"When your heart was an open book" is an example of of
A. simile
B. metaphor
C. alliteration
D. all of the above

Answer:

And 500 mL of 2M NaOH solution contains 80.02g NaOH=40.0 g of NaOH .

Explanation:

So, If we mix 40.0 g of NaOH with enough distilled water to make 500 mL, we will get a 2.00 M NaOH solution.

Answer: 0.637M

10.2M

1.36M

0.0982M

Explanation: the answer is 1.36M

The molarity of the CsOH solution is 0.636 M.

Molarity is the concentration of any substance in a place.

The reaction is

HBr + CsOH —> CsBr + H₂O

The formula of molarity

[tex]M = \dfrac{n}{V}[/tex]

[tex]\dfrac{0.25 \times 38.2 }{15} = 0.6366[/tex]

Thus, the molarity of the CsOH solution is 0.636 M.

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Answer:

Isomerism is the phenomenon in which more than one compounds have the same chemical formula but different chemical structures. Chemical compounds that have identical chemical formulae but differ in properties and the arrangement of atoms in the molecule are called isomers. Therefore, the compounds that exhibit isomerism are known as isomers.

The word “isomer” is derived from the Greek words “isos” and “meros”, which mean “equal parts”. This term was coined by the Swedish chemist Jacob Berzelius in the year 1830.

Explanation:

Answer: Biomass, Nuclear and Gas are the three forms of non- renewable energy.

Explanation:

The concept molar mass is used here to determine the compound which has the greatest mass for its one mole. The correct option is C.

The molar mass also defined as the molecular weight of a compound is generally the sum of the atomic masses of each atoms present in the given compound. Its unit is g mol⁻¹.

The mass of 1 mole of any substance is also called the molar mass. Evidently molar mass is equal to the atomic mass or the molecular mass denoted in grams depending upon whether the substance contains atoms or molecules.

Here (SiHA) is known as the most important bioceramic which is used in the field of bioactive bone implants. The compound CO is carbon monoxide, CH₃OH is methanol and C₂H₆ is ethane.

The molar mass of the given compounds are obtained by adding their atomic masses :

CO = (12.011 g/mol+ 15.999 g/mol) = 28.01 g/mol

CH₃OH = (12.011 g/mol + 3 × 1.007 g/mol + 15.999 g/mol + 1.007 g/mol) = 32.04 g/mol

C₂H₆ = (2 × 12.011 g/mol + 6 ×  1.007 g/mol) = 30.07 g/mol

Here among the given compounds CH₃OH has the greatest mass for one mole of the compound.

Thus the correct option is C - CH₃OH.

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Answer:

Metal oxide + acid —> salt + water

Explanation:

Answer: the orbital with a hauny dump bell shape is the p- orbital.

Explanation:

An orbital can be defined as part of the nucleus of an atom that consists of an electron of maximum given energy. The shape of this part gives the shape of the orbitals. There are different types of orbitals which include:

--> s-orbitals: This is the type of orbital in which the probability of finding electron is the same in all directions usually at a given distance form the nucleus. Therefore the s-orbitals are SPHERICAL in shape about the nucleus and are non- directional.

--> d-orbitals: This is said to have a clover shape. This is because the electron is pushed out four times during the rotation when an opposite spin proton aligns gluons with three spin-aligned protons.

--> p-orbitals: This is said to have a DUMP-BELL shape. This is because there are three similar p-orbitals which are arranged mutually at right angles to each other along x,y, and z axes. All the three p-orbitals are of the same energy level.

Answer:

36.16 amu

Explanation:

From the question given above, the following data were obtained:

1st Isotope:

Mass of 1st isotope = 35.01 amu

Abundance of 1st isotope = 35%

2nd isotope:

Mass of 2nd isotope = 36.01 amu

Abundance of 2nd isotope = 15%

3rd isotope:

Mass of 3rd isotope = 37.02 amu

Abundance of 3rd isotope = 50%

Atomic mass of element A =?

The atomic mass of element A can be obtained as follow:

Atomic mass = [(mass of 1st × Abundance)/100] + [(mass of 2nd × Abundance)/100] + [(mass of 3rd × Abundance)/100]

= [(35.01 × 35)/100] + [(36.01 × 15)/100] + [(37.02 × 50)/100]

= 12.25 + 5.40 + 18.51

= 36.16 amu

Thus, the atomic mass of element A is 36.16 amu

Since orbital period depends on how far you are from the sun, planets closer to the sun have a orbital period less than one earth year.

These planets are Mercury and Venus

Answer:

[tex]\rho=12g/cm^3[/tex]

Explanation:

From the question we are told that:

Length[tex]l=379.0pm=>379*10^{-10}cm[/tex]

Atomic mass of X [tex]M= 195.0 amu=>gmol^{-1}[/tex]

Where

[tex]Avogadro\ constant = 6.023 * 10^{23} mol-1[/tex]

Let

The Number of units in BCC unit cell [tex]n= 2[/tex]

Generally the equation for Density is mathematically given by

[tex]\rho= \frac{M x n}{l^3*Avogadro constant}[/tex]

[tex]\rho=\frac{197 x 2}{(379*10^{-10})^3*6.023 x 10^{23}}[/tex]

[tex]\rho=12g/cm^3[/tex]

Therefore he density of Xin g/cc

[tex]\rho=12g/cm^3[/tex]

Answer:

a.

Explanation:

electromagnetism

Answer:

79.1g of weak base must be combined with 56.0g of conjugate acid

Explanation:

that is 1.00 M in the weak base?

The weak base is C5H5N with a pKa of 5.17 (Ka=6.7×10-6)and a desire pH of 5.63

The equilibrium of the weak base is with the bromide salt of the conjugate acid is:

C5H5N(aq) + H2O(l) + Br- ⇄ C5H5NHBr(aq) + OH-(aq)

Where Kb = Kw / Ka = 1x10⁻¹⁴ / 6.7x10⁻⁶

Kb = 1.49x10⁻⁹ is defined as:

Kb = 1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]

Where [OH-] = 10^-(14- pH) = 10^-(14- 5.63) = 4.255x10⁻⁹M

[C5H5N] = 1.00M

Replacing:

1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]

1.49x10⁻⁹ = [C5H5NHBr] [4.255x10⁻⁹M] / [1.00M]

[C5H5NHBr] = 0.35M

In 1L the moles of C5H5NHBr are 0.35 moles

Mass C5H5NHBr: 160.0118g/mol

0.35 moles * (160.0118g / mol) =

56.0g of C5H5NHBr are necessaries

The mass of C5H5N is -79.1g/mol-:

1.00moles * (79.1g/mol) =

Answer:

4NH3+6NO+5N2+6H20

Explanation:

Answer:

A B D

Explanation:

Answer:  A: Being the power source of stars

                B: Forming heavier elements from light elements

                D: Being used in thermonuclear weapons

Explanation: (Edmentum)

Answer:

5.6 mol

Explanation:

n = N/NA

n: number of moles

N: number of particles

NA: Avogadro's constant

n = 3.4×10²⁴/6.02×10²³ mol^-1 = 5.6 mol

Answer:

moles= w/mm

moles=150/30

moles=5

Answer:

D

Explanation:

hope this helped and sorry if it didn't but I wish you luck:D

Answer:

27.98g/mol

Explanation:

Using ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

T = temperature (K)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

According to the information given:

V = 2.5L

P = 1.4 atm

T = 282K

n = ?

Using PV = nRT

n = PV/RT

n = 1.4 × 2.5/0.0821 × 282

n = 3.5/23.1522

n = 0.151mol

Using the formula to calculate molar mass of the elemental gas:

mole = mass/molar mass

Molar mass = mass/mole

Molar mass = 4.23g ÷ 0.151mol

Molar mass = 27.98g/mol

The gravitational pull of the Sun keeps them in their orbits. The gravitational pull of the Sun and surrounding stars combined is most likely what gives the Oort cloud its spherical shape.

The Oort Cloud is a spherical layer of ice objects that is thought to be located between 2,000 and 100,000 astronomical units (AU) from our Sun, a star.

The Oort cloud, so named after the Dutch astronomer Jan Oort who first confirmed its existence, is a collection of objects with a combined mass estimated to be 10-100 times that of Earth that are less than 100 km (60 miles) across and maybe trillions in number.

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Answer:

Option B: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .

pH = 2 because [H⁺] = 1×10¯² M

Explanation:

To know which option is correct, we shall determine the pH of the 0.010 M HClO₄ solution. This can be obtained as follow:

We'll begin by calculating the concentration of the hydrogen ion [H⁺] in the solution. This is illustrated below:

HClO₄ is a strong acid and will dessociates as follow:

HClO₄ (aq) —> H⁺ (aq) + ClO₄¯ (aq)

From the balanced equation above,

1 mole of HClO₄ produced 1 mole H⁺.

Therefore, 0.010 M HClO₄ will also produce 0.010 M H⁺.

Finally we shall determine the pH of the solution. This can be obtained as follow:

Concentration of the hydrogen ion [H⁺] = 0.010 = 1×10¯² M

pH =?

pH = –Log [H⁺]

pH = –Log 1×10¯²

pH = 2

Thus,

The pH = 2

because,

[H⁺] = 1×10¯² M

Thus, option B gives the correct answer to the question.

Based on the definition of pH, pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.

The pH of a solution is the negative logarithm of the hydrogen ion concentration of a solution.

pH of a solution is a measure of the acidity of the solution.

where

For the 0.010 M solution of HClO4, [H+} = 0.01 M

pH = -log(0.01)

pH = 2.00

Therefore,  pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.

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Answer:

pH = 10.95

Explanation:

To solve this question we must, as first, find pKb of dimethylamine. Then, using H-H equation we can solve the pH of the buffer:

pKb dimethylamine:

Based on the equilibrium:

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH2⁺(aq) + OH-(aq)

Kb is defined as:

Kb = [OH-] [(CH3)2NH2⁺] / [(CH3)2NH]

Both (CH3)2NH2⁺(aq) + OH- comes from the same equilibrium, that means:

[OH-] = [(CH3)2NH2⁺]

And: [(CH3)2NH] = 0.457M

[OH-] can be obtained from pH as follows:

14 -pH = pOH

14-12.2 = 1.8 =pOH

10^-pOH = [OH-] = 0.01585M

Replacing:

Kb = [0.01585M] [(0.01585M] / [0.457M]

Kb = 5.50x10⁻⁴

pKb = -logkb = 3.26

pH of the buffer:

Using H-H equation for bases:

pOH = pKb + log [conjugate acid] / [weak base]

pOH = 3.26 + log [0.280M] / [0.457M]

pOH = 3.05

pH = 14 - pOH

Answer:

The moon

Explanation:

The answer is A; Sorry i put the wrong answer by accident. I was trying to get to another question.

Give the answer below brainliest!!!

A. The moon influences the air movement

Answer:

C. Base.

Explanation:

Hello there!

In this case, according to the given information, it turns out convenient for us to realize that the concept acid and base we should use here is based off the Bronsted-Lowry one, which says that an acid is a hydrogen donor. In such a way, since water accepts one H ion as it goes to H3O⁺, we infer it is C. Base and the H2S the acid.

Also, we can tell HS⁻ is the conjugate base and H3O⁺ the conjugate acid.

Regards!

Answer:

The answers are in the explanation.

Explanation:

The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:

Increasing temperature of ice from -10°C - 0°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g

Q = 2.06J/g°C*10°C*10g

Q = 206J

Change from solid to liquid:

The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:

Q = 333.55J/g*10g

Q = 3335.5J

Increasing temperature of liquid water from 0°C - 100°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g

Q = 4.18J/g°C*100°C*10g

Q = 4180J

Change from liquid to gas:

The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:

Q = 2260J/g*10g

Q = 22600J

Increasing temperature of gas water from 100°C - 120°C:

Q = S*ΔT*m

Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g

Q = 1.87J/g°C*20°C*10g

Q = 374J

Total Energy:

206J + 3335.5 J + 4180J + 22600J + 374J =

30695.5J =

30.7kJ

Answer: The pressure exerted by the [tex]CO_2[/tex] gas, in atm is 1.092

Explanation:

According to the ideal gas equation:'

[tex]PV=nRT[/tex]

P = Pressure of the gas = ?

V= Volume of the gas  

T= Temperature of the gas = [tex]22.165^0C=(273+22.165)K=295.165K[/tex]  (0°C = 273 K)

n= moles of gas =  [tex]\frac{\text {given mass}}{\text {Molar mass}}[/tex]

R= Value of gas constant = 0.0821 Latm/K mol

[tex]P=\frac{mRT}{MV}[/tex]       as [tex]Density=\frac{mass}{Volume}[/tex]

[tex]P=\frac{dRT}{M}[/tex]    where d is density

[tex]P=\frac{1.983g/L\times 0.0821Latm/Kmol\times 295.165K}{44g/mol}=1.092atm[/tex]

Thus  pressure exerted by the [tex]CO_2[/tex] gas, in atm is 1.092

Answer:

m = 4.58 g.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:

[tex]PV=nRT[/tex]

As we can calculate the moles of propane given the pressure, temperature and volume as shown below:

[tex]n=\frac{PV}{RT} \\\\n=\frac{1.10atm*2.00L}{0.08206\frac{atm*L}{mol*K}*258K} \\\\n=0.104mol[/tex]

Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:

[tex]m=0.104mol*\frac{44.1g}{1mol}\\\\m= 4.58g[/tex]

Regards!

Answer:

ummm u ok?

Explanation: