Answer: 10.83
Step-by-step explanation:
Pemdas
A bacteria population is growing exponentially with a growth factor of 1/6 each hour. By what growth factor does the population change each half hour? Select all that apply
Using exponential function concepts, it is found that the change of the growth factor of the population each half hour is given by:
b. [tex]\sqrt{\frac{1}{6}}[/tex]
e. [tex]\left(\frac{1}{6}\right)^{0.5}[/tex]
What is an exponential function?An increasing exponential function is modeled by:
[tex]A(t) = A(0)(1 + r)^t[/tex]
In which:
A(0) is the initial value.r is the decay rate, as a decimal.In this problem, the growth factor of 1/6 each hour, hence, [tex]r = \frac{1}{6}[/tex], and:
[tex]A(t) = A(0)(1 + \frac{1}{6})^t[/tex]
For each half-hour, t = 0.5, hence the growth factor is of:
[tex]\left(\frac{1}{6}\right)^{0.5} = \sqrt{\frac{1}{6}}[/tex]
Hence, options b and e are correct.
You can learn more about exponential functions at https://brainly.com/question/25537936
calculate the surface are of the rectangular prism to the nearest tenth of a square centimetre
Answer:
152.32
https://youtu.be/dQw4w9WgXcQ
A rectangular ink pad is 10 centimeters tall and 15 centimeters wide.
What is its area?
Answer:
15000000000000000000000000000000000000000000
Step-by-step explanation:
Answer:
150 centimeters
Step-by-step explanation:
just multiply!
hope this helps :)
hii please help i’ll give brainliest
What is the slope of the line?
The base edge of the regular triangular pyramid is b=10 cm and altitude of the base hb ≈ 8.66 cm. The slant height of the pyramid is k=8 cm. Find: a Lateral area of the pyramid
Answer:
Lateral Area: 120
Surface Area: 163.3
(a) Construct, using a compass and straightedge, the midpoint of UV and label it M. Then
draw TM, the median from 2T to side UV.
(b) Prove algebraically that the median TM is not perpendicular to UV. Explain.
Please helpppppp
Step-by-step explanation:
a) for the first part, you take your compass and stretch it more than halfway on to line UV. Place the fixed point at V and draw a curve. make sure you keep your compass the same size, put the fixed part of your compass on point U and draw a curve again. both curves should go both upward and downward. Now, your curves should meet at two points. use your straight edge to draw the line that meets at both points. I have drawn an example of what it should approximately look like. for the second part you are simply using your straight edge to draw a line from T down to the median M you previously found. I have drawn a second picture to show you.
b) now to check if they are perpendicular, we must find the slope of each line. I will not be able to do this accurately since I didn't use an exact method to find M, so you must follow my steps.
Step 1: find the slope of UV. To do so, we must take two points from the line. I will take points U and V because they are easiest to see. To find the slope, we can use the equation:
[tex]m = \frac{y2 - y1}{x2 - x1} [/tex]
where m is the slope.
so, let's define our points.
Point V is (4,4), let's call this point one.
Point U is (14,6), let's call this point two.
So,
x1= 4
y1= 4
and
x2= 14
y2= 6
now, we can plug these into our slope equation.
[tex]m = \frac{6 - 4}{14 - 4} = \frac{2}{10} = \frac{1}{5} [/tex]
You must then use the points T and M in order to solve the second slope. Where T is (2,12). I will keep M as (x1, y1) for now.
The equation should then look like:
[tex]m = \frac{2 - y1}{12 - x1} [/tex]
now, in order for it to be perpendicular to our original slope, it must be the opposite reciprocal, which is the number flipped and made negative. The opposite reciprocal of 1/5 will be -5.
It should NOT be, as we have been told. So, we can state:
"I know that TM is not perpendicular to UV because the UV has a slope of 1/5 and TM has a slope of x, which is NOT the opposite reciprocal on 1/5."
Hope this helps! :)
Pls hurry , timed test
Answer:
c
Step-by-step explanation:
help pleaaseeeeeeeee..
Answer:
Step-by-step explanation:
Rectangle 4 sides, 4 right angles, and opposite Parallel sides
Rhombus 4 sides, all sides equal length, and 4 acute angles.
I am 100% positive this answer is correct plz mark as brainliest
Which function has a maximum that is greater than the maximum of the graph g(x)?
O y = (x + 3)2 + 2
y=-5 (x+3)2 + 4
O y=- } (x - 2)2 +3
O
y = (x - 2)2 + 4
Write the equation of the parabola in vertex form.
vertex(2,1),points (1,-4)
F(x)=?
Step-by-step explanation:
The general vertex form is given by
[tex]y = a {(x - h)}^{2} + k[/tex]
where (h, k) is the vertex and a is a constant. So we can write the y as
[tex]y = a {(x - 2)}^{2} + 1[/tex]
To find the value of a, substitute the point (1, -4)
-4 = a(1 - 2)^2 + 1
or a = -5
Therefore, the vertex form of the parabola is
[tex]y = - 5 {(x - 2)}^{2} + 1[/tex]
Solve -7g - 2 = - 30. Show your steps.
Answer:
g = 4
Step-by-step explanation:
-7g - 2 = -30
Add 2 to both sides to get:
-7g -2+2 = -30+2
which is equal to:
-7g = -28
now divide both sides by -7 to get the value of g which is:
g = -28 / - 7
--> g = 4
Answer:
g = 4
Step-by-step explanation:
First you can add 2 to both sides to isolate the x term:
-7g -2 = -30
+2 +2
-7g = -28
Now, you can divide by -7 both sides to find g,
-7g = -28
÷ -7 ÷ -7
g = 4
consider this equation tan(theta)=-5/3
if theta is an angle in quadrant II what is the value of sin(theta)
Answer:
B 5√34 / 34
Step-by-step explanation:
tan ∅ = opp/adj
In quad II
tan ∅ = 5 / (-3)
---------------------
hyp^2 = 5^2 + (-3)^2
hyp^2 =25 + 9 = 34
hyp = √34
---------------------------
sin ∅ = opp/hyp
sin ∅ = 5/√34
Rationalizing
sin ∅ = 5√34 / 34
Consider this equation [tex]tan(\theta)=-5/3[/tex]. if theta is an angle in quadrant II the of [tex]sin \theta = \dfrac{5\sqrt{34}}{{34} }[/tex].
What are the trigonometric ratios?Trigonometric ratios for a right-angled triangle are from the perspective of a particular non-right angle.
In a right-angled triangle, two such angles are there which are not right-angled(not of 90 degrees).
The slanted side is called the hypotenuse.
From the considered angle, the side opposite to it is called perpendicular, and the remaining side will be called the base.
Consider this equation
[tex]tan(\theta)=-5/3[/tex]
B 5√34 / 34
if theta is an angle in quadrant II what is the of sin(theta)
[tex]tan(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of base}}[/tex]
In quadrant II
tan ∅ = 5 / (-3)
[tex]hyp^2 = 5^2 + (-3)^2\\hyp^2 =25 + 9 = 34\\hyp = \sqrt{34}[/tex]
[tex]\sin(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of Hypotenuse}}[/tex]
[tex]sin \theta = \dfrac{5}{\sqrt{34} }[/tex]
Rationalizing
[tex]sin \theta = \dfrac{5\sqrt{34}}{{34} }[/tex]
Learn more about trigonometric ratios here:
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write an equation
(-2,4) and (-1,8)
Answer:
2(-2,4) + 2(-1,8)=-8.4
Step-by-step explanation:
2x-2
2x4
2x-1
2x8
-8.4
solve the absolute value equation
|x+1|=|2x-6|
Answer:
x = 5, and/or x= - 7/3
Step-by-step explanation:
|x+1|=|2x+6|
We know eitherx+1=2x+6orx+1=−(2x+6)
x+1=2x+6(Possibility 1)
x+1−2x=2x+6−2x(Subtract 2x from both sides)
−x+1=6
−x+1−1=6−1 (Subtract 1 from both sides)
−x=5
(Divide both sides by -1)
x=−5
x+1=−(2x+6)(Possibility 2)
x+1=−2x−6(Simplify both sides of the equation)
x+1+2x=−2x−6+2x(Add 2x to both sides)
3x+1=−6
3x+1−1=−6−1(Subtract 1 from both sides)
3x=−7
Divide both sides by 3
x= −7 / 3
Check answers. (Plug them in to make sure they work.)
x=−5(Works in original equation)
x= −7/3
(Works in original equation)
Answer:
x=−5 or x= −7 / 3
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Answer:
I think its A? Not sure though
Step-by-step explanation:
What is the answer to this question? I can't wrap my head around it because I am a 6th grader but my math teacher is making me do 8th-grade stuff to prepare me for algebra I.
Help please explanation and thank you!
Answer:
D
Step-by-step explanation:
A: The sum of Y and H is +. If the scale is correct, this is not true. Y is further away from 0 than H is. Suppose H = 5 and Y = -7. Then Y + H = 5 + -7 = - 2
B: E and Y area both minus. The minus signs cancel. Therefore the answer will be + B is wrong.
C: H>0 and E<0. A negative times a positive is a negative not a positive. C is wrong
D: A - H Suppose A = 2 and H = 5 . Then A - H = 2 - 5 which is - 3
This is your answer.
The reason is that H is further from the 0 than A is.
Give the most specific name for the quadrilateral. Explain your reasoning.
Answer:
Kite because it has two pairs of opposite sides and opposite angles that are equal .
Find the area of the composite figure
Answer:
370mm
Step-by-step explanation:
15mm×30mm=450mm
8mm×10mm
450mm-80mm =370mm
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Completed a full explanation of statistics with explanation and examples ?
Answer: Hope This Helps!
Step-by-step explanation:
Statistic Definition: A mathematical science concerned with data collection, presentation, analysis, and interpretation
Examples: "Statistics is the only mathematical field required for many social sciences." and "The statistics from the Census for apportionment are available."
1) IF (a, b ond B = (x, y) find BxH,
And show in arrow diagram
Answer:
Your question seems inaccurate. Sorry,please give the correct question.
A grocery store has 29 boxes with 204 bars of soap in each box. The store also has 2,346 bottles of hand soap. How many more bottles of hand soap than bars of soap does the store have?
Answer:
3570
Step-by-step explanation:
x=(29*204)-2346
x=5916-2346=3570
(Ples Mark Brainliest. Also if you can, please help me : https://brainly.com/question/23700476) :D
You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water your height h (in feet) above the water in terms of t seconds is given by h(t)=-16t^2+6t+12
When do you hit the water?
What is your maximum height?
Answer:
When do you hit the water?
1.075 seconds after you jump.
What is your maximum height?
the maximum height is 12.5626 ft
Step-by-step explanation:
The equation:
h(t) = -16*t^2 + 6*t + 12
Is the height as a function of time.
We know that the initial height is the height when t = 0s
h(0s) = 12
and we know that the diving board is 12 foot tall.
Then the zero in h(t)
h(t) = 0
Represents the surface of the water.
When do you hit the water?
Here we just need to find the value of t such that:
h(t) = 0 = -16*t^2 + 6*t + 12
Using the Bhaskara's formula, we get:
[tex]t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}[/tex]
Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)
The positive solution is:
t = (-6 - 28.4)/-32 = 1.075
So you hit the water 1.075 seconds after you jump.
What is your maximum height?
The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.
We know that the vertex of a general quadratic:
a*x^2 + b*x + c
is at
x = -b/2a
Then in the case of our equation:
h(t) = -16*t^2 + 6*t + 12
The vertex is at:
t = -6/(2*-16) = 6/32 = 0.1875
Evaluating the height equation in that time will give us the maximum height, which is:
h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626
And the height is in feet, then the maximum height is 12.5626 ft
You hit the water 1.075 seconds after you jump.
The maximum height is 12.56.
Given that,
You are jumping off the 12-foot diving board at the municipal pool.
You bounce up at 6 feet per second and drop to the water your height h (in feet) above the water in terms of t seconds is given by,
[tex]\rm h(t)=-16t^2+6t+12[/tex]
We have to determine,
When do you hit the water?
What is your maximum height?
According to the question,
You bounce up at 6 feet per second and drop to the water your height h (in feet) above the water in terms of t seconds is given by,
[tex]\rm h(t)=-16t^2+6t+12[/tex]
1. The initial height is the height when t = 0 second,
[tex]\\\rm h(t)=-16t^2+6t+12\\\\\rm h(0)=-16(0)^2+6(0)+12\\\\ h(0) = 12[/tex]
And the diving board is 12 feet tall.
Then the zero in h(t)
h(t) = 0
When h(t) = 0 represent the surface of the water,
[tex]\rm h(t)=-16t^2+6t+12\\\\\rm -16t^2+6t+12 =0\\\\8t^2-3t-6=0\\\\x = \dfrac{-(-3)\pm \sqrt{(-3)^2-4\times8\times(-6)}}{2\times 8}}\\\\x = \dfrac{3\pm \sqrt{9+192}}{16}}\\\\x = \dfrac{3\pm \sqrt{201}}{16}}\\\\x = \dfrac{3\pm 14.77}{16}}\\\\ x = \dfrac{3+14.77}{16} \ and \ x = \dfrac{3-14.77}{16} \\\\x = \dfrac{17.77}{16} \ and \ x = \dfrac{-11.77}{16} \ \\\\ x = 1.075 \ and \ x = -0.855[/tex]
The value of x can not be negative then the value of x is 1.075.
Therefore, you hit the water 1.075 seconds after you jump.
2. The maximum height is reached by you, you first derivative the function h(t) with respect to t:
[tex]\rm \dfrac{dh(t)}{dt} = \dfrac{d(-16t^2+6t+12)}{dt}\\\\\rm \dfrac{dh(t)}{dt} = \dfrac{d(-16t^2)}{dt} +\dfrac{d(6t)}{dt}+\dfrac{d(12)}{dt}\\\\\rm \dfrac{dh(t)}{dt} = 2\times (-16t) + 6\times 1+0\\\\ \dfrac{dh(t)}{dt} = -32t+6\\\\[/tex]
To find the maximum height the value first derivative is equal to zero.
[tex]\rm \dfrac{dh(t)}{dt} = 0\\\\-32t+6=0\\\\-32t=-6\\\\t = \dfrac{6}{32}\\\\t = \dfrac{3}{16}\\[/tex]
Substitute the value of t in the equation to find the maximum height,
[tex]\rm h(\dfrac{3}{16})=-16(\dfrac{3}{16})^2+6(\dfrac{3}{16})+12\\\\ h(\dfrac{3}{16})=-(\dfrac{9}{16})+6(\dfrac{3}{16})+12\\\\ h(\dfrac{3}{16})=-\dfrac{-9}{16}+\dfrac{18}{16}+12\\\\ h(\dfrac{3}{16})= \dfrac{-9+18+192}{16} \\\\ h(\dfrac{3}{16}) = \dfrac{201}{16}\\\\h(\dfrac{3}{16}) = 12.56[/tex]
Hence, The maximum height is 12.56.
For more details refer to the link given below.
https://brainly.com/question/20120328
What is the inter-quartile range of the given data set?
3
6
2
Answer:
IQR = 3
Step-by-step explanation:
That would be 20 - 17, or 3.
et f(x)=2\ln(x+4)f(x)=2ln(x+4)f, left parenthesis, x, right parenthesis, equals, 2, natural log, left parenthesis, x, plus, 4, right parenthesis and let g(x)=\dfrac23x+1g(x)= 3 2 x+1g, left parenthesis, x, right parenthesis, equals, start fraction, 2, divided by, 3, end fraction, x, plus, 1. The graph of y=f(x)y=f(x)y, equals, f, left parenthesis, x, right parenthesis is shown below. Use the interactive graph to sketch a graph of y=g(x)y=g(x)y, equals, g, left parenthesis, x, right parenthesis. LinearAbsolute_valueQuadraticExponentialLogarithm Let x_1x 1 x, start subscript, 1, end subscript and x_2x 2 x, start subscript, 2, end subscript be solutions of \,2\ln(x+4)=\dfrac23x+12ln(x+4)= 3 2 x+12, natural log, left parenthesis, x, plus, 4, right parenthesis, equals, start fraction, 2, divided by, 3, end fraction, x, plus, 1, where x_1
Answer:
x=-3.5 , the points of the graph are 0,1 and 3,3
Step-by-step explanation:
Find the difference of (2x -3) - (x-1) . *
5 points
x - 4
x - 2
x + 2
x + 4
Answer:
[tex]\huge\boxed{Answer\hookleftarrow}[/tex]
[tex](2x - 3) - (x - 1) \\ = 2x - 3 - x + 1 \\ = 2x - x - 3 + 1 \\ = x - 2[/tex]
⇻Option B. x - 2 is the correct answer.
Please help me y’all!!
Answer:
57
Step-by-step explanation:
Answer:
[tex]57[/tex]
Step-by-step explanation:
This is a plug-and-chug type problem. Substituting given values, we have:
[tex]\frac{3}{4}|-4-2(6^2)|,\\\\\frac{3}{4}|-4-2(36)|,\\\\\frac{3}{4}|-4-72|,\\\\\frac{3}{4}|-76|,\\\\\frac{3}{4}(76)=\boxed{57}[/tex]
Analyze the graph below to identify the key features of the logarithmic function.
Answer:
is there just 2 answers too this question? anyways the answer b
What is the measure of x?
Answer:
Hello! answer: x = 68
Step-by-step explanation:
This is a complementary angle meaning it will add up to 90 degrees 90 - 22 = 68 therefore x = 68 HOPE THAT HELPS!