The key features that should be present in the IR spectrum of your product if you successfully made the desired bromohydrin and the key features that should be absent from the IR spectrum if the starting material was completely reacted are the spectra of the other alcohols.
The spectra of the other alcohols utilized in the synthesis indicate the presence of bromohydrin. The presence of Bromohydrin with the Hydroxyl stretch characteristic demonstrates the presence of alcohol
What is bromohydrin?Bromonydrin is formed by the addition of Br and OH across an alkene, and the result is known as a bromohydrin (bromo=bromine, hydrin=hydro, water/H₂O).
The synthesis of bromohydrins includes extremely regioselective ring expansion of epoxides to halohydrins using hydrogen and lithium halides in the presence of -cyclodextrin in water as a solvent.
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If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the structure A central X atom has two lone pairs. Two Y atoms are attached to X with single bonds, could be abbreviated as XY2Z2.Classify these structures by the hybridization of the central atom.HYBRIDIZATIONS:1. sp2. sp23. sp34. sp3d5. sp3d2ABREVIATIONS:1) XY22) XY33) XY44) XY55) XY66) XY2Z37) XY2Z8) XY3Z29) XY4Z10) XY4Z211) XY3Z12) XY5Z13) XY2Z2
The following hybridization states are applicable for the various abbreviations displayed:
sp = XY₂sp² = XY₂Z, XY₃ sp3³ = XY₄, XY₂Z₂, XY₃Zsp³d = XY₅, XY₂Z₃, XY₃Z₂, XY₄Zsp³d² = XY₆, XY₄Z₂, XY₅ZThe number of electron pairs surrounding the core atom in a molecule affects its hybridization state.
The idea of hybridization is an approximation that describes the bonding in some chemical species by mixing atomic orbitals of various energies to generate orbitals of suitable energies that can be employed in chemical combinations.
The number of electron pairs that surround the center atom determines its hybridization state in a molecule.
2 electron pairs result in sp hybridization.
Sp2 hybridization is caused by three electron pairs.
Sp3 hybridization is caused by 4 electron pairs.
Sp3d hybridization is caused by 5 electron pairs.
Sp3d2 hybridization is caused by 6 electron pairs.
Remember that the molecule's core atom is surrounded by both bond pairs (Y) and lone pairs (Z) of electrons.
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how many minutes will it take to plate out 2.19 g of chromium metal from a solution of cr3 using a current of 55.2 amps in an electrolyte cell?
3.69 minutes will be needed to plate the chromium metal in the solution.
The charge transfer amount may be provided by:
q = It
where I is the current, t is the time, and q is the charge transfer
Q can be calculated by:
Moles of Cr = 0.0423 mole; As, moles = 2.19/51.9
Also, there is transfer of 3 electrons, thus, charge transfer will be faraday constant multiplied by 3
Charge transfer = 0.0423 *3* 96500 C
Charge transfer = 12245.85 C
As, q = it
12245.85 = 55.2 * Time
Time = 221.845 sec = 3.69 min
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calculate the ph of 1.00 l of a buffer that is 1.00 m in acetic acid and 1.00 m in sodium acetate after the addition of 0.900 mole of naoh.
The ph of 1.00 l of a buffer that is 1.00 m in acetic acid and 1.00 m in sodium acetate after the addition of 0.900 mole of naoh is 5.28.
initial moles of sodium acetate = acetic acid = 1 m * 1 L = 1 moles
[ acetate ] after adding NaOH = 1 mol+ 0.55 mol = 1.55 M
[acetic acid] after adding NaOH = 1 mol - 0.55 mol = 0.45 M
According to Handerson-Hasselblach equation:
PH = Pka + ㏒ [ acetate]/[acetic acid]
when Pka = 4.74
so, by substitution:
∴PH = 4.74 + ㏒[1.55/0.45]
∴ PH = 5.28
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Identify the products of the reaction that will be carried out in biodiesel synthesis lab:
A. Fatty esters
B. Sodium hydroxide
C. Propane-1,2,3-triol
D. Triglyceride
E. Methanol
Transesterification is a three-step process where a triglyceride is converted into diglycerides, followed by monoglycerides, in a sequential order.
