Which is the right answer

Answer:

Electrons and protons are not positively charged

Explanation:

Neutrons are the only ones positively charged in the structure of an atom.... Also like charges repel which means a -ive and a - ive will repel when together

Answer:

A. 5.3 X 10^-2

Explanation:

I got 100 on PLATO

Answer:

2Cu2O + C --> 4Cu + CO2

Explanation

The Law of conservation of Mass states You can not destroy or create math in a chemical reaction, meaning you must have the same amount at the beginning and the end. This equation keeps the same amount of atoms on both sides.

Answer: Yes, it is a balanced equation.

Explanation:

https://chemequations.com/en/?s=Cu2O+%2B+C+%3D+Cu+%2B+CO2

This is where I got the answer so you know.  Hope this helps :)

Answer:

1

Explanation:

Answer:

water vapor (gas) is becoming liquid

Answer : A. 3

Explanation:

3Al(s) + 3O2(g) → 3Al2O3(s)

This is the right Answer :3

I hope you are having a great day :3

Answer:

D

Explanation:

Because it has equal number of elements on each side of the arrow

Solution :

[tex]$H_2 +I_2\rightleftharpoons 2HI$[/tex]

Initial concentration               Equilibrium concentration           [tex]$K_c=\frac{[HI]^2}{[H_2][I_2]}$[/tex]

  (mol/L)                                           (mol/L)

[tex]$[H_2]$[/tex]                 [tex]$[I_2]$[/tex]            [tex]$[HI]$[/tex]    [tex]$[H_2]$[/tex]                 [tex]$[I_2]$[/tex]            [tex]$[HI]$[/tex]

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.38 \times 10^{-2}$[/tex]  0     [tex]$1.14 \times10^{-2}$[/tex]    [tex]$0.12 \times 10^{-2}$[/tex]  [tex]$2.52 \times 10^{-2}$[/tex]        46.42

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.68 \times 10^{-2}$[/tex]  0     [tex]$0.92 \times10^{-2}$[/tex]    [tex]$0.20 \times 10^{-2}$[/tex]  [tex]$2.96 \times 10^{-2}$[/tex]        47.61

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.98 \times 10^{-2}$[/tex]  0     [tex]$0.77 \times10^{-2}$[/tex]    [tex]$0.31 \times 10^{-2}$[/tex]  [tex]$3.34 \times 10^{-2}$[/tex]        46.73

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.76 \times 10^{-2}$[/tex]  0     [tex]$0.92 \times10^{-2}$[/tex]    [tex]$0.22 \times 10^{-2}$[/tex]  [tex]$3.08 \times 10^{-2}$[/tex]        46.86

[tex]$0$[/tex]                  [tex]$0$[/tex]        [tex]$3.04 \times 10^{-2}$[/tex]     [tex]$0.345 \times10^{-2}$[/tex]    [tex]$0.345 \times 10^{-2}$[/tex]  [tex]$2.35 \times 10^{-2}$[/tex] 46.39

[tex]$0$[/tex]                  [tex]$0$[/tex]        [tex]$7.58 \times 10^{-2}$[/tex]     [tex]$0.86 \times10^{-2}$[/tex]    [tex]$0.86 \times 10^{-2}$[/tex]  [tex]$5.86 \times 10^{-2}$[/tex]     46.42

Average [tex]$K_c=46.738$[/tex]

Answer:

Hydrogen H₂ will be the limiting reagent.

The excess reactant that will be left after the reaction is 3.45 moles.

4.3 moles of water can be produced.

Explanation:

The balanced reation is:

2 H₂ + O₂ → 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

To determine the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry 1 mole of O₂ reacts with 2 moles of H₂, how much moles of H₂ will be needed if 5.6 moles of O₂ react?

[tex]moles of H_{2} =\frac{5.6 moles of O_{2} *2 mole of H_{2} }{1 mole of O_{2}}[/tex]

moles of H₂= 11.2 moles

But 11.2 moles of H₂ are not available, 4.3 moles are available. Since you have less moles than you need to react with 5.6 moles of O₂, hydrogen H₂ will be the limiting reagent and oxygen O₂ will be the excess reagent.

