Which of the following represents the greatest pressure?

O 0.625 atm

O 755 mmHg

O 15.10 PSI

O 90,250 Pa

According to the trends method of forecasting, the snowstorm will arrive in about 4 hours with speed of 35 miles/hr. The correct answer is option A.

We can use the formula:

Time = Distance / Speed

to calculate the time it will take for the snowstorm to reach your town.

The distance between the snowstorm and your town is 140 miles, and it is moving at a speed of 35 miles per hour.

Time = 140 miles / 35 miles per hour

Time = 4 hours

The solution provided above uses the formula:

Time = Distance / Speed

This formula relates the time it takes for an object to travel a certain distance to the speed at which it is traveling. In this case, the object is the snowstorm, the distance is the distance between the snowstorm and your town (140 miles), and the speed is the speed at which the snowstorm is moving (35 miles per hour).

When we divide the distance (140 miles) by the speed (35 miles per hour), we get a result of 4 hours. This means that it will take the snowstorm 4 hours to travel the distance of 140 miles and reach your town. The trends method of forecasting assumes that the speed and direction of the snowstorm will remain constant, and therefore we can use this formula to estimate the time it will take for the snowstorm to arrive. It is important to note that this method is based on the assumption that the speed and direction of the snowstorm will not change, and therefore may not be accurate in all situations. Additionally, weather forecasting is a complex process that involves many factors, and the trends method is just one of many methods used to forecast weather.

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This means that for every 2 moles of carbon dioxide produced, 3 moles of oxygen are consumed. Conversely, for every 3 moles of oxygen consumed, 2 moles of carbon dioxide are produced.

What is Molar Ratio?

The molar ratio is a term used in chemistry that describes the ratio between the number of moles of one substance in a chemical reaction to another substance in the same reaction.

In a balanced chemical equation, the coefficients that are written in front of each reactant and product represent the relative numbers of moles of each substance that are involved in the reaction. The molar ratio is simply the ratio of the coefficients of any two substances in the reaction

The balanced chemical equation is:

C2H4 + 3O2 → 2CO2 + 2H2O

From this equation, we can see that the molar ratio of carbon dioxide (CO2) to oxygen (O2) is 2:3.

It's important to note that the molar ratio is based on the coefficients of the balanced equation, which represent the relative number of molecules or moles of each substance involved in the reaction. The molar ratio can be used to calculate the amount of reactants or products involved in the reaction, given the amount of one of the substances.

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Answer:

The molar mass of aspirin (C9H8O4) can be calculated as follows:

1 mol C = 12.01 g

9 mol C = 9 x 12.01 g = 108.09 g

8 mol H = 8 x 1.01 g = 8.08 g

4 mol O = 4 x 16.00 g = 64.00 g

Total molar mass of aspirin = 180.17 g/mol

To determine the number of aspirin molecules in 200 mg of aspirin, we first need to convert the mass of aspirin to moles:

200 mg aspirin x (1 g / 1000 mg) x (1 mol / 180.17 g) = 0.001110 moles aspirin

Next, we use Avogadro's number to convert moles of aspirin to molecules:

0.001110 moles aspirin x 6.022 x 10^23 molecules/mol = 6.68 x 10^20 aspirin molecules

Therefore, there are approximately 6.68 x 10^20 aspirin molecules in 200 mg of aspirin.

0.128 moles of O2 were collected.

The purpose of collecting the oxygen over water is to prevent any other gas from entering the collection vessel. The water acts as a barrier to keep out other gases.

To determine the moles of O2 collected, we need to correct for the presence of water vapor in the sample. At 25.00°C, the vapor pressure of water is 23.76 mmHg or 0.0313 atm.

First, we can calculate the partial pressure of oxygen:

P(O2) = total pressure - vapor pressure of water

P(O2) = 0.886 atm - 0.0313 atm

P(O2) = 0.8547 atm

Next, we can use the ideal gas law to calculate the moles of O2:

n = PV/RT

where P is the partial pressure of O2, V is the volume of the sample, R is the gas constant (0.08206 L·atm/(mol·K)), and T is the temperature in Kelvin (25.00°C + 273.15 = 298.15 K).

n = (0.8547 atm)(2.92 L)/(0.08206 L·atm/(mol·K))(298.15 K)

n = 0.107 mol

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Answer:

The balanced chemical equation for the reaction between butanoic acid and ethanol to produce ethyl butyrate is:

CH3CH2CH2COOH + C2H5OH → CH3CH2CH2COOC2H5 + H2O

From the equation, we can see that 1 mole of butanoic acid reacts with 1 mole of ethanol to produce 1 mole of ethyl butyrate and 1 mole of water. The molar mass of butanoic acid is 88.11 g/mol and the molar mass of ethyl butyrate is 116.16 g/mol.

