aluminium has bigger atomic size than chlorine
because atomic radii decreases across the period and increases down the group
this law would hold owing to the fact that chlorine and aluminum are on the same period
Bromine, a brick red liquid, has a density of 3.12 g/mL at room temperature. What is the mass of 25.6 mL of bromine?
Answer:
3.12 x 25.6 = 79.9 g
9.When two protons combine to form one nucleus, the result is one proton and one
neutron. How did the one proton become a neutron?
Answer:
josephmelichar
Explanation:
In the first step, 2 protons combine. In doing so one of the protons will convert into a neutron by losing a positron (positive electron) and a neutrino; this is also known as beta decay. This changes one of the protons (positive charge) into a neutron (neutral charge) and allows the two particles to combine.
Which of the following is the BEST description of a budget? *
10
Answer:
A budget is an estimation of revenue and expenses over a specified future period of time and is usually compiled and re-evaluated on a periodic basis. Budgets can be made for a person, a group of people, a business, a government, or just about anything else that makes and spends money.
An unknown solution has a pH of 6.8. Which of these chemicals is likely to increase the pH the most when added to the solution? (5 points)
a
NaOH
b
HCl
c
NH3
d
HNO3
Answer:
NaOH
Explanation:
An unknown solution has a pH of 6.8. The chemical that will increase the pH is NaOH. The correct option is a.
What are acid and bases?
Acids have lower pH, and they are sour and bases have high pH, and they are bitter in taste.
HCl, NH3, HNO3 are all acids and acid decrease the pH. Only NaOH is a base, and it will increase the pH.
Thus, the correct option is a. NaOH.
Learn more about acid and bases
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How many moles of silver chloride, produced from 100 g of silver nitrate reacting with barium chloride BaCl2?
Answer:
Equation of Reaction
2AgNO3 + BaCl2 === 2AgCl + Ba(NO3)2
Molar Mass of AgNO3 = 170g/mol
Moles of reacting AgNO3 = 100g/170gmol-¹
=0.588moles of AgNO3
From the equation of reaction...2moles of AgNO3 reacts to Produce 2Moles of Silver Chloride
So Their ratio is 2:2.
This means that 0.588Moles of AgCl Will be produced too.
ANSWER...0.588MOLES OF AgCl WILL BE PRODUCED.
Which 2 minerals are present in mafic igneous rock but not found
in felsic igneous rocks?
Answer: Mafic rocks are dominated by plagioclase and pyroxene (even if you can't see them with the naked eye) and smaller amounts of olivine. Intermediate rocks are roughly even mixtures of felsic minerals (mainly plagioclase) and mafic minerals (mainly hornblende, pyroxene, and/or biotite). There is little or no quartz.
HOPE THIS HELPS
An organic compound has the molecular formula C8H16O4. What is the empirical formula of the compound?
Answer:
C₂H₄O
Explanation:
Empirical formulas show the simplest ratio of atoms in a compound in whole numbers.
We can think that all the atoms are divisible by 4.
As we need the lowest number for each subscript, empirical formula is:
C₂H₄O
We have divided, 8/4 for carbon, 16/4 for H and 4/4 for O.
The empirical formula is also known as the simplest expression to represent a chemical
Please help I need the answer now!!!
Answer:
The answer is A: (more below)
Liquid A: Neutral
Liquid B: Acid
Liquid C: Base
Explanation:
Ph scale: 1 - 6 are acids, 7 is neutral, 8 - 14 are bases.
14
13
12
11
10
9
8
7
6
5
4
3
2
1
How much energy is contained in the six-cookie serving size recommended on the label?
Monounsaturated Fat 1g
In volcanic areas, groundwater heated by magma is a source of
a.
lava flows.
b.
silica.
c.
geothermal energy.
d.
pyroclastic flows.
Answer:I believe it is c.
Explanation:
Answer:
C., or "geothermal energy."
A student ran the following reaction in the laboratory at 1080 K: 2SO3(g) 2SO2(g) + O2(g) When she introduced SO3(g) at a pressure of 0.948 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of SO3(g) to be 0.369 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction. Kp =
Answer:
0.078
Explanation:
The equation is :
[tex]$2SO_3 (g) \ \ \ \Leftrightarrow \ \ \ 2 SO_2(g) \ \ \ + \ \ \ O_2(g)$[/tex]
Initial 0.948 ----- ----
Change -2x +2x +x
Final 0.369 2x x
So the total pressure must reman same = 0.948
And the total pressure = partial pressure of all gases
0.948 = ( 0.369 + 2x + x )
0.948 = 0.369 + 3x
[tex]$x=\frac{0.579}{3}$[/tex]
= 0.193 atm
So the partial pressure of [tex]$SO_2$[/tex] = 0.193 x 2
= 0.386 atm
Partial pressure of [tex]$O_2$[/tex] = 0.193 atm
Therefore,
[tex]$k_p=\frac{(P_{SO_2})^2(P_{O_2})^}{(P_{SO_3})^2}$[/tex]
[tex]$=\frac{(0.386)^2(0.193)}{0.369}$[/tex]
= 0.078
write down the balanced chemical equation of the reaction that takes place between iron and concentrated sulphuric acid
Answer:
2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2
Explanation:
Iron is a metallic element with chemical symbol, Fe while concentrated sulphuric acid is a chemical compound with chemical formula, H2SO4. Both are involved in a chemical reaction as follows:
Fe + H2SO4 → Fe2(SO4)3 + H2
However, this reaction is not balanced as the number of moles of each atom in both the reactants and product side is not equal. To balance the equation, we have to ensure that each number of atom is equal. The balanced equation are as follows:
2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2
What is sound? it is a form of energy produced by ____________.
A. conduction C. convection
B. radiation D. vibration
Answer:
D
Explanation:
sound is produced when the matter vibrates
Answer:
D
Explanation:
the sound that is made is basically energy. This energy we call it vibration
Give an example to illustrate the difference between "paying more in taxes ” and paying a higher tax rate .
What weather causes an anticyclone?
Answer:
In summer, anticyclones bring dry, hot weather. In winter, clear skies may bring cold nights and frost. In cold conditions, anticyclones may also bring fog and mist. This is because the cold forces moisture in the air to condense at low altitudes.
Answer:
an anticyclone is an area of high pressure that brings fine setteled weather. in an anticyclone the air is decending which means it is trapped on the ground and cannot rise, therefore we don't get rain!
Explanation:
What volume of a 1.08M KI solution would contain 0.642 moles of KI?
Answer: Volume is 0.594 litres
Explanation: Amount of moles = volume · concentration
n = Vc and V = n/c = 0.642 mol / 1.08 mol/l = 0,59344.. l
80.0 mL of oxygen gas was collected when the temperature was
20.0°C. How many milliliters will the oxygen occupy if the
temperature changes to 54.0°C?
A. 1200 mL
B. 216 mL
C. 71.7 ml
D. 89.3 mL
(Please show your work)
Answer:
89.3 mL
Explanation:
First we convert 20.0 °C and 54.0 °C to K:
20.0 °C + 273.16 = 293.16 K54.0 °C + 273.16 = 327.16 KWith the absolute temperatures we can solve this problem by using Charles' law:
T₁V₂=T₂V₁Where in this case:
T₁ = 293.16 KV₂ = ?T₂ = 327.16 KV₁ = 80.0 mLWe input the data:
293.16 K * V₂ = 327.16 K * 80.0 mLAnd solve for V₂:
V₂ = 89.3 mLNeed help ASAP!
How many moles of sodium nitrate are in 0.25 L of 1.2 M NaNO3 solution?
Answer:
[tex]\boxed {\boxed {\sf 0.3 \ mol \ NaNO_3}}[/tex]
Explanation:
Molarity is a measure of concentration in moles per liter.
[tex]molarity= \frac{moles \ of \ solute}{liters \ of \ solution}[/tex]
The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.
molarity= 1.2 mol NaNO₃/L liters of solution=0.25 L moles of solute =x[tex]1.2 \ mol \ NaNO_3/L= \frac{x}{0.25 \ L}[/tex]
We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.
[tex]0.25 \ L *1.2 \ mol \ NaNO_3/L=\frac{x}{0.25 \ L} *0.25 \ L[/tex]
[tex]0.25 \ L *1.2 \ mol \ NaNO_3/L=x[/tex]
The units of liters cancel, so we are left with the units moles of sodium nitrate.
[tex]0.25 *1.2 \ mol \ NaNO_3=x[/tex]
[tex]0.3 \ mol \ NaNO_3=x[/tex]
There are 0.3 moles of sodium nitrate.
A sample of gas has an initial pressure of 1.5 atm, an initial volume of 3.0 L, and an initial temperature of 293K. If the final pressure is 2.5 atm and the final
temperature is 303K, what will the final volume be?
Answer:
1.9 L
Explanation:
Step 1: Given data
Initial pressure (P₁): 1.5 atmInitial volume (V₁): 3.0 LInitial temperature (T₁): 293 KFinal pressure (P₂): 2.5 atmFinal volume (V₂): ?Final temperature (T₂): 303 KStep 2: Calculate the final volume of the gas
If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂ / T₁ × P₂
V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L
influnza meaning in one word
Mixed Practice:
For questions 6-9, you may not have to use your entire flow chart. Decide where to start and end using your flow chart.
4NH3 + 5O2 → 4NO + 6H2O
MM NH3 = 17.04 g/mol; MM O2 = 32 g/mol; MM NO = 30.01 g/mol; MM H2O = 18.02 g/mol
In the above reaction, how many moles of NO are formed if 824 g of NH3 react?
27.5 mol
3510 mol
48.4 mol
774 mol
Given
Mass of NO - 824 g
Molar mass of NO - 30.01g/mol
No of moles of NO = Given mass/Molar mass
No of moles of NO = 824/30.01= 27.45 mole
Hence 27.5 moles of NO are formed!
Which is the best description of a cyclone?
a dust storm
rapidly changing weather in an area
a type of tornado
an area of low air pressure
What is the mass of 564 liters of oxygen in kilograms?
Aluminum oxide forms when 3.50 moles of aluminum is combined with
3.00 moles of oxygen. What is the excess reagent? Al + O2 - ALO3
(unbalanced) *
A - oxygen
B - aluminum
C - aluminum oxide
Explanation:
Correct option is
B
18
As reaction for the formation of Al 2
is as follows:
4Al+3O
2
→Al 2
O
this shows that 4 mol reacts to 3 mol ( 96 g) of O
2
so as 3 mol O
2
to 4 mol Al
then 0.5 mol O 2 to 3, 4
×0.5=0.66 mol of Al
as 1 mol Al = 27 g
then 0.66 mol of Al=0.66×27=17.9 g≈18 g
Hence, the correct option is B.
how many grams of CO2 will be produced from 39 grams of C3H8 and 11 grams of O2
Answer:
Equation: C3H8 + 5O2 = 3CO2 + 4H2O (already balanced)
a) If you start with 14.8 g of C3H8 and 3.44 g of O2, determine the limiting reagant
b) Determine the number of moles of carbon dioxide produced
c) Determine the number of grams of H2O produced
d) Determine the number of grams of excess reagant left
What element in group 1 is not considered an alkali metal?
A. Hydrogen (H)
B. Lithium (Li)
C. Potassium (K)
D. Cesium (Cs)
Answer:
A
Explanation:
Hydrogen isn't an alkali metal
Answer:
hydrogen
Explanation:
hydrogen is a gas not a metal
13. Which of the following is NOT characteristic of metals?
Use the diagram above to answer the question. Each of the containers shown above holds a 1L volume. Which container has the
greatest number of gas molecules? Assume all containers are at the
same temperature. *
(Look at the picture)
А
B
С
D
(Explain why is this the correct answer)
Option A is correct.
This is because atoms get compressed when the pressure increases and takes less space, on the other hand, the atoms get expanded when pressure decreases and hence take more space.
A particle that has the electron configuration 1s²2s²2p³ would:
Have 2 filled orbitals and 3 partially filled orbitals.
Be able to bond with 2 hydrogens.
Have an electron configuration of a noble gas.
Have the electron configuration of an alkali earth metal.
Answer:
Have 2 filled orbitals and 3 partially filled orbitals.
Explanation:
Hello there!
In this case, according to the given information of the electron configuration for that particle; it is possible for us to infer it has 5 valence electrons, as the electrons on its outermost shell (2). Moreover, we undertand this particle needs three bonds, does not have neither the electron configuration of a noble gas which ends by p⁶ nor that of an alkali earth metal as it ends by s².
Therefore, we infer the correct answer is Have 2 filled orbitals and 3 partially filled orbitals because according to the Hund's rule, the s orbital is fulfilled and the p orbital has 1 electron orbital fulfilled and two partially filled orbitals.
Regards!
How many grams of NiNi are formed from 55.3 g of Ni2O3?
2Ni2O3(s)⟶4Ni(s)+3O2(g)
Answer:
39.2 g
Explanation:
2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)
First we convert 55.3 g of Ni₂O₃ into moles, using its molar mass:
55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃
Then we convert 0.334 Ni₂O₃ moles into Ni moles, using the stoichiometric coefficients of the balanced reaction:
0.334 mol Ni₂O₃ * [tex]\frac{4molNi}{2molNi_2O_3}[/tex] = 0.668 mol Ni
Finally we convert 0.668 Ni moles into grams, using its molar mass:
0.668 mol * 58.69 g/mol = 39.2 g