Which filter allows you to impart a stamping or raising effect in an image?

Answer:

In computer programming, a return statement causes execution to leave the current subroutine and resume at the point in the code immediately after the instruction which called the subroutine, known as its return address. The return address is saved by the calling routine, today usually on the process's call stack or in a register. Return statements in many languages allow a function to specify a return value to be passed back to the code that called the function.

An expression that returns a value is known as a​ function. Check more about function  below.

A function is often seen as a kind of expression or rule, or law that often tells more about a relationship.

Conclusively, a function is known to often returns a value back to the instruction that is known also to be the function. This is regarded as the differences that exist between a method and a function.

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Answer:

Throughout the clarification below, the description of the query is mentioned.

Explanation:

Answer:

Increased.

Explanation:

An information system interacts with its environment by receiving data in its raw forms and information in a usable format.

Information system can be defined as a set of components or computer systems, which is used to collect, store, and process data, as well as dissemination of information, knowledge, and distribution of digital products.

Generally, it is an integral part of human life because individuals, organizations, and institutions rely on information systems in order to perform their duties, functions or tasks and to manage their operations effectively. For example, all organizations make use of information systems for supply chain management, process financial accounts, manage their workforce, and as a marketing channels to reach their customers or potential customers.

Additionally, an information system comprises of five (5) main components;

1. Hardware.

2. Software.

3. Database.

4. Human resources.

5. Telecommunications.

Reliance on information and communications technologies have increased potential vulnerabilities to physical and cyber threats and potential consequences resulting from the compromise of underlying systems or networks.

In order to mitigate this physical and cyber threats, information systems usually have an encryption, authentication and authorization system integrated into them.

Answer:

yes and

Explanation:

why do you need to know about a buildings security are you going to rob it ???

Answer:

The reason that a satellite must have a distinct uplink and downlink set of frequencies is because they help avoid any type of interference that may occur. The uplink receives the signal and amplifies it so that it can be transmitted to another frequency (downlink).

Answer:

B

Explanation:

Hope this helps! :)

The digital learning can help students who enjoy classrooms and support. The correct option is 4.

Digital learning can be defined as a type of education in which the internet, a computer, or a network of computers, and softwares are used to connect students and teachers in order to provide educational services.

Digital learning brings together facilities such as classrooms and support in an effort to help and provide the necessary assistance to students who have chosen the digital medium but still enjoy the comfort of structure and face-to-face interaction.

Regardless of their learning style or preference, digital learning can benefit a variety of students.

It offers a variety of tools and resources to improve the learning experience while also accommodating various schedules and needs.

Thus, the correct option is 4.

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#SPJ7

Answer: drafting

Explanation:

Answer:

What Language? Once you respond with a comment, I will be happy to write the code for you. I write code 24/7 (Because I have nothing better to do), so I will wait for you to comment. Also is there any pre-existing code?

Explanation:

Answer:

I think the answer would be A.

Explanation:

If I'm wrong plz let me know (I think I may be wrong)

Answer:

In absolute cell reference, the reference of a cell does not change. 

Answer:

Explanation:

When your elecronic devices screen is positioned upright or the way a photo is taken

If you want an example look up portrait mode on go0gle or safar1

Answer:

5/ 18

Explanation:

Given :

List A: [20,10,20]

List B: [40,10,30,20,40,30]

Chance that number drawn from list A is larger than or equal to that drawn dlfrom list B.

If:

A = 20

B ≤ 20 : [10,20] = 2

A = 10

B ≤ 10 : [10] = 1

A = 20

B ≤ 20 : [10,20] = 2

Probability = Required outcome / Total possible outcomes

Hence,

required outcome = (2 + 2 +1) = 5

Total possible outcomes = 3C1 * 6C1 = (3 * 6) = 18

Hence,

chance that the number we drew from list A is larger than or equal to the number we drew from list B

= 5 / 18

In this exercise we have to use the knowledge in computational language in python to describe a code that best suits, so we have:

The code can be found in the attached image.

To make it simpler we can write this code as:

import random

A=[20,10,20]

B=[40,10,30,20,40,30]

print(random.choice(A))

print(random.choice(B))

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Answer:

In Python:

import os.path

from os import path

fname = input("Filename: ")

if path.exists(fname):

with open(fname) as file_in:

 lines = []

 for line in file_in:

  lines.append(line.rstrip('\n'))

f = open("stat.txt","r+")

f.truncate(0)

f = open("stat.txt", "a")

f.write("Names\tTotal\tSubjects\tAverage\n")

for i in range(len(lines)):

 rowsum = 0; count = 0

 nm = lines[i].split()

 for j in nm:

  if (j.isdecimal()):

   count+=1

   rowsum+=int(j)

 average = rowsum/count

 f.write(nm[0]+"\t %3d\t %2d\t\t %.2f\n" % (rowsum, count, average))

f.close()

else:

print("File does not exist")

Explanation:

See attachment for explanation where comments were used to explain each line

For each student, the sum of the marks, total tests were taken and the average of marks is calculated and is stored in an output file, for example, stats.txt.

The code in Python asks the user for an input file name. If the input file is not found an error is printed else the data in the file is processed further.

Try:

  # take input file name

  file = input('Enter name of the data file: ')

# open the input file

  ip = open(file, 'r')

# store the lines from input file in a list

  lines = ip.readlines()

  # close the file

  ip.close()

# open the output file

  op = open('stats.txt', 'w')

# iterate over each line

  for line in lines:

 # split data using space as delimiter

      data = line.split()

 # get name

   name = data[0]

 # get marks and convert them to integer

      marks = list(map(int, data[1:]))

# get sum of marks

      total = sum(marks)

# get number of tests

      length = len(marks)

# calculate average of marks

      avg = total/length

# add the data to output file

      op.write('{} {} {} {:.2f}\n'.format(name, total, length, avg))

# close the output file

  op.close()

print('Stats have been save in the output file')

# catch FileNotFoundError

except FileNotFoundError:

# print error

  print('Error: that file does not exist. Try again.')

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Answer:

Its b) Ctrl+Q. Hope it helps.

Explanation:

Answer:

ctrl r

Explanation:

ctrl r is redo

Answer:

In Python:

import random

p1name = input("Player 1: "); p2name = input("Player 2: ")

p1score = 0; p2score = 0

playerTurn = 1

print(p1name+" starts the game")

roll = True

while(roll):

   if playerTurn == 1:

       p1 = random.randint(1,6)

       print(p1name+"'s roll: "+str(p1))

       if p1 == 1:

           playerTurn = 2

           roll = True

       else:

           p1score+=p1

           another = input("Another Roll (y/n): ")

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 2

               roll = True

   else:

       p2 = random.randint(1,6)

       print(p2name+"'s roll: "+str(p2))

       if p2 == 1:

           playerTurn = 1

           roll = True

       else:

           p2score+=p2

           another = input("Another Roll (y/n): ")

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 1

               roll = True

   if p1score >= 50 or p2score >= 50:

       roll = False

print(p1name+":\t"+str(p1score)+"\t"+p2name+":\t"+str(p2score))

Explanation:

Note that the dice rolling is simulated using random number whose interval is between 1 and 6

This imports the random module

import random

This line gets the name of both players

p1name = input("Player 1: "); p2name = input("Player 2: ")

This line initializes the scores of both players to 0

p1score = 0; p2score = 0

This sets the first play to player 1

playerTurn = 1

This prints the name of player 1 to begin the game

print(p1name+" starts the game")

This boolean variable roll is set to True.

roll = True

Until roll is updated to False, the following while loop will be repeated

while(roll):

If player turn is 1

   if playerTurn == 1:

This rolls the dice

       p1 = random.randint(1,6)

This prints the outcome of the roll

       print(p1name+"'s roll: "+str(p1))

If the outcome is 1, the turn is passed to player 2

       if p1 == 1:

           playerTurn = 2

           roll = True

If otherwise

       else:

Player 1 score is updated

           p1score+=p1

This asks if player 1 will take another turn

           another = input("Another Roll (y/n): ")

If yes, the player takes a turn. The turn is passed to player 2, if otherwise

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 2

               roll = True

If player turn is 2

   else:

This rolls the dice

       p2 = random.randint(1,6)

This prints the outcome of the roll

       print(p2name+"'s roll: "+str(p2))

If the outcome is 1, the turn is passed to player 1

       if p2 == 1:

           playerTurn = 1

           roll = True

If otherwise

       else:

Player 2 score is updated

           p2score+=p2

This asks if player 2 will take another turn

           another = input("Another Roll (y/n): ")

If yes, the player takes a turn. The turn is passed to player 1, if otherwise

           if another == "y" or another == "Y":

               roll = True

           else:

               playerTurn = 1

               roll = True

If either of both players has scored 50 or above

   if p1score >= 50 or p2score >= 50:

roll is updated to False i.e. the loop ends

       roll = False

This prints the name and scores of each player

print(p1name+":\t"+str(p1score)+"\t"+p2name+":\t"+str(p2score))

Answer:

Explanation:

[tex]\text{This is a math function that is integrated using a trapezoidal rule } \\ \\[/tex]

[tex]\text{import math}[/tex]

def [tex]\text{trapezint2(f,a,b):}[/tex]

      [tex]\text{midPoint=(a+b)/2}[/tex]

       [tex]\text{return .5*((midPoint-a)*(f(a)+f(midPoint))+(b-midPoint)*(f(b)+f(midPoint)))}[/tex]

[tex]\text{trapezint2(math.sin,0,.5*math.pi)}[/tex]

[tex]0.9480594489685199[/tex]

[tex]trapezint2(abs,-1,1)[/tex]

[tex]1.0[/tex]

In this exercise we have to use the knowledge of computational language in python to write the code.

the code can be found in the attachment.

In this way we have that the code in python can be written as:

   h = (b-a)/float(n)

   s = 0.5*(f(a) + f(b))

   for i in range(1,n,1):

       s = s + f(a + i*h)

   return h*s

from math import exp  # or from math import *

def g(t):

   return exp(-t**4)

a = -2;  b = 2

n = 1000

result = Trapezoidal(g, a, b, n)

print result

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Answer:

The pseudocode is as follows:

open_server()

connections = N

while (connections>0 and connections <=N):

   if(new_client == connected):

       connections = connections - 1

   for i in 1 to N - connections

   if (client_i == done()):

         releast_client(client_i)

         connections = connections + 1

Explanation:

One of the functions of a semaphore is that, it is a positive variable whose value will never fall below 1. It is often shared among threads in order to keep a process running.

Having said that, what the above pseudocode does is that:

Once the server is opened, it initializes the number of connections to N.

When a new client, the semaphore decreases the number of connections is reduced by 1.

Similarly, when an already connected client is done, the client is released and the number of connections is increased by 1.

This operation is embedded in a while loop so that it can be repeatedly carried out.

Answer: Resolution or DPI, deliverables, and file types are important technical and visual demands to consider when planning a project.

Explanation: Keep in mind whether or not the project will be published in print or on the Web.

Answer:

Explanation:

The following code is written in Java. Both functions traverse the linkedlist, until it reaches the desired index and either returns that value or deletes it. If no value is found the function terminates.

public int GetNth(int index)

       {

       Node current = head;

       int count = 0;

       while (current != null)

       {

       if (count == index)

       return current.data;

       count++;

       current = current.next;

       }

       assert (false);

       return 0;

       }

public int removeNth(int index)

       {

       Node current = head;

       int count = 0;

       while (current != null)

       {

       if (count == index)

       return current.remove;

       count++;

       current = current.next;

       }

       assert (false);

       return 0;

       }

Answer:

Replace /* Your solution goes here */

with: userAge<18

Explanation:

Required

Complete the code

To complete the code, we simply write an expression that compares userAge and 18

From the question, we are to test if userAge is less than 18.

In C++, less than is written as: <

So, the expression that completes the code is: userAge<18

Answer:

Hopes this helps if not comment and I'll change it

Explanation:

import simplegui

import random

def draw_handler(canvas):

for i in range (0, 1000):

x = random.randint(1, 600)

y = random.randint(1, 600)

r = random.randint(0, 255)

g = random.randint(0, 255)

b = random.randint(0, 255)

color = "RGB( " + str(r) + "," + str(g) + "," + str(b) + ")"

canvas.draw_point((x, y), color)

frame = simplegui.create_frame('Points', 600, 600)

frame.set_canvas_background("Black")

frame.set_draw_handler(draw_handler)

frame.start()

Answer:

Computer science is the study of computers and computing as well as their theoretical and practical applications. Computer science applies the principles of mathematics, engineering, and logic to a plethora of functions, including algorithm formulation, software and hardware development, and artificial intelligence.

Answer: number 2 is the correct way to do it

Explanation:

Answer:

2 newWord = word1 + word2

Explanation:

Answer:

i need more

Explanation:

i need more

Answer:

Explanation:

The following code was written in Python and creates a function called add_elements . Whenever it finds the value within the lst that has the same entry it inserts the elem variable right infront of the entry within the list and breaks out of the loop. Finally, the function returns the newly modified list back to the user.

def add_element(lst, entry, elem):

   for value in lst:

       if value == entry:

           lst.insert(lst.index(value) + 1, elem)

           break

   return lst

In this exercise we have to use the knowledge of computational language in python to write the code.

the code can be found in the attachment.

In this way we have that the code in python can be written as:

def add_element(lst, entry, elem):

  for value in lst:

      if value == entry:

          lst.insert(lst.index(value) + 1, elem)

          break

  return lst

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Answer:

Explanation:

The following code was written in Java and follows all of the instructions provided. Some instructions were most likely written incorrectly as following them made no sense and would not allow the program to run. Such as placing the main method code into the encryptString method. Since the code inside the main method needed to stay inside the main method for the program to function accordingly. The code that most likely needed to be moved was the EncryptText code to the encryptString method.

package sample;

import java.util.Scanner;

class EncryptTextMethods {

   private static String encryptMessage(String message) {

       //convert string to character array

       char stringChars[] = message.toCharArray();

       //for each character

       for(int i=0; i< stringChars.length; i++) {

           char ch = stringChars[i];

           //if character within range of alphabet

           if(ch <= 'z' && ch >= 'a') {

           //obtain the character value

           //add 1 to the integer value

           //enter modulus by 26 since z will become a

           //once again add the remainder to 'a'

               stringChars[i] = (char)('a' + ((int)(ch - 'a') + 1) % 26 );

           }

       }

       //construct the string message

       return String.valueOf(stringChars);

   }

   public static String decryptString(String message) {

       char stringChars[] = message.toCharArray();

       String decrypted = "";

       for (int x = 0; x < stringChars.length; x++) {

           int charValue = stringChars[x];

           decrypted += String.valueOf( (char) (charValue - 1));

       }

       return decrypted;

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       System.out.println("Please enter text to encode: ");

       String message = keyboard.nextLine();

       message = message.toLowerCase();

       String encrypted = encryptMessage(message);

       String decrypted = decryptString(encrypted);

       System.out.println("Original Message: " + message);

       System.out.println("Encrypted: " + encrypted);

       System.out.println("Decrypted: " + decrypted);

       keyboard.close();

   }

}

Answer:

In Python:

pennies= int(input("Pennies: "))

while pennies<0:

   pennies= int(input("Pennies: "))

nickels = int(input("Nickels: "))

while nickels < 0:

   nickels = int(input("Nickels: "))

dimes = int(input("Dimes: "))

while dimes < 0:

   dimes = int(input("Dimes: "))

quarters = int(input("Quarters: "))

while quarters < 0:

   quarters = int(input("Quarters: "))

dollars = pennies * 0.01 + nickels * 0.05 + dimes * 0.1 + quarters * 0.25

if dollars == 1:

   print("Congratulations")

else:

   if dollars > 1:

       print("More than $1")

   else:

       print("Less than $1")

Explanation:

Prompts the user for pennies and also validates for positive values

pennies= int(input("Pennies: "))

while pennies<0:

   pennies= int(input("Pennies: "))

Prompts the user for nickels and also validates for positive values

nickels = int(input("Nickels: "))

while nickels < 0:

   nickels = int(input("Nickels: "))

Prompts the user for dimes and also validates for positive values

dimes = int(input("Dimes: "))

while dimes < 0:

   dimes = int(input("Dimes: "))

Prompts the user for quarters and also validates for positive values

quarters = int(input("Quarters: "))

while quarters < 0:

   quarters = int(input("Quarters: "))

Calculate the amount in dollars

dollars = pennies * 0.01 + nickels * 0.05 + dimes * 0.1 + quarters * 0.25

Check if amount is $1

if dollars == 1:

If yes, prints congratulations

   print("Congratulations")

If otherwise, print greater of less than $1

else:

   if dollars > 1:

       print("More than $1")

   else:

       print("Less than $1")

Answer:

This address is by default a class c network

Explanation:

This IP address in this question is a class c network because it has 196 as its first octet. A class c network is one which has its first octet to be between 192 and 223. the class c network begins with a 110 binary.  If ip is between 192 to 223 it belongs to this class. These first 3 octets are the representation of the network number in the address. Class c's were made to support small networks initially.

Answer:

of a bad product

Explanation:

Answer:

e. All of the above.

Explanation:

An instruction set architecture (ISA) can be defined as series of native memory architecture, instructions, addressing modes, external input and output devices, virtual memory, and interrupts that are meant to be executed by the directly.

Basically, this set of native data type specifies a well-defined interface for the development of the hardware and the software platform to run it.

The two (2) main types of architectural design for the central processing unit (CPU) are;

I. Complex instruction set computing (CISC): it allows multi-step operation or addressing modes to be executed within an instruction set. Thus, many low-level operations are being performed by an instruction.

II. Reduced instruction set computing (RISC): it allows fixed length instructions and simple addressing modes that can be executed within a clock cycle.

All of the following statements are true about RISC (Reduced instruction set computing) because they are its advantages over complex instruction set computing (CISC);

a. RISC (Reduced instruction set computing) architecture has a set of instructions, so high-level language compilers can produce more efficient code.

b. It allows freedom of using the space on microprocessors because of its simplicity.

c. Many RISC processors use the registers for passing arguments and holding the local variables.

d. RISC functions use only a few parameters, and the RISC processors cannot use the call instructions, and therefore, use a fixed length instruction which is easy to pipeline.

The options that are true about RISC (Reduced instruction set computing) is; E: all of the above

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