To find out how many grams of ethyl butyrate can be produced from 8.55 g of butanoic acid, we first need to determine how many moles of butanoic acid are present:

moles of butanoic acid = mass / molar mass = 8.55 g / 88.11 g/mol = 0.097 mol

Since the reaction has a yield of 78.0%, we can calculate the theoretical yield of ethyl butyrate as follows:

theoretical yield = moles of butanoic acid × (1 mol ethyl butyrate / 1 mol butanoic acid) × 78.0%

= 0.097 mol × 1 × 0.78

= 0.0757 mol

Finally, we can calculate the actual mass of ethyl butyrate produced using its molar mass:

mass of ethyl butyrate = moles of ethyl butyrate × molar mass

= 0.0757 mol × 116.16 g/mol

= 8.80 g

Therefore, from 8.55 g of butanoic acid and excess ethanol, the chemist can produce 8.80 g of ethyl butyrate with the more efficient catalyst.

Replacement is the reaction that occurs when one atoms swaps places with another in a compound or when two components in two separate compounds switch places.

Breaking chemical bonds between reactant molecules (particles) and creating new bonds between atoms in product particles are two aspects of chemical reactions (molecules). While there are the same number of atoms both before and after the chemical transition, there will be a change in the number of molecules.

When atoms establish or break chemical bonds, chemical processes take place. Reactants are the substances that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.

When two atoms collide to create a heavier atom, such as when two hydrogen atoms combine to create one helium atom, this process is known as fusion. The sun is powered by a similar mechanism that generates enormous amounts of energy that are many times bigger than those produced by fission.

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The hydrogen ion has a concentration of 1000 times more than the hydroxide ion, which has a concentration of 3.1623× 10^9 M.

Assume that x is the hydroxide ion concentration.

x=[OH−]

If the hydrogen ion is 1000 times more abundant, then [H+]=1000x (x)=1.010^14x^2=1.010^14

1000x=√1.010^14

1000x=3.162310^9

[OH] =3.1623×10^9 M

Hence, 3.1623 10^9 M of hydroxide ions are present.

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The molarity of the solution is 1.112 M. To calculate the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).

The number of moles per litre of solution is how it is defined. It is employed to calculate the gramme equivalent in respect to the entire solution volume. It is employed for calculating the mole ratio in the solution's overall volume. Normality is measured in N or eq L-1 units.

First, you need to convert the given mass of NaCl into moles. The molar mass of NaCl is 58.44 g/mol.

Number of moles of NaCl = 65 g / 58.44 g/mol = 1.112 mol

Now, you can calculate the molarity of the solution using the formula:

Molarity = Number of moles of solute / Volume of solution in liters

Molarity = 1.112 mol / 1 L

Molarity = 1.112 M

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Answer:

To calculate the number of grams in 1.75 moles of CO2, we need to use the molar mass of CO2, which is 44.01 g/mol.

The calculation is:

1.75 mol CO2 x 44.01 g/mol = 77.0175 g CO2

Therefore, there are 77.0175 grams of CO2 in 1.75 moles of CO2.

Explanation:

Answer:

First, let's find the moles of NaOH:

moles NaOH = Molarity x Volume (L)

moles NaOH = 0.700 mol/L x 0.01100 L

moles NaOH = 0.00770 mol

Next, let's find the moles of HCl:

moles HCl = Molarity x Volume (L)

moles HCl = 0.200 mol/L x 0.00100 L

moles HCl = 0.00020 mol

Since NaOH and HCl react in a 1:1 ratio, we can see that all of the HCl will react with the NaOH and none will be left over. This means that the concentration of NaOH in the final solution is:

0.00770 mol / (0.01100 L + 0.05000 L) = 0.1027 M

Now we can find the pOH of the solution:

pOH = -log[OH-]

pOH = -log(0.1027)

pOH = 0.990

And finally, we can find the pH of the solution:

pH + pOH = 14

pH = 14 - 0.990

pH = 13.01

Therefore, the pH of the resulting solution is 13.01.

