Which of these is a major drawback of using fuel cells in a car?
a lack of hydrogen filling stations
a drop in reliance on petroleum products
an increase in water vapor into the atmosphere
an increase in the use of rechargeable batteries

Which Of These Is A Major Drawback Of Using Fuel Cells In A Car?a Lack Of Hydrogen Filling Stationsa

Answers

Answer 1

A major drawback of using fuel cells in a car is a lack of hydrogen filling stations.

What is fuel cell?

A fuel cell is an electrochemical device that converts the energy stored in a fuel, typically hydrogen, directly into electrical energy.

One significant disadvantage of using fuel cells in a car is the scarcity of hydrogen filling stations.

While fuel cell technology has several advantages, including increased efficiency and lower emissions, the infrastructure for producing, transporting, and storing hydrogen is currently limited, making it difficult to refuel fuel cell vehicles on the road.

Because of this limitation, fuel cell vehicles are less suitable for long-distance travel and have a limited market penetration.

Thus, the answer is "a lack of hydrogen filling stations".

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Answer 2

Answer:

its A trust!!!!!

Explanation:


Related Questions

how can miscible liquids that different boiling points be separated

Answers

Answer:

By boiling and further condensing the liquid with the lowest boiling point.

Explanation:

Hello there!

In this case, according to the attached diagram, it turns out possible for us to infer that the mechanism whereby miscible liquids with different boiling points are separated is distillation, because the flask is heated until the boiling point of the liquid with the lowest value, in order to boil it and subsequently condense it, whereas the liquid with the highest boiling point remains in the flask; and therefore, the two liquids are separated.

Regards!

A “happy” atom is one that has a _________ valence orbital. octet rule

Answers

Answer:

Hello There!!

Explanation:

I believe the answer is 8.

hope this helps,have a great day!!

~Pinky~

The answer is 8 well it should be

For the reaction 2Na + Cl2 2NaCl, calculate the percent yield if
155.0 g of chlorine (Cl2) should be produced and your experiment
produced 143 g (C12).

Answers

Answer:

[tex]Y=92.25\%[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to calculate the percent yield by dividing the actual yield of 143 grams of gaseous chlorine by the theoretical yield of 155 g of this gas. In such a way, we proceed as follows:

[tex]Y=\frac{143g}{155g} *100\%[/tex]

Which has a result of:

[tex]Y=92.25\%[/tex]

Regards!

Is anyone good at chemistry if so can someone please help me NO LINKS PLEASE

Answers

Answer:

I think it's (a) all of the materials will reach the same temperature and heat flow will stop.

Calculate the molar mass of Ca3(PO4)2

934.32 g Ca3(PO4)2 =______
moles Ca3(PO4)2

Answers

Answer:

Molar mass of Ca₃(PO₄)₂ = 310.18 g/mol934.32 g Ca₃(PO₄)₂ = 3.01 moles Ca₃(PO₄)₂

Explanation:

The molar mass (MM) of Ca₃(PO₄)₂ can be calculated as follows:

MM of Ca₃(PO₄)₂ = (MM of Ca)*3 + [(MM of P) +(MM of O)*4]*2MM of Ca₃(PO₄)₂ = 310.18 g/mol

Now we can convert 934.32 g of Ca₃(PO₄)₂ into moles:

934.32 g ÷ 310.18 g/mol = 3.01 moles

1. The density of gasoline is 0.7 g/ml. What is the mass of 400L of gasoline?

Answers

Answer:

280,000g

Explanation:

0.7g/mL x 1000mL/1L x 400L = 280,000g

Questions
Determine the primary and secondary valencies of the following complexes and calculate their spin only magnetic
moment.
iii. [Cu(OH2)6]504
i. K[TI(CN).]
ii. [V(NH3)4Br2]
iv. K3 [Cr(CN)6]​

Answers

Answer:

yes

Explanation:

yes

Pls help I will give brainliest

Answers

Answer:

paki sagot naman pls para my isagot ako sa module ko ty

PPLLLLLZZZZZ HELPPPPPPPPP ME WITH THIS QUESTION BRAINLIEST ANY ANSWERS WOULD BE GREATLY APPRECIATED :) chemical reaction will stop when the limiting reactant is used up.
Question 1 options:
True
False

Answers

Jdjejenjrjrjrnnrnrnnndjdoekeme

How many total ions are there in 5.00 moles of cobalt (II) bromide?

Answers

15&89-28 you’re welcome bud

"When your heart was an open book" is an example of of
A. simile
B. metaphor
C. alliteration
D. all of the above

Answers

B. metaphor

The answer is metaphor, because it can't possibly be other thing.

Astronauts must be protected from extreme heat while
reentering the Earth's atmosphere. Scientists can use the
engineering design process to help make reentry safer.
You have defined the problem as a need for heat shields to be stronger. What
should be your next step in using the engineering design process to solve the
problem?
O A. Communicate your solution to your team members.
O B. Update your initial design for the heat shield.
O C. Identify the criteria and constraints of the project.
O D. Build a prototype of a possible new type of heat shield.​

Answers

The next engineering step to be taken is to update your initial design for the heat shield.

What is a heat sheild?

The term heat sheild refers to a device that can be used to shield an from astronaut  extreme heat especially as they re-enter the earth's atmosphere.

After you have identified the problem, the next engineering step to be taken is to update your initial design for the heat shield.

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In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: g

Answers

The question is incomplete. The complete question is :

In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: The color change will occur when [some amount] of NaOH is added because the color change occurs when [some condition]. The goal for your explanation is that it describes the outcome of this example, but can also be used to predict the outcome of other examples of this phenomenon. Here's an example explanation: The color of the solution will change when 40 ml of NaOH is added to a beaker of HCl because the color always changes when 40ml of base is added. Although this explanation works for this example, it probably won't work in examples where the flask contains a different amount of HCl, such as 30ml. Try to make an explanation that accurately predicts the outcome of other versions of this phenomenon.

Solution :

Consider the equation of the reaction between NaOH and [tex]$HCl$[/tex]

  NaOH (aq) + HCl (aq) → NaCl(aq) + [tex]$H_2O (l)$[/tex]

The above equation tells us that [tex]$1 \text{mole}$[/tex] of [tex]$NaOH$[/tex] reacts with [tex]$1 \text{mole}$[/tex] of [tex]$HCl$[/tex].

So at the equivalence point, the moles of NaOH added = moles of [tex]$HCl$[/tex]present.

If the volume of the [tex]$HCl$[/tex] taken = [tex]$V_1$[/tex] mL and the conc. of [tex]$HCl$[/tex] = [tex]$M_1$[/tex]  mole/L

The volume of NaOH added up to the color change = [tex]$V_2 \text{ and conc of NaOH = M}_2$[/tex] mole/L

Moles of [tex]$HCl$[/tex] taken = [tex]$V_1 \ mL \times M_1 \ mol/100 \ mL = V_2M_2 \times 10^{-3}$[/tex]  moles.

The color change will occur when the moles of NaOH added is equal to the moles of [tex]$HCl$[/tex] taken.

Thus when [tex]$V_1 M_1 \times 10^{-3} = V_2M_2 \times 10^{-3}$[/tex]

or   when    [tex]$V_1M_1 = V_2M_2$[/tex]

or [tex]$V_2=\frac{V_1M_1}{M_2}$[/tex]  mL of NaOH added, we observe the color change.

Where [tex]$V_1, M_1$[/tex] are the volume and molarity of the [tex]$HCl$[/tex] taken.

[tex]$M_2$[/tex] is the molarity of NaOH added.

When both the NaOH and [tex]$HCl$[/tex] are of the same concentrations, i.e. if [tex]$M_1=M_2$[/tex], then [tex]$V_2=V_1$[/tex]

Or the 40 mL of [tex]$HCl$[/tex] will need 40 mL of NaOH for a color change and

30 mL of [tex]$HCl$[/tex] would need 30 mL of NaOH for the color change (provided the concentration [tex]$M_1=M_2$[/tex])

A student has a sample of 1.42 moles of fluorine gas that is contained in a 28.1 L container at 305 K. What is the pressure of the sample?

Answers

Answer:

P = 1.26 atm

Explanation:

Given that,

The number of moles, n = 1.42 mol

Volume, V = 28.1 L

Temperature, T = 305 K

We need to find the pressure of the gas. The ideal gas law is as follows :

[tex]PV=nRT\\\\P=\dfrac{nRT}{V}[/tex]

R = 0.0821 L-atm/mol-K

Put all the values,

[tex]P=\dfrac{1.42 \times 0.0821\times 305 }{28.1 }\\\\P=1.26\ atm[/tex]

So, the pressure of the gas is 1.26 atm.

Select ALL of the abiotic factors

lesson 5.01

Question 1 options:

air


light


fungi


soil


salinity

Answers

Answer:

I think it should be

salinity and

light

identify two conjugate base for each compound HCN and HBr

Answers

The conjugate base of HCN is CN^-

The conjugate base of HBr is Br^-

AgI + KNO3 what type of reaction is this

Answers

Answer:

all + kn03

Explanation:

and the reaction is single replacement

Considering the side chain of each of the amino acids at pH 7.4, is that amino acid classified at neutral, basic, or acidic? You are currently in a sorting module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop. Neutral Basic Acidic

Answers

Answer:

Considering the side chain of each of the amino acids at pH 7.4, is that amino acid classified at neutral, basic, or acidic? You are currently in a sorting module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop. Neutral Basic Acidic

The answer is in the the images. I have placed all the structures in the specific boxes. I hope this helps.

what are the products of this reaction
Cu+AgNO3

Answers

Answer:

1 Cu + AgNO3 → Ag + CuNO3

2 Cu + Ag(NO3)2 → Ag + CuNO3

Explanation:

plzzz mark me brainliest

A chemistry student needs 30.0 g of acetic acid for an experiment. He has available 1.2 kg of a 7.58% w/w solution of acetic acid in acetone.
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Round your answer to 3 significant digits.

Answers

Answer:

The mass of solution will be "395.78 g".

Explanation:

Given:

Mass of acetic acid,

= 30 g

Percentage,

= 7.58% w/w

Now,

⇒ % [tex]=\frac{Mass \ of \ acetic \ acid}{Mass \ of \ solution}\times 100[/tex]

By putting the values, we get

⇒ [tex]7.58=\frac{30}{Mass \ of \ solution}\times 100[/tex]

⇒ [tex]Mass \ of \ solution=\frac{30\times 100}{7.58}[/tex]

⇒                               [tex]=\frac{3000}{7.58}[/tex]

⇒                               [tex]=395.78 \ g[/tex]

what volume of h2 can be produced at stp from 2 mol cah2 and excess water if the reaction goes 100% to completion?

Answers

Answer:

89.6 L of H₂ will be produced at STP from 2 moles of CaH₂ and excess water if the reaction goes to 100% completion.

Explanation:

The balanced chemical equation of the reaction between calcium hydride, CaH₂ and excess water to produce calcium hydroxide and hydrogen gas is given below:

CaH₂ (s) + 2H₂O (l) ----> Ca(OH)₂ (aq) + 2H₂ (g)

From the equation of the chemical reaction above, 1 mole of calcium hydride reacts with 2 moles of water to produce 2 moles of hydrogen gas.

Then, 2 moles calcium hydride will react with excess water to produce 2 × 2 -moles of hydrogen gas = 4 moles of hydrogen gas.

One mas a gas at STP has a volume of 22.4 L

4 moles of hydrogen gas will have a volume of 4 × 22.4 L = 89.6 L

Therefore, 89.6 L of H₂ will be produced at STP from 2 moles of CaH₂ and excess water if the reaction goes to 100% completion.

Once the concentration of the common ion is increased______.
a. the solubility of the ionic solid increases.
b. the solubility of the ionic solid decreases.
c. the solubility of the common ion increases.
d. the solubility of the common ion decreases.

Answers

Answer:

B

Explanation:

g For the reaction Ag2S(s)⇌2Ag+(aq)+S2−(aq)Ag2S(s)⇌2Ag+(aq)+S2−(aq), Keq=2.4×10−4Keq=2.4×10−4, and the equilibrium concentration of sulfide ion is [S2−]=0.0023M[S2−]=0.0023M. What is [Ag+]atequilibrium?

Answers

Answer:

0.32 M

Explanation:

Step 1: Write the balanced reaction at equilibrium

Ag₂S(s) ⇌ 2 Ag⁺(aq) + S²⁻(aq)

Step 2: Calculate the concentration of Ag⁺ at equilibrium

We will use the formula for the concentration equilibrium constant (Keq), which is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.

Keq = [Ag⁺]² × [S²⁻]

[Ag⁺] = √{Keq / [S²⁻]}

[Ag⁺] = √{2.4 × 10⁻⁴ / 0.0023} = 0.32 M

Pls help me with this

Answers

Answer:

[tex][I_2]=[Br]=0.31M[/tex]

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:

[tex]I_2+Br_2\rightleftharpoons 2IBr[/tex]

Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:

[tex]K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}[/tex]

Thus, we solve for x as show below:

[tex]\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M[/tex]

Therefore, the concentrations of both bromine and iodine are:

[tex][I_2]=[Br]=2.0M-1.69M=0.31M[/tex]

Regards!

When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II) sulfate PbSO4 is reduced to lead at the cathode and oxidized to solid lead(II) oxide PbO at the anode.Suppose a current of 62.0 is fed into a car battery for 23.0 seconds. Calculate the mass of lead deposited on the cathode of the battery. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.

Answers

Answer: The mass of lead deposited on the cathode of the battery is 1.523 g.

Explanation:

Given: Current = 62.0 A

Time = 23.0 sec

Formula used to calculate charge is as follows.

[tex]Q = I \times t[/tex]

where,

Q = charge

I = current

t = time

Substitute the values into above formula as follows.

[tex]Q = I \times t\\= 62.0 A \times 23.0 sec\\= 1426 C[/tex]

It is known that 1 mole of a substance tends to deposit a charge of 96500 C. Therefore, number of moles obtained by 1426 C of charge is as follows.

[tex]Moles = \frac{1426 C}{96500 C/mol}\\= 0.0147 mol[/tex]

The oxidation state of Pb in [tex]PbSO_{4}[/tex] is 2. So, moles deposited by Pb is as follows.

[tex]Moles of Pb = \frac{0.0147}{2}\\= 0.00735 mol[/tex]

It is known that molar mass of lead (Pb) is 207.2 g/mol. Now, mass of lead is calculated as follows.

[tex]No. of moles = \frac{mass}{molar mass}\\ 0.00735 = \frac{mass}{207.2 g/mol}\\mass = 1.523 g[/tex]

Thus, we can conclude that the mass of lead deposited on the cathode of the battery is 1.523 g.

Plz help me well mark brainliest if correct

Answers

Answer:

D) biodiversity

Explanation:

the answer is D) biodiversity

Which is the first step in the fusion process?

Answers

Explanation:

The first step of the Hydrogen fusion process: a nucleus of Deuterium (2H) is formed from two protons with the emission of an antielectron and a neutrino. The basic Hydrogen fusion cycle involves four Hydrogen nuclei (protons) and two electrons and yields a Helium nucleus, two neutrinos and six photons.

Answer:

C just took it

Explanation:

what is solubility? .​

Answers

Solubility is the ability of a solid, liquid, or gaseous chemical substance (referred to as the solute) to dissolve in solvent (usually a liquid) and form a solution. The solubility of a substance fundamentally depends on the solvent used, as well as temperature and pressure.

What happens in radioactive decay?
O A. An electron is lost to form a negatively charged particle.
O B. An unstable nucleus breaks down into smaller parts.
O C. Two smaller nuclei are joined to form one larger nucleus.
O D. A large nucleus breaks apart to form smaller nuclei.
SHIRME

Answers

A radioactive atom will spontaneously release radiation in the shape of energy rather than particles in order to transition into a more steady state.

Why is something radioactive?

Radioactivity, as its name suggests, seems to be the act of generating radiation without any external cause. This is carried out by an unstable atomic nucleus that "wants" to abandon certain power in order to change to a more stable form.

Are people radioactive at all?

Absolutely, since humans consume radioactive materials from the environment through food, drink, and air, our bodies are inherently radioactive. Our bodies take these substances in and store them in our bones, tissues, and organs. We also breathe them in and consume them.

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If a buffer solution is 0.190 M in a weak acid ( a=3.6×10−5) and 0.480 M in its conjugate base, what is the pH?

Answers

Solution :

[tex]pk_b = -log ( K_b)\\\\pk_b = - log ( 3.6 \times 10^{-5})\\\\pk_b = 4.44[/tex]

We know, pH of this solution :

[tex]pH = pK_a + log ( \dfrac{|conjugate\ base|}{|weak \ acid|}\\\\pH = 4.44 + log(\dfrac{0.480}{0.190})\\\\pH = 4.44 + 0.40\\\\pH =4.84[/tex]

Hence, this is the required solution.

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