Chemistry High School

what is the nature of salt which is formed by the combination of weak acid and strong base And have a great day ❤️​

What Is The Nature Of Salt Which Is Formed By The Combination Of Weak Acid And Strong Base And Have A

Answers

Answer 1
It’s either salt solution for the form or neutral for the strong acids and weak base and you too

Related Questions

Which statement describes particles of an ideal gas, based on the kinetic molecular theory?

Answers

Answer:

There are 5 steps/rules of the ideal gases based on kinetic theory.

Explanation:

1. Particles in a gas are constant moving in random motion.

2. combined volume of the particles is negligible.

3. particles exert no forces on one another

4. any collisions between the particles are completely elastic

5. the average kinetic energy of particles is proportional to temperature in kelvins.

(I had help explaining steps from Sal Khan. I hope this helps! Have a great day!)

When(NH4)2SO4(aq) and Ba(NO3)2(aq) react

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Answer:

1 (NH4)2SO4 + Ba(NO3)2 → NH4NO3 + BaSO4

2 (NH4)2SO4 + Ba(NO3)2 → Ba(SO4) + (NH4)(NO3)

Explanation:

THIS IS FOR SCIENCE PLS HELP ME WRITE MY PROMPT How does the human population and human activity affect Earth?

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both work together and the human activity is what population counts on and the activity is what effects the population

When this gas is burned what will happen to the surface of this type of star?

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Use the link above for the answer

How many moles of helium are needed to fill a balloon to a volume of 6.3 L at 28 °C and 320
mmHg?
Round answer to 0.01 decimals

Answers

Answer:

.11 mol

Explanation:

Convert mmHg to atms by dividing by 760. Then multiply 6.3 by the atms and divide by .08206*(273+28) to get mol

.11 mol is the answer


A reaction in the laboratory yields 5.98 g KAI(SO2)2, How many moles of potassium aluminum
sulfate were produced?

Answers

Answer:

0.0308 mol

Explanation:

In order to convert from grams of any given substance to moles, we need to use its molar mass:

Molar mass of KAI(SO₂)₂ = MM of K + MM of Al + (MM of S + 2*MM of O)*2Molar mass of KAI(SO₂)₂ = 194 g/mol

Now we calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g:

5.98 g ÷ 194 g/mol = 0.0308 mol

a 5 g ice cube starts life at -1 C if 2182.5 j are added to it what will be the final temperature upon his demise ?

Answers

Answer:

Final Temp = 23.92°C

Explanation:

ΔH(total) = (m·c·ΔT)ice + (m·ΔH(f))melt'g + (m·c·ΔT)water

2182.5j = (5g)(2.092j/g·°C)(1°C) + (5g)(334.56j/g) + (5g)(4.184j/g·°C)(ΔT)

(2182.5 - 10.46 - 1672.8)j = 20.92j/°C·ΔT

ΔT = (2182.5 - 10.46 - 1672.8)j / 20.92j/°C = 23.92°C

Since the melting ice starts and ends at 0°C and is then warmed to 23.92°C then the temperature change is also the final temp of the water based upon given energy input values.

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