Which of the following is a true statement about atrial natiuretic peptide? It is released by the adrenal cortex if MAP becomes too high It is released by the heart if MAP drops too low. It is a stero

Answers

Answer 1

The true statement about atrial natriuretic peptide (ANP) is: It is released by the heart if MAP drops too low.  ANP is released by the heart in response to low mean arterial pressure (MAP), not high MAP.

ANP is a hormone primarily synthesized and released by the cells of the atria (upper chambers) of the heart. Its secretion is stimulated when there is an increase in blood volume or pressure within the atria. ANP acts as a regulatory mechanism to counteract high blood pressure by promoting the excretion of sodium and water by the kidneys. By increasing the loss of sodium and water, ANP helps to reduce blood volume and lower blood pressure. Therefore, ANP is released by the heart in response to low mean arterial pressure (MAP), not high MAP.

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Related Questions

The correct answer is carbohydrates, but I am not sure why. Please provide me with an explanation for why that is. Don't proteins also have small molecules (Amino acids) and larger polymers (polypeptides)?
Which of these classes of biological molecules consist of both small molecules and macromolecular polymers?
nucleic acids
lipids, carbohydrates, proteins, and nucleic acids all consist of only macromolecular polymers
lipids
proteins
carbohydrates

Answers

Carbohydrates are the class of biological molecules that consist of both small molecules and macromolecular polymers. Proteins also have small molecules (amino acids) and larger polymers (polypeptides), but carbohydrates specifically encompass both these forms within their classification.

Carbohydrates are composed of carbon, hydrogen, and oxygen atoms. They can exist as small molecules, such as monosaccharides (simple sugars) like glucose and fructose, or as macromolecular polymers, such as polysaccharides like starch and glycogen. The small molecules of carbohydrates serve as building blocks for the synthesis of larger polymers.

Proteins, on the other hand, are made up of amino acids, which are the small molecules that form the monomeric units of proteins. However, when amino acids join together through peptide bonds, they form polypeptide chains, which are the macromolecular polymers of proteins.

While proteins do contain both small molecules and macromolecular polymers, carbohydrates specifically encompass this characteristic as a class of biological molecules. Carbohydrates exhibit a wide range of functions in living organisms, including energy storage, structural support, and cell recognition.

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A Lactobacillus strain is growing in milk. At 5 hours the cell concentration is 5 x 10 CFU/ml whereas at 10 hours the cell concentration is 4 x 108 CFU/ml. Assuming that the cells are growing exponentially during this period, calculate the maximum specific growth rate (max) (30 marks)

Answers

To calculate the maximum specific growth rate, we can use the following formula:

[tex]μmax = ln(N2/N1)/t2-t1[/tex]

where N1 is the cell concentration at time 1, N2 is the cell concentration at time 2, t1 is the time at time 1, and t2 is the time at time 2.

Using the given data, we can plug in the values:

[tex]μmax = ln(4 x 108/5 x 105)/(10-5)μ[/tex]

[tex]max = ln(8 x 103)/5μmax[/tex]

[tex]= 5.66 x 10-4 per hour or 0.566 per day[/tex]

the maximum specific growth rate is [tex]5.66 x 10-4[/tex] per hour or 0.566 per day.

Now, we can substitute these values into the equation:

[tex]μmax = 9.08 / 5 ≈ 1.82 CFU/ml/hour[/tex]

 the maximum specific growth rate (μmax) of the Lactobacillus strain is approximately [tex]1.82 CFU/ml/hour[/tex].

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Can you explain a oxyhemoglobin dissociation curve. Can you describe how this changes
regards to changes in pH, temperature, and 2,3-DPG
and what does this meaning in regards to oxygen unloading?

Answers

The oxyhemoglobin dissociation curve describes the relationship between the partial pressure of oxygen (PO2) and the saturation of hemoglobin with oxygen. Changes in pH, temperature, and 2,3-DPG can shift the curve, affecting oxygen binding and release. Decreased pH, increased temperature, and increased levels of 2,3-DPG shift the curve to the right, promoting oxygen unloading from hemoglobin, while increased pH, decreased temperature, and decreased levels of 2,3-DPG shift the curve to the left, enhancing oxygen binding and reducing oxygen unloading.

The oxyhemoglobin dissociation curve illustrates how hemoglobin binds to and releases oxygen in response to changes in the partial pressure of oxygen. The curve is typically sigmoidal, meaning that the binding of the first oxygen molecule facilitates subsequent binding, leading to a steep increase in oxygen saturation.

Several factors can influence the position of the curve. Changes in pH, temperature, and the concentration of 2,3-DPG, a byproduct of red blood cell metabolism, can shift the curve. Decreased pH (acidosis), increased temperature, and increased levels of 2,3-DPG cause the curve to shift to the right. This is known as the Bohr effect. The rightward shift decreases the affinity of hemoglobin for oxygen, promoting oxygen release in tissues with higher metabolic activity or lower oxygen levels. This is particularly important during exercise or in tissues experiencing increased carbon dioxide production.

Conversely, increased pH (alkalosis), decreased temperature, and decreased levels of 2,3-DPG cause the curve to shift to the left. This leftward shift increases the affinity of hemoglobin for oxygen, enhancing oxygen binding in the lungs where oxygen levels are higher.

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Muth detects the original methylated DNA in which of the following repair mechanisms?
a.Photo-reactivation
b. Mismatch
c. All of the answers
d. Base excision

Answers

The correct answer is: d. Base excision

Muth detects the original methylated DNA in base excision repair mechanisms.

Methylated-DNA Unwinding and Treating Helicase is a DNA repair enzyme that is required for the base excision repair (BER) mechanism. Methylated DNA, which can be caused by a variety of environmental and genetic factors, can result in cytotoxic and mutagenic lesions. In Escherichia coli, MUTH is the first protein in the adaptive response to alkylation damage. A fundamental process, DNA repair, protects our DNA from damage caused by both exogenous and endogenous factors.

The BER mechanism is a key DNA repair mechanism for repairing damaged DNA bases caused by the methylation of DNA. MUTH helps to detect the original methylated DNA in this mechanism as MUTH acts as a key player in the base excision repair process. Hence, the correct option is d. Base excision.

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Fill in the complementary DNA strand (template strand). Then transcribe \& translate these bacterial ORFs (open reading frame) from DNA sequence into mRNA / polypeptide. These are the non-template strands. 5'TCAATGGAACGCGCTACCCGGAGCTCTGGGCCCAAATTTCATTGACACT 3 ' 5′GGGATCGATGCCCCTTAAAGAGTTTACATATTGCTGGAGGCGTtAACCCCGGA 3 ′

Answers

Complementary DNA strand:3' AGTTACCTTGCGCGATGGGCCTCGAGACCCGGGTTAAAAGTAACGTGTG 5'Transcription is the process of producing an RNA molecule from a DNA template, while translation is the process of producing a polypeptide chain from an RNA molecule.

Transcription:5' UGAAUGGAACGCGCUACCCGGAGCUCUGGGCCCAAUUUCAUUGACACU 3'3' ACUUACCUUGCGCGAUGGGCCAGAGACCCGGGUUAAAAGUAAUGUGACUGAAUGUUAGGCGCGCUGACCCUGGUUGACU 5'mRNA:5' UGAAUGGAACGCGCUACCCGGAGCUCUGGGCCCAAUUUCAUUGACACU 3'3' ACUUACCUUGCGCGAUGGGCCAGAGACCCGGGUUAAAAGUAAUGUGACUGAAUGUUAGGCGCGCUGACCCUGGUUGACU 5'Polypeptide chain:5' Methionine-Asp-Asn-Cys-Ala-Cys-Lys-Thr-Pro 3'.

To find the complementary DNA strand (template strand), we can simply replace each nucleotide with its complementary base:

5' TCAATGGAACGCGCTACCCGGAGCTCTGGGCCCAAATTTCATTGACACT 3'

3' AGTTACCTTGCGCGATGGGCCTCGAGACCCGGGTTTAAAGTAACTGTGAA 5'

Now, let's transcribe each of the open reading frames (ORFs) into mRNA and translate them into polypeptides.

ORF 1 (Starting from the first AUG codon):

DNA: 5' TCAATGGAACGCGCTACCCGGAGCTCTGGGCCCAAATTTCATTGACACT 3'

mRNA: 3' AGUUAUCCUUGCUCGAUGGGCCUCGAGACCCGGGUUAAAUAAUGACACU 5'

Polypeptide: Ser-Tyr-Pro-Cys-Arg-Val-Ser-Asp-Pro-Gly-Phe-Lys-Ile-Cys-Th

ORF 2 (Starting from the second AUG codon):

DNA: 5' GGATCGATGCCCCTTAAAGAGTTTACATATTGCTGGAGGCGTtAACCCCGGA 3'

mRNA: 3' CCAUAGCUACGGGAUUUUCUCAAUUGUAUAACGACCUCCGCAttUUGGGGCCU 5'

Polypeptide: Pro-Tyr-Leu-Arg-Asp-Phe-Ser-Asn-Val-Asn-Asp-Pro-His-Leu-Gly-Pro

Please note that the lowercase "t" in the DNA sequence represents a potential mutation and should be interpreted as "T" when transcribing and translating.

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The brown tree snake introduced to Guam is only one of thousands
of unintentional species introductions that have far-reaching
effects.
Even if we know exactly what an introduced species consumes, why

Answers

It can still be challenging to predict the effects of the introduction of an introduced species on an ecosystem.

Even if we know exactly what an introduced species consumes, why might it still be difficult to predict the effects of its introduction? The introduced species' impact on the ecosystem can be challenging to predict even if we know what it consumes.

It is challenging to foresee how the species may interact with other organisms in its new habitat, how it may compete with native species for resources or whether it may bring diseases, predators, or parasites that have never existed there before. It can be tough to predict how the ecosystem will be impacted by a new species since there are so many variables involved.

These variables may include interactions with other non-native species and local predators, prey, and competitors. All of these factors can impact the new species' survival and its effect on the ecosystem. Even if we know the introduced species' habits, such as what it consumes, there are other factors to consider, such as its impact on the ecosystem as a whole.

In conclusion, knowing what an introduced species consumes does not give a full picture of the effects of its introduction. Therefore, it can still be challenging to predict the effects of the introduction of an introduced species on an ecosystem.

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Which of the following is NOT the major driving force in the formation of Concanavalin A tetramers from its dimers?
a) Randomization of several water molecules.
b) Products have a higher entropy than the reactants.
c) Organization of two protein dimers.
d) Disruption of ice-like water lattice.

Answers

In the formation of Concanavalin A tetramers from its dimers, the major driving forces are a), b), and c). The correct answer is d) Disruption of ice-like water lattice.

Randomization of several water molecules refers to the release of ordered water molecules from the protein surface, which increases entropy.

Products having higher entropy than reactants also contribute to the driving force of the reaction. The organization of two protein dimers leads to a more stable and energetically favorable configuration.

However, the disruption of an ice-like water lattice is not a major driving force in this context.

It is important to note that water molecules play a crucial role in stabilizing the protein structure, but the specific ice-like water lattice disruption is not directly involved in the formation of Concanavalin A tetramers.

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As you are studying the chromosomes of a species, you note there are many unexpected variations in the chromosomes. To better study and analyze these changes, outline the ways that the chromosomes of a species may change.
a) Through deletion of genes
b) Through translocation of genes
c) Through inversion of genes
d) Through a change in one or more nucleotide pairs
e) all of the choices are correct.

Answers

The ways that the chromosomes of a species may change include deletion of genes, translocation of genes, inversion of genes, and a change in one or more nucleotide pairs.

Chromosomal changes can occur through various mechanisms, resulting in genetic variation within a species. Deletion refers to the loss of a section of a chromosome, including genes. Translocation involves the transfer of a gene or gene segment from one chromosome to another. Inversion occurs when a segment of a chromosome breaks, flips, and reattaches in reverse orientation. Lastly, changes in nucleotide pairs, such as point mutations or insertions/deletions, can alter the DNA sequence within a chromosome.

These changes can have significant impacts on an organism's phenotype and can contribute to genetic diversity, adaptation, and evolution. Studying and analyzing these variations in chromosomes is essential for understanding genetic mechanisms, evolutionary processes, and the genetic basis of diseases.

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Substances that suppress the immune system making the organism
susceptible to infections is called?

Answers

Substances that suppress the immune system and make an organism susceptible to infections are called immunosuppressants.

Immunosuppressants are substances that suppress or dampen the activity of the immune system. They are used in medical treatments to prevent the rejection of transplanted organs or to manage autoimmune diseases where the immune system mistakenly attacks healthy cells and tissues. Immunosuppressants work by targeting various components of the immune system, such as immune cells or signaling molecules, to reduce their activity.

While immunosuppressants can be beneficial in certain medical contexts, they also have the potential to increase the susceptibility to infections. The immune system plays a crucial role in defending the body against pathogens, such as bacteria, viruses, and fungi. By suppressing immune responses, immunosuppressants can weaken the body's ability to fight off these pathogens, making the organism more susceptible to infections.

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You are a researcher trying to produce bone growth in tissue culture as part of an experiment you are working on. You placed bones in the culture the metabolites the bone would need in order to grow. You then added growth hormone to the culture media, but the bone tissue did not grow. Which something you should add to the culture and why it would work to generate the bone growth you we lookirus for as a result of arom home culture You should add insulin-like growth factors to your culture media because mulle like gowth factoes stimulate bone tissues to mano adenocorticotrope hormone which an turn causes bone to produce growth hormone which then directly stimolates bone growth You should add some liver tissue to your culture. Growth Hormone Indirectly causes bone rowenty directly stimulating the liver to relate inulle like growth octors.lt the insulin-like growth factors whose release is stimulated by Browth hormonal that then bind to bone and stimulate it to go Growth hormone stimulates the growth of many things in the body both directly and indirectly but not hone. You should add prolactin to vou media if you desirebon growth in your culture Growth hormone does directly stimulate bone growth but only when the hormone somatostatin is also present. You should therefore also a somatostatin to your culture None of these answers are correct.

Answers

As a researcher trying to produce bone growth in tissue culture, if the bone tissue did not grow despite the placement of bones in the culture, the addition of insulin-like growth factors to the culture media will generate the bone growth. This answer would explain why it is necessary to add insulin-like growth factors in the culture media and how it would work to produce the desired result of bone growth in tissue culture in

:Insulin-like growth factors (IGFs) are the hormones that stimulate bone growth in tissue culture. They are naturally produced by bone tissues and liver cells and promote the differentiation and proliferation of osteoblasts and chondrocytes, which are the cells responsible for bone formation.

When IGFs are present in the culture media, they bind to their receptors on bone tissues and stimulate them to grow.IGFs release is stimulated by growth hormone, which indirectly causes bone growth by stimulating the liver to produce IGFs. However, IGFs can also be added to the culture media to directly stimulate bone growth without requiring the presence of growth hormone. Therefore, if bone tissue did not grow in the culture despite the addition of growth hormone, adding IGFs to the culture media will generate the bone growth needed.

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Which of the following is NOT TRUE about enzymes? O A) Enzymes speed up chemical reactions by lowering activation energy. OB) Before it can be replicated, an enzyme unwinds DNA at the speed of a jet turbine. c) Without enzymes, most processes in the body would occur too slowly for life to exist OD) Extreme temperatures and pH levels can deactivate enzymes. E) Enzymes are the primary reactants in chemical reactions

Answers

Enzymes are proteins that are produced in the body and can speed up the rate of chemical reactions. A catalytic enzyme is a type of protein that can cause reactions to happen at a faster rate than they would otherwise. The primary function of enzymes is to speed up chemical reactions by lowering activation energy.

However, enzymes are not the primary reactants in chemical reactions.  This statement is not true about enzymes. Enzymes are not the primary reactants in chemical reactions. Rather, enzymes are catalysts that speed up the rate of reactions. Enzymes work by lowering the activation energy of a reaction, which allows the reaction to occur more easily and quickly. Without enzymes, many processes in the body would occur too slowly for life to exist. Enzymes can be deactivated by extreme temperatures and pH levels.

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Two glass tubes contain aqueous solutions of Fe+3 and
Zn+2 ions. Determine whether these substances are
paramagnetic or diamagnetic?

Answers

We need to take into account the electronic structure and magnetic characteristics of Fe+3 and Zn+2 ions in order to establish whether their aqueous solutions are paramagnetic or diamagnetic.

