What is the probability that a point randomly chosen in the large triangle is also in Region A?
The grid ranges from 0 to 16 on the horizontal axis and from 0 to 12 on the vertical axis. A polygon with vertices at begin ordered pair 0 comma 0 end ordered pair comma begin ordered pair 0 comma 10 end ordered pair and begin ordered pair 14 comma 0 end ordered pair. The polygon is subdivided into 2 regions. Region A is a trapezoid with vertices at begin ordered pair 0 comma 0 end ordered pair comma begin ordered pair 0 comma 10 end ordered pair comma begin ordered pair 7 comma 5 end ordered pair and begin ordered pair 7 comma 0 end ordered pair. Region B is a triangle with vertices at begin ordered pair 7 comma 0 end ordered pair comma begin ordered pair 7 comma 5 end ordered pair and begin ordered pair 14 comma 0 end ordered pair.
37.5%
62.5%
70%
75%
Answers
Answer:
75
Step-by-step explanation:
The probability that a point randomly chosen in the large triangle is also in Region A will be 11/36.
What is probability?Probability of an event is the ratio of number of favorable outcomes to the total number of outcomes.
Probability is a measure of how likely an event is going to happen.
Given is to find the probability that a point randomly chosen in the large triangle is also in Region A.
We can find the area of region A as -
Area{A} = A{Rectangle} + A{Right triangle}
Area{A} = (Length x Breadth) + (1/2 x base x height)
Area{A} = (5 x 2) + (1/2 x 1 x 2)
Area{A} = 10 + 1
Area{A} = 11 square units
Total area of the region {A + B} as -
Total Area{A + B} = 11 + (1/2 x 10 x 5)
Total Area{A + B} = 11 + 25
Total Area{A + B} = 36 square units
The probability that a point randomly chosen in the large triangle is also in Region A will be -
P{A} = (Area{A}/Total Area{A + B})
P(A) = 11/36
Therefore, the probability that a point randomly chosen in the large triangle is also in Region A will be 11/36.
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Answer:
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Step-by-step explanation:
From the above question:
Total number of marbles = 10 marbles
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