Answers
Answer:
D, or [tex]\frac{-1}{16}[/tex]
Step-by-step explanation:
To add (or subtract) fractions, you need to have a common denominator.
You might notice that the 16 on the bottom is a multiple of 8.
8*2 as a matter of fact
If we multiply [tex]\frac{1}{8\\}[/tex] by 1, it doesn't do anything, it stays as 1/8
1 is the same thing as [tex]\frac{1}{1}[/tex] and is also the same as [tex]\frac{2}{2}[/tex]
If we multiply [tex]\frac{1}{8}[/tex] by [tex]\frac{2}{2}[/tex], we get a bigger fraction, which is [tex]\frac{2}{16}[/tex]
So, our problem can be re-written as [tex]\frac{2}{16}+(-\frac{3}{16} )[/tex]
To add (or subtract) fractions with common denominators, you keep the common denominator and add (or subtract) the numerator.
[tex]\frac{2}{16}+(-\frac{3}{16})=\frac{2-3}{16}=\frac{-1}{16}[/tex]
The last step is to see if our answer can be reduced.
A fraction can't be reduced if there is a prime number in either the numerator or the denominator.
There is a -1 in the numerator, which is prime, and therefore, the fraction can't be reduced.
Related Questions
Select all intervals in which the function P(t) is decreasing
Answers
Answer:
we conclude that the intervals in which the function P(t) is decreasing are:
x < 13 < x < 4Step-by-step explanation:
At x< 1, the function P(t) is decreasing
A function p is an increasing function on an open interval if f(y) > f(x) for any two input values x and y in the given interval where y>xA function p is a decreasing function on an open interval if f(y) > f(x) for any two input values x and y in the given interval where y>xFrom the figure, it is clear that the function seems to be increasing
from (1, 3) and then 4 to onwards.
But it is clear that the function seems to be decreasing from the x < 1 and from the interval (3, 4).
Therefore, we conclude that the intervals in which the function P(t) is decreasing are:
x < 13 < x < 4identify a pair of factors of -35 that has a sum of -2
Answers
Answer:
5, -7
Step-by-step explanation:
Answer:
5 and -7
Step-by-step explanation:
The GCF of 15 and 27
Answers
the greatest common factor of 15 and 27 is 3
If the simple interest on $3000 for 3 years is $720 , then what is the interest rate?
Answers
Answer:
8%
Step-by-step explanation:
Starting Principal: $
3,000.00
Years:
3
Annual Interest Rate:
8
%
Results
Future Value, using...
Simple Interest: $
3,720.00
Annually Compounded Interest: $
3,779.14
Which of the following fractions is written in its simplest form? 22/33 18/27 13/25 42/81 please answer soon this was due today
Answers
Answer:
I think its 13/35 it cant be divided
Helppppp meeeee 3/5 Divided by 1/9
Answers
Answer: 5.4 or 5 2/5 Hope this helps have a GREAT night
Step-by-step explanation:
V'W'X'Y' has vertices V^' (-3,2),W^' (5,1),X^' (0,4),and Y'(-2,0). If V'W'X'Y' is the image of VWXY rotated 90° around the origin. What are the coordinates of VWXY (the pre-image).
Answers
Given:
V'W'X'Y' has vertices V'(-3,2), W'(5,1), X'(0,4) and Y'(-2,0).
V'W'X'Y' is the image of VWXY rotated 90° around the origin.
To find:
The coordinates of VWXY (the pre-image).
Solution:
V'W'X'Y' is the image of VWXY rotated 90° around the origin. It means, the figure VWXY is rotated 90° counterclockwise around the origin.
So, if we rotate V'W'X'Y' 90° clockwise around the origin, then we get the original figure VWXY.
If a figure rotated 90° clockwise around the origin, then
[tex](x,y)\to (y,-x)[/tex]
[tex]V'(-3,2)\to V(2,3)[/tex]
[tex]W'(5,1)\to W(1,-5)[/tex]
[tex]X'(0,4)\to X(4,0)[/tex]
[tex]Y'(-2,0)\to Y(0,2)[/tex]
Therefore, the coordinates of preimage are V(2,3), W(1,-5), X(4,0) and Y(0,2).
a shirt was originally marked as $24.95 rings up at the register as 19.96 what is the percent discount on the shirt
Answers
Answer:
The discount is 20% off
hope this helps!
Suppose that Y has density function
f(y) = ky(1 − y) if 0 ≤ y ≤ 1 0, elsewhere
A) Find the value of k that makes f (y) a probability density function.
B) Find P(Y ≤ .4|Y ≤ .8).
C) Find the .95-quantile, i.e., find a point φ.95 such that P(Y ≤ φ.95) = .95.
