What is the student's kinetic energy at the bottom of the hill if he is moving
at 18 m/s?
Variables:
Show Work

NC means North Carolina.

Answer:

The temperatures will increase.

Explanation:

What will happen is that the temperature will increase. This is because, in wind direction and weather forecasting, a wind that shifts from the south means that warmer air/temperatures are approaching whereas a wind shift from the north implies that cooler air/temperatures are approaching.

Answer:

[tex]2\sqrt{6}[/tex]  [tex]\frac{mi}{s}[/tex]

Explanation:

Assuming there is no waste of energy:

[tex]K_{1} = K_{2}\\\frac{1}{2}m_{1}v_{1_{1}}^{2} + \frac{1}{2}m_{2}v_{2_{1}}^2 = \frac{1}{2}m_{1}v_{1_{2}}^{2} + \frac{1}{2}m_{2}v_{2_{2}}^2\\\\=> m_{1}v_{1_{1}}^{2} + m_{2}v_{2_{1}}^2 = m_{1}v_{1_{2}}^{2} + m_{2}v_{2_{2}}^2\\\\m_{1} = 2 kg, m_{2} = 1 kg, v_{1_{1}} = 4 \frac{mi}{s} , v_{2_{1}} = 0\\=> 32 = 8 + v_{2_{2}}^{2} => v_{2_{2}} = 2\sqrt{6} \frac{mi}{s}[/tex]

Answer:ye

Explanation:

Answer:

Explanation:

According to law of reflection of light ,

angle of incidence = angle of reflection

angle of incidence = i

angle of reflection = r

when angle of incidence increases to i₁ and angle of reflection becomes r₁

According to law of reflection,

i₁ = r₁

i₁ - i = r₁ - r

increase in angle of incidence = increase in angle of reflection .

So angle of reflection also increases .

Answer:

30m

Explanation:

Given parameters:

Speed of the goat  = 1.5m/s

Time  = 20s

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use;

      Speed  = [tex]\frac{distance}{time}[/tex]  

 Distance = Speed x time

 So;

 Distance  = 1.5m/s x 20s  = 30m

Answer:

a) 500 m

b) 50 s

c) speed= distance/time= 500/50= 10 m/s

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Answer:

volume is 64

Explanation:

2×2×4×4

=64

Answer:

[tex]V = 16\ cm^3[/tex]

Explanation:

The Volume of a Rectangular Prism

A rectangular prism is also called a rectangular box and has three dimensions all perpendicular to each other.

Given a rectangular prism of length L, width W, and height H, the volume is calculated as:

V = WLH

We are given the dimensions of a rectangular box: L= 4 cm, W = 2 cm, H = 2 cm. Computing the volume:

V = 2 cm * 4 cm * 2 cm

[tex]\mathbf{V = 16\ cm^3}[/tex]

Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

The impulse, momentum and final velocity can all be obtained from Newton's second law.

Let us recall that the impulse is obtained as the product of force and time.

Impulse = Force × time

Impulse = 6 N × 10 s = 60 Ns

From Newton's second law of motion;

F.t = mv - mu

Since the object was initially at rest;

F.t = mv

Hence, the final velocity of the object is 60 Kgms-1

The final velocity is obtained from;

F.t = mv

v = F.t/m

v = 6 × 10/20

v = 3 m/s

Learn more about impulse and momentum: https://brainly.com/question/904448

Answer:

A. Balanced force

Explanation:

Answer:

190

Explanation:

add because your looking for the Miles

When a  person walks 60.0m and then walks 130m then the displacement of the person would be 70 meters if he first walked east and then west.

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.

As given in the problem a person walks 60.0m and then walks 130m and if he first walks east then west then we have to find the displacement.

Displacement = final position -initial position

Lets us consider eastward as positive direction,

displacement = 60 - 130

                       = -70 meters

The negative sign represents the displacement would be in a westward direction.

Thus, If a guy initially went east and then west, his displacement would be 70 meters when he traveled 60.0 meters and then 130 meters.

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Answer:

67.6m/s

Explanation:

Given parameters:

Initial velocity  = 8.2m/s

Acceleration  = 9.0m/s²

Time  = 6.6s

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we use the expression below:

     Acceleration  = [tex]\frac{v - u }{t}[/tex]

v is the final velocity

u is the initial velocity

 t is the time taken

    9  = [tex]\frac{v - 8.2}{6.6}[/tex]  

    v - 8.2  = 59.4

    v  = 59.4 + 8.2 = 67.6m/s

Answer:

30 mph

Explanation:

Answer:

Its either B or A

Explanation:

Answer:

-11,813.87N

Explanation:

According to coulombs law, the Force between the two charges is expressed as;

F = kq1q2/d²

k is the coulombs constant = 9*10⁹kg⋅m³⋅s⁻²⋅C⁻².

q1 = -0.00067 C

q2 = 0.00096 C

d  = 0.7m

Substitute into the formula:

F =  9*10^9 *  -0.00067 * 0.00096/0.7²

F = 9*10⁹*-6.7*10⁻⁴*9.6*10⁻⁴/0.49

F = -578.88*10⁹⁻⁸/0.49

F = -578.88*10/0.49

F = -5788.8/0.49

F = -11,813.87N

Hence the force between the two charges is -11,813.87N

Answer:

A

Explanation:

only is true when the objects mass is constant

Answer:

A.

Explanation:

When the mass is constant. Newton's second law will work perfectly.

Fun fact you probably won't need to know this, but the original formula that Newton derived was F=change in momentum divided by change in time. Momentum will account for a change in mass. The schooling system lies to you all the time especially in physics.

Answer:

Writing with a pencil. The pencil pushes on the paper. The paper pushes on the pencil.

Explanation:

Newton's third law.

Answer:

acceleration= -6ms^-2

Explanation:

[tex]v = u + at \\ 0 = u + ( - 6 \times 2) \\ u = 12m {s}^{ - 1} [/tex]

distance

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 12 \times 2 + \frac{1}{2} \times ( - 6) \times {2}^{2} \\ s = 12m[/tex]

Answer:

[tex]1650\:\mathrm{m}[/tex]

Explanation:

We can use the following kinematics equations to solve this problem:

[tex]v_f=v_i+at,\\{v_f}^2={v_i}^2+2a\Delta x[/tex].

Using the first one to solve for acceleration:

[tex]132=88+a(15),\\15a=44,\\a=\frac{44}{15}=2.9\bar{3}\:\mathrm{m/s^2}[/tex].

Now we can use the second equation to solve for the distance travelled by the airplane:

[tex]132^2=88^2+2\cdot2.9\bar{3}\cdot \Delta x,\\\Delta x= \frac{9680}{2\cdot2.9\bar{3}},\\\Delta x =\fbox{$ 1650\:\mathrm{m}$}[/tex](three significant figures).

Answer:

circuit b will have the higher current than circuit a

Answer:

1 or a the first bubble

Explanation:

Answer:

(4) The particle travels with a constant velocity until t0 and then comes to rest.

Explanation:

Uniform rectilinear motion is defined as the motion of a particle in a straight line with constant velocity, that is, there is no change in velocity over time.

And this can be determined by means of the following equation:

[tex]x=x_{o}+v*(t-t_{o})[/tex]

where:

x = final point [m]

xo = initial point [m]

v = velocity (slope) [m/s]

t = final time [s]

to = initial time [s]

So the slope in the graph gives the constant velocity

[tex]v=\frac{x-x_{o}}{t-t_{o}}[/tex]

Therefore, after the time to there is no displacement, that is the particle comes to rest.

Choice-D is the only velocity on the list.

(It has a speed and a direction.)

The jet's velocity might be represented by  700 km/h west. Hence, option (D) is correct.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

In this question, 700 h/km, 700 km have different unit that of velocity. So, option (A) and option (B) is not correct. . 700 km/hr has same unit that of velocity.  But it does not has direction. So, option (C) is also incorrect.  700 km/h west has the same unit of velocity with define direction. So, option (D) is correct.

Hence option (D) is correct answer.

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Answer:

T_finalmix = 45 [°C].

Explanation:

In order to solve this problem, a thermal balance must be performed, where the heat is transferred from water with the highest temperature, to the water with the lowest temperature, so the final temperature of the mix must be equal once the thermal balance is achieved.

[tex]Q_{water}=Q_{methanol}[/tex]

where:

[tex]Q_{water}=m_{water}*Cp_{water}*(T_{waterinitial}-T_{final})[/tex]

mwater = mass of the water = 300 [g] = 0.3 [kg]

Cp_water = specific heat of the water = 4180 [J/kg*°C]

T_waterinitial = initial temperature of the water = 80 [°C]

T_finalmix = final temperature of the mix [°C]

[tex]Q_{water}=m_{water}*Cp_{water}*(T_{final}-T_{water})[/tex]

Now replacing:

[tex]0.3*4180*(80-T_{final})=0.3*4180*(T_{final}-10)\\100320-1254*T_{final}=1254*T_{final}-12540\\112860=2508*T_{final}\\T_{final}=45[C][/tex]

The final temperature of the mixture is 45 °C

Heat lost by warm water = Heat gained by cold water

Qᵥᵥ = Q꜀

MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – T꜀)

0.3 × 4180 × (80 – Tₑ) = 0.3 × 4180 × (Tₑ – 10)

1254 (80 – Tₑ) = 1254(Tₑ – 10)

Clear bracket

100320 – 1254Tₑ = 1254Tₑ – 12540

Collect like terms

100320 + 12540 = 1254Tₑ + 1254Tₑ

112860 = 2508Tₑ

Divide both side by 2508

Tₑ = 112860 / 2508

Tₑ = 45 °C

Thus, the final temperature of the mixture is 45 °C

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