what should you do with all lab equipment at the conclusion of a Lab
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Answer:

Make your question clear friend

Explanation:

...

Answer:

A grown man when living single will make lunch by himself for himself

Explanation:

Answer:

This question is incomplete but the completed question is below

Which Of These Species Is Most Likely To Be A Lewis Acid And Is Also Least Likely To Be A Brønsted Acid? (A) NH4⁺ (B) BF₃ (C) H₂O (D) OH⁻

The correct option is B

Explanation:

A lewis acid is a substance that accepts (or is capable of accepting) a pair of electrons. For example BF₃, while a lewis base is a substance that donates (or is capable of donating) a pair of electrons. For example OH⁻.

If we take a look at the boron (B) in BF₃, it has 3 electrons on it's outermost shell, each of which are bonded to flourine and can still accept a pair of electrons (lone pair). This makes it very likely to be a lewis acid.

Bronsted lowry acid is a substance that donates or can donate a proton or H⁺ (for example HCl) while bronsted lowry base is a substance that accepts or can accept a proton or H⁺ (for example NH₃).

BF₃ cannot donate a proton or H⁺ hence it is least likely to be called a bronsted acid.

Answer:

[tex]V=7.07L[/tex]

Explanation:

Hello,

In this case, for the statement:

"Calculate the volume in liters of a 0.133mol/L copper (II) sulfate solution that contains 150.g of copper (II) sulfate (CuSO4). Be sure your answer has the correct number of significant digits"

We initially have the molar concentration as well as the mass of the copper (II) sulfate, therefore, we must first compute the moles of the given compound considering its molar mass (159.54 g/mol):

[tex]n=150g*\frac{1mol}{159.54g}= 0.94mol[/tex]

Then, considering the definition of molar concentration or molarity, we compute the required volume as follows:

[tex]M=\frac{n}{V}\\ \\V=\frac{n}{M} =\frac{0.94mol}{0.133mol/L}\\ \\V=7.07L[/tex]

Best regards.

Answer:

C . ns²np²

Explanation:

According to this configuration the outermost orbit has 2 electrons in p and 2 electrons in s . After first ionization from p orbital  involving energy E₁ , second ionisation from p  is possible with E₂ energy . E₂ will be greater than E₁ .

But after second ionisation , there is no electron in p orbital . Hence the third ionisation is possible when we extract electron from s orbital . The difference in the ionisation energy of s and p is quite large . Hence third ionisation will involve much greater energy .

Hence third ionisation energy will be much larger than the second ionisation energy or

E₃ >>> E₂ .

Hence option ( C ) is correct .

The electron configuration that corresponds to the valence electrons of an element for which there is an especially large jump between the second and third ionization energies is ns2

Ionization energy is the energy required for the loss of an electron from an atom. The ionization energy is a periodic trend that decreases down the group but increases across the period.

A large jump occurs when the first electron is removed from an inner shell. If we look at the options, we will discover that the electron configuration that corresponds to the valence electrons of an element for which there is an especially large jump between the second and third ionization energies is a configuration in which there are two valence electrons. This happens to be ns2.

Learn more: https://brainly.com/question/12108425

Answer:

3.9 L of H2.

Explanation:

We'll begin by calculating the number of mole in 2.82 g of aluminium, Al.

This is illustrated below:

Mass of Al = 2.82 g

Molar mass of Al = 27 g/mol

Mole of Al =?

Mole = mass /Molar mass

Mole of Al = 2.82 / 27

Mole of Al = 0.104 mole

Next, we shall write the balanced equation for the reaction. This is given below:

2Al + 6HCI —> 2AlCl3 + 3H2

From the balanced equation above,

2 moles of Al reacted with 6 moles of HCl to produce 3 moles of H2.

Next, we shall determine the number of mole H2 produced by reacting 0.104 mole of Al.

This is illustrated below:

From the balanced equation above,

2 moles of Al reacted to produce 3 moles of H2.

Therefore, 0.104 mole of Al will react to produce = (0.104 x 3)/2 = 0.156 mole of H2.

Therefore, 0.156 mole of H2 was produced from the reaction.

Finally, we shall determine the volume of H2 produced by using the ideal gas equation as shown below:

Number of mole (n) of H2 = 0.156 mole

Pressure (P) = 769 torr = 769/760 = 1.01 atm

Temperature (T) = 35°C = 35°C + 273 = 308 K

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) of H2 =?

PV = nRT

1.01 x V = 0.156 x 0.0821 x 308

Divide both side by 1.01

V = (0.156 x 0.0821 x 308) /1.01

V = 3.9 L

Therefore, 3.9 L of H2 were produced from the reaction.

Answer:

2.954 g

Explanation:

One banana contains 422 mg

One banana weighs 118 g

To make our calculations easier, we will convert both unit to the same power, that is both of them will be in g.

422 mg = 422/1000 = 0.422 g

If one banana contains 0.422 g of potassium, then 7 bananas(since he eats 1 per day) will weigh

0.422 * 7 = 2.954 g

Thus, after a week, he would have ingested at least 2.954 g of potassium.

I hope you understand the explanations. Thanks

Answer:

2.13 V

Explanation:

The balanced equation of the reaction his;

2Cr^3+(aq) + 3Ca(s) -----> 2Cr(s) + 3Ca^2+(aq)

Since this is a galvanic cell then E°cell must be positive. It implies that calcium will be the anode and chromium will be the cathode since calcium is ahead of chromium in the electrochemical series.

E°anode= -2.87 V

E°cathode= -0.74 V

E°cell= E°cathode -E°anode

E°cell= -0.74 -(-2.87)

E°cell = 2.13 V

Answer:

2×10² cg

Explanation:

We'll begin by converting each of the above to the same unit of measurement.

In this case, we shall convert each of the above to kg. This can be obtained as follow:

Conversion of cg to kg

1 cg = 1×10¯⁵ Kg

Therefore,

2×10² cg = 2×10² × 1×10¯⁵

2×10² cg = 0.002 kg

Conversion of dg to Kg

1 dg = 1×10¯⁴ kg

Therefore,

10 dg = 10 × 1×10¯⁴

10 dg = 0.001 kg

Conversion of mg to kg.

1 mg = 1×10¯⁶ Kg

Therefore,

2×10² mg = 2×10² × 1×10¯⁶

2×10² mg = 0.0002 kg

Conversion of ng to kg

1 ng = 1×10¯¹² kg

Therefore,

1×10⁵ ng = 1×10⁵ × 1×10¯¹²

1×10⁵ ng = 0.0000001 Kg

Summary

1. 2×10² cg = 0.002 kg

2. 10 dg = 0.001 kg

3. 2×10² mg = 0.0002 kg

4. 0.001 kg

5. 1×10⁵ ng = 0.0000001 Kg

From the above calculation, 2×10² cg is the highest mass.

Answer:

[tex]15141.7\frac{in}{min}[/tex]

Explanation:

Hello,

In this case, by knowing that one inch equals 2.54 centimetres and 1 minute equals 60 seconds, the required velocity in inches per minute turns out:

[tex]641\frac{cm}{s}*\frac{1in}{2.54cm}*\frac{60s}{1min}}\\\\15141.7\frac{in}{min}[/tex]

Best regards.

Answer:

95.91 g/mol

Explanation:

You need to create an equation using the given information.

X  +  O₂  ⇒  X₂O₃

You now have to balance the equation

4 X  +  3 O₂  ⇒  2 X₂O₃

Using this information, you can solve for the molar mass of X.  First, convert grams of O₂ to moles.  The molar mass is 32.00 g/mol.

(27.5 g)/(32.00 g/mol) = 0.8594 mol O₂

Next, use the mole ratio in the chemical equation to convert moles of O₂ to moles of X.  

0.8594 mol O₂ × (4 mol X/3 mol O₂) = 1.146 mol X

Now that you have the moles, divide the given grams of X by the calculated value of moles.

(109.9 g)/(1.146 mol) = 95.91 g/mol

The molar mass of element X is 95.91 g/mol.

Answer:

[See Below]

Explanation:

48 or 49 ml.

Answer:

[tex]\mathbf{\Delta \ S^0 \ system \simeq -71.862 \ J/K}[/tex]

Explanation:

The chemical equation for the reaction is given as:

[tex]\mathsf{4 H Cl _{(g)} + O_{2(g)} \to 2H_2O _{(g)} + 2Cl_{2(g)}}[/tex]

the entropy change in the system can be calculated as follows:

[tex]\Delta S^0 \ system = \Delta S(products) - \Delta S (reactants)[/tex]

[tex]\Delta S^0 \ system = (2 \times \Delta S(H_2O )+2 \times \Delta S(Cl_2 ) ) - (4 \times \Delta S (HCl) + 1 \times \Delta S (O_2))[/tex]

From the tables; the entropy values where obtained.

∴

[tex]\Delta S^0 \ system = (2 \times(188.8 \ J/K )+2 \times ( 223.1 \ J/K )) - (4 \times \ ( 186.9 \ J/K ) + 1 \times ( 205.1 \ J/K ))[/tex]

[tex]\Delta S^0 \ system = (377.6 \ J/K +446.2 \ J/K )) - (747.6\ J/K ) + 205.1 \ J/K ))[/tex]

[tex]\Delta S^0 \ system = (377.6 \ J/K +446.2 \ J/K - 747.6\ J/K - 205.1 \ J/K )[/tex]

[tex]\Delta S^0 \ system = (-128.9 \ J/K )[/tex]

i.e the entropy change in the system when 4 moles of HCl is used = -128.9 J/K

∴

when 2.23 moles of HCl is used, Then,

[tex]\Delta \ S^0 \ system = \dfrac{-128.9 \ J/K }{4 \ mol } \times 2.23 \ mol[/tex]

[tex]\Delta \ S^0 \ system = -32.225 \ J/K \times 2.23[/tex]

[tex]\Delta \ S^0 \ system = -71.86175 \ J/K[/tex]

[tex]\mathbf{\Delta \ S^0 \ system \simeq -71.862 \ J/K}[/tex]

Answer:

4.83 km

Explanation:

Let's consider the following subtraction.

4.910 km - 0.08 km

For an addition or a subtraction, the rule for significant figures is as follows: limit the reported answer to the rightmost column that all numbers have significant figures in common, in this case, 2 figures after the decimal point.

4.910 km - 0.08 km = 4.83 km

Answer: ΔH°f of gaseous nitrogen monoxide is 148.0 kJ/mol

Explanation:

The balanced chemical reaction is,

[tex]NO(g)+\frac{1}{2}O_2(g)\rightarrow NO_2(g)[/tex]

The expression for enthalpy change is,

[tex]\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)][/tex]

[tex]\Delta H_{rxn}=[(n_{NO_2}\times \Delta H_f_{NO_2})]-[(n_{O_2}\times \Delta H_f_{O_2})+(n_{NO}\times \Delta H_f_{NO})][/tex]

where,

n = number of moles

[tex]\Delta H_{O_2}=0[/tex] (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

[tex]-114.14=[(1\times 33.90)]-[(\frac{1}{2}\times 0)+(1\times \Delta H_f{NO})][/tex]

[tex]\Delta H_f{NO}=148.0kJ/mol[/tex]

Therefore, ΔH°f of gaseous nitrogen monoxide is 148.0 kJ/mol

Answer:

43.7

Explanation:

Volume of gas = 1.00L

Time = 12 hours

Decrease in 1 balloon = 0.200L

Decrease in second balloon = 0.0603L

R1 = rate at which helium diffuses= 0.20/12= 0.0166

R2 = rate at which heavier gas diffuses = 0.0693/12 = 0.00502

Using grahms law

R1²/R2² = m/4

= 0.0166²/0.00502² = m/4

= 10.935 = m/4

When we cross multiply

m is the molar mass of heavier gas = 43.73

Answer:

10nm

Explanation:

Ultraviolet (UV) is a form of electromagnetic radiation with wavelength from 10 nm (with a corresponding frequency of approximately 30 PHz) to 400 nm (750 THz), shorter than that of visible light but longer than X-rays.

Answer:

B. ΔG > 0, Q > K

Explanation:

For reverse reaction to take place Q should be greater than K

Since reverse reaction should be spontaneous, forward reaction should be non spontaneous.

So, for forward reaction, ΔG > 0

Hence, the correct answer is B

Answer: True

Explanation:

Air is indeed a mixture as the component compounds and mixtures retain their individual properties as opposed to a compound that sees the component elements lose some of theirs.

Air is a type of mixture known as a homogeneous mixture which means that no matter what quantity of air is present, the composite elements (Oxygen, nitrogen etc) and compounds( carbon dioxide etc) are of the same quantity.  

Answer:

True

Explanation:

Answer:

KE=720 joule

Explanation:

[tex]K.E.=\frac{1}{2}mv^{2}\\ KE=\frac{1}{2} *10 kg*12m/s^{2} \\KE=\frac{1}{2}*1440\\ KE=720 joule[/tex]

Answer:

Ionic bond

Explanation:

The main component of quicklime is calcium oxide, whose chemical formula is CaO.

