Answer:
Bacteria
Explanation:
pH & POH
What is the pH of Barq's Root Beer with a (H+] of 9.25 x 10-5 M?
a) 4.0
b) -4.0
c) 10.0 d) 0.000095
Answer:
4.0Explanation:
The pH of a solution can be found by using the formula
[tex]pH = - log [ { H}^{+}][/tex]
From the question we have
[tex]ph = - log(9.25 \times {10}^{ - 5} ) \\ = 4.03385[/tex]
We have the final answer as
4.0Hope this helps you
When 229 J of energy is supplied as heat at constant pressure to 3.0mol Ar(g) the temperature of the sample increases by 2.55K. Calculate the molar heat capacities at constant volume and constant pressure of the gas.
Answer:
The answer is "[tex]\bold{21.616\ \ \frac{J}{mol K}}[/tex]".
Explanation:
when it is a constant pressure:
[tex]Cp= \frac{\Delta q}{n\Delta T} \\\\[/tex]
[tex]=\frac{229}{3\times 2.55}\\\\=\frac{229}{7.65}\\\\=29.93 \frac{J}{mol\ K}\\[/tex]
and,
[tex]Cp-Cv=R\ \ (Mayer's\ formula)[/tex]
then,
[tex]Cv=Cp-R\\\\[/tex]
[tex]=29.93-8.314\\\\=21.616\ \ \frac{J}{mol K}[/tex]
If carbon can count the shared hydrogen
atoms for itself, how many electrons are
now in carbon's outer orbital?
Answer:
Mars and Orbital code saber and the alien
cloruro de litio mas sodio
Answer:
El cloruro de litio se utiliza para fabricar litio metálico. El cloruro de litio se funde y electroliza. Esto produce litio metálico líquido.
Explanation:
sowwy si mi español es malo
Answer:
give him brainliest
Explanation:
What volume of O2 at NTP is generated from 7.84 g of
FeSO, (NH4)2SO4.6H2O?
Answer:1.12 g
Explanation:Molar mass of compound FeSO4(NH4)2SO4.6H2O = 392.14 g mol-1
Number of moles of compound in 7.84g sample = 7.84 g/ 392.14 g mol-1
= 0.02 mole
1 mole of sample contain 1 mole of Fe
So, 0.02 mole of sample would contain 0.02 moles of Fe.
Mass of Fe equivalent to 0.02 mole = 0.02 mol x molar mass of Fe
= 0.02 mol x 55.84 g mol-1
= 1.12 g
How many moles of Aluminum are in 54.0 grams of Aluminum (Al)
Answer:
2 moles!
Explanation:
Hi i hope this helped! I researched it and 2 moles was what came up first.
You want to decaffeinate your coffee by extracting the caffeine outwith dichloromethane. It's too late to extract the caffeinefrom the coffee beans because you've already brewed yourself a 200mL cup of coffee. Your particular brand of coffee contains100 mg of caffeine in that 200mL cup. The partitioncoefficient of caffeine in dichloromethane/water is 9.0.
How much caffeine would still be in your 200 mL if you did:
A. One extraction using 200 mL o fdichloro methane
B. Two extractions using 100 mL of dichloro methane each.
Solution :
The partition coefficient
[tex]$k_d= \frac{\text{(mass of caffeine in }CH_2Cl_2 / \text{volume of }CH_2Cl_2)}{\text{(mass of caffeine in water/ volume of water)}}$[/tex]
= 9.0
A). 1 x 200 mL extraction
Let m be the mass of caffeine in water
Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 100 - m
∴ [tex]$\frac{(100-m)/200}{m/200}=9$[/tex]
[tex]$\frac{100-m}{m}=9$[/tex]
[tex]$10 \ m = 100$[/tex]
[tex]$m=\frac{100}{10}$[/tex]
= 10
Therefore, the mass remaining in the coffee is m = 10 mg
B). 2 x 100 mL extraction
First extraction :
Let [tex]$m_1$[/tex] be the mass of the caffeine in water.
Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 100 - m
∴ [tex]$\frac{(100-m_1)/100}{m_1/200}=9$[/tex]
[tex]$\frac{100-m_1}{m_1}=9$[/tex]
[tex]$5.5 \ m_1 = 100$[/tex]
[tex]$m_1=\frac{100}{5.5}$[/tex]
= 18.18
Mass remaining in the coffee after the 1st extraction [tex]$m_1$[/tex] = 18.18 mg
Second extraction:
Let [tex]$m_2$[/tex] be the mass of the caffeine in water.
Mass of caffeine in [tex]$CH_2Cl_2$[/tex] = 18.18 - [tex]$m_2$[/tex]
∴ [tex]$\frac{(18.18-m_2)/100}{m_2/200}=9$[/tex]
[tex]$\frac{18.18-m_2}{m_2}=9$[/tex]
[tex]$5.5 \ m_2 = 18.18$[/tex]
[tex]$m_1=\frac{18.18}{5.5}$[/tex]
= 3.3
Mass remaining in the coffee after the 1st extraction [tex]$m_2$[/tex] = 3.3 mg
What is the volume of a brick with a Length of 5cm, height of 1cm, and a
width of 2cm. *
O 8cm
O 10cm
15cm
O 12cm
all answer are cubed. I just couldn't add the cube symbol to the answer choices
Answer:
The answer is 10cm^3
Explanation:
5x1x2=10
Mind marking me brainliest? :)
Which compound is an isomer of CH3CH2OH?
A) CH3OCH3
B) CH3COOH
C) CH3COCH3
D) CH3CH2CH3
Predict the effect of an eightfold pressure increase on the equilibriunm composition of the reaction 3 Nalg) + H21g) =2 NaHlg)
According to Le cha telier's principle when we increase the pressure of a equilibrium reaction the reaction shift to the side where few moles of gas present.
Your reaction (Notice - I guess the reaction you written is wrong, but still I'm solving with your given prediction)
3NaI (g) + H2 (g) = 2NaHI (g)
Where access of sodium iodide is reacting with Hydrogen gas to form NaHI molecule.
Number of moles of gas on reaction side - 3+2 = 5 moles
Number of moles of gas on product side - 2 moles
Conclusion- the reaction will shift to the right of the reaction
According to Le cha telier's principle when we increase the pressure of a equilibrium reaction the reaction shift to the side where few moles of gas present.
Your reaction (Notice - I guess the reaction you written is wrong, but still I'm solving with your given prediction)
3NaI (g) + H2 (g) = 2NaHI (g)
Where access of sodium iodide is reacting with Hydrogen gas to form NaHI molecule.
Number of moles of gas on reaction side - 3+2 = 5 moles
Number of moles of gas on product side - 2 moles
Conclusion- the reaction will shift to the right of the reaction
i. What is this process of forming energy through combustion called when it occurs in the body?
Answer:
Respiration
Explanation:
Energy, steam and carbondioxide formed.
200 grams of iron (III) chloride reacts with ammonium carbonate [(NH4)2CO3] in the following equation.
FeCl3 + (NH4)2CO3 ---------> NH4Cl + Fe2(CO3)3
_ mole(s) of iron (III) carbonate [Fe2CO3)3] is/are produced in the balanced equation.
a
4
b
1
c
3
d
2
Answer:
0.616 moles of Fe₂(CO₃)₃ are produced when 200 g of FeCl₃ react
b. 1.
Explanation:
The balanced reaction is:
2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃First we convert 200 grams of FeCl₃ into moles, using its molar mass:
200 g ÷ 162.2 g/mol = 1.23 mol FeCl₃Then we convert 1.23 moles of FeCl₃ into moles of Fe₂(CO₃)₃, using the stoichiometric coefficients of the balanced reaction:
1.23 mol FeCl₃ * [tex]\frac{1molFe_2(CO_3)_3}{2molFeCl_3}[/tex] = 0.616 mol Fe₂(CO₃)₃The closest answer would be option b. 1.