What are fatty acids?Fatty acid may be defined as an organic compound that generally consists of a straight chain of carbon atoms, with hydrogen atoms along the length of the chain and at one end of the chain and a carboxyl group at the other end.The synthesis of fatty acid is the formation of fatty compounds from acetyl- CoA and NADPH with the action of an enzyme known as fatty acid synthases. This process of fatty acid synthesis significantly takes place in the cytoplasm as well as the endoplasmic reticulum of the cell.Triglycerol is formed with the help of adjoining three fatty acids to a glycerol backbone. This process involves the dehydration reaction. This is because three molecules of water are released in the process of fatty acid synthesis.Therefore, in fat synthesis, glycerol and fatty acids combine to make fats plus water. Thus, the correct answer is A.To learn more about Fatty acid synthesis, refer to the link:
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Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of h+ and fe3+ in the balanced reaction?.
The coefficient of in the balanced equation is 8 and coefficient of fe3+ is 5.
What is balance reaction?
balance reaction is a equation where the numbers of atom of each type in the reaction is the same on both reactance and product sides.
To balance a redox reaction in the acidic medium, the number of atoms of all the elements involved in the reaction must be equal for substrates and product.
The reaction given as-
Fe2+MnO4+------>Fe3+ +Mn3+
The change in the oxidation number of the elements on reaction is seen.
Fe changes its oxidation state from +2 +3, change is +1
The oxidation state of Mn changes from +7 +2, change is -5
There is required 5 atoms of Fe for 1 atom of Mn.
With this, the equation can be written as:
The reaction is further balanced with H and O, with formation of .
The coefficient in front of is 8 and that of is 5.
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what species are made at the anode and cathode, respectively, during the electrolysis of molten kbr? a) br⁻(aq) and k⁺(aq) b) k(l) and br⁻(aq) c) br₂(g) and k(l) d) br₂(g) kbr(l) e) br⁻(aq) k(l)
Br₂(g) and K(l) species are made at the anode and cathode, respectively, during the electrolysis of molten kbr .
The term "electrolysis" describes the use of an electric current to break down a chemical. An illustration of this is the deposit of sodium and chlorine at various electrodes when the current is run through molten sodium chloride. Thus, sodium and chlorine are formed as sodium chloride breaks down. The cathode, also known as the positive or oxidizing electrode, is reduced during the electrochemical reaction after receiving electrons from the external circuit. Cations (positively charged ions) give rise to cathodes, while anions give rise to anodes. The cathode is the electrode that is negatively charged in an electrical device.
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in class we derived the regular solution model for a binary system . the free energy of mixing for the solution model is (expressed per mole):
Answer:
A. Gmir ZuXAXB + RT (XA lnXA + XB ln Xp) Where W = WAB (WAA + WBB) and Z = the coordination number of each atom in the crystal.
Explanation:
Free enthalpy is another name for Gibbs's free energy. The energy associated with a chemical reaction needed to carry out work is known as Gibbs-free energy.
The formula: can be used to compute Gibbs free energy.
ΔG=ΔH-TΔS.
The difference between the reaction's enthalpy and its product of changing temperature and entropy yields the Gibbs free energy.
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in an experiement, 5 g of licl is dissolved into 40 ml of water orginally at 17 c in a calorimeter. the temperature rises to 40.3. determine the molar heat of solution of li cl
Moler Heat of solution is 32.7 kJ/mol
The molar heat of a solution(ΔH) is calculated by the formula
ΔH=q/n
Where, n-Number of moles
q- Energy of the system
q is calculated by the formula
q=m×c×ΔT
Where ΔT=(T_f-T_i)
T_f=40.3°C, T_i=17°C
ΔT=(40.3-17)°C=23.3°C
c=4.18 J/g°C
The mass of water is
m=40 ml×(1 g/1 ml)=40 g
Substitute all values in the formula
q=40g×(4.18 J/g°C)×23.3°C
q=3895.76 J
The molar mass of LiCl is 42g/mol.
The moles of LiCl =5g×(1 mol/42 g)=0.11905 mol
Hence, the molar heat of a solution is
ΔH=3895.76 J/0.11905 mol =32723.7295 J/mol
Convert the value in kJ
ΔH=32723.7295 J/mol×(1 kJ/1000 J)=32.7 kJ/mol
Therefore, the molar heat of a solution is 32.7 kJ/mol.
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Double Replacement Worksheet
Write the formula unit equation for this reaction occuring in water: Barium perchloate and sodium sulfate are mixed to form sodium perchlorate and barium sulfate.
1. Na2SO4(aq) + Ba(ClO)2(aq) → 2 NaClO(aq) + BaSO4(s)
2. Na2SO4(aq) + Ba(ClO3)2(s) → 2 NaClO3(aq) + BaSO4(s)
3. Na2SO4(aq) + Ba(ClO3)2(aq) → 2 NaClO3(aq) + BaSO4(s)
4. Na2SO4(aq) + Ba(ClO4)2(aq) → 2 NaClO4(s) + BaSO4(aq)
5. Na2SO4(s) + Ba(ClO4)2(aq) → 2 NaClO4(s) + BaSO4(aq)
6. Na2SO4(aq) + Ba(ClO4)2(s) → 2 NaClO4(aq) + BaSO4(s)
7. Na2SO4(aq) + Ba(ClO4)2(aq) → 2 NaClO4(aq) + BaSO4(s)
The formula unit when barium perchlorate reacts with sodium sulfate to produce sodium perchlorate and barium sulfate would be: [tex]Ba(ClO_4)_2 (aq) + Na_2SO_4 (aq) -- > 2NaClO_4 (aq) + BaSO_4 (s)[/tex]
Chemical reactionThe reaction between barium perchlorate and sodium sulfate to produce sodium perchlorate and barium sulfate is a double decomposition reaction whose chemical equation can be derived as follows:
Formula for sodium sulfate = [tex]Na_2SO_4[/tex]
Formula for barium perchlorate = [tex]Ba(ClO_4)_2[/tex]
Formula for sodium perchlorate = [tex]NaClO_4[/tex]
Formula for barium sulfate = [tex]BaSO_4[/tex]
Since barium sulfate is insoluble, the chemical equation for the reaction would be:
[tex]Ba(ClO_4)_2 (aq) + Na_2SO_4 (aq) -- > 2NaClO_4 (aq) + BaSO_4 (s)[/tex]
In other words, a double decomposition reaction can also be a precipitation reaction in which two aqueous salts exchange radicals to produce one aqueous and one insoluble salt.
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when an exothermic reaction is carried out in a coffee-cup calorimeter, what statement is correct? a. qwater is negative. b. the enthalpy of the products is lower than that of the reactants. c. the temperature of the water decreases. d. the enthalpy change for the reaction is positive. e. the reaction absorbs heat from the water.
The correct statement about an exothermic reaction carried out in a coffee-cup calorimeter is that the enthalpy of the products is lower than that of the reactants. Therefore, the correct answer is option B.
Exothermic reaction is a term that means the heat will be released during the reaction, making the environment warmer. In a coffee-cup calorimeter, the heat increases the temperature of coffee contents, which includes water.
In an exothermic reaction, the enthalpy of the product will be lower than that of reactants (B is correct).
During the reaction, heat is released so the water temperature will increase (C and E are incorrect).
Since the enthalpy of the product is lower, the enthalpy change will be negative (D is incorrect).
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Which of the following statements about Lewis bases is TRUE?a) Lewis bases are electron pair acceptors.b) Lewis bases are electron pair donors.c) Lewis bases are proton donors.d) Lewis bases are proton acceptors.
The true statement is b- Lewis bases are electron pair donors. Lewis bases are referred to as species that have extra electrons and have the tendency to give electrons to Lewis acids that have empty orbitals.
What is Lewis base?
Any substance that has the ability to give a pair of nonbonding electrons, such as the OH- ion, is considered a Lewis base. Therefore, a Lewis base is an electron-pair donor.
The correct answer is option B.
Lewis bases provide extra electrons to species with empty orbitals since they have filled orbitals compared to their own. Lewis bases are therefore electron donors, providing option (B) the proper choice.
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a 25.0 ml sample of 0.105 m hcl was titrated with 31.5 ml of naoh. what is the concentration of the naoh? group of answer choices 0.075 m 0.105 m 0.132 m 0.0833 m none of the above
A 25.0 ml sample of 0.105 m HCl was titrated with 31.5 ml of NaOH. the concentration of the NaOH is 0.0833 M.
given that :
molarity of HCl, M1 = 0.105 M
volume of HCl V1 = 25 mL
Molarity of NaOH M2 = ?
volume of NaOHV2 = 31.5 mL
by using the titration equation we get :
molarity of HCl × volume of HCl = molarity of NaOH × volume of NaOH
M1 V1 = M2 V2
M2 = (M1 V1 ) / V2
M2 = ( 0.105 × 25 ) / 31.5
M2 = 0.0833 M
The concentration of NaOH = 0.0833 M.
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Suppose 9.07 g of copper(II) nitrate is dissolved in 100. mL of a 0.70 M aqueous solution of sodium chromate Calculate the final molarity of copper(II) cation in the solution. You can assume the volume of the solution doesn't change when the copper(II) nitrate is dissolved in it. Be sure your answer has the correct number of significant digits.
Suppose 9.07 g of copper(II) nitrate is dissolved in 100. mL of a 0.70 M aqueous solution of sodium chromate the final molarity of copper(II) cation in the solution will be 0.48 M
The balanced equation is given as :
Cu(NO3)2 + Na2CrO4 = CuCrO4 + 2NaNO3
Number of mol of copper nitrate = mass /molar mass
= 9.07 g/187.5 g/mol
= 0.048 mol
mol sodium chromate = molarity x volume (L)
= 0.70 M x 0.100 L
mol sodium chromate = 0.07 mol
so copper nitrate is limiting
So number of mol of copper (II) cation will be 0.048 mol
molarity = mol/volume (L)
= 0.048 mol / 0.100 L
= 0.48 M
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A
solution of NaOH contains.
11.6 grams of solute to 150cm³ of
solution. What is the molarity
of
the solution?
Answer:
1.93 molar, or M
Explanation:
By definition, molarity is defined as moles/liter. A 0.5 molar (or M) solution will have 0.5 moles of solute per 1.0 liter. To answer this question, first calculate how many moles of NaOH there are in 11.6 grams of the compound. We'll need the miolar mass of NaOH, which is 40 grams/mole. This is found by adding the atomic masses of each atom in the compound:
Na: 23
O: 16
H: 1
Total: 40 g/mole
The moles of NaOH is found by dividing the mass by the molar mass:
(11.6 grams NaOH)/(40 g/mole NaOH) = 0.29 moles NaOH
0.29 moles NaOH is contained in 15cm^3 of solution. Convert 15cm^3 into liters (L):
(15 cm^3)*(1 ml/cm^3)*(1 liter/1000 ml) = 0.015 liters
cm^3 and ml both cancel with these conversion factors, leaving only liters, L.
The solution consists of 0.29 moles of NaOH in 0.15L. It's concentration is therefore:
(0.29 moles)/(0.015L) = 1.93 molar, or M
the degree to which all clastic sediments in a deposit are the same swize or mass is described by the of the sediment
Sorting indicates the degree to which all clastic sediments in a deposit are the same swize or mass is described by the of the sediment
Sorting involves putting information in a meaningful order so you may evaluate it more efficiently. Water will sink objects that are heavier than it. like an iron nail, etc. Sorting is the process of putting things with comparable characteristics in groups. According to how similar or different their qualities are, the materials can be categorized.
Seawater or lake water is used in mineral deposits. … It is recognized as a chemical sediment due to the fact that the mineral components are carried in solution before precipitating to form a sediment as a result of a chemical reaction.
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how many milliters of 1.00 m koh should be added to 100 ml of solution containing 10.0 g of histidine hydrochloride (his.hcl fm 191.62) to get a ph of 9.30?.
52.18mL of KOH should be added to 100 mL of solution containing 10.0 g of histidine hydrochloride to get a pH of 9.30.
What is pH?
pH is a measurement of the acidity or basicity of aqueous or other liquid solutions in terms of digits. The phrase, which is frequently used in chemistry, biology, and agronomy, converts hydrogen ion concentrations, which typically vary between 1 and 1014 gram-equivalents per liter, into numbers between 0 and 14.
Given:
pH = 9.30
pH = -log [[tex]H^{+}[/tex]]
9.30 = -log [[tex]H^{+}[/tex]]
antilog (-9.30) = [[tex]H^{+}[/tex]]
[[tex]H^{+}[/tex]] = 5.01 × [tex]10^{-10}[/tex] M
Strong acid (His HCl) + strong base (KOH)
[[tex]H^{+}[/tex]] = [tex]\frac{-M_{B}V_{B}n_{fB} + M_{A}V_{A}n_{fA}}{V_{final}}[/tex]
[tex]M_{B}[/tex] and [tex]M_{A}[/tex]= Molarity
[tex]V_{A}[/tex] and [tex]V_{B}[/tex] = Volume
[tex]n_{fA}[/tex] = n factor for acid
[tex]n_{fB}[/tex] = n factor for KOH
5.01 × [tex]10^{-10}[/tex] M = [tex]\frac{-1 M X V_{B} X 1 + 0.52 X 100 X 1 }{V_{A} + V_{B} }[/tex]
= [tex]\frac{-V_{B} + 52.18 }{100 + V_{B} }[/tex]
[tex]n_{fB}[/tex] = [tex]n_{fn}[/tex] = 1
5.01 × [tex]10^{-10}[/tex] M (100 + [tex]V_{B}[/tex] )= [tex]V_{B} - 52.18[/tex]
5.01 × [tex]10^{-10}[/tex] + 5.01 × [tex]10^{-10}[/tex] [tex]V_{B}[/tex] = -[tex]V_{B}[/tex] + 52.18
2.18 - 5.01 × [tex]10^{-8}[/tex] = 5.01 × [tex]10^{-10}[/tex] [tex]V_{B}[/tex] + [tex]V_{B}[/tex]
[tex]V_{B}[/tex] = 52.17999 mL ≅ 52.18mL of KOH.
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In general, how can you determine the mass number of the daughter product after alpha decay has taken place? how can you determine the atomic number?.
to determine the mass number of the daughter product after alpha decay has taken place Subtraction of 4 from the parent element yields the mass of the daughter product. Subtraction of 2 from the parent atom yields the atomic number of the daughter product.
Assume X is a parent element with atomic number Z and mass number A; if X decays, we obtain a daughter element Y with atomic number Z1 and mass number A1, as well as an alpha particle with atomic mass 2 and mass number 4. An alpha particle is a doubly ionised Helium atom with atomic number 2 and mass number 4.
Alpha degeneration
X4 → YA¹ + He.
The mass numbers and atomic numbers of a reaction must be balanced on either side of the equation.
→ A=A1+4
Z = Z1+2
As a result, A1 = A-4 and Z1 = Z-2.
As a result, subtracting 4 from the parent element yields the mass of the daughter product.
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suppose a 25.00 ml sample of a solution of a diprotic acid of unknown concentration requires 18.73 ml of a solution of 0.300 m koh to reach the end point. what is the molarity of the diprotic acid?
The molarity of the diprotic acid that requires 18.73 mL KOH is 1.405 M.
The chemical reaction between a diprotic acid and KOH is
H₂A + 2 KOH → K₂A + 2 H₂O
In stoichiometry, we learn the chemical reaction and the laws that work in it. According to Avogadro's law, the coefficient of a substance in a chemical reaction expresses the ratio of the number of moles of each substance.
