What's simple random sampling? Is it possible to sample data instances using a distribution different from the uniform distribution? If so, give an example of a probability distribution of the data instances that is different from uniform (i.e., equal probability).

Answers

Answer 1

Answer:

The answer is below

Step-by-step explanation:

The procedure of selecting a sample is thus called, fulfilling two fundamental properties:

-All individuals in the population have the same probability of being elected.

-All samples of the same size are equally likely.

From a mathematical point of view, simple random sampling is performed assuming that the population has infinite elements. In practice, it is often the case that the populations to be considered have a very large number of elements, which can be compared to a situation with infinite elements.

Yes, it is possible to sample data instances using a distribution different from the uniform distribution.

In excel, do the following to obtain a sample dataset.

E.g. to create a 5 element sample from the standard normal distribution, place the formula = NORM.S.INV (RAND ()) in cell A1, highlight the range A1: A15 and press Ctrl-D.


Related Questions

Given the following probabilities for an event​ E, find the odds for and against E. ​(A) eight ninths ​(B) seven ninths ​(C) 0.59 ​(D) 0.71

Answers

Answer:

(a) The odds for and against E are (8:1) and (1:8) respectively.

(b) The odds for and against E are (7:2) and (2:7) respectively.

(c) The odds for and against E are (59:41) and (41:59) respectively.

(d) The odds for and against E are (71:29) and (29:71) respectively.

Step-by-step explanation:

The formula for the odds for an events E and against and event E are:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}[/tex]

(a)

The probability of the event E is:

[tex]P(E)=\frac{8}{9}[/tex]

Compute the odds for and against E as follows:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}=\frac{8/9}{1-(8/9)}=\frac{8/9}{1/9}=\frac{8}{1}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}=\frac{1-(8/9)}{8/9}=\frac{1/9}{8/9}=\frac{1}{8}[/tex]

Thus, the odds for and against E are (8:1) and (1:8) respectively.

(b)

The probability of the event E is:

[tex]P(E)=\frac{7}{9}[/tex]

Compute the odds for and against E as follows:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}=\frac{7/9}{1-(7/9)}=\frac{7/9}{2/9}=\frac{7}{2}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}=\frac{1-(7/9)}{7/9}=\frac{2/9}{7/9}=\frac{2}{7}[/tex]

Thus, the odds for and against E are (7:2) and (2:7) respectively.

(c)

The probability of the event E is:

[tex]P(E)=0.59[/tex]

Compute the odds for and against E as follows:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}=\frac{0.59}{1-0.59}=\frac{0.59}{0.41}=\frac{59}{41}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}=\frac{1-0.59}{0.59}=\frac{0.41}{0.59}=\frac{41}{59}[/tex]

Thus, the odds for and against E are (59:41) and (41:59) respectively.

(d)

The probability of the event E is:

[tex]P(E)=0.71[/tex]

Compute the odds for and against E as follows:

[tex]\text{Odds For}=\frac{P(E)}{1-P(E)}=\frac{0.71}{1-0.71}=\frac{0.71}{0.29}=\frac{71}{29}\\\\\text{Odds Against}=\frac{1-P(E)}{P(E)}=\frac{1-0.71}{0.71}=\frac{0.29}{0.71}=\frac{29}{71}[/tex]

Thus, the odds for and against E are (71:29) and (29:71) respectively.

The product of two whole numbers is 1000. If neither of the numbers is a multiple of 10, what is their sum?

Answers

Answer:

133

Step-by-step explanation:

1000 = 2 * 2 * 2 * 5 * 5 * 5

To not have a multiple of 10, you cannot have 2 and 5 as factors of the same number.

One number is 2^3 = 8.

The other number is 5^3 = 125.

8 * 125 = 1000, so the two do multiply to 1000.

Neither 8 nor 125 is a multiple of 10.

8 + 125 = 133

Answer:

133

Step-by-step explanation:

We are given that the product of two numbers is 1000. Let's first list out the factors of 1000 (factors are numbers that evenly divide into 1000):

1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

We see that the pairs are:

(1, 1000)

(2, 500)

(4, 250)

(5, 200)

(8, 125)

(10, 100)

(20, 50)

(25, 40)

An easy way to see if a number is divisible by 1000 is to check is it has a zero at the end. Notice that all of the pairs have at least one number that ends with at least 1 zero except (8, 125), so this is the pair of numbers we're looking for.

The sum is thus 8 + 125 = 133.

~ an aesthetics lover

Me ayudan con esto 63÷X=1.06

Answers

Answer:

[tex]x = \dfrac{3150}{53}[/tex]

[tex] x \approx 59.43 [/tex]

Step-by-step explanation:

[tex] 63 \div x = 1.06 [/tex]

[tex] 63 \div x \times x = 1.06 \times x [/tex]

[tex] \dfrac{1.06x}{1.06} = \dfrac{63}{1.06} [/tex]

[tex] x = \dfrac{6300}{106} [/tex]

[tex]x = \dfrac{3150}{53}[/tex]

[tex] x \approx 59.43 [/tex]

Three polynomials are factored below but some coefficients and constants are missing. all of the missing values of a, b, c and d are integers. 1. x^2 +2x-8=(ax+b)(cx+d) 2. 2x^3+2x^2-24x=2x(ax+b)(cx+d) 3. 6x^2-15x-9=(ax+b)(cx+d) Fill in the table with the missing values of a,b,c and d.

Answers

Answer:

1) d = 42) b = -3. c = 1 3) a = 3 and d = 1

Step-by-step explanation:

To get the missing values in the table, we will factorize the given expression and compare the factored expression with the expression containing the missing constants.

1) For the expression x²+2x-8, on factorizing we have;

x²+2x-8

= (x²+4x)-(2x-8)

Factoring out the common terms from both parenthesis;

= x(x+4)-2(x+4)

= (1x+4)(1x-2)

=  (1x-2)(1x+4)

Comparing the resulting expression with (ax+b)(cx+d)

a = 1, b = -2, c = 1 and d = 4

2) For the expression 2x³+2x²-24x

Factoring out the common term we will have;

= 2x(x²+x-12)

= 2x(x²-3x+4x-12)

= 2x{x(x-3)+4(x-3)}

= 2x{(x+4)(x-3)}

=  2x(1x-3)(1x+4)

Comparing the resulting expression with 2x(ax+b)(cx+d)

a = 1, b = -3. c = 1 and d = 4

3) For the expression 6x²-15x-9 we will have;

On simplifying,

= 6x²+3x-18x-9

= 3x(2x+1)-9(2x+1)

= (3x-9)(2x+1)

Comparing the resulting expression with (ax+b)(cx+d)

a = 3, b = -9, c = 2 and d = 1

Answer:

see picture attachment

Step-by-step explanation:

The​ profit, in thousands of​ dollars, from the sale of x thousand candles can be estimated by ​P(x) = 5 x - 0.7 x ln x.
1) Find the marginal profit, P'(x).
2) Find P'(10), and explain what this number represents. What does P'(10) represent?
A. The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.
B. The additional profit, in thousands of dollars, when 10,000 candles are sold.
C. The additional cost, in thousands of dollars, to produce a thousand candles once 10,000 candles have already been sold.
D The additional cost, in thousands of dollars, to produce 10,000 candles.
C. How many thousands of candles should be sold to maximize profit?

Answers

1) The marginal profit is [tex]4.3 - 0.7 ln(x)[/tex].

2) The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.

Thus, option (A) is correct.

C) To maximize profit 462,481 thousands of candles should be sold.

Given: [tex]P(x) = 5 x - 0.7 x[/tex] [tex]{\text}ln x.[/tex]

1) Take the derivative of the profit function P(x) with respect to x.

P(x) = 5x - 0.7x ln(x)

To find P'(x), differentiate each term separately using the power rule and the derivative of ln(x):

[tex]P'(x) = 5 - 0.7(1 + ln(x))[/tex]

       = [tex]5 - 0.7 - 0.7 ln(x)[/tex]

       = [tex]4.3 - 0.7 ln(x)[/tex]

2) Substitute x = 10 into the derivative:

P'(10) = 4.3 - 0.7 ln(10)

         = 4.3 - 0.7(2.30259)

         = 4.3 - 1.61181

         = 2.68819

Therefore, the additional profit for selling a thousand candles once 10,000 candles have already been sold.

Thus, option (A) is correct.

C) Set P'(x) = 0 and solve for x:

[tex]4.3 - 0.7 ln(x) = 0[/tex]

[tex]0.7 ln(x) = 4.3[/tex]

[tex]{\text} ln(x) = 4.3 / 0.7[/tex]

[tex]{\text} ln(x) = 6.14286[/tex]

[tex]x = e^{6.14286[/tex]

[tex]x = 462.481[/tex]

Therefore, 462,481 thousands of candles should be sold.

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1) The marginal profit, P'(x), is -0.7ln(x) + 4.3.

2) The number of thousands of candles that should be sold to maximize profit is approximately 466.9.

1) To find the marginal profit, P'(x), we need to take the derivative of the profit function, P(x), with respect to x. Using the power rule and the chain rule, we can differentiate the function:

P(x) = 5x - 0.7x ln(x)

Taking the derivative with respect to x:

P'(x) = 5 - 0.7(ln(x) + 1)

Simplifying:

P'(x) = 5 - 0.7ln(x) - 0.7

P'(x) = -0.7ln(x) + 4.3

2) To find P'(10), we substitute x = 10 into the marginal profit function:

P'(10) = -0.7ln(10) + 4.3

Using a calculator, we can evaluate this expression:

P'(10) ≈ -0.7(2.3026) + 4.3 ≈ -1.6118 + 4.3 ≈ 2.6882

The value of P'(10) is approximately 2.6882.

Now, let's interpret what P'(10) represents:

The correct interpretation is A. The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.

P'(10) represents the rate at which the profit is changing with respect to the number of candles sold when 10,000 candles have already been sold. In other words, it measures the additional profit (in thousands of dollars) for each additional thousand candles sold once 10,000 candles have already been sold.

Lastly, to determine the number of thousands of candles that should be sold to maximize profit, we need to find the critical points of the profit function P(x). This can be done by setting the derivative P'(x) equal to zero and solving for x.

-0.7ln(x) + 4.3 = 0

-0.7ln(x) = -4.3

ln(x) = 4.3 / 0.7

Using properties of logarithms:

x = e^(4.3 / 0.7)

Using a calculator, we can evaluate this expression:

x ≈ e^(6.1429) ≈ 466.9

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Choose the name of the highlighted part of the figure.
O A.
side
OB.
Vertex
O c. angle

Answers

Where is the figure to chose from ?

A man starts at a point A and walks 18 feet north. He then turns and walks due east at 18 feet per second. If a searchlight placed at A follows him, at what rate is the light turning 3 seconds after he started walking east

Answers

Answer:

1/10 per sec

Step-by-step explanation:

When he's walked x feet in the eastward direction, the angle Θ that the search light makes has tangent

tanΘ = x/18

Taking the derivative with respect to time

sec²Θ dΘ/dt = 1/18 dx/dt.

He's walking at a rate of 18 ft/sec, so dx/dt = 18.

After 3seconds,

Speed = distance/time

18ft/sec =distance/3secs

x = 18 ft/sec (3 sec)

= 54ft. At this moment

tanΘ = 54/18

= 3

sec²Θ = 1 + tan²Θ

1 + 3² = 1+9

= 10

So at this moment

10 dΘ/dt = (1/18ft) 18 ft/sec = 1

10dΘ/dt = 1

dΘ/dt = 1/10 per sec

At 1/10 per second is the rate when the light turns 3 seconds after he started walking east.

It is given that a man starts at point A and walks 18 feet north. He then turns and walks due east at 18 feet per second.

It is required to find at what rate is the light turning 3 seconds after he started walking east.

What is the trigonometric ratio?

The trigonometric ratio is defined as the ratio of the pair of a right-angled triangle.

The [tex]\rm tan\theta[/tex] is the ratio of the perpendicular to the base.

When he started walking eastward direction, the searchlight makes an angle [tex]\theta[/tex]

Let the distance is x

And the  [tex]\rm tan\theta = \frac{x}{18}[/tex]

After performing the derivate with respect to time, we get:

[tex]\rm sec^2\theta\frac{d\theta}{dt} = \frac{1}{18} \frac{dx}{dt}[/tex] ...(1)    ( the differentiation of [tex]\rm tan\theta \ is \ sec^2\theta\\[/tex])

He walking at the rate of 18 ft per second ie.

[tex]\rm \frac{dx}{dt} = 18[/tex]  

After 3 seconds  [tex]\rm Speed=\frac{Distance}{Time}[/tex]

By using speed- time formula we can calculate the distance:

Distance x = 18×3 ⇒ 54 ft.

[tex]\rm tan\theta = \frac{54}{18}[/tex]  ⇒3

We know that:

[tex]\rm sec^2\theta = 1+tan^2\theta[/tex]

[tex]\rm sec^2\theta = 1+3^2\\\\\rm sec^2\theta = 10\\[/tex]

Put this value in the (1) equation, we get:

[tex]\rm 10\frac{d\theta}{dt} = \frac{1}{18} \times18[/tex]    ∵ [tex]\rm (\frac{dx}{dt} =18)[/tex]

[tex]\rm 10\frac{d\theta}{dt} = 1\\\\\rm \frac{d\theta}{dt} = \frac{1}{10} \\\\[/tex]per second.

Thus, at 1/10 per second what rate is the light turning 3 seconds after he started walking east.

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Triangler prisms help

Answers

Answer:

1. 60 in cubed.

2. 36 m cubed.

3. 96 m cubed.

4. 60 yds cubed.

5. 120 in cubed.

Step-by-step explanation:

Alright, we need to know what the formula is for the volume of a triangular prism. Before that, here is the formula to find the volume of all shapes. Some formulas may be different for cones, spheres, and pyramids, but this is the general formula.

The formula is V=Bh.

V is your volume

B is the area of the base

h is the height of the prism..

The formula for calculating the volume for a triangular prism is 1/2bh times h. 1/2bh is the formula for finding the area of your triangle which is the base shape for a triangular prism. The other h is the height of your prism.

For number 1, they already calculated the area of the base for you, so just multiply that number with the height. 20 times 3 is 60.

That is 60 meters cubed.

Number 2, they haven't calculated the area of the base, so you have to do that. The length of the triangle is 4 and the height of the triangle is 3. Lets find the area of the triangle or the base, Do 4 times 3 which is 12 and divide it by 2 or multiply it by half. it is the same thing. You get 6, and that is the area of your base. Multiply that area by the height of the prism. You get 36 meters cubed. The reason why it is cubed is because meter times meter times meter is meter cubed.

Hope this helps!

The length of a rectangle is four times its width.
If the perimeter of the rectangle is 70 ft, find its area.

Answers

Answer:

196 ft^2

Step-by-step explanation:

4(w) = L

2w + 2L = 70

2w + 2(4w) = 70

10w = 70

w = 7

4(7) = 28

Area = 28*7

Area = 196

Answer:

The area of the rectangle is 196 ft^2.

Step-by-step explanation:

Looking for: Area

The length of a rectangle is four times its width can be translated into

l = 4w

Perimeter = 2w + 2l

2w + 2(4w) = 70

2w + 8w = 70

10w = 70

w = 7

l = 4w

l= 4(7)

l=28

Area = l times w

28 times 7 = 196

The area of the rectangle is 196 ft^2.

"A researcher wants to test if the mean G.P.A. of CC students transferring to Sac State is above 3.3. She randomly samples 25 CC students and finds that their average G.P.A. is 3.45. Assuming that the standard deviation of G.P.A.’s is 0.5, what can the researcher conclude at the 5% significance level

Answers

Answer:

We failed to reject H₀

t < 2.06

1.5 < 2.06

We do not have significant evidence at significance level α=0.05 to show that the mean G.P.A. of CC students transferring to Sac State is above 3.3

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: μ = 3.3

Alternate hypotheses = H₁: μ > 3.3

Determine type of test:

Since the alternate hypothesis states that mean G.P.A. of CC students transferring to Sac State is above 3.3, therefore we will use a upper-tailed test.

Select the test statistic:  

Since the sample size is very small (n < 30) therefore, we will use t-distribution.

Determine level of significance and critical value:

Given level of significance = 5% = 0.05

Since it is a upper tailed test,

At α = 0.05 and DF = n – 1 =  25 - 1 = 24

t-score =  2.06

Set up decision rule:

Since it is a upper tailed test, using a t statistic at a significance level of 5%

We Reject H₀ if t > 2.06

Compute the test statistic:

[tex]$ t = \frac{\bar{x}-\mu}{\frac{s}{\sqrt{n} } } $[/tex]

[tex]$ t = \frac{ 3.45- 3.3 }{\frac{0.5}{\sqrt{25} } } $[/tex]

[tex]t = 1.5[/tex]

Conclusion:

We failed to reject H₀

t < 2.06

1.5 < 2.06

We do not have significant evidence at significance level α=0.05 to show that the mean G.P.A. of CC students transferring to Sac State is above 3.3

What is the simplified value of this expression pls help

Answers

Answer:

7

Step-by-step explanation:

Remove parentheses.

[tex]\frac{-8+4(4.5)}{6.25-8.25} \\[/tex]

Add −8 and 4.5.

[tex]\frac{4(-3.5)}{6.25 - 8.25} \\\\[/tex]

Subtract 8.25 from 6.25.

[tex]\frac{4*-3.5}{-2}[/tex]

Multiply 4 by −3.5.

[tex]\frac{-14}{-2}[/tex]

Divide −14 by −2.

= 7

Given h(x)=5x-5, find h(2)

Answers

Answer:

5

Step-by-step explanation:

h(2)=5(2)-5

5 x 2 = 10

10 - 5 = 5

The value of the function h(x) = 5x - 5 at x = 2 will be 5.

What is the value of the expression?

When the relevant factors and natural laws of a mathematical model are given values, the outcome of the calculation it describes is the expression's outcome.

The function is given below.

h(x) = 5x - 5

Then the value of the function at x = 2 will be

h(2) = 5 (2) - 5

h(2) = 10 - 5

h(2) = 5

The value of the function h(x) = 5x - 5 at x = 2 will be 5.

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Neil places £2000 in a bank account that pays 1.5% simple interest per year.How much interest will he earn in 6 years?

Answers

Answer:

£ 180

Solution,

Principal( P)= £ 2000

Rate (R)= 1.5%= 1.5/100

Time (t)= 6 years

Interest=?

Now,

[tex]interest = principal \times rate \times time \\ \: \: \: \: = 2000 \times \frac{1.5}{100} \times 6 \\ \: \: = 180[/tex]

Therefore, he will earn £ 180 in 6 years.

Hope this helps..

Good luck on your assignment..

180The answer is 180 the formula to calculate simple interest is:Interest= principal * rate * time

Suppose f(x)=x^2 and g(x) =7x^2 which statement best compares the graph of g(x) with the graph f(x)

Answers

Answer:

The graph g(x) is the graph f(x) vertically stretched by a factor of 7.

Step-by-step explanation:

Quadratic Equation: f(x) = a(bx - h)² + k

Since we are modifying the variable a, we are dealing with vertical stretch (a > 1) or vertical shrink (a < 1). Since a > 1 (7 > 1), we are dealing with a vertical stretch by a factor of 7.

Answer:

The graph g(x) is the graph f(x) vertically stretched by a factor of 7.

Step-by-step explanation:

Quadratic Equation: f(x) = a(bx - h)² + k

Since we are modifying the variable a, we are dealing with vertical stretch (a > 1) or vertical shrink (a < 1). Since a > 1 (7 > 1), we are dealing with a vertical stretch by a factor of 7.

ABCD is a rectangle. Rectangle A B C D is shown. All angles are right angles. The length of A D is 5 and the length of D C is 12. Use the diagram to answer the questions. The length of AB is 12 . The length of BC is 5 . The length of AC is .

Answers

Answer: 13

Step-by-step explanation:

I used Pythagorean theorem to solve this problem. As DC and AD is 12 and 5, you would do 12²+5²= c². 12²= 144 and 5²= 25. 144+25= 169. It doesn't end there. Do the square root of 169 ---> √169=13.

Given that ABCD is a rectangle, if a diagonal line cuts from A to C make a two equal right angled triangles, the hypotenuse which is the length of AC is 13.

What is a rectangle?

A rectangle is a 2-dimensional shape with parallel opposite sides equal to each other and four angles are right angles.

What is Pythagorean theorem?

Pythagorean theorem states that the "square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides.

It is expressed as;

c = √( a² + b² )

Given the data in the question;

Length AB and DC = 12Length AD and BC = 5

Let line AC be the hypotenuse as it cuts the rectangle into two equal right angled triangle.

From Pythagorean theorem.

c = √( a² + b² )

AC = √( AB² + BC² )

AC = √( 12² + 5² )

AC = √( 144 + 15 )

AC = √169

AC = 13

Therefore, given that ABCD is a rectangle, if a diagonal line cuts from A to C make a two equal right angled triangles, the hypotenuse which is the length of AC is 13.

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check my answer before I submit please!!

What similarity theorem justifies ABC-YZX

I chose SSS Similarity Theorem

Answers

Answer:

It is AA

Step-by-step explanation:

They didn't mention anything about sides but thay said that the triangles have 2 similar angles so it AA theorem

Calculate the slope of a line passing through point A at (2, 1) and point B at (4, 2). Calculate to one decimal place.

Answers

Answer

m = 1/2

Explanation

Gradient is calculated by:

Change in y/change in x

2-1/4-2 = 1/2

Answer: 0.5

Step-by-step explanation:

To find the slope of a line with two given points, you use the formula [tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex].

[tex]m=\frac{2-1}{4-2}=\frac{1}{2}=0.5[/tex]

The slope is 0.5.

Which can be the first step in finding the equation of the line that passes through the points (5,-4) and (-1, 8) in slope-intercept form?

Answers

Answer:

(8-(-4)/(-1-5)

Step-by-step explanation:

You have to find what the slope is first to get m.

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10). Match each quadrilateral, described by its vertices, to the sequence of transformations that will show it is congruent to quadrilateral JKLM. W(5,1), X(1,7), Y(9,9), and Z(11,7) O(10,1), P(6,7), Q(14,9), and R(16,7) S(4, 16), T(10, 20), U(12, 12), and V(10, 10) A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10) E(5,6), F(1,12), G(9,14), and H(11,12) a translation 2 units right and 3 units down arrowRight a translation 3 units left and 2 units up arrowRight a translation 3 units down and 3 units left arrowRight a sequence of reflections across the x- and y-axes, in any order arrowRight

Answers

Answer:

See Explanation

Step-by-step explanation:

Given:

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).

(a)If we translate  quadrilateral JKLM 3 units down and 3 units left:

(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)

Therefore, we match it with: A translation 3 units down and 3 units left

(b)If we translate  quadrilateral JKLM 2 units right and 3 units down:

(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)

Therefore, we match it with:A translation 2 units right and 3 units down

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:

A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)

(d)If we translate  quadrilateral JKLM 3 units left and 2 units up:

(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)

Therefore, we match it with: A translation 3 units left and 2 units up

(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

No suitable transformation is found from JKLM to STUV.

Answer:

a translation 3 units down and 3 units left

W(5,1), X(1,7), Y(9,9), and Z(11,7)

a translation 2 units right and 3 units down

O(10,1), P(6,7), Q(14,9), and R(16,7)

a sequence of reflections across the

x- and y-axes, in any order

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

a translation 3 units left and 2 units up

E(5,6), F(1,12), G(9,14), and H(11,12)

I need help I don’t understand

Answers

Answer:

6

Step-by-step explanation:

you have to distributw the 4 to the 1/4 so essentially youre multiplying the exponents. think of it as 4*1/4 and youll have 4/4 which equals to 1. 6^1 is just 6 so thats the answer

well first you have to multiply 6 by 1/4 and then you have to do this: 1.5*1.5*1.5*1.5 to get your answer i think....

Help please! Simplify 7/ √x

Answers

Answer:

[tex]\frac{7\sqrt{x} }{x}[/tex]

Step-by-step explanation:

To simplify 7/√x, we need to rationalize:

[tex]\frac{7}{\sqrt{x} } (\frac{\sqrt{x} }{\sqrt{x} } )[/tex]

When we multiply the 2, we should get our answer:

[tex]\frac{7\sqrt{x} }{x}[/tex]

Answer:

[tex]\frac{7\sqrt{x} }{x}[/tex]

Step-by-step explanation:

[tex]\frac{7}{\sqrt{x} } \\\\\frac{7}{\sqrt{x} } * \frac{\sqrt{x} }{\sqrt{x} } \\\\\frac{7\sqrt{x} }{\sqrt{x\sqrt{x} } } \\[/tex]

[tex]\frac{7\sqrt{x} }{x}[/tex]

Hope this helps! :)

In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz at all, and decides to randomly guess the answers. Find the probabilities of each of the following events:

a. The first question she gets right is the 3rd question?
b. She gets exactly 3 or exactly 4 questions right?
c. She gets the majority of the questions right?

Answers

Answer:

a [tex]\mathbf{P(X=3)=0.1406}[/tex]

b [tex]\mathbf{\[P\left( {X = 3 \ or \ 4 } \right) = 0.1025}[/tex]

c  [tex]\mathbf{\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = 0.1035}[/tex]

Step-by-step explanation:

Given that:

In a multiple choice quiz:

there are 5 questions

and 4 choices for each question (a, b, c, d)

let X be the correctly answered question = 1 answer only

and Y be the choices for each question = 4 choices

The probability that Robin guessed the correct answer is:

Probability = n(X)/n(Y)

Probability = 1//4

Probability = 0.25

The probability mass function is :

[tex]P(X=x)=0.25 (1-0.25)^{x-1}[/tex]

We are to find the required probability that the first question she gets right is the 3rd question.

i.e when x = 3

[tex]P(X=3)=0.25 (1-0.25)^{3-1}[/tex]

[tex]P(X=3)=0.25 (0.75)^{2}[/tex]

[tex]\mathbf{P(X=3)=0.1406}[/tex]

b) Find the probability that  She gets exactly 3 or exactly 4 questions right

we know that :

n = 5 questions

Probability P =0.25

Let represent X to be the number of questions guessed correctly i,e 3 or 4

Then; the probability mass function can be written as:

[tex]\[P\left( {X = x} \right) = \left( {\begin{array}{*{20}{c}}\\5\\\\x\\\end{array}} \right){\left( {0.25} \right)^x}{\left( {1 - 0.25} \right)^{5 - x}}\][/tex]

[tex]P(X = 3 \ or \ 4)= P(X =3) +P(X =4)[/tex]

[tex]\[P\left( {X = 3 \ or \ 4 } \right) = \left( {\begin{array}{*{20}{c}}\\5\\\\3\\\end{array}} \right){\left( {0.25} \right)^3}{\left( {1 - 0.25} \right)^{5 - 3}}\] + \left( {\begin{array}{*{20}{c}}\\5\\\\4\\\end{array}} \right){\left( {0.25} \right)^4}{\left( {1 - 0.25} \right)^{5 - 4}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 } \right) = \dfrac{5!}{3!(5-3)!}\right){\left( {0.25} \right)^3}{\left( {1 - 0.25} \right)^{5 - 3}}\] + \dfrac{5!}{4!(5-4)!} \right){\left( {0.25} \right)^4}{\left( {1 - 0.25} \right)^{5 - 4}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 } \right) = \dfrac{5!}{3!(2)!}\right){\left( {0.25} \right)^3}{\left( {0.75} \right)^{2}}\] + \dfrac{5!}{4!(1)!} \right){\left( {0.25} \right)^4}{\left( {0.75} \right)^{1}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 } \right) = 0.0879+0.0146[/tex]

[tex]\mathbf{\[P\left( {X = 3 \ or \ 4 } \right) = 0.1025}[/tex]

c) Find the probability if She gets the majority of the questions right.

We know that the probability mass function is :

[tex]\[P\left( {X = x} \right) = \left( {\begin{array}{*{20}{c}}\\5\\\\x\\\end{array}} \right){\left( {0.25} \right)^x}{\left( {1 - 0.25} \right)^{5 - x}}\][/tex]

So; of She gets majority of her answers right ; we have:

The required probability is,

[tex]P(X>2) = P(X=3) +P(X=4) + P(X=5)[/tex]

[tex]\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = \left( {\begin{array}{*{20}{c}}\\5\\\\3\\\end{array}} \right){\left( {0.25} \right)^3}{\left( {1 - 0.25} \right)^{5 - 3}}\] + \left( {\begin{array}{*{20}{c}}\\5\\\\4\\\end{array}} \right){\left( {0.25} \right)^4}{\left( {1 - 0.25} \right)^{5 - 4}}\]+ \left( {\begin{array}{*{20}{c}}\\5\\\\5\\\end{array}} \right){\left( {0.25} \right)^5}{\left( {1 - 0.25} \right)^{5 - 5}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = \dfrac{5!}{3!(5-3)!}\right){\left( {0.25} \right)^3}{\left( {1 - 0.25} \right)^{5 - 3}}\] + \dfrac{5!}{4!(5-4)!} \right){\left( {0.25} \right)^4}{\left( {1 - 0.25} \right)^{5 - 4}}\] + \dfrac{5!}{5!(5-5)!} \right){\left( {0.25} \right)^5}{\left( {1 - 0.25} \right)^{5 - 5}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = \dfrac{5!}{3!(5-3)!}\right){\left( {0.25} \right)^3}{\left( {1 - 0.75} \right)^{2}}\] + \dfrac{5!}{4!(5-4)!} \right){\left( {0.25} \right)^4}{\left( {0.75} \right)^{1}}\] + \dfrac{5!}{5!(5-5)!} \right){\left( {0.25} \right)^5}{\left( {0.75} \right)^{0}}\][/tex]

[tex]\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = 0.0879 + 0.0146 + 0.001[/tex]

[tex]\mathbf{\[P\left( {X = 3 \ or \ 4 \ or \ 5 } \right) = 0.1035}[/tex]

HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

B

Step-by-step explanation:

X^2  3*3=9

X^2 2*2=4

Hope this helps. I've done something like this before. (: Good luck

Answer:

B: x^2-9/x^2-4

Step-by-step explanation:

numerator:

(x+3)(x-3) = x^2-3x+3x-9 = x^2 - 9

denominator:

(x+2)(x-2) = x^2-2x+2x-4 = x^2 - 4

final answer:

x^2-9 /x^2-4

Flip a coin 10 times and record the observed number of heads and tails. For example, with 10 flips one might get 6 heads and 4 tails. Now, flip the coin another 20 times (so 30 times in total) and again, record the observed number of heads and tails. Finally, flip the coin another 70 times (so 100 times in total) and record your results again. We would expect that the distribution of heads and tails to be 50/50. How far away from 50/50 are you for each of your three samples? Reflect upon why might this happen? In response to your peers, comment on the similarities and differences between yours and your classmate’s data analyses. In particular, compare how far away you and your classmate are from 50/50 for each of your three samples.

Answers

Answer:

Theoretical probability = 50%

Experimental probability varies.

See below for explanation.

Step-by-step explanation:

This is a problem on theoretical and experimental probability. The results obtained would enable you understand their differences.

The theoretical probability is the result that is expected to happen, but it isn't always what eventually happens.

The theoretical probability of a coin landing on heads is ½ or 50%. This is same for tails.

The experimental probability is the probability obtained from carrying out the experiment. As this is the result of what actually happens, the experimental probability could be lesser  or greater than or equal to 50%.

You are required to carry out the experiment. This is because the result would vary from person to person as well as from one experiment to the other.

First, make a table for the number of trials, outcome (head and tail each) and the frequency. Pen down the result for each of the experiment carried out. You can use a tally to make it easy for compilation.

See attachment for table.

Theoretical probability of 10 trials:

Head= 5, tail = 5

Theoretical probability of 30 trials:

Head= 15, tail = 15

Theoretical probability of 100 trials:

Head= 50, tail = 50

It all amount to 50% each

So do your experiment and record the results. Afterwards compare your result  which is the experimental probability

for head and tail with the theoretical theoretical.

Also compare your result with that of your classmate.

In the diagram below, if AD= 100 and AC = 34, find CD.
A 59
B 76
C 45
D 66

Answers

The answer is d.66
100-34=66

If the density of an object is 8 g/cm³, and the mass is 200M m g. What is the volume of the object?

Answers

Answer:

Step-by-step explanation:

the mass is 2000 mg, or 2 g.

the density is 8 g/cm^3

divide 2 by 8

0.25 cm^3

if this helped, mark as brainliest :)

Find the greatest common factor of the
following monomials:
15r25
48353

Answers

Answer:

475r35

Step-by-step explanation:

475r35 is what I think the answer is

2{ 5[7 + 4(17 - 9) - 22]}

Answers

Answer:

170

one-hundred seventy

Step-by-step explanation:

[tex]2(5(7+4(17 - 9)-22))=\\2(5(7+4(8)-22))=\\2(5(7+32-22))=\\2(5(39-22))=\\2(5(17))=\\2(85)=\\170[/tex]

Answer:

170.

Step-by-step explanation:

2{ 5[7 + 4(17 - 9) - 22]}

2{5[7+32 -22]}

2{5[17]}

2[85] = 170

est the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test. Upper H 0 : p equals 0.89 versus Upper H 1 : p not equals 0.89 n equals 500 comma x equals 430 comma alpha equals 0.01 Is np 0 (1 minus p 0 )greater than or equals 10​? Select the correct choice below and fill in the answer box to complete your choice. ​(Type an integer or a decimal. Do not​ round.) A. ​No, because np 0 (1 minus p 0 )equals nothing. B. ​Yes, because np 0 (1 minus p 0 )equals 48.95. Your answer is not correct. Now find ModifyingAbove p with caret.

Answers

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population proportion significantly differs from 0.89.

The requirements for the test are satisfief.

n(1-p)=70>10

Step-by-step explanation:

This is a hypothesis test for a proportion.

There are 3 requirements to have a valid test of proportion: random sample, independence and normal.

For the first two (random and independent sample) we don't have details, but we assume the sampling has been random.

The latter can be verified by calculating np and n(1-p):

[tex]np=430>10\\\\n(1-p)=70>10[/tex]

Both are bigger than 10, so the normal approximation can be considered appropiate.

The claim is that the population proportion significantly differs from 0.89.

Then, the null and alternative hypothesis are:

[tex]H_0: \pi=0.89\\\\H_a:\pi\neq 0.89[/tex]

The significance level is 0.01.

The sample has a size n=500.

The sample proportion is p=0.86.

[tex]p=X/n=430/500=0.86[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.89*0.11}{500}}\\\\\\ \sigma_p=\sqrt{0.000196}=0.014[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.86-0.89+0.5/500}{0.014}=\dfrac{-0.029}{0.014}=-2.072[/tex]

This test is a two-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=2\cdot P(z<-2.072)=0.038[/tex]

As the P-value (0.038) is greater than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population proportion significantly differs from 0.89.

Graph the equation by plotting three points. If the three are correct, the line will appear. 2y=3x+11

Answers

Answer:

Create a table of xy values or use a graphing calc.

Step-by-step explanation:

Answer:

Three points you can plot are: (-6, -3.5) (-7, -5) (0, 5.5).

Step-by-step explanation:

You can use a graphing calculator to determine the points. Attached is an image.

Hope this helps! :)

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