Explanation:
[tex]FeCl₃ + (NH₄)₂CO₃ → NH₄Cl + Fe₂(CO₃)₃[/tex]
first balance the chemical equation
[tex]2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃[/tex]
2 mole. 3 mole. 6mole. 1mole
2*162g of FeCl₃ produce 236 g of Fe₂(CO₃)₃
200g of of FeCl₃
produce 236/(2*162)*20=145.68 g of Fe₂(CO₃)₃
1 mole of Fe₂(CO₃)₃=236g
145.68g of Fe₂(CO₃)=1/236*145.68=}0.61mole
closest answer is b 1
b.1mole(s) of iron (III) carbonate [Fe2CO3)3] is/are produced in the balanced equation
what's autonization of water
Explanation:
The self-ionization of water (also autoionization of water, and autodissociation of water) is an ionization reaction in pure water or in an aqueous solution, in which a water molecule, H2O, deprotonates (loses the nucleus of one of its hydrogen atoms) to become a hydroxide ion, OH−. The hydrogen nucleus, H+, immediately protonates another water molecule to form hydronium, H3O+. It is an example of autoprotolysis, and exemplifies the amphoteric nature of water
Animation of the self-ionization of water
Chemically pure water has an electrical conductivity of 0.055 μS/cm. According to the theories of Svante Arrhenius, this must be due to the presence of ions. The ions are produced by the water self-ionization reaction, which applies to pure water and any aqueous solution:
H2O + H2O ⇌ H3O+ + OH−
Expressed with chemical activities a, instead of concentrations, the thermodynamic equilibrium constant for the water ionization reaction is:
{\displaystyle K_{\rm {eq}}={\frac {a_{\rm {H_{3}O^{+}}}\cdot a_{\rm {OH^{-}}}}{a_{\rm {H_{2}O}}^{2}}}}
which is numerically equal to the more traditional thermodynamic equilibrium constant written as:
{\displaystyle K_{\rm {eq}}={\frac {a_{\rm {H^{+}}}\cdot a_{\rm {OH^{-}}}}{a_{\rm {H_{2}O}}}}}
under the assumption that the sum of the chemical potentials of H+ and H3O+ is formally equal to twice the chemical potential of H2O at the same temperature and pressure.[1]
Because most acid–base solutions are typically very dilute, the activity of water is generally approximated as being equal to unity, which allows the ionic product of water to be expressed as:[2]
{\displaystyle K_{\rm {eq}}\approx a_{\rm {H_{3}O^{+}}}\cdot a_{\rm {OH^{-}}}}
In dilute aqueous solutions, the activities of solutes (dissolved species such as ions) are approximately equal to their concentrations. Thus, the ionization constant, dissociation constant, self-ionization constant, water ion-product constant or ionic product of water, symbolized by Kw, may be given by:
{\displaystyle K_{\rm {w}}=[{\rm {H_{3}O^{+}}}][{\rm {OH^{-}}}]}
where [H3O+] is the molarity (≈ molar concentration)[3] of hydrogen or hydronium ion, and [OH−] is the concentration of hydroxide ion. When the equilibrium constant is written as a product of concentrations (as opposed to activities) it is necessary to make corrections to the value of {\displaystyle K_{\rm {w}}} depending on ionic strength and other factors (see below).[4]
At 25 °C and zero ionic strength, Kw is equal to 1.0×10−14. Note that as with all equilibrium constants, the result is dimensionless because the concentration is in fact a concentration relative to the standard state, which for H+ and OH− are both defined to be 1 molal (or nearly 1 molar). For many practical purposes, the molal (mol solute/kg water) and molar (mol solute/L solution) concentrations can be considered as nearly equal at ambient temperature and pressure if the solution density remains close to one (i.e., sufficiently diluted solutions and negligible effect of temperature changes). The main advantage of the molal concentration unit (mol/kg water) is to result in stable and robust concentration values which are independent of the solution density and volume changes (density depending on the water salinity (ionic strength), temperature and pressure); therefore, molality is the preferred unit used in thermodynamic calculations or in precise or less-usual conditions, e.g., for seawater with a density significantly different from that of pure water,[3] or at elevated temperatures, like those prevailing in thermal power plants.
We can also define pKw {\displaystyle \equiv } −log10 Kw (which is approximately 14 at 25 °C). This is analogous to the notations pH and pKa for an acid dissociation constant, where the symbol p denotes a cologarithm. The logarithmic form of the equilibrium constant equation is pKw = pH + pOH.
What is a definition for ergonomics?
If the molecule has n-C2 axes perpendicular to its Cn axis, choose True. Otherwise, choose False. Be sure to build a model or draw the structure before selecting your answer. If needed, search for the molecular structure online or in a textbook.XeF4[PdCl4]2−naphthalenefuran, C4H4O
Answer:
XeF4 True
[PdCl4]2− True
naphthalene True
Furan False
C4H4O False
Explanation:
From the given information:
Only XeF4; [PdCl4]2−; naphthalene are true. This is because their molecules contain -nC₂ axis which is perpendicular to the Cn axis. The image attached below shows the structural formula of each compound, there below, we can see that Furan only possesses one C₂ axis but not -nC₂ ⊥ C₂.
g 1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN3) into solid sodium and gaseous dinitrogen.
Answer: A balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide ([tex]NaN_{3}[/tex]) into solid sodium and gaseous dinitrogen is [tex]2NaN_{3}(s) \rightarrow 2Na(s) + 3N_{2}(g)[/tex].
