Answer: The San Andreas Fault
Explanation: Hope this helps ^^
A piano tuner stretches a steel piano wire with a tension of 765 N. The steel wire has a length of 0.800 m and a mass of 6.00 g . What is the frequency f1 of the string's fundamental mode of vibration
Answer:
the frequency of the fundamental mode of vibration is 199.6 Hz
Explanation:
Given;
tension of the piano wire, T = 765 N
length of the steel wire, L = 0.8 m
mass of the steel wire, m = 6.00 g = 6 x 10⁻³ kg
The frequency of the fundamental mode of vibration is calculated as;
[tex]f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} }[/tex]
where;
μ is the mass per unit length [tex]= \frac{6.0 \times 10^{-3}}{0.8} = 7.5 \times 10^{-3} \ kg/m[/tex]
[tex]f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} } \\\\f_o = \frac{1}{2\times 0.8} \sqrt{\frac{765}{7.5 \times 10^{-3}} } \\\\f_o = 199.6 \ Hz[/tex]
Therefore, the frequency of the fundamental mode of vibration is 199.6 Hz
WHEN AN OBJECT IS DROPPED WHAT HAPPENDS TO THE POTENTIAL AND KENETIC ENERGY AS IT FALLS?
Answer:
The sum of an object's potential and kinetic energies is called the object's mechanical energy. As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy.
Explanation:
Answer:
the potential decrease and kinetic increase
Explanation:
because it goes from a state of rest to a state of movement
Who knows this how to do this
YOU do !
The question GIVES you all of the numbers for both formulas. Except for the 'k' in the formula for the electric force. That's (9•10^9).
All you have to do is pluggum into where they go.
Plug the charges into the electrical formula, plug the masses into the gravity formula, and plug the distance into both uvum.
Then mash both formulas with your calculator, to get one simple final number for each one.
You'll discover why gravity is completely ignored while working inside atoms.
What is R2 in the circuit?
WILL GIVE BRAINLIEST !!!!
Answer:
1. Rₑq = 4 Ω
2. R₂ = 6 Ω
3. Vₜ = 12 V, V₁ = 12 V, V₂ = 12 V
4. Iₜ = 3 A, I₁ = 1 A, I₂ = 2 A
Explanation:
1. Determination of the equivalent resistance
Voltage (V) = 12 V
Current (I) = 3 A
Resistance (Rₑq) =?
V= IRₑq
12 = 3 × Rₑq
Divide both side by 3
Rₑq = 12 / 3
Rₑq = 4 Ω
Thus, the equivalent resistance (Rₑq) = 4 Ω
2. Determination of R₂.
Equivalent resistance (Rₑq) = 4 Ω
Resistance 1 (R₁) = 12 Ω
Resistance 2 (R₂)
Since the resistor are in parallel arrangement, the value of R₂ can be obtained as follow:
Rₑq = R₁ × R₂ / R₁ + R₂
4 = 12 × R₂ / 12 + R₂
Cross multiply
4(12 + R₂) = 12R₂
48 + 4R₂ = 12R₂
Collect like terms
48 = 12R₂ – 4R₂
48 = 8R₂
Divide both side by 8
R₂ = 48 / 8
R₂ = 6 Ω
3. Determination of the total voltage (Vₜ), V₁ and V₂.
From the question given above, the total voltage is 12 V
Since the resistors are arranged in parallel connection, the same voltage will go through them.
Thus,
Vₜ = V₁ = V₂ = 12 V
4. Determination of the total current (Iₜ), I₁ and I₂
From the question given above, the total current (Iₜ) is 3 A
Next, we shall determine I₁. Since the resistors are arranged in parallel connection, different current will pass through each resistor respective.
Vₜ = V₁ = 12 V
R₁ = 12 Ω
I₁ =?
V₁ = I₁R₁
12 = I₁ ×12
Divide both side by 12
I₁ = 12 / 12
I₁ = 1 A
Next, we shall determine I₂. This can be obtained as follow:
Iₜ = 3 A
I₁ = 1 A
I₂ =?