Then you can apply the following rules of three:

[tex]moles of O_{2} =\frac{1 mole of O_{2} *4.3 mole of H_{2} }{2 mole of O_{2}}[/tex]

moles of O₂= 2.15 moles

The excess reactant that will be left after the reaction can be calculated as:

5.6 moles - 2.15 moles= 3.45 moles

The excess reactant that will be left after the reaction is 3.45 moles.

[tex]moles of H_{2}O =\frac{2 moles of H_{2}O *4.3 mole of H_{2} }{2 mole of H_{2}}[/tex]

moles of H₂O= 4.3 moles

4.3 moles of water can be produced.

Answer:

0.702 /s

Explanation:

Rate constant at [tex][298 \mathrm{~K}, \mathrm{~K}_{1}=3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]

Rate constant at [tex]350 \mathrm{~K}, \mathrm{~K}_{2}=?[/tex]

[tex]T_{1}=298 \mathrm{~K}[/tex]

[tex]T_{2}=350 \mathrm{~K}[/tex]

Activation energy, [tex]\mathrm{Ea}=50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}[/tex]

Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]

Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]

[tex]\ln \frac{\mathrm{K}_{2}}{\mathrm{~K}_{1}}=\frac{\mathrm{Ea}}{\mathrm{R}}\left[\frac{1}{\mathrm{~T}_{1}}-\frac{1}{\mathrm{~T}_{2}}\right][/tex]

Therefore,

 [tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{1}{298 \mathrm{~K}}-\frac{1}{350 \mathrm{~K}}\right][/tex]

[tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{52 \mathrm{~K}}{298 \mathrm{~K} \times 350 \mathrm{~K}}\right][/tex]

[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=\mathrm{e}^{3.01}[/tex]

[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=20.3[/tex]

[tex]K_{2} &=20.3 \times 3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]

[tex]&=0.702 \mathrm{~s}^{-1}[/tex]

hence, the rate constant at [tex]350 \mathrm{~K} [/tex] is 0.702[tex]\mathrm{~s}^{-1}[/tex]

Explanation:

asexual reproduction involves 1 parent and produces offspring that are genetically identical to each other and parent.

Sexual reproduction involves 2 parents and produces offspring that are genetically unique.

Answer:

friction

Explanation:

conduction doesn't really need much to start it. it basically has that reaction from the start so it's not conduction. Since heat is produced by friction in this situation it causes static to happen. so i think its friction

It's ammonia (NH3).....

Answer:

A molecule with one lone pair and three bond pair

- Ammonia

Answer:

"0.24 J/g.k" is the appropriate solution.

Explanation:

Mass of substance,

m = 110.00 g

Heat,

q = 396 J

Change in temperature,

ΔT = 15.0°C  

Now,

The specific heat will be:

⇒  [tex]q=ms \Delta T[/tex]

On putting the given values, we get

⇒  [tex]396=110.00\times s\times 15.0[/tex]

⇒  [tex]396=s\times 1650[/tex]

⇒      [tex]s=\frac{396}{1650}[/tex]

⇒         [tex]=0.24 \ J/g.k[/tex]

Answer:

[tex]tiempo=0.72s[/tex]

Explanation:

¡Hola!

En este caso, como podemos observar, la relación entre la rapidez de reaction, las moles y el tiempo de reacción es:

[tex]rapidez=\frac{mol}{tiempo}[/tex]

De este modo, despejamos el tiempo en esta ecuación para obtener:

[tex]tiempo=\frac{mol}{rapidez}[/tex]

Así, reemplazamos la rapidez y moles dadas para obtener:

[tex]tiempo=\frac{0.323mol}{0.450mol/s}\\\\tiempo=0.72s[/tex]

¡Saludos!

Answer:

4.17M

Explanation:

m1v1/m2v2=n1/n2

What were Lamarck's ideas about evolution and Why were those ideas incorrect?

