Which of these rules are applicable for naming covalent compounds?

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Answer 1
Do u have a picture or anything so I can answer

Related Questions

Combustion Analysis of an unknown hydrocarbon resulted in the capture of 216.00 g of water vapor and 440.00 g of CO2. The total mass of the hydrocarbon before combustion was 144 g.

(1. How many moles of carbon dioxide are present after combustion?)

(2. What is the empirical formula for the unknown hydrocarbon?)

(3. How many water molecules does the water vapor trap capture?)

(4. The gram-formula mass for the unknown hydrocarbon was determined to be 72 g/mol. How many moles of the unknown hydrocarbon were present in the original sample?)

(5. infrared spectral analysis determines that the unknown hydrocarbon does NOT contain oxygen. How many moles of O2 are used in combusting the unknown sample?)

Answers

1: 10 mol CO2

2: C10H24

3: 12 mol H2O

4: 0.5 mol

5: 16 mol O2

The compound is C5H10.

From the information  available in the question;

Number of moles of carbon dioxide = 440.00 g/44 g/mol = 10 moles

Number of moles of water vapor = 216.00 g/18 g/mol = 12 moles

Mass of carbon = 10 moles × 12 g/mol = 120 g of carbon

Moles of hydrogen = 12 moles  × 2 g/mol = 24 g of hydrogen

Number of moles of carbon = 120 g/12 g/mol = 10 moles

Number of moles of hydrogen = 24 g/1 g/mol =24 moles

Divide through by the lowest number of moles =

C - 10/10   H - 24/10

C - 1          H - 2

The empirical formula is CH2

Molar mass of the compound = 72 g/mol

[12 + 2(1)]n = 72

14n = 72

n = 5

The compound is C5H10.

Learn more about hydrocarbons: https://brainly.com/question/1195122

For many purposes we can treat propane (CH) as an ideal gas at temperatures above its boiling point of - 42°C. Suppose the temperature of a sample of propane gas is lowered from 25.0°C to - 22.0 °C, and at the same time the pressure is changed. If the initial pressure was 0.58 kPa and the volume decreased by 40.0%, what is the final pressure?

Answers

Answer: The final pressure is 0.81 kPa

Explanation:

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 0.58 kPa

[tex]P_2[/tex] = final pressure of gas = ?

[tex]V_1[/tex] = initial volume of gas = v

[tex]V_2[/tex] = final volume of gas = [tex]v-\frac{40}{100}\times v=0.6v[/tex]

[tex]T_1[/tex] = initial temperature of gas = [tex]25^0C=(25+273)K=298K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]-22^0C=(-22+273)K=251K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{0.58\times v}{298}=\frac{P_2\times 0.6v}{251}[/tex]

[tex]P_2=0.81kPa[/tex]

The final pressure is 0.81 kPa

A 5.00 g piece of metal is heated to 100.0 C then placed in a beaker containing 20.0 g of water at 10.0 C. The temperature of the water rises to 15.0 C. Calculate the specific heat of the metal

Answers

Calculate the heat gained by the water first.

q = mCpΔT
m = 20.0 g
Cp = 4.186 J/g°C
ΔT = T(final) - T(initial) = 15.0°C - 10.0°C = 5.0°C

q = (20.0)(4.186)(5.0) = 419 J

This is equal to the heat lost by the metal, so calculate Cp for the metal, given:
q = -419 J (negative because heat was lost)
m = 5.00 g
ΔT = 15.0°C - 100.0°C = -85.0°C (negative because the temperature decreased)

q = mCpΔT —> Solve for Cp —> Cp = q/mΔT

Cp = -419 / (5.00 • -85.0) = 0.986 J/g°C

help me with this question?!!

Answers

Answer:

Glow sticks  and match would be light emission, slime would be preciptate, and cookies would be gas.

Explanation:

Explain why water and syrup are able to mix?​

Answers

you can’t because the water would rise and the syrup consistency would not mix

5. Choose the best description of a reversible reaction.
a reaction that occurs in both directions at the same time
a reaction that has used up all the reactants and has stopped
a reaction that can only proceed to the right
a reaction that can only proceed to the left

Answers

Answer:

A reaction that can only move towards the right.