[tex]M \:=\: \frac{n}{V}[/tex]
n = MV
n = the number of moles (mol)M = the molarity (M)V = the volume (L)KOH
The volume V = 18.73 mLThe molarity M = 0.300 MThe number of moles for KOHThe number of moles for a diprotic acid
n KOH : n H₂A = 2 : 1
n H₂A = n KOH ÷ 2
n H₂A = 5.619 ÷ 2
n H₂A = 2.8095 mmol
The molarity of a diprotic acid
[tex]M \:=\: \frac{n}{V}[/tex]
[tex]M \:=\: \frac{2.8095}{25.00}[/tex]
M = 1.405 M
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an ideal gas has a density of 1.38×10−6 g/cm3 at 1.00 × 10 −3 atm and 80.0 ∘c . identify the gas. an ideal gas has a density of 1.38×10−6 at 1.0010 and 80.0 . identify the gas. argon chlorine neon hydrogen oxygen nitrogen
The calculated mass shows that the given mass is oxygen.
calculation:-
P=m/v by arranging the equation we get
R =0.082atm/mol/k
Mm=pRT/P = [(1.10 x10^-6 x1000g/l) xo.082
atm/mol/k x(80+273] /(1.00 x10^-3) = 31.84 to the nearest ten is 32.
The ideal gas density depends on the molecular weight temperature and pressure of the system. Density is an important parameter in heat and mass transfer calculations. It is also used to derive many important dimensionless numbers such as the Reynolds number and the Peclet number.
Real gases approach ideal gas behavior at relatively low densities low pressures, and high temperatures. At high temperatures, the gas molecules have enough kinetic energy to overcome the intermolecular forces, but at low temperatures, the gas has less kinetic energy, so the intermolecular forces are more pronounced.
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If a sulfuric acid (H₂SO₄, MM = 98.09 g/mol) solution is completely neutralized with 61.37 mL of the NaOH solution above what was the mass in grams of sulfuric acid in the solution. Remember, you need a balanced chemical reaction for stoichiometry. (do not forget about SF)
The mass of the reacted sulfuric acid in solution is 3.01 g.
What is a reaction?The reaction that we have here involves the combination of an acid and a base and result of such a reaction is that we would have salt and water as the products.
From the equation of the reaction;
2 NaOH (aq) + H₂SO₄ (aq) ----> Na₂SO₄ (aq) + 2 H₂O (l)
We can see that the mole ratio of the reaction is 2:1
Number of moles of sodium hydroxide = concentration * volume in liters
If the concentration of the NaOH solution is 1.0 M
Moles of NaOH reacted = 1.0 * 61.37 mL * 1 L / 1000 mL
= 0.06137 moles
Moles of H₂SO₄ reacted = 0.0614 / 2
= 0.0307 moles
Mass of H₂SO₄ reacted = 0.0307 * 98.09
= 3.01 g
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During which changes of state do atoms overcome the attractive forces between them?freezing and condensationboiling and depositioncondensation and meltingvaporization and sublimation.
Answer:
Vaporisation and Sublimation
Explanation:
Vaporisation is conversion of liquid to gas. Atoms in the liquid overcome forces of attraction to turn into gas.
Sublimation is direct conversion of solid to gas. Atoms in the solid directly convert into gas by overcoming forces of attraction. E.g - Dry Ice
using the product isolation portion of the reaction, you extracted your reaction mixture with nahco3(aq). what did this accomplish? be specific in your answer.
Fischer esterification is a reaction that converts carboxylic acid in presence of alcohol and strong acid catalyst to give ester as final product. Thus, NaHCO³ is one of the strong acid catalyst used in this reaction.
What is role of NaHCO³ in Fischer reaction?
Fischer reaction is a reaction between carboxylic acid and alcohol. When this reaction occurs, the product may contain some unreacted amount of carboxylic acid or acidic catalyst. Hence it is necessary to remove this and thus, this is accomplished by NaHCO³.
The reaction given below shows that how NaHCO3 dissociates and the bicarbonate anion reacts with unreacted proton to give unstable carbonic acid which dissociate to give water and carbon dioxide.
NaHCO3 = Na + + HCO3-
H+ + HCO3 - = H2O + CO2
Sodium bicarbonate also reacts with unreacted carboxylic acid whose reaction is shown below:
RCOOH +NaHCO3 = RCOO- Na+ + CO2+ H2O
RCOONa easily gets dissolve to polar solvent water and get separated.
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what is a chemical equation? what is a chemical equation? it is any type of reaction that takes place at the equator. it is a shorthand notation for illustrating a chemical reaction. it is a picture of the atoms undergoing a chemical equalization. it is the sum of the masses of the products and reactants. it is the chemical combination of equal numbers of reactants and products.
