what is the pH of the 1.0 M KOH solution?

Answer: [tex]49.7\ cm^3[/tex]

Explanation:

Given

At temperature [tex]T_1=289\ K[/tex]

Volume is [tex]V_1=42\ cm^3[/tex]

and the temperature changes to [tex]T_2=342\ K[/tex]

At this temperature volume is [tex]V_2[/tex]

Consider Pressure remains the constant

[tex]\therefore \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\\Rightarrow V_2=V_1\times \dfrac{T_2}{T_1}\\\\\text{Insert values}\\\\\Rightarrow V_2=42\times \dfrac{342}{289}\\\\\Rightarrow V_2=49.7\ cm^3[/tex]

The volume at this temperature is [tex]49.7\ cm^3[/tex]

The Balanced chemical equation for above reaction will be :

[tex] \small{ \mathrm{3NaBr + H_3PO_4 \rightarrow Na_3PO_4 + 3HBr}}[/tex]

The Coefficients will be :

So, Correct option is :

A. 3, 1, 1, 3

_____________________________

[tex]\mathrm{ \#TeeNForeveR}[/tex]

Answer: the answer is a

Explanation:

always eat fresh fruits and veggiies.

(D)

Explanation:

On the left side two molecules, each made of 2 grays and 3 blues, which suggests that only (D) offers the right combination: 2 Al atoms and 3 O atoms that make up Al2O3.

Answer:

54.93 g/mol

Explanation:

a) the element with symbol Mn is known as Manganese and I figured it out by looking at the periodic table.

b) I took a look at the periodic table again, and seen how much the atomic mass is and from there I observed:

Mn= 54.938 g/mol

rounded is 54.94 g/mol

Answer:

433 m

Explanation:

Since the fall represents motion under gravity, we use the equation

s = ut - 1/2gt² where s = height of cliff or distance bowling ball falls through, u = initial velocity of bowling ball = 0 m/s(since it starts from rest), t = time = 9.4 s and g = acceleration due to gravity = -9.8 m/s².

So, substituting the values of the variables into the equation, we have

s = 0 m/s × 9.4 s - 1/2 × 9.8 m/s² × (9.4 s)²

s = 0 m - 1/2 × -9.8 m/s² × 88.36 s²

s = 1/2(865.928 m)

s = 432.964

s ≅ 433 m

Answer:

This natural gas deposit contains 1,300,813.008 moles.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

Replacing:

15 atm* 2.24*10⁶ L= n*0.082 [tex]\frac{atm*L}{mol*K}[/tex]* 315 K

Solving:

[tex]n=\frac{15 atm* 2.24*10^{6}L }{0.082\frac{atm*L}{mol*K}*315 K}[/tex]

n=1,300,813.008 moles

This natural gas deposit contains 1,300,813.008 moles.

Answer:

d. Two moles of carbon dioxide were produced from this reaction

Explanation:

The given chemical reaction can be written as follows;

2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

From the above chemical reaction, we have;

Two moles of C₂H₂ reacts with five moles of O₂ to produce four moles of CO₂ and two moles of H₂O

We have;

One mole of C₂H₂ will react with two and half moles of O₂ to produce two moles of CO₂ and one mole of H₂O

Therefore, in the above reaction, when one mole of C₂H₂ is used, two moles of CO₂ will be produced.

Explanation:

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Answer:

2. 16.4 L

3. 243.6K

4. 0.25mol

Explanation:

Using the ideal gas formula for the series of questions in this case, we have;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

QUESTION 2:

V = ?

P = 5 atm

n = 3 mol

T = 60°C = 60 + 273 = 333K

PV = nRT

5 × V = 3 × 0.0821 × 333

5V = 82.02

V = 82.02/5

V = 16.4 L

QUESTION 3:

P = 4 atm

V = 7.5L

n = 1.5mol

T = ?

PV = nRT

4 × 7.5 = 1.5 × 0.0821 × T

30 = 0.123T

T = 30/0.123

T = 243.6K

QUESTION 4:

P = 2.00 atm

V = 3L

n = ?

T = 25°C = 25 + 273 = 298K

PV = nRT

2 × 3 = n × 0.0821 × 298

6 = 24.47n

n = 6/24.47

n = 0.25mol

Answer:

halving, the mass of planet X and halving the distance between the planets

The gravitational force of attraction is the fundamental force of the universe. Doubling the mass of planet X and halving the distance between the planets increases the gravitational attraction. The correct option is C.

The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them. The formula of gravitational force is given as:

F = G m₁m₂ / r²

From the equation it is clear that the gravitational force increases with the increase in the mass and decreases with the increase in the distance between the objects. This law is true for each particle of matter, each particle of matter attracts every other particles.

Here doubling the mass of planet X and halving the distance between the planets increases the gravitational attractive force.

Thus the correct option is C.

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They are found in all living things. Hence, option D is correct.

An atom is any particle of matter which contains at least one proton.

Carbon is stored in plants and trees. Plants take carbon dioxide from the atmosphere to make the building blocks of food during photosynthesis. Carbon is stored in the hydrosphere and dissolved in ocean water and lakes. Carbon is used by several organisms to produce shells.

Hence, option D is correct.

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Answer:

0.021

Explanation:

that's the answer because I just did an exam that included this question and then the miss explained to me why this was the answer, but don't worry am 100% sure the answer is 0.021 .

The mole fraction of ethanol in a solution of 47.5 g of ethanol in 850 g of water is 0.021.

Mole fraction of any substance present in solution will be calculted by dividing the moles of sample to the total moles of solution.

Moles will be calculated as:

n = W/M , where

W = given mass

M = molar mass

Moles of ethanol will be calculated as:

n = 47.5g / 46.07g/mol = 1.03 moles

Moles of water will be calculated as:
850g / 18g/mol = 47.18 moles

Total moles of solution = 1.03 + 47.18 = 48.21 moles

Mole fraction of ethanol in water will be calculated as:

mole fraction = 1.03 / 48.21 = 0.021

Hence, mole fraction is 0.021.

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Answer:

It partially ionizes

Explanation:

Higher tier) Weak acids only partially ionise in water. Only a small fraction of their molecules break into hydrogen ions when added to water.

Answer:

0.075 moles of iron oxide would be produced by complete reaction of 0.15  moles of iron.

Explanation:

The balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

You can apply the following rule of three: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, 0.15 moles of Fe produce how many moles of Fe₂O₃?

[tex]moles of Fe_{2} O_{3} =\frac{0.15 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}[/tex]

moles of Fe₂O₃= 0.075

0.075 moles of iron oxide would be produced by complete reaction of 0.15  moles of iron.

Answer:

0.11 moles

Explanation:

The equation of the reaction is;

2SO2 + O2 ------>2SO3

Number of moles of O2 in 3.42 g = 3.42g/32 g/mol = 0.11 moles

Hence, 0.11 moles of O2 is consumed when 3.42 g of O2 reacts with SO2 to form SO3.

Answer:

The restoring force that prevents the furniture from tipping over when pushing the furniture towards the right, F= W × D

Where;

W = The weight of the furniture

D = The horizontal distance from the center of gravity of the furniture, CG and the to the lower right corner of the furniture

Given that A > D, for the furniture to tip over when pushing above the CG, we have;

F1 × A ≤ W × D

∴ F1 << W or for a force much smaller than W, the weight of the furniture applied above the center of gravity, the furniture will tip over

However when the force F2 is applied, where C < D, we have for no tipping over;

F2 × C ≤ W × D, therefore, given that C < D, when a force much higher than the weight, W, is applied at F2, the furniture will remain upright

Therefore, it is better push at a point lower than or equal to the center of gravity, whereby the point B is lower than the center of gravity, it is better to push at point B, Ravleen is correct and it is better to push at point B because the center of gravity is lower

If the furniture is pushed at the wrong spot it may tip over

Please see attached drawing

Explanation:

The presence of rust in the water of Westfield is the reason for the change in colour.

The water of Westfield has reddish-brown substance. This reddish brown substance in the water is the rust which formed due to the chemical reaction between the iron pipes and the fertilizer substance present in the water.

Due to this reaction, the colour of Westfield's water is different from normal type of water so we can conclude that the presence of rust in the water of Westfield is the reason for the change in colour.

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Answer:

2Na + 2H20--> 2NaOH+H2

............. this is the ans

Answer:

See Explanation

Explanation:

Volume of base used  = (31.79 - 1.6) + (32.12 - 0.98) + (42.87 -13.21)/3 = 30.34 cm3

Volume of acid used = (24.86 - 0.42) + (24.11 - 0.11) + (27.67 -3.42)/3 = 24.23 cm3

For trial 1= number of moles of HBr = 24.44/1000 * 0.3 = 0.0073 moles

For trial 2= number of moles of HBr = 24/1000 * 0.3 = 0.0072 moles

For trial 3= number of moles of HBr = 0.0089 moles

HBr(aq) + KOH(aq) -----> KBr(aq) + H2O(l)

One mole of base is required to neutralize one mole of acid.

From CAVA/CBVB =nA/nB

CAVAnB = CBVBnA

CB = CAVAnB/VBnA

CB = 0.3 * 24.23 * 1/30.34  * 1

CB = 0.24 moldm-3

number of moles of KOH = concentration * volume

number of moles = mass/molar mass

molar mass of KOH = 56 g/mol

mass/56 =  0.24 * 30.34/1000

mass = 0.24 * 30.34/1000 * 56

mass =0.408 g of KOH

Answer:

sodium phosphide!!!!!!!!!!!!!!!

44.5 g Al2(SO4)3

Explanation:

# moles Ba(NO3)2 = (0.543M)(0.717 L)

= 0.389 mol Ba(NO3)2

Now we use the molar ratios,

0.389 mol Ba(NO3)2 ×(1 mol Al2(SO4)3/3 mol Ba(NO3)2)

= 0.130 mol Al2(SO4)3

0.130 mol Al2(SO4)3 × (342.15 g Al2(SO4)3/(1 mol Al2(SO4)3)

= 44.5 g Al2(SO4)3

Answer:

:D

Explanation:

8. D. All of the above

9. C. Mechanical weathering

10. D. All of the above

Answer:

8. D

9. A

10. D

Answer:

600.7 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

From the question,

Given: P = 190 atm, V = 35 L, T = 135 K

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

n = (190×35)/(135×0.082)

n = 600.7 moles of xygen

The molarity (M) of a solution is 11.5 M that contains 0.75 moles of lithium fluoride, LiF in a 65 ml of solution.

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar concentration. The S.I Unit of Molarity is molar (M) or mol/L.

Molarity (M) = [tex]\frac{\text{Number of moles of solute}}{\text{Volume of solution (in liters)}}[/tex]

From the above definition it is clear that the volume of solution is in liter. In question the volume of solution is given in ml.

So, convert 65 ml into l.

65 ml = [tex]\frac{65}{1000}[/tex] = 0.065 l

Now, put the values in above formula, we get that

(M) = [tex]\frac{0.75}{0.065}[/tex] = 11.5 M

Thus, the molarity of a solution is 11.5 M that contains 0.75 moles of lithium fluoride, LiF in a 65 ml of solution.

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Answer:

1. Allele for shortness (t)

2. Allele for tallness (T)

Explanation:

Gregor Mendel performed numerous experiments using pea plants (Pisium sativum). He tested the height traits of pea plants by crossing tall pea plants (TT) and short pea plants (tt) to obtain offsprings that were all tall (Tt) in the first filial generation (F1).

This is possible because the allele for tallness is DOMINANT while the allele for shortness is RECESSIVE. This means that tallness allele (T) will mask the phenotypic expression of shortness allele (t) when in an heterozygous state (Tt) as in the F1 generation.