What is the measure of the third side of a triangle below where P is the measure of the perimeter? 2x-3y x+2y p=5x+2y

Answers

Answer 1

Answer:

[tex]2x + 3y[/tex]

Step-by-step explanation:

Given

Shape: Triangle

[tex]P = 5x + 2y[/tex]

Sides: [tex]2x - 3y[/tex] and [tex]x + 2y[/tex]

Required

The measure of the third side

The perimeter of a triangle is the sum of all three sides;

Let the third side be represented by Side3

Hence;

[tex]Side3 + 2x - 3y + x + 2y = 5x + 2y[/tex]

Collect like terms

[tex]Side3 + 2x + x - 3y + 2y = 5x + 2y[/tex]

[tex]Side3 + 3x - y = 5x + 2y[/tex]

Collect like terms

[tex]Side3 = 5x + 2y - 3x + y[/tex]

[tex]Side3 = 5x - 3x + 2y + y[/tex]

[tex]Side3 = 2x + 3y[/tex]

Hence, the measure of the third side is 2x + 3y


Related Questions

Three girls of a group of eight are to be chosen. In how many ways can this be done? ​

Answers

Answer:

Step-by-step explanation:

8P3=8*7*6=336

S=4LW+2WH;S+=136,L6,W=4 WHAT IS H

Answers

Answer:

H=5

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

S=4lw+2wh

Put S as 136, l as 6, w as 4, and solve for h.

136 = 4(6)(4)+2(4)H

136 = 8h + 96

-8h = 96 - 136

-8h = -40

h = -40/-8

h = 5

A local doctor’s office logged the number of patients seen in one day by the doctor for ten days. Find the means, median, range, and midrange of the patients seem in 10 days. 27 31 27 35 35 25 28 35 33 24

Answers

Answer:

Mean = 30, Median = 29.5, Range = 9 and Mid-range = 29.5.

Step-by-step explanation:

We are given that a local doctor’s office logged the number of patients seen in one day by the doctor for ten days.

Arranging the given data in ascending order we get;

24, 25, 27, 27, 28, 31, 33, 35, 35, 35.

(a) Mean is calculated by using the following formula;

         Mean, [tex]\bar X[/tex]  =  [tex]\frac{\text{Sum of all values}}{\text{Total number of observations}}[/tex]

                          =  [tex]\frac{27+ 31+ 27+ 35+ 35+ 25+ 28+ 35+ 33+ 24}{10}[/tex]

                          =  [tex]\frac{300}{10}[/tex]  = 30

So, the mean of the given data is 30.

(b) For calculating the median, we have to first have to observe that the number of observations (n) in the data is even or odd.

If n is odd, then the formula for calculating median is given by;

                     Median  =  [tex](\frac{n+1}{2})^{th} \text{ obs.}[/tex]

If n is even, then the formula for calculating median is given by;

                     Median  =  [tex]\frac{(\frac{n}{2})^{th} \text{ obs.}+ (\frac{n}{2}+1)^{th} \text{ obs.} }{2}[/tex]

Here, the number of observations is even, i.e. n = 10.

So,  Median  =  [tex]\frac{(\frac{n}{2})^{th} \text{ obs.}+ (\frac{n}{2}+1)^{th} \text{ obs.} }{2}[/tex]

                     =  [tex]\frac{(\frac{10}{2})^{th} \text{ obs.}+ (\frac{10}{2}+1)^{th} \text{ obs.} }{2}[/tex]

                     =  [tex]\frac{(5)^{th} \text{ obs.}+ (6)^{th} \text{ obs.} }{2}[/tex]

                     =  [tex]\frac{28+31}{2}[/tex]

                     =  [tex]\frac{59}{2}[/tex]  =  29.5

So, the median of the data is 29.5.

(c) The range of the data is given by = Highest value - Lowest value

                                                        = 35 - 24 = 9

So, the range of the data is 9.

(d) Mid-range of the data is given by the following formula;

                   Mid-range  =  [tex]\frac{\text{Highest value}+\text{Lowest value}}{2}[/tex]

                                      =  [tex]\frac{35+24}{2}[/tex] = 29.5

An equilateral triangular plate with sides 8 m is submerged vertically in water so that the base is even with the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it.

