According to the ideal gas law, pressure will rise as a gas's temperature rises. There is a limit to how much the tire can expand before the rubber gives in to the pressure build-up.
What the principles of Kinetic Molecular Theory?For every 10 degrees that the temperature drops, the inflation pressure in tires typically decreases by 1 to 2 psi. Moreover, as the tire pressure heats up during the first 15 to 20 minutes of driving, it will increase by one psi every five minutes.
The ideal gas law states that pressure will increase as a gas's temperature increases. Before the rubber gives in to the pressure build up, the tire can only expand so far.
Therefore, The pressure in your tires will increase due to the increased particle movement in hot air, which will cause the centre of the tread to bow out and wear out first. Increasing the demand for new tires.
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How much force will a 5 kg rock hit the Earth with if it falls
for 1 second?
Answer:
f
Explanation:
f
A-10A twin-jet close-support airplane is approximately rectangular with a wingspan (the length perpendicular to the flow direction) of 17.5 m and a chord (the length parallel to the flow direction) of 3 m. The airplane is flying at standard sea level with a velocity of 200 m/s. If the flow is considered to be completely laminar, calculate the boundary layer thickness at the trailing edge and the total skin friction drag. Assume that the wing is approximated by a flat plate. Assume incompressible flow.
Solution :
Given :
Rectangular wingspan
Length,L = 17.5 m
Chord, c = 3 m
Free stream velocity of flow, [tex]$V_{\infty}$[/tex] = 200 m/s
Given that the flow is laminar.
[tex]$Re_L=\frac{\rho V L}{\mu _{\infty}}$[/tex]
[tex]$=\frac{1.225 \times 200 \times 3}{1.789 \times 10^{-5}}$[/tex]
[tex]$= 4.10 \times 10^7$[/tex]
So boundary layer thickness,
[tex]$\delta_{L} = \frac{5.2 L}{\sqrt{Re_L}}$[/tex]
[tex]$\delta_{L} = \frac{5.2 \times 3}{\sqrt{4.1 \times 10^7}}$[/tex]
= 0.0024 m
The dynamic pressure, [tex]$q_{\infty} =\frac{1}{2} \rho V^2_{\infty}$[/tex]
[tex]$ =\frac{1}{2} \times 1.225 \times 200^2$[/tex]
[tex]$=2.45 \times 10^4 \ N/m^2$[/tex]
The skin friction drag co-efficient is given by
[tex]$C_f = \frac{1.328}{\sqrt{Re_L}}$[/tex]
[tex]$=\frac{1.328}{\sqrt{4.1 \times 10^7}}$[/tex]
= 0.00021
[tex]$D_{skinfriction} = \frac{1}{2} \rho V^2_{\infty}S C_f$[/tex]
[tex]$=\frac{1}{2} \times 1.225 \times 200^2 \times 17.5 \times 3 \times 0.00021$[/tex]
= 270 N
Therefore the net drag = 270 x 2
= 540 N
Two loudspeakers, A and B are driven by the same amplifier and emit sinusoidal waves in phase. Speaker B is 2.00 m to the right of speaker A. The frequency of the sound waves produced by the loudspeakers is 206 Hz. Consider a point P between the speakers and along the line connecting them, a distance x to the right of A. Both speakers emit sound waves that travel directly from the speaker to point P. For what values of x will:
a. destructive interference occur at P
b. constructive interference occur at P
Answer:
a) 0, ±1.65 b) ± 0.825m
Explanation:
This is a sound interference exercise, it can be described by the path difference between the two waves
for the case of constructive interference
Δr = 2n λ/ 2 n = 0, 1, 2 ...
for the case of destructive interference
Δr = (2n + 1) λ/ 2
the speed of sound is related to the wavelength
v = λ f
λ = v / f
λ= 340/206
λ = 1.65 m
let's set a reference system in the center between the two speakers
a) let's find the distances for constructive interference
Δr = 2n 1.65 / 2
Δr = 1.65 n
* the first interference occurs at n = 0
Δr = 0
therefore the interference in the center is maximum
* n = 1
Dr = 1.65 m
the second inference occurs at 1.65 m from the center, therefore there is a right wing and a left wing,
We do not have any more interference between the speakers because
n = 2 Δr = 3.3m this distance can be from the speaker
b) let's look for the destructive interference points
Δr = (2n + 1) 1.65 / 2
Δr = (2n + 1) 0.825
m = 0 Δr = 0.825m
m = 1 Δr = 2,475m
We can see that we only have the first destructive interference, one on each side.
Two forces are exerted on an object in the vertical direction: a 20 N force downward and a 10 N force upward. The mass of the object is 25 kg. (1) What are some possibilities about the motion of this object? (2) Represent the motion of the object with a force diagram and a motion diagram.
Answer:
They are equal.
Explanation:
A particle moves along the x-axis according to the equation (x=14-7t+t^2+t^3 ), where (x) in meter and (t) in seconds. At (t=7 sec) Find (a) The position of the particle (b) It’s velocity (c) It’s acceleration
Answer:
jjnn ok jjjmkkmmkijnnkko
An ideal heat engine operates between 778 K and 475 K. 267 J of waste heat is exhausted. What is the input heat?
Answer:
Explanation:
Suppose that the turbines of a coal-fired plant are driven by hot gases at a temperature of 886 K. the temperature of the exhaust area is only 305 K, the efficiency of this heat engine
Assuming the speed of sound is 340 m/s, what is the most likely speed of the jet shown below?
Well we know it has to be greater than 300,000 km/s since we can't see it.
We can't calculate it any closer than that using the given information.
A dropped ball gains speed because
its nature is to become closer to Earth,
its velocity changes.
a gravitational force acts on it
Of inertia
Answer:
3 and 3 and 3
Explanation:
I am sure Hope for brain list
on both sides.
F
10cm
2cm
(2 marks)
(a)
a
State the type of the lens in the box and explain your answer.
Answer:
please put pic of the questions
What is the magnitude of the electric field strength between them, if the potential 7.05 cm from the zero volt plate (and 2.95 cm from the other) is 293 V?
Answer:
E = 4156.02 Vm⁻¹
Explanation:
The magnitude of the uniform electric field between the plates can be given by the following formula:
[tex]E = \frac{\Delta V}{d}\\[/tex]
where,
E = Electric field strength = ?
ΔV = Potetial Difference = 293 V
d = distance between plates = 7.05 cm = 0.0705 m
Therefore,
[tex]E = \frac{293\ V}{0.0705\ m}\\\\[/tex]
E = 4156.02 Vm⁻¹
Calculate the magnitude of the gravitational force exerted by Mercury on a 70 kg human standing on the surface of Mercury. (The mass of Mercury is 3.31023 kg and its radius is 2.4106 m.)
Answer:
2.66×10⁻⁹ N.
Explanation:
From the question,
Applying newton's law of universal gravitation,
Fg = GMm/r²............................... Equation 1
Where Fg = gravitational force, G = universal constant, M = mass of the mercury, m = mass of the human, r = radius of Mercury
Given: M = 3.31023 kg, M = 70 kg, r = 2.4106
Constant: G = 6.67×10⁻¹¹ Nm²/kg²
Substitute these values into equation 1
Fg = 6.67×10⁻¹¹(70×3.31023)/(2.4106²)
Fg = 2.66×10⁻⁹ N.
A 40.0-kg packing case is initially at rest on the floor of a 1500-kg pickup truck. The coefficient of static friction between the case and the truck floor is 0.30, and the coefficient of kinetic friction is 0.20. Before each acceleration given below, the truck is traveling due north at constant speed. Find the magnitude and direction of the friction force acting on the case
(a) when the truck accelerates at 2.20m/s22.20m/s 2 northward and
(b) when it accelerates at 3.40m/s23.40m/s 2 southward.
Answer:
Before providing an answer to the question, the values for acceleration given in questions A and B were written twice. So correction would go like this: For (a) when the truck accelerates at 2.20m/s2 northward, and for (b) when it accelerates at 3.40m/s2 southward.
The answer:
(a) 88N, northward.
(b) 78.4, southward.
Explanation:
(a) Maximum frictional force acting on the packing case= (coefficient of static friction) X (Normal force)
Normal force = mass X acceleration due to gravity
Maximum static frictional force acting on the packing case = (coefficient of static friction) X (mass of packing case X acceleration due to gravity)
Maximum static frictional force = (0.30) X (40.0-kg) X (9.8m/s 2) = 117.6N
While Reaction force acting on the packing case = (mass of packing case) x (acceleration generated by the pickup truck)
Reaction force acting on the case = (40.0-kg) X (2.20m/s2) = 88N
With these values, one can conclude that the packing case is at rest since the reaction force of the case acting in the opposite direction is lesser than the frictional force. Making the magnitude and direction of the friction force acting on the case still move northward, and the static frictional force acting on equals the reaction force.
The answer is 88N, northward.
(b) Here too, we need to still compare the reaction force with the value of the already determined Maximum static frictional force (117.6N) above. This is necessary to know the frictional force between the pickup truck"s floor and the packing case.
Reaction force acting on the case when acceleration is 3.40m/s2 = (40.0-kg) X (3.40m/s2) = 136 N
We can conclude that the reaction force (136 N) is greater than the maximum static frictional force (117.6N), suggesting that the packing case is in motion and the frictional force is no longer static.
This means a kinetic force is now acting on the pickup truck"s floor causing the packing case to also move. This kinetic force can be calculated as:
kinetic force = (coefficient of kinetic friction) X (mass of packing case X acceleration due to gravity)
= (0,20) X (40.0-kg) X (9.8m/s 2) = 78.4N
Which statement is correct?
A. If the electric field is zero everywhere inside a region of space, the potential must also be zero in that region.
B. When the electric field is zero at a point, the potential must also be zero there.
C. If the electrical potential in a region is constant, the electric field must be zero everywhere in that region.
D. If the electric potential at a point in space is zero, then the electric field at that point must also be zero.
Answer:
The answer is "Choice C ".
Explanation:
The relationship between the E and V can be defined as follows:
[tex]\to E= -\Delta V[/tex]
Let,
[tex]\to E= \frac{\delta V}{\delta x}[/tex]
When E=0
[tex]\to \frac{\delta V}{\delta x}=0[/tex]
v is a constant value
Therefore, In the electric potential in a region is a constant value then the electric-field must be into zero that is everywhere in the given region, that's why in this question the "choice c" is correct.
if a car travels 200 m to the east in 8.0 s what is the cars average velocity?
Answer:
25 m/s
Explanation:
200/8 = 25
what was Thomas Edison first major invented?
Answer:
Thomas Edisons most famous invention was the phonograph
Thomas Edison announces his invention of the phonograph, a way to record and play back sound. Edison stumbled on one of his great inventions—the phonograph—while working on a way to record telephone communication at his laboratory in Menlo Park, New Jersey.
Explanation:
Hope I helped
A student carries a backpack for one mile. Another student carries the same backpack for two miles
Compared to the first student, how much work did the second student do?
Answer:
Compared to the first student, the second student did twice as much work as the first student.
Explanation:
The work done by the first student will be equal to the Force exerted by the backpack on the student carrying it multiplied by one mile (Distance). The work done by the second student will be equal to the Force exerted by the backpack on the student carrying it multiplied by two miles (Distance).
Can any wan help pls
Answer:
b
Explanation:
because of bonds and the bowl is used for heating purpose
Answer:
I think b not sure but I hope its right and is that the nwea test??
Use the worked example above to help you solve this problem. The amount of charge that passes through a filament of a certain lightbulb in 2.09 s is 1.56 C. (a) Find the current in the bulb. A (b) Find the number of electrons that pass through the filament in 5.24 s. electrons (c) If the current is supplied by a 12.0-V battery, what total energy is delivered to the lightbulb filament
Answer:
a) i = 0.746 A, b) # _electron = 2.44 10¹⁹ electrons, c) E = 1.87 10⁴ J
Explanation:
a) The definition of current is the charge per unit of time
i = Q / t
i = 1.56 / 2.09
i = 0.746 A
b) Let's look for the cargo in passing at this time
i = Q / t
Q = i t
Q = 0.746 5.24
Q = 3.904 C
an electron has a charge e = -1.6 10⁻¹⁹ C, let's use a direct proportions rule
# _electron = 3.904 C (1 electron / 1.6 10⁻¹⁹)
# _electron = 2.44 10¹⁹ electrons
the number of electrons has to be an integer
c) In this part you are asked to calculate the power
P = V i
P = 12 0.746
P = 8.952 W
P = E/t
E = P t
E = 8.952 2.09
E = 1.87 10⁴ J
A solar panel is used to collect energy from the sun and change it into other forms of energy. The picture below shows some solar panels on the roof of a building. Which form of energy to collected by the solar panels?
A. Wind
B. sound
C. Magnetic
D. Light
What two air masses creates hurricanes?
Answer:
The warm seas create a large humid air mass. The warm air rises and forms a low pressure cell, known as a tropical depression.
Explanation:
Hurricanes arise in the tropical latitudes (between 10 degrees and 25 degrees N) in summer and autumn when sea surface temperature are 28 degrees C (82 degrees F) or higher.
Answer:
air
Explanation:
A boy of mass 60 kg is sledding down a 70 m slope starting from rest. The slope is angled at 15° below the horizontal. After going 20 m along the slope he passes his friend of mass 50 kg, who jumps on the sled. They now move together to the bottom of the slope. The coefficient of kinetic friction between the sled and the snow is 0.12. Ignoring the mass of the sled, find their speed at the bottom.
Pls help me I’m failing
Answer:
A is the answer okkkkkkkkkkkkkkkk
Assume all of the resistors in the following circuits have a value of 5 ohms. Which ammeter will have the highest
reading?
Answer:
Circuit B
Explanation:
To know the correct answer to the question, we shall determine the reading of the ammeter i.e the current in each circuit. This can be obtained as follow:
For circuit A:
Resistance (R) = 5 ohms
Voltage (V) = 1.5 V
Current (I) =?
V = IR
1.5 = I × 5
Divide both side by 5
I = 1.5 / 5
I = 0.3 A
For circuit B:
We'll begin by calculating the total resistance in the circuit. This can be obtained as follow:
Resistance 1 (R₁) = 5 ohms
Resistance 2 (R₂) = 5 ohms
Total resistance (Rₜ) =?
Since they are in parallel connections, the total resistance can be obtained as illustrated below:
Rₜ = R₁ × R₂ / R₁ + R₂
Rₜ = 5 × 5 / 5 + 5
Rₜ = 25 / 10
Rₜ = 2.5 ohms
Finally, we shall determine the current in the circuit.
Resistance (R) = 2.5 ohms
Voltage (V) = 1.5 V
Current =?
V = IR
1.5 = I × 2.5
Divide both side by 2.5
I = 1.5 / 2.5
I = 0.6 A
For circuit C:
We'll begin by calculating the total resistance in the circuit. This can be obtained as follow:
Resistance 1 (R₁) = 5 ohms
Resistance 2 (R₂) = 5 ohms
Total resistance (Rₜ) =?
Since they are in series connections, the total resistance can be obtained as illustrated below:
Rₜ = R₁ + R₂
Rₜ = 5 + 5
Rₜ = 10 ohms
Finally, we shall determine the current in the circuit.
Resistance (R) = 10 ohms
Voltage (V) = 1.5 V
Current =?
V = IR
1.5 = I × 10
Divide both side by 10
I = 1.5 / 10
I = 0.15 A
SUMMARY:
Circuit >>>>>>> Current
A >>>>>>>>>>>> 0.3 A
B >>>>>>>>>>>> 0.6 A
C >>>>>>>>>>>> 0.15 A
from the above calculations, circuit B has the highest ammeter reading.
Cloudy days tend to have a greater range of temperatures than clear days. True or false?
Answer:
true
Explanation:
Answer:
true
Explanation:
A beam of light, incident on a flat water surface, reflects from the mirror-like surface so that the angle of incidence equals the angle of reflection. The water has waves. Would individual light beams obey the law of reflection in this case?
Answer:
a protractor
Explanation:
because protractors measure angles
The variable ______________ describes how quickly something moves.
it's up in Gogle trust me
How much work must be done to raise a 1100kg car 2m above the ground?
Answer:
21560 J
Explanation:
Work = mg*h = 1100*9.8*2 = 21560 J
21560 J work must be done to raise an 1100 kg car 2m above the ground.
Work = mass * gravity * height
= 1100 * 9.8 * 2
= 21560 J
What is work done?In precis, work is carried out whilst pressure acts upon an item to purpose a displacement. 3 portions must be regarded in the way to calculate the quantity of work. The ones 3 portions are force, displacement, and the perspective between the pressure and the displacement.
Paints carried out are elaborated in this type of manner that includes both forces exerted on the body and the whole displacement of the body. This block is preceded by a steady force F. The purpose of this pressure is to move the body a certain distance d in an immediate route in the route of the pressure.
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Show two data points from your simulation that demonstrate this behavior.
I1 V1 I2= 2I1 V2=2V1 V1/ I1 =V2/I2
For the light bulb, why is it better to take more measurements in the range 20mA < I < 40mA, instead of just taking equally spaced measurements in the entire range of 0 mA < I< 55mA
Answer:
hello your question is incomplete attached below is the complete and the required circuit diagrams
answer :
Ai) This proves that when the current across the resistor is doubled the value of the voltage across the resistor doubles as well
B) It is better to take more measurements in the range 20mA < I < 40mA because of the amount of temperature reached by the bulb and the change in resistance is affected by the temperature
hence At 0 mA current, there won't be any noticeable change
Explanation:
Ai) The voltage across the resistor will double when you double the current through the resistor
Given that : V = I*R.
lets assume : I = 2 amperes , R = 3 ohms
V = 2*3 = 6 v
secondly lets assume double the value of (I) i.e. I = 4 amperes
hence : V = 4*3 = 12 volts
This proves that when the current across the resistor is doubled the value of the voltage across the resistor doubles as well
Aii) Showing the two data points from simulation
I1 V1 I2= 2I1 V2=2V1 V1/ I1 =V2/I2
0.9*10^3 9 * 10^3 1.8*10^3 18*10^3 10 ohms
1.6 * 10^3 16 * 10^3 3.2*10^3 32*10^3 10 ohms
B) It is better to take more measurements in the range 20mA < I < 40mA because of the amount of temperature reached by the bulb and the change in resistance is affected by the temperature
hence At 0 mA current, there won't be any noticeable change
A garbage truck and a minivan are moving at the same velocity.
Which automobile will have greater momentum and why? Explain your response using Newton’s second law of motion specifically.
If the garbage truck and minivan in Part A get into an accident with each other, how can safety restraints in a car can save a life? Explain your response using one of Newton’s laws.
Which of Newton’s laws of motion act upon the vehicles at the point of impact? Explain your answer.
Answer:
Part A
Newton's second law of motion states that the force applied to an object is directly proportional to the rate of change of momentum that is produced
Mathematically, we have;
F = m·v - m·u/Δt
Where;
m = The mass of the object
v = The final velocity of the object
u = The initial velocity of the object
Δt = The duration of motion of the object during change in velocity
Therefore, given that the mass, 'M', of the truck is larger than the mass, 'm', of the minivan, where the time of change in velocity Δt, and the initial and final velocities of both automobiles are the same such as in a sudden stop, the garbage ruck will exert more force than the minivan, and therefore, the garbage truck has a greater initial momentum before the automobiles are brought to a stop
Part B;
According to Newton's first law of motion, we have;
The use of a seat belt (and airbag for front seated passengers) will prevent dashboard or windscreen for the front passengers or the front seat for the passengers in the back, from being the item that stops the continued forward motion of the passengers in the car, which can lead to injury
Part C; The Newton's law of motion that act on a body at the point of impact is Newton's third law of motion, which states that the action and reaction are equal and opposite
Therefore, the action of the garbage truck on the minivan upon impact is equal to the reaction of the minivan to the force the garbage truck exerts on the minivan
Explanation:
2. Using a giant screw, a crew does 650 J of work to drill a hole into a rock.
The screw does 65 J of work. What is the efficiency of the screw? Show your
work. Hellpppp
Answer:
42,250
Explanation:
It goes inside=
Displacemt
It does work=
Work done
To find efficiency of jule we do=
Dicplacement × Work done
650 × 65
42,250
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