They are equations that represent chemical reactions using chemical formulae and symbols. In a chemical equation, the reactants are represented on the left, and the products are shown on the right.
Chemical equations are used to represent chemical reactions using symbols and substance formulae. A and B are referred to in this equation as the reactants, and C and D are referred to as the products. The chemical reaction's direction is indicated by the arrow.
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35 g al(s) reacts with excess hcl(aq) according to the chemical equation shown above. what is the volume (in l) of h2 gas produced at a temperature of 345 k and a pressure of 1.12 atm?
35 g al(s) reacts with excess hcl(aq) according to the chemical equation shown above. what is the volume (in l) of h2 gas produced at a temperature of 345 k and a pressure of 1.12 atm?
2Al(s) + 6HCl(aq) ----------------> 2AlCl3(aq) + 3H2(g)
3 moles of H2 produced from 2 moles of Al
3*2g of H2 produced from 2*27g of Al
75g of H2 produced from = 2*27*75/(3*2) = 675g of Al >>>>answer
2Al(s) + 6HCl(aq) ----------------> 2AlCl3(aq) + 3H2(g)
2 moles of Al react with 6 moles of HCl
2*27g of Al react with 6 moles of HCl
4.25g of Al react with = 6mole*4.25g/(2*27g) = 0.472 moles of HCl
no of moles of HCl = molarity * volume in L
0.472 = 5*volume in L
volume in L = 0.472/5 = 0.0944 L = 94.4ml >>>>answer
2Al(s) + 6HCl(aq) ----------------> 2AlCl3(aq) + 3H2(g)
2 moles of Al react with excess of HCl 3 moles of H2
2*27g of Al react with excess of HCl 3 moles of H2
35g of Al react with excess of HCl = 3*35/(2*27) = 1.94 moles of H2
n = 1.94moles
T = 345K
P = 1.12atm
PV = nRT
V = nRT/P
= 1.94*0.0821*345/(1.12) = 49.1 L of H2 >>>>answer
part-D
no of moles of Al = W/G.M.Wt
= 125/27 = 4.63moles
no of moles of HCl = molarity *volume in L
= 3.2*2.5 = 8moles
2Al(s) + 6HCl(aq) ----------------> 2AlCl3(aq) + 3H2(g)
2 moles of Al react with 6 moles of HCl
4.63 moles of Al react with = 6*4.63/2 = 13.89 moles of HCl is required
HCl is limiting reactant
6 moles of HCl react with excess of Al to gives 3 moles of H2
8 moles of HCl react with excess of Al to gives = 3*8/6 = 4 moles of H2
theoretical yield of H2 = no of moles * gram mola rmass
= 4*2 = 8g
A chemical is any substance that has a described composition. In other phrases, a chemical is continually made up of the identical "stuff." a few chemical compounds occur in nature, such as water.
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A structure containing a central atom with two electron groups, designated ax2, has a _____ shape with a bond angle of _____ degrees.
A structure containing a central atom with two electron groups, designated ax2, has a Linear shape with a bond angle of 180 degrees.
The geometry surrounding a central atom that is joined to two additional atoms (or ligands) at a bond angle of 180° is known as the linear molecular geometry in chemistry. When describing linear organic compounds with carbon centers, such as acetylene (HCCH), sp orbital hybridization is frequently used.
Linear geometry occurs at central atoms with two linked atoms and zero to three lone pairs (AX2 or AX2E3) in the AXE nomenclature, according to the Valence Shell Electron Pair Repulsion (VSEPR) hypothesis. Beryllium fluoride (FBeF) has two single bonds, carbon dioxide (O=C=O) has two double bonds, and hydrogen cyanide (HCN) has one single bond and one triple bond, all of which are neutral AX2 molecules.
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Marie anne lavoisier drew illustrations of the equipment she and her husband used in their experiments. Why was this important?.
Marie Anne Lavoisier realized how crucial it was to create drawings of the tools she and her husband employed in their research. In order to impart knowledge, this is crucial.