Ca is a metal with 2 electrons in its valence shell.

O is a nonmetal with 6 electrons in its valence shell.

Ca and O form a ionic bond, in which Ca loses 2 electrons and O wins 2 electrons, so that both obey the octet rule.

Answer:

[tex]m_{solute}=3.62g\\\\m_{solvent}=57.38g[/tex]

Explanation:

Hello,

In this case, since the given concentration is molality, we have:

[tex]m=\frac{mol_{solute}}{mass_{solvent}}[/tex]

Whereas the mass of the solvent (water for aqueous solution) is given in kg. Moreover, since the total mass of the solution is 61.0 g, one could write:

[tex]m_{solute}+m_{solvent}=61.0h\\\\m_{solvent}=61.0g-m_{solute}[/tex]

Which is replaced in the definition of molality:

[tex]m=\frac{mass_{solute}*\frac{1mol}{119g} }{(61.0g-m_{solute})*\frac{1kg}{1000g} }\\\\0.530m=\frac{8.4mass_{solute}}{61.0-mass_{solute}}[/tex]

Thus, solving for the mass of solution we obtain:

[tex]mass_{solute}=3.62g[/tex]

Therefore, the mass of the solvent is:

[tex]m_{solvent}=61.0g-3.62g\\\\m_{solvent}=57.38g[/tex]

Best regards.

Answer:

1.27006 kg

Explanation:

1 lb is equal to 0.907185 kg

Answer:

Chemical change: c, f

Chemical property: a, g

Physical change: b, e

Physical property: d, h

Explanation:

Chemical properties and changes refer to things that change the chemical structure of the substance in question -- things like rusting, setting on fire, or becoming more acidic.

Physical properties and changes have to do with shape or form, which still keep the same chemical structure -- things like how something looks or smells, or changing a substance from gas to liquid to solid

Chemical Change:c,f

Chemical property:a,g

Physical change:b,e

Physical property:d,h

Answer:

You must add 13.86g of I₂

Explanation:

In the reaction:

5 P₄O₆ + 8I₂ → 4P₂I₄ + 3P₄O₁₀

5 moles of P₄O₆ reacts with 8 moles of I₂.

First, we need to determine how many moles of I₂ reacts completely with 7.15g of P₄O₆ (Molar mass: 219.88g/mol, thus:

7.15g P₄O₆ * (1mol / 219.88g) = 0.0325 moles P₄O₆.

Using the chemical reaction, the moles of I₂ that reacts are:

0.0325 moles P₄O₆ * ( 8 moles I₂ / 5 moles P₄O₆) = 0.0520 moles of I₂ react completely.

As molar mass of I₂ is 253.81g/mol, the mass of I₂ that reacts completely is:

0.0520 moles of I₂ * (253.81g / mol) =

13.2g of I₂.

As you must add 5.00% of excess:

13.2g + 5%13.2g =

You must add 13.86g of I₂

Answer:

n = 2 to n = 9

Explanation:

Atoms absorb energy when they move from a lower to a higher energy level. The magnitude of energy absorption depends on the difference in energy between the initial and final orbitals.

Hence; ∆E= Ef - Ei

Where;

Ef= energy of the final orbital

Ei= energy of the initial orbital

Considering the energy difference between n=9 and n=2, the highest amount of energy is absorbed during this transition.

Answer:

The periodic table is a table displaying each element and information about the elements, for example atomic number and chemical properties. This is necessary because without it it would be very hard to find information on the elements.

Answer:

more rapid

Explanation:

A higher temperature of fresh concrete results in a more rapid hydration of cement. This causes reduction in the setting time of the cement, also known as accelerated setting of the cement.

It also reduces the workability of the concrete; as it makes the movement of aggregates harder by reducing the lubricating effect of the cement.

Answer:

= - 0.38 eV

Explanation:

Using Bohr's equation for the energy of an electron in the nth orbital,

E = -13.6 [tex]\frac{Z^{2} }{n^{2} }[/tex]

Where E = energy level in electron volt (eV)

Z = atomic number of atom

n = principal state

Given that n = 6

⇒ E = -13.6 × [tex]\frac{1^{2} }{6^{2} }[/tex]

= - 0.38 eV

Hope this was helpful.

Answer:

A

Explanation:

Answer:Im not sure ABT THIS ONE

Explanation: