Answer:
The answer is "the angle depends on wavelength and distance of slits".
Explanation:
[tex]d \sin \theta = m\lambda[/tex] as well as angular, of mth order darkened border is indicated only by angular position, the [tex]\theta[/tex] mth order bright border generated by a light wavelength [tex]\lambda[/tex] , and use the grating of the segregation slit.
[tex]d \sin \theta = ( m + \frac{1}{2}) \lambda[/tex]
Therefore, [tex]\theta[/tex] depends on d and [tex]\lambda[/tex] for a specific order.
how do people in your community deal with loud sound
Answer: Nothing they mind thier own business instead of being really noisy.
Explanation
Now if someone was screaming they probley would go investagate investigate but something else nah.
A ball with a mass of 0.585 kg is initially at rest. It is struck by a second ball having a mass of 0.420 kg , initially moving with a velocity of 0.270 m/s toward the right along the x axis. After the collision, the 0.420 kg ball has a velocity of 0.220 m/s at an angle of 36.9 ∘ above the x axis in the first quadrant. Both balls move on a frictionless, horizontal surface.
Required:
a. What is the magnitude of the velocity of the 0.605kg ball after the collision?
b. What is the direction of the velocity of the 0.605kg ball after the collision?
c. What is the change in the total kinetic energy of the two balls as a result of the collision?
Answer:
a) [tex](v_1)=0.3989m/s[/tex]
b) [tex]\theta_1=80.5 \textdegree[/tex]
c) [tex]K.E=0.036J[/tex]
Explanation:
From the question we are told that:
Initial speed of 1st ball [tex]u_{1}=0 m/s[/tex]
Mass of 1st ball [tex]m_1=0.585kg[/tex]
Mass of 2nd ball [tex]m_2=0.420kg[/tex]
Initial speed of 2nd ball [tex]u_{2}=0.270 m/s[/tex]
Final speed of 2nd ball [tex]v_{2}=0.220 m/s[/tex]
Angle of collision [tex]\angle=36.9 \textdegree[/tex]
a)
Generally the equation for law of conservation is mathematically given by
[tex]m_1u_1+m_2u_2=m_1v_1^2+m_2v_2^2[/tex]
The final velocity [tex]v_1[/tex] is given as
[tex]0+(0.420)(0.270)=(0.585)(v_1)^2+(0.420)(0.220)^2[/tex]
[tex](v_1)^2=\frac{(0.420)(0.270)-(0.420)(0.220)^2}{0.585}[/tex]
[tex](v_1)^2=0.1591[/tex]
[tex](v_1)=0.3989m/s[/tex]
b)
Generally the equation for law of conservation is mathematically given by
[tex]m_1u_1+m_2u_2=m_1v_1cos\theta_1+m_2\theta_2[/tex]
[tex]0+(0.420)(0.270)=(0.585)(1.511)cos\theta_1+(0.420)(0.220)cos36 \textdegree[/tex]
[tex]cos\theta_1= \frac{(0.420)(0.270)-(0.420)(0.220)cos36 \textdegree}{(0.585)(0.3989)}[/tex]
[tex]cos\theta_1=0.1656[/tex]
[tex]\theta_1=80.5 \textdegree[/tex]
c)
Generally the equation for kinetic energy is mathematically given by
[tex]K.E=\frac{1}{2} mv^2[/tex]
1st Ball
[tex]K.E=\frac{1}{2} (0.585)(0.3989)^2[/tex]
[tex]K.E=0.0465J[/tex]
2nd ball
[tex]K.E=\frac{1}{2} (0.420)(0.220)^2[/tex]
[tex]K.E=0.101J[/tex]
Therefore the change in the total kinetic energy of the two balls as a result of the collision is
[tex]0.101-0.0465[/tex]
[tex]K.E=0.036J[/tex]
How much current is drawn by a television
with a resistance of 43 Ω that is connected
across a potential difference of 112 V?
Answer in units of A.
Answer:
Explanation:
v = ir
v/r = i
112/43 = i
2.60 ≈ i
Two 6 ohm resistors in parallel gives an equivalent resistance of
1/Req = 1/R1 + 1/R2 + 1/R3...
3 ohm
6 ohms
9 ohms
12 ohms
Answer:
3 ohms
Explanation:
6×6/6+6 =3 .............
Car headlights have both low beams and high beams. The high beams may be necessary when it is very dark outside. If the power for the high beam is 60.0 watts and the current is 5.0 amps, how much voltage is required?
A.
65 volts
B.
0.088 volts
C.
12 volts
D.
55 volts
Answer:
Voltage, V = 12 V.
Explanation :
It is given that,
The power for the high beam is, P = 60.0 watts
Current flowing, I = 5 A
Car headlights have both low beams and high beams. The high beams may be necessary when it is very dark outside.
So, the voltage required for the high beam is 12 V.
The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c, space-dock personnel measure the rocket ship to be 43.3 m long. Part A The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?
Complete question:
Part A:) The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c , space-dock personnel measure the rocket ship to be 43.3 m long. The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?
Part B: What is the momentum of a proton traveling at 0.62 c ?
Answer
a)Who would have aged less=The Captain would have aged less
b) [tex]p=3.96*10^{-19}kgm/s[/tex]
Explanation:
From the question we are told that
Length measured by captain [tex]l_c=50m[/tex]
Speed of rocket past tje space dock [tex]V=0.5c[/tex]
Length measured by space-dock personnel [tex]l_c=43.3m[/tex]
a)
Generally time moves slower when moving at speed of light, due to time dilation or variation.
Who would have aged less=The Captain would have aged less
b)
Generally the equation for Relativistic Momentum is mathematically given as
[tex]p=\frac{m*v}{1 - v^2/c^2}[/tex]
[tex]p=\frac{1.67*10^2-27*0.62*3.0*10^8)}{\sqrt{ 1 -0.6^2}}[/tex]
[tex]p=3.96*10^{-19}kgm/s[/tex]
The light waves transfer their oscillations and energy to other object in what way?
The frequency of the light waves physically causes the object to move
The energy of the light wave transfers to the electrons of the material which causes them to gain that energy
The wavelength of the light changes the velocity of the atoms in the material
The amplitude of the light will affect how much of it shines on the object
Answer: b the energy of light...
Explanation:
Which situation will change the direction of the bicycle?
A. An added force of 20 N down the hill
B. Added forces of 30 N up the hill and 30 N down the hill
C. An added force of 20 N to the side of the hill
D. Added forces of 10 N up the hill and 30 N down the hill
Answer:
Dont know if this is right but i say C
Explanation:
Answer:
C. an added force of 20 N toward one side of the hill
Explanation:
I just took the quiz and got it correct./
Which of the following is an example of a noncontrolled substance?
A. Sleeping pills
B. Coffee
C. Pain medications
D. Cough medications
SUBMIT
An example of noncontrolled substance from the option is Cough medications.
What are Noncontrolled substances?Noncontrolled substances are substances that are prescribed by medical personnel or pharmaceutical professionals for treatment of a disorder or ailments that is affecting a person.
Noncontrolled substances include medications that are majorly prescribed for treatment of medical conditions like high blood pressure, diabetes, and bacterial infections.
Therefore, An example of noncontrolled substance from the option is Cough medications.
Learn more about noncontrolled substances below.
https://brainly.com/question/5349491
Jupiter's Great Red Spot is
1.slowly shrinking
2.a large storm
3.smaller than Saturn's spot
4.a large area of liquid hydrogen
Answer:
2 : A large storm
Explanation: I hope this helps
2. A 0.02 kg ball spins in a horizontal circle of radius 0.50 m with a frequency
of 4.0 Hz. What is the tension force in the string (the centripetal force on
the ball)?
Given:
Frequency, f = 4.0 HzMass, m = 0.02 kgRadius, r = 0.50 mWe know,
→ [tex]W = 2 \pi f[/tex]
By substituting the values,
[tex]= 2 \pi \times 4.0[/tex]
[tex]= 8 \pi \ rad/s[/tex]
hence,
→ [tex]T = m \omega^2 R[/tex]
[tex]= 0.02(8 \pi)^2 (0.50)[/tex]
[tex]= 6.31654 \ N[/tex]
or,
[tex]= 6.3 \ N[/tex]
Thus the answer above is right.
Learn more about tension force here:
https://brainly.com/question/13047328
What is the speed of a 1.57 N bullet traveling with a total momentum equal to 131 Kg.m/s?
Answer:
https://web.njit.edu/~binchen/phys111/LectureNotes/Physics111_lecture08.pdf
Explanation:it's 38 slides so look at the more bottom ones and there will be your question and answer
Wind turbines continue to generate energy even when there isn't any wind.
O True
O False
A uniform 40-N board supports two children weighing 500 N and 350 N. If the support is at the center of the board and the 500-N child is 1.5 m from its center, How far is the 350-N child from the center
Determine the upward force exerted on the board?
Answer:
2.14 m
Explanation:
2.14m if it is write thank me hitting the heart ❤️ I took a lot of time to solve
An old shade-tree mechanic trick for removing a stubborn bolt is to slip a long pipe over the handle of the wrench, then apply a force to the end of the pipe opposite the bolt.
Why is this effective? What problems might this technique cause?
Answer: long pipe is used to increase torque and reduce force needed.
Explanation: A torque is needed to open bolt. torque = F·r, if
R increases, Force F needed to open bold is smaller.
Problem is a worn bolt may break down. It sometimes I send useful to heat bolt instead using too much power.
A typical electric refrigerator has a power rating of 500 Watts, which is the rate (J/s) at which electrical energy is supplied to do work needed to remove heat from the refrigerator. If the refrigerator releases heat to the room at a rate of 800 Watts, at what rate (in Watts) does it remove heat from inside of the refrigerator?
Answer:
The rate of heat removed from inside the refrigerator is 300 watts.
Explanation:
By the First Law of Thermodynamics and the definition of a Refrigeration Cycle, we have the following formula to determine the rate of heat removed from inside the refrigerator ([tex]\dot Q_{L}[/tex]), in watts:
[tex]\dot Q_{L} = \dot Q_{H}-\dot W[/tex] (1)
Where:
[tex]\dot Q_{H}[/tex] - Rate of heat released to the room, in watts.
[tex]\dot W[/tex] - Rate of electric energy needed by the refrigerator, in watts.
If we know that [tex]\dot Q_{H} = 800\,W[/tex] and [tex]\dot W = 500\,W[/tex], then the rate of heat removed from inside the refrigerator is:
[tex]\dot Q_{L} = \dot Q_{H}-\dot W[/tex]
[tex]\dot Q_{L} = 300\,W[/tex]
The rate of heat removed from inside the refrigerator is 300 watts.
A house brick has a volume of 1900 cm³ and a weight in air of 80N.What is its apparent weight in water?The density of water is 1.00 g cm³?
Answer:
61 N
Explanation:
We'll begin by calculating the mass of the brick when placed in water. This can be obtained as follow:
Volume of brick = 1900 cm³
Density of water = 1 g/cm³
Mass of brick in water =…?
Density = mass / volume
1 = mass of brick in water / 1900
Cross multiply
Mass of brick in water = 1 × 1900
Mass of brick in water = 1900 g
Next, we shall convert 1900 g to Kg.
1000 g = 1 Kg
Therefore,
1900 g = 1900 g × 1 Kg / 1000 g
1900 g = 1.9 Kg
Next, we shall determine the weight in water. This can be obtained as follow:
Mass (m) = 1.9 Kg
Acceleration due to gravity (g) = 10 m/s²
Weight (W) =?
W = m × g
W = 1.9 × 10
W = 19 N
Thus, the weight of the brick in water is 19 N.
Finally, we shall determine the apparent weight of the brick in water. This can be obtained as follow:
Weight in air = 80 N
Weight in water = 19 N
Apparent weight =?
Apparent weight = weight in air – weight in water
Apparent weight = 80 – 19
Apparent weight = 61 N
In a direct current motor, what is the result of the magnetic field acting on the wire
Answer:
Because the magnetic field created by the electric current in the wire is changing directions around the wire, it will repel both poles of the magnet by bending away from the wire.
Explanation:
What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?
Answer:
Wavelength = 1.36 * 10^{-34} meters
Explanation:
Given the following data;
Mass = 0.113 kg
Velocity = 43 m/s
To find the wavelength, we would use the De Broglie's wave equation.
Mathematically, it is given by the formula;
[tex] Wavelength = \frac {h}{mv} [/tex]
Where;
h represents Planck’s constant.
m represents the mass of the particle.
v represents the velocity of the particle.
We know that Planck’s constant = 6.6262 * 10^{-34} Js
Substituting into the formula, we have;
[tex] Wavelength = \frac {6.6262 * 10^{-34}}{0.113*43} [/tex]
[tex] Wavelength = \frac {6.6262 * 10^{-34}}{4.859} [/tex]
Wavelength = 1.36 * 10^{-34} meters
Explain What's make up macromolecules?
Answer:
Atoms
Explanation:
Atoms make up everything
Which theory states that the principle cause of forgetting is passage of time? A. motivated forgetting B. retrieval failure C. decay theory D. ineffective encoding
A 1.0-kg object moving 9.0 m/s collides with a 2.0-kg object moving 6.0 m/s in a direction that is perpendicular to the initial direction of motion of the 1.0-kg object. The two masses remain together after the collision, and this composite object then collides with and sticks to a 3.0-kg object. After these collisions, the final composite (6.0-kg) object remains at rest. What was the speed of the 3.0-kg object before the collisions
Answer:
v₃ = - (3 i ^ + 4 j ^) m / s
v₃ = 5 m / s, θ = 233º
Explanation:
This is a momentum problem. Let us form a system formed by the three objects so that the forces during the collisions have been internal and the moment is conserved.
Let's start working with the first two objects. As each object moves in a different direction let's work with the components in an xy coordinate system
X axis
initial instant. Before the shock
p₀ₓ = m₁ v₁₀ + 0
final instant. After the crash
p_{fx} = (m1 + m2) vₓ
the moment is preserved
p₀ₓ = p_{fx}
m₁ v₀₁ = (m₁ + m₂) vₓ
vₓ = [tex]\frac{m_1}{m_1+m_2} \ v_{o1}[/tex]
Y axis
initial instant
p_{oy} = 0 + m₂ v₀₂
final moment
p_{fy} = (m₁ + m₂) v_y
the moment is preserved
p_{oy} = p_{fy}
m₂ v₀₂ = (m₁ + m₂) v_y
v_y = [tex]\frac{m_2}{m_1 +m_2 } \ v_{o2}[/tex]
We already have the speed of the set of these two cars, now let's work on this set and vehicle 3
X axis
initial instant
p₀ₓ = (m₁ + m₂) vₓ + m₃ v₃ₓ
final instant
p_{fx} = 0
p₀ₓ = p_{fx}
(m₁ + m₂) vₓ + m₃ v₃ₓ = 0
v₃ₓ = [tex]- \frac{m_1+m_2 }{m_3} \ v_x[/tex]
Y Axis
initial instant
p_{oy} = (m₁ + m₂) v_y + m₃ v_{3y}
final moment
p_{fy} = 0
p_{oy} = p_{fy}
(m₁ + m₂) v_y + m₃ v_{3y} = 0
v_{3y} = [tex]- \frac{m_1+m_2}{m_3} \ v_y[/tex]
now we substitute the values of the speeds
v₃ₓ = [tex]- \frac{m_1+m_2}{m_3} \ \frac{m_1}{m_1+m_2} \ v_{o1}[/tex]
v₃ₓ = [tex]- \frac{m_1}{m_3} \ v_{o1}[/tex]
v_{3y} = [tex]- \frac{m_1+m_2}{m_3} \ \frac{m_2}{m_1+m_2} \ v_{o2}[/tex]
v_{3y} = [tex]- \frac{m_2}{m_3} \ v_{o2}[/tex]
let's calculate
v₃ₓ = - ⅓ 9
v₃ₓ = - 3 m / s
v_{3y} = - ⅔ 6
v_{3y} = - 4 m / s
therefore the speed of vehicle 3 is
v₃ = - (3 i ^ + 4 j ^) m / s
It can also be given in the form of modulus and angles using the Pythagorean theorem
v₃ = [tex]\sqrt{v_{3x}^2 + v_{3y}^2}[/tex]
v₃ = [tex]\sqrt{3^2+4^2}[/tex]
v₃ = 5 m / s
let's use trigonometry for the angle
tan θ' = [tex]\frac{v_{3y}}{v_{3x}}[/tex]
θ' = tan⁻¹ (\frac{v_{3y}}{v_{3x}})
θ' = tan⁻¹ (4/3)
θ' = 53º
That the two speeds are negative so this angle is in the third quadrant, measured from the positive side of the x axis
θ = 180 + θ'
θ = 180 +53
θ = 233º
solve this with figure.help me ......
[tex] \huge\mathfrak\purple{Hope \: it \: helps}\ [/tex]
A box slides to the right across a horizontal floor. A person called Ted exerts a force T to the right on the box. A person called Mario exerts a force M to the left, which is half as large as the force T. Given that there is friction f and the box accelerates to the right, rank the sizes of these three forces exerted on the box.
a. f < M < T
b. M < f < T
c. M < T < f
d. f = M < T
e. It cannot be determined.
Answer:
a. f < M < T
Explanation:
Let us take the right direction as positive.
Since Ted exerts a force T to the right his force is +T, Mario exerts a force M to the left, his force is -M. It is also given that Mario's force is half of Ted's force, so M = T/2. Finally, the frictional force , f is to the left, so it is -f. Let the net force be F and it is to the right since the box moves to the right.
So, +T - M - f = +F
Substituting M = T/2, we have
+ T -T/2 - f = F
+ T/2 - f = F
+T/2 = F + f
So, T = 2(F + f) and
M = T/2 = F + f
Since T = 2(F +f) = 2M, It follows that T > M
Also, since M = F + f, it follows that M > f
So, T > M > f ⇒ f < M < T
So, the answer is a.
How does mass differ from weight? List 2 differences.
weight is vector vary from place to place
Answer:
The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.
Explanation:
Mass is the measure of the amount of matter in a body. Mass is denoted using m or M. ... Weight is mass multiplied by the acceleration of gravity (g).
A chain is wrapped around pulley and pulled with a force of
16.0N .The pulley has a radius of 0.20 m. The pulley's rotational
speed increases from 0.0 to 17.0 rev/min in 5.00s What is the moment
of inertia of Pulley?
The moment of inertia of Pulley is 8.89 kgm².
Angular acceleration of the pulleyThe angular acceleration of the pulley is calculated as follows;
[tex]\alpha = \frac{\omega_f - \omega _i}{t}[/tex]
where;
ωi is the initial angular velocity = 0 ωf is the final angular velocity = 17 rev/mint is the time of motionFinal angular velocity in radian per second is calculated as
[tex]\omega _f = 17 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 \ s} = 1.78 \ rad/s[/tex]
Now, solve for angular acceleration
[tex]\alpha = \frac{1.78-0}{5} \\\\\alpha = 0.36 \ rad/s^2[/tex]
Moment of inertia of the pulleyThe the moment of inertia of Pulley is determined using the formula for torque.
Iα = Fr
I = Fr/α
I = (16 x 0.2)/(0.36)
I = 8.89 kgm²
Thus, the moment of inertia of Pulley is 8.89 kgm².
Learn more about moment of inertia here: https://brainly.com/question/25803184
Select the correct arrows. Identify the arrows that show the correct direction of heat transfer.
Answer:
Explanation:I Did the test and it said this was the right answer so it probally is
Answer:
That's the question that I wanted to ask!!
Explanation:
The 10-lb block A attains a velocity of 2ft/s in 5 seconds, starting from rest. Determine the tension in the cord and the coefficient of kinetic friction between block A and the horizontal plane. Neglect the weight of the pulley. Block B has a weight of 8 lb. Please work on this by using the principle of linear impulse-momentum
Answer:
Explanation:
Let T be the tension in the cord.
Impulse by cord = change in momentum of block A .
T x 5s = 10 ( 2 -0) = 20
T = 4 poundal .
acceleration of block B = 2 / 5 = 0.4 m /s²
Net force applied on A = m ( g + a ) where m is mass of block B , a is acceleration of block B .
= 8 ( 32 + .4 ) = 259.2 poundal
Frictional force on block A = 259.2 - 4 = 255.2 poundal
μ x 10 x 32 = 255.2
320μ = 255.2
μ =0 .8 .
Calculate the height of a cliff if it takes 2.35s for a rock to hit the ground when it is thrown straight up from the cliff with a initial velocity 8m/s.
Answer:
y₀ = 10.625 m
Explanation:
For this exercise we will use the kinematic relations, where the upward direction is positive.
y = y₀ + v₀ t - ½ g t²
in the exercise they indicate the initial velocity v₀ = 8 m / s.
when the rock reaches the ground its height is zero
0 = y₀ + v₀ t - ½ g t²
y₀i = -v₀ t + ½ g t²
let's calculate
y₀ = - 8 2.5 + ½ 9.8 2.5²
y₀ = 10.625 m
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Explanation:
lol ....you are right.......