Answer:
B. YOU ARE NOT ALLOWED TO ON YOUR HAZARD LIGHTS BEFORE YOU PULL OVER
HAVE A GOOD DAY!
Answer:
B.
Explanation:
Hazard Lights is a pair of flashing lights on a vehicle that signal others that the vehicle is slowing down or is in reverse mode.
Turning on the hazard light before pulling over or while driving is illegal in Florida. This has been a topic of debate as many vehicle riders use hazard lights during the fog or rain for safety. But, according the authorities and law, hazard lights should be use when the vehicle is on halt and not moving. The only exception in using hazard lights is for those heading for funerals.
Thus the correct answer is option B.
Determine size of a standard square key made of 1045 hot rolled steel for a 2 inch DIA shaft transmitting 100 HP at 500 rpm with factor of safety 2.5 for yield in direct shear. W____inch L_____inch
Answer:
Width = Length = 1.148 inches
Explanation:
We have been given the following data:
D = diameter = 2 inch = 0.0508m
P = Power = 100 HP = 74570 W
N = 500 rpm
Safety Factor = 2.5
Step 1:
We need to find yield strength which is represented by σ(y).
σ(y) for 1045 hot rolled steel = 330MPa
Step 2:Find Shear Strength. Formula is given:
τ(y) = σ(y) / 2
τ(y) = 330 / 2
τ(y) = 165 MPa
τ(y) = 165 × 10⁶ Pa
τ(y) = 165 × 10⁶ kg.m⁻¹.s⁻²
Step 3:
Find Torque. Formula is given:
T = 60P / 2πN
T= (60)(74570) / 2π(500)
T = 1424.9 Nm
Step 4:Find Shear Force. Formula is given:
F = 2T/d
F = 2(1424.9)/0.0508
F = 56098.43 N
F = 56098.43 kg.m.s⁻²
Step 5:Find length by the given formula:
F/L² = τ(y)/Safety factor
Rearrange for L:
L = √(F· Safety factor / τ(y))
Substitute the values found in previous steps to calculate L.
L = 0.02915 meters
Convert it into inches:
L = 1.148 in
As it si a square key:
L = W
Width = 1.148 in
A duct for an air conditioning system has a rectangular cross section of 2ft by 9in. The duct is fabricated from galvanized iron (e 0.006in). Calculate the pressure drop in psi for a horizontal 50-ft section of pipe with a flow rate of air of 5000cfm at 100F and atmospheric pressure
Answer:
The answer is '[tex]2.9584 \ \frac{lbf}{ft^2}[/tex]'
Explanation:
Given:
[tex]\mu=3.96 \times 10^{-7} \ \frac{lbfs}{ ft^2}\\\\\gamma=0.0709 \ \frac{lfb}{ft^3}\\\\v= 1.8 \times 10^{-4} \ \frac{ft^2}{s}[/tex]
energy balance equation:
[tex]\ P_1 - P_2 = \rho gh_{L}[/tex]
[tex]V= \frac{\ Q}{ A}\\\\V= \frac{\frac{5000}{60}}{2 \times \frac{9}{12}}\\\\V= 55.55 \frac{ft}{s}[/tex]
calculating [tex]D_h[/tex]:
[tex]D_h= \frac{4 \times \ scetor \ area }{ wetted \ permetor}\\\\D_h=\frac{4 \times 2 \times \frac{9}{12}}{2(2+\frac{9}{12})}\\\\D_h= 1.0909 ft\\\\[/tex]
calculating [tex]R_e[/tex]:
[tex]R_e=\frac{VD_h}{V}\\\\R_e=\frac{55.55 \times 1.0909}{1.8 \times 10^{-4}}\\\\R_e=3.366 \times 10^5\\\\[/tex]
calculating relative vovghness:
[tex]\frac{k_s}{D_h}= \frac{\frac{0.006}{12}}{1.0909}\\\\[/tex]
= 0.0006875
If [tex]R_e= 3.366 \times 10^5 \ and \ \ \frac{K_s}{D_h} = 0.0006875 \ \ \ so, \ \ f= 0.019[/tex]
Calculating [tex]H_f[/tex]:
[tex]H_f= \frac{f \ l\ v^2}{ 2 \ g \ D_h}\\\\[/tex]
[tex]=\frac{0.019 \times 50 \times 55.55^2}{2\times 32.2\times 1.0909}\\\\= 41.727 \ ft[/tex]
Calculating pressure drop:
[tex]P_1-P_2= \gamma h_{L}\\\\[/tex]
[tex]= 0.0709 \times 41.727\\\\= 2.9584 \ \frac{lbf}{ft^2}[/tex]
The new Boeing 777 aircraft was designed and engineered by a group of Boeing employees from manufacturing, marketing, and engineering departments and by representatives of Boeing’s customers (major airlines such as United and American Airlines), all working closely together in an intensive effort. This design and engineering group for the 777 can be classified as_________.
Answer:
A cross-functional team
Explanation:
A cross-functional team are a customer centric collection of professionals with diverse area of expertise that come together to attain a common purpose by collaboration which aids in the maximization of effort, investment, and time in achieving customer satisfaction and the goals of the organization
The team can comprise members from different departments within the organization such as marketing, finance, safety and quality, human resources as well as operations.
A widebody aircraft
The Boeing 777 is accounted as a wide body aircraft because it has 2 isles and other aircraft have one like the Boeing 737 is not considered as widebody because it has only one isle and like the Airbus A330-900 is a competitor to the Boeing 777 and has 2 isles in the aircraft so it is considered a wide body aircraft.
A prototype boat is 30 meters long and is designed to cruise at 9 m/s. Its drag is to be simulated by a 0.5-meter-long model pulled in a tow tank. For Froude scaling find a)-The tow speed b)-The ratio of model to prototype drag c)-The ratio of model to prototype power.
Answer:
a) 1.16 m/s
b) 1/216000
c) (√15)/6480000
Explanation:
The parameters given are;
Length of boat prototype, lp = 30 m
Speed of boat prototype = 9 m/s
Length of boat model, lm= 0.5 m
a) lm/lp = 0.5/30 = 1/60 = ∝
(vm/vp) = ∝^(1/2) = √∝ = (1/60)^(1/2)
vm = 9 × (1/60)^(1/2) = 1.16 m/s
b) The ratio of the model to prototype drag, Fm/Fp, is given as follows;
Fm/Fp = (vm/vp)²×(lm/lp)² = ∝³
Fm/Fp = (1/60)³ = 1/216000
c) The ratio of the model to prototype power pm/p[tex]_p[/tex] = (Fm/Fp) × (vm/vp) = ∝³×√∝
The ratio of the model to prototype power pm/p[tex]_p[/tex] = √(1/60) × (1/60)³
pm/p[tex]_p[/tex] = √(1/60) × (1/60)³ = (√15)/6480000
Explain what a margin of safety is in driving as well as how it can help minimize risk.
Answer:
A safety margin is the space left between your vehicle and the next to provide room, time and visibility at every instant
Explanation:
A safety margin is defined as an allowance given between your vehicle and the next vehicle in front to provide enough room, visibility and time to move in a safe manner to prevent the occurrence of an accident at anytime the frontal vehicle suddenly stops or slows down
Safety margins help minimize risks in the following way
1) A common knowledge of safety margins, improves predictability among road users, thereby minimizing the risk traffic accidents caused due to late communication
2) The use of safety margins helps minimize the risk due to a change in driving conditions such as when the road becomes more slippery from being covered with fluid that is being wetted
3) Safety margin can help prevent the occurrence of an accident between vehicles due to failure of a car system, such as a punctured tire or failed breaking system
4) Safety margin helps to protect road users from the introduction of obstacles on the main roads such as ongoing road construction, broken down vehicles, road blockage by vehicles involved in an accident etc
5) Safety margin help protect road users from being involved in an accident due to the loss of driving focus of the driver of the frontal vehicle
Select the best answer for the question
14. After treating the expansion valve with a blast of CO2 from a fire extinguisher, you've determined that the valve is defective. What part of the test led you to
this conclusion?
O A. The valve allowed CO2 to leak through the vents
OB. The low-side pressure failed to go into a vacuum
O C. The flow of refrigerant to the evaporator became blocked
O D. The accumulator temperature became higher than the orifice tube temperature,
Answer:
The correct option is;
C. The flow of refrigerant to the evaporator became blocked
Explanation:
The function of the expansion valve is the reduction in the refrigerant pressure entering the evaporator so as to enable the desired change from liquid to gaseous state in the evaporator with the temperature of the high pressure refrigerant that enters into the expansion valve being warm
The expansion valve controls the liquid refrigerant flowing between the low and high pressure areas of the refrigerator
The expansion valve supplies the liquid refrigerant to the evaporator coil ensures a reduction in pressure of the refrigerant before the refrigerant enters the evaporator coil.
what's the real power if Vrms = 100V, Irms = 2A, and the circuit has a power factor of 0.8?
Answer:
160 W
Explanation:
The relation is ...
Real Power = (pf)(V)(A)
= 0.8(100)(2) = 160 . . . . watts
Which material is used in a photovoltaic cell? A photovoltaic cell converts solar radiation into electric current using a thin sheet of____ like silicon.
Answer:
first on is silicon
Explanation:
Answer:
Silicon
Explanation:
Copper indium dieseline (CIS), cadmium telluride (CdTe), and thin-film silicon are certain polycrystalline thin film materials often used, whereas high-efficiency material such as gallium arsenide (GaAs) often comprise single-crystalline thin film materials3.
A piston-cylinder device contains 0.1 kg of hydrogen gas (PG model: cv=10.18, k = 1.4, R= 4.12 kJ/kg-K) at 1000 kPa and 300 K. The gas undergoes an expansion process and the final conditions are 500 kPa, 270 K. If 10 kJ of heat is transferred into the gas from the surroundings at 300 K, determine (a) the boundary work (Wb), and (b) the entropy generated (Sgen) during the process
Answer:
(a) 151.84 kJ
(b) 2.922 kJ/K
Explanation:
(a) The parameters given are;
Mass of hydrogen gas, H₂ = 0.1 kg = 100 g
Molar mass of H₂ = 2.016 g/mol
Number of moles of H₂ = 100/2.016 = 49.6 moles
V₁ = mRT/P = 0.1×4.12×300/1000 = 0.1236 m³
P₁/P₂ = (V₂/V₁)^k
V₂ = (P₁/P₂)^(1/k)×V₁ =0.1236 × (1000/500)^(1/1.4) = 0.3262 m³
Boundary work done = (V₂ - V₁)(P₂ + P₁)/2 = (0.3262 - 0.1236)*(500 + 1000)/2 = 151.84 kJ
(b) Entropy generated ΔS = Cv · ㏑(T₂/T₁) + R ·㏑(v₂/v₁)
=10.18 × ㏑(270/300) + 4.12 ·㏑(0.3262/0.1236) = 2.922 kJ/K.
An example of matching and converting would be finding a new market in which to see a product, such as online or internationally.
True
False
Answer:
True
Explanation:
Matching involves putting compatible strength and opportunities together to acquire comparative advantage over the competition
Converting involves the transformation of perceived prospects or threats and weakness or lack of capacity into a chance or opening and strength
Therefore, since finding a new market in which to see a product such as online or internationally can help match the strength of the searcher to the opportunities available internationally and convert weaknesses finding a new market is an example of matching and converting
If the heat content of one ton of coal is 28 million Btu/ton, what is the cost of electricity? a)- $0.063 b)- $0.014 °c)- $0.023 d)- $0.011
Answer:
The electricity cost will be Option d ($0.011).
Explanation:
The given values are:
1 ton coal = 28 million Btu/ton
Or,
1 metric tonne = 28 × 10⁶ Btu
As we know,
Coal's cost,
⇒ [tex]C=30/metric \ tonne[/tex]
[tex]=\frac{30}{28\times 10^6}[/tex]
⇒ [tex]H=10300 \ btu/Kwh[/tex]
Now,
Electricity's cost,
⇒ [tex]C\times H[/tex]
On substituting the estimated values, we get
⇒ [tex]\frac{30}{28\times 10^6}\times 10300[/tex]
⇒ [tex]0.011/ Kwh[/tex]