Answers

Answer:

Hydro static force is =18377 N

Step-by-step explanation:

The hydro static force is equals to the hydro static pressure times the area.

The hydro static pressure of a fluid increases as the depth of the fluid increases and the formula of it is given below.

Hydro static Pressure, P = d·g·ρ

Where, d is the depth of the object

g is the gravitational constant

ρ is the density of the fluid

Density of water   ρ = [tex]1000 kg/m3[/tex]

=1000 kg/m^3 * 9.8m/s^2 which is √(3/2).a below the water level.

Side of the plate  x = 10 m

The hydrostatic force = the pressure at the center x the area =[tex][sqrt(3)/2 m][1000 kg/m^3 * 9.8m/s^2][/tex][tex][(1/2)(3)(8)(sqrt(3)/2) m^2][/tex]=18377 N

The manager of the Danvers-Hilton Resort Hotel stated that the mean guest bill for a weekend is $600 or less. A member of the hotel's accounting staff noticed that the total charges for guest bills have been increasing in recent months. The accountant will use a sample of weekend guest bills to test the manager's claim.
a. Which form of the hypotheses should be used to test the manager's claim?
H0:
greater than or equal to 600
greater than 600
less than or equal to 600
less than 600
equal to 600
not equal to 600
Ha: Select
greater than or equal to 600
greater than 600
less than or equal to 600
less than 600
equal to 600
not equal to 600
b. When H0 cannot be rejected, can we conclude that the manager's claim is wrong?
Yes
No
c. When H0 can be rejected, can we conclude that the manager's claim is wrong?
Yes
No

Answers

Answer:

(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] $600

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $600

(b) When H0 cannot be rejected, we conclude that the manager's claim is correct.

(c) When H0 can be rejected, we conclude that the manager's claim is wrong.

Step-by-step explanation:

We are given that the manager of the Danvers-Hilton Resort Hotel stated that the mean guest bill for a weekend is $600 or less.

The accountant will use a sample of weekend guest bills to test the manager's claim.

Let [tex]\mu[/tex] = population mean guest bill for a weekend

(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] $600

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $600

Here null hypothesis states that the mean guest bill for a weekend is $600 or less.

On the other hand, alternate hypothesis states that the mean guest bill for a weekend is more than $600.

(b) When the null hypothesis ([tex]H_0[/tex]) cannot be rejected, then the correct conclusion would be: We conclude that the mean guest bill for a weekend is $600 or less which means that the manager's claim is correct.

(c) When the null hypothesis ([tex]H_0[/tex]) can be rejected, then the correct conclusion would be: We conclude that the mean guest bill for a weekend is more than $600 which means that the manager's claim is wrong.

Line segment ON is perpendicular to line segment ML. What is the length of segment NP?

Answers

Answer:

2 units.

Step-by-step explanation:

In this question we use the Pythagorean theorem which is shown below:

Given that

The right triangle OMP

The hypotenuse i.e OM is the circle radius =5 units.

The segment MP = 4 units length

Therefore

[tex]OP^2 + MP^2 = OM^2[/tex]

[tex]OP^2 + 4^2 = 5^2[/tex]

[tex]OP^2 + 16 = 25[/tex]

So OP is 3

Now as we can see that ON is also circle radius so it would be 5 units

And,

ON = OP + PN

So,

PN is

= ON - OP

= 5 units - 3 units

= 2 units

Answer:

2

Step-by-step explanation:

A bowl has 85 pieces of candy. Nineteen children empty the bowl of candy. Some children take 3 pieces, some children take 5 pieces, and 1 child takes 7 pieces of candy. How many children take 3 pieces of candy?

Answers

Answer:

6

Step-by-step explanation:

12*5=60

6*3=18

1*7=7

hope this help

The population of the city of Peachwood is currently 12,000 and increases every year at a rate of 5%. The function that describes the model is ƒ(x) = 12000 • 1.05x. Which of the following choices would be the number of people in the city after one year?