Fe+3: The electronic structure of iron (III) ions is [Ar]3d5, having five unpaired electrons in the 3d orbital. Fe+3 is paramagnetic, which means it is drawn to an external magnetic field since it has unpaired electrons.

Zn+2: The electronic configuration of zinc (II) ions is [Ar]3d10, meaning that all of the electrons are coupled in the 3d orbital. Since Zn+2 doesn't contain any unpaired electrons, it is diamagnetic. An external magnetic field does not attract diamagnetic materials.In conclusion, Zn+2 ions are diamagnetic because all of their electrons are paired, whereas Fe+3 ions are paramagnetic because they have unpaired electrons.

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what are threats to plant and animal biodiversity? explain at
least three point in details giving current example

Answers

Biodiversity refers to the number of species and genetic variability present in an ecosystem. Biodiversity is important as it contributes to the wellbeing of humans by providing a wide range of benefits such as food, fuel, shelter, medicinal resources, and also serves as a basis for ecological processes.  


Overexploitation: Over-harvesting, overfishing, and poaching of wildlife species for commercial purposes, traditional medicines, pet trade, and bushmeat have resulted in the depletion of several animal and plant populations. The commercial harvesting of some tree species for timber has led to their extinction. For example, the overfishing of the Bluefin tuna has led to a significant decline in its population.


Climate change: Climate change is an emerging threat to biodiversity as it leads to changes in temperature, rainfall, and sea levels. Climate change has resulted in habitat loss, disrupted migration patterns, and increased frequency and intensity of extreme weather events. For example, rising temperatures have led to the disappearance of many species such as the Bramble Cay Melomys, which is the first mammal that has been declared extinct due to climate change.
Therefore, it is important to address these threats to protect and conserve biodiversity. To protect biodiversity, it is important to conserve natural habitats, establish protected areas, promote sustainable harvesting, and reduce greenhouse gas emissions.

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Question 2 1 pts Alcohol is metabolized most like which other nutrient? O Fat O Protein O Glucose Starch Question 3 1 pts Alcohol metabolism is dependent on what enzyme to breakdown blood alcohol? Alcohol Dehydrogenase Acetate Lipase Acetaldehyde Question 4 1 pts Drinking large amounts of alcohol for many years will take its toll on many of the body's organs, which organ may develop cirrhosis due to alcohol consumption Liver Stomach O Pancreas O Heart

Answers

2. Alcohol is metabolized most like glucose. 3. Alcohol metabolism is dependent on the enzyme Alcohol Dehydrogenase to breakdown blood alcohol. 4. The liver may develop cirrhosis due to alcohol consumption.

Alcohol is metabolized most like which other nutrient? Alcohol is metabolized most like glucose. Glucose, a type of sugar, is the body's primary energy source. The metabolic pathway for alcohol is comparable to that of glucose. Glucose is a sugar that is broken down in the body to generate energy. Alcohol is metabolized in the same way. In the first phase, alcohol dehydrogenase (ADH) oxidizes alcohol to acetaldehyde, which is then oxidized to acetate by aldehyde dehydrogenase (ALDH). The acetate is metabolized into acetyl-CoA, which enters the TCA cycle for energy production in the second phase.

Alcohol metabolism is dependent on what enzyme to breakdown blood alcohol? Alcohol metabolism is dependent on the enzyme Alcohol Dehydrogenase to breakdown blood alcohol. Alcohol dehydrogenase (ADH) is an enzyme that catalyzes the breakdown of alcohol in the liver. The ADH enzyme breaks down ethanol into acetaldehyde, which is then broken down by the enzyme aldehyde dehydrogenase (ALDH) to acetate, which is further metabolized to acetyl-CoA.

Drinking large amounts of alcohol for many years will take its toll on many of the body's organs, which organ may develop cirrhosis due to alcohol consumption? The liver may develop cirrhosis due to alcohol consumption. Excessive alcohol intake, especially over a long period of time, can damage the liver. Liver disease caused by long-term alcohol use is known as cirrhosis. This occurs when healthy liver tissue is gradually replaced by scar tissue, making it difficult for the liver to perform its normal functions. Scar tissue can also block the flow of blood to the liver, causing further damage.

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if its right ill give it a
thumbs up
In respiratory acidosis there is a high concentration of CO2 in the lungs, True False

Answers

False.

In respiratory acidosis, there is an increased concentration of carbon dioxide (CO2) in the bloodstream, not the lungs.

Respiratory acidosis is a condition characterized by an excess of carbon dioxide in the bloodstream, leading to an imbalance in the body's pH levels. It occurs when the respiratory system fails to adequately remove carbon dioxide, resulting in its accumulation in the blood. The excess CO2 combines with water to form carbonic acid, leading to a decrease in blood pH and an increase in acidity.

Contrary to the statement, the high concentration of CO2 is present in the bloodstream rather than the lungs. In respiratory acidosis, the lungs are unable to effectively eliminate CO2, which is a waste product of cellular respiration. This can occur due to various factors such as impaired lung function, respiratory muscle weakness, airway obstruction, or inadequate ventilation. The condition can be caused by lung diseases, such as chronic obstructive pulmonary disease (COPD), asthma, pneumonia, or respiratory depression from certain medications.

In summary, respiratory acidosis is characterized by an elevated concentration of carbon dioxide in the bloodstream, not the lungs. The lungs play a crucial role in removing CO2 from the body, and when this process is impaired, it results in an accumulation of CO2 in the blood, leading to respiratory acidosis.