Iₜ = I₁ + I₂
3 = 1 + I₂
Collect like terms
I₂ = 3 – 1
I₂ = 2 A
Two resistors 5 ohm's each can be combined to give an equivalent resistance of
Answer: 10 Ω or 2.5 Ω
Explanation:
In series resistance R = 5 Ω + 5 Ω =10 Ω. If resistors are parallel, resistance is
1/R = 1/5Ω+ 1/5Ω and R = 2,5 Ω
Suppose that the equation of motion for a particle (where s is in meters and t in seconds) is s=(1/3)t3−8t2+64t+3 . (a) Find the velocity and acceleration as functions of t. Velocity at time t = Acceleration at time t = (b) Find the acceleration after 1 second. Acceleration after 1 second: (c) Find the acceleration at the instant when the velocity is 0. Acceleration:
Answer:
a) v = t² -18 t + 64, a = 2 t - 18, b) a = -18 m / s², c) a = -2 m / s²
Explanation:
In this exercise they tell us the function of position with respect to time
s = ⅓ t³ - 8 t² + 64 t + 3
a) find the velocity and acceleration.
For this we use the definition of velocity and acceleration
v = ds / dt
a = dv / dt
we make the derivatives
v = t² -18 t + 64
a = 2 t - 18
b) for this part we substitute t = 1
a = 2 1 -18
a = -18 m / s²
c) let's find the time for which v = 0
0 = t² - 18 t + 64
this expression is a binomial or perfect
(x + a) ² = x² + 2 a x + a²
in this case
x = t
a = 8
(t-8) ² = t² - 16 t + 64
therefore the velocity is zero for when t = 8 s
the acceleration at this point is
a = 2 8 - 18
a = -2 m / s²
give an example of a linear device and a non linear device
Answer:
The example of the nonlinear element is a diode and some of the nonlinear elements are not there in the electric circuit is called a linear circuit. Some other examples of the non-linear elements are transistors, vacuum tubes, other semiconductor devices, iron core inductors, and transformers.
Explanation:
what is Newton's second law
Newton's Second Law of Motion states "The rate of change of momentum of a body is directly proportional to the applied unbalanced force in the direction of force".
A barometer reads 780 mm Hg. Mercury has a density of 1.36 x 10^4 kg /m^3.
What is the pressure of the atmosphere in N / m^2?
A 1.1 x 10^4 N/m^2
B 1.1 x 10^5 N/m^2
C 1.1 x 10^7 N/m^2
D 1.1 x 10^8 N/m^2
How do we get to the answer? According to the mark scheme, it's B.
Answer:
B
Explanation:
Pressure = density × g × height
[tex]p \: = (1.36 \times {10}^{4} )(10)(780 \times {10}^{ - 3} ) \\ p = 1.1 \times {10}^{5} [/tex]
The pressure of the atmosphere, when a barometer reads 780 mm Hg. Mercury which a density of 1.36 x 10^4 kg /m^3 is B 1.1 x 10^5 N/m^2
This problem can be solved using the formula below
P = dgh................. Equation 1
Where P = Pressure of the atmosphere, d = density of the mercury, h = height of the mercury, g = acceleration due to gravity.
From the question,
Given: d = 1.36×10⁴ kg/m³, h = 780 mm = 0.78 m,
Constant: g = 10 m/s²
Substitute these values into equation 1
P = (1.36×10⁴)(10)(0.78)
P = 10.608×10⁴ N/m²
P ≈ 1.1×10⁵ N/m²
Hence the right answer is B. 1.1×10⁵ N/m²
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what is the power output needed from a motor to lift in the absence of friction a mass of 1.5 ×10⁴ kg 25 m in 6.0 s at constant speed
Answer:
the power output needed is 61.25 × 10⁴
Explanation:
The computation of the power output needed is shown below;
Given that
m = 1.5 ×10⁴ kg
v = 25m ÷ 6.0 s
And g = 9.8 m/sec^2
Now based on the above information
p = f × v
= mg × v
= 1.5 ×10⁴ × 9.8 × 25 ÷ 6
= 61.25 × 10⁴
Hence, the power output needed is 61.25 × 10⁴
The circuit is protected by a ground fault interrupter in the plug. The water in the tank is grounded. The two bare wires correspond to the two pins on the ground fault interrupter plug. If the __________ wire is touched to the water, the ground fault interrupter will disconnect the circuit. Select the best answer from the choices provided. View Available Hint(s) Select the best answer from the choices provided. Neutral Hot Ground
Answer:
Hot
Explanation:
GFI or GFCI This device protected from collecting the electric shocks arise from the faults in the electric devices that are used at home. It would be work by comparing the current on the input side that shows the hot side to the current on the outside side that shows the neutral side
In the case when hot wire give 120 VAC current source while on the other hand the neutral wire gives the return path that are given by the hot wire
Hence, the hot would be the answer
What is one benefit to measuring your body’s flexibility?
A.
meeting the national requirement for flexibility
B.
determining your muscular strength
C.
tracking your flexibility improvements over time
D.
increasing the length of your life
Answer:
C
Explanation:
if you measure your body's flexibility then you can keep track of how flexible you have gotten over time
A rocket sled accelerates from rest for a distance of 645 m at 16.0 m/s2. A parachute is then used to slow it down to a stop. If the parachute gives the sled an acceleration of -18.2 m/s2 and there is 500.0 m of sled track remaining after the shoot opens, will the sled stop before running off the track? Show why or why not?
Answer:
the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake
Explanation:
This problem can be solved using the kinematics relations, let's start by finding the final velocity of the acceleration period
v² = v₀² + 2 a₁ x
indicate that the initial velocity is zero
v² = 2 a₁ x
let's calculate
v = [tex]\sqrt {2 \ 15.0 \ 645}[/tex]
v = 143.666 m / s
now for the second interval let's find the distance it takes to stop
v₂² = v² - 2 a₂ x₂
in this part the final velocity is zero (v₂ = 0)
0 = v² - 2 a₂ x₂
x₂ = v² / 2a₂
let's calculate
x₂ = [tex]\frac{ 143.666^2 }{2 \ 18.2}[/tex]
x₂ = 573 m
as the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake
PLEASE HELP ME WITH THIS
Answer:
Air masses tend to move from west to east.
What does the force of attraction called gravity act on?
A. every mass
B. no masses
C. nearby masses
D. select masses
Answer:
Every mass
Explanation:
Because Force of gravity always act toward the center of the earth , so when an object is thrown up ,the force of gravity will act in opposite direction of motion ,that's toward the center of earth. The force is towards the center of the Earth (more or less). which gives it time get touch every mass.
The gravitational force of attraction exists between every objects in the universe that are having mass. So, the correct option is A.
What is meant by the force of gravity ?Force of gravity is defined as the force of attraction experienced by bodies due to the gravitational field of earth.
Here,
The gravitational force is the attractive force experienced by any body that have mass. Gravity is an attractive force such that every bodies that are having mass in the earth are being attracted towards the centre of earth.
The equation of gravitational force is given by,
F = GMm/r²
where G is the gravitational constant of earth, M is the mass of earth and m is the mass of the body which is being attracted towards earth's centre, and r is the distance between earth and the body.
From the equation, it is shown that gravitational force is proportional to the masses. More the mass of the objects, more will be the gravitational force of attraction existing between them.
Hence,
The gravitational force of attraction exists between every objects in the universe that are having mass.
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which force acts during projectile motion
Answer: Gravity
Explanation:A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.
explain the working and performance of a centrifugal clutch with a sketch
a centrifugal clutch works, as the name suggests, through centrifugal force. ... The rotation of the hub forces the shoes or flyweights outwards until they come into contact with the clutch drum, the friction material transmits the torque from the flyweights to the drum. The drive is then connected
a car is travelling at 18m/s accelerates ti 30m/s in 3seconds. what's the acceleration of the car
[tex] \Large {\underline { \sf {Required \; Solution :}}}[/tex]
We have ―
Initial velocity, u = 18 m/sFinal velocity, v = 30 m/sTime taken, t = 3 secondsWe've been asked to calculate acceleration.
