Answer:
The rate of change in position of an object with respect to time, and displacement is called velocity.
Juan's mother drives 12.5 miles southwest to her favorite shopping mall. What is the velocity of her
automobile if she arrives at the mall in 7.25 minutes?
Answer:
v1= 12.5miles, t= -7.25m, a= 0
v= 1/2at^2
v= 1/2×
what is fire proof plastic
Explanation:
.Flame retar,dant plastic additi,ves are compounds added to plastics and other materials to inhibit, suppress or de,lay combustion. These compounds are useful in impending burning in the ign,ition phase of fire. They do not prevent char,ring or melting nor do they increase the heat resistance of a material
-In a series LRC circuit, the frequency at which the circuit is at resonance is f0. If you double the resistance, the inductance, the capacitance, and the voltage amplitude of the ac source, what is the new resonance frequency?
A) 4 f0
B) 2 f0
C) f0
D) f0/2
E) f0/4
When you double capacitance and inductance, the new resonace frequency becomes f0/2.
Resonance frequencyThe resonace frequency of RLC series circuit, is the frequency at which the capacitivity reactance is equal to inductive reactance.
Xc = Xl
[tex]\frac{1}{2\pi f_0C} = 2\pi f_0 L\\\\4\pi^2 f_0^2 LC = 1\\\\f_0^2 = \frac{1}{4\pi^2 LC} \\\\f_0 = \sqrt{\frac{1}{4\pi^2 LC} } \\\\f_0 = \frac{1}{2\pi } \frac{1}{\sqrt{LC} }[/tex]
where;
f0 is the resonace frequencyL is the inductanceC is the capacitanceWhen you double capacitance and inductance, the new resonace frequency becomes;
[tex]f_0 = \frac{1}{2\pi } \frac{1}{\sqrt{LC} }\\\\f_1 = \frac{1}{2\pi } \frac{1}{\sqrt{2L (2C)} } \\\\f_1 = \frac{1}{2\pi } \frac{1}{\sqrt{4LC} }\\\\f_1 = \frac{1}{2}( \frac{1}{2\pi } \frac{1}{\sqrt{LC} })\\\\f_1 = \frac{1}{2} (f_0)[/tex]
Thus, When you double capacitance and inductance, the new resonace frequency becomes f0/2.
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What are some core features of waves in physics?
Answer:
Waves are disorders that travel through a fluid medium. Several simple wave features include frequency, period, wavelength, and amplitude.
Explanation:
Q 36 - URGENT HELP PLS
WILL BE MARKED AS BRAINLIEST.
what is a product made from no renewable resources
Answer:
a nail
Explanation:
Answer:
crude oil, natural gas, coal, and uranium. These are all resources that are processed into products that can be used commercially.
Explanation:
A net force of 60 N north acts on an object with a mass of 30 kg. Use Newton's second law of
motion to calculate the amount of acceleration the object will experience. Then explain how the
amount of acceleration will change if the net force or the mass of the object increases.
Answer:
Explanation:
F = ma. For us, this looks like
60 = 30a and
a = 2 m/s/s
If the force goes up to, say, 90, then
90 = 30a and
a = 3...if the force goes up, the acceleration also goes up.
If the mass goes up to say, 60, and the force stays the same, then
60 = 60a and
a = 1...if the mass goes up, the acceleration goes down.
Two arrows are shot vertically upward. The second arrow is shot after the first one, but while the first is still on its way up. the initial speeds are such that both arrows reach their maximum heights at the same instant, although these heights are different. Suppose the that initial speed of the first arrow is 34 m/s and that the second arrow is fired 0.204081632653061 seconds after the first. Determine the initial speed of the second arrow.
Answer:
The initial speed of the second arrow is 33.8 m/s.
Explanation:
initial speed of first arrow, u = 34 m/s
Let the initial height of the second arrow is h.
Let they both reaches at maximum height H.
Let the time taken by the first arrow is t and the second arrow is t - 0.0204
Let the initial speed of the second arrow is u'.
Use first equation of motion for the first arrow.
v = u - gt
0 = u - gt
34 = gt ..... (1)
For the second arrow
v =u' - g (t - 0.0204)
0 = u' - gt + 9.8 x 0.0204
u' = 34 - 0.1999 = 33.8 m/s
Compared to yesterday, you did three times the work in one-third the time. To do so, your power output must have been ___
Answer: 9 times yesterday's power output
Explanation:
Power is the rate at which a certain work is done. The unit of power is Watt and it's equal to work divided by the time taken to complete the work.
In this scenario, since the person did three times the work in one-third the time, then the power output will be:
= Work done / Time
= 3/⅓
= 3 × 3
= 9
Therefore, the power output must have been 9 times yesterday's power output.
Two light waves of equal wavelength, lambda, are emitted in phase from separate sources and propagate to a common point P. Light wave 1 must travel a longer distance (d1) than light wave 2 (d2) to reach point P, where d1 – d2 is equal to the path difference between the two light waves. If the two waves interfere constructively at point P, what must be true about the path difference between the two light waves?
Answer:
The path difference must be equal to an integral (1 * lambda, 2 * lambda, -------n * lambda) number of wavelengths for constructive interference to occur.
Which object will take the most force
to accelerate? *
4 kg
6 kg
8 kg
02 kg
Answer:
I think it might be 8kg grams because it is bigger
In regard to the Compton scattering experiment with x-rays incident upon a carbon block, as the scattering angle becomes larger, what happens to the magnitude of difference between the incident and scattered wavelengths
Answer:
Increases
Explanation:
In the Compton scattering experiment with x-rays,
The change in operation
[tex]\Delta \lambda = \frac{h}{m_oc} [1-cos\theta][/tex]
Now rest being constant, as \theta increases, cos\theta decreases
Hence, The change in wavelength will increase with the increase in \theta.
Hence, wavelength increases with an increase in the angle of scatttering.
HELP ASAP need it soon
Answer:
The answer to your question is given below.
Explanation:
The energy and frequency of a wave are related by the following equation:
E = hf
Where
E => is the energy.
h => is the Planck's constant.
f => is the frequency
From the formula i.e
E = hf
The energy is directly proportional to the frequency. Thus, an increase in the frequency of the wave will lead to an increase in the energy and a decrease in the frequency of the wave will lead to a decrease in the energy.
Considering the question given above, if the frequency of the wave is decreased, then the energy of the wave will also decrease.
Write a short paragraph about Fruit and Seed formation of Strawberry plants.
An aluminum-alloy rod has a length of 10.0 cm at 20°C and a length of 10.015 cm at the boiling point of water (1000C). (a) What is the length of the rod at the freezing point of water (0 0C)? (b) What is the temperature if the length of the rod is 10.009 cm? /4mks
Answer:
a. 9.99625 cm b. 68 °C
Explanation:
(a) What is the length of the rod at the freezing point of water (0 0C)?
Before we find the length of the rod, we need to find the coefficient of linear expansion, α = (L - L₀)/[L₀(T - T₀)] where L₀ = length of rod at temperature T₀ = 10.0 cm, T₀ = 20 °C, L = length of rod at temperature T = 10.015 cm and T = 100 °C
Substituting the values of the variables into the equation, we have
α = (L - L₀)/[L₀(T - T₀)]
α = (10.015 cm - 10.0 cm)/[10.0 cm(100 °C - 20 °C)]
α = 0.015 cm/[10.0 cm × 80 °C]
α = 0.015 cm/[800.0 cm °C]
α = 0.00001875 /°C
We now find the length L₁ at T₁ = 0 °C from
L₁ = L₀(1 + α(T₁ - T₀))
So, substituting the values of the variables into the equation, we have
L₁ = L₀(1 + α(T₁ - T₀))
L₁ = 10.0 cm[1 + 0.00001875 /°C(0° C - 20 °C)]
L₁ = 10.0 cm[1 + 0.00001875 /°C × -20° C]
L₁ = 10.0 cm[1 - 0.000375]
L₁ = 10.0 cm[0.999625]
L₁ = 9.99625 cm
(b) What is the temperature if the length of the rod is 10.009 cm?
With length L₃ = 10.009 cm at temperature T₃, using
L₃ = L₀(1 + α(T₃ - T₀))
making T₃ subject of the formula, we have
L₃/L₀ = 1 + α(T₃ - T₀)
L₃/L₀ - 1 = α(T₃ - T₀)
T₃ - T₀ = (L₃/L₀ - 1)/α
T₃ = T₀ + (L₃/L₀ - 1)/α
substituting the values of the variables into the equation, we have
T₃ = 20 °C + (10.009 cm/10.0 cm - 1)/0.00001875 /°C
T₃ = 20 °C + (1.0009 - 1)/0.00001875 /°C
T₃ = 20 °C + 0.0009/0.00001875 /°C
T₃ = 20 °C + 48 °C
T₃ = 68 °C
After being assaulted by flying cannonballs, the knights on the castle walls (12.0 m above the ground) respond by propelling flaming pitch balls at their assailants. One ball lands on the ground at a distance of 81.1 m from the castle walls. If it was launched at an angle of 53.0° above the horizontal, what was its initial speed?
Answer:
28.6 m/s
Explanation:
Using the equation for the range of a projectile,
R = U²sin2θ/g where U = initial speed of flaming pitch balls, θ = launch angle = 53° and g = acceleration due to gravity = 9.8 m/s²
Making U subject of the formula, we have
U = √(gR/sin2θ)
substituting the values of the variables into the equation given that R = 81.1 m, we have
U = √(9.8 m/s² × 81.1 m/sin2(53°))
U = √(794.78 m²/s²/sin106°)
U = √(794.78 m²/s²/0.9613)
U = √(826.78 m²/s²)
U = 28.75 m/s
U ≅ 28.6 m/s
3. How do energy transformations, energy transfers, and conservation of energy allows you to track how energy moves through in a system?
Answer:
The law of conservation of energy states that when one form of energy is transformed to another, no energy is destroyed in the process. According to the law of conservation of energy, energy cannot be created or destroyed. So the total amount of energy is the same before and after any transformation
Explanation:
The energy in a system always transforms from one form to another without any significant loss or addition. It simply changes from one form to another with the effect of numerous external influences.
What is Energy transformation?Energy transformation may be defined as the process through which energy can convert from one form to another. It also illustrates the migration of energy from one place to another due to physical factors.
According to the law of conservation of energy, in a closed system energy can neither be created nor destroyed. The total amount of energy remains the same before and after the process of transformation.
Therefore, the energy in a system always transforms from one form to another without any significant loss or addition.
To learn more about Energy transformations, refer to the link:
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large amounts of energy are converted to small amounts of mass. small amounts of energy are converted to large amounts of mass. small amounts of mass are converted to large amounts of energy. large amounts of mass are converted to small amounts of energy. mass is destroyed and energy is created. energy is destroyed and mass is created.
Answer:
small amounts of mass are converted to large amounts of energy
Explanation:
According to the mass-energy equivalence, which Albert Einstein initially proposed as a general principle. It was revealed that mass and energy are connected and that a "small amount of mass can be converted into enormous amounts of energy."
Using the formula E=mc^2. This means Energy equals mass times the speed of light squared.
Hence, it is true that "small amounts of mass are converted to large amounts of energy."
ACELLUS PHYSICS HELP!!
A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)
Answer:
Potential difference, V = -0.000224 Volts
Explanation:
Given the following data;
Quantity of charge = 6.93*10-4 C
Energy = -3.09 J
To find the electric potential V at that point?
Mathematically, the energy transferred per unit of charge is given by the formula;
E = QV
Where:
E is the energy
Q is the quantity of charge
V is the potential difference.
Substituting into the formula, we have;
[tex] -3.09 = 6.93*10^{-4} * V [/tex]
[tex] V = \frac {6.93*10^{-4}}{-3.09} [/tex]
Potential difference, V = -0.000224 Volts
f the voltage in a circuit is 80 volts and the resistance is 20 ohms, what is the current?
I = 4 A
Explanation:
From Ohm's law, the voltage is given by
V = IR
or
I = V/R = (80 V)/(20 ohms)
= 4 A
Find the temperature of a mixture obtained by mixing 32 grams of water at a temperature of 22 degrees Celsius with 88 grams of water at a temperature of 75 degrees Celsius.
Answer:
60.87 °C
Explanation:
Applying,
Heat lost = heat gain
cm'(t₂-t₃) = cm(t₃-t₁).............. Equation 1
Equation 1 can futher be simplified to
m'(t₂-t₃) = m(t₃-t₁)................Equation 2
Where m' = mass of the hot water, m = mass of the cold water, t₁ = initial temperature of the cold water, t₂ = initial temperature of the hot water, t₃ = temperature of the mixture.
From the question,
Given: m' = 88 g, m = 32 g, t₁ = 22°C, t₂ = 75°C
Substitute these values into equation 2
88(75-t₃) = 32(t₃-22)
6600-88t₃ = 32t₃-704
32t₃+88t₃ = 6600+704
120t₃ = 7304
t₃ = 60.87 °C
After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg bowling pin initially at rest. Find the final velocity of the second pin in the following situations: a) The first pin moves to the right after the collision at 0.8 m/s. Answer in units of m/s. 010 (part 2 of 2) 10.0 points b) The first pin stops moving when it hits the second pin. Answer in units of m/s
Answer:
a) v₂ = 4.2 m/s
b) v₂ = 5 m/s
Explanation:
a)
We will use the law of conservation of momentum here:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0.8 m/s
v₂ = speed of second after before collsion = ?
Therefore,
[tex](1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s[/tex]
v₂ = 4.2 m/s
b)
We will use the law of conservation of momentum here:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0 m/s
v₂ = speed of second after before collsion = ?
Therefore,
[tex](1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)[/tex]
v₂ = 5 m/s
Why does the needle of a compass point north?
a. Because the southern pole of the Earth's magnet repels it.
b. Because the southern pole of the Earth's magnet is in the north.
Because the northern pole of the Earth's magnet is in the north
d. Because the Earth's core is made of steel.
C.
Answer:
b. Because the southern pole of the Earth's magnet is in the north.
Explanation:
This is very weird to think about but Earth's southern magnetic pole is in Earth's geographic north. So when compass points north, it is actually getting attracted to the southern magnetic pole (that is actually located in the north direction- geographic location- in earth).
Charges of +3 µC and –5 µC are 2 mm from each other. The –5 µC charge is replaced with a +5 µC charge.
How will the electrical force between the charges compare with the original force?
same force, but in the opposite direction
same force, but in the same direction
greater force, but in the opposite direction
greater force, but in the same direction
Answer: same force in opposite direction.
Explanation: Charges of opposite sign attracts each other and charges with same sign repel each other. Because only sign of negative charge changes, and absolute value of charge remains same, value of force is same but is in opposite direction.
Answer:
A) same force, but in the opposite direction
Explanation:
he's right
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pls ans
a) Name the graph?
b) In first 2 s the object is said to be in ______________ motion.
(uniform motion / uniform acceleration)
c) The portion BC of the graph represents which type of motion?
d) Find out acceleration in first 2 s?
I don't know♀ what is your favorite song
If you were capable of converting mass to energy with 100%, efficiency, how much mass would you need to produce 3.5x10^12 Joules of energy?
Answer:
a) 3.9 x 10⁻⁵ kg
Explanation:
The amount of mass required to produce the energy can be given by Einstein's formula:
[tex]E = mc^2\\\\m = \frac{E}{c^2}[/tex]
where,
m = mass required = ?
E = Energy produced = 3.5 x 10¹² J
c = speed of light = 3 x 10⁸ m/s
Therefore,
[tex]m = \frac{3.5\ x\ 10^{12}\ J}{(3\ x\ 10^8\ m/s)^2} \\\\m = 3.9\ x\ 10^{-5}\ kg[/tex]
Hence, the correct option is:
a) 3.9 x 10⁻⁵ kg
A positive charge is moving across a room from south to north. A magnetic field runs from east to west. In what direction is the magnetic force on the moving positive charge?
Answer:
the force is on the z axis, coming out of the blade
Explanation:
The direction of the magnetic force is given by the right hand rule,
For a positive charge, the thumb points in the direction of velocity, the other fingers extended in the direction of the magnetic field, and the palm points in the direction of force.
In this case.
Thumb points North
The fingers extended is in the east - west direction parallel to the blade
The palm is sticking out of the leaf, in the z direction
the answer is the force is on the z axis, coming out of the blade
Can somebody please answer this correctly I will give brainliest
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The length of each rod is 1.1 m, while the mass of each is 0.10 kg. One rod is held in place above the ground, and the other floats beneath it at a distance of 11 mm. Determine the current in the rods.
Answer:
220 A
Explanation:
The magnetic force on the floating rod due to the rod held close to the ground is F = BI₁L where B = magnetic field due to rod held close the ground = μ₀I₂/2πd where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, I₂ = current in rod close to ground and d = distance between both rods = 11 mm = 0.011 m. Also, I₁ = current in floating rod and L = length of rod = 1.1 m.
So, F = BI₁L
F = (μ₀I₂/2πd)I₁L
F = μ₀I₁I₂L/2πd
Given that the current in the rods are the same, I₁ = I₂ = I
So,
F = μ₀I²L/2πd
Now, the magnetic force on the floating rod equals its weight , W = mg where m = mass of rod = 0.10kg and g = acceleration due to gravity = 9.8 m/s²
So, F = W
μ₀I²L/2πd = mg
making I subject of the formula, we have
I² = 2πdmg/μ₀L
I = √(2πdmg/μ₀L)
substituting the values of the variables into the equation, we have
I = √(2π × 0.011 m × 0.1 kg × 9.8 m/s²/[4π × 10⁻⁷ H/m × 1.1 m])
I = √(0.01078 kgm²/s²/[2 × 10⁻⁷ H/m × 1.1 m])
I = √(0.01078 kgm²/s²/[2.2 × 10⁻⁷ H])
I = √(0.0049 × 10⁷kgm²/s²H)
I = √(0.049 × 10⁶kgm²/s²H)
I = 0.22 × 10³ A
I = 220 A
A parallel combination of 3ohms and 4ohms resistor is connected in series with a resistor of 4ohms and a battery of negligible resistance. Calculate the effective resistance in the circuit
Answer:
Explanation:
Equivalent resistance of parallel combination of two resistors of 3 ohms and 4 ohms .
R₁ = 3 x 4 / ( 3 + 4 )
= 12 / 7 = 1.7 ohms .
This equivalent resistance is connected with 4 ohms in series
Total resistance = 1.7 ohms + 4 ohms
= 5.7 ohms.
Hence effective resistance of the circuit = 5.7 ohms .