What is the percent yield if 160 g of O2 reacts with excess C3H8 to produce 66 g of CO2?

Answers

Answer 1

To calculate the percent yield, we need to first find the theoretical yield, which is the amount of product that would be obtained if the reaction proceeded perfectly.

The balanced chemical equation for the reaction between C3H8 and O2 to form CO2 and H2O is:

C3H8 + 5O2 → 3CO2 + 4H2O

According to the equation, 1 mole of C3H8 reacts with 5 moles of O2 to produce 3 moles of CO2. We can use this information to calculate the theoretical yield of CO2 that would be obtained if all the O2 reacted:

160 g O2 × (1 mol O2 / 32 g/mol O2) × (3 mol CO2 / 5 mol O2) × (44 g/mol CO2) = 277.5 g CO2 (theoretical yield)

Now, we can calculate the percent yield by dividing the actual yield by the theoretical yield and multiplying by 100:

percent yield = (actual yield / theoretical yield) × 100

In this case, the actual yield is given as 66 g CO2. Substituting this value into the equation gives:

percent yield = (66 g CO2 / 277.5 g CO2) × 100 ≈ 23.8%

Therefore, the percent yield of the reaction is approximately 23.8%.

To know more about percent yield refer here

https://brainly.com/question/17042787#

#SPJ11


Related Questions

A mixture of three noble gases has a total pressure of 1. 25 atm. The individual pressures exerted by neon and argon are 0. 68 atm and 0. 35 atm, respectively. What is the partial pressure of the third gas, helium?

Answers

The partial pressure of helium in the mixture of noble gases is 0.22 atm.

To find the partial pressure of helium, we need to subtract the pressures of neon and argon from the total pressure of the mixture. Given that the total pressure is 1.25 atm, and the pressures exerted by neon and argon are 0.68 atm and 0.35 atm, respectively, we can calculate the partial pressure of helium as follows:

Partial pressure of helium = Total pressure - Pressure of neon - Pressure of argon

Partial pressure of helium = 1.25 atm - 0.68 atm - 0.35 atm

Partial pressure of helium = 0.22 atm

Therefore, the partial pressure of helium in the mixture is 0.22 atm.

To learn more about partial pressure click here : brainly.com/question/30114830

#SPJ11

What is the ph at the half-equivalence point in the titration of a weak base with a strong acid? the pkb of the weak base is 8.60.

Answers

You asked: What is the pH at the half-equivalence point in the titration of a weak base with a strong acid? The pKb of the weak base is 8.60.

To determine the pH at the half-equivalence point, follow these steps:

1. Calculate the pKa from the given pKb:
pKa = 14 - pKb = 14 - 8.60 = 5.40

2. At the half-equivalence point, the concentration of the weak base is equal to the concentration of its conjugate acid.

This is because half of the weak base has been titrated with the strong acid, forming the conjugate acid.

3. At this point, the pH is equal to the pKa of the weak acid (conjugate acid of the weak base).

So, the pH at the half-equivalence point in the titration of a weak base with a strong acid, with a pKb of 8.60, is 5.40.

To know more about half-equivalence refer here

https://brainly.com/question/13587904#

#SPJ11

a gas has a volume of 24 l at 3.0 atmospheres. what will the volume at 2.0 atmospheres be (n and t constant)?

Answers

The volume of the gas at 2.0 atmospheres would be 36 L, assuming that the number of moles (n) and temperature (T) of the gas remain constant.

This problem can be solved using the combined gas law, which states that the product of pressure and volume divided by temperature is constant when the number of moles of gas remains constant.

Mathematically, this can be represented as P₁V₁/T₁ = P₂V₂/T₂, where P₁ and V₁ are the initial pressure and volume, T₁ is the initial temperature, P₂ is the final pressure, and V₂ is the final volume.

Using the given values, we can plug them into the formula to find the final volume: P₁V₁/T₁ = P₂V₂/T₂

(3.0 atm) (24 L) / T = (2.0 atm) V₂ / T

V₂ = (3.0/2.0) (24 L) = 36 L.

To know more about moles, refer here:

https://brainly.com/question/30759206#

#SPJ11

1. Write a C++ Range Based For Loop to sum the values of the array foo. const int SIZE = 1024; int foo[ SIZE]; 2. Write a C++ For Loop to sum the odd elements of the array foo. double foo[2000);

Answers

Here's the code for the first task using range-based for loop:

c++

Copy code

const int SIZE = 1024;

int foo[SIZE];

int sum = 0;

// initialize foo array with values

for (int i = 0; i < SIZE; i++) {

   foo[i] = i;

}

// sum the values using a range-based for loop

for (int val : foo) {

   sum += val;

}

std::cout << "The sum of the array is: " << sum << std::endl;

Here's the code for the second task using a regular for loop:

c++

Copy code

const int SIZE = 2000;

double foo[SIZE];

double sum = 0.0;

// initialize foo array with values

for (int i = 0; i < SIZE; i++) {

   foo[i] = i * 1.5;

}

// sum the odd elements using a for loop

for (int i = 0; i < SIZE; i++) {

   if (i % 2 != 0) {  // check if the index is odd

       sum += foo[i];

   }

}

std::cout << "The sum of the odd elements in the array is: " << sum << std::endl;

In this example, we first initialize the foo array with some values. Then we iterate over the array using either a range-based for loop or a regular for loop. In the range-based for loop, we use a range-based syntax to iterate over each value in the array. In the regular for loop, we use an index variable to access each element of the array. Inside the loop, we check if the index is odd and add the corresponding value to the sum variable. Finally, we print the result to the console.

To know more about C++ visit:

https://brainly.com/question/30299547

#SPJ11

[2 Fe + Cu(SO4)2 – 2 FeSO4 + Cu]


How many atoms of Cu is created from 6. 02 x 1023 atoms of Fe?


o 1. 20 x 1024 atoms


O 6. 02 x 1023 atoms


O 3. 01 x 1023 atoms

Answers

6.02 x 1023 atoms of Fe can produce 1.51 x 1023 atoms of Cu. Answer: 1.51 x 1023 atoms.

The balanced equation for the reaction between iron (Fe) and copper (II) sulfate (CuSO4) can be represented as follows:2 Fe + CuSO4 → Fe2(SO4)3 + CuOne mole of Fe (55.85 g) reacts with one mole of CuSO4 (159.6 g) to produce one mole of Cu (63.55 g) and one mole of Fe2(SO4)3 (399.88 g).Now, let's determine the number of moles of Fe that react with CuSO4 to produce Cu. According to the balanced equation, two moles of Fe reacts with one mole of CuSO4 to produce one mole of Cu. This means that one mole of Cu can be produced from 2 moles of Fe.We can use this relationship to solve the problem.6.02 x 1023 atoms of Fe is equivalent to one mole of Fe.We can use this as a conversion factor to determine the number of moles of Fe in 6.02 x 1023 atoms of Fe as follows: 6.02 x 1023 atoms Fe x (1 mole Fe/6.022 x 1023 atoms Fe) = 1 mole FeThus, 6.02 x 1023 atoms of Fe is equivalent to 1 mole of Fe.Using the mole ratio from the balanced equation, we can determine the number of moles of Cu that can be produced from 1 mole of Fe as follows:1 mole Fe x (1 mole Cu/2 moles Fe) = 0.5 mole CuThus, 1 mole of Fe can produce 0.5 mole of Cu. We can use this as a conversion factor to determine the number of moles of Cu that can be produced from 6.02 x 1023 atoms of Fe as follows:6.02 x 1023 atoms Fe x (1 mole Fe/6.022 x 1023 atoms Fe) x (1 mole Cu/2 moles Fe) = 0.25 mole CuThus, 6.02 x 1023 atoms of Fe can produce 0.25 mole of Cu.Finally, we can use Avogadro's number (6.022 x 1023 atoms/mol) to determine the number of atoms of Cu that can be produced from 0.25 mole of Cu as follows:0.25 mole Cu x (6.022 x 1023 atoms/mol) = 1.51 x 1023 atoms Cu.

for such more questions on atoms

https://brainly.com/question/6258301

#SPJ8

A rigid tank is holding 1. 786 mol of argon (Ar) gas at STP. What must be the size (volume) of the tank interior?

Answers

To determine the size (volume) of the tank interior holding 1.786 mol of argon gas at STP (standard temperature and pressure), we need to use the ideal gas law equation, PV = nRT. At STP, the temperature (T) is 273.15 K, and the pressure (P) is 1 atm. We also need to know the gas constant (R), which is 0.0821 L·atm/(mol·K). By rearranging the equation and solving for volume (V), we find that the size of the tank interior must be approximately 38.7 L.

The ideal gas law equation, PV = nRT, relates the pressure (P), volume (V), number of moles (n), gas constant (R), and temperature (T). At STP, the temperature is 273.15 K, and the pressure is 1 atm.

Rearranging the equation to solve for volume (V), we have V = (nRT) / P. Plugging in the values for the number of moles (n) as 1.786 mol, the gas constant (R) as 0.0821 L·atm/(mol·K), and the pressure (P) as 1 atm, we get V = (1.786 mol * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm.

Simplifying the equation, we find V = 38.7 L. Therefore, the size (volume) of the tank interior holding 1.786 mol of argon gas at STP must be approximately 38.7 L.

To learn more about STP - brainly.com/question/24050436

#SPJ11

If you had 5. 69 x 1025 atoms of Mg, how many moles would you have?

Answers

To calculate the number of moles from a given number of atoms, we need to use Avogadro's number, which represents the number of atoms in one mole of a substance. Avogadro's number is approximately 6.022 x 10^23 atoms/mol.

To determine the number of moles from 5.69 x 10^25 atoms of Mg, we divide the given number of atoms by Avogadro's number.

By dividing 5.69 x 10^25 atoms by 6.022 x 10^23 atoms/mol, we find that the number of moles of Mg is approximately 94.6 moles.

In summary, if you have 5.69 x 10^25 atoms of Mg, you would have approximately 94.6 moles of Mg. This calculation is based on Avogadro's number, which allows us to convert between the number of atoms and the number of moles in a given sample.

To learn more about Avogadro's number - brainly.com/question/28812626

#SPJ11

which one of these species is a monodentate ligand? a. cn- b. edta c. c2o4-2 d. h2nch2ch2nh2

Answers

CN- is a monodentate ligand because it has only one atom (carbon) that can donate a lone pair of electrons to form a coordinate covalent bond with a metal ion.

The other ligands listed are polydentate ligands that can form more than one coordinate covalent bond with a metal ion due to the presence of multiple donor atoms.

EDTA (ethylene diamine tetraacetic acid) has four carboxylate groups and two amine groups, making it a hexadentate ligand.

[tex]C_{2}O_{4-2}[/tex] (oxalate ion) is a bidentate ligand because it has two carboxylate groups that can donate lone pairs to form coordinate covalent bonds.

[tex]H_{2}NCH_{2}CH_{2}CH_{2}NH_{2}[/tex] (ethylenediamine) is a bidentate ligand because it has two amine groups that can donate lone pairs to form coordinate covalent bonds.

To know more about ligand, refer here:

https://brainly.com/question/30114643#

#SPJ11

The actual yield of a product in a reaction was measured as 4. 20 g. If the theoretical yield


of the product for the reaction is 4. 88 g, what is the percentage yield of the product?

Answers

The actual yield of a product in a reaction was measured as 4. 20 g. Percentage yield ≈ 86.07%

The percentage yield of a product is a measure of how efficiently a reaction proceeds in producing the desired product. It is calculated by comparing the actual yield (the amount obtained in the experiment) to the theoretical yield (the maximum amount expected based on stoichiometry).

In this case, the actual yield of the product is measured as 4.20 g, and the theoretical yield is given as 4.88 g.

To calculate the percentage yield, we use the formula:

Percentage yield = (Actual yield / Theoretical yield) × 100%

Substituting the given values:

Percentage yield = (4.20 g / 4.88 g) × 100%

Percentage yield ≈ 86.07%

The resulting value is the percentage yield of the product.

A percentage yield less than 100% suggests that some factors, such as incomplete reactions, side reactions, or product loss during the experiment, contributed to a reduced yield compared to the theoretical maximum. In this case, the 86.07% yield indicates that 86.07% of the maximum expected amount of product was obtained in the reaction.

Calculating the percentage yield allows us to evaluate the efficiency of the reaction and identify any sources of loss or inefficiency. It provides valuable information for process optimization and quality control in chemical reactions.

Learn more about percentage yield here:

https://brainly.com/question/29200507

#SPJ11

Consider the structure of serine in its fully protonated state with a +1 charge. Give the pK, value for the amino group of serine. An answer within +0.5 is acceptable. | pK (-NH) = Give the pka, value for the carboxyl group of serine. An answer within +0.5 is acceptable. pka.(-COOH) = ___. Calculate the isoelectric point, or pl. of serine. Give your answer to two decimal places. pI=____

Answers

The pK value for the amino group of serine is approximately 9.5, the pK value for the carboxyl group of serine is approximately 2.2, and the isoelectric point (pI) of serine is approximately 5.85.

The fully protonated form of serine with a +1 charge is NH3+-CH(COOH)(OH)-.

The pKa value for the amino group (-NH3+) of serine is approximately 9.5.

The pKa value for the carboxyl group (-COOH) of serine is approximately 2.2.

To calculate the isoelectric point (pI) of serine, we need to find the pH at which the molecule has a net charge of zero. At this pH, the number of positive charges (from the NH3+ group) will be equal to the number of negative charges (from the -COO- group).

We can estimate the pI by averaging the pKa values of the two ionizable groups:

pI = (pKa of -NH3+ group + pKa of -COOH group) / 2

pI = (9.5 + 2.2) / 2

pI = 5.85

For more question on amino group click on

https://brainly.com/question/15579114

#SPJ11

For the following IR spectrum for paint taken from a hit-and-run accident, provide the wavenumber for the peak(s) corresponding to a R-CN functional group. 102 100- 98- 96- 94- 92 - % transmittance 90 88- 86- 84 82 - 80 - Mon Apr 11 15:30:57 2016 (GMT-04:00) Mon Apr 11 15:31:20 2016 (GMT-04:00) 78 4000 3500 3000 1500 1000 500 2500 2000 Wavenumbers (cm) -1 cm

Answers

The wavenumber for the peak corresponding to a R-CN functional group in the provided IR spectrum is around 2200 cm⁻¹.

Infrared (IR) spectroscopy is a technique used to identify functional groups in organic molecules based on the absorption of IR radiation. The wavenumber at which a functional group absorbs IR radiation is characteristic of that group.

In the given IR spectrum, the wavenumbers are listed on the x-axis, and the % transmittance is plotted on the y-axis. The functional group of interest is R-CN, which corresponds to a nitrile group (-CN) attached to an organic group (R).

The nitrile group (-CN) typically shows a strong peak in the region between 2200 and 2250 cm⁻¹ in the IR spectrum. Looking at the provided spectrum, we can see a peak in this region, with the highest point of the peak being around 2200 cm⁻¹.

To know more about spectrum, refer here:

https://brainly.com/question/12157930#

#SPJ11

in an alcohol-in-glass thermometer, the alcohol column has length 12.68 cm at 0.0 ∘c and length 22.55 cm at 100.0 ∘c. What is the temperature if the column has length a. 15.10 cm, and b. 22.95 cm.

Answers

An alcohol-in-glass thermometer works by using the principle that volume of a liquid changes with an increase in temperature. By using formula provided, we can calculate temperature and temperature at which alcohol column has a length of 22.95 cm is 84.39°C. Correct answer is option B

An alcohol-in-glass thermometer works on the principle that the volume of a liquid increases with an increase in temperature. In this type of thermometer, a small amount of alcohol is filled into a glass tube and sealed at both ends. As the temperature changes, the volume of the alcohol column changes and hence its length in the tube changes.



To calculate the temperature at which the alcohol column has a length of 15.10 cm, we can use the formula:
T = (L - L0) / (L100 - L0) x 100, where T is the temperature, L is the length of the alcohol column, L0 is the length of the alcohol column at 0.0°C, and L100 is the length of the alcohol column at 100.0°C.



Substituting the given values, we get:
T = (15.10 - 12.68) / (22.55 - 12.68) x 100
T = 57.02°C



Therefore, the temperature at which the alcohol column has a length of 15.10 cm is 57.02°C.
To calculate the temperature at which the alcohol column has a length of 22.95 cm, we can use the same formula:
T = (L - L0) / (L100 - L0) x 100



Substituting the given values, we get:
T = (22.95 - 12.68) / (22.55 - 12.68) x 100
T = 84.39°C



Therefore, the temperature at which the alcohol column has a length of 22.95 cm is 84.39°C. An alcohol-in-glass thermometer works by using the principle that the volume of a liquid changes with an increase in temperature. By using the formula provided, we can calculate the temperature of the thermometer for a given length of the alcohol column. Correct answer is option B

Know more about thermometer here:

https://brainly.com/question/24189042

#SPJ11

Red blood cells are destroyed by phagocytic cells in the liver, spleen and red bone marrow collectively known as this term. - revitalized management system - morphized lymph system - mononuclear monocytic system - reticuloendothelial system

Answers

Red blood cells are destroyed by phagocytic cells in the liver, spleen, and red bone marrow collectively known as the reticuloendothelial system.

The reticuloendothelial system, also known as the mononuclear phagocyte system, is responsible for the destruction of red blood cells. This system comprises phagocytic cells located in the liver, spleen, and red bone marrow. These cells work together to remove old, damaged, or abnormal red blood cells from the bloodstream, preventing them from circulating and causing harm. The phagocytic cells engulf and break down the red blood cells, recycling their components for use in producing new red blood cells.

This process ensures a healthy balance of red blood cells, which are essential for carrying oxygen and nutrients throughout the body. The reticuloendothelial system plays a crucial role in maintaining homeostasis and overall health.

To know more about the mononuclear phagocyte system visit:

https://brainly.com/question/30025395

#SPJ11

86. What attracts or directs the synthesis enzyme to the template in Translation? a. Start Codon b. 5'-cap c. Primer d. Promoter e. Poly-A Tail
92. Which of the following is the description for Catabolic Reactions? a. the energy of movement b. the breaking down of complex molecules into simpler ones c. energy converted from one form to another d. energy is neither created nor destroyed e. the linking of simple molecules to form complex molecules

Answers

86. The element that attracts or directs the synthesis enzyme to the template in Translation is a. Start Codon. The start codon is a specific sequence of nucleotides that signals the beginning of the translation process. 92. The description for Catabolic Reactions is b. the breaking down of complex molecules into simpler ones. These reactions release energy by breaking down complex molecules and are involved in processes like digestion and cellular respiration.

For the first question (86), the long answer is that the synthesis enzyme is attracted and directed to the template in Translation by the start codon. The start codon, which is usually AUG in eukaryotic cells, signals to the synthesis enzyme that it should begin the process of synthesizing a protein. The start codon is located at the beginning of the messenger RNA (mRNA) sequence, and once the synthesis enzyme recognizes it, it begins to read the codons that follow and assemble the corresponding amino acids to form the protein. For the second question (92), the long answer is that catabolic reactions are the breaking down of complex molecules into simpler ones. These reactions release energy that can be used for cellular processes. Catabolic reactions are the opposite of anabolic reactions, which involve the linking of simple molecules to form complex molecules and require energy input. The energy released from catabolic reactions can be converted from one form to another and used for activities such as movement, transport, and chemical reactions.

To know more about enzyme visit :-

https://brainly.com/question/29990904

#SPJ11

You create solutions of H2SO4 and NaOH with concentrations of 1.25M and 0.84M ,respectively. If you titrate 10.0 mL of the H2SO4 solution with the NaOH base you have created, at what volume do you expect to see the equivalence point?

Answers

To determine the volume at which we expect to see the equivalence point when titrating 10.0 mL of a 1.25 M H2SO4 solution with a 0.84 M NaOH solution, we need to use the concept of stoichiometry and the balanced chemical equation for the reaction between H2SO4 and NaOH. The balanced equation is 2NaOH + H2SO4 → Na2SO4 + 2H2O. From the equation, we can see that the stoichiometric ratio between NaOH and H2SO4 is 2:1.

Using this ratio, we can calculate the volume of NaOH solution required to react completely with the given volume of H2SO4 solution.

From the balanced chemical equation, we know that the stoichiometric ratio between NaOH and H2SO4 is 2:1. This means that for every 2 moles of NaOH, we need 1 mole of H2SO4. Based on the molar concentrations, we can calculate the moles of H2SO4 present in 10.0 mL of the 1.25 M solution:

Moles of H2SO4 = Concentration * Volume (in liters)

              = 1.25 mol/L * 0.0100 L

              = 0.0125 mol

Since the stoichiometric ratio is 2:1, we need twice the number of moles of NaOH to completely react with the H2SO4. Therefore, the moles of NaOH required are:

Moles of NaOH = 2 * Moles of H2SO4

             = 2 * 0.0125 mol

             = 0.0250 mol

Now, we can calculate the volume of the 0.84 M NaOH solution needed to provide 0.0250 moles of NaOH:

Volume of NaOH solution = Moles of NaOH / Concentration

                      = 0.0250 mol / 0.84 mol/L

                      ≈ 0.0298 L or 29.8 mL

Therefore, we would expect to see the equivalence point at approximately 29.8 mL of the NaOH solution.

To learn more about Stoichiometric ratio - brainly.com/question/6907332

#SPJ11

Determine whether the following compounds are organometallic. Explain your answer. (i) Cacz (ii) CH3COONa (iii) Cr(CO) (iv) B(C2H5)3

Answers

Cacz includes a carbon-metal link, making it an organometallic compound (i). It is an organometallic complex since the element Ca is a metal and is covalently joined to the carbon atom.

(ii) Since CH3COONa lacks a direct carbon-metal connection, it is not an organometallic compound. Na is a metal, but the carbon atoms in the acetate ion are not chemically bound to it.

Cr(CO), which has a carbon-metal link, is an organometallic compound (iii). It is an organometallic molecule because the metal Cr is covalently joined to the carbon monoxide (CO) ligands.

B(C2H5)3 is an organometallic compound since it has a carbon-metal bond. It is an organometallic compound because the metalloid element B is covalently linked to the carbon atoms in the ethyl groups.

For more such question on organometallic

https://brainly.com/question/13428382

#SPJ11

Out of the four given compounds, only B(C_{2}H_{5})_{3} is organometallic. Organometallic compounds are compounds that contain a covalent bond between a carbon atom and a metal atom. In the case of B(C_[2}H_{5})_{3}, there is a covalent bond between a boron atom and three ethyl (C_{2}H_{5}) groups. This makes it an organometallic compound.

Cacz, CH_{3}COONa, and Cr(CO) are not organometallic compounds. Cacz is calcium carbide, which is a simple ionic compound and does not contain any covalent bonds between carbon and metal atoms. CH_{3}COONa is sodium acetate, which is a salt that does not contain any metal atoms. Cr(CO) is a metal carbonyl complex, but it does not have a direct covalent bond between carbon and chromium atoms.In summary, only B(C_{2}H_{5})_{3} is an organometallic compound as it contains a covalent bond between a carbon atom and a boron atom, while the other compounds do not have this feature.

learn more about organometallic refer: https://brainly.com/question/30655091

#SPJ11

A polymer rubber band can stretch more than a metal paper clip because:-covalent bonds along polymer chains can stretch and rotate-covalent bonds along polymer chains can rotate and the van der waals bonds between chains allow chain slippage-covalent bonds along polymer chains can break and the van der waals bonds between chains allow chain slippage-covalent bonds along polymer chains can stretch and the van der waals bonds between chains allow chain slippage-covalent bonds along polymer chains can rotate and break

Answers

The correct answer is: covalent bonds along polymer chains can stretch and the van der Waals bonds between chains allow chain slippage.

When you stretch a polymer rubber band, the covalent bonds along the polymer chains stretch and rotate, allowing the chains to align in the direction of the stretching force.

Simultaneously, the van der Waals forces between the chains allow them to slip past each other, allowing the band to stretch even further. Van der Waals forces are weak intermolecular forces caused by transient dipoles in the electron distribution of polymer chains.

As a result of the elasticity produced by the covalent bonds between the atoms in the polymer chains, when the stretching force is released, the rubber band returns to its original shape.

For such more question on covalent bonds:

https://brainly.com/question/2746509

#SPJ11

The correct answer is: covalent bonds along polymer chains can stretch and the van der Waals bonds between chains allow chain slippage.

When you stretch a polymer rubber band, the covalent bonds along the polymer chains stretch and rotate, allowing the chains to align in the direction of the stretching force. Simultaneously, the van der Waals forces between the chains allow them to slip past each other, allowing the band to stretch even further. Van der Waals forces are weak intermolecular forces caused by transient dipoles in the electron distribution of polymer chains. As a result of the elasticity produced by the covalent bonds between the atoms in the polymer chains, when the stretching force is released, the rubber band returns to its original shape.

 Learn more about polymer here:

brainly.com/question/2746509

#SPJ11

predict the effect on reaction rate when the following change is made: potassium metal replaces lithium in an experiment.

Answers

Replacing lithium with potassium in a chemical reaction is likely to increase the reaction rate.

This is because potassium is more reactive than lithium and therefore can more easily donate its outermost electron to another atom, leading to faster chemical reactions.

Potassium has a larger atomic radius than lithium, which makes it easier for it to lose its outermost electron, leading to an increase in the rate of electron transfer reactions.

Additionally, potassium has a lower ionization energy than lithium, meaning it requires less energy to remove an electron from the outermost shell, allowing the reaction to proceed faster.

Therefore, replacing lithium with potassium in a chemical reaction is likely to increase the reaction rate.

To know more about ionization, refer here:

https://brainly.com/question/28385102#

#SPJ11

Name 2 cities that have an air pressure of exactly 1012 mB for this day

Answers

Air pressure is influenced by various factors such as weather patterns, elevation, and atmospheric conditions, which can vary greatly between different locations and change over time.

To obtain the air pressure readings for a particular day, I would recommend checking reliable weather sources or using weather apps or websites that provide up-to-date atmospheric pressure data. These sources often provide current weather conditions, including air pressure, for various cities around the world.

Additionally, it is worth noting that air pressure readings are typically given in units of hectopascals (hPa) or millibars (mbar) rather than meters of barometric pressure (mB). The standard atmospheric pressure at sea level is approximately 1013.25 hPa or 1013.25 mbar, so finding a precise value of exactly 1012 mB might be uncommon.

Learn more about atmospheric conditions here

https://brainly.com/question/24747263

#SPJ11

The Kb for a weak base is 4.8 x 10-7. What will be the Ka for its conjugate acid at 25 oC?1.4 x 10-37.1 x 10-122.1 x 10-81.2 x 10-94.8 x 10-7

Answers

The Kb for a weak base is 4.8 x 10-7, the Ka for its conjugate acid will be 1.2 x 10^-9.

The Ka value for the conjugate acid of a weak base can be determined by using the relationship Kw = Ka x Kb, where Kw is the ion product constant of water (1.0 x 10^-14 at 25°C), and Kb is the base dissociation constant.

Given that Kb for the weak base is 4.8 x 10^-7, we can calculate its pKb value as follows:

pKb = -log(Kb)

= -log(4.8 x 10^-7)

= 6.32.

Since the conjugate acid of a weak base is a weak acid, its pKa can be calculated as pKa = 14 - pKb = 7.68. Using this pKa value, we can calculate the Ka value as follows:

Ka = 10^(-pKa) = 1.2 x 10^-9.

Therefore, the Ka value for the conjugate acid of the given weak base at 25°C is 1.2 x 10^-9.

To know more about conjugate acid, refer here:

https://brainly.com/question/31229565#

#SPJ11

draw the best lewis structure for the free radical no2. what is the formal charge on the n? 答案选项组 2

Answers

The Lewis Structure of NO₂ is attached in the image and the Formal charge of Nitrogen is +1

In order to make a Lewis Structure,the valence electron of Nitrogen and Oxygen are counted.

Valence Electron of Nitrogen: 5

Valence Electron of Oxygen: 6 x 2 atoms= 12

Total Valence Electrons:  17

We have 17 valence electron in order to make our bonds.

Now we put the Nitrogen in the middle and the Oxygen on both sides and then we draw the principal bond between the Nitrogen and Oxygens

O=N-O

For now, we have only used 6 valence electrons when drawing the 3 covalent bonds.

17 Valence Electron were available, now we subtract 6, and we have 11 Valence electrons to distribute among the elements always fulfilling the octet rule, these 11 electrons are called non-binding electrons.

We will start by allocating electrons to the elements that are more electronegative like the Oxygen, until we fulfill the octet rule. The Oxygen with double bond will have 2 pairs of non-binding electrons, and the other oxygen with 1 bond, will have 3 pairs of non-binding electrons.  For a total of 10 electrons used out of 11.

Now we have only 1 Valence electron that will be assigned to the Nitrogen.

To know more about lewis structure here

https://brainly.com/question/31844148

#SPJ4

after the reduction of the ketone, what do you add to destroy the excess borohydride?

Answers

After the reduction of the ketone using sodium borohydride, aqueous acidic solution (such as dilute hydrochloric acid or sulfuric acid) is added to destroy the excess borohydride.

This is because borohydride is a strong reducing agent and can continue to react with water or other functional groups in the reaction mixture, causing unwanted side reactions. The addition of acidic solution helps to neutralize the excess borohydride and prevent further reduction reactions. It also protonates the alcohol product, making it easier to isolate from the reaction mixture.

The reduction of a ketone using sodium borohydride is a common method in organic chemistry to synthesize alcohols. Sodium borohydride is a mild and selective reducing agent that is capable of reducing ketones, aldehydes, and some other carbonyl compounds to their corresponding alcohols. The reaction typically takes place in an organic solvent such as methanol or ethanol and is often performed under acidic or basic conditions to facilitate the reaction.

After the reaction, it is important to destroy the excess borohydride to prevent it from continuing to react with the reaction products or other functional groups in the mixture. The addition of acidic solution not only neutralizes the excess borohydride but also helps to protonate the alcohol product, making it easier to isolate by extraction or distillation.

learn more about sodium borohydride HERE:

https://brainly.com/question/31321350

#SPJ11

consider a 0.65 m solution of c5h5n (kb = 1.7×10-9). mark the major species found in the solution.

Answers

The major species in the solution will be the solute C5H5N, which will be present mostly in the undissociated form, and the solvent water.

In a 0.65 m solution of C5H5N, the major species found in the solution would be the solute C5H5N and the solvent water. The solution contains 0.65 moles of C5H5N per liter of solution, which means that it is a concentrated solution. The basicity constant Kb of C5H5N is 1.7×10-9, which means that it is a weak base. In the solution, C5H5N molecules will undergo hydrolysis to form the conjugate acid, H+C5H5N, and hydroxide ions, OH-. However, since C5H5N is a weak base, only a small fraction of it will undergo hydrolysis. Therefore, the major species in the solution will be the solute C5H5N, which will be present mostly in the undissociated form, and the solvent water.

To know more about solution visit :

https://brainly.com/question/1416865

#SPJ11

URGENT.
What series is this element (ruthenium) part of on the periodic table? (Ex: Noble Gases, Lanthanides, Metalloids, etc.)
AND PLS ANSWER THIS TOO
What are common molecules/compounds that this element (ruthenium) is a part of?

Answers

Ruthenium is a transition metal and it is located in period 5 and group 8 of the periodic table, along with iron (Fe) and osmium (Os).

Ruthenium is commonly found in many industrial and commercial applications, including in the production of hard disk drives, electrical contacts, and jewelry. Some common molecules and compounds that ruthenium is a part of include:

Ruthenium dioxide (RuO2) - a compound commonly used in the production of resistors and other electronic components.

Ruthenium tetroxide (RuO4) - a highly toxic and volatile compound that is used as an oxidizing agent in organic chemistry.

Ruthenium red - a dye used in biological staining and electron microscopy.

Ammonium hexachlororuthenate (NH4)2[RuCl6] - a ruthenium compound used in electroplating and as a precursor for other ruthenium compounds.

Various ruthenium complexes - such as [Ru(bpy)3]2+, which is a commonly used photochemical catalyst.

These are just a few examples of the many molecules and compounds that ruthenium is a part of.

predict the major product formed by 1,4-addition of hcl to 1,3-cycloheptadiene.

Answers

1,4-addition of HCl to 1,3-cycloheptadiene yields 1-chloro-2,3-dimethylcyclohexene as the major product.

1,3-cycloheptadiene is a conjugated diene that can undergo addition reactions with electrophilic reagents.

When 1,3-cycloheptadiene is treated with HCl, 1,4-addition occurs, meaning that the HCl adds to the 1 and 4 positions of the diene. The major product formed is 1-chloro-2,3-dimethylcyclohexene.

The mechanism of the reaction involves the formation of a cyclic carbocation intermediate, followed by attack of the chloride ion on the more substituted carbon, as it is more stabilized by the adjacent methyl groups. This leads to the formation of the major product, as shown below:

1,4-Addition of HCl to 1,3-Cycloheptadiene

The product is a substituted cyclohexene, with a chlorine atom at the 1 position and two methyl groups at the 2 and 3 positions. This reaction is an example of electrophilic addition to a conjugated diene, which is an important class of reactions in organic chemistry.

Learn more about electrophilic addition at: https://brainly.com/question/21496002

#SPJ11

Two charges each +4 uC are on the x-axis, one at the origin and the other at x = 8 m. Find the electric field on x-axis at: a) x = -2 m b) x = 2 m c) x = 6 m

Answers

The specific value of k (electrostatic constant) is required to calculate the electric field at each position on the x-axis.

The specific value of k (electrostatic constant) is required to calculate the electric field at each position on the x-axis.

To find the electric field on the x-axis at different positions, we can use Coulomb's Law. Coulomb's Law states that the electric field created by a point charge is directly proportional to the magnitude of the charge and inversely proportional to the square of the distance from the charge.

Given:

Charge 1 (Q1) = +4 uC

Charge 2 (Q2) = +4 uC

Distance between charges (d) = 8 m

a) At x = -2 m:

The electric field at this position is the vector sum of the electric fields created by each charge. The direction of the electric field will be positive if it points away from the charges and negative if it points towards the charges.

The distance from Charge 1 to x = -2 m is 2 m.

The distance from Charge 2 to x = -2 m is 10 m.

Using Coulomb's Law:

Electric field due to Charge 1 (E1) = (k * Q1) / (distance from Charge 1 to x = -2 m)^2

Electric field due to Charge 2 (E2) = (k * Q2) / (distance from Charge 2 to x = -2 m)^2

The total electric field (E_total) at x = -2 m is the sum of E1 and E2, taking into account their directions.

b) At x = 2 m:

The distance from Charge 1 to x = 2 m is 2 m.

The distance from Charge 2 to x = 2 m is 6 m.

Using Coulomb's Law:

Electric field due to Charge 1 (E1) = (k * Q1) / (distance from Charge 1 to x = 2 m)^2

Electric field due to Charge 2 (E2) = (k * Q2) / (distance from Charge 2 to x = 2 m)^2

The total electric field (E_total) at x = 2 m is the sum of E1 and E2, taking into account their directions.

c) At x = 6 m:

The distance from Charge 1 to x = 6 m is 6 m.

The distance from Charge 2 to x = 6 m is 2 m.

Using Coulomb's Law:

Electric field due to Charge 1 (E1) = (k * Q1) / (distance from Charge 1 to x = 6 m)^2

Electric field due to Charge 2 (E2) = (k * Q2) / (distance from Charge 2 to x = 6 m)^2

The total electric field (E_total) at x = 6 m is the sum of E1 and E2, taking into account their directions.

Please note that in the above explanation, k represents the electrostatic constant. However, the specific value of k is not mentioned, so we cannot provide the numerical values of the electric field without the given value of k.

Learn more about        electrostatic constan

brainly.com/question/16489391

#SPJ11

add the appropriate number of hydrogen atoms to the alkynes and give their systematic names. . Add the appropriate number of hydrogen atoms to the alkyne. IUPAC name: Select Draw Rings More Erase C-CE

Answers

To add hydrogen atoms to an alkyne, you simply need to add one hydrogen to each carbon atom involved in the triple bond.

To add hydrogen atoms to an alkyne, you need to convert the triple bond to a double bond by adding one hydrogen to each carbon atom involved in the triple bond. This will result in a double bond between the two carbon atoms and each carbon will have one additional hydrogen atom attached.

For example, if you have the alkyne C≡C, adding one hydrogen to each carbon atom would result in the structure H-C=C-H, which is a double bond between the two carbon atoms with one hydrogen atom attached to each carbon. The systematic name for this compound is ethene.

Another example is the alkyne HC≡CCH3. Adding one hydrogen to each carbon atom would result in the structure H-C=C-CH3, which is a double bond between the two carbon atoms with one hydrogen atom attached to each carbon. The systematic name for this compound is propene.

Overall, to add hydrogen atoms to an alkyne, you simply need to add one hydrogen to each carbon atom involved in the triple bond.

Here is a step-by-step explanation:
Step 1: Determine the number of carbon atoms in the alkyne.
Count the number of carbon atoms in the alkyne. This will be the basis for the IUPAC name.

Step 2: Add the appropriate number of hydrogen atoms to the alkyne.
For an alkyne, the general formula is CnH2n-2. Based on the number of carbon atoms (n), you can calculate the number of hydrogen atoms (2n-2).

Step 3: Determine the IUPAC name of the alkyne.


The IUPAC name of an alkyne is based on the number of carbon atoms and the position of the triple bond.
For example, if you have an alkyne with 4 carbon atoms and the triple bond is between the first and second carbon, the IUPAC name will be Buton.

Learn more about hydrogen

https://brainly.com/question/28937951

#SPJ11

The blending of one s orbital and two p orbitals produces: a. three sp orbitals b. two sp2 c. three sp3 d. two sp3 e. three sp2

Answers

The blending of one s orbital and two p orbitals produces three sp2 orbitals. This unhybridized p orbital can participate in pi bonding with other atoms or molecules.

When an s orbital and two p orbitals combine, they form three hybrid orbitals known as sp2 orbitals. The s orbital hybridizes with two of the three p orbitals, creating three hybrid orbitals that are all equivalent in energy and shape. These orbitals have a trigonal planar geometry with bond angles of approximately 120 degrees.

When one s orbital and two p orbitals hybridize or blend, they form three equivalent sp2 orbitals. These sp2 orbitals are trigonally planar, with each orbital oriented at 120 degrees from the others. This type of hybridization is commonly observed in molecules with double bonds, such as ethene (C2H4).

To know more about atoms visit:

https://brainly.com/question/1566330

#SPJ11

how effective was the steam distillation? what data do you have to support this?

Answers

Steam distillation is a highly effective method for extracting essential oils and other volatile compounds from plant materials. The effectiveness of steam distillation is supported by a large body of scientific research, which has demonstrated the efficiency of this process in extracting high-quality essential oils from a wide range of plant materials.

One key factor that contributes to the effectiveness of steam distillation is the use of high-pressure steam, which helps to release the essential oils from the plant material.

In addition, the use of water as a solvent helps to protect the delicate chemical compounds found in essential oils, preserving their quality and aroma.

Numerous studies have demonstrated the effectiveness of steam distillation in extracting essential oils from plants, including lavender, peppermint, and eucalyptus.

These studies have shown that steam distillation is capable of extracting a high yield of essential oils with excellent purity and quality, making it an ideal method for the production of essential oils and other natural plant extracts.

Read more about Steam distillation at https://brainly.com/question/29400171

#SPJ11

Analyze each peptide or amino acid below and determine which direction it will migrate in an electrophoresis apparatus at pH = 7.

Answers

To determine the direction in which each peptide or amino acid will migrate in an electrophoresis apparatus at pH 7, we need to consider their charges at that pH.

In electrophoresis, charged molecules migrate towards the electrode of the opposite charge. Here is an analysis of each compound:

1. Peptides and amino acids with a net positive charge at pH 7 (basic amino acids):

  - Arginine (Arg), Lysine (Lys), and Histidine (His): These amino acids have a positive charge at pH 7 due to their basic side chains. They will migrate towards the negative electrode (cathode) in electrophoresis.

2. Peptides and amino acids with a net negative charge at pH 7 (acidic amino acids):

  - Aspartic Acid (Asp) and Glutamic Acid (Glu): These amino acids have a negative charge at pH 7 due to their acidic side chains. They will migrate towards the positive electrode (anode) in electrophoresis.

3. Peptides and amino acids with no net charge at pH 7 (neutral amino acids):

  - Glycine (Gly), Alanine (Ala), Valine (Val), Leucine (Leu), Isoleucine (Ile), Phenylalanine (Phe), Tryptophan (Trp), Proline (Pro), Methionine (Met), Serine (Ser), Threonine (Thr), Cysteine (Cys), Tyrosine (Tyr), Asparagine (Asn), and Glutamine (Gln): These amino acids have no net charge at pH 7. They will not migrate significantly in electrophoresis and will remain near the starting point.

It's important to note that the direction of migration may also be influenced by other factors such as the size and shape of the molecules.

Learn more about electrophoresis and the migration of molecules here:

https://brainly.com/question/32133505?referrer=searchResults

#SPJ11

Other Questions
Consider the language that consists of inputs M,a) such that (i) M is a Turing Machine, (ii) a is a symbol from its tape alphabet, and (iii) there exists some input string w such that during the course of computing on w, M writes a on its tape at some point. Show that this language is undecidable. Ayayai Corp. has 9,300 shares of common stock outstanding. It declares a $2 per share cash dividend on November 1 to stockholders of record on December 1. The dividend is paid on December 31. Prepare the entries on the appropriate dates to record the declaration and payment of the cash dividend. (Credit account titles are automatically indented when amount is entered. Do not indent manually. Record journal entries in the order presented in the problem. If no entry is required, select "No Entry" for the account titles and enter o for the amounts.) What is the molecular weight of a peptide chain with 40 residues? 0.36 Da 60 Da O 4.4 kDa 5.5 kDa shows four permanent magnets, each having a hole through its center. Notice that the blue and yellow magnets are levitated above the red ones. (a) How does this levitation occur? (b) What purpose do the rods serve? (c) What can you say about the poles of the magnets from this observation? (d) If the upper magnet were inverted, what do you suppose would happen? Sonali purchased some pants and skirts the numbers of skirts is 7 less than eight times the number of pants purchase also number of skirt is four less than five times the number of pants purchased purchased For the following reaction, to get the rate of formation of N2, what must we multiply the rate of consumption of NH3 by?2NH3---> N2 + 3H2*Report your answer as a fraction Write a mechanism for the nitration of methyl benzoate (major product only) Include formation of the electrophile from the reaction of nitric acid with sulfuric acid. Only one resonance structure is needed for the intermediate in the EAS portion of the mechanism You have to take Social Issues and Ethics course because (check all that apply) it helps you analyze ethical issues in business and personal life O as professionals, you have the potential to cause harm to society and/or your company it is a step towards minimizing major incidents due to unethical practices all professionals are competent and cannot do harm. it helps protect your job A sample of 8.8x10-12 mol of antimony-11 (122Sb) emits 6.6x109 particles per minute. Calculate the specific activity of the sample (in Ci/g). 1 Ci = 3.70x1010 d/s.Enter to 0 decimal places. Evaluate the double integral DyexdA, where D is the triangular region with vertices (0,0)2,4), and (6,0).(Give the answer correct to at least two decimal places.) A company has a fiscal year-end of December 31:(1) on October 1, $28,000 was paid for a one-year fire insurance policy;(2) on June 30 the company lent its chief financial officer $26,000; principal and interest at 8% are due in one year; and(3) equipment costing $76,000 was purchased at the beginning of the year for cash. Depreciation on the equipment is $15,200 per year.If the adjusting entries were not recorded, would net income be higher or lower and by how much? you can buy a pair of 1.75 diopter reading glasses off the rack at the local pharmacy. what is the focal length of these glasses in centimeters ? On a certain hot summer's day, 379 people used the public swimming pool. The daily prices are $1.50 for children and $2.25 for adults. The receipts for admission totaled $741.0. How many children and how many adults swam at the public pool that day? find the direction angle of v for the following vector. v=73i 7j Light of wavelength 500 nm is used in a two slit interference experiment, and a fringe pattern is observed on a screen. When light of wavelength 650 nm is useda) the position of the second bright fringe is largerb) the position of the second bright fringe is smallerc) the position of the second bright fringe does not change problem 8.27 for the circuit in fig. p8.27, choose the load impedance zl so that the power dissipated in it is a maximum. how much power will that be? which is a joint in which articulating bones are joined by long strands of dense regular connective tissue? The cylindrical pressure vessel has an inner radius of 1.25 m and awall thickness of 15 mm. It is made from steel plates that arewelded along the 45 seam. Determine the normal and shearstress components along this seam if the vessel is subjected to aninternal pressure of 3 MPa. Devons tennis coach says that 72% of Devons serves are good serves. Devon thinks he has a higher proportion of good serves. To test this, 50 of his serves are randomly selected and 42 of them are good. To determine if these data provide convincing evidence that the proportion of Devons serves that are good is greater than 72%, 100 trials of a simulation are conducted. Devons hypotheses are: H0: p = 72% and Ha: p > 72%, where p = the true proportion of Devons serves that are good. Based on the results of the simulation, the estimated P-value is 0. 6. Using Alpha= 0. 05, what conclusion should Devon reach?Because the P-value of 0. 06 > Alpha, Devon should reject Ha. There is convincing evidence that the proportion of serves that are good is more than 72%. Because the P-value of 0. 06 > Alpha, Devon should reject Ha. There is not convincing evidence that the proportion of serves that are good is more than 72%. Because the P-value of 0. 06 > Alpha, Devon should fail to reject H0. There is convincing evidence that the proportion of serves that are good is more than 72%. Because the P-value of 0. 06 > Alpha, Devon should fail to reject H0. There is not convincing evidence that the proportion of serves that are good is more than 72% an aqueous solution containing barium iodide (bai2) is electrolyzed in a cell containing inert electrodes. what are the products at the anode and cathode? choix de groupe de rponses