what’s.the perimeter of a square with an area of 49 cm2

Answers

Answer 1

Answer:

28

Step-by-step explanation:

Area of a square =

[tex]s^2[/tex]

Perimeter =

[tex]4\times s[/tex]

Where s = side

Solve for s using the area

[tex]A =49\\\\49 = s^2\\\\Square\:root \:both\:sides\:of\:the\:equation\\\\\sqrt{49} = \sqrt{s^2} \\\\7 =s\\\\s =7[/tex]

Find the perimeter

[tex]4\times s\\\\= 4 \times 7\\\\= 28[/tex]


Related Questions

What is the number of solutions in this system?
one solution
no solution
infinitely many solutions
First answer is Brainlyist

Answers

I could answer but u have no picture of the question

Brainliest ?

Find the x-intercept of the graph of the linear equation y = -1/2 x+3.
Help me please!!
Due soon!!

Answers

(6,0) that’s the right answer

Answer:

6

Step-by-step explanation:

got it right

Which one of these shapes is not like the other and why?

Answers

A and B is not, because if you were to make the A bigger it'll be the same as B, so I think is C

The table shown below displays the distance that students on a track team walked during after-school practice.
Student
Distance (Miles)
John
2.75
Paul
2
Sierra
1.4
Anastasia
31
What was the total distance, in miles, that the students walked during after-school practice?

Answers

The total distance should be: 37.15 miles

Explanation:

You just add all of the distances together:
• 2.75 + 2 + 1.4 + 31= 37.15 miles


Anastasia's distance is much different than the others so in case you meant to put 3.1 here is the answer to that:
• 2.75 + 2 + 1.4 + 3.1= 9.25 miles

which sign makes the statement true?

Answers

Answer:

Less than sign

Step-by-step explanation:

3/4 is greater than 3/5 because its 3 out of 4 making it 75% and 3/5 is 60%

Enter the mixed number as a decimal 3 and 1 over 10

Answers

3.1 i think but hopefully that might help

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t) = -4.9t^2 + 148 t + 227. Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? The rocket splashes down after 32 seconds. How high above sea-level does the rocket get at its peak? The rocket peaks at meters above sea-level.

Answers

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

Solve 5x - (2x - 1) = 2, Answer is a decimal round to the hundredth (2 digits) or use / for fraction bar.

Answers

5x - (2x - 1) = 2

Distribute the - sign.

5x - 2x + 1 = 2

Combine like terms.

3x + 1 = 2

Subtract 1 from both sides.

3x = 1

Divide both sides by 3

x = 1/3 or 0.33

4 5 6 7 8 9 10 TIME REMAINING 35:22 Triangle KNM is shown. Triangle K N M is shown. Angle M K N is 25 degrees. Angle K N M is 130 degrees. Angle N M K is 25 degrees. What is true about the sides of KNM? KN = NM KN + NM = KM KM = 2(NM) KN = One-halfKM Mark this and return

Answers

Answer:

KN = NM

Step-by-step explanation:

Given that:

In a triangle KNM

angle ∠ MKN = 25°

angle ∠ KNM = 130°

angle ∠ NMK = 25°

The objective is to determine what is true about the side of KNM.

The correct option is:

KN = NM

From the above, we will see that two angles are equal, which implies the triangle is likely to be an isosceles triangle. An isosceles triangle is a triangle that has two equal angles and sides.

Thus, the intersection of NK with KM is at an angle of 25°, so do NM and KM. We can thereby conclude that the two sides are equal in length provided that they possess the same angles and they intersect at the line at the same angle.

Answer: (A)

Step-by-step explanation: trust me!

What is the translation for this graph? O (X-4, Y-3)
O (X-3. y - 4)
O (X-3. y. 4)
O (X- 4. y-3)

Answers

Answer:

wow dis might take a while to solve

Use function notation to represent the average speed of the car on the interval from t = 2 to t = 7 .

Answers

Answer:

[tex]Average\ Speed = \frac{s(7) - s(2)}{5}[/tex]

Step-by-step explanation:

Given

t = 2 to 7

Required

Find the average speed over these intervals

The function is not given; so, I'll represent the function as s(t)

When [tex]t = 2;[/tex]

[tex]s(t)= s(2)[/tex]

When [tex]t = 7[/tex]

[tex]s(t) = s(7)[/tex]

[tex]Average\ Speed = \frac{Change\ in\ Distance}{Change\ in\ Time}[/tex]

This gives:

[tex]Average\ Speed = \frac{s(7) - s(2)}{7 - 2}[/tex]

[tex]Average\ Speed = \frac{s(7) - s(2)}{5}[/tex]

5.1436 rounded to the nearest tenth

Answers

Answer:

5.1

Step-by-step explanation:

we have

5.1436

since 4 is less than five we cannot pass the 1 to 2

so it stays like

5.1

An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining. A sample of 71 brakes using Compound 1 yields an average brake life of 41,628 miles. A sample of 31 brakes using Compound 2 yields an average brake life of 36,379 miles. Assume the standard deviation of brake life is known to be 4934 miles for brakes made with Compound 1 and 4180 miles for brakes made with Compound 2. Determine the 98% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval.

Answers

Answer:

98%  Confidencce Interval is ( 3030.6, 7467.4 )

Step-by-step explanation:

Given that:

Sample size [tex]n_1 =[/tex] 71

Sample size [tex]n_2 =[/tex] 31

Sample mean [tex]\overline x_1 =[/tex] 41628

Sample mean [tex]x_2 =[/tex] 36,379

Population standard deviation [tex]\sigma_1[/tex] = 4934

Population standard deviation [tex]\sigma_2 =[/tex] 4180

At 98% confidence interval level, the level of significcance = 1 - 0.98 = 0.02

Critical value at [tex]z_{0.02/2} = 2.33[/tex]

The Margin of Error = [tex]z \times \sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2} }[/tex]

= [tex]2.33 \times \sqrt{\dfrac{4934^2}{71}+\dfrac{4180^2}{31} }[/tex]

= [tex]2.33 \times \sqrt{\dfrac{24344356}{71}+\dfrac{17472400}{31} }[/tex]

= [tex]2.33 \times \sqrt{906504.06 }[/tex]

= 2218.40

The Lower limit = [tex]( \overline x_1 - \overline x_2) - (Margin \ of \ error)[/tex]

= ( 41628 - 36379 ) - ( 2218.40)

= 5249 - 2218.40

= 3030.6

The upper limit = [tex]( \overline x_1 - \overline x_2) + (Margin \ of \ error)[/tex]

= ( 41628 - 36379 ) + ( 2218.40)

= 5249 + 2218.40

= 7467.4

∴  98%  Confidencce Interval is ( 3030.6, 7467.4 )

What is one equivalent ratio for 1/3

Answers

Answer: 2/6

Step-by-step explanation:

Answer:

[tex]\frac{2}{6}[/tex]

Step-by-step explanation:

In order to create an equal ratio to [tex]\frac{1}{3}[/tex], we need to find a constant to multiply both the numerator and the denominator by.

Let's do 2.

[tex]1\cdot 2 = 2\\\\3\cdot 2 = 6\\\\[/tex]

So:

[tex]\frac{2}{6}[/tex]

Hope this helped!

Solve the equation t+ 25 =26

Answers

Answer:

t = 1

Step-by-step explanation:

t + 25 = 26

Subtract 25 from each side

t = 1

A store offers customers a 40% discount on the price of x of selected items. Then, the store takes off an additional 16% at the cash register. Write a price function P(x) that computes the final price of the item in terms of the original price x.

P(x) = ?

Answers

Answer:

x-40%-16%

Step-by-step explanation:

For which values of a the system has no solution: x≤5, x≥a

Answers

Given:

The system of inequalities is

[tex]x\leq 5[/tex]

[tex]x\geq a[/tex]

To find:

The values of a for which the system has no solution.

Solution:

We have,

[tex]x\leq 5[/tex]        ...(1)

It means the value of x is less than or equal to 5.

[tex]x\geq a[/tex]        ...(2)

It means the value of x is greater than or equal to a

Using (1) and (2), we get

[tex]a\leq x\leq 5[/tex]

But if a is great than 5, then there is no value of which satisfies this inequality.

Therefore, the system has no solution for a>5.

Crude oil Imports to one country from another for 2009-2013 could be approximated by the following model where t is time in years since the start of 2000,
(1) --33428001 - 1,000 thousand barrels per day (9 st s 13)
According to the model, approximately when were oil imports to the country greatest? HINT (See Example 1) (Round your answer to two decimal places.)
How many barrels per day were imported at that time? (Round your answer to two significant digits.)
thousand barrels

Answers

Answer:

Time = approximately mid 2012Oil import rate = 3600 barrels

Step-by-step explanation:

Unclear part of the questionI(t) = −35t² + 800t − 1,000 thousand barrels per day (9 ≤ t ≤ 13) According to the model, approximately when were oil imports to the country greatest?  t =  ? Solution

Given the quadratic function  

The vertex of a quadratic function is found by a formula: x = -b/2a

As per given function:

b = 800, a = -35

Then

t = - 800/2*(-35) = 11.43 which is within given range of 9 ≤ t ≤ 13

This time is approximately mid 2012.

Considering this in the function, to get oil import rate for the same time:

l(11.43) = -35*(11.43)² + 800*11.43 - 1000 = 3571.4285

Rounded to two significant figures, the greatest oil import rate was:

3600 barrels

help me please. 15 POINTS BRAINLEST ANSWER EVER (y+4)–(y–1)=6y

Answers

Answer:

5/6

Step-by-step explanation:

y+4-y+1=6y

5=6y

y=5/6

Solution for (y+4)-(y-1)=6y equation:

Simplifying

(y + 4) + -1(y + -1) = 6y

Reorder the terms:

(4 + y) + -1(y + -1) = 6y

Remove parenthesis around (4 + y)

4 + y + -1(y + -1) = 6y

Reorder the terms:

4 + y + -1(-1 + y) = 6y

4 + y + (-1 * -1 + y * -1) = 6y

4 + y + (1 + -1y) = 6y

Reorder the terms:

4 + 1 + y + -1y = 6y

Combine like terms: 4 + 1 = 5

5 + y + -1y = 6y

Combine like terms: y + -1y = 0

5 + 0 = 6y

5 = 6y

Solving5 = 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.

5 + -6y = 6y + -6y

Combine like terms: 6y + -6y = 0

5 + -6y = 0

Add '-5' to each side of the equation.

5 + -5 + -6y = 0 + -5

Combine like terms: 5 + -5 = 0

0 + -6y = 0 + -5

-6y = 0 + -5

Combine like terms: 0 + -5 = -5

-6y = -5

Divide each side by '-6'.

y = 0.8333333333

Simplifying

y = 0.8333333333

What is the value of -3.5

Answers

Answer:

[tex]3.5[/tex]

Step-by-step explanation:

The value of [tex]|-3.5|[/tex] is [tex]3.5[/tex], because you have [tex]|-3.5|[/tex] and it will change to [tex]3.5[/tex] by the absolute value, which it turned from negative to a positive.

Help please thanks.

Answers

Answer:

Step-by-step explanation:

[tex]\sqrt{1}[/tex] -2 / 6 = (1-2)/6= -1/6= .2 (rounded to tenth)

whats - 1/64 as cubed

Answers

Answer: 1/4

Step-by-step explanation:

118 meters in 2 seconds, how many meters in 11 seconds?

Answers

Answer:

It would be 649

Step-by-step explanation:

118 ÷ 2= 59

59 x 11= 649

Answer:

649m

Step-by-step explanation:

[tex]\frac{118m}{2s} =\frac{59m}{s}[/tex]

so that 59m/s we multiply by 11s

[tex]\frac{59m}{s} (11s)=649m[/tex]

Point G ia on line segment FH Given FG = 5x + 2 GH = 3x -1 and FH = 9 determine the numerical length of FG

Answers

Answer:

Step-by-step explanation:

FG=7

Given f(x)=3x-1 find f(-1)

Answers

Answer:

f( - 1) = - 4

Step-by-step explanation:

f(x) = 3x - 1

To find f(-1) substitute the value of x that's

- 1 into f(x). That's for every x in f(x) replace it with - 1 and solve

That's

f( - 1) = 3(-1) - 1

= - 3 - 1

We have the final answer as

f(-1) = - 4

Hope this helps you

Can someone do this for me? I will give brainliest!

Answers

Answer:look it up on quizlet

Step-by-step explanation:

A small pebble has a mass of
about
20 L
b.
20 ml
20 g
20 kg
d.

Answers

Answer:

20g

since mass should be in kg or gram if small then g

How hard is 6th grade math?

Answers

Answer:

super easy i can help you whenever

Step-by-step explanation:

im in high and i had As in 6th

Answer:

a little hard you just have to understand it

Step-by-step explanation:

In the diagram of circle A, what is the measure of
ZXYZ?
35°
70°
75°
140°

Answers

Using the intersecting secant theorem:

Angle xyz = 1/2( wz- XX)

Xyz = 1/2(175-105)

Xyz = 1/2(70)

Xyz= 35

The answer is 35 degrees

The measure of <XYZ is 35 degrees

Circle geometry

To find the measure of<XYZ, we will use the expression as shown below:

The angle at the vertex is half the difference of the intercepted arcs

<XYZ = 1/2(175 - 105)

<XYZ = 1/2(70)
<XYZ = 35 degrees

Hence the measure of <XYZ is 35 degrees

Learn more on geometry here: https://brainly.com/question/24375372

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Answers

Answer:

[tex]f_x(x,y,z)=4\sin (y-z)[/tex]

[tex]f_x(x,y,z)=4x\cos (y-z)[/tex]

[tex]f_z(x,y,z)=-4x\cos (y-z)[/tex]

Step-by-step explanation:

The given function is

[tex]f(x,y,z)=4x\sin (y-z)[/tex]

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

[tex]f_x(x,y,z)=4(1)\sin (y-z)[/tex]

[tex]f_x(x,y,z)=4\sin (y-z)[/tex]

Differentiate partially w.r.t. y and x, z are constants.

[tex]f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)[/tex]

[tex]f_y(x,y,z)=4x\cos (y-z)[/tex]

Differentiate partially w.r.t. z and x, y are constants.

[tex]f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)[/tex]

[tex]f_z(x,y,z)=4x\cos (y-z)(-1)[/tex]

[tex]f_z(x,y,z)=-4x\cos (y-z)[/tex]

Therefore, the first partial derivatives of the function are [tex]f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)[/tex].

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