What would the mechanical advantage of a ramp be if the length is 25 feet and the height is 5 feet?
10
125
5
30

Answers

Answer 1

Answer:

5.

Explanation:

From the question given above, the following data were obtained:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =?

Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:

Mechanical advantage = length /height

MA = L/H

With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =.?

MA = 25 / 5

MA = 5

The, the mechanical advantage of the ramp is 5.

Answer 2

Answer:

5.

Explanation:

From the question given above, the following data were obtained:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =?

Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:

Mechanical advantage = length /height

MA = L/H

With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =.?

MA = 25 / 5

MA = 5

The, the mechanical advantage of the ramp is 5.


Related Questions

what is the function of brushes in D.C motor​

Answers

Answer:

to transfer the voltage

Explanation:

The brushes make physical contact with the commutator. When a DC voltage is applied to the brushes, that voltage is transferred into the commutator which, in turn, powers the windings. This electrical input generates a magnetic field around the armature.

what is the uses of space weather data?​

Answers

Answer:

Space Weather Data

They are used to produce forecasts, such as the monthly sunspot number forecast. Most notably, sunspot numbers represent one of the longest continuous climate records available. The data give scientists the means to make many forecasts and issue space weather advisories and alerts.

Explanation:

Why do you think it is colder during the winter than the summer?

Answers

Answer:

As the earth travels around the sun during the year it maintains this tilt. Because of this tilt, in the summer we (north of the equator) are slanted more directly towards the sun so it's hotter. In the winter, we're slanted away so the sun's rays are less direct, making it colder.

pls help me with this

Answers

Answer:

A screw

Explanation:

Answer:
Screw
Explanation :
I hope it helps !

A woman can lift barrels a vertical distance of 1 meter or can roll them up a 2-meter long ramp to the same elevation. If she uses the ramp, the applied force required is

Answers

Answer:

answer is 1/2 as much force required

PLZ HELP MEEEEEEE,;-;

Answers

Answer:

thxs for the points

Explanation:

because just started

How much energy is required to raise the temperature of 5.0 g of silver from 298 K to
334 K?

Answers

Answer:

43.2J

Explanation:

Q = m × c × ∆T

Where:

Q = amount of energy

m = mass (grams)

c = specific heat capacity

∆T = change in temperature

Mass = 5.0g

Specific heat capacity of Silver (Ag) = 0.240 J/g°C

We need to convert the temperature from Kelvin (K) to °C

Initial temperature = 298 - 273 = 25°C

Final temperature = 334 - 273 = 61°C

Q = 5 × 0.240 × (61°C - 25°C)

Q = 1.2 × 36

Q = 43.2J

I need help with the questions when it says what is the topic and rest

Answers

It should be a and f would I you like me to explain

A ball of radius R and mass m is magically put inside a thin shell of the same mass and radius 2R. The system is at rest on a horizontal frictionless surface initially. When the ball is, again magically, released inside the shell, it sloshes around in the shell and eventually stops at the bottom of the shell. How far does the shell move from its initial contact point with the surface

Answers

Answer:

[tex]x =\frac{-R}{2}[/tex]

Explanation:

From the question we are told that mass

Thin layer radius [tex]= 2R[/tex]

Generally the expression for ths solution is given as

Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2

the center of mass will not move at initial state  

Considering the center of mass of both bodies

[tex]xcm=\frac{m*x+m*x)}{2m} =x[/tex]

[tex]x =\frac{-R}{2}[/tex]

Therefore the enclosing layer moves [tex]x =\frac{-R}{2}[/tex]                          

The shell move from its initial contact point with the surface is,

[tex]x =\dfrac{-R}{2}[/tex]

Given-

Radius of the ball is [tex]R[/tex].

the mass of the ball is [tex]m[/tex].

The mass of the thin shell is [tex]m[/tex].

The radius of the thin shell is [tex]2 R[/tex].

For the two bodies with mass [tex]m[/tex], the center of mass can be given as,

[tex]x_{cm}=\dfrac{m_{1} x_{1}+m_{2} x_{2} }{m_{1} +m_{2}}[/tex]

In the given question, the mass of both the bodies are equal and the given distance of center of mass for both bodies are also equal. Therefore,

[tex]x_{cm}=\dfrac{m x_+mx }{m +m}[/tex]

[tex]x_{cm}=\dfrac{2mx }{2m}[/tex]

[tex]x_{cm} =x[/tex]

Distance for center of mass can also be given as,

[tex]x_{cm} =m\times o[/tex]

[tex]x_{cm} =m\times \dfrac{-R}{2m}[/tex]

[tex]x_{cm} =\dfrac{-R}{2}[/tex]

Comparing both the values of the distance of center of mass we get,

[tex]x =\dfrac{-R}{2}[/tex]

Hence, The shell move from its initial contact point with the surface is,

[tex]x =\dfrac{-R}{2}[/tex]

For more about the center of mass follow the link below,

https://brainly.com/question/8662931

Do you think the inner planets should be explored or should the money be spent on other things? Justify your opinion.

Answers

Answer:

yes i think that inner planets should be explored because if we ever find new life or are able to live there then i think its worth takeing a risk.

Explanation:

A ball has a mass of 0.1 kg and an initial velocity of 20 m/s. The ball is given an acceleration of 30 m/s2 for 5 s. What is the net force on the ball during acceleration?

Answers

Answer:

acceleration = v-u /t

30- 20/5

= 10/5 = 2m/sec²

Force = mass * acceleration

Force = 0.1 * 2

Force = 0.2 Newton

Answer:

I hope the above pic will help you

I will always help you understanding your assingments

have a great day #Captainpower:)


a 5.00 kg plane is speeding up on the ground with an applied force of 706 N. If the net force is 450 N, what would be the force due to air resistance

Answers

Answer:

The force due to air resistance is 256 N.

Explanation:

Given;

mass of the plane, m = 5 kg

applied force on the plane, Fa = 706 N

the net force on the plane, ∑F= 450 N

Let the force due to air resistance = Fr

The net force on the plane is given as;

Net force = applied force - force due to air resistance

∑F = Fa - Fr

Fr = Fa - ∑F

Fr = 706 - 450

Fr = 256 N.

Therefore, the force due to air resistance is 256 N.

A force of 900N acts on
a stationary body
for 40sec and the body acquires the velocity of360 m/s calculate mass a body.

Answers

Answer:

Explanation:

It is still using F = m*a -- just in a disguised form.

Givens

F = 900 N

vf = 360 m/s

vi = 0

t = 40 second

Formulas

a = (vf - vi)//t

F = m * a

Solution

a = (360 - 0)/ 40

a = 9

F = m * a

900 = m * 9

m = 900/9

m - 100 kg.          Doesn't seem high enough.

Answer:

a= V- u/t

a= 360 - 0 /40 = 9 m/sec2

F = MA

900 = M * 9

M = 900/9

M= 100 kg

You are standing on a moving bus, facing forward, and you suddenly fall forward. You can imply form this that the bus’s

Answers

I think has stopped maybe

will you help me please

Answers

Answer: True

Explanation: It's true because the definition of a Command economy states that it's an economy in which production, investment, prices, and incomes are determined CENTERALLY by a GOVERNMENT.

A sign is attached to the side of a building as seen below. The sign is attached to a steel rod. A wire connects to the end of the rod for support. The mass of the sign is 50 kg. Determine the supporting force exerted by the cable

Answers

Answer:

500N

Explanation:

50kgx10N/kg

= 500N

Calculate the aceleration of a vehicle of 100 kg when applicates 400 N

Answers

Answer:

For this we applicate 2nd law of Newton:

F = ma

Replacing:

400 N = 100 kg * a

a = 400 N / 100 kg

a = 4 m/s²

The aceleration is 4 meters per second squared.

Answer:

....................

Explanation:

---------------------

If you launch an object in space, it
will continue to move forward
until an external force stops it.
This is a characteristic of which
law?

Answers

Answer:

I believe this represents Newton's first law of motion. Any object in motion will continue to move until a force stops it, be it friction or a physical object.

a small balloon containing baking soda has a mass of 4 grams. A student adds 10 ml. of vinegar
to a 100 gram glass bottle. The student stretches the opening of the balloon over the mouth of
the bottle, mixing the baking soda and vinegar inside the bottle. Once the balloon is inflated, the
student finds the mass of the balloon, bottle, and their contents to be 116 grams. What was the
mass of the vinegar originally in the bottle
F.10g G.12g J.16g

Answers

Answer:

10 grams

Explanation:

I took a test with this question earlier.

Voltage has been described as similar to the water in the water pipes in your home. What other analogy can you think of that is similar to voltage?

Answers

When describing voltage, current, and resistance, a common analogy is a water tank. In this analogy, charge is represented by the water amount, voltage is represented by the water pressure, and current is represented by the water flow.

at constant pressure by what fraction of its volume will aquantity of gas change if the temperature changes from -173degree C to 27degree C

Answers

Answer:

The volume of the gas becomes three times the initial volume.

Explanation:

Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.

So, the initial temperature, [tex]T_1[/tex] = -173 degree C = -173+273 = 100 K.

The final temperature, [tex]T_2[/tex]= 27 degree C = 27+273=300 K.

As the pressure is constant, so [tex]P_1=P_2[/tex].

Let V_1 and V_2 be the initial and final volume respectively.

Assuming that the given gas is ideal gas.

So, applying the ideal gas equation

PV=nRT

where n is the number of moles of the gas and R is the universal gas constant.

For the initial state, [tex]P_1V_1=n_1RT_1\cdots(i)[/tex]

and for the final state, [tex]P_2V_2=n_2RT_2 \cdots(ii)[/tex]

Dividing the equation (i) by (ii), we have

[tex]\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}[/tex]

As the mass of the gas is not changing, so [tex]n_1=n_2[/tex], then

[tex]\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}[/tex]

As the pressure is not changing, so [tex]P_1=P_2[/tex], then

[tex]\frac {V_1}{V_2}=\frac {100}{300}[/tex]

[tex]V_2=3V_1[/tex]

So, the volume of the gas becomes three times the initial volume.

help plz The sum of all chemical reactions that take place within an organism is known as ______________. *

Answers

Answer:

Metabolism

Explanation:

metabolism is the sum of all chemical reactions that take place within an organism

Answer:

Metabolism

Explanation:

What does this same experiment( the picture) tell you about light waves? Explain.

Answers

The picture is too blurry but I help :)

A car weighing 19600N is moving with a speed of 30 m/sec on a level road. If it is brought to rest in a distance of 100 m. Find the average distance friction force acting on it

Answers

Answer:

F = -8820 N

Explanation:

Given that,

The weight of a car, W = 19600 N

Initial speed of the car, u = 30 m/s

It is brought to rest, final velocity, v = 0

Distance, d = 100 m

We need to find the average friction force acting on it.

Firstly we find the acceleration of the car using third equation of motion. Let it is a.

[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0)^2-(30)^2}{2\times 100}\\\\=-4.5\ m/s^2[/tex]

Average frictional force,

F = ma

m is mass, [tex]m=\dfrac{W}{g}=\dfrac{19600\ N}{10\ m/s^2}=1960\ kg[/tex]

F = 1960 kg × -4.5 m/s²

= -8820 N

So, the average friction force acting on it is 8820 N.

Calculate the displacement of the following components:
1 units North
2 units South
2 units North
2 units North
3 unit South

Answers

Answer:

zero displacement

its returnin to the starting point.

5 north 5 south

An airplane cruising at a constant velocity and altitude. Which of the following diagrams best represents the four forces of the airplane?

Answers

Answer:

You need to put the diagrams. repost and include the diagrams

1. A book is at rest on a tabletop. Diagram the forces acting on the book. ​

Answers

When you place a book on a table, the book exerts a downward force on the table and the table exerts an upward force on the book.

The free-body diagram of the forces acting on a book resting on a table is shown in the figure.

When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.

So, the forces acting on a book resting on a tabletop are:

1. Weight of the book, W(downward)

2. Normal force (N) perpendicular to the surface in contact.

Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.

To know more about forces, click here:

https://brainly.com/question/13191643

#SPJ6

define light?it's types​

Answers

Answer:

Light or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that can be perceived by the human eye. Visible light is usually defined as having wavelengths in the range of 400–700 nm, or 4.00 × 10⁻⁷ to 7.00 × 10⁻⁷ m, between the infrared and the ultraviolet.

Explanation:

This is one type of light.

A steel rod has a diameter of 3.75cm.Express it's diameter in millimeters and meter

Answers

Answer:

3.75cm into millimetres

= 3.75 * 10

37.5 millimetres

3.75 cm into metres

3.75/100

= 0.0375m

a beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3

Answers

Answer:2.47

Explanation:

So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!

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