The molar solubility of lead sulfate in 1.0 × 10⁻³ m Na2So4 is (c) 1.8 × 10⁻⁵
The molar solubility of a compound is defined as the amount (in moles) of the compound that can dissolve in one liter of a solution. To determine the molar solubility of PbSO₄, we need to calculate the concentration of Pb2+ ions in the presence of 1.0 × 10⁻³ M Na₂SO₄.
The solubility product constant (Ksp) expression for lead sulfate (PbSO₄) is:
PbSO₄ (s) ↔ Pb₂+ (aq) + SO₄⁻²(aq)
The Ksp expression can be written as:
Ksp = [Pb₂][SO4⁻²]
In the presence of 1.0 × 10–3 M Na₂SO₄, the concentration of SO₄⁻² is already given. Therefore, we need to calculate the concentration of Pb₂+ ions in order to determine the molar solubility of PbSO₄.
Using the Ksp expression, we can write:
Ksp = [Pb₂+][SO₄²⁻]
1.8 × 10^-8 = [Pb₂+][SO₄²⁻]
[Pb₂+] = 1.8 × 10^-8 / [SO₄²⁻]
[Pb₂+] = 1.8 × 10^-8 / 0.001
[Pb₂+] = 1.8 × 10^-5 M
Therefore, the molar solubility of PbSO4 in 1.0 × 10⁻³ M Na₂SO₄ solution is 1.8 × 10⁻⁵ M.
Therefore, the correct answer is (c) 1.8 × 10⁻⁵.
To learn more about molar solubility here
https://brainly.com/question/31588030
#SPJ4
What is the correct assignment of the names of the following aromatic amines? 1-pyrrolidine; Il = pyrimidine;
The correct name for the aromatic amine "Il = pyrimidine" is simply "pyrimidine."
Pyrimidine is an aromatic heterocyclic compound, which consists of a six-membered ring with two nitrogen atoms at positions 1 and 3.
Pyrimidine is a six-membered heterocyclic ring structure composed of four carbon atoms and two nitrogen atoms.
The nitrogen atoms are located at positions 1 and 3 within the ring. The aromatic nature of pyrimidine arises from the presence of a conjugated π electron system, which contributes to its stability and unique chemical properties.
Pyrimidine is an essential building block in nucleic acids, where it pairs with purines (adenine and guanine) to form the genetic code in DNA and RNA. It plays a critical role in storing and transmitting genetic information and is involved in various biological processes.
To summarize, pyrimidine is an aromatic heterocyclic compound with a six-membered ring containing two nitrogen atoms. It is not an aromatic amine but rather an important component of nucleic acids.
To learn more about compound, refer below:
https://brainly.com/question/13516179
#SPJ11
A statistics professor finds that when she schedules an office hour for student help, an average of 1.9 students arrive. Find the probability that in a randomly selected office hour, the number of student arrivals is 7.
To find the probability that in a randomly selected office hour the number of student arrivals is 7, we can use the Poisson distribution formula.
The Poisson distribution is used to model the probability of a certain number of events occurring within a fixed interval of time or space, given the average rate of occurrence.
In this case, the average number of student arrivals is 1.9.
The probability of exactly k events occurring in a Poisson distribution is given by the formula:
P(X=k) = (e^(-λ) * λ^k) / k!
Where λ is the average rate of occurrence.
Using this formula, we can calculate the probability of exactly 7 student arrivals in the given office hour:
P(X=7) = (e^(-1.9) * 1.9^7) / 7!
Calculating this expression will give us the desired probability.
Note: The value of e in the formula represents the base of the natural logarithm and is approximately equal to 2.71828.
To learn more about Poisson click here:brainly.com/question/31019106
#SPJ11
the conversion of 4-pentanoylbiphenyl to 4-pentanylbiphenyl with hydrazine and potassium hydroxide is an overall of carbon? a. oxidation b. not a redox c. reduction
The conversion of 4-pentanoylbiphenyl to 4-pentanylbiphenyl with hydrazine and potassium hydroxide is a reduction . Option c. is correct.
Because it involves the addition of hydrogen atoms to the carbon atoms in the molecule, resulting in a decrease in the oxidation state of the carbons. During the reaction, hydrazine acts as a reducing agent and reduces the ketone group (-[tex]CO^-[/tex]) to an alcohol group (-[tex]CH_2OH[/tex]). This reduction results in the conversion of the carbonyl carbon from sp2 hybridization to sp3 hybridization, resulting in the formation of a new C-H bond.
Therefore, the reaction involves a gain of electrons by the carbonyl carbon, and a reduction of the ketone functional group. There is no simultaneous oxidation of any other species in the reaction.
Therefore, the reaction is a reduction and not an oxidation or a non-redox reaction. Hence, option c. is correct.
To know more about Reduction refer here :
https://brainly.com/question/4222605
#SPJ11
in an aqueous solution of a certain acid the acid is 0.050 issociated and the ph is 4.48. calculate the acid dissociation constant ka of the acid. round your answer to 2 significant digits.
The acid dissociation constant Ka of the acid is 2.48 x 10⁻⁸ M.
The pH of a solution is related to the concentration of H+ ions by the equation:
pH = -log[H⁺]
We know that the pH of the solution is 4.48, so we can find the concentration of H+ ions:
[H+] = [tex]10^(^-^p^H^) = 10^(^-^4^.^4^8^) = 3.52 x 10^(^-^5^) M[/tex]
Since the acid is 0.050 dissociated, the concentration of the undissociated acid is:
[HA] = 0.050 M
The dissociation reaction of the acid can be written as:
HA(aq) ⇌ H+(aq) + A-(aq)
The acid dissociation constant Ka is defined as:
Ka = [H+(aq)][A-(aq)]/[HA(aq)]
At equilibrium, the concentration of H+ ions and A- ions is equal to each other, so we can write:
Ka = [H+(aq)]²/[HA(aq)] = (3.52 x 10⁻⁵)²/0.050 = 2.48 x 10⁻⁸ M
Learn more about acid dissociation: https://brainly.com/question/15012972
#SPJ11
How many grams of ammonia are consumed in the reaction of 103.0 g of lead(ii) oxide?
Approximately 15.7 grams of ammonia are consumed in the reaction of 103.0 g of lead(II) oxide.
To answer this question, we need to first write the balanced chemical equation for the reaction of lead(II) oxide with ammonia:
PbO + 2NH3 → Pb(NH3)2O
From this equation, we can see that 1 mole of lead(II) oxide reacts with 2 moles of ammonia. We can use the molar mass of lead(II) oxide to convert the given mass of 103.0 g into moles:
103.0 g PbO × (1 mole PbO/223.2 g PbO) = 0.462 moles PbO
Since 1 mole of PbO reacts with 2 moles of NH3, we can use stoichiometry to calculate the amount of NH3 consumed in the reaction:
0.462 moles PbO × (2 moles NH3/1 mole PbO) = 0.924 moles NH3
Finally, we can convert moles of NH3 to grams using its molar mass:
0.924 moles NH3 × (17.03 g NH3/1 mole NH3) = 15.62 g NH3
Therefore, 15.62 grams of ammonia are consumed in the reaction of 103.0 grams of lead(II) oxide.
To determine how many grams of ammonia are consumed in the reaction of 103.0 g of lead(II) oxide, we need to use stoichiometry. First, we need a balanced chemical equation for the reaction:
PbO (lead(II) oxide) + 2 NH3 (ammonia) → Pb(NH2)2 (lead(II) amide) + H2O (water)
Now, follow these steps:
1. Calculate the molar mass of lead(II) oxide (PbO): 207.2 g/mol (Pb) + 16.0 g/mol (O) = 223.2 g/mol.
2. Determine the moles of PbO: 103.0 g / 223.2 g/mol ≈ 0.461 mol PbO.
3. Use the stoichiometry from the balanced equation to find the moles of NH3: 0.461 mol PbO × (2 mol NH3 / 1 mol PbO) = 0.922 mol NH3.
4. Calculate the grams of NH3: 0.922 mol NH3 × 17.0 g/mol (NH3) ≈ 15.7 g.
To know more about chemical equation visit:-
https://brainly.com/question/30087623
#SPJ11