What is the target audience of an ad?

Answer:

The overview including its problem is listed in the explanation segment following.

Explanation:

The subsequent weather system seems to be close to something like a moving warmer front.

So that the above seems to be the right answer.

Answer:

One of the strategies to avoid nested conditional is to use logical expressions such as the use of AND & operator.

One strategy is to use an  interface class with a method. That method can be created to be used for a common functionality or purpose. This is also called strategy design pattern. You can move the chunk of conditional statement to that method. Then each class can implement that interface class and use that shared method according to their own required task by creating objects of sub classes and call that common method for any such object. This is called polymorphism.

Explanation:

Nested conditionals refers to the use of if or else if statement inside another if or else if statement or you can simply say a condition inside another condition. For example:

if( condition1) {  

//executes when condition1 evaluates to true

  if(condition2) {

//executes when condition1  and condition2 evaluate to true

  }  else if(condition3) {

 //when condition1 is true and condition3 is true

} else {

 //condition1  is true but neither condition2 nor conditions3 are true

}  }

The deeply nested conditionals make the program difficult to understand or read if the nested conditionals are not indented properly. Also the debugging gets difficult when the program has a lot of nested conditionals.

So in order to avoid nested conditionals some strategies are used such as using a switch statement.

Here i will give an example of the strategies i have mentioned in the answer.

Using Logical Expressions:

A strategy to avoid nested conditionals is to use logical expressions with logical operators such as AND operator. The above described example of nested conditionals can be written as:

if(condition1 && condition2){  //this executes only when both condition1 and condition2 are true

} else if(condition1 && condition3) {

this executes only when both condition1 and condition3 are true

} else if(condition1 ){

//condition1  is true but neither condtion2 nor condtion3 are true  }

This can further be modified to one conditional as:

if(!condition3){

// when  condition1 and condition2 are true

}

else

// condition3 is true

Now lets take a simple example of deciding to go to school or not based on some conditions.

if (temperature< 40)

{

   if (busArrived=="yes")

   {

       if (!sick)

       {

           if (homework=="done")

           {

               printf("Go to school.");

           }

       }                    

   }

}

This uses nested conditionals. This can be changed to a single conditional using AND logical operator.

if ((temperature <40) && (busArrived=="yes") &&

(!sick) && (homework=="done"))

{    cout<<"Eligible for promotion."; }

The second strategy is to use an interface. For example you can

abstract class Shape{

//declare a method common to all sub classes

  abstract public int area();

// same method that varies by formula of area for different shapes

}

class Triangle extends Shape{

  public int area() {

     // version of area code for Triangle

return (width * height / 2);

  }

}

class Rectangle extends Shape{

  public int area() {

     // version of area code for Rectangle

    return (width * height)

  }

}

// Now simply create Rectangle or Triangle objects and call area() for any such object and the relevant version will be executed.

Answer:

c is the answer I'm pretty sure but wait for more

Answer:

Create a validation rule

Explanation:

Solution

The action a developer would take to enforce this requirement is by creating a validation rule.

Validation rule: A validation rules demonstrate that the data a user enters in a record meets the standards you identify before the user can save the record.

A validation rule can have a formula or expression that assesses the data in more than one fields and returns a value of either “True” or “False”.

It allow for values which are or are not allowed on a specific field.

Answer:

true

Explanation:

else if used so I think it's true

Answer:

the correct answer is a. Word processing.

Explanation:

hope this works out!!!!!

Hi there! Hopefully this helps!

--------------------------------------------------------------------------------------------------

The answer is A, testing the circuit at the power source.

Answer:

Here is the SwapArrayEnds()

//function with two parameters; the array and array size

void SwapArrayEnds(int sortArray[],int SORT_ARR_SIZE){  

int temp;   //temporary variable to hold the first element of sortArray

if(SORT_ARR_SIZE > 1){   //if sortArray size is greater than 1

temp = sortArray[0];   // set value of temp to the first element of sortArrray

sortArray[0] = sortArray[SORT_ARR_SIZE-1];   // set the value of first element of sortArray to the last element of sortArray

sortArray[SORT_ARR_SIZE-1] = temp;  }  } // set last element  value to temp

Explanation:

Lets understand the working of the above function with the help of an example. Suppose the sortArray has the following elements: {10,20,30,40}. So the size of this array is 4.

if(SORT_ARR_SIZE > 1) has an if statement which checks if the array size is greater than 1. This condition evaluates to true as 4 > 1. So the body of if condition executes.

Next the statement temp = sortArray[0];   sets the value of temp variable to the value of first element of sortArray. As sortArray[0] means the element at 0-th index position of the sortArray. So using the above example the first element of the array is 10. So temp = 10.

Next the statement sortArray[0] = sortArray[SORT_ARR_SIZE-1];   sets the last element of the sortArray to the position of first element of the sortArray.

SORT_ARR_SIZE-1 is the position of last element of the array. As the size of sortArray is 4, so 4-1 = 3 which points to the last element. Now this element is moved to the first position of the array. This means that the value of first element of array becomes 40 as the element at 3-th index of the sortArray is 40.

Next the statement sortArray[SORT_ARR_SIZE-1] = temp moves the value in temp variable to the last position of the sortArray. As we know that the value of temp= 10. So this element 10 of the sortArray is positioned at SORT_ARR_SIZE-1 position of sortArray which is 4-1 = 3-th index of sortArray. This simply means that 10 is moved to the last position of sortArray.

So now the final sortArray becomes: 40,20,30,10 as the first and last element of the array are swapped using above function SwapArrayEnds().

The program along with the output is attached in screenshot.

Functions are collection of codes or instructions merged together to act as one.

The function, where comments are used to explain each line is as follows:

//This defines the function

void SwapArrayEnds(int sortArray[],int SORT_ARR_SIZE){  

//This increments the array element at index 0

       sortArray[0] += sortArray[SORT_ARR_SIZE-1];

//This replaces the last element with the first

       sortArray[SORT_ARR_SIZE-1]= sortArray[0]- sortArray[SORT_ARR_SIZE-1];

//This replaces the first element with the last

       sortArray[0]= sortArray[0]- sortArray[SORT_ARR_SIZE-1];

}

At the end of the function, the first and the last elements of the array are swapped.

Read more about similar programs at:

https://brainly.com/question/15582117

Answer:

Option A (Implementing a site-to-site VPN for server access) seems to be the correct choice.

Explanation:

Other choices are not related to the given instance. So that Option A would be the right one.

Answer:

public static List<String> listUpper(List<String> list){

    List<String> upperList = new ArrayList<String>();

    for(String s:list){

        s = s.toUpperCase();        

        upperList.add(s);

    }

    return upperList;

}

Explanation:

Create a method named listUpper that takes list as a parameter

Inside the method, initialize a new list named upperList. Create a for-each loop that iterates through the list. Inside the loop, convert each string to uppercase, using toUpperCase method, and add it to the upperList.

When the loop is done, return the upperList

Answer:

it's a

Explanation:

Answer:

In this sense, the different types of computers would range from Desktop to Laptops, to iPads, then Mobile Phones. Somewhere in-between the phone and the iPad is the phablet.

A phablet is a group of mobile devices with the combined functionality and size of a smartphone and a tablet.

On the balance of probabilities, Jan is trying to replace her laptop.

Cheers!

Answer:

Explanation:

Given that:

number of surfaces on a hard disk = 4

number of sectors = 2048 sectors

number of tracks per surface = 131, 072 (2^17)

a block holds 512 bytes.

Since, 'The disk is not "zoned.".....

then, Number of bytes / sector = 512

a) What is the total capacity of this disk?

The total capacity of the disk is:[tex]= 4 \ surfaces \times 131072 \dfrac{tracks}{surfaces} \times 2048 \dfrac{sector}{tracks} \times 512 \dfrac{bytes}{sector}[/tex]

[tex]= 5.49755814\times 10^{11} \ bytes[/tex]

= 549755814 KB ( kilobytes)

= 549755.814 MB (megabytes)

=549.755814  GB (gigabytes)

b. Given the disk in Part 1, how much data can be accessed without moving the disk heads. (i.e what is the capacity of one cylinder?)

The capacity of one cylinder can be estimated by determining the capacity of one surface and the capacity of one track.

The capacity of one surface = [tex]131072\dfrac{tracks}{surface} \times 2048 \dfrac{sector}{tracks} \times 512\dfrac{bytes}{sector}[/tex]

The capacity of one surface = [tex]1.37438953 \times 10^{11[/tex] byte = 137.44 GB

Capacity of one track = 2048 sectors/track × 512 bytes/sector

Capacity of one track = 1048576 Bytes/track

Capacity of one track =1048 KB/track

Capacity of one track ≅ 1 MB/track

Since the hard disk contains four surfaces

∴

capacity of one cylinder = 1 MB/track × 4 track/cylinder

capacity of one cylinder  = 4 MB

Answer:

Following are the algorithm to this question:

y = 0 //  initialize variable y that assigns the value  0

p = 1 // initialize value 1 in the variable p which also known as starting position

init num = 1//define variable num that assign value 1

for j = 1 to n: //defining loop

y = m[j] - m[p]

if (y > 10) //defining if block

num++;  //increment num variable

p=i; //holding loop value in p variable

y= 0//assign value 0 in y variable

Explanation:

Following are the runtime analysis of the above-given algorithm:

The above-provided algorithm is greedy, but if it doesn't exceed the scope, it operates by greedily choosing its next object. Therefore the algorithm selects the fewest number of pens.

Running time:

This algorithm merely iterates once over all the points. The run-time is therefore O(n).

Answer:

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

Answer:  

I am writing a Python program:

For taking input from user:

user_input = input() # takes input from user

short_names = user_input.split() #splits user_input into list of strings

short_names.pop(0) # removes the first element of the list i.e. Gertrude

short_names[-1] = "Joe" #sets the last element to Joe

print(short_names)    #prints modified list of Sam Ann Joe

If you do not want to take input from user:  

short_names=['Gertrude', 'Sam', 'Ann', 'Joseph']  #list of 4 elements

short_names=short_names[1:]  # removes the first element Gertrude

short_names.pop()  # removes last element i.e. Joseph from list

short_names.append('Joe')  #adds Joe to the end of the list

print(short_names) #prints modified list Sam Ann Joe

If you do not want to use pop() and append() methods:

short_names = ['Gertrude', 'Sam', 'Ann', 'Joseph']  #creates list of 4 values

short_names = short_names[1:]  # removes first value i.e. Gertrude from list

short_names[-1] = "Joe"  #set the last element to Joe

print(short_names) #prints modified list Sam Ann Joe

Explanation:

The first program takes the names from the user, splits them into list of strings, then pop(0) has given index value 0 which means 1st value in the list. So it removes and returns first value from the list. Next statement sets the last value of list to Joe.

The second program has a hard coded list ['Gertrude', 'Sam', 'Ann', 'Joseph']  

short_names = short_names[1:] removes the first value of the short_names list i.e. Gertrude. Next pop() removes and returns last value in the list i.e. Joseph from list. Last statement append('Joe') adds Joe to the end of the list.

The third program has a list of 4 elements. short_names = short_names[1:]   removes first value i.e. Gertrude from list and short_names[-1] = "Joe"  sets the last element to Joe.

The function was implemented using the JavaScript language, the shift, pop and push function was used to get the desired output

The function bellow is written in JavaScript

function shortName (short_names){

short_names.shift() // The first element "Gertrude" was removed

short_names.pop() //The last element "Joseph" was removes

short_names.push("joe") //"Joe" is added to the new list

return short_names //The new list is returned as output

}

Learn more about array operation here:

https://brainly.com/question/26104158

Answer:

The Encryption solution that best prevents a competitor from receiving confidential information is the SSL(secure Socket Layer) Or TLS(Transport Layer Security).

Explanation:

Solution:

From my own perspective the encryption solution that i will use that prevents s a competitor from receiving confidential information and justify the recommendation is the SSL(secure Socket Layer) Or TLS(Transport Layer Security).

This is because in this case we have to share data confidentially (information need to be hidden from Unauthorized  security access. also these provides the Transport Layer security that we needed in above example above.

The purpose of these protocol is to provide server and client authentication, Data confidentiality,and Data integrity (protected from unauthorized change). Application Layer client/server program such as HTTP that uses the service of TCP can encapsulate their data in SSL Packets.

SSL (Secure Socket Layer): is defined as the normal technology for protecting an internet connection secure and defend any sensitive data that is being sent between two systems, and not allowing criminals from reading and changing any information sent, including potential personal details.

TLS (Transport Layer security): It is a procedure that allows  data integrity  and privacy over Internet communications.

Answer:

public static List<String> listSearch(String searchFor, List<String> list){

    List<String> foundList = new ArrayList<String>();

    for(String s:list){

        if(s.contains(searchFor)){

            foundList.add(s);

        }

    }

    return foundList;

}

Explanation:

Create a method named listSearch that takes two parameters, a String named searchFor and a String list named list

Inside the method, initialize a new String list named foundList, this will be used to hold the strings that contains the target string. Create a for loop that iterates through the list. Check if a string in the list contains the searchFor using the contains method. If it does, add the string to the foundList. When the loop is done, return the foundList.

Answer:

The program is written in python and it doesn't make use of any comment;

(See explanation section for line by line explanation)

def getN(num):

     fact = 1

     for i in range(1, 1 + num):

           fact = fact * i

     print("Factorial: ",fact)

num = int(input("Number: "))

if num < 0:

     print("Invalid")

else:

     getN(num)

Explanation:

The function getNum is defined here

def getN(num):

Initialize the result of the factorial to 1

     fact = 1

Get an iteration from 1 to the user input number

     for i in range(1, 1 + num):

Multiply each number that makes the iteration

           fact = fact * i

Print result

     print("Factorial: ",fact)

Ths line prompts user to input number

num = int(input("Number: "))

This line checks if user input is less than 0; If yes, the program prints "Invalid"

if num < 0:

     print("Invalid")

If otherwise, the program calls the getN function

else:

     getN(num)

Answer:

starvation

Explanation:

An indefinite postponement is sometimes make reference to as more colorfully as starvation when a stable influx of preferential or higher-priority threads could postponeâ possibly indefinitelyâ the execution of lower-priority threads though depending on operation system

Operating systems employ a technique called aging to curb against or avoid starvation, when a thread waits in the ready state, the operating system moderately grow the thread’s priority to ensure that the thread will eventually run.

Answer:

the answer is A avoid drinking 10 Tips to Avoid Driving Drunk

Explanation:

Give someone your keys. Find someone trustworthy who isn't drinking and hand over your keys for the night. ...

Don't drink on an empty stomach. ...

Know your body and pace yourself. ...

Take public transit. ...

Spend the night. ...

Wait an hour or two. ...

Stop drinking 90 minutes before you plan to leave. ...

Take the night off from drinking. hope this helps you :)

Answer:

The programming language is not stated;

However, I'll answer this question using Java Programming Language;

The method is as follows;

   public static void isPalindrome(String userinput)

    {

       String reverse = "";

       int lent = userinput.length();

int j = lent - 1;

while(j >= 0)

       {

           reverse = reverse + userinput.charAt(j);

           j--;

       }

       if(reverse.equalsIgnoreCase(userinput))

       {

           System.out.println("True");

       }

       else

       {

           System.out.println("False");

       }    

    }

Explanation:

This line defines the method isPalindrome with a string parameter userinput

public static void isPalindrome(String userinput) {

This line initializes a string variable

       String reverse = "";

This line gets the length of the userinput

       int len = userinput.length();

The following while-loop gets the reverse of userinput and saved the reversed string in reverse

int j = lent - 1;

while(j >= 0)

       {

           reverse = reverse + userinput.charAt(j);

           j--;

       }

The following if statement checks if userinput and reverse are equal (cases are ignored)

       if(reverse.equalsIgnoreCase(userinput))

       {

           System.out.println("True"); This line is executed if the if condition is true

       }

       else

       {

           System.out.println("False"); This line is executed if otherwise

       }  

    } The method ends here

Answer:

Following are the answer to this question:

Explanation:

A)

The memory size is 1 Giga Bytes which is equal to [tex]2^{30}[/tex]

[tex]\texttt{Number of address bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ Number of addresses}\\\\ \ \ \ \ 30 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2^{30}= 1073741824[/tex]

B) [tex]\texttt{I \ \ \ Opcode \ \ \ Register address \ \ \ Immediate operand \ \ \ Memory address}\\\\\\\textt{1 \ bit \ \ \ \ \ \ 128 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 24 \ bits \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 30 \ bits}\\\\\\[/tex]            [tex]= 2^7 \\\\ = 7 \ bits[/tex]

calculating the register Bits:

[tex]= 64-(1+7+24+30)\\\\=64 -62\ \ bits\\\\= 2\ \ bits\\[/tex]

C)

Immediate value size while merging the additional benefit with the address field:

[tex]= 2^{24} + 2^{30}\\\\= 2^{54}\\\\[/tex][tex]\texttt{Range before combining(-,+) 24 bits \ \ \ \ \ \ Range after combining( -,+)54bits}\\\\[/tex]                         [tex]\textt{-2^{12} from + (2^{12}-1) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -2^{27} from + (2^{27}- 1)}[/tex]

[tex]= \frac{24}{2} = 12\\\\= \frac{54}{2} = 27[/tex]

The range is accomplished by dividing the bits by 2 into the two sides of the o and the number is one short to 0.

Answer:

Are highly portable.

Explanation:

Java is a object oriented and class-based programming language. It was developed by Sun Microsystems on the 23rd of May, 1995.

Java was designed by a software engineer called James Gosling and it is originally owned by Oracle. Also, worthy of mention is the fact that Java was originally known as Oak.

Generally, Java as a software application usually are developed having a ".jar", ".class" or ".java" filename extensions.

Because Java byte code is the same on all computers, compiled Java programs are highly portable. This simply means that, the Java byte code was designed such that it has very few implementation dependency, thus, once the code is written, it can run on all computer platforms that supports the Java programming language.

Hence, the Java byte code is a write once, run anywhere software program.

The Java byte code instructions are read and executed by a computer program known as a Java Virtual Machine (JVM).

Additionally, Java program is used for developing varieties of applications such as, mobile, desktop, games, web and application servers etc.

Answer:

=OR(B2>=60, C2>=60)

Explanation:

If you want to check if at least one of the scores is equal to or greater than 60, you should use the OR function. The OR function tests multiple conditions and returns TRUE if at least one is met. Therefore, the function in cell D2 would be:

= OR(B2>=60, C2>=60)

In other to obtain the boolean value True if one of two or more conditions are met, the OR operator is used. Hence, the appropriate function is =OR(B2>=60, C2>=60)

Hence, the appropriate function is =OR(B2>=60, C2>=60).

Learn more : https://brainly.com/question/20702793

Answer:

d) 0 1 1 2

The above piece of code prints the Fibonacci series.

Explanation:

def a(n):

   if n == 0:

       return 0

   elif n == 1:

       return 1

   else:

       return a(n-1)+a(n-2)

for i in range(0,4):

   print(a(i),end=" ")

sorry i would help if i knew

.

Answer:

I am writing a JAVA and Python program. Let me know if you want the program in some other programming language.

import java.util.Scanner; // class for taking input from user

public class Reverse{ //class to reverse a sentence

public static void main(String[] args) { //start of main() function body

Scanner input = new Scanner(System.in); //create a Scanner class object

   System.out.print("Enter a sentence: "); //prompts user to enter a sentence

   String sentence = input.nextLine(); // scans and reads input sentence

   String[] tokens = sentence.split(" "); // split the sentence into tokens using split() method and a space as delimiter

   for (int i = tokens.length - 1; i >= 0; i--) { //loop that iterates through the tokens of the sentence in reverse order

       System.out.println(tokens[i]); } } } // print the sentence tokens in reverse order

Explanation:

In JAVA program the user is asked to input a sentence. The sentence is then broken into tokens using split() method. split method returns an array of strings after splitting or breaking the sentence based on the delimiter. Here the delimiter used is space characters. So split() method splits the sentence into tokens based on the space as delimiter to separate the words in the sentence. Next the for loop is used to iterate through the tokens as following:

Suppose the input sentence is "How are you"

After split() method it becomes:

How

are

you

Next the loop has a variable i which initialized to the tokens.length-1. This loop will continue to execute till the value of i remains greater than or equals to 0.

for (int i = tokens.length - 1; i >= 0; i--)

The length of first token i.e you is 3 so the loop executes and prints the word you.

Then at next iteration the value of i is decremented by 1 and now it points at the token are and prints the word are

Next iteration the value of i is again decremented by i and it prints the word How.

This can be achieved in Python as:

def reverse(sentence):

   rev_tokens = ' '.join(reversed(sentence.split(' ')))

   return rev_tokens

line = input("enter a sentence: ")

print((reverse(line)))

The method reverse takes a sentence as parameter. Then rev_tokens = ' '.join(reversed(sentence.split(' ')))  statement first splits the sentence into array of words/tokens using space as a delimiter. Next reversed() method returns the reversed sentence.  Next the join() method join the reversed words of the sentence using a space separator ' '.join(). If you want to represent the reversed tokens each in a separate line then change the above statement as follows:

rev_tokens = '\n'.join(reversed(sentence.split(' ')))  

Here the join method joins the reversed words separating them with a new line.

Simply input a line of text and call this reverse() method by passing the input line to it.

Answer:

i will send you the answers in the next 10minute

Explanation:

In my opinion this is computer assisted legal search