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1. design one simple experiment to find out whether your protein
of interest is overexpressed in E.coli

Answers

To determine whether a protein of interest is overexpressed in E. coli, you can design a simple experiment using a comparative approach.

Here's an outline of the experiment:

Experimental Setup:

a. Select two sets of E. coli cultures: one with the protein of interest (experimental group) and another without it (control group).

b. Prepare identical growth conditions for both groups, including media, temperature, and incubation time.

Protein Extraction:

a. After the incubation period, harvest the bacterial cells from both groups by centrifugation.

b. Lyse the cells to extract the total protein content using a suitable protein extraction method.

Protein Quantification:

a. Measure the total protein concentration in the extracted samples from both the experimental and control groups using a protein quantification assay (e.g., Bradford assay, BCA assay).

b. Ensure that the protein concentrations in the samples are normalized for accurate comparison.

Protein Analysis:

a. Perform Western blotting or a similar protein analysis technique to detect and quantify the expression levels of the protein of interest.

b. Use an appropriate primary antibody that specifically recognizes the protein of interest.

c. Perform suitable controls, including a loading control (e.g., housekeeping protein) to normalize protein expression levels.

Data Analysis:

a. Compare the protein expression levels between the experimental and control groups by quantifying the signal intensity or band density obtained from the Western blot or protein analysis.

b. Calculate the fold change in protein expression in the experimental group compared to the control group.

Statistical Analysis:

a. Perform statistical analysis (e.g., Student's t-test) to determine the significance of the differences observed between the experimental and control groups.

b. Set a significance threshold (e.g., p-value < 0.05) to determine if the overexpression of the protein of interest is statistically significant.

By following this experimental design, you can assess whether the protein of interest is overexpressed in E. coli compared to the control group.

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What is the purpose/ functions of the respiratory system? Write the function of the following structures in the respiratory. 1. Goblet cells 2. Nasal conchae_ 3. Nasopharynx 4. Epiglottis 5. Diaphragm and external intercostals

Answers

The respiratory system performs a crucial role in the human body. It involves the exchange of oxygen and carbon dioxide gases, allowing humans to inhale oxygen and exhale carbon dioxide. The human respiratory system's primary function is to supply oxygen to all of the cells in the body and remove carbon dioxide produced by the cells.

It has three primary functions: air distribution, gas exchange, and regulation of respiration.

Let's discuss the function of some of the structures involved in the respiratory system:

1. Goblet CellsThe respiratory system's goblet cells produce and secrete mucus. It traps and eliminates dust, dirt, and other irritants that enter the respiratory tract.

2. Nasal Conchae Nasal conchae increase the surface area of the nasal cavity, which helps to warm and moisturize the air passing through. They also trap airborne particles, which helps to prevent them from reaching the lungs.

3. Nasopharynx The nasopharynx is the uppermost portion of the pharynx. It acts as a pathway for air traveling to and from the nasal cavity. It also helps regulate air pressure in the middle ear.

4. Epiglottis The epiglottis is a flap of tissue located at the base of the tongue. It acts as a valve, directing air and food to the correct passage. When a person swallows, the epiglottis closes to prevent food from entering the trachea.5. Diaphragm and External Intercostals The diaphragm is a dome-shaped muscle that separates the thoracic and abdominal cavities.

It contracts and relaxes to alter the pressure in the thoracic cavity, allowing air to flow in and out of the lungs. The external intercostals are muscles that connect the ribs.

They help to raise the ribcage, increasing the volume of the thoracic cavity. This expansion enables air to enter the lungs. In summary, the respiratory system's purpose is to supply the body's cells with oxygen while removing carbon dioxide.

The goblet cells produce and secrete mucus, nasal conchae increase the surface area of the nasal cavity, the nasopharynx acts as a pathway for air, the epiglottis directs air and food to the right passage, and the diaphragm and external intercostals muscles help the lungs inhale and exhale air.

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How does the ‘dominance hypothesis’ explain large X effect in speciation?
How does ‘fast X’ hypothesis explain large effect of that chromosome in speciation?

Answers

The dominance hypothesis and the fast X hypothesis are two explanations for the large effect of the X chromosome in speciation.

Dominance Hypothesis: The dominance hypothesis proposes that the X chromosome plays a significant role in speciation due to the expression of recessive alleles. In many organisms, the X chromosome is hemizygous in males, meaning they have only one copy of the X chromosome.

As a result, recessive alleles on the X chromosome in males are expressed phenotypically, leading to a higher chance of divergence between populations. This divergence can contribute to reproductive isolation and eventually speciation.

Fast X Hypothesis: The fast X hypothesis suggests that the X chromosome evolves faster than the autosomes, which are non-sex chromosomes. This rapid evolution is attributed to several factors, including a smaller effective population size, fewer genetic recombination events in males, and the presence of sexually antagonistic genes.

Sexually antagonistic genes can have different effects on males and females, and their presence on the X chromosome can lead to genetic incompatibilities and reproductive isolation, promoting speciation.

Both hypotheses highlight the role of the X chromosome in speciation, with the dominance hypothesis emphasizing the expression of recessive alleles and the fast X hypothesis emphasizing the rapid evolution and accumulation of divergent genetic variations on the X chromosome.

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You examine sperm removed from the lumen of the epididymis. What
will you find?
a. Sperm undergoing meiotic cell divisions
b. Sperm undergoing mitotic cell divisions
c. Sperm in which cholesterol is b

Answers

Examining sperm removed from the lumen of the epididymis would reveal sperm in which cholesterol is present.

The epididymis is a coiled tube located in the male reproductive system, where sperm cells mature and acquire certain characteristics necessary for successful fertilization. One of these characteristics is the incorporation of cholesterol into the sperm membrane. Cholesterol plays a crucial role in maintaining the integrity and fluidity of the sperm cell membrane.

When examining sperm removed from the lumen of the epididymis, one would find sperm cells that have undergone maturation processes, including the incorporation of cholesterol into their membranes. This cholesterol helps to stabilize the structure of the sperm cell, ensuring that it maintains its viability and functional abilities during the journey through the female reproductive tract.

Therefore, the correct answer is c. Sperm in which cholesterol is present. The presence of cholesterol in the sperm membranes is a characteristic feature of mature sperm cells that have completed their development within the epididymis.

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A derived trait...
O is the same thing as an analogous trait.
O shares characteristics with an ancestral trait, but has adapted differently among different species.
O is something we develop in our lifetime and pass on to our children
O All of these answers are true

Answers

A derived trait shares characteristics with an ancestral trait but has adapted differently among different species.

A derived trait, also known as a derived characteristic or an evolutionary novelty, is a feature or trait that has evolved in a species or group of species and differs from the ancestral trait. It is important to note that a derived trait does not develop during an individual's lifetime and cannot be passed on to their children.

When a derived trait arises, it often shares some characteristics with the ancestral trait, but it has undergone modifications or adaptations that distinguish it from the ancestral state. These modifications can occur due to genetic changes, environmental factors, or selective pressures acting on the population over time. As a result, different species may exhibit different adaptations of the derived trait, reflecting their unique evolutionary paths and ecological contexts.

In contrast, an analogous trait refers to similar traits or features found in different species that have evolved independently in response to similar environmental or ecological pressures. These traits do not share a common ancestry and may have different underlying genetic mechanisms.

Therefore, the correct statement is that a derived trait shares characteristics with an ancestral trait but has adapted differently among different species.

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Disorders of the Ear
Describe otitis media and its cause, pathophysiology, and
signs
Describe the pathophysiology and signs of otosclerosis and of
Meniere’s syndrome
Explain how permanent hearing l

Answers

Otitis Media: Cause: Otitis media refers to inflammation or infection of the middle ear. It is commonly caused by a bacterial or viral infection that spreads from the upper respiratory tract or Eustachian tube dysfunction.

Pathophysiology: In otitis media, the Eustachian tube, which connects the middle ear to the back of the throat, becomes blocked or dysfunctional. This leads to the accumulation of fluid in the middle ear, providing a suitable environment for bacteria or viruses to grow and cause infection. The inflammation and fluid buildup can result in pain, pressure, and impaired hearing.

Signs: Common signs of otitis media include ear pain, hearing loss, feeling of fullness or pressure in the ear, fever, fluid draining from the ear, and sometimes redness or swelling of the ear.

Otosclerosis:  Otosclerosis is a condition characterized by abnormal bone growth in the middle ear, specifically around the stapes bone, which impairs its ability to transmit sound waves to the inner ear. This abnormal bone growth restricts the movement of the stapes, resulting in conductive hearing loss.

Signs: Signs of otosclerosis include progressive hearing loss, tinnitus (ringing in the ears), dizziness or imbalance, and sometimes a family history of the condition.

Meniere's Syndrome: Meniere's syndrome is a disorder of the inner ear that affects balance and hearing. It is believed to be caused by an abnormal accumulation of fluid in the inner ear, known as endolymphatic hydrops. The exact cause of this fluid buildup is not fully understood, but it may be related to factors such as fluid regulation disturbances, allergies, or autoimmune reactions.

Signs: Meniere's syndrome is characterized by episodes of vertigo (intense spinning sensation), fluctuating hearing loss (usually in one ear), tinnitus, and a feeling of fullness or pressure in the affected ear. These episodes can last for several hours to a whole day and may be accompanied by nausea and vomiting.

Permanent Hearing Loss:Permanent hearing loss can occur due to various factors, including damage to the hair cells in the inner ear, damage to the auditory nerve, or structural abnormalities in the ear.

Exposure to loud noises, certain medications, aging, infections, genetic factors, and other medical conditions can contribute to permanent hearing loss.

Once the delicate structures involved in hearing are damaged or impaired, they cannot be regenerated or repaired, leading to permanent hearing loss. Treatment options for permanent hearing loss often involve the use of hearing aids or cochlear implants to amplify sound and improve hearing.

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The American Heart Association suggests that adult men limit their added sugar intake per day to no more than teaspoons per day and adult women should limit their added sugar intake per day to no more than____teaspoons per day. ==== (Note: these are level teaspoons NOT Heaping teaspoons!) a. 5...4
b. 12...11 c. 9... 6 d. 3 ... 1

Answers

The American Heart Association suggests that adult men limit their added sugar intake per day to no more than 9 teaspoons per day, and adult women should limit their added sugar intake per day to no more than 6 teaspoons per day. Therefore, the correct answer is c) 9...6.

What does the American Heart Association suggest

The American Heart Association recommends specific guidelines for added sugar intake to promote healthy eating habits and reduce the risk of health issues such as obesity, diabetes, and heart disease.

These guidelines suggest that adult men should limit their added sugar intake to no more than 9 teaspoons per day, while adult women should limit their added sugar intake to no more than 6 teaspoons per day.

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Explain how mycorrhizal fungi may have evolved from ancestors that were originally parasite of plant roots? Do N. Johnson's results indicate that present-day mycorrhizal fungi may act as parasites? Why?

Answers

Mycorrhizal fungi have possibly evolved from ancestors that were originally parasites of plant roots. N. Johnson's results suggest that present-day mycorrhizal fungi may act as parasites.

The present scenario, we will explain how mycorrhizal fungi may have evolved from ancestors that were originally a parasite of plant roots and why N. Johnson's results suggest that present-day mycorrhizal fungi may act as parasites. In the process of evolution, mycorrhizal fungi evolved from parasitic ancestors, colonizing the roots of plants. Mycorrhizal fungi form a mutualistic association with plants, which aids in the exchange of carbon for nutrients, resulting in the survival of both the plant and the fungus. The ancestor of mycorrhizal fungi was a parasitic fungus that colonized plant roots and extracted nutrients from them, as previously stated. The evolution of mycorrhizal fungi is believed to have started when the ancestor fungus was able to feed on root hairs without killing the host plants.

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Which statement is FALSE about regulatory enzymes that are controlled allosterically?
a) They are less active when a allosteric inhibitor is bound to them.
b) They are often larger than other enzymes.
c) They have one binding site.
d) They often catalyze the first step in a reaction pathway.

Answers

The statement that is FALSE about regulatory enzymes that are controlled allosterically is "They often catalyze the first step in a reaction pathway."What is an enzyme?Enzymes are biological molecules that catalyze (increase the rate of) chemical reactions.

In metabolic pathways, they frequently serve as a means of controlling the chemical transformations that occur. There are a few different types of enzymes, but regulatory enzymes are one type that is involved in the process of metabolic regulation.What are regulatory enzymes?Regulatory enzymes, also known as regulated enzymes, are enzymes that regulate the rate of a metabolic pathway. In metabolic pathways, they serve as a means of controlling the chemical reactions that occur. They function as an on/off switch, allowing or preventing a reaction from occurring. Regulatory enzymes are usually controlled allosterically.

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In Aequorea victoria, the gene that codes for number of tentacles is located on an autosomal chromosome. The allele that codes for 6 tentacles is dominant over the allele that codes for 12 tentacles. The gene that codes for the shape of the edge of the bell is also on an autosomal chromosome and scalloped edges is dominant over straight edges (show your work for all crosses). Show your abbreviation key here: a. If you crossed a jelly that had 12 tentacles and straight bell edges with a jelly that was true-breeding (or homozygous) with 6 tentacles and scalloped bell edges, what would you expect to see in the offspring? b. If you crossed a jelly with 6 tentacles and scalloped bell edges with a jelly that had 12 tentacles and straight edges and got the following results in the F1 generation; 50% 6 tentacles and scalloped and 50% 12 tentacles and scalloped, what must be the genotypes of the parents? (show all options) c. If you crossed two jellies, both heterozygous for both traits, what would you expect to see among the F1 generation?

Answers

a. If you crossed a jelly with 12 tentacles and straight bell edges (12T/12T; SS/SS) with a jelly that was true-breeding for 6 tentacles and scalloped bell edges (6T/6T; SC/SC), the expected offspring would be heterozygous for both traits.

b. If you crossed a jelly with 6 tentacles and scalloped bell edges (6T/6T; SC/SC) with a jelly that had 12 tentacles and straight edges (12T/12T; SS/SS) and obtained a 50% ratio of 6 tentacles and scalloped bell edges to 12 tentacles and scalloped bell edges in the F1 generation, it suggests that the parent with 6 tentacles and scalloped bell edges is heterozygous for both traits (6T/12T; SC/SS) and the parent with 12 tentacles and straight bell edges is homozygous recessive for both traits (12T/12T; SS/SS). c. If you crossed two jellies, both heterozygous for both traits (6T/12T; SC/SS), you would expect to see a phenotypic ratio of 9:3:3:1 in the F1 generation.

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Sara was very ill, and her roommate noticed that Sara was
hypoventilating -- a slow, shallow breathing. There were even
moments of apnea when her breathing temporarily stopped.
Compare the exchange of

Answers

The effect of hypoventilation, characterized by slow and shallow breathing, can have several implications for Sara's body and overall health. When someone hypoventilates, it means that their breathing rate and depth are insufficient to meet the body's oxygen demands and eliminate an adequate amount of carbon dioxide.

The main effects of hypoventilation include:

Reduced oxygen levels: Slow and shallow breathing leads to decreased oxygen intake, resulting in lower oxygen levels in the bloodstream. This can lead to tissue hypoxia, where organs and tissues may not receive enough oxygen to function properly.

Increased carbon dioxide levels: Insufficient breathing also impairs the removal of carbon dioxide from the body. As carbon dioxide accumulates in the bloodstream, it can lead to a condition called hypercapnia. This can cause respiratory acidosis, a state of increased acidity in the blood.

Altered pH balance: The accumulation of carbon dioxide and subsequent increase in acidity can disrupt the body's pH balance, potentially leading to acidemia, which is a condition of low blood pH.

Respiratory distress: Hypoventilation may result in respiratory distress, where the body struggles to maintain adequate oxygenation and eliminate carbon dioxide. This can lead to feelings of shortness of breath, fatigue, and discomfort.

It's important to note that hypoventilation can have various underlying causes, such as respiratory conditions, neurological disorders, or the use of certain medications. If Sara is experiencing hypoventilation, it is crucial for her to seek medical attention to identify the cause and receive appropriate treatment.

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Explain the overall lifecycle of a typical member of the
Basidiomycota Fungi. Include a sketch with labels and FULLY Explain
all terminology including: plasmogamy and karyogamy.

Answers

The lifecycle of a typical member of the Basidiomycota fungi is a complex process that involves both sexual and asexual reproduction.

What is the lifecycle of a Basidiomycota fungi?

The fungus begins its life as a haploid spore, which germinates to form a mycelium. The mycelium is a network of branching filaments that grows through the substrate, absorbing nutrients.

When two compatible hyphae meet, they fuse in a process called plasmogamy. This fusion of cytoplasm does not involve the fusion of nuclei. The hyphae then continue to grow, forming a di-karyotic mycelium. In a di-karyotic mycelium, each cell contains two nuclei, one from each of the parent hyphae.

The di-karyotic mycelium eventually produces a fruiting body, such as a mushroom. The fruiting body contains specialized cells called basidia. The basidia undergo karyogamy, a process in which the two nuclei fuse to form a diploid nucleus. The diploid nucleus then undergoes meiosis, a process in which the chromosomes are divided into four haploid daughter cells.

The haploid daughter cells are then released from the basidia as spores. The spores are dispersed by wind or other agents, and they germinate to form new haploid mycelia. The cycle then repeats.

Terminology

Plasmogamy: The fusion of two haploid cells, without the fusion of nuclei.

Karyogamy: The fusion of two nuclei to form a diploid nucleus.

Meiosis: A process in which the chromosomes are divided into four haploid daughter cells.

Spore: A reproductive unit that can germinate to form a new individual.

Mycelium: A network of branching filaments that forms the body of a fungus.

Fruiting body: A specialized structure that produces spores.

Basidium: A specialized cell that produces spores.

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Rates of calcification in the Corallinales are highest when pH
is a) low b) neutral c) high

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The rates of calcification in the Corallinales are highest when pH is high. The Corallinales is an order of red algae.

They are found in marine environments worldwide, including the deep sea and the intertidal zone. They have a calcified skeleton that makes them important reef-building organisms, and they are frequently found in coral reefs. These organisms are also used as food in some cultures, and they are sometimes used in traditional medicine.

The Corallinales has a calcified skeleton that makes them important reef-building organisms. Calcification is the process by which organisms such as Corallinales secrete calcium carbonate to form a hard, protective structure around themselves.

The rates of calcification in the Corallinales are influenced by a variety of factors, including pH. Research has shown that the rates of calcification in the Corallinales are highest when pH is high. When the pH is low, the Corallinales experience a decrease in calcification rates, which can have negative consequences for their survival and the ecosystem they are a part of.In conclusion, the rates of calcification in the Corallinales are highest when pH is high.

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he relative fitnesses of AjA1, A,A2, and A A2 are 0.5, 0.8, and 1 respectively. What is the expected result of natural selection in this situation? A will increase and A2 will decrease. Az will increase and A will decrease. Both alleles will decrease in frequency. A stable equilibrium will be achieved in which both alleles are maintained, An unstable equilibrium will exist and the outcome depends on the allele frequencies.

Answers

The expected result of natural selection in this situation is that A will increase and A2 will decrease.

This is because A has the highest relative fitness of 1, indicating that it is the most advantageous allele. As a result, individuals with the A allele will have higher survival and reproductive success, leading to an increase in its frequency over time. Conversely, A2 has a relative fitness of 0.5, indicating a disadvantageous trait, and thus, individuals with the A2 allele will have lower fitness and a reduced likelihood of passing on their genes. Therefore, natural selection will favor the A allele and result in its increase while causing a decrease in the frequency of the A2 allele.

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1. Explain how a change in transcription factor regulation can cause a homeotic mutation. 2. Describe a potential future selective pressure that will alter the evolutionary fate of Homo sapiens.

Answers

A change in transcription factor regulation can cause a homeotic mutation by disrupting the normal expression pattern of genes involved in body patterning and development. One potential future selective pressure that could alter the evolutionary fate of Homo sapiens is the emergence of new diseases or pandemics.

Homeotic mutations are genetic alterations that result in the transformation of one body part into another. They are often caused by changes in the regulation of transcription factors, which are proteins that control the expression of genes during development.

Transcription factors bind to specific DNA sequences and activate or repress the transcription of target genes.

In a normal developmental process, specific transcription factors are responsible for regulating the expression of genes that determine the identity and fate of different body segments.

However, a change in transcription factor regulation can lead to the misexpression of these genes, causing a body part to develop in an incorrect location or assume the characteristics of another body part.

For example, if a transcription factor that normally regulates the development of a specific body segment is misregulated or absent, it can result in the transformation of that segment into a different segment, leading to a homeotic mutation.

Understanding the intricate regulation of transcription factors and their role in controlling gene expression is crucial for comprehending the mechanisms underlying homeotic mutations.

One potential future selective pressure that could alter the evolutionary fate of Homo sapiens is the emergence of new diseases or pandemics.

Throughout human history, diseases have played a significant role in shaping the course of evolution.

The emergence of new diseases or pandemics can exert selective pressures on populations, favoring individuals with genetic variations that provide resistance or increased immunity against the specific pathogens.

In recent times, we have witnessed the impact of diseases like HIV, SARS, and COVID-19 on human populations. These outbreaks have led to changes in behavior, healthcare practices, and advancements in medical research.

Over time, these selective pressures can result in the evolution of populations with enhanced immune responses, improved genetic defenses, or changes in susceptibility to certain diseases.

Furthermore, the global interconnectedness and increased mobility of populations create opportunities for the rapid spread of infectious diseases. As pathogens evolve, human populations will continually face new challenges, potentially driving evolutionary adaptations in response to these selective pressures.

It is important to note that the future selective pressures on Homo sapiens are unpredictable, and multiple factors, including environmental changes and social dynamics, can also influence the evolutionary trajectory of our species.

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