[tex]\qquad \implies\boxed{\red{\sf{ a = \dfrac{v-u}{t} }}}\\[/tex]
a denotes accelerationv denotes final velocityu denotes initial velocityt denotes time[tex] \twoheadrightarrow \quad \sf {a = \dfrac{30-18}{3} \; ms^{-2} } \\ [/tex]
[tex] \twoheadrightarrow \quad \sf {a =\cancel{ \dfrac{12}{3} \; ms^{-2} }} \\ [/tex]
[tex]\twoheadrightarrow \quad \boxed{\red{\sf{ a = 4 \; ms^{-2} }}}\\[/tex]
Therefore, acceleration of the car is 4 m/s².
I’ll give points plz and brainliest I know the result I just need the process.
4. How much work is required to lift a 500 kg block 12 m2?
A magnetic field is passing through a loop of wire whose area is 0.014 m^2. The direction of the magnetic field is parallel to the normal to the loop, and the magnitude of the field is increasing at the rate of 0.19 T/s.
a. Determine the magnitude of the emf induced in the loop.
b. Suppose the area of the loop can be enlarged or shrunk. If the magnetic field is increasing as in part (a), at what rate (in m^2/s) should the area be changed at the instant when B = 1.6 T if the induced emf is to be zero? (Give the magnitude of the rate of change of the area.) (m^2/s). Explain whether the area is to be enlarged or shrunk.
Answer:
a. 0.00266v
b. -0.0016625
the area should be shrunk
Explanation:
the magnitude of the EMF induced in the loop
= area * rate
= 0.014 * 0.19
= 0.00266 V
B we are to solve for the rate at which the are has to be change with B = 1.6
δA/δt = -A/B * dB/dt
= (-0.014 * 0.19) /1.6
= -0.0016625
the sign is negative so the EMT is negative and so the area has to be shrunk.
2. Oscar walked to the milktea house for a snacks. He walk 2 kilometers
east, 2 kilometers south, and 2 kilometers west. What distance did he
cover? What was the displacement?
The distance Oscar covered was 6km while the displacement was 2km.
What is Displacement?Displacement is defined as the vector whose length is the shortest
distance from the initial to the final position of a point M.
Distance = Total length of space between points
= 2km+ 2km+ 2km = 6km.
Displacement = 2km.
This is because it is the shortest distance from the positions in this
scenario.
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In one cycle of any heat engine
A. the net work done is larger than the heat exhausted.
B. more heat flows from the engine than enters the engine.
C. The internal energy of the engine does not change.
D. the net heat flow is zero.
Answer:
D. the net heat flow is zero
Explanation:
In one cycle of any heat engine, three things happen:
Heat is added; this causes high temperature in the engine ([tex]Q_H[/tex])Some of the energy from that input heat is used to perform work (W). The rest of the heat is removed at a relatively cold temperature ([tex]Q_C[/tex]).[tex]Q_H = W + Q_C[/tex]
Conclusively, the net heat flow is zero
Which of the following is true about scientific knowledge?
OA. It can be changed as new information becomes available.
OB. It cannot be changed under any circumstances.
OC. It can be changed only if all scientists approve the change.
OD. It can be changed without information that supports the change.
The true statement about scientific knowledge is it can be changed as new information becomes available.
option A
What is scientific knowledge?Science is a dynamic process, and scientific knowledge is continually evolving as new data and evidence are discovered.
Scientific theories and hypotheses are constantly being tested and refined, and they can be modified or even rejected if new evidence contradicts them.
This is one of the key features of the scientific method - that it is self-correcting and always open to revision based on new evidence.
Thus, the true statement about scientific knowledge is it can be changed as new information becomes available.
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1. A 455 g mass, hanging at rest on a spring, stretches the spring 22.4 cm beyond its relaxed
position. What is the spring constant of that spring?
Answer:
19.9 N/m
Explanation:
From the question,
Applying Hook's law
F = Ke.................. Equation 1
Where F = Force on the spring, k = spring constant, e = extension
But the force on the spring is the weight of the mass
Therefore,
mg = ke.................. Equation 2
Where m = mass. g = acceleration due to gravity
make e the subject of the equation
e = mg/e................ Equation 3
Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,
Constant: g = 9.8 m/s²
Substitute these values into equation 3
e = (0.455×9.8)/0.224
e = 19.9 N/m
The spring constant of the given spring is 20 N/m.
