Which is NOT a form of erosion?


a

Rivers moving dirt


b

Water running downhill, carving out the land and pushing dirt to the side

c

Water evaporating and condensing

d

Heavy winds blowing soil to other locations

HELP ASAP

Answer:

1 rev = 2(pi) rad  pi(rad) = 180 degrees

so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees

Explanation:

63.36 estimated to 63 so 63

The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.

1 rev = 2(pi) rad

So here  pi(rad) = 180 degrees

Now for 33 rpm it should be like

=  33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s

= 63.36 degrees

= 63 degrees

hence, The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.

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Answer:

all are true so d is right

Explanation:

Electromagnets use electrlcity and magnets is true.

Magnetic fields are strongest around the poles of a magnet is true.

The south pole of a magnet will repel the south pole of another magnet is true

and since all of them is true the answer is d all of the above

Answer:

816

Explanation:

We must remember that torque is defined as the product of a force by a distance.

This distance is measured from the pivot point of the Bolt to the point where the force is applied. in this way, we have the following equation to be able to determine the torque.

[tex]T=F*d[/tex]

Now if we double the turning distance we have the torque should also be double.

[tex]T =F*2*d[/tex]

Answer:

A & D your welcome

Propanol surface is more flattered and has less boiling point than that of water.

To determine the correct statements among all the statements, we need to know about the surface tension.

Since, propanol has less surface tension than that of water, so its surface is more flattered and has less boiling point than that of water.

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#SPJ2

Answer:

C) 0.00026 Hz

Explanation:

       [tex]v = \lambda * f (1)[/tex]

       [tex]f = \frac{v}{\lambda} = \frac{700km/hr}{750 km} = 0.93 1/hr (2)[/tex]

       [tex]f = 0.93 \frac{1}{hr} *\frac{1 hr}{3600sec} = 2.6e-4 = 0.00026 Hz (2)[/tex]

p = 36 kgm/s

v = 4m/s

we know that,

p = mv

so,

[tex]m = \frac{p}{v} [/tex]

[tex]m = \frac{36}{4} [/tex]

[tex]m = 9kg[/tex]

Answer:

None of the mass or the radius of the sphere

Explanation:

When a uniform solid sphere of any given mass, say M and any given radius, say R, rolls without slipping downwards an inclined plane that starts from rest. The linear velocity of the sphere at about the bottom of the inclined happens not to depend on either of its mass or that of the radius of its sphere.

Option B

Explanation:

no distance was given only the acceleration due to the fact that it went up (10m/s/s)

s0 it is

0 m/s and 10m/s/s (option B)

Answer:

2.1 m/s

Explanation:

According to law of conservation of momentum;

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the common velocity

Given

m1 = 2150kg

m2 = 3250kg

u1 = 10.0m/s

u2 = ?

v = 5.22m/s

Substitute and get u2

2150(10) + 3250u2 = (2150+3250)5.22

21,500 + 3250u2 = 5400(5.22)

3250u2 = 28,188 - 21500

3250u2 = 6688

u2 = 6688/3250

u2 = 2.1 m/s

Hence the 3250 kg car’s initial velocity has an initial velocity of  2.1 m/s

[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

[tex] \underline{\green{\large \sf For\: example :}} [/tex]

[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]

In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.

Answer:

sounds like a you problem

Explanation:

yeah

Asteroids are known through the help of artificial gravity, to have small gravity. The forces that cannot be neglected when analyzing the motion of the astronaut is that the gravitational force between the astronaut and the asteroid.

Unbalanced forces are simply known to be brought about due to a change in motion, speed, and/or direction. If two forces act in the same direction on an object, the net force is said to be equal to the sum of the two forces.

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Answer:

Those substances which can conduct electricity are called conductors, while those substances which don't conduct electricity are called insulators.

Resistance is the obstruction provided by the material through which the current passes,so since conductors conduct electricity and insulators don't,so the obstruction i.e resistance provided by the conductor must be less,while insulators being unable to conduct electricity,has very high resistance.

Example of conductor is copper

Example of insulator is plastic

Answer a

Explanation: a

Answer:

A) Z-1

Explanation:

when a radioactive element of atomic number Z emits an alpha particle, the mass of the new nucleus decreases by 2, i.e the new atomic number of the element = ( Z- 2).

Also, when the daughter nucleus emits a beta particle, the new nucleus increases by 1,  that is the new atomic number of the element = (Z + 1).

Thus, the atomic number of resulting nuclide = Z ( - 2) + ( + 1).

                                                                           = Z - 2 + 1

                                                                           = Z - 1

Therefore, the atomic number of resulting nuclide is Z - 1

Answer:

V2 = 1.899*10^-3 m^3

T2 = 347.125 K

Explanation:

Using gas law, we know that

PV = nRT,

Where

V1 = 0.00115743 m^3.

gamma = 1.4

Now, when we solve for final volume, V2 we get

V2 = V1/((P2/P1)^(1/gamma))

V2 = 1.899*10^-3 m^3

Using the same law and method, when we try to solve for the temperature, we find that the final temperature, T2 is

T2 = T1*((V1/V2)^(gamma-1))

T2 = 347.125 K

The final volume is 1.899*10^-3 m^3

And, the final temperature is 347.125 K

here we used gas law,

we know that

PV = nRT,

Here

V1 = 0.00115743 m^3.

gamma = 1.4

Now final volume is

V2 = V1/((P2/P1)^(1/gamma))

V2 = 1.899*10^-3 m^3

Now the final temperature is

T2 = T1*((V1/V2)^(gamma-1))

T2 = 347.125 K

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Answer:

A

Explanation:

Option B) 10m/s² is the correct answer.

Hence, the acceleration of the new sports car in the given period of time is 10m/s².

Motion is simply the change in position of an object over time.

From the First Equation of Motion;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given the data in the question;

To determine the acceleration of the new sports car, we substitute our given values into the expression above.

v = u + at

120m/s = 0m/s + (a × 12s)

a × 12s = 120m/s - 0m/s

a × 12s = 120m/s

a = 120m/s ÷ 12s

a = 10m/s²

Option B) 10m/s² is the correct answer.

Hence, the acceleration of the new sports car in the given period of time is 10m/s².

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Answer:

The correct answer is  C

Explanation:

  From the question we are told that  

       The frequency of the radar is [tex]f = 24.15 \ GHz = 24.15 *10^{9} \ Hz[/tex]

         The speed of the car is [tex]v = 50 mph = \frac{50}{2.237} = 22.35 \ m/s[/tex]

Generally the difference frequency reflected by the car and the frequency which the radar receives back is mathematically represented as

        [tex]\Delta f = \frac{f * 2 * v }{ c }[/tex]

Here  c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

=>    [tex]\Delta f= \frac{2 * 24.15 *10^{9} * 22.35}{ 3.0*10^{8}}[/tex]      

=>    [tex]\Delta f = 4000 \ Hz[/tex]

=>     [tex]\Delta f = 4.0 \ kHz[/tex]  

Given that the value is positive then it a higher frequency

Given that,

Mass of the object, m = 1.2 kg

Initial speed of the object, u = 8 m/s

Final speed of the object, v = -6 m/s (in opposite direction)

Time, t = 2 ms

To find,

The average force on the object by the wall.

Solution,

Let F be the force. Using Newton's second law of motion,

F = ma, a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{1.2\times ((-6)-8)}{2\times 10^{-3}}\\\\=8400\ N[/tex]

or

F = 8.4 N

So, the magnitude of average force in the object by the wall is 8.4 N.

Answer:

F = 6[N].

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

[tex]P=m*v\\or\\P=F*t[/tex]

where:

P = impulse or lineal momentum [kg*m/s]

m = mass = 10 [kg]

v = velocity [m/s]

F = force [N]

t = time = 5 [s]

Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]

where:

m₁ = mass of the object = 10 [kg]

v₁ = velocity of the object before the impulse = 1 [m/s]

v₂ = velocity of the object after the impulse = 4 [m/s]

[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]

A would land before since its heavier

Unclear/incomplete question. However, I inferred you need an explanation of the phenomenon of rainfall​.

Explanation:

Basically, the phenomenon of rainfall​ follows a natural cycle called the water cycle. What we call 'rainfall' occurs when water condensed (in liquid form) in the atmosphere is made to fall down on the ground as tiny droplets as a result of the forces of gravity.

The water cycle makes rainfall possible:

Answer:

B. Mass would be the same but its weight would be less on the Moon.

Explanation:

The mass of a body can be expressed as the quantity of matter it contains. While the weight of a body is the extent of the gravitational force impressed on the body by a massive body.

Thus, the mass of a body is constant either on the Earth or on the Moon. But the weight would be less on the Moon because the gravitational force on the Moon is far less than that on the Earth. Therefore the weight would be less on the Moon.

The appropriate option is B.

The mass will remain same on both moon and Earth, but weight will be lesser on Moon than Earth. Hence, option (B) is correct.

The prime focus to solve this problem is the mass and weight of an object. The mass of a body can be expressed as the quantity of matter it contains. While the weight of a body is the extent of the gravitational force impressed on the body by a massive body.

So, the mass of a body is constant either on the Earth or on the Moon. But the weight of an object will depend on the mass and the gravitational acceleration.

W = mg

Here, W is weight, m is mass and g is gravitational acceleration.

Weight would be less on the Moon because the gravitational force on the Moon is far less (due to lower value of g) than that on the Earth. Therefore the weight would be less on the Moon.

Thus, we can conclude that the mass will remain same on both moon and Earth, but weight will be lesser on Moon than Earth. Hence, option (B) is correct.

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Answer:

We know that the carousel does a complete rotation in 45 seconds.

Then the frequency of this carousel will be f =  1/45 seconds.

And the angular frequency will be 2*pi times the frequency, then we have:

angular frequency = w = 2*3.14*(1/45s) = 0.1396 s^-1

Now, the linear speed of an object that rotates with a radius R, and an angular frequency W is:

S = R*W

then:

a) in this case the radius is 2.75m, then the linear speed is:

S = 2.75m*0.1396 s^-1 = 0.3839 m/s

b) in this case the radius is 1.75m, then the linear speed here is:

S = 1.75m*0.1396 s^-1 = 0.2443 m/s

(a) The linear speed of an outer horse on the carousel is 0.384 m/s.

(b) The linear speed of an inner horse on the carousel is 0.244 m/s.

Given data:

The time interval for the rotation of carousel is, t = 45 s.

The distance of the outer horse from the axis of rotation is, r = 2.75 m.

The distance of an inner horse from the axis of rotation is, r' = 1.75 m.

(a)

The linear speed in this problem can be obtained from the concept of rotational mechanic, in which the ratio of the circumference and the time gives required linear speed. So,

v = 2 π r/t

Solving as,

v = 2 π (2.75) / 45

v = 0.384 m/s

Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.384 m/s.

(b)

Now similarly the linear speed of an inner horse is calculated as,

v' = 2 π r' / t

Solving as,

v' = 2 π (1.75) / 45

v' = 0.244 m/s

Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.244 m/s.

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Answer:

52.095 m/s

Motorcycle a was moving faster

Explanation:

We start by using one of the equations of motion

V = u + at

If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as

V(a) = u(a) + a(a).t

If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as

V(b) = u(b) + a(b).t

Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have

0 = u(a) - u(b) + a(a).t - a(b).t

-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have

u(b) - u(a) = [a(a) - a(b)]t

Since we have the values for acceleration and the time, we substitute so that

u(b) - u(a) = (4.55 - 18.9)3.63

u(b) - u(a) = -14.35 * 3.63

u(b) - u(a) = -52.095, or we rearrange to get

u(a) - u(b) = 52.095 m/s

(a) When the kinetic energy of an electron is transformed into potential energy is when it interacts with other electrons, decreasing its speed.

(b)  The region of atoms that interact in bonds is electric fields of particles with negative charge.

(c) Initial repulsion is low and increases as they approach.

(d) The force between the charges is 562.5 N.

This theory states that, the collision of particles (electrons) of matter is perfectly elastic. This implies that as the particles (electrons) collides with one another, kinetic energy is transferred from one electron to another.

ΔK.E = ΔP.E

Change in kinetic energy is equal to change in potential energy of the electrons.

Thus, when the kinetic energy of an electron is transformed into potential energy is when it interacts with other electrons, decreasing its speed. Decrease in speed implies decrease in kinetic energy and increase in potential energy.

Chemical bond is formed from the transfer or sharing of electrons between atoms. (electrons between atoms implies negative charge to negative charge)

Thus, the region of atoms that interact in bonds is electric fields of particles with negative charge.

This law states that the force of attraction or repulsion between two charges is directly proportional to the product of the charges and inversely proportional to the distance between the charges.

[tex]F = \frac{kq_1q_2}{r^2}[/tex]

When the distance between the electrons are large, the repulsive force is low and the distance is small, the repulsive force is high.

The force between the charges is determined by applying Coulomb's law,

[tex]F = \frac{kq_1q_2}{r^2} \\\\F = \frac{9\times 10^9\times (5 \times 10^{-5}) \times (2\times 10^{-6})}{0.04^2} \\\\F = 562.5 \ N[/tex]

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Answer:

[tex]31.32\ m/s[/tex]

Explanation:

[tex]We\ are\ given\ that:\\Height\ to\ which\ there're\ lifted=50m\\Displacement\ during\ the\ descent=50m\\Now,\\In\ order\ to\ find\ the\ velocity\ of\ the\ customers\ at\ 50\ m,\\We\ can\ use\ the\ Third\ Equation\ Of\ Motion,\ which is:\\2as=v^2-u^2\\As\ we\ know\ that,\\Acceleration\ due\ to\ gravity=9.81\ m/s^2\ or\ roughly\ 10\ m/s^2\\Displacement=50\ m\\Initial\ velocity=0\ m/s^2\\ [As\ they\ stop\ when\ they\ reach\ the\ maximum\ height\ of\ 50\ m\\ and\ begin\ their\ descent][/tex]

[tex]By\ reconstructing\ the\ Third\ Equation\ Of\ Motion,\ we\ have:\\2gs=v^2\\Hence,\\v^2=2*9.81*50 \\v^2=981\ m^2/s^2 \\v=\sqrt{981\ m^2/s^2} \\v=31.32\ m/s[/tex]

Answer:

97.3 MJ

Explanation:

The formula for the coefficient of Perfomance is given as

COE = Q/W, where

COE is the coefficient of Perfomance

Q is the heat provided

W serves as the work input.

Dividing both sides of the equation by a factor of time t, we get the coefficient of Perfomance in terms of heating power and input power, so we say

COE = P / P(i),

making heating power, P the subject of formula, we have

P = COE * P(i)

P = 3.85 * 7020 * 1 * 3600

P = 97297200 J

P = 97.3 MJ

Answer:

c.

Explanation: