Which distance–time graph most closely represents an object moving with uniform motion? and for the second one, Which speed–time graph most closely represents an object travelling with uniform motion?

Which Distancetime Graph Most Closely Represents An Object Moving With Uniform Motion? And For The Second

Answers

Answer 1

Answer:

1. B

2. D

Explanation:

Answer 2

1. The distance–time graph most closely represents an object moving with uniform motion is B.

2. The speed–time graph most closely represents an object travelling with uniform motion is D.

What is uniform motion?

The motion of the object when it is moving with constant velocity or velocity is not changing with time, is called the uniform motion.

1. For uniform motion, equal distance is moved in equal interval of time. So, the best fit graph for uniform motion is B having linear relationship.

Thus, the correct option is B.

2. . For uniform motion, velocity is same at all times. So, the best fit graph for uniform motion is D having straight line parallel to x axis representing time.

Thus, the correct option is D.

Learn more about uniform motion.

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Related Questions

how does an electric iron work when the power is on​

Answers

Answer:

The basic principle on which the electric iron works is that when a current is passed through a piece of wire, the wire heats up. This heat is distributed to the sole (base) plate of the electric iron through conduction.

What method of charge transfer is shown in the above diagram? A. friction B. induction C. radiation D. conduction

Answers

Explanation:

Since how I can't see the graph I'll explain as best as I can.

Friction is the process of two things rubbing against each other causing heat, and pressure. A example would be rubbing a stick into a log to start a fire.

Conduction is heat transfer that usually involves heat flowing from a hot object to a cold object increasing the cold objects temperature. A example would be putting a spoon in a pot of hot water and in result the spoon will also get hot.

Radiation is a type of transfer that involved the sun shining it's energy transforming it's light energy into electrical energy. Or increasing somethings temperature by using light.

Induction is the process of using a conductor to change the magnetic field of a magnet in order to do this you need a electrical conductor and a magnet you put the magnet in the conductor and the heat causes the magnetic field to change.

Hope this helps.

I believe it's B, induction.

A gas is held at atmospheric pressure, approximately 100kPa, and room temperature, 298K,
in a container closed with a piston. The piston is initially in a fixed position so the container has a volume of 2.0dm3.
The gas is heated to a temperature of 100∘C
What is the pressure in the container?

Answers

Answer:

125 KPa

Explanation:

Data obtained from the question include:

Initial pressure (P1) = 100 KPa

Initial temperature (T1) = 298 K

Final temperature (T2) = 100°C = 100°C + 273 = 373 K

Final pressure (P2) =..?

Since the volume of the container is fixed, the final pressure in the container can be obtained as follow:

P1/T1 = P2/T2

100/298 = P2/373

Cross multiply

298 x P2 = 100 x 373

Divide both side by 298

P2 = (100 x 373) / 298

P2 = 125.2 ≈ 125 KPa

Therefore, the final pressure in the container is approximately 125 KPa.

a shot putter shoots a 7.3kg shot from rest to 14m/s in 1.5s. what was the average power?

Answers

Answer: 477W

Explanation:

Given the following :

Mass (m) = 7.3kg

Initial Velocity (u) = 0

Final velocity (v) = 14m/s

time (t) = 1.5s

Power = workdone (W) / time (t)

The workdone can be calculated as the change in kinetic energy (KE) :

Recall ;

KE = 0.5mv^2

Therefore, change in KE is given by:

0.5mv^2 - 0.5mu^2

Change in KE = 0.5(7.3)(14^2) - 0.5(7.3)(0^2)

Change in KE = 715.4J

Therefore ;

Average power = Workdone / time

Workdone = change in KE = 715.4N

Average power = 715.4 / 1.5

Average power = 476.93333 W

= 477W


Where is the energy in a glucose molecule stored?

Answers

Answer:

Energy is stored in the bonds between atoms

Answer:

Energy is stored in the bonds between atoms

Explanation:

Ape-x

Why are fuel cells used on space shuttles instead of batteries?

Answers

Answer:

Fuel cells are used in the space shuttle as one component of the electrical power system. ... The fuel cell power plants generate heat and water as by-products of electrical power generation. The excess heat is directed to fuel cell heat exchangers, where the excess heat is rejected to Freon coolant loops

which glass is used in astrology?​

Answers

Answer:

The answer is either looking glass or stained glass.

Explanation:

The popular glass used in astrology is stained glass which is popular in symbolization of huge astrology figures. As for looking glass, it's more popular in astrological souvenirs or objects.

Answer:

i think answer is pisces horoscope

How do you calculate the speed of a 3.1eV photon and a 3.1eV electron?

Answers

Explanation:

We need to find the speed of a 3.1eV proton and a 3.1eV electron.

For proton, using conservation of energy such that,

[tex]\dfrac{1}{2}m_pv_p^2=eV\\\\v_p^2=\dfrac{2eV}{m_p}\\\\v_p=\sqrt{\dfrac{2eV}{m_p}}[/tex]

[tex]m_p[/tex] is mass of proton

[tex]v_p=\sqrt{\dfrac{2\times 3.1\times 1.6\times 10^{-19}\ J}{1.67\times 10^{-27}\ kg}}\\\\v_p=2.43\times 10^5\ m/s[/tex]

For electron,

[tex]\dfrac{1}{2}m_ev_e^2=eV\\\\v_e^2=\dfrac{2eV}{m_e}\\\\v_e=\sqrt{\dfrac{2eV}{m_e}}[/tex]

[tex]m_e[/tex] is mass of proton

[tex]v_e=\sqrt{\dfrac{2\times 3.1\times 1.6\times 10^{-19}\ J}{9.1\times 10^{-31}\ kg}}\\\\v_e=1.44\times 10^6\ m/s[/tex]

Hence, this is the required solution.


Suppose that an object is moving with a constant velocity. Make a statement concerning its acceleration

Answers

The acceleration is zero

Hope this helps

When an object is moving at a constant velocity, the acceleration of the object is zero because the change in the velocity of the object is zero.

Acceleration is defined as the change in velocity per change in time of motion.

The acceleration of an object is calculated as;

[tex]a = \frac{\Delta v}{\Delta t } = \frac{v_2 - v_1}{t_2 - t_1}[/tex]

When an object is moving at a constant velocity, the change in the velocity of the object is zero.

[tex]v_2 = v_1\\\\a = \frac{v_2 - v_1}{t_2 -t_1} = \frac{v_2 - v_2}{t_2 -t_1} = 0[/tex]

Thus, we can conclude that when an object is moving at a constant velocity, the acceleration of the object is zero because the change in the velocity of the object is zero.

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A 22.8 kg rocking chair begins to slide across the carpet when the push reaches 57.0 N. What is the coefficient of static friction?​

Answers

Answer:

0.255

Explanation:

The following data were obtained from the question:

Force (F) = 57 N

Mass (m) = 22.8 Kg

Coefficient of static friction (µ) =...?

Next, we shall determine the normal reaction (R). This is illustrated below:

Mass (m) = 22.8 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal reaction (R) =?

R = mg

R = 22.8 x 9.8

R = 223.44 N

Finally, we can obtain the coefficient of static friction (µ) as follow:

Force (F) = 57 N

Normal reaction (R) = 223.44 N

Coefficient of static friction (µ) =...?

F = µR

57 = µ x 223.44

Divide both side by 223.44

µ = 57/223.44

µ = 0.255

Therefore, the coefficient of static friction (µ) is 0.255.

Answer:

.255

Explanation:

I'm also on acellus and it's the right answer

Why is it advisable not to look directly at the Sun? Please Give scientific reason for your answer

Answers

This sunlight can flood your retinas, overstimulating the rods and cones that sense light and causing them to release chemicals that can damage the retinas. This condition is known as solar retinopathy, and it can cause permanent eye damage.

Answer:

your eyes would get seriously damaged

Explanation:

when you look directly at the sun, the sun shines it's rays directly to your eyes , which damage them. that's why you should always wear sunglasses in that type of weather, and never point directly at the sun. if you find this answer helpful, mark it as brainliest.

Which describes refraction? *

10 points

O

Refracted rays travel through a boundary into a new medium.

O

The angle of incidence is the same for angle of refraction

Refracted rays change direction and go back to the original medium

Answers

Answer:

Refracted rays travel through a boundary into a new medium.

Explanation:

Refracted rays travel through a boundary into a new medium. is only true for refraction.

The angle of incidence is the same for angle of refraction, is not true for refraction. Refraction follows Snell's law, states that ratio of the sine of the angle of refraction and the sine of the angle of incidence is always constant and equivalent to the ratio of phase velocities of the two mediums it is passing through.

Refracted rays change direction and go back to the original medium is false for refraction however, it is true for reflection.

5. A bus starting from rest accelerates in a straight line at a constant rate of 3m/s2 for 8s. Calculate the distance travelled by the bus during this time interval.

Answers

Answer:

d = 96 meters

Explanation:

a = acceleration

t = time

d = distance

[tex]d = \frac{1}{2} \times a \times {t}^{2} [/tex]

[tex]d = \frac{1}{2} \times 3 \times {8}^{2} [/tex]

[tex]d = 96[/tex]

A force of 6 N is used to open a door, wherein the distance of the force to the axis of rotation is 80 cm. If the angular acceleration it acquires is 0.5 rad/s 2, determine the moment of inertia of the door.

Answers

Explanation:

∑τ = Iα

(6 N) (0.80 m) = I (0.5 rad/s²)

I = 9.6 kg m²

A drop
of
oil volume 10 m
Spreads out on water to make a
Circular fils of diameter 10
What is that thickness?​

Answers

Answer:

[tex]27.5\ m[/tex]

Explanation:

As we know that volume of cylinder is

[tex]v=\pi r^{2} *h[/tex]

Where v=volume , h= height or thickness and r= radius

Here,

[tex]v= 10 m ,\ diameter= 10, \ r=\frac{diameter}{2} \ r=\frac{10}{2}\\ r=5[/tex]

Putting these values in the previous equation , we get

[tex]10\ = \frac{22}{7} *5 *5*h\\ 14\ =\ 110*h\\h=\frac{110}{14} \\h=\frac{55}{2} \\\\h=27.5\ m[/tex]

Therefore thickness is 27.5 m

Is Einstein's equation E=mc^2 is applicable on our earth if it is not why?is it applicable in space can a body moves through speed of light

Answers

◦•●◉✿hello friend ur answer✿◉●•◦

◦•●◉✿What does E mc2 actually mean?

E = mc2. It's the world's most famous equation, but what does it really mean? "Energy equals mass times the speed of light squared." On the most basic level, the equation says that energy and mass (matter) are interchangeable; they are different forms of the same thing.✿◉●•◦

1. Two blocks (5.0 kg and 6.0 kg) are connected through a frictionless system. The angle of
the ramp is 45°
A. Find the tension in the string.
B. Determine the normal force on the 5.0 kg block.

Answers

Answer: A) 45.5N b) 34.6N

Explanation:

Given the following :

Mass of block A(m1) = 5kg

Mass of block B (m2) = 6kg

Angle of incline (Θ) = 45°

Force pulling the down the incline = m1×a×sinΘ

Tension (T) = (m2×a) - (m2)×g

Where g = acceleration due to gravity

a = acceleration

Net force = (5×9.8×sin45°) - (6×9.8)

Net force = 34.648232 - 58.8

The net force acting on the body = 24.4N

Therefore,

Acceleration, a = Net force/ total mass

a = 24.4 / (6+5)

a = 2.22ms^-2

T = (m2 ×g) - (m2×a)

T = (6 × 9.8) - (6 × 2.22)

T = 58.8 - 13.32

T = 45.48

T = 45.5N

B) Normal reaction:

Horizontal component:

m1gCosΘ = 5 × 9.8 × cos45°

= 5 × 9.8 × 0.7071067

= 34.648232

= 34.6N

The tension on the string is 45.62N and the normal force is 34.65N

Data;

m1 = 5.0kgm2 = 6.0kgangle = 45°

Tension in The String

Taking the two mass into consideration

for the 6kg mass

[tex]6g - 6a[/tex]

for the 5kg mass

[tex]5gsin45 + 5a\\[/tex]

Equating the tension in both equations

[tex]6g - 6a = 5gsin45 + 5a[/tex]

Let's solve for a

[tex]6a + 5a = 6g - 5gsin45\\11a = 6g - 5gsin45\\a = \frac{6g - 5gsin45}{11}\\ a = \frac{6* 9.8 - 5*9.8*sin45}{11}\\ a = 2.1956 m/s^2\\T = 6g - 6a\\T = 6*9.8 - 6*2.1956\\T = 45.62N[/tex]

b)

The normal force on the 5kg block.

The normal force on the 5kg block can be calculated as

[tex]N = 5 * 9.8 cos 45 = 34.65N[/tex]

The tension on the string is 45.62N and the normal force is 34.65N

Learn more on tension and normal force here;

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An electron is in motion at 4.0 × 106 m/s horizontally when it enters a region of space between two parallel plates, as shown, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 102 N/C and separation between the charged plates is 2.0 cm. Determine the horizontal distance travelled by the electron when it hits the plate.

Answers

Answer:

xmax = 9.5cm

Explanation:

In this case, the trajectory described by the electron, when it enters in the region between the parallel plates, is a semi parabolic trajectory.

In order to find the horizontal distance traveled by the electron you first calculate the vertical acceleration of the electron.

You use the Newton second law and the electric force on the electron:

[tex]F_e=qE=ma[/tex]             (1)

q: charge of the electron = 1.6*10^-19 C

m: mass of the electron = 9.1*10-31 kg

E: magnitude of the electric field = 4.0*10^2N/C

You solve the equation (1) for a:

[tex]a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(4.0*10^2N/C)}{9.1*10^{-31}kg}=7.03*10^{13}\frac{m}{s^2}[/tex]

Next, you use the following formula for the maximum horizontal distance reached by an object, with semi parabolic motion at a height of d:

[tex]x_{max}=v_o\sqrt{\frac{2d}{a}}[/tex]             (2)

Here, the height d is the distance between the plates d = 2.0cm = 0.02m

vo: initial velocity of the electron = 4.0*10^6m/s

You replace the values of the parameters in the equation (2):

[tex]x_{max}=(4.0*10^6m/s)\sqrt{\frac{2(0.02m)}{7.03*10^{13}m/s^2}}\\\\x_{max}=0.095m=9.5cm[/tex]

The horizontal distance traveled by the electron is 9.5cm

Derive the following equations for uniformly accelerated motion by graphical method. a) Velocity -time relation b) Position - time relation 3) Position – velocity relation.

Answers

Answer:

a) velocity - time realation

that graph's gradient gives the uniform acceleration

A wind blows at 100 km / h from the east. An aircraft points due north and sets off. In still air its speed is 150 km / h. What will the aircraft's actual velocity be?

Answers

Answer:

180.28 km/h

Explanation:

Let north and south represent the positive and negative y axis and east and west represent the positive and negative x axis.

Given;

Velocity of wind vx= 100 km/s

Velocity of aircraft in still air vy = 150 km/s

The resultant velocity Vr is;

Vr = √(vx^2 + vy^2)

Vr = √(100^2 + 150^2)

Vr = 180.2775637731 km/h

Vr = 180.28 km/h

Un automovil circula a 126km/h por una autopista. Su conductor observa que a 150 m delante de el, se encuentra un árbol caído que ocupa toda la calzada. Inmediatamente presiona los frenos con una aceleración de -3,5 m/s². Determinar si logra evitar el choque.

Answers

Answer:

El conductor no puede evitar el choque.

Explanation:

Primero, convierta la velocidad del conductor a m / s:

1 km/h = 0.277778 m/s

126 km/h = 126 * 0.277778 = 35 m/s

La velocidad del automóvil es de 35 m / s.

El conductor presiona los frenos con una aceleración de -3.5 m / s² para evitar un choque a 150 m por delante.

Veamos qué distancia se moverá el automóvil después de que comience a desacelerar.

Utilizaremos una de las ecuaciones de movimiento lineal de Newton:

[tex]v^2 = u^2 + 2as[/tex]

donde v = velocidad final = 0 m / s (el automóvil debe detenerse)

u = velocidad inicial = 35 m / s

a = aceleración = -3.5 m / s².

s = distancia recorrida

Por lo tanto:

[tex]0 = 35^2 + (2 * -3.5 * s)\\\\=> 1225 = 7.0s\\\\s = 1225 / 7 = 175 m[/tex]

Esto significa que el automóvil se detendrá a 175 m.

Por lo tanto, a esa velocidad y aceleración, el conductor chocará contra el árbol caído porque el automóvil no podrá detenerse antes de alcanzar la posición del árbol.

A box of mass 4.5 kg is pushed across a rough surface (μK = 0.18) for a distance of 2.0 m by a constant force of 10 N. If the object reaches a speed of 2.0 m/s by the end of the push, what was its speed at the beginning of the push?

Answers

Answer:

Explanation:

  Work done by force applied = force x displacement

= 10 x 2 = 20 J

Negative work done by frictional force

= μ mg x d where μ is coefficient of kinetic friction , m is mass and d is displacement

= - .18 x 4.5 x 9.8 x 2

= - 15.87 J

Net positive work done on the mass = 4.13 J

If v was the initial velocity

increase in kinetic energy = positive work done on mass

= 1 / 2 m v² - 1/2 m u² = 4.13 where v is final and u is initial velocity

1 /2 x 4.5 x 2 ² - 1/2 x 4.5 u² = 4.13

9 - 2.25 u² = 4.13

2.25 u² = 4.87

u² = 2.16

u = 1.47 m /s .

The earth attracts an apple with a force of 15 Newton. taking this as an action force, how much is reaction force? who accepts the reaction force? on which body does a reaction force act?

Answers

Answer:

action = reaction

land accepts

reaction force acts on the apple

Answer:

15 Newton

Explanation:

According to Newton's third law of motion, "Every action has a reaction which is equal in magnitude but opposite in direction" (Right now, we're not talking about direction, so we'll ignore it)

So,

Action Force = Reaction Force

Reaction Force = 15 N

The action force is by the Earth on the Apple, So the reaction force will be by the Apple on the Earth.

Samuel applies a horizontal force of 35.0 N to a sleigh over a distance of 1.50 m along a level surface. Calculate the work done on the sleigh by samuel. show your work.

Answers

Answer:

52.5 J

Explanation:

Work done (W) is the product of the force (F) applied on a body and the distance (s) moved in the direction of the force.

i.e W = F × s

It is a scalar quantity and measured in Joules (J).

Given that: F = 35.0 N and s = 1.50 m, then;

W = F × s

W = 35.0 × 1.5

   = 52.5 J

Therefore, the work done on the sleigh by Samuel is 52.5 J.

What is electronic configuration?​

Answers

Answer:

Electronic Configuration is the distribution of electrons in sub shells (s,p,d,f).

For Example,

The electronic configuration of Carbon (6 electrons) is [tex]1s^22s^22p^2[/tex]

a disc starts from rest with an angular acceleration completes 10 revolutions in 2 seconds. the time taken by it to complete 10 more revolution from that instant is​

Answers

Starting from rest, the disc completes [tex]\theta[/tex] revolutions after [tex]t[/tex] seconds according to

[tex]\theta=\dfrac\alpha2t^2[/tex]

with angular acceleration [tex]\alpha[/tex]. It completes 10 rev in 2 s, which means

[tex]10\,\mathrm{rev}=\dfrac\alpha2(2\,\mathrm s)^2\implies\alpha=5\dfrac{\rm rev}{\mathrm s^2}[/tex]

Find the time it takes to complete 20 rev with this acceleration:

[tex]20\,\mathrm{rev}=\dfrac12\left(5\dfrac{\rm rev}{\mathrm s^2}\right)t^2\implies t=\sqrt8\,\mathrm s\approx2.83\,\mathrm s[/tex]

so it takes approximately 0.83 s to complete 10 more rev.

As the distance between a satellite in a circular orbit and the central object increases, the period of the satellite .

Answers

Answer:

As the distance between a satellite in a circular orbit and the central object increases, the period of the satellite increases .

Explanation:

Answer:

Increases

Explanation:

A body is acted upon by a force of 4N.
As a result, the velocity of the body has
changed from 0.3 m/s to 0.1 m/s passing
through a certain distance. If the mass
of the body is 1 kg, find the distance travelled.

Answers

[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Kinematics.

so here we get as,

V^2 = U^2 + 2as

so here, a = -0.2 m/s^2

(0.1)^2 = (0.3)^2 + (-0.2)(s)

=> 0.01 = 0.09 - 0.2s

=> 0.2s = 0.08

=> s = 0.08/0.2

=> s = 0.4 m

Ratio of acceleration due to grabity and universal gravitational constant

Answers

Answer:

acceleration due to gravity = 9.8m/s^2

universal gravitational constant= 6.67×10 ^_11 nm^2 kg_2

now, ratio=9.8/6.67×10^_11.

Quantum mechanics applies to A) subatomic, atomic, nanometer-size, and micrometer-size systems. B) nanometer, micrometer, and kilometer-size systems. C) atomic, nanometer-size, and micrometer-size systems. D) subatomic, atomic, and nanometer-size systems.

Answers

Answer: D) subatomic, atomic, and nanometer-size systems.

Explanation: Quantum mechanics applies to subatomic, atomic, and nanometer-size systems.

Other Questions
Which literary technique is used in this excerpt from Frankenstein by Mary Shelley? My life, as it passed thus, was indeed hateful to me, and it was during sleep alone that I could taste joy. O blessed sleep! Often, when most miserable, I sank to repose, and my dreams lulled me even to rapture. The spirits that guarded me had provided these moments, or rather hours, of happiness that I might retain strength to fulfil my pilgrimage. Deprived of this respite, I should have sunk under my hardships. During the day I was sustained and inspirited by the hope of night, for in sleep I saw my friends, my wife, and my beloved country; again I saw the benevolent countenance of my father, heard the silver tones of my Elizabeth's voice, and beheld Clerval enjoying health and youth. Often, when wearied by a toilsome march, I persuaded myself that I was dreaming until night should come and that I should then enjoy reality in the arms of my dearest friends. What agonizing fondness did I feel for them! How did I cling to their dear forms, as sometimes they haunted even my waking hours, and persuade myself that they still lived! At such moments vengeance, that burned within me, died in my heart, and I pursued my path towards the destruction of the daemon more as a task enjoined by heaven, as the mechanical impulse of some power of which I was unconscious, than as the ardent desire of my soul. What his feelings were whom I pursued I cannot know. Sometimes, indeed, he left marks in writing on the barks of the trees or cut in stone that guided me and instigated my fury. "My reign is not yet over"these words were legible in one of these inscriptions"you live, and my power is complete. Follow me; I seek the everlasting ices of the north, where you will feel the misery of cold and frost, to which I am impassive. You will find near this place, if you follow not too tardily, a dead hare; eat and be refreshed. Come on, my enemy; we have yet to wrestle for our lives, but many hard and miserable hours must you endure until that period shall arrive." Scoffing devil! Again do I vow vengeance; again do I devote thee, miserable fiend, to torture and death. Never will I give up my search until he or I perish; and then with what ecstasy shall I join my Elizabeth and my departed friends, who even now prepare for me the reward of my tedious toil and horrible pilgrimage! Which one of the following minerals participates in more than 300 types of enzyme-driven reactions, including those in DNA and protein synthesis, blood clotting, muscle contraction, and ATP production? 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Do not use the examples give above Cellar Wines has a debt-equity ratio of 0.54, sales of $728,700, net income of $94,900, and total debt of $382,000. What is the return on equity PRE CALC, help please A material that does not conduct electricity is called a... what? A customer buys 100 shares of ABC at $30 as the initial transaction in a new margin account. Subsequently, ABC rises to $40 per share in the market. What is the account's equity after the change in market value