→ These and other examples show that Lamarck's theory does not explain how life formed and became the way it is. The other way that Lamarck's theory has been proven wrong is the study of genetics. Darwin knew that traits are passed on, but he never understood how they are passed on.

Answer:

The arrangement of electrons within an atom is called electron configuration

If I help you, will you help other people?

Actually "this is the worst question i've ever seen use the internet bud" why don't you do that.

Answer:

A. 2AgI + Na2S → Ag2S + 2NaI

B. Na3PO4 + 3HCl → 3NaCl + H3PO4

C. Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3

D. TiCl4 + 2H2O → TiO2 + 4HCl

E. 3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl

Explanation:

Answer:

To find the relative formula mass (M r) of a compound, you add together the relative atomic mass values (A r values) for all the atoms in its formula.

Explanation: Find the M r of carbon monoxide, CO. Find the M r of sodium oxide, Na 2O. The relative formula mass of a substance, shown in grams, is called one mole of that substance.

Answer:

"When two or more elements combine to form more than one compound, the mass of one of them, which joins the fixed mass of the other, is in relation to whole numbers and simple" Example: The carbo

Answer:

D . It describes a compound being broken down into the elements from which it was formed.

Explanation:

A compound consists of two or more elements chemically combined together in a chemical reaction. The compound carbon monoxide is represented by the chemical symbol, CO. This means that it contains 1 atom of the carbon element and 1 atom of the Oxygen element.

This compound is formed when carbon is directly oxidized in a limited supply of oxygen. In the above reaction, this compound is disintegrated into its individual components, namely, carbon and oxygen.

Answer:

Option C (1.2 L) is the correct option.

Explanation:

The given values are:

Pressure,

[tex]P_1=1.9 \ atm[/tex]

[tex]P_2=3.8 \ atm[/tex]

Volume,

[tex]V_1=2.3 \ L[/tex]

[tex]V_2=?[/tex]

As we know,

The gas equation is:

⇒  [tex]PV=nRT[/tex]

At constant temperature,

⇒  [tex]P_1 V_1=P_2 V_2[/tex]

or,

⇒      [tex]V_2=\frac{P_1 V_1}{P_2}[/tex]

By substituting the values, we get

⇒           [tex]=\frac{1.9\times 2.3}{3.8}[/tex]

⇒           [tex]=\frac{4.37}{3.8}[/tex]

⇒           [tex]=1.15 \ L[/tex]

or,

⇒           [tex]=1.2 \ L[/tex]

Answer:

D ) Chemical Change

Explanation:

Equation balance:

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

2Al(OH)3+3H2SO4

H=12

SO4=3

O=6

Al=2

Al2(SO4)3+6H2O

H=12

SO4=3

O=6

Al=2

Answer:

a) pentane

b) 1,3-dimethyl butane

c) 3,4-diethyl-5-methlyl heptane

d) 1,3,5-triethyl-2,4,6-trimethyl  cyclohexane

Explanation:

The essence of IUPAC nomenclature is to provide a generally accepted nomenclature for chemical compounds which enables the structure of a compound to be drawn from its name without ambiguity.

In order to name straight chain organic compounds, we have to identify the parent chain and then give numbers to the substituents or locants such that they have the lowest possible numbers in alphabetical order.

The correct names of the organic compounds in the question are;

a) pentane

b) 1,3-dimethyl butane

c) 3,4-diethyl-5-methlyl heptane

d) 1,3,5-triethyl-2,4,6-trimethyl cyclohexane

Answer:

250cm³ de disolución se deben preparar

Explanation:

El porcentaje volumen volumen (%v/v) se define como el volumen de soluto -En este caso, H2O2- en 100cm³ de disolución.

Se desea preparar una solución que contenga 20cm³ de H2O2 por cada 100cm³

Como solamente se cuenta con 50cm³ de H2O2, el volumen que se debe preparar es:

50cm³ H2O2 * (100cm³ Disolución / 20cm³ H2O2) =