Answer:
Q:
What volume will 3.50 mol of Xe gas occupy at STP?
A:
78.4 L
Explanation:
The volume occupied by 3.5 moles of ammonia gas at standard temperature and pressure (STP) is 78.45 L
Data obtained from the question Number of mole (n) = 3.5 moles Pressure (P) = STP = 1 atm Temperature (T) = STP = 273 KGas constant (R) = 0.0821 atm.L/Kmol Volume (V) =? How to determine the volume
The volume of the gas at standard temperature and pressure (STP) can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
1 × V = 3.5 × 0.0821 × 273
V = 78.45 L
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Which hypothesis is directly tested in an experiment?
a. One specific confounding variable hypothesis.
b. All of the confounding variables hypotheses.
c. The research hypothesis.
d. both b and c
What element is steel mainly composed of?
A. Iron
B. Carbon
C. Manganese
D. Silver
El acero esta compuesto por Hierro y Carbono
To which of the three main chemical classes does Mercury (Hg) belong?
a) It's not an element in the periodic table
b) Metalloids
c) Non-metals
d) Metals
Answer:
Metals
Explanation:
It is a transition metal
The periodic table has a lot of different properties in how it is presented, one of these, is that the elements are separated in blocks by their properties.
From its position in the table, we can see that the correct option is d) metals.
The general way of knowing if an element is a metal or not, is to look if it is the D block in the periodic table.
This block contains all the transition metals (not all the metals) but every element in it is a metal. If we look for the mercury, we can see that it is in block D, just next to gold (Au).
Just from this, we can conclude that mercury is a metal, so the correct option is d.
If you want to learn more, you can read:
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Which equation has x = 5 as the solution?
2x = 5
2x = 5
x - 10 = 15
x - 10 = 15
x + 15 =10
x + 15 =10
2x = 10
Answer:
x-10 should be the answer
Can someone pls help me with this its due in 20 minutes.
Answer:
15. The velocity of a sound wave is affected by two properties of matter: the elastic properties and density.
16. The greater the density of a medium, the slower the speed of sound. This observation is analogous to the fact that the frequency of a simple harmonic motion is inversely proportional to m, the mass of the oscillating object.
17. Temp °C 0 m/s2 m/s
50 360.51 361.62
18. Molecules at higher temperatures have more energy, thus they can vibrate faster. Since the molecules vibrate faster, sound waves can travel more quickly. The speed of sound in room temperature air is 346 meters per second. ... The speed of sound is also affected by other factors such as humidity and air pressure.
A sample of oxide iron weighing 2.40g was heated in a stream of hydrogen until it was completely converted to the metal. If the metal weighed 1.68g. What is the formula of the iron oxide? (Fe=56, O=16)
Answer:
Fe₂O₃
Explanation:
To solve this question we must find the moles of Iron in 1.68g. With the difference of the masses we can find the moles of oxygen. The formula will be obtained with the ratio of both amount of moles:
Moles Fe:
1.68g * (1mol / 56g) =0.03moles
Moles O:
2.40g-1.68g = 0.72g * (1mol/16g) = 0.045moles
The ratio O/Fe is:
0.045moles / 0.03moles = 1.5 moles. this ratio is obtained if the formula is:
Fe₂O₃If 23.2 g of a given gas occupies a volume of 93.2 L at a particular temperature and pressure, what
mass of the gas occupies a volume of 10.4 L under the same conditions?
Answer:
2.59g
Explanation:
Using Avagadro's law equation as follows:
V1/n1 = V2/n2
Where;
V1 = initial volume (litres)
V2 = final volume (litres)
n1 = first amount of gas in grams
n2 = second amount of gas in grams
According to the information provided in this question, v1 = 93.2L, v2 = 10.4L, n1 = 23.2 g, n2 = ?
Using V1/n1 = V2/n2
93.2/23.2 = 10.4/n2
Cross multiply
93.2 × n2 = 23.2 × 10.4
93.2n2 = 241.28
n2 = 241.28/93.2
n2 = 2.588
n2 = 2.59g
The mass of the gas is 2.59g that occupies a volume of 10.4 L under the same conditions.
Avogadro's law equation:V₁/n₁ = V₂/n₂
Where
V₁ = initial volume (litres)
V₂ = final volume (litres)
n₁ = first amount of gas in grams
n₂ = second amount of gas in grams
Given:
V₁ = 93.2L,
V₂ = 10.4L,
n₁ = 23.2 g,
To find:
n₂ = ?
On substituting the values:
93.2/23.2 = 10.4/n₂
93.2 * n₂ = 23.2 * 10.4
93.2* n₂ = 241.28
n₂ = 241.28/93.2
n₂ = 2.588
n₂ = 2.59g
Thus, the mass of the gas is 2.59g.
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A compound containing 5.93% H and 94.07% O has a molecular mass of 34.02 g/mol determine the empirical and Molecular formula Of this compound
Answer:
7% 4)2(10
Explanation:
beacouse if you divide it you can get the answer
What is the solution to the problem expressed to the correct number of significant figures?
7.21= ?
A. 1.688
OB.
1.69
O C.
1.7:
OD
1.70
Answer:
(102 900 ÷ 12) + (170 × 1.27) = 8800
Step 1. Evaluate the expressions inside the parentheses (PEMDAS)
102 900 ÷ 12 = 8575
170 × 1.27 = 215.9
In multiplication and division problems, your answer can have no more significant figures than the number with the fewest significant figures.
Thus, the underlined digits are not significant, but we keep them in our calculator to avoid roundoff error.
Step 2. Do the addition (PEMDAS).
8575
+ 215.9
= 8790.9
Everything that you add to an insignificant digit gives an insignificant digit as an answer.
Thus, the underlined digits are not significant.
We must drop them and round up the answer to 8800.
Explanation:
Find Jay's instantaneous speed at 35 minutes.
Find jays instantaneous speed at 35 minutes.
2. Hydrocarbons consist of carbon and hydrogen. 5.7 g of a hydrocarbon contains 4.8 g of carbon.
If the relative molecular mass of the hydrocarbon is 114, determine its molecular formula.
Answer:
The molecular formula of the hydrocarbon compound is C₈H₁₈
Explanation:
The type of chemical substance in the question = Hydrocarbon
The mass of the hydrocarbon = 5.7 g
The mass of carbon in the given hydrocarbon (sample) = 4.8 g
The relative molecular mas of the hydrocarbon = 114 g
Therefore, the mass of hydrogen in the sample, H = 5.7 g - 4.8 g = 0.9 g
The ratio of the mass of carbon in the sample = 4.8/5.7
The ratio of the mass of hydrogen in the sample = 0.9/5.7
By the law of constant composition, we have;
The mass of carbon in a mole of the hydrocarbon = (4.8/5.7) × 114 g = 96 g
The molar mass of carbon, C = 12 g/mol
The number of moles of carbon in a mole of the hydrocarbon, 'n₁', is given as follows;
n₁ = 96 g/12 g = 8 moles
The mass of hydrogen in a mole of the hydrocarbon = (0.9/5.7) × 114 g = 18 g
The molar mass of hydrogen, H ≈ 1 g/mol
The number of moles of hydrogen in a mole of the hydrocarbon, 'n₂', is given as follows;
n₂ = 48 g/1 g = 18 moles
Therefore, in each each molecule of the compound, we have have 8 atoms of carbon, 'C', and 18 atoms of hydrogen, 'H'
Therefore, we get;
The molecular formula of the hydrocarbon compound is C₈H₁₈ which is the chemical formula for the hydrocarbon also known as octane
PLEASE HELP: 60 POINTS
Select all that apply!
The emission of a Beta particle has the effect of:
a change in mass of an electron emitted from the nucleus
decreasing mass by one unit
increasing mass by one unit
adding a proton to the nucleus
converting 1 neutron to 1 electron and 1 proton
b. What useful functions do oxidation numbers
serve?
20.
b. How many molecules are in 1 mole of
molecules?
c. What is the name given to the number of
molecules in 1 mole?
21. a. What is the molar mass of an element?
b. Write the molar mass rounded to two
decimal places of carbon, neon, iron and
uranium.
Explanation:
b. What useful functions do oxidation numbers serve?
It is used to show oxidation and reduction (loss and gain of electrons)
b. How many molecules are in 1 mole of molecules?
1 mole = 6.022 * 10^23 molecules
c. What is the name given to the number of molecules in 1 mole?
Avogadro's Number of molecules
21. a. What is the molar mass of an element?
This is the mass of an element divided by the number of moles.
Molar mass = Mass / Number of moles
b. Write the molar mass rounded to two decimal places of carbon, neon, iron and uranium.
amu = Atomic Mass Unit
Carbon = 12.01 amu
Neon = 20.18 amu
Iron = 55.85 amu
Uranium = 238.03 amu
If the Moon is in the position shown, what is the view from Earth?
Answer:
When the Moon is in the position shown below, how would the Moon look to an observer on the North Pole ... The moon's rotational period is equal to its revolutional period around Earth.
Explanation:
is lime flavor ionic or covalent
Answer:Calcium carbonate (CaCO3), essentially, is an ionic compound having the bivalent calcium and carbonate ions. But the carbonate anion is a polyatomic species. The carbon atom is bonded to all the three oxygen atoms by covalent bonds - two carbon-oxygen single bonds and one carbon-oxygen double bond.
Explanation:So it's ionic hope this helps u. Btw may i have brainlist plz.
What is the primary difference between a molecule and a compound?
A. All molecules are compounds, but not all compounds are molecules
B. Molecules always contain only one type of atom, unlike compounds
C. Compounds must be composed of more than one type of atom
Answer:
A. "All molecules are compounds, but not all compounds are molecules"
Explanation:
An example of a compound-molecule is oxygen. The elemenal is O, because the periodic table isn't describing molecules, it's describing atoms. The molecule is O2 because it takes 2 O atoms to make a molecule of oxygen.
The primary difference between a molecule and a compound is 'compounds must be composed of more than one type of atom'.
Explanation:
A molecule is a group of atoms of the same or different types of atoms bound to each other.Molecules are the smallest unit of a substance that possesses the characteristic of the substance.A compound is a substance in which two or more different types of atoms are bound to each other.In compounds, atoms of different elements are in a fixed proportion.So, from this, we can conclude that the primary difference between a molecule and a compound is 'compounds must be composed of more than one type of atom'.
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use ideas about particles and energy transfer to explain why sweat cools you down
Answer:
So the paws in your body like ot opens up and when the wind blows on the sweat it basically cools you down
Explanation:
I hope it is what you were looking for.
A rectangular poster is /4 yard wide and / yard tall. What is its area? Solve this problem any way you choose
Answer:
Area of rectangular poster = [tex]\frac{3}{16}[/tex] yard²
Explanation:
P.S - The exact question is -
Given - A rectangular poster is [tex]\frac{1}{4}[/tex] yard wide and [tex]\frac{3}{4}[/tex] yard tall.
To find - What is its area ?
Proof -
We know that ,
The area of rectangle = Length × Breadth
Here,
Given that,
Length of rectangle = [tex]\frac{3}{4}[/tex] yard
Breadth of rectangle = [tex]\frac{1}{4}[/tex] yard
∴ we get
Area of rectangular poster = [tex]\frac{3}{4}[/tex] × [tex]\frac{1}{4}[/tex] yard²
= [tex]\frac{3}{16}[/tex] yard²
⇒Area of rectangular poster = [tex]\frac{3}{16}[/tex] yard²
what is electron cloud?
The molar mass of two equally sized samples of unknown gaseous compounds is shown in the table. Molar Mass Comparison Gas Molar Mass A 17 g/mol B 36.5 g/mol Which statement describes the density and diffusion of both gases at STP? Gas A has a higher density and diffuses faster than Gas B. Gas A has a higher density and diffuses slower than Gas B. Gas A has a lower density and diffuses faster than Gas B Gas A has a lower density and diffuses slower than Gas B.
Answer:
Effusion is the process of a gas being poured out through a hole diametrically smaller than the structural exit of the container.
A lighter gas effuses faster than a heavier gas.
Thus gas A has a lower density and effuses slower than Gas B.
Explanation:
The gas with a lower molar mass will have a lower density and diffuses at a slower rate. Thus gas A has a lower density than gas B and diffuses slower than gas B.
Three points should be noted here;
The density of any substance is related to the molar mass.[tex]D=M/V[/tex], where [tex]D[/tex] is the density, [tex]M[/tex] is the mass and [tex]V[/tex] is the volume of the substance.The density of the gas is directly proportional to the molar mass of the gas.Hence the gas A has lower density and the gas B has higher density as the molar mass of A is [tex]17 g/mol[/tex] and of B is [tex]36.5 g/mol[/tex].
About Diffusion please note the below points;
Diffusion is the process of movement of a substance from the area of higher concentration to the area of lower concentration.The gas with a smaller mass will diffuse slower in rate than the gas with a higher mass.Hence the gas A diffuses slower in rate than gas B.
Thus the correct answer is "Gas A has a lower density and diffuses slower than Gas B".
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What does Boyle's Law describe?
Answer: Image result for What does Boyle's Law describe?
This empirical relation, formulated by the physicist Robert Boyle in 1662, states that the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature; i.e., in equation form, pv = k, a constant.
Explanation:
Two students pull a box with force of 100 N to the left and 200 N to the right.
What is the net force and direction in which the box moved?
Answer:
net force is 100 N and direction is right
Explanation:
100 point and brainlist answer the question below
Answer:
a
Explanation:
because am pro
It late, I need help quick
Answer:
what is late ? there is no attachment ?
Answer:
For people asking for the questions
Explanation:
How are chemical reactions classified from an energy point of view?
Answer:
normanie tykohoukdh kjdj jj jjd
Explanation:
Solutions of calcium nitrate and sodium chloride are mixed.
Answer:
For example, when water solutions of calcium nitrate and sodium carbonate are mixed, calcium carbonate precipitates from the solution while the other product, sodium nitrate, remains dissolved. It is a precipitate.
Explanation:
If 3.22 g of precipitate are recovered from the reaction of limewater (Ca(OH),) with carbon dioxide to produce
water and calcium carbonate, what is the percent yield if 20.0 g of carbon dioxide was mixed with the
limewater?
the correct answer is 7.1% but i don't understand what they did
Answer:
Percent yield = 7.1%
Explanation:
The general reaction of the problem is:
Ca(OH)₂ + CO₂ → H₂O + CaCO₃
To solve this question we need to find theoretical yield using the amount of carbon dioxide added because:
Percent yield = Actual yield (3.22g) / Theoretical yield * 100
Theoretical yield is the maximum amount of product that could be obtained. To find it we need to convert the mass of CO₂ to moles. The moles of CO₂ = Moles of CaCO₃:
Moles CO₂ -Molar mass: 44.01g/mol):
20.0g * (1mol / 44.01g) = 0.454 moles CO₂ = Moles of CaCO₃ produced
Mass CaCO₃ = Theoretical yield -Molar mass: 100.09g/mol-:
0.454 moles * (100.09g / mol) = 45.5g of CaCO₃ = Theoretical yield.
Replacing:
Percent yield = 3.22g / 45.5g * 100
Percent yield = 7.1%What is the pH of a solution with a (H+] = 0.80 M? *Please round your answer to the appropriate number of significant figures. Your answer can be in standard notatic "e" in place of x10.*
Answer:
The pH of a solution with a (H+] = 0.80 M is [tex]9.6 e^{-2}[/tex]
Explanation:
As we know
pH = -[log H+]
Substituting the value of H+ ion concentration in the above equation, we get -
pH = -log [0.80]
pH [tex]= -[-0.096] = 0.096 = 9.6 e^{-2}[/tex]
In the reaction below identify the products. CH4 + 202 --> CO2 + 2H2O
Answer:
CO2 and H20
Explanation:
The products are on the right hand side of the equation.
please help me lol
How many grams of magnesium sulfate (MgSO4) are dissolved in 0.965 L of a 0.0575 M solution? Molar Mass Mg: 24.30 g/mol Molar Mass S: 32.06 g/mol Molar Mass O: 16.00 g/mol
Answer:
in 4 liters of solution
MgSO4) are dissolved in 0.965 L of a 0.0575 M solution? Molar Mass Mg: 24.30 g/mol Molar Mass S: 32.06 g/mol Molar Mass O: 16.00 g/
Answer:
6.68
Explanation:
i did it and got it right