What term is defined as speed with a specific direction?
velocity
position
distance
displacement

Answer:

b

Explanation:

I did this question earlier

Answer:

the friction force f=36

and the coefficient of friction =0.45

Answer:

The answer is "0.047".

Explanation:

Given value:

[tex]\to t_{\frac{1}{2}}= 0.4406\\\\\to V=0.9375 V_{max}[/tex]

Calculating the capacitance:

[tex]\to V=V_{max} (1-e^{\frac{-t}{Rc}})[/tex]

In this, the t = time, which is taken to calculates its maximum voltage.

[tex]\to 0.9375 V_{max} = V_{max}(1-e^{- \frac{t}{103\times(165.279\times10^{-6})}})\\\\\to e^{- \frac{t}{103\times(165.279\times10^{-6})}}= 0.0625\\\\\to - \frac{t}{103\times(165.279\times10^{-6})} = \ln(0.0625)\\\\\to -t= 0.01702\times(-2.77258) \\\\ \to -t = -0.04719 \\\\ \to t= 0.04719 \approx 0.047 \ s[/tex]

Answer:

10m/s

Explanation:

Vf=v0+at

30m/s=v0+2.5m/s^2*8s

Solve for v0=10m/s

Sorry for the vague explanation I'm on my phone right now. Hope this still helps!

Initial velocity of the car where final velocity of a car is 30m/s and it is accelerating at a rate of 2.5 [tex]m/s^{2}[/tex] over an 2.8 [tex]m/s^{2}[/tex] 8 second period of time is 10 m/s.

To find the initial velocity of the car, we can use the kinematic equation:

Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)).

Given the final velocity (v) as 30 m/s, acceleration (a) as 2.5 [tex]m/s^{2}[/tex], and time (t) as 8 seconds, we can plug these values into the equation:

30 m/s = u + (2.5 [tex]m/s^{2}[/tex] * 8 s).

Now, solve for the initial velocity (u):

30 m/s = u + 20 m/s.

Subtract 20 m/s from both sides:

u = 30 m/s - 20 m/s = 10 m/s.

Therefore, the initial velocity of the car is 10 m/s.

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Mark as brainlist

Answer:

Answer:answer is C

is the magnetic field

Answer:

The moment of inertia depends on the following factors, The density of the material. Shape and size of the body. Axis of rotation (distribution of mass relative to the axis)

Answer:

The answer is 45 degree angle

Answer:I think I’m not sure But I think that the force that would be accurated the car would be friction or something like that and to solve the equation you would do f/m

Explanation:

It just makes sense

Explanation:

uasjwwbwjwbwia GJ wkwkjwnwnwjwjjwjwd7beba s

Answer:

Concave mirror

Explanation:

Because as we move the object far away from the mirror the image gets inverted

Answer:

Energy stored, E = 5929 J

Explanation:

Given that,

The mass of a test dummy, m = 55 kg

It is launched 11 m into the air.

We need to find the energy stored in the bungee cords. It can be calculated as follows :

[tex]E=mgh\\\\E=55\times 9.8\times 11\\\\E=5929\ J[/tex]

So, 5929 J of energy is stored in the bungee cords.

Answer:

Blood group

Explanation:

Answer:

A. Blood group.

Explanation:

They could purely random genetic changes.

Answer:

[tex]1.2\times 10^{10}\ kg[/tex]

Explanation:

Given that,

The energy of the nuclear plant, [tex]E=10^{27}\ J[/tex]

We need to find how much mass wast lost.

The relation between energy and mass is given by :

[tex]E=mc^2[/tex]

Where

c is speed of light

[tex]m=\dfrac{E}{c^2}\\\\m=\dfrac{10^{27}}{(3\times 10^8)^2}\\\\m=1.2\times 10^{10}\ kg[/tex]

So, [tex]1.2\times 10^{10}\ kg[/tex] of mass was lost.

Answer:

Given: V = 220V, Pmin = 360W, Pmax = 840W

For minimum heating case:

We know that

Pmin = VI

360 = 220 X I

I = 1.63 amp

R = V/I

R = 220/1.63

R = 134.96ohms

For maximum heating case:

We know that

Pmax = VI

840 = 220 X I

I = 3.81 amp

R = V/I

R = 220/3.81

R = 57.74 ohms

Answer:

Sound waves are translated into transverse waves to know the frequency, amplitude, wavelength etc of the waves.

Explanation:

They translate the sound waves to know the depth about that specific waves and translating it to transverse waves makes it easier.

Hope it helps :D

Explanation:

KE = 1/2mv^2

6,250 J =1/2(250kg) v ^2

6250 J = 125kgv^2

125kg. 125kg

v =

[tex] \sqrt{50} [/tex]

Answer:

Upward direction.

The friction is kinetic friction

Answer:

your answer is 21 n

Explanation:

Answer:

a.) Maximum height of the projectile. =32.5m

b.) The time it takes to reach the maximum height=2.6s

c.) Time of flight=2.6s

d.) Range=99.5m

Explanation:

Answer:

has any one finished the lab yet?????

Explanation:

The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.  

The potential energy can be calculated with the following equation:

[tex] E_{p} = mgh [/tex]

Where:

m: is the mass of the baseball

g: is the acceleration due to gravity

h: is the height

We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:

[tex] E_{p_{1}} = mg*1 = mg [/tex]  (1)

[tex] E_{p_{2}} = mg*2 = 2mg [/tex]   (2)

By entering equation (1) into 2 we have:

[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]

Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.

Therefore, the baseball held 2 m above the ground has more potential energy.

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I hope it helps you!

Answer:

0.16239316239316239316239

Explanation:

ang haba nang solve ko dito hehe

Answer:

steel is suitable for making permanent magnet

as still has hi factor coercity.

iron is for electromagnet and magnetic screen as iron loses its magnetism as soon as the switch is open and a current is switched off.

Steel is better suitable for making permanent magnets than soft iron since it has higher retentivity and lower coercivity. Compared to soft iron, steel has a lower retentivity and higher coercivity. Compared to soft iron, steel is more resilient and coercive.

Since , steels have high remanence which means it will remain magnetized even after magnetic field is removed which is not suitable for electromagnetic . iron has high permeability so magnetization is larger and have low retentivity so that material will not retain the magnetic properties . Magnetic screen ​, Iron has high permeability hence it can shield better than steel

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Answer:

Displacement a combination of distance

Explanation:

I'm not sure eh

Answer:

I am in favor of the dance event being in may. Because it is nice weather outside, more people will decide to come and spend their time there. It is also light in the evening in may, meaning that you could have the dance event at any time, and younger people will still feel safe at night, meaning their parents will be more open to lwtting kids go.

Answer:

1) The angle of projection of the ball is approximately 52.496° above the horizontal

2) The velocity with which the boy throws the ball to enable him accomplish his desire is approximately 14.769 m/s

Explanation:

In the projectile motion of the ball, the parameters are;

The distance the boy stands from the front of the house = 5 m

The depth of the house, front to back = 6 m

The height of the opening of the front window above him = 5 m

The height of the back window = 2 m higher than the front window

Therefore, the height of the back window = 5 m + 2 m = 7 m

1) The general formula for the vertical height of a parabolic projectile motion is given as follows;

y = a·x² + b·x + c

At y = 0, x = 0, therefore, c = 0

At y = 5, x = 5, we have;

5 = a·5² + b·5

∴ 5 = 25·a + 5·b...(1)

At y = 7, x = 11, we have;

7 = a·11² + b·11

7 = 121·a + 11·b...(2)

Making 'a' the subject of equation (1) and (2) and equating both values of 'a' gives;

For equation (1);

a = (5 - 5·b)/25 = 1/5 - b/5

a = 1/5 - b/5

For equation (2);

a = (7 - 11·b)/121 = 7/121 - b/11

a = 7/121 - b/11

∴ 1/5 - b/5 = 7/121 - b/11

1/5 - 7/121 = b/5 - b/11

86/605 = 6·b/55

b = (86/605) × (55/6) = 43/33

b = 43/33

a = 1/5 - b/5 = 1/5 - (43/33)/5 = -2/33

∴ y = (-2/33)·x² + (43/33)·x

The slope of the curve = dy/dx = d((-2/33)·x² + (43/33)·x)/dx = -4/33·x + 43/33

The slope of the curve at any point on the projectile = -4/33·x + 43/33

The slope at the origin is given by plugging x = 0  as follows

The slope at the origin = -4/33 × 0 + 43/33 = 43/33

The slope at the origin = tan(θ) = 43/33

Where;

θ = The angle of projection of the ball

∴ θ = arctan(43/33) ≈ 52.496°

The angle of projection of the ball, θ ≈ 52.496° above the horizontal

2) At the back widow, the equation for the vertical height, 'h', is given as follows;

[tex]h = (tan \angle \theta) \cdot x - \left(\dfrac{g}{2 \cdot v_1^2 \cdot cos^2 \angle \theta } \right )\cdot x^2[/tex]

Where;

h = The vertical height of the back window = 7 m

tan∠θ = 43/33

x = The horizontal distance of the back window from the boy = 5 m + 6 m = 11 m

g = The acceleration due to gravity = 9.8 m/s²

v₁ = The velocity with which the boy throws the ball

cos²∠θ = cos²(arctan(43/33)) = 1089/2938

Plugging in the values gives;

[tex]7 = \left (\dfrac{43}{33} \right) \times 11 - \left(\dfrac{9.8}{2 \cdot v_1^2 \cdot \dfrac{1089}{2938} } \right )\cdot 11^2[/tex]

[tex]\therefore v_1^2 = \dfrac{71981}{330}[/tex]

[tex]\therefore v_1 = \sqrt{\dfrac{71981}{330}} \approx \pm14.769[/tex]

The velocity with which the boy throws the ball to enable him accomplish his desire, v₁ ≈ 14.769 m/s.