Explanation:

For a reversible reaction when one of the products of the reaction is removed the reaction moves towards right hand side. More and more reactants will be converted into products. This will nullify the effect of removal of product.

Which of the following is true according the the Arrhenius theory of acids?
A strong acid increases the OH-ion concentration in an aqueous solution.
A strong acid decreases the OH-ion concentration in an aqueous solution.
O A strong acid decreases the H+ and OH-ion concentration in an aqueous
solution.
A strong acid increases the H+ ion concentration in an aqueous solution.

Answers

The correct answer is D, a strong acid increases H+ concentration in an aqueous solution, because strong acids dissociate 100% in water to produce the Conjugate Acid H+ and the Conjugate Base.

For example
HCl———>H+ + Cl-

Balance the following equations:
C3H8 (g) + O2 (g) → CO2 (g) + H2O (g)
NH3 (g) O2 (g) NO2 (g) H2O (g)
Al(NO3) Na3S Al2S3 NaNO3

Answers

Explanation:

C3H8 + 502 ----> 3CO2 + 4H20

4NH3+7O2------> 4NO2+6H2O

2Al(NO3)3 + 3Na2S -------> Al2S3+6NaNO3

This molecule undergoes a substitution reaction through an SN1 pathway when warmed and stirred with HBr. Draw the two substitution products of this reaction. Show the correct stereochemistry by using wedges and dashes at all chiral centers. In part two, select the term that correctly describes the relationship between the products.

Answers

Answer:

See explanation and image attached

Explanation:

The mechanism of this reaction is shown in the image attached. The image was obtained from HomeworkLib.

The first step in the reaction is protonation and loss of -OH2. A carbocation is now created which undergoes a 1,2 hydride shift. This yields a tertiary carbocation which is more stable.

A racemic mixture of two products, major and minor are now obtained as shown.

Predict the shape of the molecule.....

Answers

Answer:

bent

Explanation:

he image shows two air fronts moving in a region. The cold front is moving faster than the warm front.



Which will likely happen if the cold front continues to advance faster than the warm front?


Cold air will pass over the warm air, causing dry weather in the region.
Cold air will pass over the warm air, causing dry weather in the region.

Cold air will push up the warm air, resulting in heavy rainfall in the region.
Cold air will push up the warm air, resulting in heavy rainfall in the region.

Cold air will push up the warm a

Answers

Answer:

Cold air will push up the warm air, resulting in heavy rainfall in the region.

help Tell me the answer.

Answers

Answer:

it's easy u just have to put them in a calculator the way they are it will give you your answer atleast I think so hope this helps

consider the following atoms and ion: Cl,Mg,P,K,Ce =
A)which one is an example of ns² family?
B)which one is an example of p-block element?
C) which is (are) isoelectronic with Argon?
D) Which one is an example of alkaline earth metal?
E) which one has core configuration [Ne]3s²?
F) which one is an example of f-block element?
G) which one is d-block element?
H) which one has outer shell configuration of ns²p³?

Answers

Answer:it would be f

Explanation:

Chlorination of phenol gives para product but bromination of phenol gives Ortho para product why

Answers

Answer:

here you go

Explanation:

The reaction of phenol with bromine is known as bromination of phenol. Solvent has great influence on the reaction. In different solvents, different products are obtained. The action of bromine on phenol can be explained as:

Reaction with bromine in water:—-

Reaction with bromine in water

Phenol reacts with bromine water to give 2,4,6-tribromophenol.

In water, ionisation is facilitated. Phenol gets ionised to form phenoxide ion, which is even better ortho,para-directing. Bromine also gets ionised to a larger extent to form a large number of bromonium ions. And Bromine ions are highly stabilized in ionic solvents. So the formation of strong o,p-directing group and stabilization of Br+ enhances the formation of tribromophenol.

Reaction with bromine in CS2:—-

Reaction with bromine in non-polar organic solvents

Phenol reacts with bromine in a presence of Carbon disulphide to form a mixture of o-bromophenol and p-bromophenol. Among which p-bromophenol predominates. In CS2 ionisation is not facilitated that much. As it is a non-polar solvent it doesn't the Br+ on. Also −OH group is moderately o,p-directing. So as usual para-product is more formed.

Combustion of hydrocarbons such as octane (C_8H_18) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosphere can trap the Sun's heat, raising the average temperature of the Earth. For this reason there has been a great deal of international discussion about whether to regulate the production of carbon dioxide.
1. Write a balanced chemical equation, including physical state symbols, for the combustion of liquid octane into gaseous carbon dioxide and gaseous water.
2. Suppose 0.330 kg of octane are burned in air at a pressure of exactly 1 atm and a temperature of 10.0 ?C. Calculate the volume of carbon dioxide gas that is produced. Round your answer to 3 significant digits.

Answers

Answer: 1. [tex]2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)[/tex]

2. The volume of carbon dioxide gas that is produced is 537 L

Explanation:

1. Combustion is defined as the type of chemical reaction where a hydrocarbon is combusted in the presence of oxygen to give carbon dioxide and water.

The balanced reaction for combustion of octane is:

[tex]2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)[/tex]

2.

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]   [tex]\text{Moles of octane}=\frac{0.330\times 1000g}{114.23g/mol}=2.89moles[/tex]

According to stoichiometry:

2 moles of octane produce = 16 moles of carbon dioxide

2.89 moles of octane produce = [tex]\frac{16}{2}\times 2.89=23.1moles[/tex] of carbon dioxide

According to ideal gas equation:

[tex]PV=nRT[/tex]

P = pressure of gas = 1 atm

V = Volume of gas = ?

n = number of moles = 23.1

R = gas constant =[tex]0.0821Latm/Kmol[/tex]

T =temperature =[tex]10.0^0C=(10+273)K=283K[/tex]

[tex]V=\frac{nRT}{P}[/tex]

[tex]V=\frac{23.1\times 0.0821Latm/K mol\times 283K}{1atm}=537L[/tex]

Thus the volume of carbon dioxide gas that is produced is 537 L

Which material would conduct heat best?
А.Air
B.Copper
C.Wood
D.Rubber

Answers

Answer:

I believe the best answer is B. Copper.

What heats up faster but loses heat faster?


-Water
-Air
Or
Land

Answers

The answer is land because land absorbs heat more quickly but it also loses heat more quickly. And it is not water because water is a low conductor of heat and water has to lose more energy in order for the temperature to decrease. And air could not be the answer.

does water burn? for my sister that says water does burn

Answers

no, water can’t burn

Answer:

No, water doesn't burn. It only can burn under specific conditions in a lab.

Explanation:

To determine the concentration of a sodium thiosulfate solution as in this experiment, a student pipetted 25.0 mL of 0.0100 M potassium iodate (KIO3) solution into a 125 mL Erlernmeyer flask. Potassium iodide and sulfuric acid were added as in this experiment. The titration needed 15.21 mL of the sodium thiosulfate to reach the end point. What is the concentration of the sodium thiosulfate solution

Answers

Answer:

0.0986M is the concentration of the Na₂S₂O₃ solution

Explanation:

Potassium iodate, KIO₃, reacts with sodium thiosulfate, Na₂S₂O₃, as follows:

KIO₃ + 6Na₂S₂O₃ +5KI + 3H₂SO₄ → 3H₂O + 3K₂SO₄ + 3Na₂S₄O₆ + 6NaI

To solve this question we must find the moles of sodium thiosulfate that reacts as follows:

Moles KIO₃:

0.0250L * (0.0100mol / L) = 2.5x10⁻⁴moles KIO₃

Moles Na₂S₂O₃:

2.5x10⁻⁴moles KIO₃ * (6mol Na₂S₂O₃ / 1mol KIO₃) = 1.5x10⁻³ moles Na₂S₂O₃

Molar concentration:

1.5x10⁻³ moles Na₂S₂O₃ / 0.01521L =

0.0986M is the concentration of the Na₂S₂O₃ solution

Which of the following compounds is the most stable?​

Answers

Answer:

Hey mate......

Explanation:

This is ur answer......

fluorides

Thus, fluorides are the most stable while iodides are the least stable.

Hope it helps!

Mark me brainliest pls.....

Follow me! :)

Answer:

LICI

Explanation:

a p e x :)

If you obtain 3.0 grams of aspirin from an experiment that could make no more than 3.14 grams, what is the percent yield?

87%
105%
96%
92%

Answers

Answer:

96%

Explanation:

To find the percent yield, we can use this equation

[tex]\frac{Actual}{Theoretical} *100[/tex]

The actual yield of aspirin is 3.0 and the theoretical is 3.14 in this case, so just plug the numbers in.

[tex]\frac{3.0}{3.14} *100\\\\ =96[/tex]

Thus the percent yield is 96%

;)

KBr is the formula for an ionic compound. The fact that neither symbol is followed by a subscript means that there is a(an) of ions in the compound ​

Answers

Answer:

equal number of ions

Explanation:

They cancel each other out that's why there is none

What might happen if an endocrine hormone such as thyroid hormone was controlled by positive instead of negative feedback?​

Answers

Answer:

cdg I will be a little late to the party but I have to go to the store and get ❤️❤️❤️❤️❤️❤️

(giving brainiest) solve please! dont copy I've looked up everything ill know if you copied something!

Answers

Answer:

Precipitation falls in liquid and solid

Evaporation changes liquid water to gas

Explanation:

Precipitation exists in snow, rain, sleet, many forms liquid or solid but NOT gas.

Evaporation is from a liquid to a gas change, also called vaporization.

arrow futhermost to left is evaporation (rising into air)

arrow futhermost to right is precipitation ( falling back to ground)

hope this helped xxx please mark brainliest

How many molecules of CO2 at standard temperature and pressure in 5.4 moles of CO2

Answers

Answer:

3.25×10²⁴ molecules.

Explanation:

From the question given above, the following data were obtained:

Number of mole of CO₂ = 5.4 moles

Number of molecules of CO₂ =?

The number of molecules of CO₂ in 5.4 moles can be obtained as follow:

From Avogadro's hypothesis,

1 mole of CO₂ = 6.02×10²³ molecules

Therefore,

5.4 moles of CO₂ = 5.4 × 6.02×10²³

5.4 moles of CO₂ = 3.25×10²⁴ molecules

Thus, 5.4 moles of CO₂ contains 3.25×10²⁴ molecules.

Is that flirting? I'm not sure and I really need to know-

Answers

Answer:

I mean ig it is, but i dk

Explanation:

A student pours 800.0 mL of a 3.000 molar solution of sodium hydroxide into a 2.00 liter volumetric flask and fills the flask up with water. What is the new molarity of the solution?
A) 12.00 M
B) 1.20 M
C) 14.00 M
D) 0.0750 M

Answers

C) 14.00

(Sorry if it’s wrong)

(giving brainiest)

please answer correctly im failing school and these are my last points!

Answers

Answer:

i answered your other post with it

Explanation:

Identify each of the patterns labeled in the ridge pattern diagram

Answers

Answer: The suspected and crime scene fingerprint patterns are similar which means they belong to the same individual.

Explanation:

A:  Ending ridge between two lines forming a loop like structure common in both suspected and crimes scene patterns.

B: Bifurcation which includes the formation of fork like shape of the ridge.

C: Island is a dot or point like structure which is common in both patterns.

D: It includes delta which is seen in the case of loop and whorl patterns of the fingerprint in loop there is only one delta and in case of whorl there are two deltas. The delta have an island and a bifurcation in it which is common in both patterns of the fingerprints.

E: Intersection occurs when two ridges changes their directions. It is common in the two patterns.

Which equation represents neutralization?
(1 ) 6Li(s)+N 2 (g)=>2Li3N(s)(2) 2Mg(s)+O2(g)=>2MgO(s) (3) 2KOH(aq)+H2SO4(aq) =>K 2 SO 4 (aq)+2H 2 O(l)
(4) Pb(NO 3 ) 2 (aq)+K 2 CrO 4 (aq) => 2KNO 3 (aq)+PbCrO 4 (s)

Answers

Answer:

3) 2KOH(aq) + H2SO4(aq) ⇒ K2SO4(aq) + 2H2O(l)

Explanation:

KOH is a strong base and a H2SO4 is a strong acid. The two react in a neutralization reaction, producing a salt and water.

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