Which of the following is a limited resource

Mass if a substance is the product of its volume and density. The mass of gold of 0.02 m³ with a density of 19300 kg/m³ is 386 kg.

Density of a substance is the measure of its mass per unit volume. Thus, it says how much denser the object is in a given volume. Density of a substance is dependent on its bond type, temperature and pressure beside the volume and mass.

Volume can be defined as the space occupied by the substance. Larger the volume , less dense the substance is. However as the mass increases volume also increases.

Mass of an object is the product of its volume and density.

Given the volume of gold = 0.02 m³

density = 19300 kg/m³.

mass = volume ×  density

         = 0.02 m³ × 19300 kg/m³

         = 386 kg

Therefore, the mass of gold is 386 Kg.

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Answer:

I think it's false

Explanation:

clouds also help regulate the Earth's energy balance by reflecting and scattering solar radiation and by absorbing the Earth's infrared radiation.

Answer:

false

Explanation:

Answer:

D-A radiator emitting warm air and drawing in cool air

Explanation:

Answer:

Explanation:

The car will fall with acceleration due to gravity which is equal to 9.8 m /s²

For downward fall ,

initial velocity u = o

acceleration due to gravity = g = 9.8 m /s

final velocity v = ?

displacement h = 5.2 m

v² = u² + 2 gh

v² = 0 + 2 x 9.8 x 5.2

= 101.92

v = 10.1 m /s

Answer:

The Lambda-CDM model contains a cosmological constant, denoted by a lambda (λ), which is associated with dark energy and cold dark matter.

^Also works for Plato users.

Answer:

"cold dark matter"

Explanation:

other person is correct!!!

Answer:

c

Explanation:

c. the ability to do work or to produce heat

Answer:

When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.

Answer:

3.766 kg or 3.7 kg

Explanation:

F= M*A equation

Answer:

A supply of compressed air is maintained aboard the submarine in air flasks for life support and for use with the ballast tanks. In addition, the submarine has movable sets of short "wings" called hydroplanes on the stern (back) that help to control the angle of the dive.

Explanation:

Hope this helped u

Have a nice day

Answer:

a. endothermic

Explanation:

The reaction shown is an endothermic reaction. In such reaction, they require an input of energy.

Explanation:

... in every interaction, there is a pair of forces acting on the two interacting objects. The size of the force on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.

Explanation:

0.10kg

0.5kg×0.2kg=

0.10

Answer:

Digestion begins in the mouth, when you chew.

Answer:

I think it's part c . but sorry if its wrong

Answer:

Evidence for continental drift

Wegener knew that fossil plants and animals such as mesosaurs, a freshwater reptile found only South America and Africa during the Permian period, could be found on many continents. He also matched up rocks on either side of the Atlantic Ocean like puzzle pieces.

Explanation:

Answer:

b

Explanation:

Answer:

a

Explanation:

because the crest and trough are the same length when together and they squeeze together making the length shorter for higher frequencies and are spaced apart when lower frequencies occur

Answer:

men

Explanation:

Answer:

A.100J

Explanation:

Given parameters:

Force on car = 20N

Distance  = 5m

Unknown:

Work done  = ?

Solution:

Work done is the product of force and distance;

  Work done  = force x distance;

Insert given parameters and solve;

        Work done  = 20 x 5  = 100J

Answer:

The shortest possible distance is  [tex]|s| = 91.9 \ m[/tex]

Explanation:

From the question we are told that

   The mass of the car is   [tex]m = 1800 \ kg[/tex]

    The speed along the horizontal road is  [tex]v_o =u = 18.4 \ m/s[/tex]

     The static friction coefficient is  [tex]\mu_s = 0.188[/tex]

      The kinetic friction coefficient is  [tex]\mu_k = 0.1316[/tex]

Generally the static frictional force acting on the car is  mathematically represented as

          [tex]F_f = m * g * \mu_s[/tex]

Generally the force propelling the car is mathematically represented as

        [tex]F = m * a[/tex]

Here a is the maximum acceleration

at the point which the car stops ,

       [tex]F = F_f[/tex]  

=> [tex]m * g * \mu_s = ma[/tex]

=> [tex]g * \mu_s =a[/tex]

=> [tex]a = 9.8 * 0.188[/tex]

=> [tex]a = 1.8424 \ m/s^2[/tex]

Generally from kinematic equation

    [tex]v^2 = u^2 + 2as[/tex]

Here v  is the final velocity of the car and the value is zero given that the car comes to rest

So

        [tex]0^2 = 18.4^2 + 2* 1.8424 s[/tex]

=>     [tex]s = - \frac{18.4^2}{2 * 1.8424}[/tex]

=>     [tex]|s| = 91.9 \ m[/tex]

Answer:

reflection

Explanation:

Answer:

reflection

Explanation:

A p e x

Answer:

Metaphase

Explanation:

During metaphase,chromosome line up in the middle of the cell.