Answers
I'm assuming
[tex]f(y)=\begin{cases}ky(1-y)&\text{for }0\le y\le1\\0&\text{otherwise}\end{cases}[/tex]
(a) f(x) is a valid probability density function if its integral over the support is 1:
[tex]\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=k\int_0^1 y(1-y)\,\mathrm dy=k\int_0^1(y-y^2)\,\mathrm dy=1[/tex]
Compute the integral:
[tex]\displaystyle\int_0^1(y-y^2)\,\mathrm dy=\left(\frac{y^2}2-\frac{y^3}3\right)\bigg|_0^1=\frac12-\frac13=\frac16[/tex]
So we have
k / 6 = 1 → k = 6
(b) By definition of conditional probability,
P(Y ≤ 0.4 | Y ≤ 0.8) = P(Y ≤ 0.4 and Y ≤ 0.8) / P(Y ≤ 0.8)
P(Y ≤ 0.4 | Y ≤ 0.8) = P(Y ≤ 0.4) / P(Y ≤ 0.8)
It makes sense to derive the cumulative distribution function (CDF) for the rest of the problem, since F(y) = P(Y ≤ y).
We have
[tex]\displaystyle F(y)=\int_{-\infty}^y f(t)\,\mathrm dt=\int_0^y6t(1-t)\,\mathrm dt=\begin{cases}0&\text{for }y<0\\3y^2-2y^3&\text{for }0\le y<1\\1&\text{for }y\ge1\end{cases}[/tex]
Then
P(Y ≤ 0.4) = F (0.4) = 0.352
P(Y ≤ 0.8) = F (0.8) = 0.896
and so
P(Y ≤ 0.4 | Y ≤ 0.8) = 0.352 / 0.896 ≈ 0.393
(c) The 0.95 quantile is the value φ such that
P(Y ≤ φ) = 0.95
In terms of the integral definition of the CDF, we have solve for φ such that
[tex]\displaystyle\int_{-\infty}^\varphi f(y)\,\mathrm dy=0.95[/tex]
We have
[tex]\displaystyle\int_{-\infty}^\varphi f(y)\,\mathrm dy=\int_0^\varphi 6y(1-y)\,\mathrm dy=(3y^2-2y^3)\bigg|_0^\varphi = 0.95[/tex]
which reduces to the cubic
3φ² - 2φ³ = 0.95
Use a calculator to solve this and find that φ ≈ 0.865.
Using probability concepts, it is found that
a) The value is k = 6.
b) P(Y ≤ .4|Y ≤ .8) = 0.554.
c) The 95th percentile is x = 0.86465.
The density function is:
[tex]f(y) = ky(1 - y)[/tex]
Item a:
The condition that makes it a probability density function is:
[tex]\int_0^1 f(y) dy = 1[/tex]
Thus:
[tex]\int_0^1 f(y) dy = \int_0^1 ky - ky^2 dy[/tex]
[tex]\int_0^1 f(y) dy = k(\frac{y^2}{2} - \frac{y^3}{3})|_{y = 0}^{y = 1}[/tex]
[tex]\int_0^1 f(y) dy = k(\frac{1}{2} - \frac{1}{3})[/tex]
Then
[tex]k(\frac{1}{2} - \frac{1}{3}) = 1[/tex]
[tex]k(\frac{3-2}{6}) = 1[/tex]
[tex]k = 6[/tex]
The value is k = 6.
Item b:
This probability is:
[tex]\int_0.4^0.8 f(y) dy = 6(\frac{y^2}{2} - \frac{y^3}{3})|_{y = 0.4}^{y = 0.8}[/tex]
Then
[tex]p = 6\left(\frac{0.8^2}{2} - \frac{0.8^3}{3} - \frac{0.4^2}{2} + \frac{0.4^3}{3}\right)[/tex]
[tex]p = 0.554[/tex]
Thus, P(Y ≤ .4|Y ≤ .8) = 0.554.
Item c:
This is x for which:
[tex]\int_0^x f(y) dy = 0.95[/tex]
Thus:
[tex]6(\frac{x^2}{2} - \frac{x^3}{3}) = 0.95[/tex]
[tex]-2x^3 + 3x^2 - 0.95 = 0[/tex]
Solving a cubic equation with the help of a calculator, and considering [tex]0 \leq x \leq 1[/tex], this is x = 0.86465.
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Give answer please
Water bottles are sold in cases of 24. Select the TWO expressions that can represent the total number of water bottles in c cases
Options:
24 X c,
24 ÷ c,
24 + c,
24 - c,
24c
Answers
Answer:
24c
Step-by-step explanation:
First off, we know what in each case there are 24 bottles. So if we have c crates and want to know the water bottles inside them, we need to multiply 24 by c resulting in 24c or 24 x c.
9. Solve the equation.
4(6 – x) + 4 = 2 (3x + 1) – 6
Answers
Answer:
x=3.2
Step-by-step explanation:
4(6 – x) + 4 = 2 (3x + 1) – 6
24 - 4x + 4 = 6x + 2 - 6
28 - 4x = 6x -4
-4x - 6x = - 4 - 28
-10x = - 32
divide both sides
x = 16/5 or x = 3.2
hope this helps :)
Can someone help me find the area of the triangle
please!!!
Answers
Answer:
18
Step-by-step explanation:
PLEASE HELP QUICKLY!!!!! PLZZZZZZ!!!!!!!
Answers
Can you help with these questions please i would appreciate it
Answers
Answer:
[tex]\boxed{k = \frac{log_{e}(\frac{L +A }{A} )}{t} }[/tex]
2. I earned $9. I bought 4 candy bars for $0.85 each. How much money do I
have left? *
A. $5.60
B. $8.15
C. $9.85
D. $12.40
Answers
Answer:
A
Step-by-step explanation:
4 x $0.85= $3.40
$9-$3.40= $5.60
Answer:
A. $5.60
Step-by-step explanation:
4x0.85 =3.4 and 9 -3.4 = 5.6
help :((
Provide a small explanation if possible!!
Answers
Answer:
r = 24
Step-by-step explanation:
Just reverse everything,
3 x 16 = 48,
48 ÷ 2 = 24,
to double-check,
if you plug in 24 for r then you have,
2(24)/3 = 16
48/3 = 16
16 = 16
Which expression can be used to solve the problem below? On a recent math test,
Jill scored 3 points for each of the 18 multiple choice questions she answered
correctly and 5 points for each of the 6 short response questions she answered
correctly. What was her total score on the test?
1 : 3+16 • 18+6
2 : 3+18 • 5+6
3 : 3 • 5 + 18 • 6
4 : 3 • 18 + 5 • 6
Answers
Answer:
4
Step-by-step explanation:
Because she gets 3 per multiple choice question, so 3 times 18
she gets 5 per response question, so 5 times 6
Jill total score on the test is 3 • 18 + 5 • 6. The correct option is 4.
What is multiplication?Multiplication is a mathematical arithmetic operation. It is also a process of adding the same types of expression for some number of times.
Example - 2 × 3 means 2 is added three times, or 3 is added 2 times.
Given;
Jill scored 3 points for each of the 18 multiple choice questions she answered correctly.
That means,
use the multiplication operation,
3 x 18
And 5 points for each of the 6 short response questions she answered correctly.
That means,
5 x 6
To find the total score:
Add the scores,
3 x 18 + 5 x 6
or, 3 • 18 + 5 • 6
Therefore, 3 • 18 + 5 • 6 is the required expression.
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r−5r−6s+8s−15 what is the answer for this equation
Answers
Step-by-step explanation:
r-5r-6s+8s-15
-4r+2s-15
= 2s-4r-15
The simplified form of the given expression is -4r+2s-15.
The given expression is r-5r-6s+8s-15.
What is an expression?An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division.
The given expression can be solved as follows:
r-5r-6s+8s-15
= -4r+2s-15
Therefore, the simplified form of the given expression is -4r+2s-15.
To learn more about an expression visit;
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50 POINTS PLS HELP!!!!
Quadrilateral EFGH was dilated by a scale factor of 2 from the center (1, 0) to create E'F'G'H'. Which characteristic of dilations compares segment F'H' to segment FH?
A: A segment that passes through the center of dilation in the pre-image continues to pass through the center of dilation in the image.
B: A segment that does not pass through the center of dilation in the pre-image is parallel to its corresponding segment in the image.
C: A segment in the image has the same length as its corresponding segment in the pre-image.
D: A segment that does not pass through the center of dilation in the pre-image is perpendicular to its corresponding segment in the image.
Answers
Answer:
Answer choice C.
Step-by-step explanation:
What is a secure line of credit?
a. A line of credit offered only to individuals with excellent credit ratings.
b. A line of credit offered to a business or corporation.
c. A line of credit backed by the government.
d. A line of credit backed by collateral.
Answers
Answer:
D. A line of credit backed by collateral.
Step-by-step explanation:
Answer:
D. A line of credit backed by collateral.
Step-by-step explanation:
did the quiz
Simplify the following expression (-8)-(-6)
Answers
second: -8+6 which equals -2
There are 3,785 milliliters in 1 gallon, and there are 4 quarts in 1 gallon.
How many milliliters are in 3 gallons?
Answers
Answer:11,356
Step-by-step explanation: that is the answer! I’m sure
Answer:11.355
Step-by-step explanation:
Peter collected 171 marbles but lost 3/4 of them on his way home through of hole in his bag when he arrived at home now many marbles did Peter have left?
Answers
The number of marbles Peter had when he arrived home was 43 marbles
What is Percentage?
A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, %
Given data ,
The number of marbles Peter had on his way home = 171
The amount of marbles he lost on his way home = ( 3/4 ) th
Now , the amount of marbles Peter have left = 1 - amount of marbles he lost on his way home
The amount of marbles Peter have left = 1 - 3/4
= ( 1 / 4) th
So , The number of marbles Peter had left when he arrived home is =
Amount of marbles Peter have left x Number of marbles Peter had
The number of marbles Peter had left when he arrived home is = (1/4) x 171
= 171 / 4
= 42.75
≈ 43 marbles
Hence , the number of marbles Peter had left when he reached home is 43
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I WILL GIVE BRIANLEIST PLZ SOLVE I WILL ALSO GIVE 800 robux slove for line ad BC = 6 cm
Answers
Answer:
20 to 25 cm. Hope this helps. Tell me if i'm right or wrong. Can I have brainliest if I am right?
Step-by-step explanation:
Answer:
20 to 25 cm give that robux boi
Step-by-step explanation:
To compute a student's Grade Point Average (GPA) for a term, the student's grades for cach course are weighted by the number of credits for the course. Suppose a student had these grades: 3.6 in a 5 credit Math course 2.5 in a 2 credit Music course 3.0 in a 5 credit Chemistry course 3.4 in a 5 credit Journalism course What is the student's GPA for that term? Round to two decimal places. Student's GPA=_________
Answers
Answer:
The student's GPA = 3.24
Step-by-step explanation:
To determine the student's GPA for the term,
First, we will determine the weighted grade points and then divide the result by the total credit.
The weighted grade point is the sum of the grade points in the courses.
Grade point for a course is calculated by multiplying the grade by the course credit.
For the Math course,
Grade point = 3.6 × 5 = 18.0
For the Music course,
Grade point = 2.5 × 2 = 5.0
For the Chemistry course,
Grade point = 3.0 × 5 = 15.0
For the Journalism course,
Grade point = 3.4 × 5 = 17.0
Hence,
The weighted grade point = 18.0 + 5.0 + 15.0 + 17.0
The weighted grade point = 55.0
Total credit = 5 + 2 + 5 + 5 = 17
∴ The student's GPA = 55.0 / 17 = 3.24
Hence, The student's GPA = 3.24
What is the surface area of this rectangular pyramid?
4 mm
5 mm
5 mm
square millimeters
Answers
Answer:
100 mm i think
Step-by-step explanation:
The ratio of girls to boys in the coed soccer league is 3:7. Choose True or
False for each statement.
The ratio of girls to total students in the league is 3:10.
O Truc
False
Next >
Previous
Answers
Answer:
True
Step-by-step explanation:
3:7 is girls to boys, and to find the total, do 7+3. After that, you'd get 10, and the ratio would be 3:10, so TRUE
11. Use matrices to solve the system of equations below. Be sure to show [A] and [B].
(3a + 2b + c = 15
a-b4c = 23
4b – 2c = -16
Answers
Answer:
2a=-16
Step-by-step explanation:
all I could think of
The cost of an item is $0.30 per ounce. If total cost of the item is $3.60, how many ounces are in the item?
Answers
Answer:
Example 1: - If the item's label displays the weight as 3 lb 2 oz, type the shop name and item's brand, enter 3 in the pounds field, leave the 00 (decimal) value unchanged, enter 2 in the ounces field, leave the 00 (decimal) value unchanged, fill out the Price field and Calculate to get the price per ounce
Answer:
12 ounces
Step-by-step explanation:
3.60 = .3x
divide by .3 on both sides
12 = x
it given that f (x) =xsquared 2+3x+2 find f(0) the value of x for which f (x)=0 help me to solve the question pls
Answers
Answer:
f(x) = 0 on x= -1 and x = -2
Step-by-step explanation:
Given function is:
[tex]f(x) = x^2+3x+2[/tex]
In order to find the value of x on which the function will have value zero we have to factorize the function and find zeroes of the function. The method used will be factorization of polynomial as the function is in polynomial form.
So,
[tex]x^2+3x+2\\=x^2+2x+x+2\\=x(x+2)+1(x+2)\\=(x+1)(x+2)[/tex]
To find the zeroes, putting the function = 0
[tex]f(x) = 0\\(x+1)(x+2) = 0\\x+1 = 0\\x = -1\\x+2 = 0\\x= -2[/tex]
Hence,
f(x) = 0 on x= -1 and x = -2