It is widely acknowledged that Lavoisier's major contributions to chemistry came mostly from his transformation of the field from a qualitative to a quantitative one. The discovery of the function of oxygen in combustion is what made Lavoisier famous. He challenged the phlogiston idea and identified and called the elements oxygen and hydrogen (1778). Lavoisier contributed to the development of the metric system, created the first comprehensive list of elements, and reformed chemical nomenclature. In addition to discovering that matter's mass never changes despite its form or shape, he also anticipated the creation of silicon in 1787. Lavoisier served as the general manager of the Ferme and was a key member of several aristocratic councils
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Why are a weak acid and the salt of its conjugate base used in preparing a buffer, rather than a strong acid and a salt of its conjugate base?.
An acid is more acidic than its conjugate base if its pKa value is less than or equal to seven prepared a buffer solution .
When making a buffer, why do you utilize a weak acid and the salt of its conjugate base?A weak acid and its conjugate base are present in high amounts in buffer solutions (or a weak base and its conjugate acid). Buffers are extremely resistant to fluctuations in pH because these ingredients may neutralize extra H+ or OH.
Why is it necessary to create a buffer solution using both an acid and a base?In buffers, basic species are present to neutralize H + ions and acidic species to do the opposite. These two species must, nevertheless, be able to coexist in a solution without fully negating one another.
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consider the redox reaction 3ni2 (aq) 2co(s)⟶2co3 (aq) 3ni(s) which substance gets oxidized? co3 ni co ni2
In this equation there's a little mistake, Co never suggests -three kingdoms, therefore, it ought to be + three.
Redox is a kind of chemical response in which the oxidation states of substrate trade. Oxidation is the loss of electrons or a boom inside the oxidation kingdom, whilst discount is the benefit of electrons or a lower in the oxidation nation.
An oxidation-discount redox response is a form of chemical reaction that involves a switch of electrons between species. An oxidation-reduction response is any chemical reaction wherein the oxidation range of a molecule, atom, or ion changes by means of gaining or losing an electron.
The five principal sorts of redox reactions are aggregate, decomposition, displacement, combustion, and disproportionation.
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A chunk of dry ice, solid co2, disappears after sitting at room temperature for a while. There is no puddle of liquid. What happened?.
After a while at room temperature, a piece of dry ice, or solid CO2, vanishes without leaving a puddle of liquid behind.
What is solid CO2?Dry ice, which is a solid form of carbon dioxide, is available. When used for short-term refrigeration, CO2 is usually used because it frequently sublimates from the solid form to the gas state due to the fact that it does not have a liquid state at normal atmospheric pressure. Carbon dioxide that is solid is known as "dry ice." Due to its ice-like appearance and the fact that it truly sublimes rather than melting, dry ice appears to be made of ice. Because the solid does not first become a liquid when heated, it is known as dry ice.
What is solid CO2 used for?Dry ice, also known as solid carbon dioxide, is very cold (109 °F / 78 °C), and it is frequently used to cool vaccines, chill and freeze food, preserve blood and tissue samples, heat-treat metals, and even produce special effects like fog for events or stage plays. Because solid CO2 does not melt into a liquid when heated but instead transforms instantly into gas, it is referred to as dry ice. Sublimation is the name of this procedure.
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substance q had a vapor pressure of 345 mmhg at 22.00c. what's the temperature at a vapor pressure of 275 mmhg? the heat of vaporization of q is 36.0 kj/mol.
A substance q had a vapor pressure of 345 mmHg at 22.0 °C. the temperature at a vapor pressure of 275 mmHg. the heat of vaporization of q is 36.0 kJ/mol is 19.6 °C.
The Clausius Clapeyron equation is given as :
ln ( P2 / P1 ) = - ΔH /R ( 1 / T2 - 1 / T1)
ln ( 275 / 345 ) = - 36 / 8.314 (1 / T2 - 1 / 295)
- 0.235 = - 4.33 ( 295 - T2 / 295 T2 )
15.98 T2 = 295 - T2
14.98 T2 = 295
T2 = 19.6 °C
The temperature at vapor pressure 275 mmHg is 19.6 °C.
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