Answer:
The power output of the reactor is approximately 63.387 MW
Explanation:
The energy released per one fission reaction = 200 MeV
The Avogadro's number, [tex]N_A[/tex] = 6.023 × 10²³
The mass of fuel used = 2 kg
The mass of one mole of uranium 235, U²³⁵ = 235 grams = 0.235 kg
Therefore, the number of moles of U²³⁵ in 2 kg = 2 kg·mol⁻¹/(0.235 kg) = 400/47 moles ≈ 8.51 moles
The number of uranium atoms in 400/47 moles of U²³⁵ = (400/47) × 6.023 × 10²³ ≈ 5.126 × 10²⁴ atoms of U²³⁵
The energy released per fission of an atom = 200 MeV = 200 × 10⁶ eV × 1.602177 × 10⁻¹⁹ J/(eV) ≈ 3.204354 × 10⁻¹¹ J
The energy, 'E', released by the 5.126 × 10²⁴ atoms of U²³⁵ in the 2 kg of U²³⁵ is given as follows;
E = 3.204354 × 10⁻¹¹ J/atom × 5.126 × 10²⁴ atoms = 1.643 × 10¹⁴ Joules
The power, P = Energy/Time
The time = 30 days = 30 × 24 × 60 × 60 = 2,592,000 seconds
∴ P = (1.643 × 10¹⁴ Joules)/(2,592,000 s) = 63.3873457 megawatts ≈ 63.387 MW
The power output of the reactor, P ≈ 63.387 MW
**Can someone please help me solve these problems step by step, thank you!
1. If a 12-inch diameter driving Gear A has 100 tooth which turns CCW with a torque of 200 ft-lb and 100 rpm is meshed with Gear B, 25 tooth, turn along with Gear C, 50 tooth as they are a compound gear and Gear D, 150 tooth meshed with C.
-->sketch and annotate the gear train.
-->what direction does gear ratio B, C, and D turn?
-->what is the gear ratio for B, C, and D?
-->what is the angular velocity for gears B, C, and D?
-->what is the torque for gears B, C, and D?
-->what is the diameter of gears B, C, and D?
2. In a pulley system, pulley A is moving 1000 rpm and has a diameter of 18inches. There are two pulleys with different sizes, B moving ot 1575 rpm and C moving at 1850 rpm attached on a single axle.
-->sketch and annote the pulley system.
-->what is the diameter of pulley B and pulley C?
Answer:
The answer is "[tex]\bold{11.428 \ in \ \ and \ \ 9.729 \ in}[/tex]".
Explanation:
The second question solution can be defined as follows:
[tex]N_A= 1000 \ rpm\\\\N_B=1575 \ rpm\\\\N_C=1850 \ rpm\\\\D_A= 18 \ in \\\\[/tex]
In point 1:
Calculating the value of the linear velocity is the same:
[tex]\to V_A=V_B\\\\\to \pi D_A N_A=\pi D_BN_B\\\\\to D_B= \frac{D_A \times N_A}{N_B}[/tex]
[tex]=\frac{18 \times 1000}{1575}\\\\=11.428 \ in \ \ \text{Diameter of pulley B}[/tex]
In point 2:
[tex]\to V_A=V_C\\\\\to \pi D_A N_A=\pi D_C N_C\\\\\to D_C=\frac{D_A \times N_A}{N_C}\\\\[/tex]
[tex]=\frac{1000 \times 18}{1850}\\\\=9.729 \ in \ \ \text{Diameter of pulley B}[/tex]
Dim the room lights. Neutralize the plate and put it back on the charged Styrofoam plate. With the tape up, touch the free wire from the bulb while watching the electrodes inside the casing.The light produced may be weak so you may have to shadow the bulb to see the flash. Lift the plate, check that the tape rises again and touch the free bulb wire while observing the bulb. Without charging the Styrofoam, repeat placing the pie pan on and then off the Styrofoam plate, each time touching the free wire while observing which electrode lights. For each case, state whether the light emanates for the electrode connected to the free wire or from the electrode attached to the rim. Based on the results of the previous step, explain how your results are consistent (or inconsistent with the sign of the charge on the rim as determined in steps 4-6 of the instructions, assuming the Styrofoam plate becomes positively charged when rubbed with paper towels.
Which statement describes a possible limitation on a experimental design? A. Collecting samples to analyze is expensive B. The experiment has a very simple procedure C. The subject of the experiment has been studied by other scientist's D. There is a large number of constants
Answer:
A. Collecting samples to analyze is expensive
Explanation:
Experimental research designs may be referred to as an analytical approach which is based on establishing a scientific hypothesis through by subjecting observations or subjects to certain treatment carried out in a controlled environment. In a typical experimental research design, we have two groups which are the constant group or observation and the variable group which are the actual experimetal group which are subjected to treatment and whose behavior are compared to that of the constant group. From the options given, one actual limitation of the experimetal research design is the associated cost particularly those which require longer time to study and analyse. Other limitations include ; difficulty in measuring human response and skepticism over applicability of findings in a natural environment.
Answer:
collecting samples to analyze is very expensive is correct^
Explanation:
just took the quiz, thanks btw
Summarize three reasons for the failure of the Tacoma Narrows Bridge, and identify the steps in the engineering design process they relate to.
Answer:
1) Perform
2) Prototype
Explanation:
The prototype testing phase of the design process to test the readiness of the design for the intended use
The prototype which is a first or early model of the project made so as to ensure proper functioning of the concept is to pass through general function test as well as design performance evaluation in a testing or lab setting
Other tests include, excessive stress test, testing to failure and other design tests.
Therefore;
The problem faced by Galloping Gertie the failed bridge across the Tacoma Narrows, was caused because the engineers did not perform tests on the prototype in the engineering design process.