Answer:

Explanation:

For vertical displacement of food-supply

if time taken to reach the ground be t

235 = 1/2 g t²  , initial velocity downwards is zero.

t = 6.92 s

Horizontal displacement of food during this period

= 6.92 x 69.4 m

= 480.25 m .

b )

time required to cover horizontal distance of 425 m

= 425 / 69.4 = 6.124 s  

This time period will be the time of vertical fall of 235 m . Let initial vertical velocity required be u

h = ut + 1/2 gt²

235 = u x 6.124 + .5 x 9.8 x 6.124²

235 = u x 6.124 + 183.76

u = 8.36 m /s

c )

v = u + gt

= 8.36 + 9.8 x 6.124

= 68.37 m /s

This will be vertical component of velocity .

horizontal velocity = 69.4 m /s

resultant velocity = √ ( 68.37² + 69.4²)

= √(4674.45 +4816.36)

= 97.42 m /s

Answer:

Ultrasou­nd has been used in a variety of clinical settings, including obstetrics and gynecology, cardiology and cancer detection. The main advantage of ultrasound is that certain structures can be observed without using radiation. Ultrasound can also be done much faster than X-rays or other radiographic techniques

Answer:

Ultrasound can be used for various purposes like diagnosing conditions, including those in the heart, blood vessels, liver and more. Yet most commonly to monitor growth and development of a fetus. A echocardiogram is a ultrasound of the heart.

Explanation:

Answer: the answer is c

Explanation:

1. Heat transfer from a hot burner on the stove into a pot or pan

2. A metal spoon that gets hot from the boiling water

3. Chocolate candy in your hand that melts because of the heat

4. The wires in your house that conduct electricity

5. Roasting marshmallows, the heat will soften the marshmallow

Answer:

the engine heat from a car you just turned on.

a heater

a pad warmer

a hot pot

using a campfire to roast hot dogs

Answer:

a)  y_total = 575.4 m , b)   t_total = 22.56 s , c)  v = 106.20 m

Explanation:

a) We can solve this exercise using the scientific relations

Let's find the height reached while the engines are running

         v₁ = v₀ + a t

         v₁ = 62.3 + 4.30 3.73

         v₁ = 78.339 m / s

in this time it rose

        y₁ = v₀ t₁ + ½ a t₁²

        y₁ = 62.3 3.73 + ½ 4.30 3.73²

         y₁ = 262.29 m

At this moment the engines are turned off and the rocket continues in a vertical launch, suppose that the acceleration of gravity is constant in this path

        v₂ = v₁ 2 - 2 g y₂

at maximum height the velocity is zero (v₂ = 0)

        y₂ = v₁ 2 / 2g

        y₂ = 78.339 2/2 9.8

        y₂ = 313.11 m

the total height is

       y_total = y₁ + y₂

       y_total = 262.29 + 313.11

       y_total = 575.4 m

b) the time the rocket is in the air is

       t_total = t₁ + t₂

where t₂ is the time after the engines have shut down

       y = y₁ + v₁ t₂ - ½ g t₂²

      y = 0

      0 = 262.29 + 78.339 t₂ - ½ 9.8 t₂²

      t₂² - 15.99 t₂ - 53.53 = 0

      t₂ = [15.99 ±√ (15.99² +4  53.53)] / 2

      t₂ = [15.99 ± 21.67] / 2

      t₂´ = 18.83 s

      t₂´´ = -2.84 s

since the time must be a positive quantity the correct result is t2 = 18.83 s, the total time in the air is

      t_total = 3.73 + 18.83

      t_total = 22.56 s

c) the speed when it hits the ground

We can perform this calculation starting with the maximum height y = 575.4 m where it has zero initial velocity (vo = 0)

      v² = v₀² + 2 g y

      v = √ 2gy

       v = √ (2 9.8 575.4)

       v = 106.20 m