Answers

Answer: 12600

Step-by-step explanation:

We are given the function that f(x) = 12000 * 1.05x

the x in f(x) is the amount of years that passed in the city of Peachwood, and the f(x) is the total population of Peachwood

These are two key elements in this function,

Therefore after 1 year the equation would be f(1) = 12000*1.05(1)

or f(1) = 12600

Select the correct answer. Vector u has its initial point at (-7, 2) and its terminal point at (11, -5). Vector v has a direction opposite that of vector u, and its magnitude is three times the magnitude of u. What is the component form of vector v? A. v = B. v = C. v = D. v =

Answers

Answer:

Step-by-step explanation:

vector u=<(11-(-7),(-5-2)>=<18,-7>

as direction is opposite to u

so vector v=-3(18,-7)=(-54,21)

A hiker starting at point P on a straight road wants to reach a forest cabin that is 2 km from a point Q, 3 km down the road from P . She can walk 8 km/hr along the road but only 3 km/hr through the forest. She wants to minimize the time required to reach the cabin. How far down the road should she walk before setting off through the forest straight for the cabin?

Answers

Answer:

2.19 km

Step-by-step explanation:

If x is the distance she walks down the road before turning, then the total time is:

t = x/8 + √((3 − x)² + 2²) / 3

t = x/8 + √(9 − 6x + x² + 4) / 3

24t = 3x + 8√(13 − 6x + x²)

24t = 3x + 8(13 − 6x + x²)^½

Take derivative of both sides with respect to x.

24 dt/dx = 3 + 4(13 − 6x + x²)^-½ (-6 + 2x)

When t is a minimum, dt/dx = 0.

0 = 3 + 4(13 − 6x + x²)^-½ (-6 + 2x)

-3 = 4(13 − 6x + x²)^-½ (-6 + 2x)

3 / (6 − 2x) = 4(13 − 6x + x²)^-½

3 / (24 − 8x) = (13 − 6x + x²)^-½

(24 − 8x) / 3 = (13 − 6x + x²)^½

(24 − 8x)² / 9 = 13 − 6x + x²

576 − 384x + 64x² = 117 − 54x + 9x²

459 − 330x + 55x² = 0

Solve with quadratic formula.

x = [ 330 ± √((-330)² − 4(55)(459)) ] / 2(55)

x = (330 ± √7920) / 110

x = 2.19 or 3.81

Since 0 < x < 3, x = 2.19.

Find the Prime factors of 1729. Arrange the factors in ascending order. Find a relation between
consecutive prime factors​

Answers

Answer:

prime factors in ascending order of 1729 is 7 , 13 , 19

relation between  consecutive prime factors is 6

Step-by-step explanation:

given data

number = 1729

solution

we get here factors of 1729

1729 = 7 × 13 × 19

so that required prime factors in ascending order of 1729 is 7 , 13 , 19

and

now we get relation between these prime factors is the difference between consecutive prime factors is

13 - 7 =  6

19 - 13 = 6

so relation between  consecutive prime factors is 6

Step-by-step explanation:

Prime factors of the number 1729 are 7,13,19

i.e. 1729 =7×13×19

The factors in ascending order are 7,13,19.

Clearly we can see that each consecutive prime factors​ have difference of 6.

13-7=6

19-13=6

I NEED HELP PLEASE, THANKS! Use Cramer's Rule to find the solution of the system of linear equations, if a unique solution exists. –5x + 2y – 2z = 26 3x + 5y + z = –22 –3x – 5y – 2z = 21 A. (–1, –7, 2) B. (–6, –1, 1) C. (–1, 3, 1) D. no unique solution

Answers

Answer:

Option B

Step-by-step explanation:

We are given the following system of equations -

[tex]\begin{bmatrix}-5x+2y-2z=26\\ 3x+5y+z=-22\\ -3x-5y-2z=21\end{bmatrix}[/tex]

Now by Cramer's Rule, we would first write down the matrix of the coefficients , replacing each column with the answer column -

[tex]\begin{bmatrix}-5&2&-2\\ 3&5&1\\ -3&-5&-2\end{bmatrix}[/tex] ,

[tex]\begin{bmatrix}26\\ -22\\ 21\end{bmatrix}[/tex]

Replace each column of the coefficients shown at the top, with the answer column at the bottom respectively -

[tex]\begin{bmatrix}-5&2&26\\ 3&5&-22\\ -3&-5&21\end{bmatrix}[/tex]

Now solve through Cramer's Rule -

x = Dx / D = - 6,

y = Dy / D = - 1,

z = Dz / D = 1

Solution = ( - 6, - 1, 1 ) = Option B

-5 x + 2 y - 2 z = 263 x + 5 y + z = -22 - 3 x - 5 y - 2 z = 21

Answer is x=-6,\:z=1,\:y=-1

A farmer is building a fence to enclose a rectangular area consisting of two separate regions. The four walls and one additional vertical segment (to separate the regions) are made up of fencing, as shown below. A rectangular area consisting of two separated regions. If the farmer has 162 feet of fencing, what are the dimensions of the region which enclose the maximal areas?

Answers

Answer:

The maximal area will be "1093.5 square feet".

Step-by-step explanation:

Let,

Length = L feet

Breadth = b feet

Given Total fencing = 162 feet

According to the question,

 [tex](2\times L)+(3\times b)=162[/tex]

              [tex]2L+3B=162[/tex]

                         [tex]L=\frac{162-3b}{2}[/tex]

                         [tex]L=81-\frac{3}{2}b[/tex]

As we know,

 [tex]Area=Length\times breadth[/tex]

          [tex]=(81-\frac{3}{2}b)\times b[/tex]

          [tex]=81b-\frac{3}{2}b^2[/tex]

Now, we required to decrease or minimize the are. So for extreme points:

 [tex]\frac{dA}{db}=0[/tex]

or,

 [tex]\frac{dA}{dB}=\frac{d}{db}(81-\frac{3}{2}b^2 )=0[/tex]

       [tex]81-\frac{3}{2}\times 2\times b=0[/tex]

                            [tex]b=\frac{81}{3}[/tex]

                            [tex]b=27 \ feet[/tex]

Now on putting the value of b, we get

 [tex]l=81-\frac{3}{2}\times 27[/tex]

   [tex]=81-40.5[/tex]

   [tex]=40.5 \ feet\\[/tex]

So that the dimensions will be:

⇒  40.5 feet by 27 feet

Therefore when the dimension are above then the area will be:

=  [tex]81\times 27-\frac{3}{2}\times 27\times 27[/tex]

=  [tex]2187-\frac{3}{2}\times 729[/tex]

=  [tex]2187-1093.5[/tex]

=  [tex]1093.5 \ square \ feet[/tex]

Suppose you toss a coin 100 times and get 65 heads and 35 tails. Based on these​ results, what is the probability that the next flip results in a tail​?

Answers

Answer:

[tex] P(Head) = \frac{65}{100}=0.65[/tex]

[tex] P(Tail) = \frac{35}{100}=0.35[/tex]

And for this case the probability that in the next flip we will get a tail would be:

[tex] P(Tail) = \frac{35}{100}=0.35[/tex]

Step-by-step explanation:

For this case we know that a coin is toss 100 times and we got 65 heads and 35 tails.

We can calculate the empirical probabilities for each outcome and we got:

[tex] P(Head) = \frac{65}{100}=0.65[/tex]

[tex] P(Tail) = \frac{35}{100}=0.35[/tex]

And for this case the probability that in the next flip we will get a tail would be:

[tex] P(Tail) = \frac{35}{100}=0.35[/tex]

the cube of a number increased by 4 times the same number

Answers

Answer:

x=∛4 x

Step-by-step explanation:

Let the number be x.

According to the question,

x^3=4 x

x=∛4 x

This is the only answer we can conclude from the information given in the question.

The required expression is x³ + 4x.

Given that,

The cube of a number increased by 4 times the same number is to be determined.


What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,

Let the number be x,
cube of number = x³
4 time of number = 4x
The cube of a number increased by 4 times the same number, which implies,
x³ + 4x

Thus, the required expression is x³ + 4x.

Learn more about arithmetic here:

brainly.com/question/14753192

#SPJ2

b. Parallelogram PQRS has base RS=14 m and an area of 70 m². What is the height of
the parallelogram?


Rs=14m and an area of 70m2

Answers

Answer

h = 5m

Step-by-step explanation:

area of a parallelogram is b * h

base = 14 m

h = ?

Area = 70 m²

Area = b * h

70 = 14 * h

h = 70 / 14

h = 5 m

The length of a rectangle is 3 yd longer than its width. If the perimeter of the rectangle is 62 yd, find its width and length

Answers

Answer:

Length=17 yds, Width=14 yds

Step-by-step explanation:

62=x+x+(x+3)+(x+3)

4x+6=62

4x=56

x=14

x+3=17

Suppose the average lifetime of a certain type of car battery is known to be 60 months. Consider conducting a two-sided test on it based on a sample of size 25 from a normal distribution with a population standard deviation of 4 months.a) If the true average lifetime is 62 months and a =0.01, what is the probability of a type II error?b) What is the required sample size to satisfy and the type II error probability of b(62) = 0.1?

Answers

Answer:

a. the probability of a type II  error is 0.5319

b. the required sample size to satisfy and the type II error probability  is 59.4441

Step-by-step explanation:

From the information given; we have:

sample size n = 25

Population standard deviation [tex]\sigma[/tex] = 4

true average lifetime = Sample Mean [tex]\bar X[/tex] = 62

We can state our null hypothesis and alternative hypothesis as follows:

Null hypothesis:

[tex]\mathbf{H_o : \mu = 60}[/tex]

Alternative hypothesis

[tex]\mathbf{H_1 : \mu \neq 60}[/tex]

Where ;

∝ = 0.01

From the standard normal tables at critical value ∝ = 0.01 ; the level of significance is -2.575 lower limit and 2.575 upper limit

The z statistics for the lower limit is:

[tex]lower \ limit = \dfrac{\bar X - \mu }{\dfrac{\sigma}{\sqrt {n}}}[/tex]

[tex]-2.575= \dfrac{\bar x - 60 }{\dfrac{4}{\sqrt 25}}}[/tex]

[tex]-2.575= \dfrac{\bar x - 60 }{0.8}}}[/tex]

[tex]-2.575*0.8= {\bar x - 60 }{}}}[/tex]

[tex]-2.06= {\bar x - 60 }{}}}[/tex]

[tex]\bar x = 60-2.06[/tex]

[tex]\bar x = 57.94[/tex]

The z statistics for the upper limit is:

[tex]lower \ limit = \dfrac{\bar X - \mu }{\dfrac{\sigma}{\sqrt {n}}}[/tex]

[tex]2.575= \dfrac{\bar x - 60 }{\dfrac{4}{\sqrt 25}}}[/tex]

[tex]2.575= \dfrac{\bar x - 60 }{0.8}}}[/tex]

[tex]2.575*0.8= {\bar x - 60 }{}}}[/tex]

[tex]2.06= {\bar x - 60 }{}}}[/tex]

[tex]\bar x = 60-(-2.06)[/tex]

[tex]\bar x = 60+2.06[/tex]

[tex]\bar x = 62.06[/tex]

Thus; the probability of a type II error is determined as follows:

β = P (  [tex]57.94 < \bar x < 62.06[/tex] )

[tex]= P ( \dfrac{57.94 -62 }{\dfrac{4}{\sqrt{25}}}<\dfrac{62.06 -62 }{\dfrac{4}{\sqrt{25}}})[/tex]

[tex]= P ( \dfrac{-4.06 }{0.8}}<\dfrac{2.06 }{0.8})[/tex]

= P ( -5.08 < Z < 0.08 )

= P ( Z < 0.08) - P ( Z < - 5.08)

Using Excel Function: [ (=NORMDIST (0.08)) - (=NORMDIST(-5.08)) ] ; we have:

= 0.531881372 - 0.00000001887

= 0.531881183

0.5319

b.

What is the required sample size to satisfy and the type II error probability of b(62) = 0.1

Recall that:

The critical value of ∝ = 2.575  ( i. e   [tex]Z_{1 - \alpha/2 } = 2.575[/tex]  )

Now ;

the critical value of β is :

[tex]Z _{1- \beta} = 1.28[/tex]

The  required sample size to satisfy and the type II error probability  is therefore determined as :

[tex]n = [\dfrac{(Z_{1 - \alpha/2} + Z_{1 - \beta} ) \sigma }{\delta}]^2[/tex]

[tex]n = [\dfrac{(2.575+1.28 ) 4 }{2}]^2[/tex]

[tex]n = [\dfrac{(3.855 ) 4 }{2}]^2[/tex]

[tex]n = [\dfrac{(15.42 ) }{2}]^2[/tex]

n = 7.71 ²

n= 59.4441

Thus; the required sample size to satisfy and the type II error probability  is 59.4441

A)

In order to calculate the Type II Error, we proceed with stating the factors:

Hypothesized Mean is given as  =  μ[tex]_{0} [/tex]        = 60

True Mean  is given as                 =  μa        = 62

Standard Deviation  is given as  = σ           = 4

Sample Size                                   = n           = 25

Standard error of mean                = σx          =σ/[tex]\sqrt{\\} [/tex]σ               =  0.80

given 0.01 level and two tailed test critical value Zσ             ±  2.58 or approximately 3

Acceptance region is

given as:   = μ - Z∝ * σx ≤ Π ≤ μ+Z∝⇄            =57.9360 ≤x≤   62.0640

Type II Error = probability of not rejecting β    = P(57.94-μa/σx))     <Z< (62.064-μa)/σx))

                                      = P (-5.08   <Z<    0.08)
                                      = 0.5319-0)

                                      = 0.532


B

Hypothesized mean                        = μ₀             =        60

True Mean                                        =μₐ               =       62          

Standard Deviation                          =σ                 =      4

for 0.01 level and two-tailed test critical value Z∝/2              ± 2.58

for 0.01 level of type II error critical value Z[tex]\beta [/tex]                         = 1.28

Required sample size    = n                                       = ([tex]Z_{\alpha /2} [/tex] + [tex]Z_{\beta } [/tex])²σ²/(μ₀-μ₀)²
                                                                                    = 60


See the link below for more about two-sided tests:
https://brainly.com/question/8170655

 

GO DEEPER
In the last six months, Sonia's family used 456, 398,655, 508,
1,186, and 625 minutes on their cell phone plan. In an effort to spend less
time on the phone each month, Sonia's family wants to try and keep the
mean cell phone usage at 600 minutes or less. Over the last 6 months,
by how many minutes did the mean number of minutes exceed their goal?​

Answers

Answer:

46

Step-by-step explanation:

A glass vase has a circular rim with a diameter of 5in. How many inches of ribbon are needed to go once around the rim? Use 3.14

Answers

Answer:

31.4 inches

Step-by-step explanation:

The circumference of a circle has the formula 2πr.

2 × π × 5

= 10 × 3.14

= 31.4

31.4 inches of ribbon is needed to go once around the rim.

Answer:

15.7 inches of ribbon.

Step-by-step explanation:

This question is basically asking for the circumference of the glass vase's rim. We can calculate that by multiplying the diameter by π, which in this case, is 3.14.

The diameter is 5 inches, so all you need to do is 5 * 3.14 = 15.7 inches of ribbon.

Hope this helps!

Solve 3v2 – 84 = 0, where v is a real number.
Round your answer to the nearest hundredth.
If there is more than one solution, separate them with commas.
If there is no solution, click on "No solution".

Answers

Answer:

The given equation has two solutions

[tex]v = (-5.29, \: 5.29)[/tex]

Step-by-step explanation:

The given equation is

[tex]3v^2 - 84 = 0[/tex]

Let’s solve the equation

[tex]3v^2 - 84 = 0 \\\\3v^2 = 84 \\\\v^2 = \frac{84}{3} \\\\v^2 = 28 \\\\[/tex]

Take the square root on both sides

[tex]\sqrt{v^2} = \sqrt{28} \\\\v = \sqrt{28} \\\\v = \pm 5.29 \\\\[/tex]

So the equation has two solutions

[tex]v = (-5.29, \: 5.29)[/tex]

Also refer to the attached graph of the equation where you can verify that the equation has two solutions.

Note:

It is a very common mistake to consider only the positive value and not the negative value.

Consider the square root of 25

[tex]\sqrt{25} = \pm 5 \\\\Since \\\\5 \times 5 = 25 \\\\-5 \times -5 = 25 \\\\[/tex]

That is why we have two solutions for the given equation.

Help me with this problem, thank you<3

Answers

Answer:

1,050 workers

Step-by-step explanation:

25% = 0.25

0.25 × 1400 = 350

1400 - 350 = 1050

Hope this helps.

Consider the function g(x) = x^12. Describe the range of the function.

Answers

Answer:

  0 ≤ g(x) < ∞

Step-by-step explanation:

The range is all non-negative numbers.

___

g(x) is an even-degree polynomial with a positive leading coefficient, so it opens upward. There is no added constant, so its minimum value is zero. The function can take on all values zero or greater.

  range: [0, ∞)

Please answer this correctly

Answers

Answer:

1/5

Step-by-step explanation:

The number 5 or greater than 4 is 5.

1 number out of 5 total parts.

= 1/5

P(5 or greater than 4) = 1/5

The kitchen is 15 feet wide and wight 18ft long. How many 12 inch Square tiles will it take to tile the kitchen floor?

Answers

Answer:

270 tiles.

Step-by-step explanation:

The kitchen is 15 x 18 feet. If we multiply we find the area is 270 square feet. one square foot is a 12 x 12 inch square, so we can fit one tile per square foot, giving us 270 tiles.

Suggest changing to “On the graph of an exponential function representing growth, what happens to the slope of the graph as x increases?”

Answers

Answer:

If we have a growing exponential relation, we can write it as:

f(x) = A*r^x

Where A is the initial amount, r is the rate of growth, in this case, r > 1 (because is a growing exponential relation)

Now, the "slope" of the graph in x, is equal to the derivate of f(x) in that point, and we have:

f'(x) = A*(r^x)*ln(r)

Now, remember that r > 1, then ln(r) > 0.

then, f'(x) is a growing function as x grows, and f'(x) grows exponentially, this means that the slope of the graph also grows exponentially as x grows.

I paid twice as much by not waiting for a sale and not ordering on line. Which ofthe following statements is also true?
(a) I paid 200% more than I could have online and on sale.
(b) I paid 100% of what I could have online and on sale.
(c) I paid 200% of what I could have online and on sale.
(d) I paid 3 times what I could have online and on sale.

Answers

Answer:

Option (c).

Step-by-step explanation:

It is given that, I paid twice as much by not waiting for a sale and not ordering online.

Let the cost of items ordering online be x.

So, now i am paying twice of x = 2x

Now, we have find 2x is what percent of x.

[tex]Percent =\dfrac{2x}{x}\times 100=200\%[/tex]

It means, I paid 200% of what I could have online and on sale.

Therefore, the correct option is (c).

Please answer question now in two minutes

Answers

Answer:

V lies in the exterior of <STU.

Step-by-step explanation:

V lies in the exterior of <STU.

Ujalakhan01! Please help me! ASAP ONLY UJALAKHAN01. What's (x-1)(x-1)?

Answers

Answer:

x^2-2x+1

Step-by-step explanation:

We can solve this by using FOIL

First, Outside, Inside, Last

Multiply the x with the x to get x^2

Then x times -1 for the outside numbers to get -x

Then -1 times x for the inside numbers to get -x

And finally -1 and -1 for the last numbers to get 1

Add the two -x to get -2x.

Put it all together

x^2-2x+1

Answer:

[tex]x^2-2x+1[/tex]

Step-by-step explanation:

=> (x-1)(x-1)

USING FOIL

=> [tex]x^2-x-x+1[/tex]

=> [tex]x^2-2x+1[/tex]

What is 6 1/2 subtracted by 2 2/3

Answers

Answer:

The answer to this equation is 3 5/6

Step-by-step explanation:

in order to solve this problem, we must first turn these fractions into improper fractions. We can do this by multiplying the base number with the denominator and adding the numerator to that number.

6 1/2 = 13/2

2 2/3 = 8/3

Now, set up your equation.

13/2 - 8/3

Change the denominators to the same number so it will be easier to subtract.

39/6 - 16/6

Now subtract.

23/6 = 3 5/6

Answer:

3 5/6

Step-by-step explanation:

6 1/2 - 2 2/3 = 13/2 - 8/3

(39 - 16)/6 = 23/6 = 3 5/6

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