The given parameters:
Mass attached, m = 455 g = 0.455 kgExtension of the spring, x = 22.4 cm = 0.224 mThe spring constant is calculated by applying Hooke's law as follows;
[tex]F = kx\\\\mg = kx\\\\k = \frac{mg}{x} \\\\k = \frac{0.455 \times 9.8}{0.224} \\\\k = 20 \ N/m[/tex]
Thus, the spring constant of the spring is 20 N/m.
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1. The nearest distance of distinct vision of
a hypermetropial person is 60 cm. If this
distance is reduced by 20 cm by using
spectacles. What is the nature and focal
length of the lens?
a. +30 cm b. +35 cm
-30 cm
d. -40 cm
c.
Answer:
The focal length of the lens is +30 and it is a convex lens.
Explanation:
Given that,
The nearest distance of distinct vision of a hypermetropial person is 60 cm, v = -60 cm
The distance is reduced by 20 cm, u = -20 cm
We need to find the nature and focal length of the lens.
Let f be the focal length of the lens. Using lens formula,
[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{f}=\dfrac{1}{(-60)}-\dfrac{1}{(-20)}\\\\f=+30\ cm[/tex]
So, the focal length of the lens is +30 and it is a convex lens.
a pool and stops at the
Which best describes his
motion?
A. Linear
B. Projectile
C. Vibrational
In Linear motion the swimmer swims
Answer: A
Explanation: Linear motion.
1 ) when a ball is projected upwords its time of rising is ...............the time of falling .
a) greater than b) smaller than c) equal to d ) double
2 ) when an object falls freely under the effect of gravity , the distance moved is
a ) directly proportional to time
b ) inversely proportional to time
c ) directly proportional to square of time
d ) inversely proportional to square of time.
Answer:
correct answer is C
Explanation:
In this exercise, you are asked to complete the sentences so that the sentence makes sense.
1) in projectile launching, the only force that acts is gravity in the vertical direction, so the time of going up is EQUAL to the time of going down
correct answer C
2) when a body falls freely, the acceleration is the ratio of gravity, therefore if it starts from rest, its height is
y = v₀ t - ½ gt²
v₀ = 0
y = -1/2 g t²
so the position is not proportional to the square of the time
correct answer is C
Monochromatic light is incident on a pair of slits that are separated by 0.240 mm. The screen is 2.80 m away from the slits. (Assume the small-angle approximation is valid here.) (a) If the distance between the central bright fringe and either of the adjacent bright fringes is 1.62 cm, find the wavelength of the incident light.
Answer:
λ = 1.388 x 10⁻⁶ m = 1388 nm
Explanation:
We can use the Young's Double Slit experiment formula here to solve this numerical:
[tex]\Delta x = \frac{\lambda L}{d} \\\\\lambda = \frac{\Delta x d}{L}\\[/tex]
where,
λ = wavelength = ?
Δx = distance between adjacent bright fringes = 1.62 cm = 0.0162 m
d = slit separation = 0.24 mm = 0.00024 m
L = distance from screen to slits = 2.8 m
Therefore,
[tex]\lambda = \frac{(0.0162\ m)(0.00024\ m)}{2.8\ m} \\[/tex]
λ = 1.388 x 10⁻⁶ m = 1388 nm
What is earth's magnetic field made of
Answer:
if you have a rotating electric current it will create a magnetic field on earth flowing of liquid metal in the outer core of the planets General Health recurrence the rotation of earth on its Axis causes this electric current to form a magnetic field which extends around the planet.
Explanation:. please give me brainlest
Question 12 of 34 Which of the following means that an object is slowing down? /13 ယာ O A. Its velocity is decreasing. B. Its acceleration is increasing. O C. Its acceleration is decreasing. O D. Its velocity is increasing.
Answer:
A. Its velocity is decreasing
Explanation: