Which expression is equivalent to 6(5m-7)

a 11m-13
b 11m-42
c 30m-13
d 30m-42

Answer:

Step-by-step explanation:

7) A

8) D

9) B

10) A

Answer:

£5.40

Step-by-step explanation:

just add a zero for it to be pence

Answer:

Step-by-step explanation:

660

Answer:

660 pounds

Step-by-step explanation:

Answer:

9) 21

10) 24

11) 14.6

Step-by-step explanation:

Literally just add up all the sides.

Answer:

Step-by-step explanation:

[tex] \frac{8}{32} = \frac{4}{16} = \frac{2}{8} = \frac{1}{4} [/tex]

[tex] \frac{27}{54} = \frac{9 }{18} = \frac{3}{6} = \frac{1}{2} [/tex]

[tex] \frac{36}{24} = \frac{18}{12} = \frac{9}{6} = \frac{3}{2} [/tex]

[tex] \frac{30}{60} = \frac{15}{30} = \frac{5}{10} = \frac{1}{2} [/tex]

Answer:

The answer is 6.8

Step-by-step explanation:

Check on your calculator 6.8^2 equals 46

Answer:

90 mallards

Step-by-step explanation:

No. of ducks = 200

Mallards = 45%

45% of 200 = 45/100 × 200

=90

Answer:

A. 6x^{2}+6y^{2}=144

Step-by-step explanation:

Answer:

C≈18.85

Step-by-step explanation:

Answer:

x=8

Step-by-step explanation:

23x=184

x=8

Step-by-step explanation:

s it will be just know the right

Answer:

SA = 200π cm²

Step-by-step explanation:

The surface area is calculated as

SA = area of base + area of curved surface

     = πr² + πrs ( r is the radius and s the slant height )

Using Pythagoras' identity in the right triangle to find s

s² = 15² + 8² = 225 + 64 = 289 ( take square root of both sides )

s = [tex]\sqrt{289}[/tex] = 17

SA = π × 8² + π × 8 × 17

      = 64π + 136π

      = 200π cm²

Answer:

The subjects in the study are not representative of the population, because some members of the population were not able to participate in the study.

Step-by-step explanation: i got it right on the test

A sample is said to exhibit undercoverage bias, if some of the portion or category of the population are not adequately represented or exempted from the selected sample. Hence, undercoverage bias exists because, The subjects in the study are not representative of the population, because some members of the population were not able to participate in the study.

Undercoverage translates that the opinion of some members of the population were not even considered. Hence, the introduction of undercoverage bias.

Learn more : https://brainly.com/question/21774717

Answer:   5x + 2y = 19

x + 4y = 13

Step-by-step explanation:

let x be the cost of each five-pound bag of candy, and y be the cost of each one-pound bag of candy.

5x + 2y = 19

x + 4y = 13

Answer: p = - 6y - 2x + 8

Step-by-step explanation:

p = 2l + 2w

p = 2(4+5y-3x) + 2(2x - 8y​)

p = 8 + 10y - 6x + 4x- 16y

p = - 6y - 2x + 8

Answer:

P=-2x-6y+8 i believe

Step-by-step explanation:

P= 2(4+5y-3x) + 2(2x-8y)

P= 8+10y-6x +4x-16y

=8+10y+−6x+4x+−16y

=(−6x+4x)+(10y+−16y)+(8)

=−2x−6y+8

Answer:

1x-2y

Step-by-step explanation:

You have to go down 2 on the y-axis and over to the right 1 on the x axis

Answer:

Step-by-step explanation:

To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points.

Here are the equations you can use to find the slope;

Slope. y2 - y1 / x2 - x1 = slope.

Slope Intercept form. y = mx + b.

Point slope form. y - y1 = m ( x - x1)

Answer:

Step-by-step explanation:

Area = 1/2bh

since b = 10in and height = 6in

then

1/2 x 10 x 6

= 30

Answer:

Area = 1/2bh since b = 10in and height = 6in next you do 1/2 x 10 x 6 = 30

Answer:

I think it is 19 I not really sure

Step-by-step explanation:

o work it out of my paper and I got 19

Answer: The answer to this math question about finding the statement is very true about 2 similar rectangles are being shown here below is B). B) The area of rectangle B is [tex]\frac{1}{9}[/tex] of the area of rectangle A.

Step-by-step explanation: I'm very sorry about that, but I don't have any step-by-step explanation to this math question about finding the statement is very true about 2 similar rectangles are shown here below, so anyways, I hope that my full short given answer without my given step-by-step explanation to your own math question about finding the statement is very true about 2 similar rectangles are being shown here below, please mark me as Brainliest, take care, always be safe, and have a great rest of the day and good night! :D

Sincerely,

Jason Ta,

The Ambitious of The Brainly And The Role of The TDSB And WHCI Student of The High School.

Answer:

Each algebra book costs $60.

Step-by-step explanation:

A=bill for algebra books; S=bill for science books=A+$360

S+A=$3960 Substitute for S

A+$360+A=$3960 Subtract $360 from each side.

2A=$3600 Divide each side by 2.

A=$1800 The order for 30 algebra books cost $1800.

Individual book=A/30

individual book=$1800/30=$60 ANSWER: Each algebra book cost $60.

Answer:

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

[tex]\cot(x)+\tan(x)[/tex]

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{1}{\cos(x)}][/tex]

[tex]\csc(x)[\sec(x)][/tex]

[tex]\csc(x)[\csc(\frac{\pi}{2}-x)][/tex]

[tex]\csc(x)\csc(\frac{\pi}{2}-x)[/tex]

Step-by-step explanation:

I'm going to use [tex]x[/tex] instead of [tex]\theta[/tex] because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

I'm going to use a cofunction identity for the 2nd term.

This is the identity: [tex]\tan(x)=\cot(\frac{\pi}{2}-x)[/tex] I'm going to use there.

[tex]\cot(x)+\tan(x)[/tex]

I'm going to rewrite this in terms of [tex]\sin(x)[/tex] and [tex]\cos(x)[/tex] because I prefer to work in those terms. My objective here is to some how write this sum as a product.

I'm going to first use these quotient identities: [tex]\frac{\cos(x)}{\sin(x)}=\cot(x)[/tex] and [tex]\frac{\sin(x)}{\cos(x)}=\tan(x)[/tex]

So we have:

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

I'm going to factor out [tex]\frac{1}{\sin(x)}[/tex] because if I do that I will have the [tex]\csc(x)[/tex] factor I see on the right by the reciprocal identity:

[tex]\csc(x)=\frac{1}{\sin(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

Now I need to somehow show right right factor of this is equal to the right factor of the right hand side.

That is, I need to show [tex]\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}[/tex] is equal to [tex]\csc(\frac{\pi}{2}-x)[/tex].

So since I want one term I'm going to write as a single fraction first:

[tex]\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}[/tex]

Find a common denominator which is [tex]\cos(x)[/tex]:

[tex]\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}[/tex]

[tex]\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}[/tex]

[tex]\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}[/tex]

By  the Pythagorean Identity [tex]\cos^2(x)+\sin^2(x)=1[/tex] I can rewrite the top as 1:

[tex]\frac{1}{\cos(x)}[/tex]

By the quotient identity [tex]\sec(x)=\frac{1}{\cos(x)}[/tex], I can rewrite this as:

[tex]\sec(x)[/tex]

By the cofunction identity [tex]\sec(x)=\csc(x)=(\frac{\pi}{2}-x)[/tex], we have the second factor of the right hand side:

[tex]\csc(\frac{\pi}{2}-x)[/tex]

Let's just do it all together without all the words now:

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

[tex]\cot(x)+\tan(x)[/tex]

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{1}{\cos(x)}][/tex]

[tex]\csc(x)[\sec(x)][/tex]

[tex]\csc(x)[\csc(\frac{\pi}{2}-x)][/tex]

[tex]\csc(x)\csc(\frac{\pi}{2}-x)[/tex]

Answer:

20 stacks of 5 pennies weight 0.33 pounds

Step-by-step explanation:

First, we need to calculate the weight in kilograms of 20 stacks of 5 pennies:

20 stacks= 0.0075*20

20 stacks= 0.15 kg

Now, we can determine the weight in pounds:

1kg = 2.2 pounds

0.15kg = ?

Weight in pounds= (0.15*2.2)/1

Weight in pounds= 0.33 pounds

20 stacks of 5 pennies weight 0.33 pounds

Step-by-step explanation:

40, 58, 58, 72, 74, 74, 76, 81,  83, 84, 92

1      2    3   4        5     6      5     4   3    2   1

1) A. 74

2) B. 40

3) A. 92

4) A. 58

Brainlist pls!

Answer:

600

Step-by-step explanation:

6 percent of 5000 is 300. 300x2=600.

Sorry if im wrong