it's the last one because it's depended on the rock layers
Answer:
The law of superposition is used to determine a rocks relative age.
How many grams of silver nitrate are needed to prepare 0.125 M solution in 250.0 mL of water?*
(1 Point)
AgNO₃
Ag
= 107.868 8
mol
N = 14.0078
mol
8
0 = 15.999
mol
0.313 g
169.872 g
0.0849 g
5.31 g
O 31.3 g
Answer:5.3 grams AgNO3
Explanation:
To solve your problem, take a look at the definition of molality (m):
moles of solute/kg of solvent
You are given the grams of solvent (water) to find the grams of silver nitrate.
First, convert 250 grams to kg:
250 g * 1 kg / 1000g = 0.250 kg
Now that you have the kg of solvent, you can solve for the moles of solute:
kg of solvent * molality = moles of solute
0.250 kg * 0.125 m = 0.03125 mol AgNO3
You can convert the number of moles to grams using the molar mass of AgNO3, which is 169.872 g/mol:
moles of solute * molar mass of solute = grams of solute
0.03125 mol AgNO3 * 169.872 g/mol = 5.3085 g
Because your question provides two significant digits, you must round this number to get the final answer:
5.3 grams AgNO3
I hope this helps!
3. You can express the density of an object in units of kg/L or in units of
g/mL. How is the density of an object in kg/L related to its density in g/mL?
Given the following balanced chemical equation:
N2(g) + 3H2(g) + 2NH3(8)
What is the maximum amount of NH3(g) that can be produced from 2.0 mol H2(g)? Assume that N2(g) is the excess reactant.
Answer:
22 g
Explanation:
Step 1: Write the balanced equation
N₂(g) + 3 H₂(g) ⇒ 2 NH₃(g)
Step 2: Calculate the moles of NH₃ produced from 2.0 moles of H₂
The molar ratio of H₂ to NH₃ is 3:2.
2.0 mol H₂ × 2 mol NH₃/3 mol H₂ = 1.3 mol NH₃
Step 3: Calculate the mass corresponding to 1.3 moles of NH₃
The molar mass of NH₃ is 17.03 g/mol.
1.3 mol × 17.03 g/mol = 22 g
list 5 island in the Philippines
Answer:
Coron, Palawan, El Nido, Palawan, Cebu, Boracay, Siargao.
Explanation:
I hope this helps.
coron,palawan,El nidu, Cebu and boracay are 5 island in Philippines.....
which has more gravity
A. Earth
B. Sun
C. Saturn
B
the sun!
yay
!!!!!!!!!!!
Answer:
EARTH
Explanation:
Earth‘s gravity, as already noted, is equivalent to 9.80665 m/s² (or 32.174 ft/s²). This means that an object, if held above the ground and let go, will accelerate towards the surface at a speed of about 9.8 meters for every second of free fall.
Richard sketched models of two different neutral isotopes of oxygen. If the
isotope models are accurate, which statement might be true? (Refer to the
periodic table if necessary.)
A. One shows 7 protons, and one shows 9.
B. One shows 8 neutrons, and one shows 9.
C. One shows 8 electrons, and one shows 9.
D. One shows 8 protons, and one shows 7.
Answer:
its b
Explanation:
just did the test on A P E X
If the isotope models are accurate, One shows 8 neutrons, and one shows 9. Therefore, the correct option is option B.
What is isotope?A chemical element's isotope is one of more than one species of atoms that share the same atomic number, spot on the periodic table, and almost identical chemical activity, but differ in atomic mass and physical characteristics. There are a number of isotopes for each chemical element.
The first step in identifying and labelling an atom is to count the protons within its nucleus. Usually, this nuclear number is denoted by the letter Z. The fact that all atoms possessing the same number of electrons have essentially equal chemical characteristics lends the atomic number its enormous significance. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.
Therefore, the correct option is option B. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.
To know more about isotope, here:
https://brainly.com/question/11680817
#SPJ5
Can someone please rephrase this question, I dont understand what it is asking for.
Which disease might have cures developed as a result of their understanding of structure and function of protein?
Answer:
Which infection may have fixes created because of their comprehension of construction and capacity of protein?
What are mand n in the rate law equation?
Rate = k[A]”[B]"
A (they are experimentally determined exponents)
A continuously stirred tank reactor is designed to remove the hazardous waste compound trichloroethylene (TCE) from industrial wastewater. The tank is 3250 liters. The wastewater flows into the tank at 200 L/min with a TCE concentration of 25 mg/L. The reactor decays TCE at a reaction rate of 0.20 min-1 . What is the steady-state concentration of TCE in the treated water leaving the reactor
Answer:
the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L
Explanation:
Given that;
Tank volume v = 3250 liters
wastewater flows into the tank Q = 200 L/min
TCE concentration Co= 25 mg/L
reactor decays TCE at a reaction rate K = 0.20 min-1
mass balance
we know that;
Accumulation = inflow - outflow ± generation
⇒dc/dt = QCo - Qc ± rc.V
now at a steady state; dc/dt = 0
so
0 = QCo - Qc + rcV
where rc = -kc
0 = QCo - Qc - kcV
Qc + kcV = QCo
c(Q + kV) = QCo
c = QCo / (Q + kV)
so we substitute
c = (200 × 25) / (200 + (0.2×3250))
c = 5000 / 850
c = 5.88 mg/L
Therefore, the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L
Hello! Please help :((
Find the distance from point B to point C. Enter as a decimal rounded to the nearest tenth. А 61° 5.7 mi B С BC = [?] mi Enter
Answer:
BC = 10.28 ≈ 10.3 mi to the nearest tenth
Explanation:
Using the trigonometry rules; SOH CAH TOA,
TOA would be more suitable in this question.
Tan ∅ = Opposite / Adjacent
Tan 61 = BC / AB
1.8040 = BC / 5.7
BC = 5.7 * 1.8040
BC = 10.28 ≈ 10.3 mi
the answer is 10.3, i already rounded it.
Help me please omg
Answer the following question:
How many moles of ammonia are in 375. mL of a 2.25 M aqueous ammonia solution?
Find the numerical answer for this question and make sure to include the following:
What is the chemical formula for ammonia?
What is the formula for molarity?
When you give your numerical answer, what is the correct significant figures and how do you know that is the correct amount?
Answer:
NH₃
M = n/V(L)
0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)
Explanation:
Step 1: Given and required data
Volume of solution (V): 375. mLMolar concentration of the solution (M): 2.25 MChemical formula for ammonia: NH₃Step 2: Calculate the moles (n) of ammonia (solute)
Molarity is equal to the moles of solute divided by the liters of solution.
M = n/V(L)
n = M × V(L)
n = 2.25 mol/L × 0.375 L = 0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)
____ Al + ____ Cr2O3 ____ Al2O3 + ____ Cr
If the reaction of 23.3 grams of Cr2O3 produces 5.35 grams
of Al2O3, what is the percent yield?
Answer:
[tex]Y=34.3\%[/tex]
Explanation:
Hello there!
In this case, according to the balanced chemical reaction:
[tex]2Al + Cr_2O_3 \rightarrow Al_2O_3 + 2Cr[/tex]
We notice there is a 1:1 mole ratio between Al2O3 and Cr2O3; thus, the following stoichiometric setup is used to compute the theoretical yield first:
[tex]m_{Al_2O_3 }=23.3gCr_2O_3*\frac{1molCr_2O_3}{151.99gCr_2O_3} *\frac{1molAl_2O_3}{1molCr_2O_3} *\frac{101.96gAl_2O_3}{1molAl_2O_3} \\\\m_{Al_2O_3}=15.6gAl_2O_3[/tex]
Thus, the percent yield turns out:
[tex]Y=\frac{5.35g}{15.6g} *100\%\\\\Y=34.3\%[/tex]
Best regards!
The hydronium ion concentration of an aqueous solution of 0.502 M pyridine (a weak base with the formula C5H5N) is
Answer:
1.99×10¯¹⁴ M
Explanation:
We'll begin by writing the balanced dissociation equation of pyridine. This is illustrated below:
C₅H₅N + H₂O <=> C₅H₆N⁺ + OH¯
From the balanced equation above,
1 mole of C₅H₅N produced 1 mole of OH¯.
Therefore, 0.502 M C₅H₅N will also produce 0.502 M OH¯.
Finally, we shall determine the concentration of hydronium ion, H₃O⁺ in the solution. This can be obtained as follow:
Concentration of Hydroxide ion [OH¯] = 0.502 M
Concentration of hydronium ion [H₃O⁺] =?
[H₃O⁺] [OH¯] = 1×10¯¹⁴
[H₃O⁺] × 0.502 = 1×10¯¹⁴
Divide both side by 0.502
[H₃O⁺] = 1×10¯¹⁴ / 0.502
[H₃O⁺] = 1.99×10¯¹⁴ M
Thus, the concentration of hydronium ion, H₃O⁺ in the solution 1.99×10¯¹⁴ M
CH3CH3C(CH3)2CH2I classification and name
Answer:
1,2 di methyl 5 ene tri chloro hexane
tell me how is your life as a youngster
Answer:
ruthless, my style as a juvenile
ran with a gang, slanged in the meanwhile
Explanation:
1. How would you describe what red cabbage juice is?*
(1 Point)
Acid
Neutral
Alkali
Indicator
Salt
**will give brainlists if correct answer***
Predict all of the products of the incomplete reaction shown below.
K+ Cl2 →
A)KCIO3
B)K2
С)КСІ
D)KCI2
Answer:
C)
Explanation:
Can someone help with these questions please???
(trying this again because this test is due at 3 and paimon has to get this done or she will fail!! paimon will try to give brainlist if brainly lets her!!)
The _________________molecules in the food we eat are_____________.
A. Enzyme, water
B. Small, insoluble
C. Large, insoluble
D. Enzyme, insoluble
Ge(NO2)2 whats the name of this formula?
Answer:
Germanium monoxide
hope this helps :)
Surface tension is a force that affects....
A. Gases
B. Plasmas
C. Solids
D. Liquids
Answer:
option A iis the right answer
Use the drop-down menus to label the graph
according to its type.
Answer:
relation (but not a function)
Explanation:
c on edge
A silver nitrate solution contains 14.77 g of primary standard AGNO3 ( Molecular weight 169.87) in 1.00 L. What volume of this solution will be needed to react with 0.2631 g of NaCl ( Molecular weight 58.44) ?
Answer:
[tex]V=5.2 mL=0.052L[/tex]
Explanation:
Hello!
In this case, since the chemical reaction between silver nitrate and sodium chloride is:
[tex]AgNO_3(aq)+NaCl(aq)\rightarrow AgCl(s)+NaNO_3(aq)[/tex]
We can see there is a 1:1 mole ratio between each solution; thus, we first compute the moles of each reactant considering their molar masses:
[tex]n_{AgNO_3}=14.77g*\frac{1mol}{169.87g}=0.087molAgNO_3\\\\ n_{NaCl}=0.2631g*\frac{1mol}{58.44}=0.0045molNaCl[/tex]
Now, since the concentration of the silver chloride solution is 0.087 M, we may assume that the concentration of the NaCl solution is the same, so we can compute the volume as shown below:
[tex]V=\frac{n_{NaCl}}{M}=\frac{0.0045mol}{0.087mol/L}\\\\V=0.052L[/tex]
Or:
[tex]V=5.2 mL[/tex]
Best regards!
The volume of solution needed to react with 0.2631 g of NaCl is 0.052 L.
How we calculate the volume?Volume of the solution will be calculated by using the below formula:
M = n/V, where
M = concentration in terms of molarity
n = no. of moles
V = volume
Given chemical reaction is:
AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
First we calculate the moles of given reactants by using the formula:
n = W/M , where
W = given mass
M = molar mass
Moles of AgNO₃ = 14.77g / 169.87g/mole = 0.087 mole
Moles of NaCl = 0.2631g / 58.44g/mole = 0.0045 mole
Concentration of AgNO₃ = 0.087 mole / 1L = 0.087M
From the stoichiometry of the reaction it is clear that mole ration of AgNO₃ & NaCl is 1:1. So, we take the concentration of NaCl is equal to the concentration of AgNO₃ and calculate the volume by using the above formula as:
Volume of NaCl = 0.0045mole / 0.087M = 0.052 L
Hence, 0.052 L is the required volume of NaCl.
To know more about moles, visit the below link:
https://brainly.com/question/17199947
How many grams are in 2.49 x 10^24 atoms of Hg?
Answer:
[tex]m_{Hg}=829.4gHg[/tex]
Explanation:
Hello there!
In this case, considering the Avogadro's number, which helps us to realize that 1 mole of mercury atoms contains 6.022x10²³ atoms and at the same time 1 mole of mercury weights 200.59 g, we obtain:
[tex]m_{Hg}=2.49x10^{24}atoms*\frac{1mol}{6.022x10^{23}atoms} *\frac{200.59g}{1molHg}\\\\m_{Hg}=829.4gHg[/tex]
Best regards!
10-kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.
Answer:
Temperature = 0.605°C
Total enthalpy at 300kpa = 545.2 kJ
Total enthalpy at 600kpa = 846.45 kJ.
Explanation:
Checking the table for 134a pressure table. It is given that the specific volume of saturated liquid and the specific volume of the saturated vapor of 280kpa is 0.0007699 m^3/kg and 0.072352 m^3/kg respectively.
Also, the specific volume of saturated liquid and the specific volume of the saturated vapor of 320kpa is 0.0007772 m^3/kg and 0.063604 m^3/kg respectively.
The first thing to do is to determine the value for the specific volume of saturated liquid.
At 300 kpa, the specific volume of saturated liquid,n is given below as;
300 - 280/ 320 - 280 = (n - 0.0007699)/ 0.0007772 - 0.0007699.
Therefore, n = specific volume of saturated liquid = 0.0007735 m^3/kg.
300 - 280/ 320 - 280 = n - 0.072352/ (0.063604 - 0.072352).
n = 0.0679 m^3/kg.
The second thing to do is to determine the value of the specific volume.
Specific volume = 14 × 10^-3/ 10 = 0.0014 m^3/kg.
Determine the enthalpy of the mixture,b(I). This is given below as;
300 - 280/ 320 - 280 = b(I) - 199.54/ (196.7 - 199.54).
b(I) = 198.125 kJ/Kg.
Hence, b = [ 300 - 280/ 320 - 280 = j - 50.18 / 55.16 - 50.18] + [ ( 0.0014 - 0.00077735) / 0.067978 - 0.00077735] × 198.125.
b = 54.517 KJ/Kg.
Total enthalpy = 10 × 54.517 = 545.17 kJ.
Temperature can be Determine as below;
300 - 280/ 320 - 280 = T + 1.25 / 2.46 - 1.25.
Temperature = 0.605°C.
Hence, at 600kpa, the total enthalpy = [81.51 + ( 0.0014 - 0.0008199/ 0.034295 - 0.0008199) × 180.90] × 10
Total enthalpy at 600kpa = 846.45 kJ.
Convert the volume, nm^3, to liters (L) by using the box dimensions of 4nm x 8.75nm x 10nm. Use the conversion factor of 1 L = 1 dm^3. Do not convert directly from nm^3 to dm^3
Answer:
[tex]V=3.50x10^{-22}L[/tex]
Explanation:
Hello there!
In this case, given the dimensions of the box, we first compute the volume by multiplying each side:
[tex]V=4nm*8.75nm*10nm=350nm^3[/tex]
Next, we apply the following conversion factor in order to obtain the corresponding liters:
[tex]V=350nm^3*(\frac{1m}{10^9nm} )^3*\frac{1000L}{1m^3} \\\\V=350nm^3*\frac{1m^3}{10^{27}nm^3} *\frac{1000L}{1m^3}\\\\V=3.50x10^{-22}L[/tex]
Best regards!
Just like cans of soup, atoms of the same element often have different masses. These different varieties are called isotopes. In the Average Atomic Mass Gizmo, you will learn how to find the average mass of an element using an instrument called a mass s
Answer:
ions are deflected and the lighter the ions the more the deflection.
Placing magnetic field in the path of the ions cause them to move in a curved path.
Explanation:
This question is all about the way in which mass spectroscopy works. Mass spectroscopy Is one of the techniques in spectroscopy which is used in the identification of chemical compounds.
Mass spectroscopy works based on the principle of ionization. For a mass spectroscopy to start ionization must first occur that is to say this is the first step in the identification of compound in mass spectroscopy.
The following steps are involve in mass spectroscopy;
=> Ionization: the molecules of the sample are first ionized. The ions formed here are positive ions.
=> Acceleration: the ions in step one are accelerated.
=> Deflection: the smaller ions get deflected more than the bigger ions. The magnetic field is used in the deflection of this ions.
=> Detection: the ions are then detected.
Therefore, to answer the question, the ions are deflected and the lighter the ions the more the deflection.
Placing magnetic field in the path of the ions cause them to move in a curved path.
Gold's natural state has a definite shape and a definite volume. What is gold's natural state(s)?
Answer:
If your asking what golds natural state of matter is it's solid.
Explanation:
Answer:
the answer is soild
Explanation:
i did it on edge :)
In general chemicals enter Ecosystems through which two spears
Answer:
biosphere and lithosphere
Explanation:
The biosphere is described as the zone of life on Earth. It is a sum of all ecosystems. The biosphere is composed of living organisms and non-living factors.
The lithosphere is the outer part of the Earth such that this part is rocky. The lithosphere is made up of the brittle crust.
In general, chemicals enter Ecosystems through the biosphere and lithosphere.
After going through a guided tutorial by selecting Run Grams Demonstration, you can create your own experiment by clicking the Run Experiment button at the end or by clicking the Overview tab and returning to the Experiment tab to select Run Experiment. There are nine reactions you can explore on your own. Sulfur dioxide gas (SO2) and oxygen gas (O2) react to form the liquid product of sulfur trioxide (SO3). How much SO2 would you need to completely react with 6.00 g of O2 such that all reactants could be consumed
Answer: Thus 24.0 g of [tex]SO_2[/tex] would be needed.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} O_2=\frac{6.00g}{32g/mol}=0.1875moles[/tex]
[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(l)[/tex]
According to stoichiometry :
1 mole of [tex]O_2[/tex] require = 2 moles of [tex]SO_2[/tex]
Thus 0.1875 moles of [tex]O_2[/tex] will require=[tex]\frac{2}{1}\times 0.1875=0.375moles[/tex] of [tex]SO_2[/tex]
Mass of [tex]SO_2=moles\times {\text {Molar mass}}=0.375moles\times 64g/mol=24.0g[/tex]
Thus 24.0 g of [tex]SO_2[/tex] would be needed to completely react with 6.00 g of [tex]O_2[/tex] such that all reactants could be consumed.