dis
The ball rolled 15 meters in 3 seconds. What was the speed of the ball?
Answer:
5 meter / sec.Explanation:
speed = distance / time
= 15 meters / 3 seconds
= 5 meter / sec.
Answer:5/sec
Explanation:
Two football players are attempting to tackle each other. If one football player has a mass of 100 kg and pushes with a force of 100N onto another football player whose mass is 80kg, how much force does the other player push back with?
Answer:
is it 20kg. Two opposing forces pushing onto each other
State the career function of mining engineering
Answer:Mining engineers are responsible for the effective, safe and profitable operation of mining undertakings. They are mining experts and engineers and have a background in geology as well as civil, mechanical and electrical engineering.
Explanation:
Two bowling balls, each with a mass of 8.52 kg, are traveling toward each other. Find the total momentum of the system if both balls have a speed of 2.13 m/s, but are traveling opposite of one another.
a. 18.1
b. 36.3
c. 0.0
d. 17.4
b=36•3
momentum=mass×velocity
The total momentum of the given system is equal to zero. Therefore, option (C) is correct.
What is the law of conservation of momentum?The linear momentum can be described as the product of the mass times the velocity of that object. Conservation of momentum is a property of an object as the total amount of momentum stays the same.
According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂v₂
where u₁ and u₂ are initial speed while v₁ & v₂ is final speed and m₁ and m₂ is the mass of the collided objects.
The first ball, m = 8.52 g and v = 2.13 m/s
The momentum of the first ball = 18.15 g.m/s
The second ball is moving in the opposite direction w.r.t. first ball,
The second ball, m = 8.52 g and v = - 2.13 m/s
The momentum of the first ball = - 18.15 g.m/s
The total momentum of the system = 18.15 + (-18.15) = 0
Therefore, the total momentum of the given system is zero.
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PLEASE HELP IF YOU KNOW THE ANSWER QUICK PLEASE!!!
Answer:
d
Explanation:
can somone pls help me??!! i’m very stuck
Answer:
R
Explanation:
Her distance from home and Time increase
the stops when she gets to the library
then her distance from home decreases while her time increases
Suppose the mass of the object below was to double. What would happen to the force needed to accelerate the object 10 m/s2?
Answer:
It would also double
Explanation:
F (force) = mass * acceleration; twice the mass means double tue force needed
Define acceleration. Give its mathematical formula and SI unit. When is acceleration of a body negative? Give two examples of situations in which acceleration of the body is negative.
Answer:
The rate of change of velocity of a moving body is called acceleration. mathematical formula of Acceleration = Final velocity-Initial velocity
________________________
Time taken
SI Unit of Acceleration is m/s2. If the Velocity of a moving body decreases, it's acceleration will be negative. Two examples of situations in which acceleration of the body is negative are ÷
* Applying brakes * When a ball is thrown upward it experiences a negative AccelerationOnce a metamorphic rock, always a metamorphic rock. Rocks cannot change from one type of a rock to another.
true or false?
Answer:
False
Explanation:
Metamorphic rock can melt into magma or weathers down (erosion) into sediments.
can I get some help on this
Answer:
sound
Explanation:
but im not exactlly sure so sorry if its wrong.
Answer:
It's Surface wave
Explanation: It travels in a circular motion. The particles travel both parallel and perpendicular in the direction of the wave-
If the astronaut from question #9 collides with a satellite and comes to a complete stop, where did his momentum go? Explain this in terms of conservation of momentum.
Answer:
m v ´- MV = (m + M) v ’
Explanation:
If the astronaut initially has a speed v the satellite has a speed V, we can define a system that is formed by the two bodies, therefore the forces during the collision are internal, so the momentum is conserved
initial instant. Before the crash
p₀ = m v - MV
final instatne. After the crash, we have two cases
1) inelastic shock
m_f = (m + M) v '
p₀ = p_f
m v ´- MV = (m + M) v ’
2) elastic collision with the astronaut's velocity, zero in this case the moment remains
m v - MV = mv ’+ Mv’
also the kinetic energy is conserved
mv'2 + M V2 = mv'2 + m v'2
with these two equations we can find the speed of the cars
A child throws a baseball straight up into the air and it takes 4.5 seconds to reach maximum height. What is the total time of flight for the baseball after being thrown and the baseball player catching it? What are the known and unknown variables? And what equation must be used?
Answer:
9 s.
Explanation:
The following data were obtained from the question:
Time (t) taken to reach the maximum height = 4.5 s
Time of flight (T) =?
The time of flight (T) is simply defined as the total time spent by the ball in the air. Mathematically, it defined as twice the time taken (t) to reach the maximum height i.e
T = 2t
With the above formula, we can obtain the time of flight as follow:
Time (t) taken to reach the maximum height = 4.5 s
Time of flight (T) =?
T = 2t
T = 2 × 4.5
T = 9 s
Thus, the time of flight of the ball is 9 s.
How do you solving kinematic equations for horizontal projectiles?
answer number 19 pls
Answer:
1. Net force = 90 N
2. Acceleration = 9 m/s²
Explanation:
From the question given above, the following data were obtained:
Mass (m) of bag = 10 Kg
Force applied 1 (Fₐ₁) = 45 N
Force applied 2 (Fₐ₂) = 60 N
Force of friction (Fբ) = 15 N
Net force (Fₙ) =?
Acceleration (a) =?
1. Determination of the net force acting on the bag.
We'll begin by calculating the total force applied on the bag.
Force applied 1 (Fₐ₁) = 45 N
Force applied 2 (Fₐ₂) = 60 N
Total force applied = Fₐ₁ + Fₐ₂
Total force applied = 45 + 60
Total force applied = 105 N
Finally, we shall determine the net force acting on the bag. This is illustrated below:
Total force applied = 105 N
Force of friction (Fբ) = 15 N
Net force (Fₙ) =?
Net force (Fₙ) = Total force applied – Force of friction (Fբ)
Net force (Fₙ) = 105 – 15
Net force (Fₙ) = 90 N to the right
2. Determination of the acceleration of the bag.
Mass (m) of bag = 10 Kg
Net force (Fₙ) = 90 N
Acceleration (a) =?
Force (F) = mass (m) × acceleration (a)
90 = 10 × a
Divide both side by 10
a = 90 / 10
a = 9 m/s²
Thus, the acceleration of the bag is 9 m/s² to the right.
the mass of the whole object is equal to the sum of all its parts A. Law of Conservation of Energy B. Law of Conservation of Mass C. Law of Conservation of Weight
HELP PLEASE ILL GIVE YOU BRAINLIEST OR WHATEVER AND LIKE 30 POINTS JUST PLEASE ANSWER ME
Answer:
B. Law of Conservation of Mass
Explanation:
In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction. If we account for all reactants and products in a chemical reaction, the total mass will be the same at any point in time in any closed system.
The kinetic energy of a roller coaster is 100 joules. The potential energy of the same coaster is 100 joules. What is the mechanical energy of the coaster?
Answer/Explanation:
The mechanical energy is 200 joules. Mechanical energy is determined by adding the total kinetic energy by the total potential energy.
M = kp
100 + 100 = 200
Qui:
3
A fish is swimming forward in the ocean. Which of the following is accurate of the forces
between the fish and the water?
mplete
out of
ove flag
Select one:
O a. The force of the fish's tail on the water is less than the force of the water on the fish's
tail
11
O b. The force of the fish's tail points back while the force of the water points forward
Finis
O c. The force of the fish's tail on the water is greater than the force of the water on the fish's
tail
Time
O d. The forces of both the fish's tail and the water point in the same direction
Check
aus page
Next page
Answer:
O c.the force of the fish tail on the water..........
What is a transverse wave like?
Answer:
a transverse wave is a moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation
Explanation:
wave oscillate along paths at right angles to the direction of the wave’s advance.
Explanation:
In a perfectly insulated container of negligible mass, 4.00 × 10−2 kg of steam at 100◦C and atmospheric pressure is added to 0.200 kg of water at 50.0◦C.
A) If no heat is lost to the surroundings, what is the final temperature of the system? B) At the final temperature, how many kilograms are there of steam and how many of liquid water?
Answer:
Following are the solution to this question:
Explanation:
Given value:
[tex]m_s= 4.00 \times 10^{-2} \ kg \\\\L_v=2256 \times 10^{3} \ \frac{J}{kg}\\\\m_w= 0.2 \ kg\\\\\Delta T= 50^{\circ}[/tex]
In point A:
[tex]Q_{Steam}=m_s \ L_v[/tex]
[tex]=0.04 \times 2256 \times 10^{3}\\\\=9.02 \times 10^4 \ J[/tex]
[tex]Q_{water}= m_w \ c_w \ \Delta T\\\\[/tex]
[tex]=0.2 \times 4190 \times 50\\\\=4.19 \times 10^4 \ J[/tex]
[tex]Q_{steam}> Q_{water}[/tex], that's why the final temperature is [tex]= 100^{\circ}[/tex]
In point B:
[tex]\to \Delta m_s L_v=m_w\ c_w \Delta T\\\\\to \Delta m_s \times 2256\times 10^3= 0.2 \times 4190 \times 50\\\\\to \Delta m_s= 1.86 \times 10^{-2} \ kg\\\\\to m_s = 2.14 \times 10^{-2} \ kg\\\\\to liquid \ left = 0.2+ 2.14 \times 10^{-2} = 2.34 \times 10^{-2} \\[/tex]
The yoga term asanas are which of the following?
A.
The yoga breathing method.
B.
The yoga term for mediation.
C.
The yoga term for exercises or poses.
D.
The yoga term for spiritual enlightenment.
Answer:
i guss its A
Explanation:
If it takes Charlie .45 hrs walking at 2.5 km/hr to get to the chocolate factory and it takes Willy Wonka 25 hrs walking at 3.5 km/hr then who lives closer and by how far?
Answer:
6.4
Explanation:
trust
An electric heater is rated 1000watts. If a current of 5A pass through the heater, find the value of its resistance.
Answer: R=40 Ω
Explanation: [tex]P=I^{2} R[/tex]
R=1000/ (25)=40
An airplane flies north at 300.0 km/h relative to the air and the wind is blowing south at 15.0 km/h. What is the airplane’s velocity relative to the ground? *
315 km/h North
15 km/h south
285 km/h North
300 km/h South
Answer:
285
Explanation:
read and alot jbgdxtffhgdae
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional questions.
Online Content: Site 1
Fitness Log
Name each of the five steps in the PRICE treatment. (Site 1)
Answer:
Protection – Protect the wounded area with a support or something similar.
Rest – Do not continue to exercise while your wound is healing. It may take a few weeks or months to recover. You may need crutches or a sling.
Ice – Wrap a bag of ice or a bag of frozen peas in a towel and apply it to the wounded area for 15–20 minutes every two to three hours.
Compression – Apply elastic compression bandages to the wounded area during the day to reduce swelling.
Elevation – Make sure the injured body part is elevated above the height of your heart as much as possible to help reduce swelling.
Explanation:
Just did it.
Answer:
The five-step process for treating a muscle or joint injury such as an ankle sprain is called "P.R.I.C.E." which is short for Protection, Rest, Ice, Compression, and Elevation).
It can be used even by someone without first-aid training, and should be used immediately when an injury occurs – the earlier, the better – while further medical attention is being sought.
If the athlete experiences too much pain during the process, stop immediately.
"P" is for Protection
Protect the injured person and the area being treated but also protect yourself. If the injury occurs on the sports field, stop the game.
Protect the area being treated with a splint if possible.
If the athlete can move, carefully move them to a safer area using a stretcher or a crutch, but if there is any doubt, do not move the injured athlete.
"R" is for Rest
When a child is injured, the body responds in an effort to defend, localize, protect, and clean up the injured area, a response called inflammation. At the time of injury small blood vessels at the injury site rupture and cause tissue bleeding, which, in turn, can cause bruising and swelling.
Explanation:
There are five warning signs of inflammation:
Pain
Redness;
Tissue hotness;
Swelling, and
Loss of function.
Not every injury exhibits all these signs, but if your child is in pain then it is important to stop exercising immediately to avoid further damage.
"I" is for Ice
As soon as possible after injury, begin applying ice continuously for the first 15-20 minutes to decrease swelling and pain.
An ice bag can be applied directly to the skin (except on the outside of the knee) unless the child has a known cold allergy.
The safest form of icing is to use a plastic bag with ice cubes or crushed ice, or instant cold packs. Do not use “blue ice” or “gel packs”.
While icing will be uncomfortable at first, in 2 to 3 minutes, the skin will go numb and the ice bag will feel more comfortable.
If the child is very uncomfortable with ice bag, then a barrier like a wet towel can be placed between the ice and skin.
The ice bag can be secured in place using an elastic bandage, but the compression should not be too tight.
During the application of the ice, ask the child to wiggle their fingers/toes and monitor tissue around area that is being iced to ensure that they are not experiencing a lost of sensation.
Icing for 15-20 minutes with an ice bag is unlikely to cause nerve damage or frostbite; however, any loss of sensation and any changes in tissue coloration in areas other than the area that is being iced indicate that the application is no longer safe.
Because ice and plastic bags are so important, make sure that someone brings these to every practice and game. Better yet, to be on the safe side, bring your own!