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]NaN_{3}(s) \rightarrow Na(s) + N_{2}(g)[/tex]
Here, number of atoms present on reactant side are as follows.
Na = 1N = 3Number of atoms present on product side are as follows.
Na = 1N = 2To balance this equation, multiply [tex]NaN_{3}[/tex] by 2 on reactant side. Also, multiply Na by 2 and [tex]N_{2}[/tex] by 3 on product side.
The equation will be rewritten as follows.
[tex]2NaN_{3}(s) \rightarrow 2Na(s) + 3N_{2}(g)[/tex]
This equation contains same number of atoms on both reactant and product side. Hence, this equation is now balanced.
The symbols (s) and (g) depicts the physical state of substances present in the equation as solid and gas.
Thus, we can conclude that balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide ([tex]NaN_{3}[/tex]) into solid sodium and gaseous dinitrogen is [tex]2NaN_{3}(s) \rightarrow 2Na(s) + 3N_{2}(g)[/tex].
which element is found in period 6 group 14
Answer:
Lead
that can be found in the periodic table of elements
Explanation:
Equal masses of gaseous N2 and Ar are placed in separate flasks of equal volume at the same temperature. Tell whether each of the following statements is true or false. a. There are more molecules of N2 present than atoms of Ar. Blank 1 b. The pressure is greater in the Ar flask. Blank 2 c. The N2 molecules collide more frequently with the walls of the flask than do the Ar atoms.
Answer:
c. The N2 molecules collide more frequently with the walls of the flask than do the Ar atoms.
Explanation:
The statements are:
a. There are more molecules of N2 present than atoms of Ar. FALSE. Because 1 mol of molecules of N2 = 28g and 1 mol of molecules of Ar = 40g. As there are equal MASSES, you will have more molecules of N2 than Ar molecules
b. The pressure is greater in the Ar flask. FALSE
Because pressure is directly proportional to amount of molecules. As molecules N2 > Molecules Ar. The pressure is greater in N2 flask
c. The N2 molecules collide more frequently with the walls of the flask than do the Ar atoms. TRUE
The collision probability of N2 is higher because there are more molecules presents
What did ancient astronomers not know about eclipses?
Answer:
yes of course everyone know eclipse in ancient January 2004 eclipse was founded in other country's
An unknown compound (152 mg) was dissolved in water to make 75.0 mL of solution. The solution did not conduct electricity and had an osmotic pressure of 0.328 atm at 27°C. Elemental analysis revealed the substance to be 78.90% C, 10.59% H, and 10.51% O. Determine the molecular formula of this compound.
Answer:
The molecular formula of the compound is C10H16O.
Explanation:
Based on the given information, the mass of an unknown compound is 152 mg or 0.152 g, which was dissolved to produce 75 ml of solution.
The osmotic pressure of the solution is 0.328 atm at 27 degrees C or 300 K.
The formula of osmotic pressure is,
P = CRT
Now putting the values in the formula we get,
0.328 = C*0.0821*300
C = 0.013317
C = (mass/molecular mass) * (1000/volume of solution in ml)
0.013317 = (0.152/Molecular mass) * (1000/75)
Molecular mass = 152.186
C mass = 152.186 * 0.789 = 120.07 grams
C mole = 120.07/12 = 10
H mass = 152.186 * 0.1059 = 16.11 grams
H mole = 16.11/1 = 16
O mass = 152.186 - 120.07 - 16.116 = 16 grams
O mole = 16/16 = 1
Thus, the molecular formula of the compound will be,
C10H16O
Calculate the pH of a solution whose H3O+ concentration is 2.1 x 10-3 M. Is the solution acidc, basic, or neutral?
a
The pH of the solution is 2.7 and the solution is acidic.
b
The pH of the solution is 13.3 and the solution is acidic.
c
The pH of the solution is 13.3 and the solution is basic.
d
The pH of the solution is 2.7 and the solution is basic.
Answer:
Option A, The pH of the solution is 2.7 and the solution is acidic
Explanation:
As we know,
pH = - log [H3O+]
Substituting the given values, we get
pH = - log [2.1 x 10-3 M]
pH = - (-2.678)
pH = 2.678 or 2.7
The solution is acidic as pH value is less than 7
Hence, option A is correct
I have added 15 L of air to a balloon at sea level (1.0 atm). If I take the balloon with me
to Denver, where the air pressure is 0.85 atm, what will the new volume of the balloon
be?
Answer:17.65 or 18 L
Explanation:
What is the name of the molecule formed when two amino acids join
together?
O A. Peptide
B. Nucleic acid
C. Amine
O D. Disaccharide
Peptide is the name of the molecule formed when two amino acids join together. Therefore, the correct option is option A.
What is peptide?
Short strands of amino acids connected by peptide bonds are called peptidides. A polypeptide is a peptide chain that is longer, continuous, and unbranched. Proteins are polypeptides with a molecular weight of 10,000 Dalton or higher. Oligopeptides, which comprise dipeptides, tripeptides, and tetrapeptides, are chains of fewer than twenty amino acids.
Peptides, along with nucleic acids, oligosaccharides, carbohydrates, and others, belong to the vast chemical families of biological polymers or oligomers. Proteins are made up of one or even more polypeptides structured in a biologically useful manner. They are frequently coupled to other proteins, other macromolecules like DNA or RNA, or ligands like coenzymes and cofactors. Peptide is the name of the molecule formed when two amino acids join together.
Therefore, the correct option is option A.
To know more about peptide, here:
https://brainly.com/question/14351838
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A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?
Answer:
571.81 mL
Explanation:
Assuming constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:
V₁T₂=V₂T₁Where in this case:
V₁ = 852 mLT₂ = 200 KV₂ = ?T₁ = 298 KWe input the data:
852 mL * 200 K = V₂ * 298 KAnd solve for V₂:
V₂ = 571.81 mLThe new volume would be 571.81 mL.
Why hydrogen iodide is not produced by the same method is for HCL.
Answer:
acidic in the order. HBr and HI can't be prepared like H
They ic in the order . HBr & HI can,t be prepared like HCl by using Concentrated
Answer:
acidic in the order. HBr and HI can't be prepared like H
They ic in the order . HBr & HI can,t be prepared like HCl by using Concentrated
Interpreting Velocity vs. Time Graphs
Velocity vs Time
Use the information presented in the graph to answer
the questions,
Which segments show acceleration?
Which segment indicates that the object is slowing
down?
What is the velocity of segment B?
What is the acceleration of segment B?|
50
B
40
30
Velocity (m/s)
20
А
10
0
8 9 10
1 2 3 4 5 6 7
Time (s)
Answer:first part is A and C, second part is C, third part is 40 m/s and the fourth part is zero
Explanation: I guessed and got them right lol
define photo electric effect
Photoelectric effect, phenomenon in which electrically charged particles are released from or within a material when it absorbs electromagnetic radiation.
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Measure the initial temperature of the water to the nearest 0.1°C. Record in the data table.
Initial Temp. of Metal
Initial Temp. of water
Initial Temp. of Both
Subtract to find the temperature changes for the water and the metal
Water
Metal
The heat capacity of the metal is calculated using the formula:
Heat capacity = quantity of heat/(mass * temperature difference)What is temperature?
The temperature of a substance is the degree of hotness or coldness of that substance.
Temperature difference between substances enables heat flow.
Heat flows from hot to cold bodies.
In the given experiment, to determine the heat capacity of a metal, the temperature difference is obtained by substracting the initial and final temperatures.
The heat capacity of the metal is then calculated using the formula:
Heat capacity = quantity of heat/mass * temperature differenceLearn more about heat capacity at: https://brainly.com/question/21406849
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Find the mass of 0oC ice that 10 gof 100oC steam will completely melt. Latent heat of fusion of ice is 80cal/g oCand heat of vaporization of water 540 cal/g oC ?
Answer:
The right approach is "80 g".
Explanation:
Given:
[tex]L_f=80 \ Cal/g[/tex]
[tex]L_v=540 \ Cal/g[/tex]
[tex]S=1 \ Cal/g[/tex]
Now,
The amount of heat cooling will be:
= [tex]mL_v+mS \Delta T[/tex]
= [tex](10\times 540)+10\times 1\times (100-0)[/tex]
= [tex]5400+1000[/tex]
= [tex]6400 \ Cal[/tex]
then,
⇒ [tex]m_{ice} L_f=6400[/tex]
[tex]m_{ice}\times 80=6400[/tex]
[tex]m_{ice}=\frac{6400}{80}[/tex]
[tex]=80 \ g[/tex]
10. What is the molarity of a solution containing 20 moles of NaCl dissolved in 10 liters of water?
0.5 mol/L
2 mol/L
5 mol/L
10 mol/L
Answer:
2 mol/L
Explanation:
M=Mol of solute/L. of solution
M=20mol/10L of H2O= 2mol/L
Answer:
2mol/L
Explanation:
got it correct on my quiz