Answer: To answer this question, we will need the following equation: SPEED = DISTANCE/TIME (A multiplication and division triangle will be shown)i) The speed of the car is calculated by doing 100 metres/ 20 seconds which gives us 5 metres per second. ii) Rearranging the equation earlier, we can make the distance the subject of the equation so that we get SPEED x TIME = DISTANCE. We worked out the speed and the time was given as 1 minute 40 seconds but we cannot plug in the numbers yet as the time has to be converted to units of seconds (because our speed is in meters per second). 1 minute 40 seconds = 60 seconds + 40 seconds = 100 secondsWe then plug in the numbers to get the distance travelled = 5 metres per second x 100 seconds = 500 metres.
Explanation:
An organ pipe is 1.6 m long and open at both ends. What are the first three harmonic frequencies of this pipe?
Answer:
first harmonic = 56.7 Hz
Third harmonic = 170 Hz
Fifth harmonic = 283.3 Hz
Explanation:
Score
A 4400 Kg Track Travelling at Intial speed 52m\s can be stopeed in 42 sec. By Gently Break, also the track can be stoped
in 7.6 m\s if the driver hit the wall.
a. What is the Impulse Excerted on the Vehicle?
b. Whta is the Averge force is exeted on the Track in each stops ?
Answer:
(a) J = 10560 kg-m/s (b) 251.42 N
Explanation:
Given that,
Mass, m = 4400 kg
Initial speed, u = 5.2 m/s
Final speed, v = 7.6 m/s
Time, t = 42 s
(a) Let J be the impulse exerted on the vehicle. Impuse is equal to the change in momentum such as :
J = m(v-u)
J = 4400 (7.6-5.2)
J = 10560 kg-m/s
(b) Impulse = Force × t
[tex]F=\dfrac{J}{t}\\\\F=\dfrac{10560}{42}\\F=251.42\ N[/tex]
Hence, this is the required solution.
3.5 Temperature sensing in a light bulb. Incandescent light bulbs use a tungsten wire as the light-radiating filament by heating it to a temperature at which it is bright enough to produce light. The temperature of the wire can be estimated directly from the power rating and the resistance of the wire when it is cold. Given a 120 V, 100 W light bulb with a resistance of 22 W at room temperature (20 C): (a) Calculate the temperature of the filament when the light bulb is lit. (b) What are the possible sources of error in this type of indirect sensing
Answer:
Following are the solution to the given points:
Explanation:
In point a:
Given:
[tex]Temperature =20^{\circ } \ C, \\\\Resistance (R_o) = 22 \Omega[/tex]
However, the resistance of the bulb is 120 V or 100 W.
[tex]R= \frac{v^2}{P}=\frac{120^2}{100} =144 \Omega[/tex]
Let Tungsten's standard temperature coefficient be = 0.0045 [tex]20^{\circ} \ C[/tex]
Calculating temperature:
[tex]\to R=R_0(1+ \alpha (T-T_0))[/tex]
[tex]\to 144=22(1+0.0045(T-20))\\\\\to 144=22+0099(T-20)\\\\\to T -20 1232.32\\\\\to T =1252.32^{\circ } \ C \\[/tex]
In point b:
Potential consequences for indirect failures on iridescent bulb power device atmosphere does have a minor impact on defects, humidity, pressure, and surface that light bulb within the glass as well as the sensor attributable to the mercury.
How much Work is done when a 5 kg object is picked up a distance of 8 m.
Answer:
392J?
Explanation:
The filament in the bulb is moving back and forth, first pushed one way and then the other. What does this imply about the current in the filament? Select the best answer from the choices provided. View Available Hint(s) Select the best answer from the choices provided. The current is turning on and off. The magnitude of the current is varying with time. The current switches direction, going one way and then the other.
Answer:
the correct answer is: The magnitude of the current varies with time.
Explanation:
The movement of a filament by a current is due to the electric force when electrons accumulate on one side attract positively charged nuclei.
In this case the voters in a period of time are on one side, let's call it forward and in another period of time it accumulates on the other side, let's call it back, this explains the very small movement of the filament, therefore we have a current that varies over time.
The other two options are not correct because turning off the current the filament goes to the central position and does not go back, the other explanation the current goes in one direction or another, the voters are always on the same side therefore the filament only goes in a sense.
Consequently the correct answer is: The magnitude of the current varies with time.
Question 2 of 25
Which symbol in the first law of thermodynamics represents the result of a
gas expanding against a constant pressure?
O A. a
B. V
C. U
D. W
Answer: The symbol representing the result of a gas expanding against a constant pressure is W
Explanation:
According to first law of thermodynamics, energy can neither be destroyed nor created but rather transferred to one place to another and converted to and from other energy forms.
The mathematical form of first law of thermodynamics is:
[tex]\Delta U=q+W[/tex]
where [tex]\Delta U[/tex] = change in internal energy
q = heat absorbed or released
W = work [tex](W= P\Delta V)[/tex]
P = pressure
[tex]\Delta V[/tex] = volume change
Thus the changes in heat or work leads to change in internal energy.
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 ×102 T, what is the number of turns per meter for this solenoid?
Correct question:
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?
Answer:
the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Explanation:
Given;
length of solenoid, L= 0.35 m
diameter of the solenoid, d = 0.04 m
current through the solenoid, I = 5.0 A
magnetic field in the center of the solenoid, 2.8 x 10⁻² T
The number of turns per meter for the solenoid is calculated as follows;
[tex]B =\mu_o I(\frac{N}{L} )\\\\B = \mu_o I(n)\\\\n = \frac{B}{\mu_o I} \\\\n = \frac{2.8 \times 10^{-2}}{4 \pi \times 10^{-7} \times 5.0} \\\\n = 4.5 \times 10^3 \ turns/m[/tex]
Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
g A wheel of radius 1.2 meters initially rotates clockwise around its center with an angular speed of 10 rad/s, and it steadily increases its rate of rotation. 4 second later, the rate of rotation is 30 rad/s. What is the ratio of the angular acceleration of a point on the rim of the wheel to a point that is 0.6 meters from the center of the wheel?
Answer:
α = 5 rad / s²
Explanation:
This is a rotational kinematics exercise.
They indicate the initial velocity wo = 10 rad / s
w = w₀ + α t
α = [tex]\frac{w-w_o }{t}[/tex]
let's calculate
α = [tex]\frac{30-10}{4}[/tex]
α = 5 rad / s²
The velocity, the angular relation are the same in all the points of the wheel, the velocities and linear accelerations are the ones that change
a = α r
v = w r
why do fishermen like fishing during a full moon?
Answer:
The full moon attracts more fish towards the surface of the water.
Explanation:
It is a proven fact that fish are attracted to shiny/glowing items. for example, a metal fishing lure. Or, an angler fish light-bulb.
A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of 29.5 m. The runner starts the race at a constant speed. If she completes the 200-m dash in 24.4 s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track
Answer: [tex]2.27\ m/s^2[/tex]
Explanation:
Given
Length of the race track [tex]L=200\ m[/tex]
the radius of curvature of the track [tex]r=29.5\ m[/tex]
time taken to run on track is [tex]t=24.4\ s[/tex]
Speed of runner is
[tex]\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s[/tex]
Centripetal acceleration is
[tex]\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2[/tex]
Suppose you are standing at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward. You have a compass that is free to swivel in any direction. Which way does your compass point? Suppose you are standing at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward. You have a compass that is free to swivel in any direction. Which way does your compass point? It would point up. It would point east. It would point down. It would point west.
Answer:
It would point up.
Explanation:
Since I am at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward, the north pole of the compass would also point towards the earth's geographic north magnetic pole, since all other compasses point toward there.
Since the compass is free to swivel in any direction, the compass would point up, since it is at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward.
So, the compass would point up.
Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water
at 6◦ C. How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the
specific heat is 4190 J/kg · K.Immersive Reader
Answer:
7.55 g
Explanation:
Given that:
Heat of fusion = 333kj/kg
Heat capacity, c = 4190 j/kg /k
The Number of grams of ice that will melt can be represented as y:
Number of grams of ice that will melt * heat of fusion = specific heat capacity * temperature change
y * 333 * 10^3 J = (4190) * (6 - 0)
333000y = 25140
y = 25140 / 333000
y = 0.0754954 kg
y = 0.0754954 * 100
y = 7.549 g
Hence, Number of grams of ice that will melt = 7.55 g
tlo
A Cu rod whose length at 80 degree is 10.0 metres is heated at 50 degree find the new length take x-for cu as 0.000 to 17 k - 1
Answer:
9.949 m
Explanation:
From the question,
L' = L+LαΔT................. Equation 1
Where L' = New length, L = Original length, α = linear expansivity of Cu, ΔT = change in temperature
Given: L = 10 m, α = 0.00017 K⁻¹, ΔT = 50-80
L' = 10+10(0.00017)(50-80)
L' = 10-0.051
L' = 9.949 m
Hence the new legth of Cu is 9.949 m
what happens to the loudness of the sound as the amplitude increases
it increases and gets louder
and it amplifies the noise
In an electrical circuit, the amperage is 10A. It is supplied in a circuit with a voltage of 110V.
A. Calculate the resistance in the circuit.
B. Calculate the amount of electric charge passing through the circuit in 15 minutes
Answer:
11 ohm,,, 9kilo Columb
Explanation:
V=IR,,, Q =IT
1) How much work is done when a force of 50N
pulls a wagon 20 meters?
Answer:
100J
Explanation:
50N*20m=100J
N*m=J(joule)
A balloon rubbed against a pair of jeans gains a charge of -6x10^-6 C. If the balloon is moved to a distance of 0.25 m away from the jeans, what is the size and direction of the electric force between the balloon and jeans ?
Answer: 5.184 N
Explanation:
Given
The charge on the balloon is [tex]q_1=-6\times 10^{-6}\ C[/tex]
distance between balloon and jeans is [tex]r=0.25\ m[/tex]
After rubbing jeans must acquire the same opposite charge i.e.
[tex]q_2=6\times 10^{-6}\ C[/tex]
The electrostatic force between them
[tex]\Rightarrow F=\dfrac{kq_1q_2}{r^2}\\\\\Rightarrow F=\dfrac{9\times 10^9\times 6\times 10^{-6}\times 6\times 10^{-6}}{0.25^2}\\\\ \Rightarrow F=4\times 4\times 9\times 36\times 10^{-3}=5.184\ N[/tex]
nature of force will be attractive i.e. Jeans will try to pull the balloon
A man with a weight of 450 N climbs a ladder to a height of 5.2 meters. How much work did he do?
Answer:
the work done by him is 2,340 joules
Explanation:
The computation of the work done by him is shown below:
= Weight of man × height
= 450 N × 5.2 meters
= 2,340 joules
Hence, the work done by him is 2,340 joules
We simply multiply the man weight with the height
a floating boat weighs 20,000 N what is the size of the upthrust
Answer:
20,000N
explanation:
a body can only float when the upthrust
balances with the weight of the body,
hence in accord with the question,as the body floats the upthrust is equal to it's weight.
We have that For a floating boat weighing 20,000N, the size of the upthrust is
20,000N
From the question we are told
a floating boat weighs 20,000 N what is the size of the upthrust
Generally the equation for the upthrust is mathematically given as
U=W
The upthrust is Directly equal the weight it suspends or acts on in water or any liquid
Since
The upthrust is Directly equal the weight it suspends or acts on in water or any liquid
Therefore
The Upthrust must be Directly equal the Weigh
Therefore
For a floating boat weighing 20,000N, the size of the upthrust is
20,000N
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An electric dipole is formed from ± 5.0 nC point charges spaced 3.0 mm apart. The dipole is centered at the origin, oriented along the y-axis. What is the electric field strength at point (x,y) = ( 20 mm ,0cm)? What is the electric field strength at point (x,y) = (0cm, 20 mm )?
Answer:
The electric field strength at point (x,y) = ( 20 mm ,0cm) is =16321.0769 N/C
The electric field strength at point (x,y) = (0cm, 20 mm) is =35321.58999 N/C
Explanation:
Question: What is the electric field strength at point (x,y) = ( 20 mm ,0cm)?
Answer:
The electric field at any given point of the dipole is given as:
E= (KP) ÷ (r^2 + a^2)^3/2
Where:
K = 9x10^9 Nm^2/c^2 (coloumb constant)
P = (0.003) (5x10^-9c) which is the movement of the dipole
(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.
r= the point, in the question above is 20mm = 0.02m
Now, the electric field, E can be calculated by putting the values in the formula above:
E = (KP) ÷ (r^2 + a^2)^3/2
= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2
= 0.135 ÷ (8.271513x10^-6)
=16321.0769 N/C
Question: What is the electric field strength at point (x,y) = (0cm, 20 mm )?
Answer:
Here, the electric field, E= 2krp ÷ (r^2 - a^2)^2
E= 2 (9x10^9 Nm^2/c^2) (0.02m) (0.003 m) (5x10^-9c) ÷ [(0.02m)^2 - (0.003)^2]^2
= 0.0054 ÷ 0.000000152881
=35321.58999 N/C
d. Two point charges, q1 = +25 nC and q2 = -75 nC, are separated by a distance of 3.0 cm. Find the magnitude and direction of; i. the electric force q1 exerts on q2 [5] ii. the force that q2 exerts on q1 [4] (take k = 9.0 x 109 N.m2 /C2 )
Answer:
a) F₂₁ = 0.02 N, attracting.
b) F₁₂ = 0.02 N, attracting.
Explanation:
a)
The magnitude of the force that q₁ exerts on q₂ (F₂₁) is given by Coulomb's Law, as follows:[tex]F_{21} = k * \frac{q_{1} *q_{2}}{r_{12}^{2} } = 9e9 N.m2/C2 * \frac{(25e-9C)*(75e-9C)}{(0.03m)^{2}} = 0.02 N (1)[/tex]
Since q₁ and q₂ have opposite signs, the force between them will be always attractive, i.e., from q₂ towards q₁, along the line that joins both charges.b)
The magnitude of the force on q₁ due to q₂ can be obtained applying Newton's 3rd Law, or using (1), because all parameters are the same, so F₁₂ (in magnitude) = F₂₁ = 0.02 NAs we have already said, it must be opposite to the one found in a) so it must go from q₁ towards q₂, it is an attracting force also.What is the weight of a 3000g girl who is swimming in the Pacific Ocean?
Answer: 3000g ;-;
she feels lighter in the water but the water doesn't actually take away her weight
Explanation:
How many electron flow through a light bulb each second if the current flow through the light bulb 0.75A.The electric charge of one electron is 1.6 x 10-19C
Answer:
[tex]n=4.68\times 10^{18}[/tex]
Explanation:
The current through the bulb, I = 0.75 A
We need to find the number of electrons flowing per second. We know that the electric current is given by :
[tex]I=\dfrac{ne}{t}\\\\n=\dfrac{It}{e}\\\\n=\dfrac{0.75\times 1}{1.6\times 10^{-19}}\\\\n=4.68\times 10^{18}[/tex]
So, there are [tex]4.68\times 10^{18}[/tex] electrons flowing per second.
There are "[tex]4.68\times 10^{18}[/tex]" electron flowing per second.
Electric charge:Whenever retained inside an electric as well as the magnetic field, this same basic physical attribute of matter which thus permits it to perceive a force, is considered as Electric charge.
According to the question,
Current flow, I = 0.75 A
Electric charge of one electron, e = 1.6 x 10⁻¹⁹ C
As we know the relation,
Current, I = [tex]\frac{ne}{t}[/tex]
or,
→ n = [tex]\frac{It}{e}[/tex]
By substituting the given values in the above formula, we get
= [tex]\frac{0.75\times 1}{1.6\times 10^{-19}}[/tex]
= [tex]4.68\times 10^{18}[/tex]
Thus the approach above is appropriate.
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Light undergoes refraction as it travels from water to glass. The refractive index of water = 1.33 and refractive index of glass = 1.5. Calculate the angle of refraction inside glass if angle of incidence in the water is 32 degrees
Answer:
28°
Explanation:
Snell's Law and equation
Can someone please help
ummmmmmmmmmm thats confusing
when an object slides over a smooth horizontal surface, how does the force of friction depend on the surface area of blocks that's are in contact with the table?
Answer: with a greater surface area, there will be a greater force of friction
Explanation:
Season and date for this person
Answer:
summer June 21 is the answer
12. If the distance an object travels and the time it takes to travel the distance are known, which of the following can be calculated? А Average speed B Average acceleration С Instantaneous speed Instantaneous acceleration
Answer:
A
Explanation:
Average speed
Which type of land usage would increase as the population increases?
Answer:
If the population were to INCREASE land use would also INCREASE, if the human population DECREASED so would land use because there wouldn’t be as many people to using it. hope i helped
Answer:
D. Urban use
Explanation:
It shows here on this graph that overtime urban use is rising as the population is increasing! The other answers that are on this graph does not show it increasing!
Where do animals such as snakes and frogs, which do not make their own body heat, usually get their heat?
fuel
the sun
hot lava
friction
plssssssss answer correctly
The answer to this question is the Sun.
As im writing this, 12,826 people vote the Sun.
animals such as snakes and frogs, which do not make their own body heat. They usually get their heat from the sun. Hence option B is correct.
What is Cold-blooded animals ?A body temperature that is only slightly higher than the ambient temperature. This condition differentiates cold-blooded, or homoiothermic, animals from fishes, amphibians, reptiles, and invertebrates (birds and mammals). Due of their reliance on external warmth for metabolic activity, terrestrial cold-blooded species are restricted to locations with temperatures ranging from 5-10° to 35-40° C (41-50° to 95-104° F).
Cold-blooded creatures cannot create their own body heat, but they may control it by modifying their surroundings. Alligators and other reptiles frequently lay in the sun to warm up. They, on the other hand, cool off by swimming, going into a burrow in the earth, or moving inside the sade of a rock.
Hence option B is correct.
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