Which nucleus completes the following equation?

Answer:

try S or Q

Explanation:

Answer: 0.00693

Explanation:

Given

Spring constant [tex]k=2\ N/m[/tex]

Mass of object [tex]m=75\ g[/tex]

The amplitude of the oscillation decreases from 10 mm to 5 mm  in 15 s

Equation of amplitude for the ideal spring-mass system is

[tex]\Rightarrow A=A_oe^{-\frac{bt}{2m}}\quad \quad [\text{b=damping constant}]\\\text{Insert the values}\\\\\Rightarrow 5=10e^{\frac{b\times 15}{2\times 0.075}}\\\\\Rightarrow e^{-\frac{b\times 15}{2\times 0.075}}=0.5\\\\\text{Taking natural log both sides}\\\\\Rightarrow \ln \left(e^{-\frac{b\times 15}{2\times 0.075}}\right)=\ln 0.5\\\\\Rightarrow -\dfrac{15b}{0.15}=-0.693\\\\\Rightarrow b=0.00693[/tex]

Answer:

the magnitude of the velocity of one particle relative to the other is 0.9988c

Explanation:

Given the data in the question;

Velocities of the two particles = 0.9520c

Using Lorentz transformation

Let relative velocity be W, so

v[tex]_r[/tex] = ( u + v ) / ( 1 + ( uv / c²) )

since each particle travels with the same speed,

u = v

so

v[tex]_r[/tex] = ( u + u ) / ( 1 + ( u×u / c²) )  

v[tex]_r[/tex] = 2(0.9520c) / ( 1 + ( 0.9520c )² / c²) )  

we substitute

v[tex]_r[/tex] = 1.904c / ( 1 + ( (0.906304 × c² ) / c²) )  

v[tex]_r[/tex] = 1.904c / ( 1 + 0.906304 )

v[tex]_r[/tex] = 1.904c / 1.906304

v[tex]_r[/tex] = 0.9988c

Therefore, the magnitude of the velocity of one particle relative to the other is 0.9988c

The work-energy theorem says that the total work done on the block is equal to the difference of its kinetic energies at points B and A. Then the total work done on the block is

[tex]W_{\rm total} = K_B - K_A = 4.0\,\mathrm J - 5.0\,\mathrm J = -1.0\,\mathrm J[/tex]

Friction acts on the block to oppose its motion, so it does negative work on the block, -4.5 J.

The only other force acting on the block as it moves is the force P. Let [tex]W_P[/tex] be the work done by the force P. Then the total work done on the block is

[tex]W_{\rm total} = W_P + W_{\rm friction} \iff -1.0\,\mathrm J = W_P - 4.5 \,\mathrm J \implies W_P = \boxed{3.5\,\mathrm J}[/tex]

Answer:

b

Explanation:

The materials are most likely used to change the surface area of the ramp. For example, the sand paper can change the ramp's texture. The wax paper can also change the surface area of the ramp by texture, it can be made smoother.

Answer:

B.

Explanation:

Hope it helped!

Answer:

To protect us.

Explanation:

For ex. your dunking on a basketball hoop if that wasn't strong you would fall on your back and get injured.

Answer:

If you use P = 2 * pi * (L / g)^1/2  for the period of the simple pendulum

g = 4 * pi^2 * 1.2 / 2.8^2 = 6.04 m/s2

Note: omega = 2 pi * f = 2 pi / P  and omega = (g / L)^1/2

Answer:

6.0426 m/s^2

Explanation:

The period of a simple pendulum is equal to 2pi sqroot L/g

T = 280s/100 rev = 2.8s

Plug in 1.2 m for L and 2.8s for T, then solve for g to get 6.04 m/s^2 (dependent on how you round)

Answer:

The right solution is "0.511".

