Which of the following values does not satisfy the equation x-2=3.5

A 5 1/2

B 5.5

C 1.5

Answers

Answer 1
1.5 does not satisfy the equation

Related Questions

the jawbreaker machine

Answers

Answer:

D.

Step-by-step explanation:

If you add them all up and subtract 30 you get 60

I MAYBE MESSED UP // haven't done this math in a while

Helpppp hurry and no links please

Answers

Answer:

8.3

Step-by-step explanation:

what is the square root of 36x6y2​

Answers

Step-by-step explanation:

Please refer to the attachment

What's the slope and y-intercept of the graph of 7x + y = 8? Question 4 options: A) Slope = –7, y-intercept = 8 B) Slope = –7, y-intercept = –8 C) Slope = –8, y-intercept = 7 D) Slope = 7, y-intercept = 8

Answers

Slope is -7 and the y-intercept is 8

Answer:

Slope is -7 and the y-intercept is 8

Step-by-step explanation:

Brianna has six bags of soil filling one flower pot requires 1/3 of a bag of soil how many flower pots can be filled with the six flags

Answers

Answer:

18

Step-by-step explanation:

[tex]\frac{6}{1}[/tex] ÷ [tex]\frac{1}{3}[/tex]

Keep Change Flip

[tex]\frac{6}{1}[/tex] × [tex]\frac{3}{1}[/tex] = [tex]\frac{18}{1}[/tex]

The dot plot below shows the number of concerts students at Albus Middle School have attended.

What is the interquartile range of the data set shown?
A. 2
B. 6
C. 3
D. 1

Answers

Answer:

2

Step-by-step explanation:

The interquartile range of the given data set is 2.

We need to find the interquartile range of the data set given.

How to find the interquartile range?

To find the interquartile range (IQR), ​first, find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

The given set of data is

0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6

To find Q1:

The lower half of the numbers are

That is 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2,

So the median of the lower half (Q1)=1

To find Q3:

The upper half of the numbers are 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6

So the median of the upper half (Q3)=3

Then, IQR=Q3-Q1=3-1=2

Therefore, the interquartile range of the given data set is 2.

To learn more about the interquartile range visit:

https://brainly.com/question/15686744.

#SPJ5


Graph the linear equation.

Answers

does that say y=4x-1??
Wot wot wot wot wot wot

) Find the area of the shape. *

Answers

Answer:

20 + 75 = 95

Step-by-step explanation:

10 - 5 = 5 x 4 = 20

5 x 15 = 75

Add them together,

75 + 20 = 95

Hi I hope you have a great day

how many rhombuses in a trapezoid?

Answers

1 a trapezoid is a rhombus
It would be 2 hope it helps.

Which expression is equivalent to 4(m+2)?

Answers

Answer:

=4m+8

Step-by-step explanation:

=(4)(m+2)

=(4)(m)+(4)(2)

=4m+8

Answer:

4m +8

Step-by-step explanation:

Take out the parenthesis

A teacher buys a binder for $1.75 and a monthly planner for $9.50 for each student in their classroom. The teacher spends a total of $562.50 for all of the binders and monthly planners.
How many students are in the teacher's class?
Please help I need the answer ASAP

Answers

Answer:

for 1 student it would equal 11.25

11.25 x 50 = 562.50

ur answer is 50 students hope this helps :)

Answer:

the teacher has 50 students

Step-by-step explanation:

1.75+9.50=11.25

562.50/11.25=50

Cylinders a and b each stated with different amounts of water. The graphs shows how the height of the water changed as the volume of the water increased in each cylinder. Which cylinder has the larger radius? a or b

Answers

uh i think its a but ok

A tank contains 350 liters of fluid in which 40 grams of salt is dissolved. Pure water is then pumped into the tank at a rate of 5 L/min; the well-mixed solution is pumped out at the same rate. Let the A(t) be the number of grams of salt in the tank at time t. Find the rate at which the number of grams of salt in the tank is changing at time t.

Answers

Answer:

[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]

A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]

Step-by-step explanation:

Given - A tank contains 350 liters of fluid in which 40 grams of salt is dissolved. Pure water is then pumped into the tank at a rate of 5 L/min; the well-mixed solution is pumped out at the same rate. Let the A(t) be the number of grams of salt in the tank at time t.

To find - Find the rate at which the number of grams of salt in the tank is changing at time t.

Find the number A(t) of grams of salt in the tank at time t.

Proof -

Given that,

Total fluid in the tank = 350 litres

Total salt = 40 grams

Rate in flow = 5 L/min

Rate out flow = 5 L/min

Concentration in = 0

Concentration out = (Amount of salt at time t )/ (Solution in tank at time t)

Now,

Total solution in the tank at time t = Total fluid in the tank + (Rate in flow - Rate out flow )t

                                                        = 350 + (5 - 5)t

                                                        = 350

⇒Solution in the tank at time t = 350

⇒Concentration out = [tex]\frac{A(t)}{350}[/tex]

Now,

Rate of change in the tank at time t = [tex]\frac{dA}{dt}[/tex]

                                                           =  (Rate in flow )( Concentration In) - (Rate out flow )( Concentration out)

                                                           = 5(0) - 5([tex]\frac{A(t)}{350}[/tex])

                                                           = 0 - [tex]\frac{A(t)}{70}[/tex]

                                                           = [tex]-\frac{A(t)}{70}[/tex]

⇒[tex]\frac{dA}{dt}[/tex] = [tex]-\frac{A(t)}{70}[/tex]

⇒[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]

Integrate both sides , we get

ln(A) = [tex]-\frac{1}{70}t + C[/tex]

⇒A(t) = [tex]e^{-\frac{t}{70}+ C}[/tex]

         = [tex]e^{-\frac{t}{70}}*e^{C}[/tex]

         = [tex]C_{1} e^{-\frac{t}{70}}[/tex]

⇒A(t) = [tex]C_{1} e^{-\frac{t}{70}}[/tex]

Now,

Given that,

Initially, the tank has 40 grams of salt

⇒A(0) = 40

⇒C₁ = 40

⇒A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]

Tony and Edwin each built a rectangular garden. Tony’s garden is 4 feet longer and 5 feet wider than Edwin’s garden. If the perimeter of Edwin’s garden is 36 feet, what is the perimeter of Tony’s garden?

Answers

First look at the in for on Tony's garden, it is equal to 2(w) and 2(L) as Edwins Garden. Second. Look at Edwins Garden. The area is is 600 sq ft. and we know that Area is the formula A = L(w) so the equation for Edwin is 600 = L(W) If Tonys garden is 2(L) and 2(w) then it is 4 times the size of Edwins. So 600 times 4 equals 2400.

A lake is 200 feet wide. Two boats start to move towards one another from opposite shores. In one minute, the first boat goes 40 feet, and the second boat goes 30 feet (they are very slow!).

Answers

Answer:

I use faction

Step-by-step explanation:

The first boat.

[tex]\frac{40 feet}{60 seconds}[/tex] ÷ 10 = [tex]\frac{4 feet}{6 seconds}[/tex]

[tex]\frac{4 feet}{6 seconds}[/tex] ÷ 2 = [tex]\frac{2 feet}{3 seconds}[/tex]

The first boat move [tex]\frac{2 feet}{3 seconds}[/tex]

The second one do the same

[tex]\frac{30 feet}{60 seconds}[/tex] ÷ 10 = [tex]\frac{3 feet}{6 seconds}[/tex]

[tex]\frac{3 feet}{6 seconds}[/tex] ÷ 2 = [tex]\frac{1.5 feet}{3 seconds}[/tex]

That is the speed of each boat.

The first boat need 50 minutes to get to the other side

2000 ÷ 2 =1000

1000 x 3 = 3000

3000 ÷ 60 = 50

The second boat need 66.6666666667 minutes to get to the other side

200 ÷1.5 = 1333.33333333

1333.33333333 x 3 = 4000

4000 ÷ 60 = 66.6666666667

X-7>29 inequalities someone please help

Answers

Answer:

x>36

Step-by-step explanation:

Hope this helps and good luck

What is the solution to the following system?
x+2y+z=9
x-y+3z=13
2z=10

Answers

Answer:

x=0 y=2 z=5

Step-by-step explanation:

so for z

2z=10

divid both side by 2

z=5

equation one

x+2y+5=9

x+2y=4 ------eqn1

equation two

x-y+ 3(5)=13

x-y+15=13

x-y=-2-----eqn2

now you solve it by elimination

eqn1-eqn2

3y=6

y=2

put y=2 into eqn2

x-2=-2

x=0

The first Portuguese explorer to lay claim to Brazil was

Question 3 options:

Getulio Vargas


a Jesuit priest


Pedro Cabral


Ferdinand Magellan

Answers

Answer:

Cabral is right

Step-by-step explanation:

Mark me brainleyest plz

Lucy invested $19,000 in an account paying an interest rate of 3% compounded annually. Assuming no deposits or withdrawals are made, how much money, to the nearest hundred dollars, would be in the account after 8 years?​

Answers

23560
3% of 19k is 570
570*8=4560
4560+19000=23560
(I hope this is right)

Answer:

Step-by-step explanation:

A=19000( 1 + 0.03)^8

A=24068.6315464

A≈24100

Round to the nearest hundred dollars

72 - 4
f(x) = 3x3 + 8x2
= 2x
6
Find (f - g)(x).
5x + 2
9x + 2
O A. (f - g)(x) = 3x3 + 822
O B. (f - g)(x) = 3x3 + 8x2
O c. (f - g)(x) = 323 + 8x2
O D. (f - g)(x) = 3x3 + 8x2
9x
10
53
-
10

Answers

Answer:

B.

Step-by-step explanation:

(f-g)(x) = f(x) - g(x) =

= (3x³ + 8x² -7x - 4) - (2x - 6) = 3x³ + 8x² - 7x - 4 - 2x + 6 =

= 3x³ + 8x² - 9x + 2

Dave sold 60 general and reserved tickets for a concert. He sold general tickets for $10 each and reserved tickets for $15 each collecting a total of $725. Write a system of equations to determine the number of tickets he sold at each price and solve your system of equations?

Answers

Answer:

The system is of equations is:

[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]

Where g is the amount of general tickets and r is the amount of reserve tickets.

35 general tickets and 25 reserve tickets were sold.

Step-by-step explanation:

Let general tickets be represented by g and reserved tickets be represented by r.

Each general ticket sells for $10 each and reserved tickets $15 each. Dave collected a total of $725. Thus:

[tex]10g+15r=725[/tex]

And a total of 60 tickets were sold. Hence:

[tex]g+r=60[/tex]

Our system of equations is:

[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]

We can solve by substitution. First, divide both sides of the first equation by 5:

[tex]2g+3r=145[/tex]

Next, we can subtract a variable (r in this case) from the second equation:

[tex]g=60-r[/tex]

Substitute:

[tex]2(60-r)+3r=145[/tex]

Distribute:

[tex]120-2r+3r=145[/tex]

Simplify:

[tex]120+r=145[/tex]

Subtract:

[tex]r=25[/tex]

Using the previous equation:

[tex]g=60-r[/tex]

Substitute and evaluate:

[tex]g=60-(25)=35[/tex]

So, 35 general tickets and 25 reserve tickets were sold.

-4x-y=24−4x−y=24minus, 4, x, minus, y, equals, 24 Complete the missing value in the solution to the equation.

Answers

Answer:

-4x-y=24......1

24−4x−y=24

substituting value of−4x−y

24-24=24

it has no solution. I think question is incomplete

Answer:-8 on khan academy

Step-by-step explanation


Write a ratio for each phrase :
5 cupcakes for every 2 children

Answers

5/2
....................

inverse operation needed​

Answers

Answer:

it is C.

Step-by-step explanation:

we know,

14+17= 31

so if we subtarct 17 from 31 we get 14

and if we subtract 14 from 31 we get 17

Liam, Sarah and Emily shared some money in the ratio 3:6:8
Emily got £80 more than Liam.
How much money did Sarah get?

Answers

hdndhdjhdbhsjdwkdbdjdjdd

What is the equation that describes the function please help

Answers

Answer:It’s the third choice y=3x+1

Step-by-step explanation:

The perimeter of a rectangle is 72 meters. The width of the rectangle is 4 meters less than the
length. Find the length and width of the rectangle. (Use I for the length)
e meters
le - 4) meters

Answers

Answer:

Step-by-step explanation:

Perimeter = 2l + 2w

With the given statement, the width of the rectangle is 4 meters less than the

length,

w = l - 4

sub that in the first equation,

Perimeter = 2l + 2(l - 4)

Perimeter = 2l + 2l - 8

Perimeter = 4l - 8

Since perimeter is 72m,

72 = 4l - 8

4l = 80

l = 20m

HELP ME.,,,,,,,,,,,,,,,,,,,

Answers

Answer:

Step-by-step explanation:

Use pythagorean theorem

9^2 +40^2=x^2

81+1600=x^2

1681=x^2

now find the square root of each side

[tex]\sqrt{1681} =\sqrt{x}[/tex]

x=41

justin is 7 meters below the surface of the water and ben is 3 meters above justin. what is bens position Relative to the surface of the water​

Answers

Answer:

Ben stands 4 meter below Surface water

Step-by-step explanation:

In the given situation,

Justin stands 7 meter below Surface water

Ben stands 3 meter above Justin

So,

We can say that Ben stands (7-3) meter below Surface water.

Ben stands 4 meter below Surface water.

What is the area of this figure?

Enter your answer in the box.

Answers

Answer:

20

Step-by-step explanation:

add 3ft+3ft+11ft+3ft and that's your answer

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