Answer:

A:16

Explanation:

it's one of those things where there is no way to explain it but I hope this helps

c

first balance the chemical equation / the equation is already balanced/

secondly write the given mole above the compound

then place the coefficient as a number of mole under the compound

after that set up the proportion

finally calculate the unknown mole

x/16 = 10/5

x=32

Answer:

The molar mass of O2 is 32g/mol.

Explanation:

So the mol amount of these O2 is 56/32=2 mol. STP stands for the standard temperature and pressure which means the temperature is 0 ℃ and pressure is 100 kPa. And the molar volume of gas is 22.7 L/mol under STP. So the answer is 22.7*2=45.4 L

The molecular formula of HFO2 tells us that it contains one hydrogen atom (H), one fluorine atom (F), and two oxygen atoms (O). The atomic masses of H, F, and O are 1.0, 19.0, and 16.0 g/mol, respectively.

Formula mass = (1 x atomic mass of H) + (1 x atomic mass of F) + (2 x atomic mass of O)

= (1 x 1.0 g/mol) + (1 x 19.0 g/mol) + (2 x 16.0 g/mol)

= 1.0 g/mol + 19.0 g/mol + 32.0 g/mol

= 52.0 g/mol

By adding the masses of each individual atom in the compound's formula, the formula mass is determined. The ions can be regarded as atoms for the purposes of determining the formula mass since a valid formula is electrically neutral (with no net electrons gained or lost).

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Answer:

To determine the moles of potassium chloride required to completely precipitate all of the silver, we first need to write a balanced chemical equation for the reaction between silver and potassium chloride. The balanced chemical equation is:

AgNO3 + KCl → AgCl + KNO3

This equation shows that 1 mole of AgNO3 reacts with 1 mole of KCl to produce 1 mole of AgCl.

Next, we can calculate the moles of silver in the solution using its molar mass:

moles of Ag = mass / molar mass

moles of Ag = 3.08 g / 107.87 g/mol

moles of Ag = 0.0286 mol

Since the reaction between silver and potassium chloride is 1:1, we need the same number of moles of KCl as the number of moles of Ag:

moles of KCl = 0.0286 mol

Finally, to determine the mass of KCl required, we can use its molar mass:

mass of KCl = moles of KCl x molar mass

mass of KCl = 0.0286 mol x 74.55 g/mol

mass of KCl = 2.13 g

Therefore, we need to add 0.0286 moles of KCl (equivalent to 2.13 g) to completely precipitate all of the silver.

Answer:

Lockout/Tagout direct wired equipment at energy source

Explanation:

The purpose of Lockout Tagout (often referred to as LOTO) is to keep the affected employees in the area from any active energy sources on a machine. The best way to isolate hazardous energy is to isolate it at the energy source to dissipate all hazardous energy that could harm an affected employee.

Answer:

Hypothesis: If I use SuperGro fertilizer on my tomato plants, then the harvest will be greater than if I do not use the fertilizer.

Experiment: I would divide my tomato plants into two groups. The first group would be the control group and receive no fertilizer. The second group would be the experimental group and receive SuperGro fertilizer. I would use the same type and number of tomato plants in both groups and plant them in the same location with the same amount of sunlight and water.

Control group: Tomato plants that receive no fertilizer

Experimental group: Tomato plants that receive SuperGro fertilizer

Independent variable: SuperGro fertilizer

Dependent variable: Tomato harvest

Control variables: type and number of tomato plants, location, amount of sunlight and water

Hypothetical results: The tomato plants in the experimental group that received SuperGro fertilizer produced double the amount of tomatoes compared to the tomato plants in the control group that did not receive fertilizer.

Conclusion: Based on the results of the experiment, it can be concluded that SuperGro fertilizer does have a significant effect on increasing tomato harvest. Therefore, using SuperGro fertilizer can be recommended for individuals who want to increase their tomato harvest.

Explanation:

An ether's basic composition is as follows:

B. R-O-R

The oxygen atom is connected to two R groups, and R here stands for an alkyl or aryl group. Using the "oxy" group in place of the "alkyl" or "aryl" group, this structure is also referred to as an "alkoxy" group.

The two R groups could be the same or distinct. Ethers are a group of organic substances that are frequently employed as solvents, anesthetics, and chemical synthesis intermediate.

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In order to satisfy the Law of Conservation of Mass, 64.7 grammes of items must be produced.

The following diagram illustrates the balanced chemical equation for propane combustion: C 3 H 8 ( g ) ( g ) Propane plus O2O ( g ) CO2 3 Oxygen ( g ) Carbon dioxide + 4 hydrogen ions ( l ) Heat plus water.

We must create a balanced chemical equation for propane combustion in order to resolve this issue:

C3H8 + 5O2 → 3CO2 + 4H2O

We must figure out how many moles of oxygen and propane are used in the reaction.

moles of propane = 14.0 g / 44.1 g/mol = 0.317 mol

moles of oxygen = 102.0 g / 32.0 g/mol = 3.1875 mol

moles of oxygen used = 0.317 mol x 5 = 1.585 mol

moles of oxygen left over = 3.1875 mol - 1.585 mol = 1.6025 mol

we can use the mole ratios in the balanced equation to determine the moles of products formed:

moles of carbon dioxide = 3 x 0.317 mol = 0.951 mol

moles of water = 4 x 0.317 mol = 1.268 mol

Now we can calculate the total mass of the products:

mass of carbon dioxide = 0.951 mol x 44.01 g/mol = 41.8 g

mass of water = 1.268 mol x 18.02 g/mol = 22.9 g

Total mass of products = mass of carbon dioxide + mass of water

= 41.8 g + 22.9 g

= 64.7 g

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To determine the number of moles of gas in the sample, we can use the Ideal Gas Law: PV = nRT

n = PV/RT

n = (1.99 atm)(85.81 L) / (0.0821 Latm/(molK) * 397.15 K)

n = 6.51 moles

Therefore, there are 6.51 moles of gas in the sample.

An ideal gas is a theoretical gas composed of randomly moving point particles not subject to intermolecular interactions.

The ideal gas law describes the behavior of ideal gases, which relates the pressure, volume, temperature, and number of moles of a perfect gas. Natural gases do not strictly obey the ideal gas law, particularly at high pressures and low temperatures where intermolecular interactions become significant.

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Answer:

(I) - B

(II) - C
(III) - C
(IV) - D

Explanation:

(I) both of carboxylic acids (B) and alcohols (E) are miscible in H2O, but carboxylic acids increase the acidity of water/solution

(II) Saturated hydrocarbons are from alkane hydrocarbons and they don't have pi bonds, only sigma bonds, and (C) is an alkane (Propane).

(III) Alkanes (C) are unreactive because of sigma bonds which are strong bonds that needs high energy to break

(IV) any unsaturated hydrocarbon (having pi bonds or double bonds, "==" in Lewis Structure) decolourizes Br2 since Br atoms react with the unsaturated hydrocarbon, producing bromo-alkane, for instance, 1-propene (D) + Br2 ---> 1-bromo propane

The temperature of sample gas that fills a 0.725L container is 576K which initially is collected in a 0.4L container at a temperature of 318K.

Given the volume of a sample gas (V1) = 0.4L

The temperature of gas (T1) = 45°C = 273 + 45 = 318K

The volume of container that fills gas (V2) = 0.725L

The temperature of gas at volume V2 = T2

We know that from ideal gas laws, the volume of gas and temperature are directly related to each other where its equation is: PV = nRT

If we assume the pressure is constant, then,

From the above equation we can say that:

V1/T1 = V2/T2

0.4/318 = 0.725/T2

T2 = 576.315K

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A base is a proton acceptor according to the Brnsted-Lowry classification of acids and bases, whereas an acid is a proton (H+) donor. A Brnsted-Lowry acid drops a proton, creating a conjugate base.

Any hydrogen-containing substance that has the ability to donate a proton (hydrogen particle) to another substance is considered an acid. A base is a molecule or particle that can take on an acid's hydrogen ion.

A Bronsted-Lowry base is a compound that can receive a hydrogen ion, whereas a Bronsted-Lowry acid can donate one. A substance that can give two electrons is known as a Lewis base.

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The balanced equation for the dissolution of Ba(IO3)2 is: [tex]Ba(IO3)2 (s) → Ba2+ (aq) + 2IO3- (aq)[/tex]

Let x be the molar solubility of Ba(IO3)2 in the presence of 0.0200 M Ba(NO3)2. Then, the equilibrium concentrations of Ba2+ and IO3- can be expressed in terms of x as follows: [Ba2+] = x + 0.0200 M [IO3-] = 2x The solubility product constant (Ksp) expression for Ba(IO3)2 is: [tex]Ksp = [Ba2+][IO3-]^2[/tex]

Substituting the expressions for [Ba2+] and [IO3-] into the Ksp expression, we get: [tex]Ksp = (x + 0.0200)(2x)^2 = 4x^3 + 0.12x^2[/tex]+ 0.0008 Since the molar solubility of Ba(IO3)2 is small compared to the initial concentration of Ba(NO3)2, we can assume that x is much smaller than 0.0200 M.

This means that we can neglect the contribution of x to 0.0200 M and simplify the Ksp expression to:[tex]Ksp ≈ 8x^3[/tex]At equilibrium, the value of Ksp must be equal to the product of the concentrations of the ions raised to their stoichiometric coefficients.

Thus: [tex]Ksp = [Ba2+][IO3-]^2 ≈ 8x^3[/tex] Substituting the expressions for [Ba2+] and [IO3-] into this equation, we get: [tex]8x^3 = (x + 0.0200)(2x)^2[/tex]Simplifying and solving for x, we obtain: [tex]x = 4.56 x 10^-6 M[/tex]Therefore, the molar solubility of Ba(IO3)2 in a solution that is 0.0200 M Ba(NO3)2 is [tex]4.56 x 10^-6 M[/tex]

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Answer:

In sphingolipids, the hydrophobic region consists of a longchain sphingoid base with generally 18 carbons, such as sphingosine, which is linked to the acyl group of a fatty acid via an amide bond (R2). The hydrophilic region (R1) consists in the simplest case of a hydroxyl group in the case of ceramide.

Explanation:

The sample of iodized salt contains 0.9105 g of KCI, which is a mixture of NaCl and KCI with a KCI content of 60.7%.

KCI makes up 60.7% of the sample's total mass, and NaCl makes up the remaining portion (100% - 60.7%) of the sample's mass.

Firstly, let's determine the mass of NaCl in the sample:

NaCl mass is equal to (0.5935 g) (100% - 60.7%)*1.50 g.

We can now determine the mass of KCI:

KCI mass equals 60.7% * 1.50 g = 0.9105 g

KCI thus has a mass of 0.9105 g in the iodized salt sample.

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The concentration of phosphoric acid is 1.11 M.

Phosphoric acid is a colorless, odorless phosphorus-containing solid, and inorganic compound with the chemical formula H₃PO₄.

To determine the concentration of the phosphoric acid (H3PO4) in this reaction, we can start by using the balanced chemical equation:

H3PO4 + 3 NaOH → Na3PO4 + 3 H2O

From the equation, we can see that 1 mole of H3PO4 reacts with 3 moles of NaOH. Therefore, we can first calculate the number of moles of NaOH in the reaction:

Since the reaction is a 1:1 ratio between H3PO4 and NaOH, the number of moles of H3PO4 is also 0.040 mol.

Next, we can calculate the concentration of H3PO4:

concentration of H3PO4 = moles of H3PO4 / volume of H3PO4

volume of H3PO4 = 36.0 mL = 0.036 L

concentration of H3PO4 = 0.040 mol / 0.036 L

concentration of H3PO4 = 1.11 M

Therefore, the concentration of phosphoric acid is 1.11 M.

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Answer:

we need 19.52 g of sugar to produce 10 g of ethanol.

Explanation:

The balanced chemical equation for the fermentation of glucose (sugar) to ethanol (C2H5OH) is:

C6H12O6 → 2C2H5OH + 2CO2

From the equation, we can see that one mole of glucose (C6H12O6) reacts to produce two moles of ethanol (C2H5OH). To determine how many grams of sugar are needed to produce 10g of ethanol, we need to use stoichiometry and the molar mass of glucose.

The molar mass of glucose is 180.16 g/mol, and the molar mass of ethanol is 46.07 g/mol. Therefore, we can calculate the number of moles of ethanol produced from 10 g as follows:

moles of C2H5OH = mass / molar mass = 10 g / 46.07 g/mol = 0.217 moles

Since two moles of ethanol are produced from one mole of glucose, we can calculate the number of moles of glucose needed as follows:

moles of glucose = 0.217 moles / 2 = 0.1085 moles

Finally, we can calculate the mass of glucose needed as follows:

mass of glucose = moles of glucose × molar mass of glucose

mass of glucose = 0.1085 moles × 180.16 g/mol

mass of glucose = 19.52 g

[tex] \:\:\:\:\:\: \sf \underline{\pink{C_6H_{12}O_6} \longrightarrow \pink{2\:C_2H_5OH}+2CO_2}\\[/tex]

As per this equation, 1 mole of [tex]\sf C_6H_{12}O_6 [/tex] produces 2 moles of [tex]\sf C_2H_5OH[/tex] and 2 moles of [tex]\sf CO_2[/tex]

Molar mass of 1 mole of [tex]\sf C_6H_12O_6 [/tex]-

[tex] \:\:\:\:\:\:\longrightarrow \sf Molar\: Mass_{( C_6H_{12}O_6 )} = 12\times 6 + 1\times 12 + 16 \times 6\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Molar\: Mass_{( C_6H_{12}O_6 )} =\underline{180 \:grams }\\[/tex]

Molar Mass of 2 moles of [tex]\sf C_2H_5OH[/tex]-

[tex] \:\:\:\:\:\:\longrightarrow \sf Molar \:Mass _{( C_2H_5OH)} = 2\bigg(12 \times2 + 1\times 5 + 16 +1\bigg)\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Molar \:Mass _{( C_2H_5OH)} =2\times 46 \\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Molar \:Mass _{( C_2H_5OH)} =\underline{92\: grams }\\[/tex]

As per equation, 92 grams of [tex]\sf C_2H_5OH[/tex] can be produced from 180 grams of sugar. So, for making 10 grams of [tex]\sf C_2H_5OH[/tex],we have to multiply 180 by 10 and then divide by 92. 180 grams of sugar is needed to make 92 grams of ethanol. Therefore -

[tex] \:\:\:\:\:\:\longrightarrow \sf \dfrac{180\times 10}{92}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{\pink{19.565 \:grams }}\\[/tex]

19.565 grams of sugar will be needed to make 10 g [tex]\sf C_2H_5OH[/tex]

The Arrhenius equation relates the rate constant of a reaction to the activation energy, the temperature, and a constant known as the pre-exponential factor or frequency factor. The equation is given by:

k = A * exp(-Ea/RT)

where:

k = rate constant

A = pre-exponential factor or frequency factor

Ea = activation energy (in Joules/mol)

R = gas constant (8.314 J/mol-K)

T = temperature (in Kelvin)

We are given that the rate constant at 89.0°C (362.15 K) is 1.9 × 10^7 M^-1s^-1. We want to find the rate constant at 121.0°C (394.15 K).

First, we need to calculate the pre-exponential factor, A. We can do this by rearranging the Arrhenius equation and solving for A:

A = k * exp(Ea/RT)

We can plug in the values we know:

A = (1.9 × 10^7 M^-1s^-1) * exp((5.0 kJ/mol) / (8.314 J/mol-K * 362.15 K))

A = 6.46 × 10^11 M^-1s^-1

Now we can use the Arrhenius equation to calculate the rate constant at 121.0°C:

k = A * exp(-Ea/RT)

k = (6.46 × 10^11 M^-1s^-1) * exp((5.0 kJ/mol) / (8.314 J/mol-K * 394.15 K))

k = 1.9 × 10^9 M^-1s^-1

Therefore, the rate constant at 121.0°C is approximately 1.9 × 10^9 M^-1s^-1.

Answer:(−NH−CHR−CO−)n is a homopolymer. The reason is that it has a single monomer (NH2−CHR−COOH), α−amino acid.

If a polymer consists of only one kind of monomer then it is called a homopolymer, while a polymer that consists of more than one kind of monomer is called a copolymer