Explanation:

Given:

Initial moment of inertia,

= 1630 kg.m²

Radius,

= 5 m

Angular speed,

= 1.6 rad/s

Now,

The moment of inertia after stepping on will be:

= [tex]1630+2\times (69.5\times (5)^2)[/tex]

= [tex]1630+2\times (69.5\times 25)[/tex]

= [tex]5105 \ Kg.m^2[/tex]

hence,

As per the question, the angular speed is conserved, then

⇒ [tex]1630\times 1.6=5105\times \omega'[/tex]

            [tex]2608=5105\times \omega'[/tex]

                [tex]\omega'=\frac{2608}{5105}[/tex]

                     [tex]=0.511[/tex]

Answer:

In which school you are???

Explanation:

Answer:

V=IR

since the circuit is parallel both resistor have same voltage and different current value according to OHMs law.

total resistance in parallel=

1/R=1/R1+1/R2+...+1/Rn

since we have two resistor in parallel

Rt=R1R2/R1+R2

2*4/2+4=4/3 ohms

I=V/R

12/4/3=36/4=9Amp

OR

I=12/2=6amp

I=12/4=3amp

total current

I=6+3

9amp

The correct option is E. Increase her speed​

High-diving is the process or way in which a person jump into water  or swimming pool from a higher heights.

A Diver  is a person who dive or Fall into a water from a top board or diving board .

Therefore she was curving her body from the top board in order to Increase her speed​ which will enable her to spin or flip more faster.

Inconclusion The correct option is E. Increase her speed.

Learn more about Diving here:

https://brainly.com/question/2784286

Answer:

  α = 0.357 ras / s²

Explanation:

This is a rotational kinematics exercise, it tells us that it performs 10 squats in 30 s, for which it performs one squat at t = 3 s, also indicates that the angle of the squat is θ = 92º

            θ = θ₀ + w₀ t + ½ α t²

the athlete starts from rest, whereby w₀ = 0 and the initial angle in the vertical position is zero (θ₀=0)

            θ = ½ α t²

            α = 2 θ /t²

let's reduce the magnitudes to the SI system

            θ = 92º (π rad /180º) = 0.511π rad

let's calculate

            α = 2 0.5111π /3²

            α = 0.1136π rad / s²

            α = 0.357 ras / s²

Answer:

just multiply the frequency and wavelength

200× 2

400

Answer:

"In water, the speed of light is v01.33=2.26 x 108 m/s."

Explanation:

Answer:

Explanation:

From the options given,

The atmospheric features of Neptune are easier to see than those of Uranus because Neptune has more methane

Neptune has small amount of methane and water which gives it blue colour and white patches which distinguish it from uranus

For more information, visit

http://abyss.uoregon.edu/~js/ast121/lectures/lec20.html

Answer:

The person's velocity is zero.

Explanation:

Answer:

The f-ratio describes the relationship between the lens diameter and the focal length and is calculated by dividing the focal length by the diameter of the lens. For example, if a lens were to have a focal length of 50mm and a diameter of 10mm, then the f-ratio would be 50mm/10mm=5 or otherwise referred to as f5.

Explanation:

Answer:

The f-ratio describes the relationship between the lens diameter and the focal length and is calculated by dividing the focal length by the diameter of the lens. For example, if a lens were to have a focal length of 50mm and a diameter of 10mm, then the f-ratio would be 50mm/10mm=5 or otherwise referred to as f5.

Explanation:

i just want a thank you :)

Answer:

V = 3.5 x 10⁻⁶ m³/s = 3.5 cm³/s

Explanation:

The volume flow rate of the blood in the artery can be given by the following formula:

[tex]V = Av[/tex]

where,

V = Volume flow rate = ?

A = cross-sectional area of artery = πd²/4 = π(0.004 m)²/4 = 1.26 x 10⁻⁵ m²

v = velcoity = 0.28 m/s

Therefore,

[tex]V = (1.26\ x\ 10^{-5}\ m^2)(0.28\ m/s)[/tex]

V = 3.5 x 10⁻⁶ m³/s = 3.5 cm³/s

Answer:

Transverse.

Explanation:

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

An electromagnetic spectrum refers to a range of frequency and wavelength that an electromagnetic wave is distributed or extends. The electromagnetic spectrum comprises of gamma rays, visible light, ultraviolet radiation, x-rays, radio waves, and infrared radiation.

A transverse wave can be defined as a type of wave in which particles of the medium of propagation oscillates or vibrates in a direction that is perpendicular to the direction that the wave moves i.e at right angle to the direction of propagation of the wave.

Basically, sound is a transverse and all transverse wave are the direct opposite of a longitudinal wave that usually travel in the same direction of its oscillation.

Hence, this wave is transverse.

Answer:

F = 580.75 N

Explanation:

The force can be calculated through the following formula:

[tex]F = PA[/tex]

where,

F = Force = ?

P = Pressure = (72 mm Hg)(133.322 Pa/1 mm Hg) = 9599.18 Pa

A = Area = (605 cm²)(1 m²/10⁴ cm²) = 0.0605 m²

Therefore,

[tex]F = (9599.18\ Pa)(0.0605\ m^2)[/tex]

F = 580.75 N

Answer:

The air in the soil is similar in composition to that in the atmosphere with the exception of oxygen, carbon dioxide, and water vapor. In soil air as in the atmosphere, nitrogen gas (dinitrogen) comprises about 78%. In the atmosphere, oxygen comprises about 21% and carbon dioxide comprises about 0.036%.

hope this helps

have a good day :)

Explanation:

Answer:

Apparent weight of pilot due to centripetal acceleration:

m v^2 / R = 5 g m = 5 * 70 * 9.8 = 3430 N

Weight of pilot = 70 * 9.8 = 686 N

Total = 3430 + 686 = 4116 N

Answer:

Explanation:

comfortable distance is 25 cm .

He must be using convex lens . In that case rays coming from object placed at 25 cm appears to be coming from 59.1 cm due to converging nature of convex lens.

object distance u = -25 cm

image distance v = -59.1 cm

Lens formula

1 / v - 1 /u = 1 /f

-1 / 59.1 + 1 / 25 = 1/f

- .0169 + .04 = 1 / f

.0231 = 1 / f

f = 43.3 m

Answer:

Solution given:

North car

mass[m1]=1460kg

velocity[u1]=27 m/s

mass[m2]=2165kg

velocity [u2]=18m/s

let v be velocity after collision

we have

From the principle of conservation of linear momentum

m1u1+m2u2=(m1+m2)v

1460*27+2165*18=(1460+2165)v

v=[tex] \frac{78390}{3625} [/tex]

v=21.6m/s

the speed after the collision in 21.6 m/s.

For angle.

Tan angle =[tex] \frac{m1u1}{m2u2} [/tex]

Tan angle =[tex] \frac{1460*27}{2165*18} [/tex]

Tan angle=327.74

angle=Tan-¹(327.74)=89.82=90°

in degrees north of east is 90°

Answer:

[tex]T=35.625sec[/tex]

Explanation:

From the question we are told that:

Length [tex]L=100 m[/tex]

Width [tex]W=50m[/tex]

Velocity of Car A [tex]V_A=5m/s[/tex]

Velocity of Car B [tex]V_B=3m/s[/tex]

Distance traveled by car A before car B moves

[tex]d_l=5*3[/tex]

[tex]d_l=15[/tex]

Therefore total distance traveled at same time interval

[tex]D=total\ distance-d_l[/tex]

Where

Total distance=Perimeter of rectangle

[tex]P=2(L+B)[/tex]

[tex]P=2(100+50)[/tex]

[tex]P=300[/tex]

Therefore

[tex]D=total\ distance-d_l[/tex]

[tex]D=300-15\\D=285m[/tex]

Generally the equation for time taken to meet is mathematically given by

[tex]T=\frac{Distance D}{Relative\ speed V_r}[/tex]

Where

Relative speed = Speed of car A +Speed of car B

[tex]V_r=V_A+V_B[/tex]

[tex]V_r=5+3[/tex]

[tex]V_r=8m/s[/tex]

Therefore the time taken to meet

[tex]T=\frac{ D}{ V_r}[/tex]

[tex]T=\frac{ 285}{ 8}[/tex]

[tex]T=35.625sec[/tex]